PHP - Problem Using Limit In Select Statement
I have got a set of data for a country for each week of the year, but want to display the data a quarter at a time, using a form which posts a value into LIMIT, which was OK for the 1st quarter, but for subsequent quarters I needed to use LIMIT in the form LIMIT start, rows.
I found by experiment that this had to be the last statement in the query.
when I added the start I got an error:
Parse error: syntax error, unexpected ',' in /homepages/43/d344817611/htdocs/Admin/Visitdata.php on line 10
Here is the SQL part of my code:
$Visit_data="SELECT WeekNo.WNo, WeekNo.WCom, Countries.Country, ctryvisits.CVisits FROM ctryvisits LEFT JOIN Countries ON ctryvisits.country=Countries.CID LEFT JOIN WeekNo ON ctryvisits.WNo=WeekNo.WNo WHERE Countries.Country = '".$_POST["Country"]."' ORDER BY ctryvisits.WNo LIMIT '".$_POST["QUARTER"]."'" - 13, '".$_POST["QUARTER"]."'";Is this the best way of doing what I require or is there an easier way of achieving what I want? Similar TutorialsHi everybody i am beginnet with working with sql in php..so i confused.....i made one scripte and i am making the secound and now i am facing a problem....i hope u could help!! i have a dat=abse of my chatroom....this is the code i typed...please have a look at it! Code: [Select] $usern=$_SESSION['etchat_'.$this->_prefix.'username']; $con1 = mysql_connect("localhost","manosir_main","********"); if (!$con1) { die('Could not connect: ' . mysql_error()); } mysql_select_db("manosir_manoshos_main", $con1); $users= mysql_query(" select etchat_user_online_user_sex from db1_etchat_useronline where etchat_user_online_user_name = $usern "); in my database, i ahve a table called db1_etchat_useronline that keeps record of online users in chatroom. as u usee i qant to to get the user sex ( etchat_user_online_user_sex) of th current user!!! as u see i conected to database correctly but now i dont know how to echo the $users . before this i echo my sql results with mysql_fetch_array ..but now i cant.......i got nothing!!!! can someone help me!!!!! Hi... I have query in highlighting null data using this code: Code: [Select] <?php include 'config.php'; $currentEmpID = $_SESSION['empID']; if(!isset($_POST['Regsubmit_'])){ $DATE1 = $_GET['Regfirstinput']; $DATE2 = $_GET['Regsecondinput']; $sql = "SELECT DISTINCT IF(ISNULL(a.LOG_IN), 'rdc', '') AS LOGIN_CLASS, IF(ISNULL(a.LOG_OUT), 'rdc', '') AS LOGOUT_CLASS, a.EMP_ID, CONCAT(LASTNAME, ', ' , FIRSTNAME) AS FULLNAME, a.LOG_IN, a.LOG_OUT FROM $ATTENDANCE.attendance_build AS a JOIN $ADODB_DB.employment em ON (a.EMP_ID = em.EMP_NO AND em.STATUS IN ('Reg Operatives', 'Reg Staff')) WHERE LOG_IN BETWEEN '$DATE1' AND '$DATE2' OR ISNULL(LOG_IN) OR ISNULL(LOG_OUT)"; $DTR = $conn3->GetAll($sql); $smarty->assign('attendance', $DTR); } $smarty->display('header_att.tpl'); $smarty->display('RegAttendance.tpl'); $smarty->display('footer.tpl'); ?> and here is the tpl code: Code: [Select] {section name=att loop=$attendance} <tr> <td colspan="2">{$attendance[att].EMP_ID}</td> <td colspan="2">{$attendance[att].FULLNAME}</td> <td colspan="2" class="{$attendance[att].LOGIN_CLASS}">{$attendance[att].LOG_IN|date_format:"%d-%m-%Y %I:%M %p"}</td> <td colspan="2" class="{$attendance[att].LOGOUT_CLASS}">{$attendance[att].LOG_OUT|date_format:"%d-%m-%Y %I:%M %p"}</td> </tr> {sectionelse} <tr><td colspan="1">No DATA</td></tr> {/section} this code highlight the null value of login or logout or both. this is the css: Code: [Select] .rdc {background-color:#ff0000;} Now, I need to revised my query statement, because i have separate code for adding attendance if the employee has no attendance or no login or no logout. I just want to happen is if the employee is already add his attendance in NRS table or should I said if the LOG_IN in attendance table is equal to TIME_IN in NRS table the data will have a color yellow. For Example: I have this data in attendance table: EMP_ID = 012012 LOG_IN = NULL LOG_OUT = 2011-12-12 13:35:00 I will his attendance in NRS table to have his attendance: EMP_NO = 012012 TIME_IN = 2011-12-12 05:35:00 TIME_OUT = 2011-12-12 13:35:00 In my above query the LOG_IN has a background color of RED. I want to happen is if I add his attendance in NRS the EMP_NO, LOG_IN, LOGOUT will have a color to notice that it is already have in NRS. Because theirs a scenario that the employee has no login or no logout or both. Feel free to ask me if my explanation is not clear to you. Thank you in advance I have searched for a solution to a code that I wrote, with unique numbers in the SQL statement of LIMIT at the end and using execute(). I have also set PDO::ATTR_EMULATE_PREPARES, false I know that there is ways to use bindValue() or bindParam() instead of execute() for this. However, the way I have it set up works, but is there a security flaw with the way I am using LIMIT and should I be using bindParam() instead of execute()? <?php if ($numbered_row == 0) { $limitation = ''; } else { $started_page = ($page_number - 1) * $items_on_each_page; $limitation = ' LIMIT '. $started_page . ',' . $items_on_each_page; } $sql_query = "SELECT * FROM `myTable` WHERE `id` = :id AND `group` = :group AND `name` LIKE :name AND `country` = :country ORDER BY `date` DESC" . $limitation; $query_result = $pdo_connecting->prepare($sql_query); $query_result->execute(array(':id' => '73', ':group' => 'Furniture', ':name' => '%'.$name.'%', ':country' => $country)); ?> Edited November 21, 2018 by Cobra23 I am building a commenting system, it's sort of like facebooks comments. I have it right now so it loads the first last 3 comments in the database, and then there's a button to view all comments. I have it working fine, except when you add another comment to it, and then click the view all comments, This is the script that loads onload showing the last 3 comments $limit = 3; $query5 = mysql_query("SELECT * FROM sub_comments WHERE status_id='$id' ORDER BY id DESC LIMIT $limit"); This is the php script that runs when you click view more //($start_id would be 3 in this case) $query5 = mysql_query("SELECT * FROM sub_comments WHERE status_id='$comment_id' ORDER BY id DESC LIMIT $start_id, 1000"); so to try to show you what's happening: OnLoad--------------------------------|---When you add more comments, (let's just say u add 1 comment before u click view comments)---- comment 9 --------------------------| comment 10 comment 8 --------------------------| comment 9 comment 7 --------------------------| comment 8 ------------------------------------------| comment 7 ----to be loaded onclick-------------|------What's loaded onclick--- comment 6 --------------------------| comment 7 comment 5 --------------------------| comment 6 comment 4 --------------------------| comment 5 comment 3 --------------------------| comment 4 comment 2 --------------------------| comment 3 comment 1 --------------------------| comment 2 ------------------------------------------| comment 1 (see how "comment 7" is being shown twice in a row) I have two tables...one is scheduled_umps and one is games. Both tables have a column 'game_id'. I need to select how many games a person is scheduled for in a given time frame. Here's what I have for the select...and it's not working (You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE scheduled_umps.ump_id = '34' AND games.game_id = scheduled_umps.game_id AN' at line 1) Code: [Select] <?php $today_is_this_date = date('Y-m-d'); $four_months_ago = date('Y-m-d', strtotime('-4 months', strtotime($today_is_this_date))); $four_months_from_now = date('Y-m-d', strtotime('+4 months', strtotime($today_is_this_date))); /// How many games have you worked? //$query = "SELECT COUNT(ump_id) FROM scheduled_umps WHERE `ump_id` = '$_SESSION[ump_id]'"; ///this one selects how many games you've worked NO MATTER WHAT THE DATE $query = "SELECT scheduled_umps.game_id, games.game_id, COUNT(scheduled_umps.ump_id) WHERE scheduled_umps.ump_id = '$_SESSION[ump_id]' AND games.game_id = scheduled_umps.game_id AND games.game_id BETWEEN $four_months_ago AND $four_months_from_now"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "You have been scheduled on <b>". $row['COUNT(ump_id)'] ."</b> dates for the $_SESSION[association_name]."; } ?> [\code] Any ideas where I'm going wrong? Thanks for the help...I HATE multi-table selects! Hey guys, I'm trying to get this working... No errors right now, but I'm not returning any results :/ been messing with it for days. Code: [Select] <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" /> <label for="search_by">Search By</label> <select name="search_by"> <option value"player">Player</option> <option value"city">City</option> <option value"alliance">Alliance</option> <option value"browse">Browse</option> </select> <input type="text" name"search"> <input type="submit" value="search" name="search"> <?php $search_by = $_POST['search_by']; $search = $_POST['search']; echo "<table><tr><td>Player</td><td>city</td><td>alliance</td><td>x</td><td>y</td><td>other</td><td>porters</td><td>conscripts</td><td>Spies</td><td>HBD</td><td>Minos</td><td>LBM</td><td>SSD</td><td>BD</td><td>AT</td><td>Giants</td><td>Mirrors</td><td>Fangs</td><td>ogres</td><td>banshee</td></tr>" ; $dbc = mysqli_connect('xx', 'xx', 'xx', 'xx') or die ('Error connecting to MySQL server'); $sql = "SELECT * FROM players WHERE ('$search_by') LIKE ('$search') "; //problem is here^^?? $result = mysqli_query($dbc,$sql) or die("Error: " .mysqli_error($dbc)); Not sure, any help would be greatly appreciated. Hi All, I have the following Query: Code: [Select] $query = 'SELECT `BookingID`,`OfferID`, `name`, `OfferCount`,`OfferPrice` FROM `Offers_Finance` JOIN offers_details ON `OfferID` = `o_d_id` WHERE `BookingID` ="' .$bookerid. '"'; if ( !$result = $mysqli->query( $query ) ) { die( $mysqli->error ); } $field = $result->fetch_object(); This will return anywhere between 0 and 50 Rows of Data. For Each Row returned, I want to do the following: Quote echo '<tr>'; echo '<td>' . $field->name.'</td>'; echo '<td></td>'; echo '<td>£' . $field->OfferPrice.'</td>'; echo '<td></td>'; echo '<td>' . $field->OfferCount . '</td>'; echo '<td></td>'; echo '<td>£' . $field->OfferPrice * $field->OfferCount . '</td>'; echo '</td>'; echo '</tr>'; The problem I have is - how do I loop through the results returned from the query to output multiple rows? Sorry if this doesn't make much snese, I'm new to PHP and the whole web development world, but have been landed with finishing a project someone else started! If someone would be kind enough to turn this into a working example, it would help no end as I have about 20 of these things to figure out across the project! I have a Select statement that relies on two session variables to complete the statement. One variable, $egroup, supplies a column name. I cannot make the SELECT work. It works fine if I substitute the real name of one of the columns such as "egroup1", or "egroup6", but that's what the variable $egroup is for. Can anyone tell me where I'm wrong? I guess the answer is in the syntax, but I'm not very good at this and I've been on it for too long. Any help gratefully taken. Code: [Select] <?php $query1 = mysql_query("SELECT * FROM topics WHERE managerId='".$managerId."' AND "$egroup"= 1 ORDER BY title ASC"); ?> $sql=mysql_query("SELECT * FROM `buds` WHERE `level`<='$user_level' UNION SELECT * FROM `buds`, `unlocked_buds` WHERE buds.`id` = unlocked_buds.`bud_id` ORDER BY buds.`id` ASC") or die("A MySQL error has occurred.<br />Your Query: " . $sql . "<br /> Error: (" . mysql_errno() . ") " . mysql_error()); I have been trying to learn about UNION select statements. I ran the query above and got this response: Quote Error: (1222) The used SELECT statements have a different number of columns I think I know what the problem is, but not sure how to fix it. There is two columns, one is "buds" which holds the flowers seeds info. The seconds is "unlocked_buds" which just links the "id" from buds to "user_id" to the user table. Both buds and unlocked_buds are both 8 columns. What do I need to learn? //DATABASE CONNECTION VARIABLES $myserver ="localhost"; $myname = "myname"; $mypassword = "mypassword"; $mydb ="mygamedb"; /*SQL CONNECTION*/ // Create connection $conn = new mysqli($myserver, $myname, $mypassword, $mydb); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } else { //variables $username = $_POST["username"]; $password = $_POST["password"]; $ip = $_SERVER['REMOTE_ADDR']; //INSERT USER //prepare and bind $stmt = $conn->prepare("INSERT INTO Players (Username, Password, IP) VALUES (?, ?, ?)"); //bind parameters $stmt->bind_param("sss", $username, $password, $ip); //set parameters and execute $stmt->execute(); //close $stmt->close(); //FETCH ID $resultnews = mysql_query("SELECT * FROM Players WHERE Username ='$username'"); $rownews = mysql_fetch_array($resultnews); $user_id = $rownews["ID"]; }After having suffered an SQL injection into one of my sites, I figured it was time to overhaul it and use prepared statements. I am new to this. I figured out how to an INSERT with an example, but now I need to fetch an ID and cannot get it to work. Any help much obliged. All I need is just one good example. Looked all over the place, but all I get are insert examples, which is NOT what i need. Really need one with a select and fetch. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=322930.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=327011.0 What's the correct syntax for having a variable in a select statement? Here's an example of what I'm trying to do (after I'm already connected to the database). Code: [Select] $username = "thomas"; $query = mysql_query( "SELECT * from users WHERE username = $thomas" ); if( mysql_num_rows( $query ) > 0 ) { bla bla... It works if I don't put the WHERE part in, but I get an error if I use it, so I'm assuming I have the wrong syntax for using a variable in the select statement. here is some simple code for getting and displaying fata from a database Code: [Select] $sql="SELECT * FROM messages WHERE m_id = '".$id."'"; $result = mysql_query($sql); <table border='0' cellspacing="4"> while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<th>Message</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['message'] . "</td>"; echo "</tr>"; } now ive used that while loop to display those results how can i do that again without having a new SQL statement. i cant do 2 while loops because the first one has already got to the end of the amount of rows basically how can i have another while loop displaying those same results again? Hi Guys I don't know if this is possible but can someone point me in the right direction. I have a php function which takes two inputs and returns an output. for simplicity's sake let's say it's an addition function. What I want to do is use a mysql select statement to show all the rows from a database where field1 and field2 equal '3'. Here's the sort of thing I mean. function addNumbers($one,$two) { return $one + $two; } mysql_query("SELECT * FROM table WHERE 'addNumbers(field1,field2)' = '3'"); What I actually want to do is a lot more complex than this but I am trying to understand how to make the syntax work in simple terms first. Can anybody help? Many Thanks Dan I need to convert the following select statement to a pdo->query but have no idea how to get it working: SELECT t.id FROM ( SELECT g.* FROM location AS g WHERE g.start <= 16785408 ORDER BY g.start DESC, g.end DESC LIMIT 1 ) AS t WHERE t.end >= 16785408; Here's the code I'm trying: <?php $php_scripts = '../../php/'; require $php_scripts . 'PDO_Connection_Select.php'; require $php_scripts . 'GetUserIpAddr.php'; function mydloader($l_filename=NULL) { $ip = GetUserIpAddr(); if (!$pdo = PDOConnect("foxclone_data")) { exit; } if( isset( $l_filename ) ) { $ext = pathinfo($l_filename, PATHINFO_EXTENSION); $stmt = $pdo->prepare("INSERT INTO download (address, filename,ip_address) VALUES (?, ?, inet_aton('$ip'))"); $stmt->execute([$ip, $ext]) ; $test = $pdo->prepare("SELECT t.id FROM ( SELECT g.id FROM lookup AS g WHERE g.start <= inet_aton($ip) ORDER BY g.start DESC, g.end DESC ) AS t WHERE t.end >=inet_aton($ip)"); $test ->execute() ; $ref = $test->fetchColumn(); $ref = intval($ref); $stmt = $pdo->prepare("UPDATE download SET ref = '$ref' WHERE address = '$ip'"); $stmt->execute() ; header('Content-Type: octet-stream'); header("Content-Disposition: attachment; filename={$l_filename}"); header('Pragma: no-cache'); header('Expires: 0'); readfile($l_filename); } else { echo "isset failed"; } } mydloader($_GET["f"]); exit; It gives the following error: QuoteFatal error: Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '.144.181) ORDER BY g.start DESC, g.end DESC ) AS t WHERE t.end >=inet_aton(7' at line 1 in /home/foxclone/test.foxclone.com/download/mydloader.php:19 Stack trace: #0 /home/foxclone/test.foxclone.com/download/mydloader.php(19): PDO->prepare('SELECT t.id FRO...') #1 /home/foxclone/test.foxclone.com/download/mydloader.php(38): mydloader('foxclone40a_amd...') #2 {main} thrown in /home/foxclone/test.foxclone.com/download/mydloader.php on line 19 How do I fix this? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=312377.0 how do i handle single quotes in sql query Code: [Select] " SELECT name from phrase WHERE name='$stitle' ";this returns an error because the name contains single quotes like this: Johnson's. I'm able to use PHP-ODBC to read the tables in an MDB file, as well as the column names on the tables. But when I try to read data from a particular table, it fails (I don't get an error, instead the browser pops up a message asking if I want to save the file "mdbtest.php" which is 0 bytes in size)! Any idea what's wrong? Code: [Select] //THIS WORKS $conn = odbc_connect( 'TestDB', '', '' ); if ( !$conn) exit("Connection Failed: " . $conn); //STILL FINE HERE $sql = 'SELECT * FROM Customers'; //INCLUDING THIS LINE OF CODE CAUSES THE PROBLEM $rs = odbc_exec( $conn, $sql ); Is it possible to have a loop inside a mysql select statement? If yes, can someone please give me an idea. |