PHP - Retrieve Data From Database Question?

I have this code which uoploads and resizes the images into a folder without a problem. My problem is I am unable to view the Thumb or Full image which has uploaded to the folder and the database with the other data.  How do i correct this problem code below. Thanks

upload form and script
Code: [Select]

<?php
//database properties
$dbhost = 'localhost';
$dbuser = 'user';
$dbpass = 'pass';
$dbname = 'DB';

// make a connection to mysql here
$conn = mysql_connect ($dbhost, $dbuser, $dbpass) or die ("I cannot connect to the database because: " . mysql_error());
mysql_select_db ($dbname) or die ("I cannot select the database '$dbname' because: " . mysql_error());

/******** start function ********/

function errors($error){
if (!empty($error))
{
$i = 0;
echo "<blockquote>\n";
while ($i < count($error)){
echo "<p><span class=\"warning\">".$error[$i]."</span></p>\n";
$i ++;}
echo "</blockquote>\n";
}// close if empty errors

} // close function


// ----------------Create Smaller version of large image---------------------
function createthumbfull($src_filename, $dst_filename_full)
{
  // Get information about the image
        list($src_width, $src_height, $type, $attr) = getimagesize( $src_filename );

        // Load the image based on filetype
        switch( $type ) {
        case IMAGETYPE_JPEG:
                $starting_image = imagecreatefromjpeg( $src_filename );
                break;
        case IMAGETYPE_PNG:
                $starting_image = imagecreatefrompng( $src_filename );
                break;
        case IMAGETYPE_GIF:
                $starting_image = imagecreatefromgif( $src_filename );
                break;
        default:
                return false;
        }


// get the image to create thumbnail from
    $starting_image; 
// get image width
$width = imagesx($starting_image);
// get image height
    $height = imagesy($starting_image);
// size to create thumnail width
$thumb_width = 600;

    // divide iwidth by specified thumb size
    $constant = $width/$thumb_width;
// round height by constant and add t thumb_height
    $thumb_height = round($height/$constant, 0);


//create thumb with true colours
    $thumb_image = imagecreatetruecolor($thumb_width, $thumb_height);

//create thumbnail resampled to make image smooth
    imagecopyresampled($thumb_image, $starting_image, 0, 0, 0, 0, $thumb_width, $thumb_height, $width, $height);

$ran = rand () ;
$thumb1 = $ran.".jpg";

global $thumb_Add_full;
$thumb_Add_full = $dst_filename_full;
$thumb_Add_full .= $thumb1;

imagejpeg($thumb_image, "" .$dst_filename_full. "$thumb1");
} 



//-------------------- create thumbnail --------------------------------------------
//$src_filename = source of image
//$dst_filename_thumb = location to store final image
function createthumb($src_filename, $dst_filename_thumb)
{
    $size = getimagesize($src_filename); // get image size
   $stype = $size['mime']; //get image type : gif,png,jpg
   $w = $size[0]; // width of image
   $h = $size[1]; // height of image
   
   //do a switch statment to create image from right image type
   
   switch($stype) {
      //if image is gif create from gif
      case 'image/gif':
      $simg = imagecreatefromgif($src_filename);   
      break;
      //if image is jpeg create from jpeg
      case 'image/jpeg':
      $simg = imagecreatefromjpeg($src_filename);      
      break;
      //if image is png create from png
      case 'image/png':
      $simg = imagecreatefrompng($src_filename);      
      break;
      }

   
   $width = $w; // get image width   
    $height = $h; // get image height
   
   // size to create thumnail width
   $thumb_width = 150;
   $thumb_height = 150;
   
   //use true colour for image
   $dimg = imagecreatetruecolor($thumb_width, $thumb_height);
   $wm = $width/$thumb_width; //width divided by new width
   $hm = $height/$thumb_height; //height divided by new height
   $h_height = $thumb_height/2; //ass new height and chop in half
   $w_height = $thumb_width/2; //ass new height and chop in half
   
   //if original width is more then original height then modify by width
   if($w> $h) {
      $adjusted_width = $w / $hm; // add original width and divide it by modified height and add to var
      $half_width = $adjusted_width / 2; // chop width in half
      $int_width = $half_width - $w_height; // take away modified height from new width
      //make a copy of the image
      imagecopyresampled($dimg,$simg,-$int_width,0,0,0,$adjusted_width,$thumb_height,$w,$h);
      
      //else if original width is less or equal to original height then modify by height
      
   } elseif(($w <$h) || ($w == $h)) {
      $adjusted_height = $h / $wm; // diving original height by modified  width
      $half_height = $adjusted_height / 2; // chop height in half
      $int_height = $half_height - $h_height; // take away modified height from new width
      //make a copy of the image
      imagecopyresampled($dimg,$simg,0,-$int_height,0,0,$thumb_width,$adjusted_height,$w,$h);
   } else { // don't modify image and make a copy
      imagecopyresampled($dimg,$simg,0,0,0,0,$thumb_width,$thumb_height,$w,$h);
   }
      
   $ran = "thumb_".rand (); // generate random number and add to a string   
   $thumb2 = $ran.".jpg"; //add random string to a var and append .jpg on the end
   
   global $thumb_Add_thumb; //make this var available outside the function as it will be needed later.
   $thumb_Add_thumb = $dst_filename_thumb; // add destination
   $thumb_Add_thumb .= $thumb2; // append file name on the end
      
   //actually create the final image
    imagejpeg($dimg, "" .$dst_filename_thumb. "$thumb2");    
}

/********end functions ***********/

// if form submitted then process form
if (isset($_POST['submit'])){

// check feilds are not empty
$imageTitle = trim($_POST['imageTitle']);
if (strlen($imageTitle) < 3 || strlen($imageTitle) > 255) {
$error[] = 'Title must be at between 3 and 255 charactors.';
}

// check feilds are not empty or check image file size
if (!isset($_FILES["uploaded"])) {
$error[] = 'You forgot to select an image.';
}

// check feilds are not empty
$imageDesc = trim($_POST['imageDesc']);
if (strlen($imageDesc) < 3) {
$error[] = 'Please enter a description for your image.';
}

// location where inital upload will be moved to
$target = "productimages/" . $_FILES['uploaded']['name'] ;


// find the type of image
switch ($_FILES["uploaded"]["type"]) {
case $_FILES["uploaded"]["type"] == "image/gif":
move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target);
    break;
case $_FILES["uploaded"]["type"] == "image/jpeg":
    move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target);
    break;
case $_FILES["uploaded"]["type"] == "image/pjpeg":
    move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target);
    break;
case $_FILES["uploaded"]["type"] == "image/png":
    move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target);
    break;
case $_FILES["uploaded"]["type"] == "image/x-png":
    move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target);
    break;

default:
    $error[] = 'Wrong image type selected. Only JPG, PNG or GIF accepted!.';
}

// if valadation is okay then carry on
if (!$error) {

// post form data 
   $imageTitle     = $_POST['imageTitle'];
   $imageDesc     = $_POST['imageDesc'];
   
   //strip any tags from input
   $imageTitle   = strip_tags($imageTitle);
   $imageDesc   = strip_tags($imageDesc);
   
   
   // add slashes if needed
   if(!get_magic_quotes_gpc())
{ 
$imageTitle   = addslashes($imageTitle);
$imageDesc   = addslashes($imageDesc);
 }
   
   // remove any harhful code and stop sql injection
   $imageTitle = mysql_real_escape_string($imageTitle); 
   $imageDesc = mysql_real_escape_string($imageDesc); 
   
  
//add target location to varible $src_filename 
$src_filename = $target;
// define file locations for full sized and thumbnail images
$dst_filename_full = 'productimages/';
$dst_filename_thumb = 'productthumb/';

// create the images
createthumbfull($src_filename, $dst_filename_full); //call function to create full sized image
createthumb($src_filename, $dst_filename_thumb); //call function to create thumbnail image
// delete original image as its not needed any more.
unlink ($src_filename);


// insert data into images table
$query = "INSERT INTO table (imageTitle, imageThumb, imageFull, imageDesc) VALUES
  ('$imageTitle', '$thumb_Add_thumb', '$thumb_Add_full', '$imageDesc')";
  $result  = mysql_query($query) or die ('Cannot add image because: '. mysql_error());
 
// show a message to confirm results
echo "<h3 align='center'> $imageTitle uploaded</h3>";
 
}
}


//dispaly any errors
errors($error);
?>

<form enctype="multipart/form-data" action="" method="post">
<fieldset>
<legend>Upload Picture</legend>
<p>Only JPEG, GIF, or PNG images accepted</p>
<p><label>Title<br /></label><input type="text" name="imageTitle" <?php if (isset($error)){ echo "value=\"$imageTitle\""; }?> /></p>

<p><label>Image<br /></label><input type="file" name="uploaded" /></p>

<p><label>Description<br /></label><textarea name="imageDesc" cols="50" rows="10"><?php if (isset($error)){ echo "$imageDesc"; }?></textarea></p>

<p><label>&nbsp;</label><input type="submit" name="submit" value="Add Image" /></p>

</fieldset>
</form>

view data
Code: [Select]

<?php 
 
 // Connects to your Database 
 mysql_connect("localhost", "user", "pass") or die(mysql_error()) ; 
 mysql_select_db("DB") or die(mysql_error()) ; 
 
 //Retrieves data from MySQL 
 $data = mysql_query("SELECT * FROM table") or die(mysql_error());  //Puts it into an array 
 while($info = mysql_fetch_array( $data )) 
 { 
 ?>
 
<?php echo "<img src=http://www.web.com/productimages/" .$info['imagefull'] ." > <br>"; ?>
<?php echo "<img src=http://www.web.com/productthumb/" .$info['imageThumb'] ." > <br>"; ?>


<?php echo "<b>imageTitle:</b> ".$info['imageTitle'] . "<br> "; ?>
<?php echo "<b>imageDesc:</b> ".$info['imageDesc'] . " <hr>"; ?>
 
<?php  }?>

I AM WORKING ON A PROJECT , I NEED YOUR HELP.  I WANT TO USE EXISTING SRC OF IFRAME + RETRIVED VALUE FROM DATABASE INTO IFRAME

This is my data.php to retrive values from database into iframe without refresh web page.

<?php
	$conn = new mysqli('localhost', 'root', '', 'x');
if ($conn->connect_error) {
    die("Connection error: " . $conn->connect_error);
}
$result = $conn->query("SELECT number1 FROM users");
if ($result->num_rows > 0) {
    while ($row = $result->fetch_assoc()) {
        echo $row['number1'] . '<br>';
    }
}
?>

FOLLOWING IS INDEX FILE

<?php include('data.php') ?>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
	</head>
<body>
    <div id="show"></div>
    <script type="text/javascript" src="jquery-3.1.1.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function() {
            setInterval(function () {
                $('#show').load('data.php')
            }, 1000);
        });
    </script>
	    <iframe id="w3" src="DATABASE RETRIVED VALUE" height="80px" width="300px" frameborder="0" style="border: 0; width:300px; height:80px; background-color: #FFF;"></iframe>
    </body>
</html>

 

INDEX FILE CODES CAN SUCCESSFULLY RETRIVE VALUES FROM DATABASE BUT, I WANT TO STORE IT IN IFRAME SRC .

VAR= URLS = 'HTTP://WWW.GOOGLE.COM'

IFRAME SRC WILL BE VAR URLS + RETRIEVED VALUE FROM DATABASE

 

 

 

CAN ANYONE TELL ME WHAT i AM DOING WRONG. I WANT TO RETRIEVE THE VERY FIRST RECORD IN MY DATABASE WHEN THE CODE EXECUTE IT ONLY SHOWS THE LAST RECORD IN THE DATABASE

<?PHP
$thisMonth = date('M');
$thisDay = date('j');
$eventMonth = array();
$eventDay = array();
$eventTime = array();
$eventName = array();
$eventLocation = array();
$dbMonth="";
$dbDay="";

$i=0;

$conn = odbc_connect('eventsDB','','');

$sql= "SELECT month,day, time, event,location FROM Events";
$rs="$conn,$sql";
if (!$conn)
{
   exit("Connection Failed: " . $conn);
}
 $rs=odbc_exec($conn,$sql);

if(!$rs)
{
   exit("Error in SQL");
}
 echo "DATABASE OPEN";
 

while($i<3)
{
   $dbMonth= odbc_result($rs,"month");
   echo $eventMonth[$i]=odbc_result($rs,"month")."\n"; 
   
   
   if($dbMonth<>$thisMonth)
   {
      odbc_fetch_row($rs);   
   
   }
                echo $eventMonth[$i]=odbc_result($rs,"month")."\n"; 
               echo $eventDay[$i]=odbc_result($rs,"day")."\n";
               echo $eventTime[$i]=odbc_result($rs,"time")."\n";
               echo $eventDay[$i]=odbc_result($rs,"event")."\n";
               echo $eventLocation[$i]=odbc_result($rs,"location")."\n";
               $i++;
               odbc_fetch_row($rs);
            
                  
         
   

echo $i;
} //ends while loop
odbc_close($conn);
?>

Hi,
Im trying to retrieve HTML from a mysql database but nothing i've tried seems to work.
The HTML im trying to retrieve is an iframe with a link and styles (code from amazon associates). Im trying to display links to specific products on amazon from the product page on my site. All data about the product is retrieved from the database so i have code to select the amazon link row in my database table but i cant get it to display. It says the html isnt a string so i cant echo it, fair enough. I have tried using the following code:
Code: [Select]
$get_buylink_sql = "SELECT mobo_buylink FROM mobo WHERE mobo_id = $mobo_id";
$get_buylink_res = mysqli_query($mysqli, $get_buylink_sql)
or die(mysqli_error($mysqli));

while ($buylink = mysqli_fetch_array($get_buylink_res)) {
echo"<iframe src=\"".$buylink."\" style=\"width:120px;height:240px;\" scrolling=\"no\" marginwidth=\"0\" marginheight=\"0\" frameborder=\"0\"></iframe>";
}

mysqli_free_result($get_buylink_res);

mysqli_close($mysqli);I have also tried putting the whole iframe code in the database which didnt work either.
The mobo_id variable works fine for retrieving the rest of the data and i need to get the amazon link from the same record.

I hope i've put this in a way you can understand, but if not i'll try and explain better and give you a link to my site if needed.

Thanks,
Alex

hi,
i have a form that requires image to be uploaded.
i know how to store the form values in a database but i don't know how to store the image into the database.
i want the user to upload picture and preview the data provided review (including the image) before submitting to the database.

thanks

Code: [Select]
<?php echo 
  $row_Recordset1['name']; 
      ?>
i want to convert the name in to like

<a href=main.php?name= $row_Recordset1['name']  >>

in databse i has 3 name
Steve
Mark
Lisa

i want that names into link like main.php?name=mark and so on
how to do it
help me
h
   

Hello people,
I have created an application in Code Charge where my site users can login and play games online.The game code is run via flash and html. The Game has 5 stages and from a page in my application called transfertogame.php , i transfer them to the game page. Now i want to be able to track each players progress via database so that when they log back in and they get to the transfertogame.php page, it can check the page they were on before and immediately take them to the page without starting from page 1. Any help will be appreciated as i am very poor with php scripting
This is the session ID i guess is being used from my application page

//Initialize Method @4-537EA73F
function Initialize()
{

if(!$this->Visible)
return;

$this->ds->Parameters["sesUserID"] = CCGetSession("UserID");
}
//End Initialize Method

//Validate Method @4-7E1FC38C
function Validate()
{
$Validation = true;
$Where = "";
$this->CCSEventResult = CCGetEvent($this->CCSEvents, "OnValidate");
return (($this->Errors->Count() == 0) && $Validation);
}
//End Validate Method

I have some php code on view invoice and it's getting all the data I need to from three database tables but for some reason it's not getting the data for one specific column and unsure why

I have done a echo sql and it is echoing the sql query ok and have ran the sql query in phpmyadmin and is displaying the column in phpmyadmin that is not displaying on the php page so am bit confused, below is the coding I have. I took out a lot of it and tried to keep to the relevant parts

<?php
$sql = "SELECT t1.id, t1.invoice_number, DATE_FORMAT(t1.invoice_date,'%d/%m/%Y') AS invoice_date, t1.user_id, t2.invoice_number, t2.service_name, t2.service_price, t3.user_id, t3.customer_name, t3.customer_phone, t3.customer_email, t2.service_name, t2.service_price, t1.invoice_total, t1.balance, t1.notes, DATE_FORMAT(t1.payment_date,'%d/%m/%Y') AS payment_date, t1.payment_method
FROM invoices as t1
LEFT JOIN invoice_products as t2
ON t1.id = t2.invoice_id
LEFT JOIN users as t3
ON t1.user_id = t3.user_id
WHERE t1.user_id = '".$_SESSION['user_id']."' and t1.id = '".$_GET['id']."'";

$result = mysqli_query($connect, $sql);

                if(mysqli_num_rows($result) > 0)
                {
                if($row = mysqli_fetch_array($result))  
                {
                ?>

                Notes: <?php echo $row['notes'];?>

                <?php
                    }
                    }
                    ?>

 

Hi

I have coded a drop down menu with php and i am trying to retrieve the data when a user select a option from the menu and the data is retrieved from the database. So far i have tried and nothing is displaying when i tried to process the php form.

Sales.php Page

<form action="saleprocess.php" method="GET">
<?php
echo 'Product Model:';
$query="SELECT * FROM products";
/* You can add order by clause to the sql statement if the names are to be displayed in alphabetical order */
$result = mysql_query ($query);
echo "<select name=product_model value=Select>Product Model</option>";
// printing the list box select command
while($rows=mysql_fetch_array($result)){//Array or records stored in $nt

echo "<option name=product_model value='.$rows[product_id].'>$rows[product_model]</option>";
/* Option values are added by looping through the array */
}
echo "</select><br>";
?>
<input type='submit' name='submit' value='Create'></input> <br>
</form>

********************************************************************************
Salesprocess.php page

<?php
include("connect.php");

if(isset($_GET['product_id'])){

$product_id = $_GET['product_id'];


$query = mysql_query("SELECT * FROM products WHERE product_id= $product_id");

while($rows = mysql_fetch_assoc($query))
{
echo 'Product Model<br>';
echo $rows['product_id'];
echo $rows['product_model'];


}
}
?>

Muchly appreciated if someone can help me

I insert multiple id from my checkbox to mysql database using php post form. in e.x i insert id (checkbox value table test) to mysql. no i need to any function for retrieve data from mysql and print to my page with my e.x output.(print horizontal list name of table test where data = userid)

my checkbox value ( name table is test ) :
Code: [Select]
01 ---id----- name    ----
02 ---1 ----- test1   ----
03 ---2 ----- test2   ----
04 ---3 ----- test3   ----
05 ---4 ----- test4   ----
06 ---5 ----- test5   ----
07 ---6 ----- test6   ----
08 ---7 ----- test7   ----
09 ---8 ----- test8   ----
10 ---9 ----- test9   ----
mysql data Insert ( name of table usertest ):

Code: [Select]
1 ---id----- data    ---- userid -----
2 ---1 ----- 1:4:6:9 ---- 2      -----
3 ---2 ----- 1:2:3:4 ---- 5      -----
4 ---3 ----- 1:2     ---- 7      -----
example outout : ( print horizontal list name of table test where data = userid )


print?
Code: [Select]
1 user id 2 choise : test1 - test4 - test6 - test9
Thanks

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=322859.0

Hi folks,

Complete No0b here when it comes to PHP and MySQL.

I am in the middle of creating a PHP website. What I want to do is have the contents of a page in a MySQL table and have PHP gather the page content and display it on the page.
Here is what I have in my home.tpl file:

Code: [Select]
<?php $query  = "SELECT home, FROM $database_name";
$result = mysql_query($query); ?>
And, in my index.php I simply call that home.tpl to display the data by using:

Code: [Select]
<?php include 'templates/default/home.tpl'; ?>
Now, all I get is a blank page on index.php. Is there something else I should be doing?
Remember, I am a complete No0b!

Thanks folks.

Hi all,

I have the following code that generates a table of results from a MySQL query:

$i=1;
        while($arr = mysql_fetch_array($result, MYSQL_NUM))
        {
            $table .= "<tr>" 
                              ."<td width='5px';><input type='checkbox' name='transcheck".$i."'></td>"
                              ."<td id='parent".$i."A'>".$arr[0]."&nbsp;".$arr[1]."</td>"
                              ."<td id='parent".$i."B'>".$arr[2]."</td></tr>"
                              ."<tr style='display:none'><input type='hidden'; name='transemail".$i."'; value='".$arr[9]."'></tr>";
        $i++;
        }
        $table .= "</table>";
echo $table;


As you can see it generates a table containing (amongst other things):
checkboxes:       transcheck1,2........9...etc.
hidden inputs:    transemail1,2........9...etc.

This table is inside a form, so that the above gets posted to another php file. What I now want to do in this 2nd php file, is to retrieve all the checkboxes and hidden inputs and then to display the values of the hidden inputs, where the corresponding checkbox has been checked. So e.g. if transcheck1, transcheck3 and transcheck12 have been checked, then I want to display transemail1, transemail3 and transemail12.

I can see that this should be relatively straightforward, but I'm fairly new to this stuff, could someone pls help me out?

Thanks!

I want to use session to do a query and will I be able to do this?

I have a session that was gathered from login and now i was to use this session to do a query

If Yes, How?

I m trying to fetch a image from mysql (blob) with header..here is my coding..."<?php
include("db.php");

$query=mysql_query("select * from table where id='3' ");
$row=mysql_fetch_array($query);
$r=$row['image'];
header("content-type:image");
echo $r;

?>"

i want to fetch another fields from the database....but when i try to echo another fields...the page shows error or it does not echo other fields of database....please help me...how can i resolve it...i want to fetch other fields from database,like'username'password'firstname'lastname and image...thanks in advance...