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PHP - Search Tags From Mysql Database
Hello, so i made table with Tags row which is Text(126).. and idea is to put text like "PHP, MySQL, Forum, Blog" etc etc...
I have problem searching tags my search code:
$requestedtag = $con->real_escape_string($_GET['tag']);
$sql = "SELECT * FROM images WHERE tags = '$requestedtag' ORDER BY ID DESC LIMIT 12";
$result = $con->query($sql);
if ($result->num_rows > 0)
{
while($row = $result->fetch_assoc()) {
$image_id = $row["ID"];
$image_title = $row["Title"];
$image_url = $row["ImgURL"];
$image_tags = $row["Tags"];
echo '<div class="col-3"><div class="thumb"><a href="/image.php?id='.$image_id.'" title="'.$image_title.'"><img src="'.$image_url.'"></img></a></div></div>';
}
}
But it doesnt return anything. I think the problem is that row["Tags"]; is divided by "," from tags and i should split it somehow but i dont really know what to do...
Similar TutorialsSay I have the following text stored in a MySQL database... Code: [Select] <b>Classic Quote from movie</b> and I retrieve it into a variable called $text, how do I properly echo that so that it keeps the bold tags and actually display the text "Classic quote from movie" in BOLD? I'm doing something wrong somewhere along the line (simply doing "echo $text;") because it displays on the page as... Code: [Select] <b>Classic Quote from movie</b> Instead of... Classic Quote from movie Any info on properly storing and echoing back HTML would be very appreciated. Need some help I have 2 tables in a database and I need to search the first table and use the results from that search, to search another table, can this be done? and if it can how would you recommend that I go about it? Thanks For Your Help Guys! Hi. I have a database named 'Forums' with a table named 'forumlist'. The fields in the table are 'id', 'name', 'link', and 'keys'. I am trying to search the database in either the 'name' or 'keys' field and display the matches. I am getting this error: Parse error: syntax error, unexpected T_STRING, expecting ']' in C:\xampp\htdocs\search3.php on line 51 (The define fields) <html> <head> <title>My Forum Search</title> <style type="text/css"> table { background-color: #CCC } th { width: 150px; text-align: left; } </style> </head> <body> <h1>Forum Search</h1> <form method="post" action="search3.php"> <input type="hidden" name="submitted" value="true" /> <label>Search Category: <select name="category"> <option value="keys">Keyword</option> <option value="name">Name</option> </select> </label> <label><input type="text" name="criteria" /></label> <input type="submit" /> </form> <?php if (isset($_POST['submitted])) { DEFINE ('DB_USER', 'root'); DEFINE ('DB_PSWD', '******'); DEFINE ('DB_HOST', 'localhost'); DEFINE ('DB_NAME', 'Forums'); $dbcon = mysqli_connect(DB_HOST, DB_USER, DB_PSWD, DB_NAME); $category = $_POST['category']; $criteria = $_POST['criteria']; $query = "SELECT * FROM forumlist WHERE $category LIKE '$criteria'"; $result = mysqli_query($dbcon, $query) or die ('Error retrieving data') echo "<table>"; echo "<tr> <th>Name</th><th>Link</th> </tr>"; while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) { echo "<tr><td>"; echo $row['name']; echo "</td><td>"; echo $row['link']; echo "</td></tr>"; } echo "</table>"; } // end of main if state ?> </body> </html> Thanks in advance Hi, I'm am trying to use a search engine that search's for a username in the database and displays the information back. I have searched for a script but none of them has helped me. I have tried to use this without any luck: mysql_connect("localhost", "", "") or die(mysql_error()); mysql_select_db("dbsystem") or die(mysql_error()); $todo=$_POST['todo']; if(isset($todo) and $todo=="search"){ $search_text=$_POST['search_text']; $type=$_POST['type']; $search_text=ltrim($search_text); $search_text=rtrim($search_text); if($type<>"any"){ $query="select * from users where name = '$search_text'"; }else{ $kt=split(" ",$search_text);//Breaking the string to array of words // Now let us generate the sql while(list($key,$val)=each($kt)){ if($val<>" " and strlen($val) > 0){$q .= " name like '%$val%' or ";} }// end of while $q=substr($q,0,(strlen($q)-3)); // this will remove the last or from the string. $query="select * from users where $q "; } // end of if else based on type value echo $query; echo "<br><br>"; $nt=mysql_query($query); echo mysql_error(); while($row=mysql_fetch_array($nt)){ echo "$row[name]<br>"; } // End if form submitted }else{ echo "<form method='post' action=''><input type='hidden' name='todo' value='search' /> <input type='text' name='search_text' /><input type='submit' value='Search' /><br> <input type='radio' name='type' value='any' checked />Match any where <input type='radio' name='type' value='exact' />Exact Match </form> "; } I will be grateful if you can help with this. I'm using some code to create a select menu of a fieldname of data I have in a mysql database : Code: [Select] <?php mysql_connect('localhost' , 'dbname', 'password'); mysql_select_db('dbname'); $result=mysql_query("SELECT * FROM Persons"); if(mysql_num_rows($result)>0) { ?> <select name="Persons"> <?php while($rows=mysql_fetch_array($result)){ ?> <option value="<?php echo $rows['id']; ?>"> <?php echo $rows['FirstName']; ?></option> <?php } ?> </select> What I would like to do is to elevate this into a jump menu form so that if the user selects an item from my form they are taken to a results page showing the full row of data from the database. Basically a search form containing items from the database they can choose to see more details on. eg. In my example you select a persons name and then you are taken to a results page which displays the details of that person from the database. Problem is I don't know how to do this and have been trawling around for a couple of days to find a solution (sorry I'm new to php). I would appreciate some help or a working example would be great of : 1/ A working dynamic jump menu 2/ The page that would process the form 3/ The results page displaying the data I have selected. Thank you for your time... I have a search set up to search a table for the text entered in a textbox, I have two columns in the table, one with the first name of people, and the second with their last names, I am wondering how I can search both, so for instance: I type in the search field: Roger Smith in the database it would look like: First_name-----|-----Last_name -------------------|------------------- Roger------------|-------Smith my current query is: Code: [Select] $query = mysql_query("SELECT * FROM users WHERE fname LIKE '%$find%' OR lname LIKE '%$find%'"); But if I type both parts of the name it doesn't return anything. works fine if I just search for "Roger" OR "Smith". Say a user puts in a support request, and for every request it generates a unqiue string, and enters it into the database. Ok, now say there is a text field, when the user enters their unique string and it finds a match, it displays the data along with it. How can I accomplish this? Im kind of new to mysql, but I know basic SQL. Would be great if somebody could point me in the right direction! Thanks This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=326703.0 I have a standard form that displays users current data from a mysql database once logged in(code obtained from the internet). Users can then edit their data then submit it to page called editform.php that does the update. All works well except that the page does not display the updated info. Users have to first logout and login again to see the updated info. even refreshing the page does not show the new info. Please tell me where the problem is as i am new to php.
my form page test.php
<?PHP
require_once("./include/membersite_config.php");
if(!$fgmembersite->CheckLogin())
{
$fgmembersite->RedirectToURL("login.php");
exit;
}
?>
<form action="editform.php?id_user=<?= $fgmembersite->UserId() ?>" method="POST">
<input type="hidden" name="id_user" value="<?= $fgmembersite->UserId() ?>"><br>
Name:<br> <input type="text" name="name" size="40" value="<?= $fgmembersite->UserFullName() ?>"><br><br>
Email:<br> <input type="text" name="email" size="40" value="<?= $fgmembersite->UserEmail() ?> "><br><br>
Address:<br> <input type="text" name="address" size="40" value="<?= $fgmembersite->UserAddress() ?> "><br><br>
<button>Submit</button>
my editform.php
<?php
$con = mysqli_connect("localhost","root","user","pass");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
mysqli_query($con,"UPDATE fgusers3 SET name = '".$_POST['name']."', email= '".$_POST['email']."', address= '".$_POST['address']."' WHERE id_user='".$_POST['id_user']."'");
header("Location: test.php");
?>
I have code to search a database of members, I can search by lastname but having a little problem. I want to be able to search by lastname starting with the first letter. (ie: a or b or c or d and so on). As it is right now I can only search by first letter of last name if I add % to the search (ie: a% b% c%) will give me all members with the last names starting with the approiate letter designation. I'm not sure how to handle this, any help would be appreciated. Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <center><table cellspacing="10" cellpadding="10" width="750" border="0"> <h4>Search</h4> <form name="search" method="post" action="<?php $PHP_SELF?>"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="lname">Last Name</option> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <?php // check to see if anything is posted if (isset($_POST['find'])) {$find = $_POST['find'];} if (isset($_POST['searching'])) {$searching = $_POST['searching'];} if (isset($_POST['field'])) {$field = $_POST['field'];} //This is only displayed if they have submitted the form if (isset($searching) && $searching=="yes") { echo "<h4>Results</h4><p>"; // If they did not enter a search term we give them an error if (empty($find)) { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "root", "1910") or die(mysql_error()); mysql_select_db("cmc_member") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); // Now we search for our search term, in the field the user specified $results = mysql_query("SELECT * FROM members WHERE upper($field) LIKE'$find'"); // And we display the results if($results && mysql_num_rows($results) > 0) { $i = 0; $max_columns = 3; while($row = mysql_fetch_array($results)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; // make sure we have a valid product ALIGN='CENTER' if($fname != "" && $fname != null) echo "<td ALIGN='CENTER'><FONT COLOR='red'><b>$fname $lname</b></FONT><br> $address <br> $city $state $zip <br>$phone<br><a href=\"mailto: $email\">$email</a><br></td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i < $max_columns) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches = mysql_num_rows($results); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </tr> </table></center> </body> </html> I am developing a intranet forum in Php and MySQL and I am using ajax to display searched results on the same page but right now I am using query LIKE text% to search in database which is slower. but I want to make it fast search engin which can parse *,+ and show result. Since I am using ajax i am not able to use free search engin,so if possible pls provide a complete solution The result pages is supposed to have pagination like google help me please
Hi all How do I modify the below code to search multiple tables in mySQL database? $query = "select * from store_items where description like \"%$trimmed%\" or title like \"%$trimmed%\" or dimensions like \"%$trimmed%\" order by id ASC"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); It is for a search function and I need it to search another table called 'about_text' and 'faq_text' Thanks Pete So today I thought I'd try my hand at building a nice little search script for my site in progress. I haven't had any real success with this previously, but I'm trying to amend that. I've produced this search script which should take the user's search request, call information from the 'ad' database - it contains all the advertisement information (name,images,tags etc.) - compare it to the 'name' and 'tag' fields of the database and display any matching results. I'm here of course because this is not working as planned. There are no errors popping up, the script just isn't displaying results when it should be. Searches that use keywords featured in tags do not produce any results. Anyone have any idea why this script doesn't produce any results? SQL 'ad' Table: Code: [Select] CREATE TABLE IF NOT EXISTS `ad` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(300) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL, `text` varchar(600) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL, `apic` varchar(300) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL, `usr` varchar(100) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL, `tags` mediumtext CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL, PRIMARY KEY (`id`), KEY `usr` (`usr`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=9 ; PHP script: Code: [Select] <?php include 'connect.php'; session_start(); $_SESSION['username']; if(!(isset($_SESSION['login']) && $_SESSION['login']!= " ")){ header("Location: login.php"); } $username = $_SESSION['username']; $tablename = 'ad'; $search = stripslashes($_POST['search']); $search = mysql_real_escape_string($search); $search = trim($search); if (isset($search)) { $sql = " SELECT * FROM $tablename"; $result = mysql_query($sql) or die (mysql_error()); } else header("Location:search_err.php"); if (mysql_num_rows($result) <0) { header("Location:search_err.php"); } $ad_data = "Results for: " .$search.""; $x=1; while($ads = mysql_fetch_array($result) && $x <= mysql_num_rows($result)) { $ad_name = $ads['name']; $ad_text = $ads['text']; $ad_pic = $ads['apic']; $ad_usr = $ads['usr']; $ad_tags = $ads['tags']; if(stristr($ad_name, $search)) { $ad_data = "<a href = ad_page.php>". $ad_name ."</a>"; $xi=1; } else { $xi=0; } if(isset($xi) && $xi == 1) { $ad_tags_exp = explode(',',$ad_tags); $fi = 0; while($fi = 0) { if($ad_tags_exp[$fi] == $search) { $fi = 1; $ad_data = $ad_data = "<a href = ad_page.php>". $ad_name ."</a>"; } } } $x++; } echo $ad_data; ?> For a long time, I think I have been using heading tags wrong on websites.
They always show like this on Google.
Websitename websitename.com/category?name=mystery Posted by Night Flyer; 7 days ago; 5 views. « first; « prev; 1 of 1; next »; last ». Contact Us; @ 2014 websitename Inc. All Rights Reserved.As you can see, Google takes all the heading tags on my page and puts them in the description of the search result. So I have finally come to the conclusion that I should not be using heading tags for those things. Am I correct on that? I am using html5 and all the pages have h2 headings as titles. They all show up in google search results fine. The only thing that doesn't show up fine are some of the descriptions under each heading. Some meta descriptions show up fine under the correct heading title, while rest shows ALL the heading tags AS description under each search result.
For eg.
Cars
www.mywebsite.com/category?id=5&name=cars Hi Guys Whats the easiest way to store tags in a database from a php form? If I have a text field called tags, and each tag is comma seperated how do I process the data? I have a table called tags, with 3 fields, tag_id, post_id and tag Basically how would I basically turn this input: a tag, b tag, c tag from a form field to tag_id cat_id tag 1 dont worry about me, i can work this out! tag a 2 dont worry about me, i can work this out! tag b 3 dont worry about me, i can work this out! tag c Many Thanks At the moment I am creating a search function for my website. The approach I have in mind is a pseudo-PHP database. To give an example: A HTML form will submit the results to a PHP file. HTML FORM - Colour: Black PHP RESULT PAGE - if ($_POST['color'] == 'Black') {readfile("./products/black/*.html");} HTML FORM - Price: <$50 PHP RESULT PAGE - if ($_POST['Price'] == '<$50') {readfile("./products/less50/*.html");} The problem here is if there is an item that is black and costs less than $50, then its going to be listed twice. There is probably some code I can write to ommit the listing of duplicate entries, but it is probably going to be messy, so I am wondering if its better to use a centralized MySQL database, rather than a pseudo-PHP database? I've never used MySQL and don't know much about it and this is my first real attempt at using PHP. I have a tag column in the table of posts. I store tags as "tag1,tag2,tag3,...". When displaying tags in the post, I explode to have an array. Everything is OK, but I cannot create a tags cloud; as I need to have the occurrence of each tag to increase the font. What is a practical trick to create tag clouds? I think the common method is to build a table for post tags and store each single tag in a separate cell. But I hope to keep my database tidy. |
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