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PHP - Creating A Dynamic Table With 5 Columns Per Row
Hello,
I have this very frustrating problem
I'm trying to make a dynamic table with only 5 columns per row. So every 5 items, I need a new row. I have tried many different examples with no success. What is the best way to approach this? Here is what I am working with, this doesn't show what I have tried, just what I am working with at the moment which of course, just outputs it one column per row. http://www.mesquitew.../inc-legend.php
// Lets parse the data
$entries = simplexml_load_file($data);
if(count($entries)):
//Registering NameSpace
$entries->registerXPathNamespace('prefix', 'http://www.w3.org/2005/Atom');
$result = $entries->xpath("//prefix:entry");
foreach ($result as $entry):
$event = $entry->children("cap", true)->event;
// Set the alert colors for the legend
include ('../inc-NWR-alert-colors.php');
// Lets creat some styles for the list
$spanStyle = "background-color:{$alertColor};border:solid 1px #333;width:15px;height:10px;display:inline-block;'> </span><span style='font-size:12px;color:#555;";
$legend .= "<table>";
$legend .= "<tr>";
$legend .= "<td> <span style='$spanStyle'> $event</span></td>";
$legend .= "</tr>";
$legend .= "</table>";
endforeach;
endif;
echo $legend;
-Thanks!
Similar TutorialsHello guys. I'm kinda new to PHP, I've been understanding everything so far. I have trouble with "imagestring" What I want is to query a row in MySQL. I want to display some of that info in the image. It's not working properly. Here's the code: <?php $imagepath="css/images/dog.jpg"; $image=imagecreatefromjpeg($imagepath); $imgheight=imagesy($image); $color=imagecolorallocate($image, 255, 255, 255); include("config.php"); $result = mysql_query("SELECT * FROM playerinfo WHERE Level > 0 ORDER BY Level DESC", $connect); while($myrow = mysql_fetch_row($result)) { // Not working properly. imagestring($image, 5, 50, $imgheight-50, $myrow[0], $color); } // This line works like it should: //imagestring($image, 5, 50, $imgheight-50, "Using it like this works!", $color); header('Content-Type: image/jpeg'); imagejpeg($image); ?> Any help will be GREATLY appreciated it. Thanks! Hi Everyone I found some code to decrease the writing of $_POST variables especially on big forms, but I cannot seem to get it to work: I am trying to get the $_POST variables from this: Code: [Select] <?php $callsign = $_POST['mf_callsign']; $surname = $_POST['mf_surname']; $firstnames = $_POST['mf_firstnames']; $knownas = $_POST['mf_knownas']; $rsaid = $_POST['mf_rsaid']; $birthdate = $_POST['mf_birthdate']; //more code [code] to this (see //Create $_POST Variables section) [code] <?php //Initailise Database first mysql_connect ("localhost", "***", "***") or die ('I cannot connect to the database because: ' .mysql_error()); mysql_select_db ("***"); ========================= //Create $_POST Variables foreach($_POST as $inputKey=>$inputValue): //find all form fields starting with 'mf_' if((strstr($inputKey,'mf_') === true)): $inputKey = mysql_real_escape_string($inputValue); endif; endforeach; ========================= //Then do the Insert into the Table $query="INSERT INTO personal_details (callsign, surname, firstnames, knownas, rsaid, birthdate)Values ('$mf_callsign', '$mf_surname', '$mf_firstnames', '$mf_knownas', '$mf_rsaid', '$mf_birthdate')"; mysql_query($query) or die ('Error Inserting Data into Database'); //If Insert Successful, Goto next Form header("Location: contactdetails.html"); die; ?> The //Create $_POST Variables section is not correct as it is not setting the variables correctly. If I go back to the old way and use that ($callsign = $_POST['mf_callsign'] it inserts no problem. What Am I doing wrong? Regards Allen This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=342341.0 Hi there,
I have a table in a MySQL database where I keep a list of user privileges. I am trying to create variables where the name of variable matches the privileges in the table.
This is also known as variable variables (I think).
EDIT (17/07/2014 04:02 PM): This might be a better way to describe what I'd like, so if the value from the table is admin_panel I'd like to dynamically create a variable with that name.
I have created a code so far, but all I seem to be getting is a list of Notice errors telling me that the variable is undefined. (I have supplied a list of errors a bit further down the post).
Here is the code:
<?php
$host = "localhost";
$account = "***";
$password = "****";
$dbname = "****";
$connect = mysql_connect($host,$account,$password) or die("Unable To Connect");
$db = mysql_select_db($dbname,$connect) or die("Unable To Select DB");
$perm_query = "SELECT * FROM `privileges`";
$permission_query = mysql_query($perm_query);
while($row = mysql_fetch_array($permission_query))
{
$rows[] = $row;
}
foreach($rows as $row)
{
${$row['privilege']};
}
?>
The list of errors:
Notice: Undefined variable: admin_panel in C:\xampp\htdocs\DynamicVariables.php on line 20
Notice: Undefined variable: create_user in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: edit_user in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: delete_user in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: create_group in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: edit_group in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: delete_group in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: view_log in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: log_settings in C:\xampp\htdocs\DynamicVariables.php on line 20 Notice: Undefined variable: password_change in C:\xampp\htdocs\DynamicVariables.php on line 20 Thanks Edited by chrisrulez001, 17 July 2014 - 10:05 AM. This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=357949.0 i've to populate google charts with dynamic data. the data looks llike. +----+-------+---------+-------+-----------+---------+------+ | id | name | physics | maths | chemistry | biology | sst | +----+-------+---------+-------+-----------+---------+------+ | 1 | Name1 | 10 | 25 | 35 | 42 | 62 | | 2 | Name2 | 80 | 45 | 45 | 45 | 25 | | 3 | Name3 | 63 | 25 | 63 | 36 | 36 | | 4 | Name4 | 82 | 36 | 75 | 48 | 42 | | 5 | Name5 | 45 | 45 | 78 | 25 | 24 | | 6 | Name6 | 36 | 36 | 15 | 75 | 36 | | 7 | Name7 | 99 | 45 | 24 | 24 | 45 | | 8 | Name8 | 45 | 85 | 85 | 85 | 96 | +----+-------+---------+-------+-----------+---------+------+ i have to create google charts based on this such that # namewise - such that when i select a name it displays all subject marks of that particular name in a column chart #markswise - when i select a subject, it displays all the names with marks in that particular subject. conisdiering that data may be added and i've to accumulate that also, for namewise i did
// chart.php
<?php
include("connection.php");
$query = "SELECT name FROM csv GROUP BY name DESC";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
?>
<!DOCTYPE html>
<html>
<head>
<title>Google charts</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
</head>
<body>
<br /><br />
<div class="container">
<div class="panel panel-default">
<div class="panel-heading">
<div class="row">
<div class="col-md-9">
<h3 class="panel-title">Student Wise Marks Data</h3>
</div>
<div class="col-md-3">
<select name="name" class="form-control" id="name">
<option value="">Select Student</option>
<?php
foreach($result as $row)
{
echo '<option value="'.$row["name"].'">'.$row["name"].'</option>';
}
?>
</select>
</div>
</div>
</div>
<div class="panel-body">
<div id="chart_area" style="width: 1000px; height: 620px;"></div>
</div>
</div>
</div>
</body>
</html>
<script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script>
<script type="text/javascript">
google.charts.load('current', {packages: ['corechart', 'bar']});
google.charts.setOnLoadCallback();
function load_student_data(name, title)
{
var temp_title = title + ' '+name+'';
$.ajax({
url:"fetch.php",
method:"POST",
data:{name:name},
dataType:"JSON",
success:function(data)
{
drawStudentwiseChart(data, temp_title);
}
});
}
function drawStudentwiseChart(chart_data, chart_main_title)
{
var jsonData = chart_data;
var data = new google.visualization.DataTable();
data.addColumn('number', 'Physics');
data.addColumn('number', 'Maths');
data.addColumn('number', 'Chemistry');
data.addColumn('number', 'Biology');
data.addColumn('number', 'SST');
$.each(jsonData, function(i, jsonData){
var Physics = jsonData.Physics;
var Maths = jsonData.Maths;
var Chemistry = jsonData.Chemistry;
var Biology = jsonData.Biology;
var SST = jsonData.SST;
data.addRows([[Physics,Maths,Chemistry,Biology,SST]]);
});
var options = {
title:chart_main_title,
hAxis: {
title: "Subjects"
},
vAxis: {
title: 'Percentage'
}
};
var chart = new google.visualization.ColumnChart(document.getElementById('chart_area'));
chart.draw(data, options);
}
</script>
<script>
$(document).ready(function(){
$('#name').change(function(){
var name = $(this).val();
if(name != '')
{
load_student_data(name, 'Student wise marks data');
}
});
});
</script>
and in order to fetch data
// fetch.php
<?php
//fetch.php
include('connection.php');
if(isset($_POST["name"]))
{
$query = "
SELECT * FROM csv
WHERE name = '".$_POST["name"]."'
ORDER BY id ASC
";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
foreach($result as $row)
{
$output[] = array(
'Physics' => $row["Physics"],
'Maths' => $row["Maths"],
'Chemistry' => $row["Chemistry"],
'Biology' => $row["Biology"],
'SST' => $row["SST"],
);
}
echo json_encode($output);
}
?>
it diplays a blank page. however when i play with singular values i.e one subject at a time it displays fine Edited March 19, 2019 by zetastreakHi,
I am trying to make a list of all countries listed in a database and the number of times they appear. But I am clearly doing something wrong as I am not able to list out the number of times that they appear.
This is what I have got so far:
<h4>Countries</h4>
<table><col width='150px'><col width='150px'>
<tr>
<th>
Country
</th>
<th>
Number of Occurences
</th>
</tr>
<?php
$location = DB::getInstance()->query("SELECT country, COUNT(country) as countCountry FROM users GROUP BY country ORDER BY count DESC");
foreach ($location->results() as $locations)
{
echo "<tr><td>";
echo $locations->country;
echo "</td><td>";
echo $locations->countCountry;
echo "</td></tr>";
}
?>
</table>
Can anyone point me in the right direction?
So I have a database that is structured like this: https://imgur.com/a/DdyTqiE
I would like to loop through this table, and get a count of how many were 'is_no_show' and 'is_cancelled' per (unique) category with respect to 'scheduled_student_services.' How would I approach this? I know I probably need to do two loops but I'm not sure the PHP syntax for this. Any suggestions or tips would be helpful. Thank you for your time! Hey guys seem to have tricky question here, I am just wondering how I could do the following:
I have an SQL table that contains these columns:
As you can see there is a 'Make' column and a 'Model' column and each row displays what make it is.
I now want to associate the 'Makes' with the 'Models' in another table just like this example:
BMW AUDI VOLVO FORD TOYOTA
X5 All Road XC90 Focus Supra
3 Series A1 C30 Mustang Yaris
5 Series Galaxy
So for example if the first table has a row that contains the make 'AUDI' within the 'Make' column I then want it to take the value of the 'Model' and list it into my other table under the 'AUDI' column, any ideas how I can do this with PHP?
Thanks!
Hello everybody,
I have been racking my brain trying to decipher something that should be really simple for a seasoned programmer. Newbieprogrammer
<html>
function display($randomNr) Hi, Mary Christmas My result of mysql database is LIMIT 8; now i have to retrieve and show this to two Horizontal columns As each columns 4 result. how to generate this Without tables!! only with DIV or UL/LI list . Thanks When displaying data from a mysql table, what php code can I use to display the number of columns in said table? Like, say I'm displaying comments by users. I want to be able to put "displaying 'thismany' comments". Any suggestions? i'm trying to echo out the results from a query onto a page, but rather than having them echo out as rows in a table, i want them to be displayed in columns, i.e. first column would have the first 10 results and the second column would have the next to. Any ideas on how i could do this? at the moment i'm using this code to display my results $read=mysql_query("SELECT * FROM entry WHERE category_id=".$id." ORDER BY entry_title") or die("query failed".mysql_error()); $result=mysql_num_rows($read); for($j = 0; $j < $result; $j++) { $row = mysql_fetch_array($read); echo "<a href=article.php?id=".$row['entry_id']. ">".$row['entry_title']."</a><br />"; } but this just displays it as a list down the middle thanks What I want to do is what is in the shown in the table. I want to only get the Math subject and order the units from unit 1 (UI) to the last available unit in the database; after this, under each unit, to show the homework related to each unit. I have tried to save it into an array with mysql_fetch_array but it stores the row that involves one unit. I want all the units and only the units with their homework under them.
My database is attached to this post in a txt file.
hope someone can help.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Documento sin título</title> </head> <body> <form action="" method="post" name="form1" id="form1"> <table width="200" border="1"> <tr> <td>Subject:</td> <td>Math</td> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td>UI</td> <td>UI</td> <td>UII</td> <td>UIII</td> <td>UII</td> <td>...</td> </tr> <tr> <td>Home work</td> <td>Math work1</td> <td>Math work2</td> <td>Math work3</td> <td>Math work4</td> <td>Math work5</td> <td>...</td> </tr> <tr> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> </tr> </table> </form> </body> </html> Hi There, I have an SQL query that returns 10 rows, which I want to echo over 2 columns and 5 rows, however, I want rows 1-5 on the left hand column and rows 6-10 on the right hand side. Is there an easy way to do this? Normally I would do a fetch_array but, that would place the rows in order of, left, right, left, right - if that makes sense? Table is a standard table with 2 columns and 5 rows. Thanks Matt Hello, I have a script that processes data from a form, and then outputs data from a MySQL table based on which selections are made on the form. What I'm trying to do is create columns showing data for each month depending on which months the user selects, and then a "Total" column at the end of that. The output first determines the "family" the results are in, then the ID the product is for the parent family, and then it outputs the data based on what ID is listed. Unfortunately, I have no idea how to do this without nesting while loops inside other while loops which I know is bad for server performance - and yes this does take a long time to complete. Here is some of my code for this to show what I'm doing wrong: Code: [Select] $searchdatabase5 = "SELECT field3 FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field3 != 0 AND field4 != '995' GROUP BY field3"; $run5 = mysql_query($searchdatabase5) or die(mysql_error()); while($row5 = mysql_fetch_assoc($run5)) { $field5_3 = $row5['field3']; echo '<tr><td colspan="0"><hr style="width: 100%; height: 1px; color: #a0a0a0;"></td></tr><tr><td colspan="0" bgcolor="#ccffcc"><strong>FAMILY '. $field5_3 .'</strong><br /></td></tr>'; $searchdatabase12 = "SELECT field4 FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field3 = '$field5_3' AND field4 != 0 GROUP BY field4"; $run12 = mysql_query($searchdatabase12) or die(mysql_error()); while($row12 = mysql_fetch_assoc($run12)) { $field12_4 = $row12['field4']; $searchdatabase6 = "SELECT field3,field4,field5,field6 FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field4 = '$field12_4' GROUP BY field3,field4,field5"; $run6 = mysql_query($searchdatabase6) or die(mysql_error()); while($row6 = mysql_fetch_assoc($run6)) { $field6_3 = $row6['field3']; $field6_4 = $row6['field4']; $field6_5 = $row6['field5']; $field6_6 = $row6['field6']; echo '<tr><td colspan="0">'. $field6_5 .' - '. $field6_6 .'</td></tr><tr><td valign="middle" align="left" bgcolor="#ccc" width="183px">Units</td>'; $searchdatabase7 = "SELECT * FROM slssum2 WHERE company = '$companyname' AND CONCAT(year,month) BETWEEN '$startyear$startmonth' AND '$endyear$endmonth' AND field5 = '$field6_5' ORDER BY year,month ASC"; $run7 = mysql_query($searchdatabase7) or die(mysql_error()); while($row7 = mysql_fetch_assoc($run7)) { $field7_3 = $row7['field3']; $field7_4 = $row7['field4']; $field7_5 = $row7['field5']; $field7_9 = $row7['field9']; $field7_10 = $row7['field10']; $field7_month = $row7['month']; $field7_year = $row7['year']; $startmonth2 = ltrim($startmonth, '0'); echo '<td bgcolor="#e6e6e6" width="95px" nowrap="nowrap" align="right">'; echo $field7_10; echo '</td>'; } Here is the output: I know the code is very bad, but what would be the best way to recreate what I have in the image? Thank you. Well I have a script file that was originally written like this: Code: [Select] $query = "UPDATE ".$prefix."users SET nickname='".$nickname."' WHERE username='".$loggedinname."'"; mysql_query($query); $query = "UPDATE ".$prefix."users SET gender='".$gender."' WHERE username='".$loggedinname."'"; mysql_query($query); $query = "UPDATE ".$prefix."users SET color='".$color."' WHERE username='".$loggedinname."'"; mysql_query($query); $query = "UPDATE ".$prefix."users SET profile='".$profile."' WHERE username='".$loggedinname."'"; mysql_query($query); $query = "UPDATE ".$prefix."users SET favpet='".$favpet."' WHERE username='".$loggedinname."'"; mysql_query($query); $query = "UPDATE ".$prefix."users SET about='".$about."' WHERE username='".$loggedinname."'"; mysql_query($query); I tried to simplify it by rewriting the following codes below, but unfortunately it did not work. It wouldnt give any errors, but the columns aint updated at all: Code: [Select] mysql_query("UPDATE ".$prefix."users SET nickname='".$nickname."' , gender='".$gender."' , color='".$color."' , profile='".$profile."' , favpet='".$favpet."' , about='".$about."' , WHERE username='".$loggedinname."'"); Did I make any mistake rewriting the codes? Or is it actually impossible to update six columns using only one mysql_query? Please help... Hello, I am trying insert the values of csv file into a table. I want to concatenate the values of some columns of csv into one String column of table by delimiting them my commas. $im="INSERT into TB1 (col1, col2 ) values ('$a[2]','$a[3]')"; $b = ""; $b=".'$a[6]'."||".'$a[7]'."||".'$a[8]'."||".'$a[9]'."; $im1=$im+"UPDATE TB1 set latlng=.'$aline'."; mysql_query($im1) OR die(mysql_error()); I need to enter the value of $a[6] till $a[9] into a string column with delimiters and insert into the column col3 of TB1 with value as $a[4]. I am stuck up here could anyone help me with this issue. right now it displays the first column of the array as a header for each foreach loop then i've got the data displayed under each header and it has 4 columns or a number of my choosing with data displayed under the Table Headings. I am trying to make it display 4 or so columns but with the each group having a certain number of grouped table (data/header) in each column. a different amount for each column that i can choose IF Possible i'd like the choice of being able to remove the headers eg. Z when there is no data in them. This is an example of how it is being displayed right now Any Help would be greatly appreciated Quote A Airlie Beach Andergrove Alexandra Armstrong Beach Alligator Creek B Bucasia Blacks Beach Beaconsfield Bakers Creek Balberra Bloomsbury Breadalbane Ball Bay Belmunda C Cannonvale Calen Crystal Brook Cremorne Chelona Campwin Beach Cape Hillsborough Conway Heres The Code i have so far. Code: [Select] <?php $file = "widget.csv"; @$fp = fopen($file, "r") or die("Could not open file for reading"); $outputArray = array(); $count = 0; while(($shop = fgetcsv($fp, 1000, ",")) !== FALSE) { $outputArray[array_shift($shop)] = array_filter($shop); } echo "<table>"; foreach ($outputArray as $alphabetical=>$value){ echo "<th colspan='4'><b>" . $alphabetical ."</b></th>"; echo "<tr>"; foreach ($value as $key){ $afterkey=preg_replace('/\s+/','-',$key); if ($count == 4){ echo '</tr><tr><td><a href="map.php?mapaddress='.$afterkey.'-qld&mapname='.$key.'">'.$key.'</a></td>'; $count = 0; }else{ echo '<td><a href="map.php?mapaddress='.$afterkey.'-qld&mapname='.$key.'">'.$key.'</a></td>'; } $count++; } echo "</tr>"; $count = 0; } echo "</table>"; echo "\n<br />"; ?> Heres an example of what i am trying to do. A D K N S AlexandraHeadlands DickyBeach KingsBeach Nambour SandstonePoint Aroona Diddillibah KielMountain Ninderry ShellyBeach Doonan KundaPark NoosaHeads SippyDowns B Dulong Kuluin Ningi SunriseBeach Beachmere DeceptionBay Kilcoy NorthArm SunshineBeach BanksiaBeach Noosaville Scarborough Beerburrum E L Beerwah EerwahVale Landsborough O T Bellara Elimbah Tanawha Bellmere Eudlo M P TowenMountain Birtinya Eumundi Maleny Petrie Tewantin Bongaree Mapleton Palmview TwinWaters Bokarina F Marcoola Palmwoods BribieIslandArea Flaxton MarcusBeach Parklands U Buddina ForestGlen MaroochyRiver Parrearra UpperCaboolture Burnside Maroochydore PeregianBeach Buderim G Minyama Pinbarren V Burpengary GlassHouseMountains MoffatBeach PointArkwright Valdora BliBli Mons PelicanWaters H Montville PacificParadise W C Highworth Mooloolaba WeybaDowns CoolumBeach Hunchy Mooloolah Q Warana Caboolture MountainCreek WestWoombye CabooltureSouth I MountCoolum R Woombye Caloundra ImageFlat Morayfield Rosemount Woorim CastawaysBeach Mudjimba Redcliffe WamuranBasin Chevallum J Woodford CoesCreek WoodyPoint Cooroy Wamuran Currimundi Wurtulla X Y YandinaCreek Yandina Z Now I am stumped this is far any help would be awesome This is what I have gotten so far, this is what it does right now is display each Header above each bit of data and spans across 5 columns for each foreach loop but what i am trying to understand here is i am trying to get the header then the data then another header and data and so on but only about 4 or number of my choosing grouped header/data but select how many are in each column up to 5 columns. Heres an example of what i am trying to do. A D K N S AlexandraHeadlands DickyBeach KingsBeach Nambour SandstonePoint Aroona Diddillibah KielMountain Ninderry ShellyBeach Doonan KundaPark NoosaHeads SippyDowns B Dulong Kuluin Ningi SunriseBeach Beachmere DeceptionBay Kilcoy NorthArm SunshineBeach BanksiaBeach Noosaville Scarborough Beerburrum E L Beerwah EerwahVale Landsborough O T Bellara Elimbah Tanawha Bellmere Eudlo M P TowenMountain Birtinya Eumundi Maleny Petrie Tewantin Bongaree Mapleton Palmview TwinWaters Bokarina F Marcoola Palmwoods BribieIslandArea Flaxton MarcusBeach Parklands U Buddina ForestGlen MaroochyRiver Parrearra UpperCaboolture Burnside Maroochydore PeregianBeach Buderim G Minyama Pinbarren V Burpengary GlassHouseMountains MoffatBeach PointArkwright Valdora BliBli Mons PelicanWaters H Montville PacificParadise W C Highworth Mooloolaba WeybaDowns CoolumBeach Hunchy Mooloolah Q Warana Caboolture MountainCreek WestWoombye CabooltureSouth I MountCoolum R Woombye Caloundra ImageFlat Morayfield Rosemount Woorim CastawaysBeach Mudjimba Redcliffe WamuranBasin Chevallum J Woodford CoesCreek WoodyPoint Cooroy Wamuran Currimundi Wurtulla X Y YandinaCreek Yandina Z This is an example of how it is being displayed right now A Airlie Beach Andergrove Alexandra Armstrong Beach Alligator Creek B Bucasia Blacks Beach Beaconsfield Bakers Creek Balberra Bloomsbury Breadalbane Ball Bay Belmunda C Cannonvale Calen Crystal Brook Cremorne Chelona Campwin Beach Cape Hillsborough Conway Heres The Code i have so far. Code: [Select] <?php $file = "widget.csv"; @$fp = fopen($file, "r") or die("Could not open file for reading"); $outputArray = array(); $count = 0; while(($shop = fgetcsv($fp, 1000, ",")) !== FALSE) { $outputArray[array_shift($shop)] = array_filter($shop); } echo "<table>"; foreach ($outputArray as $alphabetical=>$value){ echo "<th colspan='4'><b>" . $alphabetical ."</b></th>"; echo "<tr>"; foreach ($value as $key){ $afterkey=preg_replace('/\s+/','-',$key); if ($count == 4){ echo '</tr><tr><td><a href="map.php?mapaddress='.$afterkey.'-qld&mapname='.$key.'">'.$key.'</a></td>'; $count = 0; }else{ echo '<td><a href="map.php?mapaddress='.$afterkey.'-qld&mapname='.$key.'">'.$key.'</a></td>'; } $count++; } echo "</tr>"; $count = 0; } echo "</table>"; echo "\n<br />"; ?> Heres my CSV File: Quote A,Airlie Beach,Andergrove,Alexandra,Armstrong Beach,Alligator Creek,,,,,,,,,,,,,, B,Bucasia,Blacks Beach,Beaconsfield,Bakers Creek,Balberra,Bloomsbury,Breadalbane,Ball Bay,Belmunda,,,,,,,,,, C,Cannonvale,Calen,Crystal Brook,Cremorne,Chelona,Campwin Beach,Cape Hillsborough,Conway,,,,,,,,,,, D,Dows Creek,Dumbleton,Dolphin Heads,,,,,,,,,,,,,,,, E,Eimeo,Eton,Erakala,,,,,,,,,,,,,,,, F,Foulden,Foxdale,Flametree,Farleigh,Freshwater Point,,,,,,,,,,,,,, G,Glen Isla,Glenella,,,,,,,,,,,,,,,,, H,Homebush,Hampden,,,,,,,,,,,,,,,,, I,,,,,,,,,,,,,,,,,,, J,Jubilee Pocket,,,,,,,,,,,,,,,,,, K,Kinchant Dam,Kolijo,Koumala,Kuttabul,,,,,,,,,,,,,,, L,Laguna Quays,,,,,,,,,,,,,,,,,, M,McEwens Beach,Mackay,Mackay Harbour,Mandalay,Marian,Mia Mia,Middlemount,Midge Point,Mirani,Moranbah,Mount Charlton,Mount Jukes,Mount Julian,Mount Marlow,Mount Martin,Mount Ossa,Mount Pelion,Mount Pleasant,Mount Rooper N,Narpi,Nebo,Nindaroo,North Eton,,,,,,,,,,,,,,, O,Oakenden,Ooralea,,,,,,,,,,,,,,,,, P,Palmyra,Paget,Pindi Pindi,Pinevale,Pioneer Valley,Pleystowe,Preston,Proserpine,,,,,,,,,,, Q,,,,,,,,,,,,,,,,,,, R,Racecourse,Richmond,Riordanvale,Rosella,Rural View,,,,,,,,,,,,,, S,St Helens Beach,Sandiford,Sarina,Seaforth,Slade Point,Shoal Point,Shute Harbour,Shutehaven,Strathdickie,Sugarloaf,Sunnyside,,,,,,,, T,Te Kowai,The Leap,,,,,,,,,,,,,,,,, U,,,,,,,,,,,,,,,,,,, V,Victoria Plains,,,,,,,,,,,,,,,,,, W,Wagoora,Walkerston,Woodwark,,,,,,,,,,,,,,,, X,,,,,,,,,,,,,,,,,,, Y,Yalboroo,,,,,,,,,,,,,,,,,, Z,,,,,,,,,,,,,,,,,,, |
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