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PHP - Adapting Mailchimp Subscribe Code
Hi there,
Mailchimp supplies web form code for adding subscribers from a web page. I need to adapt this code so that instead of form fields, php variables get passed on to mailchimp. This is because the form fields are part of another form and you can have forms in forms. The variables I need to pass to Mailchimp a rev as follows:
$firstname
$lastname
$email
These variables have been passed from an earlier form via $_POST with similar names e.g. firstName, lastName and email.
The mailchimp form code is below with the id numbers replaced with XXX, YYY and ZZZ
<form action="//asn.us7.list-manage.com/subscribe/post?u=XXX;id=YYY" method="post" id="mc-embedded-subscribe-form" name="mc-embedded-subscribe-form" class="validate" target="_blank" novalidate>
<h2>Subscribe to our mailing list</h2>
Similar Tutorialscould someone please help me adapt the following code to make it resize the image before uploading? Any help would be appreciated, thanks <?php if($_GET['submit'] == 'yes') { $image = $_FILES['image']['name']; if ($image) { $filename = stripslashes($_FILES['image']['name']); $extension = getExtension($filename); $extension = strtolower($extension); if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { echo 'Unknown extension!'; $errors=1; } else { $size=filesize($_FILES['image']['tmp_name']); if ($size > MAX_SIZE*1024) { echo 'You have exceeded the size limit! the limit is 500KB'; $errors=1; } $rand = rand(0,9999999); $date = DATE("d.m.y"); $image_name=$date.$id.$rand.'.'.$extension; $newname="./images/$gender/".$image_name; $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { echo 'Copy unsuccessfull!'; $errors=1; }}}} ?> Hi I found this php code which I'm adapting for a project, and I've run into the curly braces problem - could someone look at it for me as I've been looking for hours and still can't sort it out!. It's a form that adds dates and information to a database, the problem is at the error handling stage towards the end of the script - if anyone has any ideas I would be very grateful Code: [Select] <form name="reminder" action="remind.php" method="post"> <table border='0' align='center' cellpadding="5" cellspacing="5"> <tr> <td>First Name:</td> <td colspan="3"> <input name="fname" type="text" maxlength="30" /> </td> </tr> <tr> <td>Last Name:</td> <td colspan="3"> <input name="lname" type="text" maxlength="30" /> </td> </tr> <tr> <td>Email Address:</td> <td colspan="3"> <input name="email" type="text" maxlength="50" /> </td> </tr> <tr> <td>Comapny:</td> <td colspan="3"> <input name="company" type="text" maxlength="50" /> </td> </tr> <tr> <td>Date Certificate taken:</td> <td> Day:<br /> <select name="day"> <?php for($counter=1;$counter<=31;$counter++) { if($counter < 10) $prefix = "0"; else $prefix = ""; echo("\n<option>$prefix$counter</option>"); } ?> </select></td> <td>Month:<br /> <select name="month"> <?php for($counter=1;$counter<=12;$counter++) { if($counter < 10) $prefix = 0; else $prefix = ""; echo("\n<option>$prefix$counter</option>"); } ?> </select></td> <td>Year:<br /> <select name="year"> <?php $current_year = date("Y"); for($counter=$current_year;$counter>=$current_year-5;$counter--) { echo("\n<option>$counter</option>"); } ?> </select></td> </tr> <tr> <td id="alert">*Please complete all fields</td> <td colspan="3"> <input name="step" type="hidden" value="1" /> <input name="submit" type="submit" value="add" /> </td> </tr> </table> </form> </div> </body> </html> <?php // Check for errors in the submitted form... } else { $error = ""; $date = date( "dmY" ); $renew_date = $_POST['day'].$_POST['month'].$_POST['year']; if( empty($_POST['fname']) ) $error .= "Please enter a first name<br />"; if( empty($_POST['lname']) ) $error .= "Please enter a last name<br />"; if( empty($_POST['email']) ) $error .= "Please enter a valid email address<br />"; if(!isEmail($email) ) $error .= "You have entered an invalid e-mail address, please try again.<br />"; if( !checkdate( $_POST['day'], $_POST['month'], $_POST['year'] )) $error .= "The date entered is invalid, please check<br />"; if( empty( $error ) ) { // No error let's add the entry mysql_query( "INSERT INTO clients('first_name', 'last_name', 'email', 'enrolled', 'company') VALUES('".addslashes($_POST['fname'])."', '".addslashes($_POST['lname'])."', '".addslashes($_POST['email'])."', '".addslashes($renew_date)."', '".addslashes($_POST['company'])."')" ); // Let's go to the Reminder List page Header("Refresh: 1;url=list.php"); echo <<< _HTML_END_ Reminder Added, redirecting ... _HTML_END_; } else { // Error occurred let's notify it echo( $error ); } } ?> I have a php script that saves some data as a .xml document. When I view this in my browser I can subscribe to the feed (I am using firefox). However I asked someone else to see if they could subscribe (they were using IE) but the couldn't. Therefore how can users subscribe to my feed? Will only some be able to subscribe? Thanks for any help. I have a 'subscribe' form on a website that uses Ajax to validate the input fields, the form is then processed via php. The actual html code resides on a Wordpress page.
I had actually just got the form to work again. The website was static, and I transferred everything over to Wordpress, and the form didnt work. I was able to get it working by specifying the url: in ajax, as an absolute path to my php form. Overnight, something, I'm not sure what, stopped the form from processing. No data is posted to myql, and no email is sent or received. The status message just hangs at "Please wait while we process your information..." This message is in part of my Ajax code, so I am thinking something is wrong with my php script. I have a 'contact' page that uses nearly identical code that the 'subscribe' pages uses to validate the input fields, and it works.
I was able to recover both the ajax and php script from an earlier time when they did work, I uploaded back to my server and nothing, the form still does not process. I also made sure my database credentials were correct with my host, and even tested my connection to mysql which I was able to connect. Next, I made sure I was able to send mail with my host.
I don't know what is causing the form to hang, and I would love to get this solved; any help would be appreciated! i am new with web socket
and in same time
I try to make server and client communication for soccer manager application, and for this purpose, i need to create closed "chat rooms" or "games" where two users can watch (read game event) and menage (create) game event (make substitution, formation ... or if you want, to send message to server, that they make changes in formation)
this game (room) mast bi secret, and only this two player can use this game for "read" and "write" events in game
for example: Game no: 200001 between user A and user B in 14.05.
when User A, and User B click on game no. 200001 they can read and write game event.
PS: for now, i create basic chat aplication with PHP, jQuery and webSocket and in this app, all user see wath all other user do (public chat) and i want to make secret chat for specific user (already automate subscribed from server) All work with no problem (i work on this example http://www.sanwebe.c...ket-php-socket)
How i can create chat room(s) and subscribe user to specific chat room?
Thanks
Edited by laponac84, 30 November 2014 - 09:09 AM. I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> I use this type of a code to send automatic emails from my website: Code: [Select] $headers = ; $headers .= ; $to = ; Click here to go to Google. ", $headers); I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this: Code: [Select] <a href='http://www.google.com'>here</a> it spits out that exact thing out. Thanks you for your input Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Can you help me integrate this code :
<form method="post" action="submit.php"> <input type="checkbox" class="required" /> Click to check <br /> <input disabled="disabled" type='submit' id="submitBtn" value="Submit"> </form>In to this Contact Form code, please? <form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);"> <table cellpadding="5" width="100%"> <tr> <td width="10" class="required_field">*</td> <td width="80">Your Name</td> <td><input type="text" name="name" maxlength="40" style="width:400px;/></td> </tr> <tr> <td class="required_field">*</td> <td>Email Address</td> <td><input type="text" name="email" maxlength="40" style="width:400px;/></td> </tr> <tr> <td></td> <td>Comments:</td> <td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td> </tr> </table> </form Can I combine also HTML code in PHP function? For example, can a PHP function include HTML form and the PHP code to handle this form? If yes, this will make my main code much more smaller and readable. If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias? Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Alright so I'm attempting to save config data via php. Bellow is the code I currently have, however I'm afraid that when I "flip the switch" and use it that it will error out because of the <?php and ?> tags inside of it... Ideas, suggestions? $config = '../includes/config.php'; $fh = fopen($config, 'w'); $data = ' <?php $dbhost = "'.$database_host.'"; $dbuser = "'.$database_username.'"; $dbpass = "'.$database_password.'"; $dbname = "'.$database_name.'"; $key = "'.$site_key.'"; $cron_key = "'.$database_cron_key.'"; ?> '; fwrite($fh, $data); fclose($fh); How can I make sure that when I submit an new form and new ID (record) is created it is always 4-Digits. record 14 = 0014, record 225 = 0225. Thanks Hello Everyone I am new to php and indeed Web Development. After testing and Playing a bit, I can get the following code to work as two files, the form calling the *.php file to insert into the database, however, I am trying to create one html/php file that displays the form and then executes the php code to insert into the database once user clickes the button. Please can you assist me with the code? I have something horribly wrong and I cannot find it. Code: [Select] <?php> <html> <head> <title>Personal Details</title> </head> <body> <form method="post" action="contactdetails.html"><font face="Arial"> Call Sign:<br> <input name="callsign" size="5" type="text"><br> Surame:<br> <input name="surname" size="30" type="text"><br> First Name:<br> <input name="firstnames" size="30" type="text"><br> Known as:<br> <input name="knownas" size="30" type="text"><br> RSA ID No.:<br> <input name="rsaid" size="13" type="text"><br> Birth Date:<br> <input name="birthdate" size="12" type="text"><br> <input name="Insert" value="Next" type="submit"></form> </font><br> </body> </html> //php to insert data into table $callsign = $_POST['callsign']; $surname = $_POST['surname']; $firstnames = $_POST['firstnames']; $knownas = $_POST['knownas']; $rsaid = $_POST['rsaid']; $birthdate = $_POST['birthdate']; mysql_connect ("localhost", "jredpixm_testuse", "PHPDevelopment") or die ('I cannot connect to the database because: ' .mysql_error()); mysql_select_db ("jredpixm_test"); $query="INSERT INTO personal_details (callsign, surname, firstnames, knownas, rsaid, birthdate)Values ('$callsign', '$surname', '$firstnames', '$knownas', '$rsaid', '$birthdate')"; mysql_query($query) or die ('Error updating Database'); echo "<p>Thanks, your information has been added to the database.</p>"; ?> Regards Allen Michael Feathers coined the term Legacy Code as being code without automated tests.
Still however Legacy Code evokes a vision in me that it is code that is ugly, old, runs on mainframes, and is probably 3000 lines long, uses globals and questionable code practices.
But say we take this ugly nasty code, and put it very nicely under test, but without doing any refactoring, other than that necessary to be able to put it under test in the first place.
Now that code is under test. But it it still ugly. How would you call ugly code under test?
Would you make a differentiation between old & ugly and modern & pretty code if both are under test?
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