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PHP - Query 2 Tables In 1 While
I want to count the number of likes a status has. I have a 'likes' table seperate from the 'stream' table. For now I will keep it simple and only display the number of likes instead of displaying all the usernames that have liked it (even though the system already saves the usernames).
Here is the main query:
//query the database
$query = mysql_query("SELECT `stream_id`, `stream_username`, `stream_status`, `stream_date` FROM stream ORDER BY stream_id DESC LIMIT 50");
//fetch the results /
echo "<hr><br />";
WHILE($rows = mysql_fetch_array($query)):
$name= $rows['stream_username'];
$status = $rows['stream_status'];
$statustime = $rows['stream_date'];
$time = strtotime($statustime);
$thisid = $rows['stream_id'];
echo $name . $status . timeAgo($time) . " ago"
echo "<br /><hr><br />";
endwhile;
And here is one which counts the number of likes
$likesresult = mysql_query("SELECT likes_location_id FROM likes WHERE likes_location_id='$thisid'");
$likescount = mysql_num_rows($likesresult);
So how would I go about merging the two together and displaying '$likescount' after '$status'?Thanks, Similar TutorialsIs it possible to do this with one query? Tried with union and join but no luck.
<?php
$query = 'SELECT cashReward, pointsReward FROM pts WHERE signupsAvailable > 0 AND status = "active" AND id = :id';
$select = $db->prepare($query);
$select->bindParam(':id', $id, PDO::PARAM_INT);
$select->execute();
$rowCount = $select->rowCount();
$queryC = 'SELECT COUNT(id) FROM ignored_pts WHERE user = :username AND ptsId = :id';
$selectC = $db->prepare($queryC);
$selectC->bindParam(':username', $userInfo['username'], PDO::PARAM_INT);
$selectC->bindParam(':id', $id, PDO::PARAM_INT);
$selectC->execute();
$count = $selectC->fetch(PDO::FETCH_COLUMN);
if($rowCount == 1){// PTS //
$row = $select->fetch(PDO::FETCH_ASSOC);
if($count == 0){// IGNORED PTS //
// ...................... //
// INSERT INTO ignored_pts TABLE $row['cashReward'], $row['pointsReward']//
// ...................... //
print 'PTS IGNORED';
}else{
print 'You have already ignored this PTS!';
}
}else{
print 'An invalid PTS was provided!';
}
$db = NULL;
?>
this is the problem i have 2 tables table named ZAMJENE with fields id_event_1, id_event_2 table named EVENTS with fields id_event and event_date and i need echo $id_event_1 on date(EXTRACT FROM TABLE EVENTS FIELD event_date) can be replaced with $id_event_2 on date(EXTRACT FROM TABLE EVENTS FIELD event_date) structure must remains because i have half site build already and i have 3rd table where i just need use JOIN hope you understand problem Hi everyone. I am a newbie to mysql php and have a question. I can display records in a loop from one table but i want to display the records from another table as well that has the same quoteid and where approved is "n" This is what have so far, but there is also only 3 fields from the quotes table i want to display in the loop. $sql = mysql_query("SELECT * FROM comments WHERE approved LIKE 'n%'"); while ($row = mysql_fetch_array($sql)) { $count = mysql_num_rows ( $sql ); foreach($row as $key=>$value){ $$key = htmlentities(stripslashes($value)); } echo ' Hope i make sense. Hello to everybody! I'm developing a beach guid web site, and I need all beach spot have a Country, Region, SubRegion and Spot And I want display this in a <ul> hierarchy. I Create 4 tables TABLE coutry idCoutry name TABLE region idRegion idCoutry name TABLE subregion idSubRegion idRegion name TABLE beach idBeach idSubRegion name I would like display this values like that - Country - Region -SubRegion -Beach -Beach -Beach -Beach -Beach -SubRegion -Beach -Beach -Beach -Beach -Beach - Country - Region -SubRegion -Beach -Beach -Beach -Beach -Beach -SubRegion -Beach -Beach -Beach -Beach -Beach etc. I can do this with multi query but if I have 4000 Beachs the script made many query's If some can help me! Thanks! I have a MySQL data base with two tables. (questions then answers?) I need to query the second table to find related results from a query on the first table. Here is what I have, How do I get it to combine the two queries? <?php $db = @mysqli_connect('localhost', 'unsabook', 'Password', 'unsabook');
if (!$db) { $rs_message = $db->query ("SELECT * FROM `messages` ORDER BY `message_ID` ASC LIMIT 0,200");
while ( $message_array = $rs_message->fetch_assoc() )
echo '<div class="left10">';
$rs_replies = $db->query ("SELECT * FROM `replies` WHERE `message_ID` = '".$message_ID."' ORDER BY `reply_ID` DESC");
echo '<div class="left10">'; I am trying to create a little code, and need to get info from more than one table, preferable like so: $query = "SELECT xxx FROM xxx WHERE xxx="xxx" .......... then do stuff here. $query = "SELECT yyy FROM yyy WHERE yyy="yyy" .......... how to do this the right way? Hey, I have a query running inner joins... which currently works, but I need some more information pulled from other tables... Code: [Select] define('WPSC_TABLE_PRODUCT_LIST', "{$wp_table_prefix}wpsc_product_list"); define('WPSC_TABLE_PRODUCTMETA', "{$wp_table_prefix}wpsc_productmeta"); define('WPSC_TABLE_CATREF', "{$wp_table_prefix}wpsc_item_category_assoc"); define('WPSC_TABLE_CATNAME', "{$wp_table_prefix}wpsc_product_categories"); $cf="Linked Products"; $sku = get_post_meta($post->ID, $cf, true); $array = explode(",",$sku); $products = array_count_values($array); foreach($products as $key => $value) { $product = $wpdb->get_row("SELECT meta.product_id AS pid, list.name AS name, list.price AS price, retailer.category_id AS catid FROM ".WPSC_TABLE_PRODUCTMETA." AS meta INNER JOIN ".WPSC_TABLE_PRODUCT_LIST." AS list ON ( list.id = meta.product_id ) INNER JOIN ".WPSC_TABLE_SHOPNAME." AS retailer ON ( retailer.product_id = meta.product_id ) WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC"); ?> But I also need the category name - So I have to cross reference the following... wordpdem_wpsc_product_list id name 433 itemone 432 itemtwo 431 itemthree wordpdem_wpsc_item_category_assoc id product_id category_id 1 433 1 2 432 2 3 410 3 wordpdem_wpsc_product_categories id name 1 Bread 2 Fish 3 Snacks I've now written: Code: [Select] SELECT meta.product_id AS pid, list.name AS name, list.price AS price, retailer.category_id AS catid, category.name AS catname FROM wordpdem_wpsc_productmeta AS meta INNER JOIN wordpdem_wpsc_product_list AS list ON ( list.id = meta.product_id ) INNER JOIN wordpdem_wpsc_item_category_assoc AS retailer ON ( retailer.product_id = meta.product_id ) INNER JOIN `wordpdem_wpsc_product_categories``wordpdem_wpsc_product_list` AS category ON ( retailer.category_id = category.id ) WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC However it fails on line 12 (the Where statement...) Any ideas what I've done wrong? I am in the process of making a stream page where users can enter a status, like and comment others statuses, like on facebook.
I have 4 tables, stream, users, likes and comments as shown below, with the rows I will be using:
stream stream_status $query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' users.username='$username'"); How do I get it so it selects data from the table tickets where id='$existing', but I also want to get a user's (who is viewing the ID) position (rank). $username is a session. So, any thoughts on how I would do so? My updated code: <?php session_start(); include("../includes/mysql.php"); include("../includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link href="../style.css" rel="stylesheet" type="text/css" /> <title><?php echo $title; ?></title> </head> <body> <div id="container"> <div id="content"> <div id="left"> <div class="menu"> <?php include("../includes/navigation.php"); ?> <div class="menufooter"></div> </div> <?php include("../includes/menu.php"); ?> </div> <div id="middle"> <?php $existing = $_POST['existing']; $ip = $_SERVER['REMOTE_ADDR']; $username = $_SESSION['user']; $query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' OR users.username='$username'"); $get = mysql_fetch_assoc($query); if(!$existing) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>You have not enetered in a ticket ID. Please go back and do so.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['COUNT(id)'] < 1) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>The ticket ID you are trying to use doesnt exist. Please go back or submit another ticket.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['tickets.ip']==$ip || $get['user.position'] >= 1) { $status["tickets.status"]["0"] = "Waiting for support..."; $status["tickets.status"]["1"] = "Waiting for user..."; $status["tickets.status"]["2"] = "Ticket Closed..."; $status["tickets.status"]["3"] = "Ticket Opened..."; echo ' <div class="post"> <div class="postheader"><h1>View Ticket Status - ID '. $get["id"] .'</h1></div> <div class="postcontent"> <p>Title: '. $get["tickets.title"] .' - Posted on: '. $get["tickets.date"] .'</p> <p>Ticket Status: '. $status[$get["tickets.status"]] .'</p> <p>Question: '. nl2br($get["tickets.question"]) .'</p> </div> <div class="postfooter"></div> </div> '; } else { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>This is not your ticket. You only have permission to view your tickets. Please go back.</p> </div> <div class="postfooter"></div> </div> '; } ?> </div> </div> </div> </body> </html> Hi all, I'm currently working on a webpage that dynamically shows tables of sales for products. I'm using SQL to store 2 tables, one containing product info (name, price etc.) and one containing sales for each product. One on of my web pages I want to show the product name and sales for a single year. This would involve ripping the product name from my product table and the sales and year from my sales table. Is this possible in one query? $Query= "select name from productTable and sales, year from salesTable where year = $desiredyear; Obviously I know this is wrong because it isn't working but am I even on the right lines? Thank you. Hi, I'm trying to write a query that retrieves the comments from one table where "touser=$username" and retrieve statuses from another table where byuser=$username, and I want to sort it all by date posted. How would I go about doing that? I'm used to writing normal single table queries, but retrieving from multiple tables is new to me. Thank you for your help in advance. Hi guys, I'm trying to query two tables for different data and echo the results that match both tables. Here are the tables I have and the query I'm trying to run. (Table) qc_reports (Fields) id report_date report_lot_number report_po report_supplier report_buyer report_inspectedby report_pulptemprange report_carrierconditions report_supplierclaim report_carrierclaim report_temprecorder report_temprange_N report_temprange_M report_temprange_B report_suppliercontact report_contactedby report_time report_comments (Table) qc_lots (Fields) id report_id lot_temprange lot_commodity lot_rpcs lot_brand lot_terms lot_cases lot_orgn lot_estnum lot_avgnum This is the query that I'm trying to do. Code: [Select] <?php $sql = "SELECT * FROM qc_reports, qc_lots WHERE "; if (!empty($start_date) and !empty($end_date)) $sql .= " qc_reports.report_date BETWEEN '$start_date' and '$end_date' AND "; if (!empty($search_fronteralot)) $sql .= " qc_reports.report_lot_number = '$search_fronteralot' AND "; if (!empty($search_buyer)) $sql .= " qc_reports.report_buyer = '$search_buyer' AND "; if (!empty($search_supplier)) $sql .= " qc_reports.report_supplier = '$search_supplier' AND "; if (!empty($search_po)) $sql .= " qc_reports.report_po = '$search_po' AND "; if (!empty($search_carrierconditions) and $search_carrierconditions != 'all') $sql .= " qc_reports.report_carrierconditions = '$search_carrierconditions' AND "; if (!empty($search_commodity) and $search_commodity != 'all') $sql .= " qc_lots.lot_commodity = '$search_commodity' AND "; if (!empty($search_inspectedby)) $sql .= " qc_reports.report_inspectedby = '$search_inspectedby' AND "; $sql = substr($sql, 0, -4); $query = mysql_query($sql); $numrows = mysql_num_rows($query); ?> RESULTS - <?php echo $numrows; ?> <hr> <table width='500'><tr><td><b>Date</b></td><td><b>Lot Number</b></td><td><b>PO</b></td><td> </td></tr> <tr> <td> </td> </tr> <?php while ($row = mysql_fetch_assoc($query)) { $id = stripslashes($row['id']); $report_lot_number = stripslashes($row['report_lot_number']); $report_po = stripslashes($row['report_po']); $report_date = stripslashes($row['report_date']); echo "<tr> <td>" . $report_date . "</td></td><td>" . $report_lot_number . "</td><td>" . $report_po . "</td><td><a href='view_report.php?id=" . $id . "'>View</a></td> </tr>"; } echo '</table><br><br><br><hr><br><br>'; } ?> All the variables are passed from a HTML form with $_POST. I need the search to work like this: If there is a value in a form field then the query gets appended with that value but when it gets to the $search_commodity it needs to search the second table (qc_lots) and check for the results. Any results that match have to be matched to the results from the first table (qc_reports) and display (echo) only qc_reports that match to both tables. The only common field is the report_id on the qc_lots table and the id on the qc_reports table. I'm stuck and need some guidance. Can someone help please? Hi, i have a database with multiple records. One of those values is an image. When i query the database and i want only the images as a result it gives the result in a field. It then fills up the field horizontal and when there is no more field left it starts a new row. That is what i want. But now i want some extra info next to the picture so i put that in a table with two colums like this: echo '<table border="1" width="400"><td><a href="'.$row['website'].'"> <img src="'.$row['prod_img'].'"> '.$row['prod_name'].' <a href="'.$row['website'].'">'.$row['website'].'</td></table> ';}} But i still want the result to fill up the field and when the field is full i want the next results on a row below this.... Anyone? I have a table that contains the schools in my system: schools id name location ... Then, I have three tables that use the id of this table: schoolAdmins schoolID schoolContests schoolID students schoolID When I go to delete a school from my system, I want to check to see if that school is connected to any of these three other tables first. This is what I tried (but obviously failed because I'm here) where I'm passing the query the $studentID in question: SELECT * FROM schoolAdmins, schoolContests, students WHERE (schoolAdmins.schoolID = $schoolID) OR (schoolContests.schoolID = $schoolID) OR (students.schoolID = $schoolID) I'm really new to the concept of querying multiple tables in a single statement, so I'm just kind of guessing at this point. Thanks in advance. Hey there. Not sure how to word this. I've been flying blind as a newbie trying to figure out some pagination for a left joined query. I've got syntax errors trying to set up the SELECT COUNT function that adds up the results of the search on a previous page so it knows how many results matched both tables. Right now, I've got this mess, and it's giving me a syntax error, "You have an error in your SQL syntax; .... near 'LEFT JOIN plantae ON (descriptors.plant_id = plantae.pla' at line 12" Code: [Select] $data = "Select (SELECT COUNT(*) FROM descriptors ) AS count1, (SELECT COUNT(*) FROM plantae ) AS count2 LEFT JOIN plantae ON (descriptors.plant_id = plantae.plant_name) WHERE `leaf_shape` LIKE '%$select1%' AND `leaf_venation` LIKE '%$select3%' AND `leaf_margin` LIKE '%$select4%'"; $result = mysql_query ($data); if (!$result) { die("Oops, my query failed. The query is: <br>$data<br>The error is:<br>".mysql_error()); } Below is a page which is supposed to output the name, blog contribution and picture of contributing members of a website. <div id="blog_content" class="" style="height:90%; width:97%; border:5px solid #c0c0c0; background-color: #FFFFFF;"> <!--opens blog content--> <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //include the config file require_once("config.php"); //Define the query. Select all rows from firstname column in members table, title column in blogs table,and entry column in blogs table, sorting in ascneding order by the title entry, knowing that the id column in mebers table is the same as the id column in blogs table. $sql = "SELECT blogs.title,blogs.entry,members.firstname,images.image FROM blogs LEFT JOIN members ON blogs.member_id = members.member_id LEFT JOIN images ON blogs.member_id = images.member_id ORDER BY blogs.title ASC "; $query = mysql_query($sql); if($query !== false && mysql_num_rows($query) > 0) { while(($row = mysql_fetch_assoc($query)) !== false) { echo '<div id="blog_content1" style="float:left; position:relative;bottom:18px;left:13px; background-color: #FFFFFF; height:16.7%; width:100%; border:0px none none;" <!--opens blog_content1 same as main center top 1 and 2 from index page everything scaled down by a factor of 3, heightwise--> <div class="red_bar" style="height:3%; width:100%; border:1px solid #959595;"> <!--a--> <div class="shade1" style="height:5px; width:100%; border:0px none none;"> </div> <div class="shade2" style="height:5px; width:100%; border:0px none none"> </div> <div class="shade3" style="height:5px%; width:100%; border:0px none none"> </div> </div> <!-- closes red bar--> <div class="content" style="height:28.3%; width:100%; border:0px none none;"> <!----> <div class="slideshow" id="keylin" style="float:left; width:20%; border:0px none none;"> <!--a--> <div><img header("Content-type: image/jpeg"); name="" alt="" id="" height="105" width="105" src="$row[image]" /></div> </div> <!-- closes pic--> <div class="content_text" style="float:right; position:relative;top:7px;left:0px; max-height:150px; width:78.5%; border-width:4.5px; border-bottom-style:solid; border-right-style:solid; border-color:#c0c0c0; "> <!--a-->'; echo "<h3>".$row['title']."</h3>"; echo "<p>" .$row['entry']."<br />".$row['firstname']."</p>"; echo '</div> <!-- closes content text--> </div> <!-- closes content--> </div> <!-- closes blog_content1-->'; } } else if($query == false) { echo "<p>Query was not successful because:<strong>".mysql_error()."</strong></p>"; echo "<p>The query being run was \"".$sql."\"</p>"; } else if($query !== false && mysql_num_rows($query) == 0) { echo "<p>The query returned 0 results.</p>"; } mysql_close(); //Close the database connection. ?> </div> <!-- closes blog content--> The select query is designed to retrieve all the blog contributions(represented by the fields blogs.title and blogs.entry) from the database, alongside the contributing member (member.firstname) and the member's picture(images.image), using the member_id column to join the 3 tables involved, and outputs them on the webpage. The title, entry and firstname values are successfully displayed on the resulting page. However, I can't seem to figure out how to get the picture to be displayed. Note that the picture was successfully stored in the database and I was able to view it on a separate page using a simple select query. It is now just a question of how to get it to display on this particularly crowded page. Anyone knows how I can output the picture in the img tag? I tried placing the header("Content-type: image/jpeg"); statement at the top of the php segment, then just right below the select query and finally just right above the img tag, but in every case, I just got a big white blank page starring at me. How and where should I place the header statement? And what else am I to do to get this picture displayed? Any help is appreciated. I have a photo album style gallery to build and i'm finding it dificult to list all the table names (these are names of photo albums) and then enter the data into a seperate query for each album name (these will change often so i cant keep updating the file as normal. this will then post all the data to the xml file and show the set of photos in the individual albums in a flash file. can anyone help me where im going wrong at all? <?php $dbname = 'cablard'; if (!mysql_connect('localhost', 'cablard', '')) { echo 'Could not connect to mysql'; exit; } $sql = "SHOW TABLES FROM $dbname"; $result = mysql_query($sql); if (!$result) { echo "DB Error, could not list tables\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_row($result)) { echo "Table: {$row[0]}\n"; } mysql_free_result($result); $query = "SELECT * FROM photo ORDER BY id DESC"; $result2 = mysql_query ($query) or die ("Error in query: $query. ".mysql_error()); while ($row = mysql_fetch_array($result2)) { echo " <image> <date>".$row['date']."</date> <title>".$row['title']."</title> <desc>".$row['description']."</desc> <thumb>".$row['thumb']."</thumb> <img>".$row['image']."</img> </image> "; } ?> Thanks James To accomplish the layout I was looking for, I used the following code: for ($i=1; $i<=7; $i++) { //set day of week for display as title of columns $dow=date("l", strtotime($year.'W'."$weekno"."$i")); echo "<td class=\"wvcolumn\" valign=\"top\"> <table cellpadding=\"0\" cellspacing=\"0\" border=\"0\" align=\"center\" width=\"$daycolumn\"> <tr><th class=\"wvtitle\" valign=\"bottom\" align=\"center\" width=\"$daycolumn\"><a class=\"titledate\" href=\"createticket.php?action=o&month=".date("m", strtotime($year.'W'."$weekno"."$i"))."&date=".date("d", strtotime($year.'W'."$weekno"."$i"))."&year=".date("Y", strtotime($year.'W'."$weekno"."$i"))."\">$dow, ".date("F d", strtotime($year.'W'.$weekno."$i"))."</a> <a onClick=\"window.open('http://www.batchgeo.com')\" title=\"Map $dow's Appointments\" href=\"mapday.php?week=$weekno&year=$year&day=$i\"><img width=\"20\" style=\"border-style: none\" src=\"../images/icon_globe.png\"></a></th></tr>"; if(date("Y-m-d")==date("Y-m-d", strtotime($year.'W'."$weekno"."$i"))) { $query = "SELECT fieldtickets.ticketnumber, fieldtickets.business, title, apptdatetime, DATE_FORMAT(apptdatetime,'%h:%i %p') AS fapptdatetime, status, billstatus, type, assigntech, clients.business FROM fieldtickets LEFT JOIN clients ON fieldtickets.business = clients.id WHERE status='Open' AND (type = 'Field' OR type = 'Phone') AND apptdatetime BETWEEN '".date("Y-m-d", strtotime($year.'W'."$weekno"."$i"))." 00:00:00' AND '".date("Y-m-d", strtotime($year.'W'."$weekno"."$i"))." 23:59:59' UNION SELECT fieldtickets.ticketnumber, fieldtickets.business, title, apptdatetime, DATE_FORMAT(apptdatetime,'%h:%i %p') AS fapptdatetime, status, billstatus, type, assigntech, clients.business FROM fieldtickets LEFT JOIN clients ON fieldtickets.business = clients.id WHERE status = 'Pending' ORDER BY status ASC, apptdatetime ASC"; } else { $query = "SELECT fieldtickets.ticketnumber, fieldtickets.business, title, apptdatetime, DATE_FORMAT(apptdatetime,'%h:%i %p') AS fapptdatetime, status, billstatus, type, assigntech, clients.business FROM fieldtickets LEFT JOIN clients ON fieldtickets.business = clients.id WHERE status='Open' AND (type = 'Field' OR type = 'Phone') AND apptdatetime BETWEEN '".date("Y-m-d", strtotime($year.'W'.$weekno."$i"))." 00:00:00' AND '".date("Y-m-d", strtotime($year.'W'.$weekno."$i"))." 23:59:59' ORDER BY apptdatetime ASC"; } $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ //if ticket is open show appt time and business, if ticket pending display DELIVERY and business name if($row[status]=="Open") { $href="createticket.php?action=e&ticket=".$row[ticketnumber]; $time=$row[fapptdatetime]; $delivery=""; } elseif($row[status]=="Pending") { $href="createticket.php?action=c&ticket=".$row['ticketnumber'].""; $time=""; $delivery="DELIVER"; } echo "<tr><td valign=\"top\"><a title=\"".$row[ticketnumber]." - ".$row[title]."\" class=\"".$row[status]."\" href=\"$href\"><span>$delivery$time ".substr($row['business'], 0, $displaychars)."</span></a></td></tr>\n"; } echo "</table>"; } echo "</td></tr> </table>"; Output is similar to this, and any existing "deliveries" are displayed under the current day. _________________________________________________ ______________ | Monday | Tuesday | Wednesday | Thursday | Friday | |appointments |appointments |appointments |appointments |appointments This works great, but requires 5 separate queries. My database is very small for now, so its not a big deal, but I know this can be done much more efficiently. How can I query the whole week and put appointments in their corresponding tables (days)? Thank you for your help! Heres what i got... function printLB1 (){ $result = mysql_query("SELECT * FROM leaderboards ORDER BY CollegeFootballPoints DESC"); while ($row = mysql_fetch_object($result)) { $leaderboard[] = $row->Username; $leaderboardPoints[] = $row->CollegeFootballPoints; } $num = mysql_num_rows($reault); //I know from here to ................... needs to be in a var or echo or something. <tr> <td>1.</td> //This will auto increment too like i++ but i cna do that myself! <td>echo $leaderboard;</td> <td>echo $leaderboardPoints;</td> </tr> //Here......................................................... } I need to pull a table row per user. But i want to somehow do it once in a function and then ill echo the function into a table after the php stuff is done. Like i want to pull every a table row per user in the function. then display the function below that way i don't have to write a whole extra query and table row per person. If you understand please help if not please let me know where i can explain more. Thanks This portion is kind of stumping me. Basically, I have a two tables in this DB: users and users_access_level (Separated for DB normalization) users: id / username / password / realname / access_level users_access_level: access_level / access_name What I'm trying to do, is echo the data onto an HTML table that displays users.username in one table data and then uses the users.access_level to find users_access_level.access_name and echo into the following table data, I would prefer not to use multiple queries if possible or nested queries. Example row for users: 1234 / tmac / password / tmac / 99 Example row for users_access_level: 99 / Admin Using the examples above, I would want the output to appear as such: Username: Access Name: Tmac Admin I am not 100% sure where to start with this, but I pick up quickly, I just need a nudge in the right direction. The code I attempted to create just shows my lack of knowledge of joining tables, but I'll post it if you want to see that I did at least make an effort to code this myself. Thanks for reading! |
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