PHP - Sql Is Works In Phpmyadmin But Not Working In Php With Special Case
Hi all,
I'v table called vehicles with
id (int auto_increment) and plate_number (varchar 150). the plate_number have records like (a a a 1 1 1 1) (b b b 2 2 2 2), three chars and four numbers spliced by spaces. I'v php search page with url like this: http://localhost/vehicles/show.php?plate_number=f%20f%20f%205%205%205%205 search about plate_numbet = f f f 5 5 5 5my php code: // pdo connection. // first sql test $sql = "SELECT * FROM vehicles WHERE plate_number LIKE '%".$_GET['plate_number']."%'"; // second sql test // $sql = "SELECT * FROM vehicles WHERE plate_number = '".$_GET['plate_number']."'"; $db->query($sql); if($db->rowcount() > 0){ // print all results... }else{ echo "There are no results."; }The query result is: There are no results.. But, when I copy the sql statements into phpmyadmin it is works fine. (there is a result). like this: SELECT * FROM vehicles WHERE plate_number LIKE '%f f f 5 5 5 5%'; OR SELECT * FROM vehicles WHERE plate_number = 'f f f 5 5 5 5';Also i used string functions (htmlspecialchars, rawurldecode, ... ), still not work. any suggestion to solve this issue? Thanks to all Similar TutorialsI have a really weird problem. I'm trying to run a mysql query that works fine in phpmyadmin but in php script is giving me an error. The query is: Code: [Select] (SELECT DISTINCT art.`TEMPLATE`,gal.`ARTICLE_ID`,art.`TITLE`,art.`DESCRIPTION`,MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('WORD*' IN BOOLEAN MODE) AS score FROM articles art,galeries gal WHERE gal.`ARTICLE_ID`=art.`ARTICLE_ID` AND MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('WORD* ' IN BOOLEAN MODE)) UNION (SELECT DISTINCT `TEMPLATE`,`ARTICLE_ID`,`TITLE`,`DESCRIPTION`,MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('WORD* ' IN BOOLEAN MODE) AS score FROM articles WHERE (MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('WORD* ' IN BOOLEAN MODE))) ORDER BY score DESC LIMIT 0,30 Snipset from php script code: function search($start_row,$ammount,$search_key,$pages){ $start_row = intval($start_row) * $ammount; $return_val = ""; $symbols = array('/','\\','\'','"',',','.','<','>','?',';',':','[',']','{','}','|','=','+','-','_',')','(','*','&','^','%','$','#','@','!','~','`' );//this will remove punctuation $pattern = "#[^(\w|α|β|γ|δ|ε|ζ|η|θ|ι|κ|λ|μ|ν|ξ|ο|π|ρ|σ|τ|υ|φ|χ|ψ|ω|Α|Β|Γ|Δ|Ε|Ζ|Η|Θ|Ι|Κ|Λ|Μ|Ν|Ξ|Ο|Π|Ρ|Σ|Τ|Υ|Φ|Χ|Ψ|Ω|ς|ά|έ|ό|ί|ύ|ώ|ή|ϊ|ϋ|ΐ|ΰ|Ά|Έ|Ό|Ί|Ύ|Ώ|Ή|Ϊ|Ϋ|\d|\'|\"|\.|\!|\?|;|,|\\|\/|\-|:|\&|@)]+#"; $search_key = greek_text::to_upper($search_key); $wc = strip_tags($search_key); $wc = preg_replace($pattern, " ", $wc); for ($i = 0; $i < sizeof($symbols); $i++) { $wc = str_replace($symbols[$i],' ',$wc); } $wc = str_replace("΄", " ", $wc); $wc = str_replace(chr(162), " ", $wc); if( !$keep_numbers ) { $wc = preg_replace('#(^|\s+)[\d\s]+(\s+|$)#',' ',$wc); $pattern = '#(^|\s+)([0-9]+[a-zA-ZαβγδεζηθικλμνξοπρστυφχψωΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩςάέόίύώήϊϋΐΰΆΈΌΊΎΏΉΪΫ]+\s*)+(\s+|$)#'; preg_match($pattern,$wc,$aa); $wc = preg_replace($pattern, " ", $wc); } $wc = trim(preg_replace("/\s\s+/", " ", $wc)); $wc = explode(" ", $wc); $cleaned_keyword = array_filter($wc); $cleaned_keyword = greek_text::removeStopWordsFromArray($cleaned_keyword); $stemmed_keywords = greek_text::stemWordsArray($cleaned_keyword); $query = "(SELECT DISTINCT art.`TEMPLATE`,gal.`ARTICLE_ID`,art.`TITLE`,art.`DESCRIPTION`,MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('"; while(list($key,$val)=each($stemmed_keywords)){ if($val<>" " and strlen($val) > 1){ $query .= $val."*"; $search_keys .= $val."* "; } } $query .= "' IN BOOLEAN MODE) AS score FROM articles art,galeries gal WHERE gal.`ARTICLE_ID`=art.`ARTICLE_ID` AND MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('".$search_keys."' IN BOOLEAN MODE))"; $query .= " UNION (SELECT DISTINCT `TEMPLATE`,`ARTICLE_ID`,`TITLE`,`DESCRIPTION`,MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('".$search_keys."' IN BOOLEAN MODE) AS score FROM articles WHERE (MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('".$search_keys."' IN BOOLEAN MODE))) ORDER BY score DESC LIMIT ".intval($start_row).",".$ammount; $rs = $this->dbActions->execQuery($query); $this->dbActions->execQuery("INSERT INTO searches (`KEY`,`DATE`,`RESULTS`) VALUES ('".$search_key."',NOW(),".$pages.")"); $search_results = "<div id='results'>"; while($row = mysql_fetch_array($rs)){ $search_results.= "<div id='result'>"; $search_results.= "<div class='result_title'><h4><a href='article.php?articleId=".$row["ARTICLE_ID"]."'>".$row['TITLE']."</a></h4></div>"; $search_results.= "<div class='result_description'>".$row['DESCRIPTION']."</div>"; $search_results.= "</div>"; $search_results.= "<div class='result_seperator'></div>"; } $search_results .= "</div>"; $return_val = $search_results; return $return_val; } dbactions class: require 'includes/errors.php'; error_reporting(0); class DBActions{ var $dbCon; var $errorHandler; function DBActions(){ $this->dbCon = $this->dbCon(); $errorHandler = new errors(1); } private function dbCon(){ require 'conf/configuration.php'; $dbcon = mysql_connect($dbUrl,$dbUser,$dbPass); if(!$dbcon)trigger_error("Unable to connect to database $dbUrl for user $dbUser",E_USER_ERROR); mysql_select_db($dbName); mysql_query("SET NAMES 'UTF8'"); mysql_query('set character set utf8'); return $dbcon; } function dbClose(){ if($this->dbCon) mysql_close($this->dbCon); } function execQuery($query){ $result = mysql_query($query,$this->dbCon); $msg = "Unable to execute query ".$query; if(mysql_num_rows($result) > 0) return $result; else if($result == false) trigger_error($msg,E_USER_ERROR); else return $result; } function send_error_mail(){ $this->errorHandler->sendErrorEmail(); } } I've try everything but can't get this working.. Any healp whould be really appreciated. Thanks in advance. Good Afternoon Team, Am sitting with something simple using the language below. If I copy the echo output of my query as included below it works perfectly in phpmyadmin but doesn't work on a website. Variables all seem to echo consistently/correctly and POST checks seem to verify this is working correctly as well. I worry the error comes with the syntax I used in combining the sql queries. That, or perhaps LAST_INSERT_ID does not work in the php script as well as it does in phpmyadmin. All help appreciated.
if(isset($_POST[`region_id`])) {
Hello everyone, I'm having this problem which is really annoying, tried to solve it but couldn't, I write that code in PHPMyAdmin and it works great, but it doesn't work in the website it self ok long story short, there are three tables, hotels, cities, countries hotels include in addition to hotel info, 2 columns (city_id) and (country_id) Cities include id and name and also countries include id and name what I was trying to do, that when a person inputs a city or country name in the search form, it should get the hotels that exists in this city or country, but unfortunately it shows all the hotels in all cities and countries, although the pagination code for number of pages works just fine, it count the number of hotels in that city or country and show the number of pages correctly so here is the code for both for hotel search Code: [Select] class hotelManager { public function getHotel($where) { $where = isset($_POST['where']) ? $_POST['where'] : ""; $dbObj = new DB(); $sql = "select * from hotels where city_id = (select id from cities where name = '$where' ) or country_id = (select id from countries where name = '$where' )"; $result = MYSQL_QUERY($sql); $arr = array(); echo "<table>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td valign=\"top\" width=\"120px\">"; $rowid = $row['id']; $imageqry=mysql_query("SELECT * FROM `hotelphotos` where hotel_id='$rowid' LIMIT 1"); $image=mysql_fetch_array($imageqry); $imagename=$image['attachmentName']; echo "<img src=\"foxmaincms/webroot/files/small/$imagename\"/>"; echo "</td>"; echo "<td valign=\"top\">"; echo "<table> <tr> <td valign=\"top\"> <a href=\"hotels.php?id=".$row['id']."\" class=\"titleslink\">".$row['name']."</a> </td> </tr> <tr> <td class=\"text\" valign=\"top\"> ".$row['location']." </td> </tr> </table>"; echo "</td>"; echo "</tr>"; } echo "</table>"; for hotel pagination Code: [Select] <?php include("includes/hotelsManager.php"); $hotelObj = new hotelManager(); $where = isset($_POST['where']) ? $_POST['where'] : ""; if(isset($_POST['where'])) { $hotelObj -> getHotel($where); $per_page = 9; //Calculating no of pages $sql = "select * from hotels where city_id = (select id from cities where name = '$where' ) or country_id = (select id from countries where name = '$where' )"; $result = MYSQL_QUERY($sql) or die("<br />No Hotels found in this city, please check the city name and try again"); $count = mysql_num_rows($result); $pages = ceil($count/$per_page) ?> <div id="loading" ></div> <div id="maincontent" ></div> <ul id="pagination"> thank you in advance
Hi, this query runs fine when I run it from PHPMyAdmin: UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1 However, when I run the same query in a PHP file on my server, the page doesn't load at all. The message I get is: www.somesite.com is currently unable to handle this request. HTTP ERROR 500. This is my PHP code: <?php include("/database/connection/path/db_connect.php"); $result4 = mysqli_query($GLOBALS["___mysqli_ston"], "UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1"); echo $result4; ?> So how do I make this query work please? Thanks for your guidance. My case statement is not working. What happened is that two students got a $markgrade of 61 and 67. So they both should get grade B but instead they both get Grade A. 1 student got 55 which should be grade C but gets grade A. why is it not following the switch statement? Code: [Select] function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ''; switch($grade){ case ($markGrade >=70): $grade = 'A'; break; case ($markGrade >=60 && $markGrade <=69): $grade = 'B'; break; case ($markGrade >=50 && $markGrade <=59): $grade = 'C'; break; case ($markGrade >=40 && $markGrade <=49): $grade = 'D'; break; case ($markGrade >=30 && $markGrade <=39): $grade = 'E'; break; case ($markGrade >=0 && $markGrade <=29): $grade = 'F'; break; }; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} {$session['Mark']} {$session['SessionWeight']}%</p>\n"; $markTotal += ($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = ($markTotal / $weightSession * 100); } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} {$markTotal} {$markGrade} {$grade}</p>\n"; return $moduleHTML . $sessionsHTML; } I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5'; this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice? <?php session_start(); if(!isset($_SESSION['User'] )) header('Location : error.php'); ?> im not being redirected even when the $_SESSION['User'] is not set neither does it display any error message other than a white blank space. Please help me som1 as how I can make this to work or suggest any other altenatives so as to get it redirected as i dont want anonymous users to access some contents unles he logs in as members. Thanx I'm testing out small bits of code for myself, and I'm trying to understand why this isn't coming out how I would imagine it to... I have my function which stores colors in an array from a text file, then I return back a random color from my array like so... function getColor() { $ball_color = explode("\n", file_get_contents('colors.txt')); // Takes file contents and stores them into an array. return $ball_color[array_rand($ball_color)]; } And now in the main program, I simply have this: $color = getColor(); switch($color) { Case "blue": // echo stuff break; Case "red": // echo stuff break; etc... } For some reason though, my switch statement always reads the default case, making me assume that the words "blue" "red" "green" etc... aren't matching up to what I have set the cases at. When I output what color is actually being read, it displays exactly as it should, so I don't understand why the case "red" isn't opening up when that color is chosen, or same with any of the other colors. Is there some small conflict I'm unaware of in this tiny practice code? Any help is appreciated, thanks. This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=309442.0 For years I have used a simple captcha application displaying a simple combination of letters and numbers.
All has worked fine except that my hosting company upgraded some of their servers from PHP 5.2.17 to PHP 5.4.29. The numbers now down't display and I can submit the form without filling any captcha into the text box.
On the otherhand, I have a couple of sites on different servers, (same hosting company) using PHP 5.2.17 and the captcha application works perfectly.
The code to make the captcha works uses $HTTP_SESSION_VARS and I understand it is deptrecated with newer versions of PHP so I changed to $_SESSION.
If I fill out the form and leave the captcha blank it will default to the error message and require a return to the form page to fill in the captcha. Once filled in and the form submitted, it goes to the default message.
It appears that the session variable is not passing to the page and recognized.
so my situation is something like this , i'm trying to fetch user details based on `id` that isset is getting, but some how the `variable that contains the $_GET value doesn't work` in query but when i put an static value to pdo query then it works and show the result. i have checked by doing `var_dump` of variable `$user` before query and it shows the correct value but not working in query. Below is the code i'm working with: I have developed a code for a login and seems to work well (No syntax error according to https://phpcodechecker.com/ but when I enter a username and a password in the login form, I get an error HTTP 500. I think that everything is ok in the code but obviously there is something that I am not thinking about. The code (excluding db connection): $id="''"; $username = $_POST['username']; $password = md5($_POST['password']); $func = "SELECT contrasena FROM users WHERE username='$username'"; $realpassask = $conn->query($func); $realpassaskres = $realpassask->fetch_assoc(); $realpass= $realpassaskres[contrasena]; $func2 = "SELECT bloqueado FROM users WHERE username='$username'"; $blockedask = $conn->query($func2); $blockedres = $blockedask->fetch_assoc(); $bloqueado = $blockedres[bloqueado];
//Login if(!empty($username)) { // Check the email with database i have been working with a website but only locally. i am now trying to put it online which is ok. when i was working with it locally i have been able to create multiple users which have different privileges to each page. for example i said one of my users can only read and the other can read write. the problem is when i have went to create these users online i can't seem to find the create user option in phpmyadmin. i am missing the obvious or will i have to code them in and if so can you direct me to a tutorial which shows me how. thanks in advance I have a form where it ask the user to select the student ID, course ID, enter the grades and comments. The Student ID and CourseID is selected from a drop down menu, but when the data is sent to PHPMYADMIN it enters a 0 into the SID and CID How to I get it save the numbers which has been selected Hi guys I have two questions: Question 1: phpmyadmin If my host does not provide phpmyadmin and I want to install it myself, can I just download phpmyadmin and copy it to my public_html folder or is there another way to install it on my site?? Question 2: Email Script I have a script that sends an email to a system that sends out multiple sms's. The system works like this, I send an email to an address with an attachment called cellnumbers.txt with a list of all the cellnumbers. I must add a specific subject. When I send the email to my own email address, it comes correctly through. But when it is sent to the address of the server, no sms are received. I attached my script. Please take a look. Your help will be greatly appretiated. Thank you I have used the XAMPP installer to install php and MySQL locall on my computer. I also succeeded in setting the security for XAMPP pages, the MySQL admin user root and phpMyAdmin login. When I enter phpMyAdmin via the link in the XAMPP initial page I do however receive a red notification: phpMyAdmin configuration storage is not fully configured; some extensions are not activated. To find out click here. I have attached a screenshot showing three items which are not OK, shown in red. I looked up in the documentation, but could not find out. I hope someone can help. I don't even know if it is important to fix this problem. Regards, Erik Attached Files XAMPP2.jpg 41.08KB 0 downloads Hi, I cannot find where to add foreign key constraints in phpmyadmin! Any help is appreciated! Each time i try to open WAMP's phpmyadmin so i can create a database it has this ERROR #1045 - Access denied for user 'root'@'localhost' (using password: NO) how do i fix it Using phpMyAdmin I loaded 6 test records with the id set to auto_increment and it loaded all the data correctly with id # 1-6. Then from somewhere it got the number 333353 and auto_increments it as the value for the id. So now I have id's 1-6 and 333353, 333354, ect. For every record I add it increments it. I deleted all but records 1-6 and tried again but it has the last value of 3333xx stored somewhere and increments it. Deleted them again, closed the program, came back and it still does it. Hi. I having trouble with counting rows in phpmyadmin. It works fine this way: Code: [Select] $result_rows = mysql_query("SELECT * FROM events"); But when i modify the code to this it doesnt work at all. Code: [Select] $result_rows = mysql_query("SELECT * FROM events WHERE category = 'adults' ORDER BY 'date'"); Any idea what is wrong? |