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PHP - Problems With Mysql And Phpmyadmin
I have a db.php and inside it I filled out all the info needed:
<?php
define('DB_HOST', 'example.com');
define('DB_NAME', 'database_name');
define('DB_USERNAME', 'user_name');
define('DB_PASSWORD', '*******');
$odb = new PDO('mysql:host=' . DB_HOST . ';dbname=' . DB_NAME, DB_USERNAME, DB_PASSWORD);
?>
My problem is with the DB_HOST, is that my direct URL to the site? for example, google.com or is it like an IP?
Similar TutorialsI have a really weird problem. I'm trying to run a mysql query that works fine in phpmyadmin but in php script is giving me an error. The query is: Code: [Select] (SELECT DISTINCT art.`TEMPLATE`,gal.`ARTICLE_ID`,art.`TITLE`,art.`DESCRIPTION`,MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('WORD*' IN BOOLEAN MODE) AS score FROM articles art,galeries gal WHERE gal.`ARTICLE_ID`=art.`ARTICLE_ID` AND MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('WORD* ' IN BOOLEAN MODE)) UNION (SELECT DISTINCT `TEMPLATE`,`ARTICLE_ID`,`TITLE`,`DESCRIPTION`,MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('WORD* ' IN BOOLEAN MODE) AS score FROM articles WHERE (MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('WORD* ' IN BOOLEAN MODE))) ORDER BY score DESC LIMIT 0,30 Snipset from php script code: function search($start_row,$ammount,$search_key,$pages){ $start_row = intval($start_row) * $ammount; $return_val = ""; $symbols = array('/','\\','\'','"',',','.','<','>','?',';',':','[',']','{','}','|','=','+','-','_',')','(','*','&','^','%','$','#','@','!','~','`' );//this will remove punctuation $pattern = "#[^(\w|α|β|γ|δ|ε|ζ|η|θ|ι|κ|λ|μ|ν|ξ|ο|π|ρ|σ|τ|υ|φ|χ|ψ|ω|Α|Β|Γ|Δ|Ε|Ζ|Η|Θ|Ι|Κ|Λ|Μ|Ν|Ξ|Ο|Π|Ρ|Σ|Τ|Υ|Φ|Χ|Ψ|Ω|ς|ά|έ|ό|ί|ύ|ώ|ή|ϊ|ϋ|ΐ|ΰ|Ά|Έ|Ό|Ί|Ύ|Ώ|Ή|Ϊ|Ϋ|\d|\'|\"|\.|\!|\?|;|,|\\|\/|\-|:|\&|@)]+#"; $search_key = greek_text::to_upper($search_key); $wc = strip_tags($search_key); $wc = preg_replace($pattern, " ", $wc); for ($i = 0; $i < sizeof($symbols); $i++) { $wc = str_replace($symbols[$i],' ',$wc); } $wc = str_replace("΄", " ", $wc); $wc = str_replace(chr(162), " ", $wc); if( !$keep_numbers ) { $wc = preg_replace('#(^|\s+)[\d\s]+(\s+|$)#',' ',$wc); $pattern = '#(^|\s+)([0-9]+[a-zA-ZαβγδεζηθικλμνξοπρστυφχψωΑΒΓΔΕΖΗΘΙΚΛΜΝΞΟΠΡΣΤΥΦΧΨΩςάέόίύώήϊϋΐΰΆΈΌΊΎΏΉΪΫ]+\s*)+(\s+|$)#'; preg_match($pattern,$wc,$aa); $wc = preg_replace($pattern, " ", $wc); } $wc = trim(preg_replace("/\s\s+/", " ", $wc)); $wc = explode(" ", $wc); $cleaned_keyword = array_filter($wc); $cleaned_keyword = greek_text::removeStopWordsFromArray($cleaned_keyword); $stemmed_keywords = greek_text::stemWordsArray($cleaned_keyword); $query = "(SELECT DISTINCT art.`TEMPLATE`,gal.`ARTICLE_ID`,art.`TITLE`,art.`DESCRIPTION`,MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('"; while(list($key,$val)=each($stemmed_keywords)){ if($val<>" " and strlen($val) > 1){ $query .= $val."*"; $search_keys .= $val."* "; } } $query .= "' IN BOOLEAN MODE) AS score FROM articles art,galeries gal WHERE gal.`ARTICLE_ID`=art.`ARTICLE_ID` AND MATCH(art.`TITLE`,art.`DESCRIPTION`,gal.`CONTENT`) AGAINST ('".$search_keys."' IN BOOLEAN MODE))"; $query .= " UNION (SELECT DISTINCT `TEMPLATE`,`ARTICLE_ID`,`TITLE`,`DESCRIPTION`,MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('".$search_keys."' IN BOOLEAN MODE) AS score FROM articles WHERE (MATCH(`TITLE`,`DESCRIPTION`,`CONTENT`) AGAINST ('".$search_keys."' IN BOOLEAN MODE))) ORDER BY score DESC LIMIT ".intval($start_row).",".$ammount; $rs = $this->dbActions->execQuery($query); $this->dbActions->execQuery("INSERT INTO searches (`KEY`,`DATE`,`RESULTS`) VALUES ('".$search_key."',NOW(),".$pages.")"); $search_results = "<div id='results'>"; while($row = mysql_fetch_array($rs)){ $search_results.= "<div id='result'>"; $search_results.= "<div class='result_title'><h4><a href='article.php?articleId=".$row["ARTICLE_ID"]."'>".$row['TITLE']."</a></h4></div>"; $search_results.= "<div class='result_description'>".$row['DESCRIPTION']."</div>"; $search_results.= "</div>"; $search_results.= "<div class='result_seperator'></div>"; } $search_results .= "</div>"; $return_val = $search_results; return $return_val; } dbactions class: require 'includes/errors.php'; error_reporting(0); class DBActions{ var $dbCon; var $errorHandler; function DBActions(){ $this->dbCon = $this->dbCon(); $errorHandler = new errors(1); } private function dbCon(){ require 'conf/configuration.php'; $dbcon = mysql_connect($dbUrl,$dbUser,$dbPass); if(!$dbcon)trigger_error("Unable to connect to database $dbUrl for user $dbUser",E_USER_ERROR); mysql_select_db($dbName); mysql_query("SET NAMES 'UTF8'"); mysql_query('set character set utf8'); return $dbcon; } function dbClose(){ if($this->dbCon) mysql_close($this->dbCon); } function execQuery($query){ $result = mysql_query($query,$this->dbCon); $msg = "Unable to execute query ".$query; if(mysql_num_rows($result) > 0) return $result; else if($result == false) trigger_error($msg,E_USER_ERROR); else return $result; } function send_error_mail(){ $this->errorHandler->sendErrorEmail(); } } I've try everything but can't get this working.. Any healp whould be really appreciated. Thanks in advance. I am trying to simplify my coding work for my website and wanting to make it operate more professionally (as part of my training to better my programming skills, which I know will take a lot of time to do). One of the things I`d like to improve on it is to create tables and fields in my mysql database, but not have to go into phpmyadmin to do it. I know open source programs like Drupal can do this easily so that when you add modules, the user does not have to access the database to set it up. But looking at the codes, I`m unable to figure out how it works. How will I be able to program my code to do something like, I`ll have a form where I enter in what I want the new table to be called, what fields to add in and their specifications, where I could do this by just going into my website as the admin? Hi, I have a sql query that executes perfectly in phpMyAdmin but when applied to a PHP script returns nothing. It won't even start a "while" loop. Please review code snippits below. Submission Script calls function in Database Class: $result = $database->testReturnId($_POST['years'], $_POST['model']); while($row = mysql_fetch_array($result)) { $i = $i + 1; echo "ROW " . $i . " " . $row['auto_id'] . " " . $row['auto_year'] . " " . $row['auto_year_high'] . " " . $row['auto_make'] . " " . $row['auto_model'] . "<br />"; } Database Class Function: function testReturnId($year, $model){ global $form; $q = 'SELECT * FROM tbl_svc_auto WHERE auto_model = "$model" AND "$year" BETWEEN auto_year AND auto_year_high'; if(!mysql_query($q, $this->connection)){ return false; }else{ return $result = mysql_query($q, $this->connection); } } I have moved the query to the submission script and replaced the variables with actual data and it still will not work. I can take the same query with out the variables and input it into phpMyAdmin and it works great. On the submission script, I added a row number to the echo thinking that it would a least return the word "ROW" and it does not. I have tested each step of the execution of the query and have not returned any errors. I do not receive any errors at all even during execution. It just seems to refuse to run the "while" statement. I do not know where my problem is......Please help. Thank you in advance for any assitance you can offer. Joshua
Hi, this query runs fine when I run it from PHPMyAdmin: UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1 However, when I run the same query in a PHP file on my server, the page doesn't load at all. The message I get is: www.somesite.com is currently unable to handle this request. HTTP ERROR 500. This is my PHP code:
<?php
include("/database/connection/path/db_connect.php");
$result4 = mysqli_query($GLOBALS["___mysqli_ston"], "UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1");
echo $result4;
?>
So how do I make this query work please? Thanks for your guidance. Hello Im just new to coding into php and im getting this error? i cant seems to see database into my php ? what wrong need help CREATE TABLE IF NOT EXISTS `payment_details` ( `id` int(11) NOT NULL AUTO_INCREMENT, `idnumber` varchar(30) NOT NULL, `date` varchar(30) NOT NULL, `amount` varchar(30) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;Here my php code i cant seems to understand what wrong i dont get any error from mysql or from my php please i dont know what wrong
<label for="filter">Filter</label> <input type="text" name="filter" value="" id="filter" />
<table cellpadding="1" cellspacing="1" id="resultTable">
<thead>
<tr>
<th style="border-left: 1px solid #C1DAD7"> Date </th>
<th>Amount</th>
</tr>
</thead>
<tbody>
<?php
include('../connect.php');
$id=$_SESSION['SESS_MEMBER_ID'];
$result = mysql_query("SELECT * FROM student WHERE id='$id'");
while($row = mysql_fetch_array($result))
{
echo '<tr class="record">';
echo '<td style="border-left: 1px solid #C1DAD7"><div align="left">'.$row['date'].'</div></td>';
echo '<td><div align="left">'.$row['amount'].'</div></td>';
echo '</tr>';
}
?>
</tbody>
</table>
It seems the code below doesn't work properly. Even if there isn't a record that has the same username or name, it will say there is on in the database, which prevents them from making an account. Why so? Code: [Select] $check1 = $db->prepare("SELECT username,name FROM servers WHERE username = ? OR name = ? LIMIT 1"); $check1->execute(array($username, $password)); if($check1->rowCount() > 0) { echo "Sorry, there is already an account with this username and/or server name!"; } And here is my other problem, the harder one. It seems my execute wont work properly. The data will NEVER insert in the database, and it just says: "You've successfully created your account!" Here is my code: Code: [Select] $insertQuery = $db->prepare("INSERT INTO servers (id, username, password, name, type, description, ip, votes, beta) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)"); $insertQuery->execute(array(null, $username, $password, $name, $server_type, $description, $ip, 0, 1)); if($insertQuery->errorInfo() > 0) { echo "Sorry, there was the following error:"; print_r($insertQuery->errorInfo()); } else { echo "Server has been succesfully created!"; } [MAY LOOK SLOPPY. CODED IN NOTEPAD++, BEST VIEWED WITH IT.] Full, whole page code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = $_POST['username']; $password = $_POST['password']; $name = $_POST['name']; $server_type = $_POST['type']; $description = $_POST['description']; //This check isn't 100% secure. It allows for registration with no server details if(!$username || !$password) { //Ideally HTML and PHP should be as separate as possible. Perhaps consider having a different PHP script that runs the registration echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = $db->prepare("SELECT username,name FROM servers WHERE username = ? OR name = ? LIMIT 1"); $check1->execute(array($username, $name)); if($check1->rowCount() > 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; $insertQuery = $db->prepare("INSERT INTO servers (id, username, password, name, type, description, ip, votes, beta) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)"); $insertQuery->execute(array(null, $username, $password, $name, $server_type, $description, $ip, 0, 1)); if($insertQuery->errorInfo() > 0) { echo "Sorry, there was the following error:"; print_r($insertQuery->errorInfo()); } else { echo "Server has been succesfully created!"; } } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> Hi, I'm not sure if this should be posted in the PHP forum or the mySQL forum as it's a bit of both to be honest. Basically I am generating what I think is a fairly complex SQL statement (although I'm by no means a mySQL master so it might not be that complex) through the use of PHP. The PHP that is generating the statement looks like so: Code: [Select] // Availability $availability = 'SELECT * FROM indivdual_teachers WHERE 1=1'; foreach($_GET as $key=>$value){ if(strpos($key, 'availability_') == 0 and $value=='Available'){ $day = (int)str_replace('availability_', '', $key); $availability .= ' AND teacher_id IN (SELECT candidate_id FROM availability_calendar WHERE (DAY = '.$day.' AND MONTH = '.$month.' AND YEAR = '.$year.' AND availability = "Available")) '; } } // Staff Yype if($_GET['staff_required'] == 'Non Teaching Staff') { $search_str[] = "role !=\"\""; } elseif($_GET['staff_required'] == 'Teaching Staff') { $search_str[] = "role=\"\""; } else { } // Lives in... if(!empty($_GET['location'])) { $location = mysql_real_escape_string($_GET['location']); $search_str[] = "address2 LIKE '%$location%' OR city LIKE '%$location%'"; } elseif(!empty($_GET['region'])) { $region = mysql_real_escape_string($_GET['region']); $search_str[] = "region = '$region'"; } else { // They don't want to search on lives in... so do nothing } // Registered with... if(!empty($_GET['LA'])) { $local_authority = mysql_real_escape_string($_GET['LA']); $search_str[] = "id IN (SELECT teacher_id FROM teacher_LEAs WHERE LEA = '$local_authority')"; } elseif (!empty($_GET['Agency'])) { $agency = mysql_real_escape_string($_GET['Agency']); $search_str[] = "id IN (SELECT teacher_id FROM teacher_agencies WHERE agency = '$agency')"; } else { // They don't want to search on registered with... so do nothing } $total = $_GET["keywords"]; $keyarr = explode(',',$total); // In order to process this array values here is the code foreach($keyarr as $key=>$value) { // becareful to check the value for empty line $value = trim($value); if (!empty($value)) { $search_str[] = "id IN (SELECT teacher_id FROM test_cv_tags WHERE skills = '$value')"; } } // Subject/Specalism if(!empty($_GET['subject'])) { $subject = mysql_real_escape_string($_GET['subject']); $search_str[] = "id IN (SELECT teacher_id FROM teacher_specialisms WHERE specalism = '$subject')"; } if(!empty($_GET['additional_subject'])) { $additional_subject = mysql_real_escape_string($_GET['additional_subject']); $search_str[] = "id IN (SELECT teacher_id FROM teacher_additional_subjects WHERE subject = '$additional_subject')"; } // Ranking if(!empty($_GET['overall'])) { $overall = mysql_real_escape_string($_GET['overall']); $search_str[] = "avg_overall >= $overall "; } else { if(!empty($_GET['behaviour'])) { $behaviour = mysql_real_escape_string($_GET['behaviour']); $search_str[] = "avg_behaviour_management >= $behaviour "; } if(!empty($_GET['ability'])) { $ability = mysql_real_escape_string($_GET['ability']); $search_str[] = "avg_teaching_ability >= $ability "; } if(!empty($_GET['planning'])) { $planning = mysql_real_escape_string($_GET['planning']); $search_str[] = "avg_preperation_planning >= $planning "; } if(!empty($_GET['professional'])) { $professionalism = mysql_real_escape_string($_GET['professional']); $search_str[] = "avg_professionalism >= $professionalism "; } } This is all brought together like so; Code: [Select] if(!empty($search_str)){ $sql = "$availability AND ".join(" AND ", $search_str)." AND public_profile = 'Yes' ORDER BY avg_overall DESC"; echo $sql; } else { $sql = "$availability AND public_profile = 'Yes' ORDER BY avg_overall DESC"; echo $sql; } When I complete my form and echo the completed query it looks something like this; Code: [Select] SELECT * FROM indivdual_teachers WHERE 1=1 AND teacher_id IN (SELECT candidate_id FROM availability_calendar WHERE (DAY = 19 AND MONTH = 04 AND YEAR = 2012 AND availability = "Available")) AND role="" AND region = 'North East' AND id IN (SELECT teacher_id FROM teacher_agencies WHERE agency = 'Education World') AND id IN (SELECT teacher_id FROM test_cv_tags WHERE skills = 'french') [color=red]AND[/color] id IN (SELECT teacher_id FROM test_cv_tags WHERE skills = 'golf') [color=red]AND[/color] id IN (SELECT teacher_id FROM test_cv_tags WHERE skills = 'spanish') AND id IN (SELECT teacher_id FROM teacher_specialisms WHERE specalism = 'Accounting') AND id IN (SELECT teacher_id FROM teacher_additional_subjects WHERE subject = 'Art') AND avg_behaviour_management >= 5 AND avg_teaching_ability >= 5 AND avg_preperation_planning >= 5 AND avg_professionalism >= 5 AND public_profile = 'Yes' ORDER BY avg_overall DESC The problem I have is that the part I have highlighted in red should actually be an OR statement in order for the query to work as intended. I realise why it is an AND statement, simply because it is using this (highlighted in green). I can't simply change the green AND to an OR because that would cause the rest of my query to misfunction; Code: [Select] $sql = "$availability AND ".join(" [color=green]AND[/color] ", $search_str)." AND public_profile = 'Yes' ORDER BY avg_overall DESC"; However I have been unable to resolve the issue. Would someone be kind enough to offer me some advice/guidance here? Many thanks. Hi all, I have a query that runs just fine from the command line in MySQL, but when I try to run the exact same query using PHP to query the same database I get an error. The query is: SELECT Street, City, ZipCode, providers.bWebpage, OpHours.Open, OpHours.Close, lat, lng, ( 3959 * acos( cos( radians('41.757787') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('-88.321416') ) + sin( radians('41.757787') ) * sin( radians( lat ) ) ) ) AS distance FROM Providers, OpHours WHERE providers.bName = OpHours.bName AND OpHours.Close > '17:00:00' HAVING distance < '10' ORDER BY distance LIMIT 0 , 30 Like I stated above, when I run this query from the MySQL command line it returns 12 rows, which is what it should. But when I try executing the same query via PHP I get this error message: Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''17:00:00' HAVING distance < '10' ORDER BY distance LIMIT 0 , 30' at line 1 The PHP code is thus: $connection=mysql_connect ($server, $username, $password); if (!$connection) { echo 'Connection error'; die("Not connected : " . mysql_error()); } $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { echo 'Database selection error' . '\n'; die ("Can\'t use db : " . mysql_error()); } $query = sprintf("SELECT Street, City, ZipCode, providers.bWebpage, OpHours.Open, OpHours.Close, lat, lng, ( 3959 * acos( cos( radians('%s') ) * cos( radians( lat ) ) * cos( radians( lng ) - radians('%s') ) + sin( radians('%s') ) * sin( radians( lat ) ) ) ) AS distance FROM Providers, OpHours WHERE providers.bName = OpHours.bName %s HAVING distance < '%s' ORDER BY distance LIMIT 0 , 30", mysql_real_escape_string($center_lat), mysql_real_escape_string($center_lng), mysql_real_escape_string($center_lat), mysql_real_escape_string($hours), mysql_real_escape_string($radius)); $result = mysql_query($query); if (!$result) { die("Invalid query: " . mysql_error()); } I've also checked the MySQL logs and they don't report any errors. I'm running this on a Mac using Snow Leopard. MySQL version is 5.1.37 and the PHP version is 5.2.11. If it makes any difference both of these are from MAMP version 1.8.4. Hi, I only just worked out (a little slow) that mysql is not redundant and crap =\ Apparently I should be using mysqli.
However I need help I tried following a tutorial online but it failed. This is my login script and it doesn't work
<?php
require_once '../inc/conn.php';
session_start();
if ($_POST['username']) {
$username = $_POST['username'];
$password = $_POST['password'];
$requestLogin = mysqli_query( $retreat, "SELECT * FROM login WHERE username='$username' AND password='$password'");
while($row = mysqli_fetch_array($requestLogin)){
$userID = $row['userID'];
$_SESSION['userID'] = $userID;
$username = $row['username'];
$_SESSION['username'] = $username;
header('location: /administrator/');
}
}
?>
And this is the conn.php ( something hidden for safety, however it does connect correctly.
<?php
$hostname = 'localhost';
$username = '';
$password = '';
$database = '';
$retreat = mysqli_connect($hostname, $username, $password, $database) or die('Connecting to MySQL failed');
?>
The actual <form> is also correct as it's just normal html and worked before I tried converting to mysqli.
After this login I have a script which is this that goes in the header of all admin pages.
<?php
require_once '../inc/conn.php';
session_start();
if (isset($_SESSION['userID'])) {
$username = $_SESSION['username'];
$getUser = mysqli_query( $retreat, "SELECT user_rights FROM login WHERE username='$username'");
while($row = mysqli_fetch_array($getUser)){
$user_rights = $row['user_rights'];
}
} else {
include_once 'login.php';
exit();
}
?>
I am no coding professional by any means but I get the job done. However this mysqli is sort of new ground.
Hello PHPFreaks. I have one problem, that I've tried to fix for a day or two now. I need a function, that picks out a random row in a table, and returns one thing. I tried with, getting the max rows in the table, make a random number in the interval 0 to max rows, then select the random number, but it failed. I hope someone can help me out with this one? -Niixie This is my code, and I know it's pretty messy, because i fooled around with it for a day or two, so it's hard to find head or tail in it. Code: [Select] $query0 = sprintf("SELECT * FROM registertest"); $result = mysql_query($query0); if (!$result) { $message = 'Invalid query: ' . mysql_error() . "\n"; $message .= 'Whole query: ' . $query; die($message); } $nums = mysql_num_rows($result); $rand_nums = rand(0,$nums); $query1 = sprintf("SELECT question FROM registertest WHERE id='%i'", $rand_nums); $result1 = mysql_query($query1) or die(mysql_error()); if (!$result1) { $message = 'Invalid query: ' . mysql_error() . "\n"; $message .= 'Whole query: ' . $query; die($message); } $row = mysql_fetch_row($result1); mysql_free_result($result); mysql_free_result($result1); $_SESSION['registerquestion'] = $row; if(strlen($_SESSION['registerquestion'])!=0){return 1;}else{return 0;} i have been working with a website but only locally. i am now trying to put it online which is ok. when i was working with it locally i have been able to create multiple users which have different privileges to each page. for example i said one of my users can only read and the other can read write. the problem is when i have went to create these users online i can't seem to find the create user option in phpmyadmin. i am missing the obvious or will i have to code them in and if so can you direct me to a tutorial which shows me how. thanks in advance This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=323935.0 Hi all, I use a MySQL insert query of the following form: Code: [Select] <?php $insert1= mysql_query ("INSERT INTO tablename (H1, H2, H3) VALUES '$V1','$V2','$V3')"); ?> However, I encounter problems when $V1, $V2 or $V3 contain certain symbols, such as quotes ("'). What is the best way to avoid this? Thanks! I have a post.php that is suposted to run a mysql query, and it used to, but it won't anymore and I don't have the old file. Can someone just look see if there is something i'm missing? <?php //header("Location: ./?p=UCP"); setcookie("Errors", 0, time()-3600); // Connects to your Database mysql_connect("SERVER", "USER", "PASS") or die(mysql_error()); mysql_select_db("DB") or die(mysql_error()); if (isset($_POST['remove'])) { $id=$_POST['ID']; if($_POST['initals'] == "NLW") { if (is_numeric ($id)) { mysql_query("DELETE FROM `users` WHERE `users`.`ID` = $id LIMIT 1"); $error="<span style="; $error .="color:green"; $error .=">"; $error .= "User Removed."; $error .="</span>"; setcookie(Errors, $error, time()+20); } else { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "Please enter a valid ID"; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } } else { $error="<span style="; $error .="color:red"; $error .=">"; $error .="Initials are not correct"; $error .="<span/>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } } elseif (isset($_POST['submit'])) { //This makes sure they did not leave any fields blank if (!$_POST['username'] | !$_POST['pass'] | !$_POST['pass2'] ) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "You did not complete all of the required fields"; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } // checks if the username is in use if (!get_magic_quotes_gpc()) { $_POST['username'] = addslashes($_POST['username']); } $usercheck = $_POST['username']; $check = mysql_query("SELECT username FROM users WHERE username = '$usercheck'") or die(mysql_error()); $check2 = mysql_num_rows($check); //if the name exists it gives an error if ($check2 != 0) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "Sorry, the username is already in use."; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } // this makes sure both passwords entered match if ($_POST['pass'] != $_POST['pass2']) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= 'Your passwords did not match.'; $error .="</span>"; setcookie(Errors, $error, time()+20); echo $error; } // here we encrypt the password and add slashes if needed $_POST['pass'] = md5($_POST['pass']); if (!get_magic_quotes_gpc()) { $_POST['pass'] = addslashes($_POST['pass']); $_POST['username'] = addslashes($_POST['username']); $_POST['pass2'] = $_POST['pass2']; } // now we insert it into the database $insert = "INSERT INTO users (username, password, Human-Readable) VALUES ('".$_POST['username']."', '".$_POST['pass']."', '".$_POST['pass2']."')"; mysql_query("INSERT INTO users (username, password, Human-Readable) VALUES ('".$_POST['username']."', '".$_POST['pass']."', '".$_POST['pass2']."')"); $error="<span style="; $error .="color:green"; $error .=">"; $error .= "<h1>User Registered</h1> <p><h2>Thank you, the user has been registered - he/she may now login</a>.</h2></p>"; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location: ./?p=UCP'); } else { header('Location: ./?p=UCP'); echo $error; } ?> The remove function works but its the submit. Thanks in advanced I wasn't too sure if this should be in the MySQL help section so please (admin/mods) feel free to move this if you feel it's necessary. I'm attempting to connect to a URL through cURL that is being grabbed from a mysql table. The url within the table is: http://es-us.noticias.yahoo.com/ue-podr%C3%ADa-revisar-veda-crudo-ir%C3%A1n-en-pr%C3%B3ximos-124018543.html" When I plug this into firefox it works. When using it through cURL directly (see below) it works. Code: [Select] $url = "http://es-us.noticias.yahoo.com/ue-podr%C3%ADa-revisar-veda-crudo-ir%C3%A1n-en-pr%C3%B3ximos-124018543.html"; // create a new curl resource $ch = curl_init(); // set URL to download curl_setopt($ch, CURLOPT_URL, $url); // user agent: curl_setopt($ch, CURLOPT_USERAGENT, "MozillaXYZ/1.0"); // remove header? 0 = yes, 1 = no curl_setopt($ch, CURLOPT_HEADER, 0); // should curl return or print the data? true = return, false = print curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); // timeout in seconds curl_setopt($ch, CURLOPT_TIMEOUT, 60); // download the given URL, and return output $page = curl_exec($ch); However, when I grab the url from a table within mysql it does not work and no curl error (or any error for that matter) is returned. Code: [Select] $get_url_links = "SELECT * FROM tabe"; $url_link = mysql_query($get_url_links); $row = mysql_fetch_array($url_link); $url = $row['link']."<br />"; I'm suspecting this is some kind of encoding issue. I've tried $url = mysql_real_escape_string($url); --- before entering it into the table $url = mysql_real_escape_string($url); --- before calling cURL mysql_query("set names 'utf8'"); --- before inserting the url into the table I've also set the column table type to 'text'. Suggestions appreciated. I have a form where it ask the user to select the student ID, course ID, enter the grades and comments. The Student ID and CourseID is selected from a drop down menu, but when the data is sent to PHPMYADMIN it enters a 0 into the SID and CID How to I get it save the numbers which has been selected Hi guys I have two questions: Question 1: phpmyadmin If my host does not provide phpmyadmin and I want to install it myself, can I just download phpmyadmin and copy it to my public_html folder or is there another way to install it on my site?? Question 2: Email Script I have a script that sends an email to a system that sends out multiple sms's. The system works like this, I send an email to an address with an attachment called cellnumbers.txt with a list of all the cellnumbers. I must add a specific subject. When I send the email to my own email address, it comes correctly through. But when it is sent to the address of the server, no sms are received. I attached my script. Please take a look. Your help will be greatly appretiated. Thank you Hi guys I am working on adding a third party php members register and login into a clients web site but every time I try the regidter page is shows me this error message. Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'username'@'localhost' (using password: YES) in /home/cpassoc2/public_html/register-exec.php on line 15 Failed to connect to server: Access denied for user 'username'@'localhost' (using password: YES) This is what i have in the config.php page. <?php define('DB_HOST', 'localhost'); define('DB_USER', 'cpassoc2-memark'); define('DB_PASSWORD', '?????????'); password replaced define('DB_DATABASE', 'cpassoc2-me'); ?> I have set up the my SQL within the control panel of the site, So do i need to do any thing else???, what am i missing???. Mark..... Hello, First post here! I am using a script to store small files into a database. I know it is not highly recommended but this is the only solution I can find in this case. All seems fine when inserting but when retrieving all documents are corrupt. I am working with PHP 5 on Windows server. Part script after upload: (the document is uploaded to the server first and this is working fine) Code: [Select] if (!empty($_FILES)) { $folder = "kenya/docs_temp/";//including last / $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__); $targetPath = substr($targetPath,0,strrpos($targetPath, "uploadify")). $folder; $targetFile = str_replace('\\','/',$targetPath) . $_FILES['Filedata']['name']; $fileName = $_FILES['Filedata']['name']; $tmpName = $_FILES['Filedata']['tmp_name']; $fileSize = $_FILES['Filedata']['size']; $fileType = $_FILES['Filedata']['type']; $conn=odbc_connect('xxx','xxx','xxxx'); $content = file_get_contents($tmpName,true); $content = addslashes($content); if(!get_magic_quotes_gpc()){ $fileName = mysql_real_escape_string($fileName); } $file_info = pathinfo($_FILES['Filedata']['name']); $addDoc = "INSERT INTO tblfiles (file_name,file_type,file_size,file_content,file_extension) VALUES ('".addslashes($fileName)."','".$fileType."','".$fileSize."','".$content."','".$file_info['extension']."')"; odbc_exec($conn,$addDoc); } The the script to retrieve and output to the browser: Code: [Select] $conn=odbc_connect('xxxx','xxx','xxxx'); //get the document $getF = "SELECT * FROM tblfiles WHERE userId = '".$_GET['userId']."' AND fileId = '".$_GET['fileId']."'"; $rsF = odbc_exec($conn,$getF); $size = floor(odbc_result($rsF,'file_size')); $type = odbc_result($rsF,'file_type'); $name = odbc_result($rsF,'file_name'); $content = odbc_result($rsF,'file_content'); ob_end_clean(); header("Content-length: ".$size.""); header("Content-type: ".$type.""); header('Content-Disposition: attachment; filename="'.$name.'"'); echo $content; And finally here is the structure for the table: Code: [Select] CREATE TABLE `tblfiles` ( `fileId` int(11) NOT NULL auto_increment, `userId` int(11) NOT NULL, `file_name` varchar(100) NOT NULL, `file_type` varchar(100) default NULL, `file_size` int(11) default NULL, `file_content` mediumblob, `file_extension` varchar(50) NOT NULL, PRIMARY KEY (`fileId`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ; many thanks for any assistance. I have used the XAMPP installer to install php and MySQL locall on my computer. I also succeeded in setting the security for XAMPP pages, the MySQL admin user root and phpMyAdmin login. When I enter phpMyAdmin via the link in the XAMPP initial page I do however receive a red notification: phpMyAdmin configuration storage is not fully configured; some extensions are not activated. To find out click here. I have attached a screenshot showing three items which are not OK, shown in red. I looked up in the documentation, but could not find out. I hope someone can help. I don't even know if it is important to fix this problem. Regards, Erik Attached Files XAMPP2.jpg 41.08KB 0 downloads |
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