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PHP - Animate Leaving A Page Code Modification
Hi,
I have the following code which gives a fading out effect when clicking on links. I need to be able to disable it for anchor links so it is disabled when using # as the link.
Any ideas ?
/*
* Function to animate leaving a page
*/
$.fn.leavePage = function() {
this.click(function(event){
// Don't go to the next page yet.
event.preventDefault();
linkLocation = this.href;
// Fade out this page first.
$('body').fadeOut(400, function(){
// Then go to the next page.
window.location = linkLocation;
});
});
};
Thanks,
Scott.
Similar TutorialsI have used this same php contact form many times and never had this problem. I just checked it in online php code checker and comes up with no errors but when uploaded to the site and I got to test the form it goes to mysite.com/contact.php stuck on trailing code
\nReply-To: \"$name\" <$email>\nX-Mailer: chfeedback.php 2.03" ); header( "Location: $thankyouurl" ); exit ; ?>
It has me stumped I can't work it out.
The full code is:
<?
/*
CHFEEDBACK.PHP Feedback Form PHP Script Ver 2.03
*/
$mailto = 'contact@gmail.com' ;
$subject = "Contact Form" ;
$formurl = "http://www.mysite.com/contact.html" ;
$errorurl = "http://www.mysite.com/error.html" ;
$thankyouurl = "http://www.mysite.com/thanks.html" ;
$name = $_POST['name'] ;
$email = $_POST['email'] ;
$comments = $_POST['comments'] ;
$http_referrer = getenv( "HTTP_REFERER" );
if (!isset($_POST['email'])) {
header( "Location: $formurl" );
exit ;
}
if (empty($name) || empty($email) || empty($comments)) {
header( "Location: $errorurl" );
exit ;
}
if (get_magic_quotes_gpc()) {
$comments = stripslashes( $comments );
}
$messageproper =
"This message was sent from:\n" .
"$http_referrer\n" .
"------------------------- COMMENTS -------------------------\n\n" .
$comments .
"\n\n------------------------------------------------------------\n" ;
mail($mailto, $subject, $messageproper, "From: \"$name\" <$email>\nReply-To: \"$name\" <$email>\nX-Mailer: chfeedback.php 2.03" );
header( "Location: $thankyouurl" );
exit ;
?>
But when I look at the source code in browser I can see all of it is in red except for the last trailing bit which appears in black .
Edited by bmbc, 07 June 2014 - 03:54 AM. Hi again PhpFreaks, yet again I got a problem regarding coding. Hello Freaks! I am having problem with following code: <?php simplexml_load_string ('?xml version="1.0" encoding="utf-8"?>'); php?> This code is giving me following error Parse error: syntax error, unexpected '<' in public_html/wp-content/plugins/pluginnamehere/whatever.php on line 665 I know there is only a minor bracket problem that causing me this error. I would be helpful to you if you can modify it for me Thanks I have a WYSIWYG on my site and somehow the users input it in the database with this at the end Code: [Select] <p The p tag is left open and messing up the styling on the page How can I fix it so this tag is removed or closed? Is there a php function I can use? Can someone tell me what's wrong with this? I'm trying to remove any folders listed in the url but maintaining the rest of the structure.... Example: http://example.com/test/test.php changes to http://example.com/test.php My current config is removing the folder but leaving a double slash - i.e. http://example.com//test.php Any help is greatly appreciated! Code: [Select] <?php function modify_url($mod) { $url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']; $query = explode("/", $_SERVER['QUERY_STRING']); // modify/delete data foreach($query as $q) { list($key, $value) = explode("/", $q); if(array_key_exists($key, $mod)) { if($mod[$key]) { } else { $url = preg_replace('/&?'.$key.'wp'.$value.'/', '', $url); } } } // add new data return $url; } $url = modify_url(array('' => '')); ?> <?php echo $url ?> This topic has been moved to Other. http://www.phpfreaks.com/forums/index.php?topic=309813.0 I want to create an animation using an image that refreshes every hour hosted at this url: http://www.bungie.net/stats/reach/nightmap.ashx What is the best way to store the images and then animate(loop) the 24 most recent images? Should I use a mysql database to store it or something else? What are your thoughts? Thanks I am trying to make a simple vertical scrolling slideshow type page. I have 1 div that is 100% width and height of the body and inside that 4 divs that are 100% w&h one below the other. In each "slide" div is an input button with an onclick call to a JavaScript function that uses jquery animate and scrolltop to move to the next div. Moving from the first to second is OK. It will not move from second to third. If I set each inner divs height to 90%, I can see the third div's next button. Clicking that moves the third slide to the top, though it is supposed to move the forth slide to the top. Not sure what I'm missing? I hope my attempt to paste the code on my note 3 works OK! Thanks for even looking! Nick <code> <html> <head> </head> <body style="margin:0px;padding:0px;"> <style> .a_slide { width:100%;height:100%;background-color:blue; } .b_slide { width:100%;height:100%;background-color:green; } .c_slide { width:100%;height:100%;background-color:blue; } .d_slide { width:100%;height:100%;background-color:green; } </style> <div style="width:100%;height:100%;overflow:hidden;margin-left:auto;margin-right:auto;" id="container" name="container" class="container"> <div class="a_slide" id="a_slide">a <input type="button" onclick="move(this.name);" name="b_slide" value="Next Page"> </div> <div class="b_slide" id="b_slide">b <input type="button" onclick="move(this.name);" name="c_slide" value="Next Page"> <input type="button" onclick="move(this.name);" name="a_slide" value="top"> </div> <div class="c_slide" id="c_slide">c <input type="button" onclick="move(this.name);" name="d_slide" value="Next Page"> <input type="button" onclick="move(this.name);" name="a_slide" value="top"> </div> <div class="d_slide" id="d_slide">d <input type="button" onclick="move(this.name);" name="a_slide" value="top"> </div> </div> <script type="text/javascript" src="http://ajax.googleap...n.js"></script> <script type="text/javascript"> function move(to_who) { $('.container').animate({scrollTop: $("."+to_who).offset().top},'slow'); }; </script> </body> </html></code> This code works when theres no predefined value however I'm trying to modify it in case there IS a value from the DB which is from the " . $row2['content'] . " data. Code: [Select] echo "<select name=" . $row2['ID'] . " id=" . $row2['ID'] . " class=dropdown biofield title=" . $row2['fullName'] . " >"; echo "<option value= >None</option>"; if ($styleID == 1 || $styleID == 2 || $styleID == 6) { $charactersQuery = " SELECT characters.ID, characters.characterName FROM characters WHERE characters.styleID = 3 ORDER BY characters.characterName"; } else { $charactersQuery = " SELECT characters.ID, characters.characterName FROM characters WHERE characters.styleID IN (1,2,6) ORDER BY characters.characterName"; } $charactersResult = mysqli_query ( $dbc, $charactersQuery ); // Run The Query while ( $row3 = mysqli_fetch_array ($charactersResult, MYSQLI_ASSOC)) { echo "<option value=" . $row3['ID'] . ">" . $row3['characterName'] . "</option>\r"; } echo "</select>"; I normally use something like this but with the other code not sure how to modify it to work the same way. Code: [Select] while ( $champion_row = mysqli_fetch_array ( $charactersResult, MYSQL_ASSOC ) ) { print "<option value=\"".$champion_row['ID']."\" "; if($champion_row['ID'] == $row['champID']) { print " SELECTED"; } print ">".$champion_row['characterName']."</option>\r"; } I am currently trying to build a contact form for a website. I have been given a script to use that was used on another site but it has an iff statement in it to change the strEmail according to the location and requirement. My first real attempt to mess with MySql. Keep getting a syntax error and I am quite confused. Error: Code: [Select] Parse error: syntax error, unexpected '}' in /home/a8152576/public_html/MemberSystem/install1.php on line 68 Here is my php code: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <h2><center>Fill in the following info properly to install required databases.</center></h2> <p> <label>Host: <input type="text" name="host" id="host" /> </label> </p> <p> <label>Database User: <input type="text" name="dbUser" id="dbUser" /> </label> </p> <p> <label>Database Password: <input type="text" name="dbPass" id="dbPass" /> </label> </p> <p> <label>Desired Admin Username: <input type="text" name="adminName" id="adminName" /> </label> </p> <p> <label>Desired Admin Password: <input type="text" name="adminPass" id="adminPass" /> </label> </p> <p> <label>Email: <input type="text" name="adminEmail" id="adminEmail" /> </label> </p> <p> <input type="submit" name="submitBtn" id="submitBtn" value="Submit" /> </p> </form> <?php if(isset($_POST['submit'])){ $hostName = $_POST['host']; $dbUserName = $_POST['dbUser']; $dbPassword = $_POST['dbPass']; $adminUserName = $_POST['adminName']; $adminPassword = $_POST['adminPass']; $email = $_POST['adminEmail']; $sqlLink = mysql_connect('$hostName','$dbUserName','$dbPassword'); if(!$sqlLink){ die('Could not connect: ' .mysql_error()); mysql_close(); } else { $queryCreate = 'CREATE DATABASE member_db'; echo 'Connected successfully!'; if(mysql_query($queryCreate,$link)){ echo 'Created database!'; mysql_select_db('member_db'); $createAdminTable = "CREATE TABLE " .$adminUserName. " (`secLvl` tinyint(1) default NOT NULL,`rank` tinyint(2) default NOT NULL,`username` varChar(32) NOT NULL UNIQUE,`password` varChar(32) NOT NULL,`email` varChar(32) NOT NULL UNIQUE"; $insertAdminInfoQuery = "UPDATE " .$adminUserName. " SET `secLvl` = '5', `rank` = '10', `username` = '$adminUserName', `password` = '$adminPassword', `email` = '$email' WHERE '$adminUserName' LIMIT 1"; mysql_query($createAdminTable) or die("ERROR: " .mysql_error()); mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error()) } else { echo 'Error: '.mysql_error(); } } } ?> </body> </html> You can even see the error on this web page directly: http://www.ptcptc.info/MemberSystem/install1.php Thanks, Brandon I am trying to get this script to display the date like Dec 17, 2010 and have the search function work too. If I try to change the date the search malfunctions and if I take the date function away the date is 2010 12 17 I thought we had this nailed down the other day but in my excitement I neglected to test the city search. Here is the script. <?php $find = trim($_GET['find']); $field = $_GET['field']; if($find && $field) { // we have search form submitted // check for values to prevent sql injection $valid_fields = array("venue_state", "venue_city", "start_date"); if(!in_array($field, $valid_fields)) die("Error: Invalid field!"); //connect mysql_connect("localhost", "arts_cshow", "TrPh123Yuo") or die(mysql_error()); mysql_select_db("arts_shows") or die(mysql_error()); echo "<h2>Search Results for $find in $field</h2>\n"; $find = addslashes($find); $result = mysql_query("SELECT * FROM craft_shows WHERE $field LIKE '%$find%'"); if(mysql_num_rows($result) == 0) { echo "<p>0 matches found.</p>"; } else { echo "<table><tr><td class=\"shows\">"; $sql = "SELECT *, DATE_FORMAT(`start_date`, '%b %e, %Y') AS s_date FROM craft_shows"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { echo "<a href='/show_submits/show_detail.php?id={$row['id']}'>Details</a>\n"; echo $row['venue_state'] . " {$row['s_date']} {$row['show_name']} {$row['venue_city']}<br>\n"; } echo "</td></tr></table>\n"; } } ?> thanks Thank you for writing this script. It has been most helpful in doing a search for a website I manage. Everything is working fine but I would like some help in modifying the "$results[] = " line. For instance, I would like to show or hide the address of a business if a data value is set to 1 if set to 0 then hide. Same for the business web address. if ( $row_memberrs['WebAddress'] != NULL ) { echo <a href=\"{$row['WebAddress']}\" target=_blank>Visit our website</a>; } I am a newbie to php and would appreciate any help you can give me. Here is a link to the search page http://www.wildwoodba.org/searchsite.php If it is not too much trouble I would like to hide the check boxes and make it search the body, title or disc for the words entered. Thank you for your help. This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=327718.0 I have a table in my database which stores lot of file names & file path. iam currently listing the files on the basis of its uploaded date (stored in databse) but I want to list it on the basis of its file modification time. How i can do it ?? my current sql statement is Code: [Select] $sql = mysql_query("SELECT * FROM `files` WHERE `cid` = '$types' ORDER BY `uploaded` DESC LIMIT $start,$limit"); anyone can help me ?? Hi all. I have the following function which auto-generates a form based on a database table. What I want to do is "cancel" the function if the table doesn't exist. The function as is... function build_form($table_name){ $sql="SELECT * FROM $table_name"; $result=mysql_query($sql); $num=mysql_num_rows($result); $i=0; echo "<form method=\"post\" action=\"/php/process_data.php\">"; echo "<input type=\"hidden\" name=\"selected_table\" value=\"" . $table_name . "\"/>"; echo "<table>"; echo "<tr><td colspan=\"2\" style=\"font:1em arial;font-weight:bold;text-align:center;\">Input Form: " . $table_name ."</td></tr>"; $field_names=array(); while ($i < mysql_num_fields($result)){ $fields=mysql_fetch_field($result,$i); echo "<tr><td>" . $fields->name . "</td><td><input type=\"text\" size=\"30\" name=\"" . $fields->name . "\" /></td></tr>"; $i++; }; echo "<tr><td colspan=\"2\" style=\"text-align:center;\"><input type=\"submit\" value=\"Submit Data\" style=\"width:75%\" /></td></tr>"; echo "</table>"; echo "</form>"; }; Would something like this work? (note lines 3-5) function build_form($table_name){ $sql="SELECT * FROM $table_name"; if(!$sql){ return; }; $result=mysql_query($sql); $num=mysql_num_rows($result); $i=0; echo "<form method=\"post\" action=\"/php/process_data.php\">"; echo "<input type=\"hidden\" name=\"selected_table\" value=\"" . $table_name . "\"/>"; echo "<table>"; echo "<tr><td colspan=\"2\" style=\"font:1em arial;font-weight:bold;text-align:center;\">Input Form: " . $table_name ."</td></tr>"; $field_names=array(); while ($i < mysql_num_fields($result)){ $fields=mysql_fetch_field($result,$i); echo "<tr><td>" . $fields->name . "</td><td><input type=\"text\" size=\"30\" name=\"" . $fields->name . "\" /></td></tr>"; $i++; }; echo "<tr><td colspan=\"2\" style=\"text-align:center;\"><input type=\"submit\" value=\"Submit Data\" style=\"width:75%\" /></td></tr>"; echo "</table>"; echo "</form>"; }; This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=355561.0 Hello Coder Guys, I need a small help from you. I want to list all files & directories based on last file modification time of server. I want to list new files as first & old files as last. Consider "files" as the directory name which contains all files & directories. Please make the php code to display all files & directories from "files" directory based on last file modification time of server. Thanks IN Advance ! This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=332575.0 Hey everyone... I'm having trouble with code on my website and needed some input. Can someone help? When I press the send code on a contact us page the following pops up Warning: Cannot modify header information - headers already sent by (output started at /home/content/XXXXXXXXXXXX/XXXXXXXXXXXX/html/XXXXXXXXXXXX/contact_us.php:32) in /home/content/XXXXXXXXXXXX/XXXXXXXXXXXX/html/XXXXXXXXXXXX/contact_us.php on line 192 I just hid some of the information with XXXXXXXXXXXX since I didn't know what to post |
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