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PHP - Passing Object As Arg To Function
function chk_error($site_mode, $obj)
{
if( $site_mode == 'dev' )
{
echo'Error : ('. $obj->errno .') '. $obj->error;
}
}
chk_error($site_mode, $stmt);
the above is not working for me. it echos out the text but no values for errno and error. what am i doing wrong?
Similar TutorialsHi Guys, I'm new to OOP. I've mastered some basic syntax, but am wondering about an issue of design. To clarify in this example, I'm simply looking to pull Team data from a Database (I've not included my db class (PDO wrapper) although I know it is working. Although I have seen this sort of method below in a book (I believe and on the net) and it does work, I cannot help thinking coupling the DB class so tightly with the Team Class isn't a great approach. Can anyone give me feedback as to whether my approach is valid? While I can see the negative issue of tight coupling (i.e. changes to any database method would require multiple changes in Team (as team methods were added), I cannot really see an alternative way of doing this? I guess this is an issue of a design pattern or more advance OOP. Can anyone suggest an alternative way and/or more reading on making the coupling looser while still achieving my objectives? Should, for example, all DB functionality in getName be done during implementation? I initally thought pushing all db related functionality inside a Team method was wise and the best way then to add further methods, i.e. getResults method would be similar to getName but obviously with a different query and processing afterwards inside Team, but now I wonder if all should be in the implementation, or is there another approach? Thanks in advance.
// create team class
class Team {
private $db;
private $team_name;
private $team_id;
private $result;
// in constructor lets pass DB object
public function __construct($db) {
$this->db = $db;
}
//function to get team name
public function getName($team_id) {
$this->team_id = $team_id;
$this->db->query("SELECT team_name, nickname, founded FROM club WHERE team_id=:teamid");
$this->db->bind(':teamid', $this->team_id);
if ($result = $this->db->single());
{
return $result[];
}
}
}// end class
// Implementation
$team_id=1; //passed from user input
// First Create Db Object with correct passed variables
$database = new Database($server,$db_type);
// Invoke DB connect method
$database->connect();
// Now create Team object, pass it database object
$team = new Team($database);
// call Team method
$team_display = $team->getName($team_id);
// close db
$database->closedb();
I'm practicing my OOP skills and want to pass $_POST values to an Object's Instance Variables when a form is submitted. This is what I have so far... index.php Code: [Select] <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> </head> <body> <!-- Registration Form --> <form method="post" action="results.php"> <!-- Registration Fields --> <div> <label for="email">E-mail:</label> <input type="text" name="email" class="txt" id="email" /> </div> <div> <label for="password">Password:</label> <input type="password" name="password" class="txt" id="password" /> </div> <div> <input type="submit" name="btnSubmit" value="Register" class="btn" id="btnSubmit" /> </div> </form> </body> </html> results.php Code: [Select] <?php include ('classes/FormHandler.class.php'); ?> FormHandler.class.php Code: [Select] <?php class HandleForm { // Define Variables. private $email; private $password; public function __construct($email, $password){ $this->email = $email; $this->password = $password; } } ?> I'm a little stuck on how I initialize the Instance Variables in the Constructor?! TomTees I don't know why it won't work.. as the topic titles says that I am trying to pass a mysqli object to a property in another class but it keeps me getting an error.
here's the code for the mysqli object that i want to pass to another class
class ConnectMe2Db
{
public $dbname = 'somedatabase';
public $dbuname = 'root';
public $dbpass = '';
public $dbhost = 'localhost';
function __construct()
{
$mysqli = new mysqli($this->dbhost,$this->dbuname,$this->dbpass,$this->dbname)
or die ('ERROR: '.$mysqli->connect_errno);
return $mysqli;
}
# OTHER CODES...
}
and here is the class that i want the Mysqli object to pass to:
class DatabaseUsers
{
private $dbconnection;
function __construct()
{
$this->dbconnection = new ConnectMe2Db();#mysqli object will be passed to this attribute '$dbconnection'
}
public function session($username, $password)
{
$UserName = mysqli_real_escape_string($this->dbconnection,$username);
$Password = mysqli_real_escape_string($this->dbconnection,md5($password));
$querry = "SELECT * FROM trakingsystem.login WHERE username='$username' and password='$password'";
$result = mysqli_query($this->dbconnection,$querry) or die (mysqli_error($this->dbconnection));
$count = mysqli_num_rows($result);
$row = mysqli_fetch_array($result);
if ($count > 0)
{
#some code here
}
}
#some other code here
}
and this outputs 4 errors:
#outputs 2 of these: Warning: mysqli_real_escape_string() expects parameter 1 to be mysqliand some mysqli_query() expects parameter 1 to be mysqli mysqli_error() expects parameter 1 to be mysqliis there something wrong with the logic that I've made? please help thanks I everyone, I'm developing a small MVC framework for my personal work, now, in order to have access from all the classes to certain variables I've created a registry class, for this to work I have 2 options: 1.- passing every time the registry object to the constructor class(controllers, models, etc) or 2.- create in the registry static set and get so I can reach the variables by Registry::set(name, value) and Registry::get(name) My question is, which one of this two options takes less resources(is faster)? I hope anyone can help me with this, thanks in advance Help I am trying to pass a php variable into a javasript function. Here is my code.
<a href="<?php echo $row['track']; ?>" download="<?php echo $row['track']; ?>" onclick="myhit(<?php echo $row['track']; ?>)">Download</a>
<script>
function myhit(top){
alert(top);
}
</script>
the javascript function is never called
Mon Aug 24, 2020 2:41 pm I'm using php_serial.class.php, called once
require_once("php_serial.class.php");
and call it $serial: $serial = new phpSerial;
The above are in a global.php file that sets up the serial com parameters.
Function checkInput($serial){
And one in the Function: $read = $serial->readPort();
This throws an error: "PHP Fatal error: Uncaught Error: Call to a member function readPort() on string" I have a odd one here, two classes and one which calls another class. I want to pass all of the parameters from the array as seperate variables into the next function. Hope my example explains a little better class master{ public function __call($name, $args) { second->$name($args); }}class second{ public function example($param1, $param2) { }}master->example($param1, $param2);() ( i know its not accurate php, but should get the idea of what im trying to do) I need to do something with the following line second->$name($args); Where param1 and param2 will be seperated out Is there a php function which you can tell it the class, method name and pass it an array of parameters? Thanks Code: [Select] function display_details($name, $department="sales", $sex="male") { return "You are {$name} from {$department} and you are {$sex}"; } I need to use the default value for $department, but none of the below work. How do I do it? echo $display_details("Sally", NULL, "female"); // sets $department as empty/blank echo $display_details("Sally", "", "female"); // sets $department as empty/blank echo $display_details("Sally", , "female"); // PHP error Firstly i am new to php.Iv currently got this while loop iterating through a database drawing polygons from the info in the datatable.each polygon has its own id stored in the datatable and with the on click event i am trying to just output to the screen the specific id of the polygon clicked on.It looks ok to me but it doesnt work for some reason. Below is the loop and the function it is trying to call. /////////////////////////////////////////////////////////////////////// <?php while($info = mysql_fetch_array( $data )){ echo "<polygon fill=".$info['fill_colour']." stroke=\"black\" id=".$info['id']." onclick=\"buildingClick(id)\" points=".$info['coordinates']." />"; } ?> ///////////THIS IS THE FUNCTION/////////////////////////// <?php function buildingClick($id) { echo "building id : {$id}"; } ?> /////////////////////////////////////////////////////////////////// If anyone could help it would be hugely appreciated. Eoin Hello everyone, Pretty much what I am trying to do is run a query and based of the queries result, return a string - as of now it is turning up blank and cant seem to pass any strings through the function. Current function: function addNewBookmark($hash,$url,$title,$username){ Code: [Select] $query = "INSERT INTO bookmarks (hash,url,title,username) VALUES '".md5($hash)."', '".$url."', '".$title."', '".$username."')"; $result = mysql_query(query, $this->connection); $message = ''; if(mysql_affected_rows($this->connection)!=1) { $message = 'This URL already exists in the database!'; return $message; } else $message = 'The URL was shared!'; return $message; } The above code seems to run fine, just cant seem to pass a string...read that you can possibly use a __toString function? but that keeps throwing errors when I try to work with it. Thanks all! Ok, starting around line 137 with the functions..... Commented well. Just not sure If im doing it right. Any help greatly appreciated. Basic stuff and still learning. Just trying to figure out if Im passing by reference correctly or if not how to do it. Thanks. php File is attached but heres a snippet. Thanks in advance. Peace, Adam // The grand total and the item total need to be passed BY REFERENCE. function show_table_contents($cart_items, $table, &$grand_total, &$item_total) http://pastebin.com/DbHQSYd7 Been stumbling my way through OOP and seem to be understanding it for the most part (I think..) But I've got a couple questions / kinks that I can't seem to work out. a) How do I return a variable from a class so that a different class has access to it (meta_data) b) I'm getting a "$this" cannot be redefined error (which I know why, but I don't know how to fix)) c) How do I call a function from within one class, where the function resides in another class, AND pass it variables? Any help would be greatly appreciated I've tried to Google warrior A and I think I can figure that one out, but B and C are proving to be the real stumbling blocks. I work with a large codebase and I have this situation come up fairly often:
the legacy class has large objects such as:
$design->motor->dimensions->a; $design->motor->dimensions->bd; $design->specifications->weight; $design->data->height; //etcWhen I create a new class, that class sometimes operates on the specific data, so say:
class MyClass
{
public function compute($weight, $height, $a)
{
//stuff
}
}
//and I call this for example as such:
(new MyClass())->compute($design->specifications->weight, $design->data->height, $design->motor->dimensions->a);
CONS: Potential issue: if design specs change and I need to change things parameters in "compute" function, I need to "re-key" the variables I pass to the function, and adjust things accordinly in MyClass as wel.
PROS: only the exact data is being passed, and this data can come from anywhere it is viable, so in effect the function is fairly well separated, I think.
Alternative option for me is to pass the entire design object, i.e
class MyClass
{
public function compute(&$design) //can also be done via DI through a setter or constructor.
{
print $design->specifications->weight;
print ($design->data->height + $design->motor->dimensions->a);
//stuff
}
}
(new MyClass())->compute($design);
PROS: In this case when things change internally in which variables are needed and how things are computed, I only need to change the code in compute function of the class itself.
CONS: MyClass now needs to be aware of how $design object is constructed.
When it comes to this parameter passing, and Dependency Injection like this in general, does Computer Science advocate a preference on this issue? Do I pass the entire object, or do I pass only the bits and pieces I need?
Hey guys, I want to pass the unique id of a node to a function when that image is clicked. Actually i am a newbee in php so don't know what to search about or where to look for it,but find this place and you all guys so helpful so i am asking for a guide here Ok, so I don't really understand a lot about OOP. I was given a two big files full of classes and functions. We were hand coding this file for each use. My objective was to make an array we could use to ease the pain of coding these features. Here is an example of what is happening to me. Can someone advise me conceptually on what to do. Code: [Select] include('Tons of files included here'); $myarray = array( 0 => array("question" => "answer"), 1 => array("question1" => "answer1") ); class BigClass { var $a var $b function fiststep(){ global $myarray; foreach($myarray as $anarray) { $this->$anarray = new includedfunction1($anarray["question"]); $this->$anarray->Values = array(array("yes", "yes"), array("no", "no")); $this->$anarray->Multiple = true; } } function nthstep(){ global $myarray; foreach($myarray as $anarray) { $this->$anarray->astep(); // Error occurs: Call to a member function on a non-object } } } include('Tons of files included here'); There seem to be a number of steps that occur in one of the 10-20 include files before the data comes back to the nthstep. Once it comes back. I cannot seem to get it to be recognized as an object. If I were to manually type out the contents of $anarray. I get NO error. I am very over my head. Does anyone have a conceptual idea of my issue? ERROR 0 Fatal error: Call to a member function execute() on a non-object ... i've tested the $mysqli and $stmt, both are objects, i have other requests that work well and are built the same way (copy - paste) all vars on the query are also ok. There are working functions over and under this part of my code, if i remove it everything works fine. Code: [Select] $query2 = "INSERT INTO TABLE_NAME(accountSmtp, passwordSmtp, merchantID, adsPrice, adsWidth, adsHeigh, adsAmount, email, emailFrom, adsSense) VALUES('$gmailUser', '$gmailPassword', '$merchantID', '$prix', '$width', '$height', '$adsAmount', '$email', '$from', '$sense')"; if (!$stmt = $mysqli->prepare($query2)) { printf("Erreur : %d.\n", $stmt->errno); print_r($query2); } /* execute statement */ $stmt->execute(); //close statement $stmt->close(); This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=348942.0 I am trying to pass a variable from inside of a function in a file that is included eg include.php Code: [Select] <? function noms(){ $foobar = "apples"; } ?> main.php Code: [Select] <? include("include.php"); noms(); echo "these ". $foobar. " are most delicious... OM NOM NOM"; ?> I am essentially using a include file for a mysql connection and based on the connection outcome i am either setting a value to true or false. It prints "Connected succesfully" and what not just fine, but, after that it wont pass on the variables data. I know its the function because, it passes the data if i put the variable before the function... i just dont get it.. any help would be great. Thanks. Ansel I am getting this error while building OOP portal.
Fatal error: Call to a member function count() on a non-object in C:\Users\Rishi\Documents\xampp\htdocs\PDO\Pitch_It\index.php on line 6
My index.php file:
<?php what's wrong in this line $tpl->set('main_content',set_block($heading,'center',$err_tpl->fetch(load_template('error.tpl')))); |
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