PHP - Server Unable To Resolve Simple Php-info - File. Bug Or Feature

Hey guys i am writing a code which will get data frm the user and then write a file in my server and well sadly i am really confused with the annoying errors and warnings i am getting please help here is my code
<?php
//This File Gets the data from the chat setup form and then writes the chat file or edits it 
  
 //Get Data from the form
$cname=$_POST['cname'];
$nicklen=$_POST['nicklen'];
$msglen=$_POST['msglen'];
$pm=$_POST['pm'];
$msgh=$_POST['msgh'];
$aname=$_POST['aname'];
$pass=$_POST['pass'];
$cheight=$_POST['cheight'];
$cwidth=$_POST['cwidth'];
$prcadmin=$_POST['prcadmin'];
$cas=$_POST['cas'];
$frznick=$_POST['frznick'];
$sm=$_POST['sm'];
$id=$_COOKIE["id"];
//Check if the cookie id is empty
if (!isset($id))
{
header( 'Location: www.techbreeze.in/mychat/chat-add.html') ;
}
//Check if any field is empty and redirect to setup page if empty
if ((isset($cname))&&(isset($nicklen))&&(isset($msglen))&&(isset($pm))&&(isset($msgh))&&(isset($aname))&&(isset($pass))&&(isset($cheight))&&(isset($cwidth)))
{
if ((is_numeric ($nicklen)) && (is_numeric ($msglen))&&(is_numeric($pm))&&(is_numeric($msgh))&&(is_numeric ($cheight))&&(is_numeric ($cwidth)))
{
//Start writting data into the file
                        $str1=";";
                $str2 = ".php";
                $str4 = "\n";
               
$File = $id . $str2;
$fh = fopen($File, 'w') or die("can't open file");
               
       $stringData = "<?php\n";
                fwrite($fh, $stringData);
               
                $strt1= "require_once /mychat/src/phpfreechat.class.php;\n";
                $stringData = $strt1;
                fwrite($fh, $stringData);
                             
                $strt1='$params["serverid"]    =';
                $stringData = $strt1 . $id . $str1 . $str4;
                fwrite($fh, $stringData);
                fclose($fh);


$strt3 = "$params";
$stringData = $strt3;
fwrite($fh, $stringData);
fclose($fh);
}
else
{
echo "Only numeric Inputs allowed for the fields";
echo  "<br><br><br>";
echo "Enter the maximum length of nick";
echo  "<br>";
echo "Maximum Lenth of message";
echo  "<br>";
echo "Max number of Simultaneous PM";
echo  "<br>";
echo "No. of msg to be stored in history";
echo  "<br>";
echo "Height of the Chat Room";
echo  "<br>";
echo "Width of Chat Room";
echo  "<br><br><br>";
echo "Please Fill them up Carefully!";
echo "<meta HTTP-EQUIV='REFRESH' content='6; url= http://www.techbreeze.in/chat-setup.html'>";

}
}
else
{
echo "You Have one or more incomplete Field";
echo  "<br>";
echo "Please Fill them up Carefully!";
echo "<meta HTTP-EQUIV='REFRESH' content='2; url= http://www.techbreeze.in/chat-setup.html'>";
}

       ?>

ok now the error i am getting is Quote

Warning: fclose(): 3 is not a valid stream resource in /home/techbr/domains/techbreeze.in/public_html/mychat/chatcreate.php on line 52

Any ideas as to what i should do and why i am getting this error.

In the given code below I am getting this error
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\samples\getcustomers.php on line 20
WHY?


Code: [Select]
<?php
 $value = $_GET["q"];
  $con = mysql_connect('localhost', 'root', ''); 
  //db_connect();
  if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
  $db_selected = mysql_select_db("ajaxDb",$con);
  $sql = "SELECT * FROM 'cutomers' WHERE Name = '".$value."'";
 // echo $sql;
 $result = mysql_query($sql);
  echo "<table border='1'>
<tr>
<th>Name</th>
<th>Address</th>
<th>Country</th>
</tr>";
        
  while($row = mysql_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['Name'] . "</td>";
  echo "<td>" . $row['Address'] . "</td>";
  echo "<td>" . $row['Country'] . "</td>";
  echo "</tr>";
  }
  echo "</table>";
  mysql_close($con);
?>

Hi. I am trying to create a simple video file server. I finished the skeleton of it but when it came to creating the multitude of pages I realized that there could be an easier way to do it.   I started out basically getting the folder names in the server then printing them on the page.

<?php
$dirs = glob("*", GLOB_ONLYDIR);
echo '<ul>';
foreach($dirs as $dir)
{
	$forbidden_folders = array("not4u", "ignore", Styles);
	$filename = str_replace($forbidden_folders, '', $dir);
	if (!empty($filename))
	{
    echo '<li><a href="'.$dir.'">'.$dir.'</a></li>';
	}
}
echo '</ul>'
?>

Then I created in each of the folders with files a php file with this code:

<?php

function date_sort_desc($a, $b)
{
  preg_match('/\w+ \d{4}/', $a, $matches_a);
  preg_match('/\w+ \d{4}/', $b, $matches_b);
  $timestamp_a = strtotime($matches_a[0]);
  $timestamp_b = strtotime($matches_b[0]);
  if ($timestamp_a == $timestamp_b) return 0;
  return $timestamp_a < $timestamp_b;
}

$files = array();
$dir = opendir('.');
while(false != ($file = readdir($dir))) {
        if(($file != ".") and ($file != "..") and ($file != "index.php")) {
                $files[] = $file;
        }   
}

natsort($files);

$i = 0;
foreach($files as $file) {
$i++;
$string = str_replace("TV Show Name S1 E$i - ", '' , $file);
        echo '<div><a href="../Discriptions/'.$file.'.php">'.basename($string, '.m4v').'</a></div><br>';
}
?>

This opens up a php file with the same file name as the file to be played containing the episode's thumbnail and description. That file then contains a link pointing back to the real file. The problem here is that I'd have to make a new php file for every file in my collection. I'm wondering if there's somehow a way to simplify all of this.
Edited by chrisyroid, 11 August 2014 - 12:13 AM.

Hi    Im trying to make a simple connect from my centos server to my test domain. I have disabled the firewall on the Windows Server & Centos. Installed php-ldap.x86_64 : A module for PHP applications that use LDAP   print scr from my AD     The ERROR i get:

Warning: ldap_bind(): Unable to bind to server: Can't contact LDAP server in /var/www/html/edit/ldap.php on line 16
LDAP bind failed...

I can telnet from Centos terminal too the DC fine. : telnet dc1.devlab.local 389  

Hi all, I'm very new to the wonderful world of php, so I'd appreciate any and all help in the matter. I've greatly simplified the code below to hopefully help you in helping me. Thanks!

Ok, so I'm integrating a very simple message board feature into my site. The basic idea is that people post a comment, and have the option of replying to existing comments. I'm definitely not looking for a complete forum; just something that allows users to post and reply.

I've tackled the posting bit easily enough. I have a form. Users fill in the form and the message, along with user information, is sent to a MySQL database. The information includes the username(Poster), the message(Message), an id that corresponds to the topic in question(Messid), a unique ID code for the message itself (ID), and a number of other variables like date and rank.

I then use a while statement to bring up all of the messages that pertain to a particular topic; The output will only show messages that share the same Messid, and they are arranged in terms of descending ID:
Code: [Select]
<?
while($row = mysql_fetch_array($resultcomments))
  {
    $poster=$row['Poster'];
  $message= $row['Message'];
 $ID=$row['ID'];

echo $message.$poster.$ID;

}


 So far, so good. What I want is for users to be able to click on any one of the particular messages, and post a response comment that will appear directly below the message to which it responds. Any ideas how I might go about such a task?

So far, I've created a new MySQL table that corresponds to these "subcomments". Each subcomment has a "subID" that corresponds to the ID of the message to which it responds. By including a while statement within the while statement above, I can successfully list all of the subcomments that correspond to a message directly below it. The problem, of course, is that I have to insert the subID values manually in php_my_admin. I'm hoping there's a way for php to automatically detect the ID value of the message in question...

Many many thanks for any assistance I can get. Once this revolution in communication makes me a billionaire, I will be certain to reward you most properly. Thanks again.