PHP - Echo Php Page In Iframe

Hi, I have this snippet in my page:

<?php echo $EM_Booking->get_price(true) * $EM_Booking->get_spaces(); ?>

The page executes with no hitches except the price is not multiplied by the spaces. I get and echo of "0".   I'm new to this. Any help would be greatly appreciated and thanks!

Need help with some whiles, etc., and .php page refreshes.

$num; Comes from mysql_num_rows from a database table's regular 'select'. And gets the row id numbers for every row that the id numbers are listed in order.

$totalrows comes from another select but is select * instead. And pulls the total rows in the whole table instead there are 49 rows in the whole table.

I'm trying to get the page to show 5 table rows at a time like the following, but then when the page is still open on next page refresh to show the next 5 rows and continue that way.

This following:


Quote

PHP Code:
<?php
$i=$num;
if
($num == 5);
{echo "The number is " . $num . "<br />";}
do
  {$i = $i + 5;
echo "The number is " . $i . "<br />";
  }
while ($i<$totalrows);
?>



Brings up these results:
The row number is 10
The row number is 15
The row number is 20
The row number is 25
The row number is 30
The row number is 35
The row number is 40
The row number is 45
The row number is 50

Shows all these on the page at the same time. I'm trying to get these to only show the 5 rows after every page refresh instead. Please let me know how to do that, and whether it can be done without any cookies.

I don't know if there is a better way to show the first 5 separate like I have it.

Thank you very much for your help.     

i have built pages that paginate with 10 rows per page (some pages show more but for the moment i want to focus on this particular page)

//Define Some Options for Pagination
$num_rec_per_page=10;
if (isset($_GET["page"])) { $page  = $_GET["page"]; } else { $page=1; }; 
$start_from = ($page-1) * $num_rec_per_page;

$results = mysql_query("SELECT * FROM `ecmt_memberlist` WHERE toonCategory='Capital' AND oldMember = 0 ORDER BY CONCAT(MainToon, Name) LIMIT $start_from, $num_rec_per_page") or die(mysql_error());

	$results_array = array();
	while ($row = mysql_fetch_array($results)) {
    	$results_array[$row['characterID']] = $row;
}

The above sets the variables for the pagination and below the results are echo with 10 rows per page   then i show the pagination links:

<?php 
$sql = "SELECT * FROM `ecmt_memberlist` WHERE toonCategory='Capital' AND oldMember = 0 ORDER BY CONCAT(MainToon, Name)";

$rs_result = mysql_query($sql); //run the query
$total_records = mysql_num_rows($rs_result);  //count number of records
$total_pages = ceil($total_records / $num_rec_per_page); 
?>


      <table width="100%" border="0" cellspacing="0" cellpadding="0">
        <tr>
          <td align="center"><div style="width:100%; text-align:center;">
          <ul class="pagination">
    <li class="selected">
	<?php
echo "<a href='capitalmember.php?page=1'>".'«'."</a> ";?> 
</li>
<?
for ($i=1; $i<=$total_pages; $i++) { 
            echo "<li><a href='capitalmember.php?page=".$i."'>".$i."</a></li> "; 
};
?>
<li class="selected">
<? 
echo "<a href='capitalmember.php?page=$total_pages'>".'»'."</a> "; // Goto last page
?></li>
  </ul></div>
    <?php
  $pageNr = $page;   // Get Current Page Number
$from = $pageNr * $rowsPerPage;  // 3 * 10 = 30  // 3 * 10 = 30
$to = $from + $rowsPerPage;      // 30 + 10 = 40
echo $pageNr;
/* Result: From page 30 to 40 */
  ?></td>
        </tr>
      </table>

this works great and shows me 10 results per page,   what i need to work out and work on next is:   echo the number of results above the records (for example: "showing records 1 to 10" and then on page 2 "showing records 11 to 21" and page 3 "showing records 22 to 32"   how can i work out the maths for this echo?   i was thinking along the lines of;

    <?php
$pageNr = $page;   // Gets Current Page Number
$from = $pageNr * $rowsPerPage;  // 3 * 10 = 30  
$to = $from + $rowsPerPage;      // 30 + 10 = 40
// Now Show Results
echo $from; // Echo from
echo $to // Echo to
  ?>

but i'm still working on this..   then i need to look at shortening the amount of page links on the page if for example i have 500 records it shows me links 1 to 50 and eats up the page....   Appreciate any help and light onto my problems.   Many thanks
Edited by jacko_162, 11 January 2015 - 05:43 PM.

Hi,

I wonder if I somebody can help me

I have three drop down lists which are populated from data thats stored in my sql database. I also have a table which is echoed from the database all on the same page.


What i want to do is allow users to select values in the drop down lists which will then echo different results below in the table. Is this possible.

So on page load it will show all of the info in the html table. Then when the user changes the drop downs and clicks submit it will change the query to something SELECT dropdown1 value FROM users where Dropdown2 = 1 AND Dropdown3 = 2 etc.

Is this possible to display this information on the same page using the dropdown list or does it need to load a different page as the client side is trying to edit a server side script?

If its possible please can someone give me an example.

Thanks in advance

Edd

Here's the code, this is the PHP in my html contacts page (that IS in fact saved with a PHP extension): 
  <div class = "centercontainer">

OK, have no idea what's going on... I've done this a million times... why wont this output!??
I must have a major brain meltdown and dont know it yet!!!

Code: [Select]
<?php

// this echoes just fine:
echo $_POST['testfield'];


// but this wont echo:
echo 
if (isset($_POST['testfield']))
{
$_POST['testfield'] = $test;
}
echo $test;


/// or even this DOESNT echo either!:
$_POST['testfield'] = $test;
echo $test;

?>

how do i set the scrolll width of the page in the iframe, so i can scroll horizontally in the iframe?

Code: [Select]
<Iframe src="test.php?search=<?php echo $search; ?>" width="900px" height="600px"></Iframe>
this sets the iframe perimeter size, but i want the inner size to be much bigger.

maybe a better question is how to increase page size of test.php

Ok, my php skills are such that I can customize an existing script to some extend, but I can't write one.

My problem is the following:
I'm using a php-based forum script in a friends website. I load the 'forum.php' script  in an iframe of a static page.

When a user gets a response to a post that he wrote on the forum, he receives a mail with a link which - if clicked - gets him to the response he got ie. http://someurl.com/forum.php?todo=viewtopic&tid=6#t2

The problem is now that if he clicks the link, the file of course doesn't open in the iframe of the static page (http://someurl.com/forum.html) where normally this forum.php file opens.

I guess I will have to make the static page also into a php-file and then use parts of the clicked url (forum.php?todo=viewtopic&tid=6#t2) and insert it into the iframe as the file to load ... would appreciate a lot if anyone can advice me how to do that!

Thanks in advance,
K.

Hi All,

I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result.

Please help?

<?php   
$mysqli = mysqli_connect("removed", "removed", "removed", "removed");  
$sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'";  
$result = mysqli_query($mysqli, $sql);   
echo {$result['message']}; 
?>

So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code:


$con = mysql_connect("$host","$username","$password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("main", $con);

$result = mysql_query("SELECT * FROM Vendor");

while($row = mysql_fetch_array($result))
  {
//I need to echo right here  .................. but I get a blank page when I try this. Please Help.
  echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>';
  }

mysql_close($con);

Result: A Blank page.
Thanks in advance!

I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas?

Hi   I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems. 1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?

for($x = 1;$x<=40;$x++) {
		$lines = file("$filename.html");
        echo $lines[rand(0, count($lines)-1)]."<br>";
        }

I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text  without the html code?P.S file_get_contents doesn't work either have tried that one.     2nd Problem:   As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?   My code:

if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}

If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.   

Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way.

First set up everything for DB:

<?php
//connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//create the main database if it doesn't already exist
$query = 'CREATE DATABASE IF NOT EXISTS moviesite';
mysql_query($query, $db) or die(mysql_error($db));

//make sure our recently created database is the active one
mysql_select_db('moviesite', $db) or die(mysql_error($db));

//create the movie table
$query = 'CREATE TABLE movie (
        movie_id        INTEGER UNSIGNED  NOT NULL AUTO_INCREMENT,
        movie_name      VARCHAR(255)      NOT NULL,
        movie_type      TINYINT           NOT NULL DEFAULT 0,
        movie_year      SMALLINT UNSIGNED NOT NULL DEFAULT 0,
        movie_leadactor INTEGER UNSIGNED  NOT NULL DEFAULT 0,
        movie_director  INTEGER UNSIGNED  NOT NULL DEFAULT 0,

        PRIMARY KEY (movie_id),
        KEY movie_type (movie_type, movie_year)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die (mysql_error($db));

//create the movietype table
$query = 'CREATE TABLE movietype (
        movietype_id    TINYINT UNSIGNED NOT NULL AUTO_INCREMENT,
        movietype_label VARCHAR(100)     NOT NULL,
        PRIMARY KEY (movietype_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

//create the people table
$query = 'CREATE TABLE people (
        people_id         INTEGER UNSIGNED    NOT NULL AUTO_INCREMENT,
        people_fullname   VARCHAR(255)        NOT NULL,
        people_isactor    TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,
        people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,

        PRIMARY KEY (people_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Movie database successfully created!';
?>



********************************************************************
***********************************************************************

second file to load info into DB:



<?php
// connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//make sure you're using the correct database
mysql_select_db('moviesite', $db) or die(mysql_error($db));

// insert data into the movie table
$query = 'INSERT INTO movie
        (movie_id, movie_name, movie_type, movie_year, movie_leadactor,
        movie_director)
    VALUES
        (1, "Bruce Almighty", 5, 2003, 1, 2),
        (2, "Office Space", 5, 1999, 5, 6),
        (3, "Grand Canyon", 2, 1991, 4, 3)';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the movietype table
$query = 'INSERT INTO movietype
        (movietype_id, movietype_label)
    VALUES
        (1,"Sci Fi"),
        (2, "Drama"),
        (3, "Adventure"),
        (4, "War"),
        (5, "Comedy"),
        (6, "Horror"),
        (7, "Action"),
        (8, "Kids")';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the people table
$query  = 'INSERT INTO people
        (people_id, people_fullname, people_isactor, people_isdirector)
    VALUES
        (1, "Jim Carrey", 1, 0),
        (2, "Tom Shadyac", 0, 1),
        (3, "Lawrence Kasdan", 0, 1),
        (4, "Kevin Kline", 1, 0),
        (5, "Ron Livingston", 1, 0),
        (6, "Mike Judge", 0, 1)';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Data inserted successfully!';
?>



**************************************************************
****************************************************************

MY CODE FOR THE QUESTION:


<?php
$db = mysql_connect('localhost', 'root', '000') or
die ('Unable to connect. Check your connection parameters.');

mysql_select_db('moviesite', $db) or die(mysql_error($db));

//get our starting point for the query from the URL
if (isset($_GET['offset'])) {
   $offset = $_GET['offset'];
} else {
   $offset = 0;
}

//get the movie
$query  = 'SELECT
   movie_name, movie_year
FROM
   movie
ORDER BY
   movie_name
LIMIT ' . $offset . ' , 1';
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
?>
<html>
<head>
<title><?php echo $row['movie_name']; ?></title>
</head>
<body>
<table border = "1">
<tr>
<th>Movie Name</th>
<th>Year</th>
</tr><tr>
<td><?php echo $row['movie_name']; ?></td>
<td><?php echo $row['movie_year']; ?></td>
</tr>
</table>
<p>
<a href="page.php?offset=0">Page 1</a>,
<a href="page.php?offset=1">Page 2</a>,
<a href="page.php?offset=2">Page 3</a>
</p>
</body>
</html>

Code: [Select]
<?php
$sum_num = mysql_query("SELECT SUM(likes) as totallikes FROM facebook");
echo $sum_num;

?>


i got this result Resource id #27
how to get a number only?
 

What is the correct way to write an if/else statement within an echo? I need to alter this so that I can query to see what data is found and if not correct not to echo the rest of the statement.

Code: [Select]
echo '<td class="productbox">
<h1>' . $product_title . '</h1>
</td>';

So from the above code which is echoed within  the single quotes, what is the correct way to include an if else check on a value from the database.

I know how its done, but just want to save time and write it the correct way within this.