PHP - Open File Found With 'find' Command In Linux
This is probably an easy one, but I can't figure it out and it's pretty much not searchable. on a linux-machine i have installed filezilla the filezilla runs pretty well and all is ok. now i need to have the passwd that i have stored years ago. The passprhase is stored in a plain in a file called sitemanager.xmlfile I want to find that file and open it with a terminal command. find . -name *.sitemanagerwell i thought that this will return the file I'm looking for. Now how do I open it automatically, without typing the name? find . -name *sitemanager.xm | openThis doesn't work. It says it doesn't found the open command. question: why it does not work on opensuse? should i use any other command - eg the following: find . -name *xyz | xargs openor find . -name *sitemanager.xml | xargs openor find . -name *.xyz -exec open {} \;and find . -name *.xyz -exec open {} \; .any and all help will be greatly appreciate again: what is wanted and needet is to find out the passphrase in the filezilla-configuration Similar TutorialsI have a PHP file that is executed via batch file very frequently for live updating. This is a sort of "sync" file for reading/writing to a MySQL database. I am able to get it functioning absolutely fine when executed manually via a web browser (and my echo debug lines output the expected information), yet when I run the same PHP file via the command line, it seems to just not be capable of opening any file for reading, so the equivalent variables that are correct when executed on a web browser are blank when echoed through the command line. Is there a different way of handling reading of files when running a php script via the command line, or should it function exactly the same as when run via a browser? For instance: $k = "0"; $line = file("examplefile.log")[$k]; echo $line; Hi, I am trying to use php to pass some commands to my linux box.From my webpage I am using the shell_exec function which is working OK but for some administrative tasks in linux I must have root access. As I am sending the commands from the webpage the apache user is used and so I am not allowed to do several tasks. I have also tried to use a bash script to pass the commands but with no result. Any ideas ? Hi guys, I'm trying to run a php script from command line in linux. I installed xampp for linux a.k.a lampp so typing php /path/to/file.php Just brings up a message saying I need to install php. Whats the correct way to do this? Hi everyone, i'm trying to get it so when i visit my webpage called start.php it executes the command (/bigbrotherbot start) in the terminal which then should start the process on my linux machine. I'm currently using this code Code: [Select] <?php shell_exec('sudo /bigbrotherbot start'); ?> This script doesn't appear to do anything though. I'm very new to php and would really appreciate the help. P.S the file bigbrotherbot is the bash script which works if i actually go to the terminal myself and type /bigbrotherbot start yet when i try to make the php do it it doesnt do anything. any ideas? Hello, I'm working with Zend Framework on Linux, and I'm trying to generate a CAPTCHA using Zend_Form_Element_Captcha. Whenever the CAPTCHA page loads I get this error: [12-Jan-2011 18:14:54] PHP Warning: imagepng() [<a href='function.imagepng'>function.imagepng</a>]: Unable to open '/var/www/square/application/../public/captcha/ebf44d292149b3ebda05571c54c463a8.png' for writing: Permission denied in /usr/local/zend/share/ZendFramework/library/Zend/Captcha/Image.php on line 563 Here's my code for generating the CAPTCHA: // create captcha $captcha = new Zend_Form_Element_Captcha('captcha', array( 'captcha' => array( 'captcha' => 'Image', 'wordLen' => 6, 'timeout' => 300, 'width' => 300, 'height' => 100, 'imgUrl' => '/captcha', 'imgDir' => APPLICATION_PATH . '/../public/captcha', 'font' => APPLICATION_PATH . '/../public/fonts/LiberationSansRegular.ttf', ) )); I've checked permissions, and all directories mentioned above are accessible to root. Has anyone had a similar problem or have an idea how I can fix this? Kind Regards, Mike I am a bit rusty with mySQL and I tried to borrow some other query code and modify it into an update command...apparently I am trying to use an invalid property in my error checking. Basically I just want to check and see if there were NO rows updated so I can let the user no that nothing was changed. There are probably easier ways to do this? The page where I set the variable values is based on a form post. I am not sure how to write my validation tests. Right now it is running the update successfully but it is reporting back an error based on hitting the "else if" test where I am trying to see if no rows were updated. The error message is: Quote Encountered error: 8 in /home/omgma/public_html/member_community/mbr_profiles/mbr_profile_updt_post.php, line 85: Trying to get property of non-object No fields were updated! Error: 0 Code: [Select] //create a SQL statement $updt_cmd = "UPDATE users t1, directory t2 " ."SET t1.email = '$email', " ."t2.first_name='$first_name', " ."t2.last_name='$last_name', " ."t2.suffix='$suffix', " ."t2.website_url='$website_url' " ."WHERE t1.username ='$username' AND t2.directory_id = t1.directory_id"; $conn = db_connect(); $result = $conn->query($updt_cmd); if (!$result) {//could not execute query throw new Exception('<h2>Could not execute member profile update!</h2><p>Error: ' .mysqli_errno($conn) .mysqli_error($conn) .'</p>' ); } else if ($result->num_rows==0) {// no rows so nothing was updated. throw new Exception('<h2>No fields were updated! </h2><p>Error: ' .mysqli_errno($conn) .mysqli_error($conn) .'</p>' ); } else { $mbr_profile = $result->fetch_object(); print_r($mbr_profile); return $mbr_profile; } Am I using the right functions here to do this and if so where can I find the class properties to use to test if nothing was updated? Thanks I want to do something like the following: exec('open /Applications/Safari.app'); I can run exec on other commands like: $output = exec('ls -ll); echo $output; And I can run the open command via Terminal, but I can't seem to run the open command via a PHP page using exec(). I've tried the permissions of the .app file at 777 and the open binary at 777. Any suggestions? I am new to Php and the linux environment. I have written a php program which sames a file to folder using xampp in Windows but I am having a problem with the pathway using my Ubuntu server and LAMP. My code I used in Windows was: $fileName = "guessbook.txt"; $file = fopen ($fileName, "ab"); if(!$file) { echo "ERROR! did not create the file! Exiting.<br />; exit(); } This file was saved correctly using xampp into the htdoc folder and worked fine when I called it in my browser. I tried to substitute a Linux pathway ie: /var/www/assignment2/guessbook.txt, where guessbook is in the code but still nothing. Can someone explain how to write the correct pathway to save this file? Thank you Paul Sorry for posting this here, but for some reason the "create new topic" in linux subforum doesnt exist. anyways i made a small php script that enables me to retrieve data between two dates. now am stuck on how i should copy it or u0pload it into linux. system tells me i need to upload to /usr/bin/libexec , i am there now but i dont have the slightest idea on how to do that. help is much appreciated. Thanks Hello! I am executing an external command from a PHP script, using the exec function. Since this program can take more than 1-2 minutes to run, I thought I should use a "Loading page...please wait". What I need is to be able to get the process id from the external program that is being run and, when this finishes, I'll start outputting the results. Is there a way to do this? Hello, I'm trying to have my index.php to open/run another test.php file. I'm having my own server that I play with, that I run Ubuntu on. So the index.php are located at /var/www/ directory, but I want to run a file that are located at /testing/test.php The final test.php is file for showing pictures, and I don't want to out all the pictures under the /var/www/ location. It's alot of photos. I don't know much about php but I have been trying this: <?php header("Location: /var/www/testing/test.php"); //These below are desperat old tries. //header("Location: ./testing/test.php"); //header("Location: ../testing/test.php"); //$handle = fopen("/privat/Web_pictures/test.php", "r"); //"/testing/test.php" // header("Location: ./test.php"); //This one actually works, but I'm still in the wrong folder (/var/www/) echo "test "; // NN4 requires that we output something... exit(); ?> Thankful for help! Hey there, Thanks for taking the time to read my thread, well basically I'm in a bit of a dilemma. I've got a string in PHP containing the contents of a file I would like to be created and I have a method of sending the command to the remote server like so: $Connection->exec('ps aux'); Now my issue is I am unaware of any file editors via command like that don't have some sort of user prompt I've scoured Google for hours searching for the best possible method for this but all the file editors aren't simply processed by one line commands and edited in that same command e.g Create File -> Write File -> Close File Is there no possible means of doing that via one line command?. Here is my string I wish to be written to the file. $RestartFile = "#!/bin/bash export SERVER_PATH=/home/client".$Server['server_owner']."/".$Server['server_id']." cd $SERVER_PATH while [ true ]; do ./server".$Server['server_id']." & done"); Thank you for your time. http://bayarearcsociety.com/prototype/index.php When I click the Home link in the nav panel I get these errors Code: [Select] Warning: include(/content/pages/testpage.php) [function.include]: failed to open stream: No such file or directory in /home/bayare27/public_html/prototype/content/maincontent.php on line 7 Warning: include() [function.include]: Failed opening '/content/pages/testpage.php' for inclusion (include_path='.:/usr/lib/php:/usr/local/lib/php:/home/bayare27/php') in /home/bayare27 /public_html/prototype/content/maincontent.php on line 7 index.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <meta http-equiv="Content-language" content="en" /> <link type="text/css" rel="stylesheet" href="css/reset.css" /> <link type="text/css" rel="stylesheet" href="css/960.css" /> <link type="text/css" rel="stylesheet" href="css/custom.css" /> <title></title> </head> <body> <div id="wrapper" class="container_12"> <div id="header" class="grid_12"> <div id="left-header" class="grid_5 alpha"></div> <div id="newsflash" class="grid_7 omega"><?php include('content/newsflash.php'); ?></div> </div> <div id="leftmenu" class="grid_3"><?php include('content/menu.php'); ?></div> <div id="maincontent" class="grid_9"><?php include('content/maincontent.php'); ?></div> <div id ="footer" class="grid_12"><?php include('content/footer.php'); ?></div> </div><!-- end wrapper --> </body> </html> menu.php <?php ?> <div class="content"> <ul id="menu"> <li><a href="<?php echo htmlentities($_SERVER['SCRIPT_NAME']); ?>?page=testpage"><span>Home</span></a></li> <!-- Tried both these $_SERVER['PHP_SELF'] and $_SERVER['SCRIPT_NAME']--> <li><a href=""><span>About us</span></a></li> <li><a href=""><span>Schedule</span></a></li> <li><a href=""><span>Media</span></a></li> <li><a href=""><span>Products</span></a></li> <li><a href=""><span>Miscellaneous</span></a></li> </ul> </div> testpage.php <?php ?> <p> lalalaa </p> The file structure on the server is: prototype content - I know these are ok pages - testpage.php is in this file css - I know these are ok images - I know this one is ok Just don't know what to do next. Thanks I apologize, I thought I was posting in php. I assume you will move it. I'm trying to compare 2 files, each with data separated by ::. I'm trying to make a comparison that if the data to the left of the separator from one file is not found in the same column of the other file, then it is copied to an array. For example: file1.txt abc::def ggg::hhh mmm::ppp file2.txt abc::def zzz::aaa bbb::ccc So... ggg::hhh mmm::ppp is copied from file1.txt because ggg and mmm was not found on the same side in file2.txt ...but I'm not getting any error message with this. The operation just hangs. Code: [Select] <?php $dic1 = file('file1.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); $dic2 = file('file2.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); $titleText = array(); // Storing results into this array. foreach ($dic1 as $dic1line){ list($dic1field1, $dic1field2) = explode('::', $dic1line); foreach ($dic2 as $dic2line){ list($dic2field1, $dic2field2) = explode('::', $dic2line); if ($dic1field1 != $dic2field1) { // Found a non match in DB. array_push($titleText, "$dic1field1 :: $dic1field2\n"); // Store all finds in array. } } } // Finish outputting anything left over. if (empty($titleText)) { // $value was not found -- array is empty. echo 'All matched, or something else.'; } else { $arrayOut = implode("", $titleText); // output the results found in the search. echo $arrayOut; } unset($value); ?> Anyone know how to do this? Thanks. hello and good day dear Linux-experts, i want to install a new opensuse linux on a notebook. i want to upgrade is the following: this one: Akoya P 6512 15" OpenSuse 13.1: AMD Athlon X2 P320, 2,10 GHz, 4 GB 320 GB hdd-drive what is wanted: i want to do a total fresh installation i want to have not tooo much partitions! i only want to run opensuse 13.2 i want to have some kind of native linux partitions - such as ext 4 - # what do you suggest - should go with the new default BTRFS file system?!? well to begin with the beginning: i applied the following commands a. lsblk b. fdisk -l see the results,,,, ; linux-c5sz:/home/martin # lsblk NAME MAJ:MIN RM SIZE RO TYPE MOUNTPOINT sda 8:0 0 465,8G 0 disk ├─sda1 8:1 0 4G 0 part [SWAP] ├─sda2 8:2 0 102M 0 part ├─sda4 8:4 0 1K 0 part ├─sda5 8:5 0 2G 0 part ├─sda6 8:6 0 4G 0 part ├─sda7 8:7 0 10G 0 part ├─sda8 8:8 0 20G 0 part / └─sda9 8:9 0 389,6G 0 part /home sr0 11:0 1 1024M 0 rom and the following fdisk -l linux-c5sz:/home/martin # fdisk -l Disk /dev/sda: 500.1 GB, 500107862016 bytes, 976773168 sectors Units = Sektoren of 1 * 512 = 512 byte Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk label type: dos Disk identifier: 0xb8fa3ecd Gerät boot. Anfang Ende Blöcke Id System /dev/sda1 63 8385929 4192933+ 82 Linux swap / Solaris /dev/sda2 8385930 8594774 104422+ 83 Linux /dev/sda4 * 8803620 976768064 483982222+ 5 Extended /dev/sda5 8803683 12996584 2096451 83 Linux /dev/sda6 12996648 21382514 4192933+ 83 Linux /dev/sda7 21382578 42347339 10482381 83 Linux /dev/sda8 117821440 159766527 20972544 83 Linux /dev/sda9 159768576 976766975 408499200 83 Linux linux-c5sz:/home/martin # subsequently the questions; which partition logic should i choose. what is wanted: i want to have not tooo much partitions! i only want to run opensuse 13.2 note: i want to erase all the existing partition logic /(that is currently existing) i do this with Gparted. which partitions should i take? which file system ? i am curious to get to know your ideas linux-file-structu what needs to be saved while moving the installation
well this is one of the best place to ask joomla-related question. today i have no question regarding joomla. today i want to ask a linux-question: i am preparing a upgrade from opensuse 13.1 to 13.2 and i want to do a fresh installation. first of all - as a preliminary task i will do a saving of all the files - that are in the home of the current installation what else shoud i safe - more than the /home/my_name should i save anyting else ... http://tldp.org/LDP/...sect_03_01.html Table 3-2. Subdirectories of the root directory Directory Content /bin Common programs, shared by the system, the system administrator and the users. /boot The startup files and the kernel, vmlinuz. In some recent distributions also grub data. Grub is the GRand Unified Boot loader and is an attempt to get rid of the many different boot-loaders we know today. /dev Contains references to all the CPU peripheral hardware, which are represented as files with special properties. /etc Most important system configuration files are in /etc, this directory contains data similar to those in the Control Panel in Windows /home Home directories of the common users. /initrd (on some distributions) Information for booting. Do not remove! /lib Library files, includes files for all kinds of programs needed by the system and the users. /lost+found Every partition has a lost+found in its upper directory. Files that were saved during failures are here. /misc For miscellaneous purposes. /mnt Standard mount point for external file systems, e.g. a CD-ROM or a digital camera. /net Standard mount point for entire remote file systems /opt Typically contains extra and third party software. /proc A virtual file system containing information about system resources. More information about the meaning of the files in proc is obtained by entering the command man proc in a terminal window. The file proc.txt discusses the virtual file system in detail. /root The administrative user's home directory. Mind the difference between /, the root directory and /root, the home directory of the root user. /sbin Programs for use by the system and the system administrator. /tmp Temporary space for use by the system, cleaned upon reboot, so don't use this for saving any work! /usr Programs, libraries, documentation etc. for all user-related programs. /var Storage for all variable files and temporary files created by users, such as log files, the mail queue, the print spooler area, space for temporary storage of files downloaded from the Internet, or to keep an image of a CD before burning it. well - reagarding the thunderbird and other things more. note: i have thunderbird and enigmail up and running. so i need to save a. the passwords b. the mails. question: is there a need to save more than the home/my_name ?! love to hear from you greetings How can i find out parent (including) file of included file? Lets imagine that we want to for example auto_prepend file to each file on our server that would write out the name of file its being executed. I know, i can use PHP_SELF but what if i want to write name of file which is already included? I have a web page and i want on it show its name even if it was included, but not the included page itself is showing name but auto_prepend file to each php file, its duty of this auto_prepend_file to write it out i dont want myself to echo it on each page? do you feel me? I have short urls on the same page that this javascript code is on. the problem is that the code now can't find the poll.php. I have tried the full path and full url to the poll.php, but the code still outputs file not found. how to get this code working?
$.post('poll.php', $(this).serialize(), function(data, status){ Say I have... Code: [Select] <? echo("do something"); include("include_file.php"); echo("do something else"); ?> include_file.php Code: [Select] <? $a_$string = "a string"; echo($a_string); ?> I have put an error in the include_file.php an extra $ in the variable name. The first script would kick up an error that there is a problem with file include_file.php as line 3 or what ever the line may be. How can I have it so I can choose what the error message is, say a cryptic code and the line number without having the file names show as this is showing up my hidden includes folder and the file name which means that someone may try to visit this page alone and this can cause security issues. Adding in extra lines to every file to see if it is being use correctly a bit like sessions is not an option although I have looked at it as I have houndreds of files to alter in this case. I have just tried this instead of the top script but I does not show the secret code on error Code: [Select] <? echo("top"); @include("dummy.php") or die("secreterrorcode123"); echo("bottom"); ?> |