PHP - Not Able To Open Network Shared Folder In Chrome
Hi,
I'm newbie. My requirement is to open network shared folder from PHP.
This works fine in IE but not in Chrome.
Can anyone please help me ....
Thanks
Similar TutorialsHi I am trying to get the structure of some folders/files on my server to create an xml "Feed" which then goes to a flash file. I keep getting the error message that I can't open the folder (it is set to 755) ERROR: Could not open folder: http://www.name/templates/bluezoo/mp3s What am I doing wrong please. Many thanks in advance Edward Here's some php: Code: [Select] $directoryLocation="http://www.name/templates/bluezoo/mp3s"; // XML Doctype $xml = new DomDocument('1.0', 'UTF-8'); $xml->xmlStandalone = false; // XML Root element $root = $xml->createElement('mp3s'); $root = $xml->appendChild($root); // Grab a list of folders from the specified directory if ($dir = @opendir($directoryLocation)) { while (false !== ($file = readdir($dir))) { if (is_dir($directoryLocation . DIRECTORY_SEPARATOR . $file) && $file != '.' && $file != '..') { // If it is a folder, put it in the folders array $folders[] = $file; } } This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=308625.0 Hello all, i am go9090go. Today i made a domains for a jar file people can upload from my website. I made this to make the jar file close source and its easy to update. Now i made a java classloader and everything i made works. The classloader call a php document with the password and username. The pass and name will be checked inside a databse and if its inside i use header() to load the jar file. But when i just go to my main domain i get the index of the site and people can easly download the jar file without have to walk thru the php pass checker. So i want to place the jar file inside a protected folder,and i want that only way you get acces to this jar is by the php file. How can i get a file from a protected folder? here is the php used when the jar file is not inside a protected folder: <?php $DBName = "name";//name database $DBUser = "name";//user $DBPassword = "pass"; //passs $DBHost = "host"; //might be different mysql_connect($DBHost, $DBUser, $DBPassword); mysql_select_db($DBName); $username = $_GET['username']; $password = $_GET['password']; $IP = $_SERVER['REMOTE_ADDR']; $string = "Java"; $pos = strpos($agent, $string); if (!strpos($_SERVER['HTTP_USER_AGENT'], "Java")) { echo("Your Auth has been banned for trying to breach security."); //mysql_query("delete from users where username='$username'"); exit(); } $query = "select * from users where name='$username' and pass='$password'"; mysql_query($query); $num = mysql_affected_rows(); if ($num > 0) { header('Location:script/Script.jar'); } ?> now i want to use the header to a file inside a folder that is protected : so how can i make the header() methode to open script.jar inside a protected folder. The folder haves name and pass: blabla,balbla for exempel thanks for help I got this script: But it give me error, file_get_contents cannot open stream. I need to add the FTP connection with user/pass paramaters. then look in set http url, to get the file contents(images) and transfer to ftp server location. Can Anyone take alook and tell me if I am going down the right path and how to get there. Please Code: [Select] function postToHost($host, $port, $path, $postdata = array(), $filedata = array()) { $data = ""; $boundary = "---------------------".substr(md5(rand(0,32000)),0,10); $fp = fsockopen($host, $port); fputs($fp, "POST $path HTTP/1.0\n"); fputs($fp, "Host: $host\n"); fputs($fp, "Content-type: multipart/form-data; boundary=".$boundary."\n"); // Ab dieser Stelle sammeln wir erstmal alle Daten in einem String // Sammeln der POST Daten foreach($postdata as $key => $val){ $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n"; } // Sammeln der FILE Daten if($filedata) { $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$filedata['name']."\"; filename=\"".$filedata['name']."\"\n"; $data .= "Content-Type: ".$filedata['type']."\n"; $data .= "Content-Transfer-Encoding: binary\n\n"; $data .= $filedata['data']."\n"; $data .= "--$boundary--\n"; } // Senden aller Informationen fputs($fp, "Content-length: ".strlen($data)."\n\n"); fputs($fp, $data); // Auslesen der Antwort while(!feof($fp)) { $res .= fread($fp, 1); } fclose($fp); return $res; } $postdata = array('var1'=>'today', 'var2'=>'yesterday'); $filedata = array( 'type' => 'image/png', 'data' => file_get_contents('http://xxx/tdr-images/images/mapping/dynamic/deals/spot_map') ); echo '<pre>'.postToHost ("localhost", 80, "/test3.php", $postdata, $filedata).'</pre>';
Not experienced coding PHP and need help doing something which is probably very easy but looks like Mt Everest to me. FOO = 123456 BAR = abc Then, write URLs with those variables and have them work the same in a browser:
http://webpage1.com/?var1=FOO&var2=BAR
http://webpage2.com/?var1=FOO&var2=BAR
http://webpage3.com/?var1=FOO&var2=BAR If I update the fields in my local webpage and refresh browser, would like the new value(s) to be used instead. Any help with this greatly appreciated. If someone will put a file together think that I can edit and modify from there for my specific application. Thank you. Edited December 1, 2020 by XcloneHello - I have usually run my own servers, and always drop my .php files with MYSQL connection strings in a directory like /var, with webroot being /var/www/mysite. I now find myself in a shared hosting environment for a client and wondering the safety of my connection string .php files. Unfortunately they are sitting in a folder in the root of my hosting directory right now, and they feel vulnerable. It seems the only thing I could do would be to put the root of my hosting into a subdirectory, point the site there, and then put my connection strings on directory back. But seems the problem is they are still in my shared hosting. What's the best way to secure this type of sensitive info in a shared environment? I'm also getting ready to explore credit card processing via an API, and wondering if shared hosting is even worth it. Thanks!! Ok here it is, seems like it is an easy problem but my developers are having some issue with this, I hope you guys can help. Basic question and answer problem, where I am developing a website that uses Items and questions like " How many of this Item do you need?" the answer seems to simple. Lets say the answer Is "1". The display is given to the Item list and we move on. Here is the Problem: When selecting Muiltiple Items in the List and they all have the same question associated to each Item: "How Many Items do you need?" the the answer is shared between the Items, Again, sounds simple so far, However, when the USER selects Multiple Items on a list say 30 Items then the Question should only be dispalyed one time, not 30 times, then the answer is shared 30 times. Thats what I have now being displayed on my website, 30 of the same questions over and over again. The USER will get frustrated and leave the site never to return. Question: How can I get the Question to be displayed only once, but shared between several items on a list? This is a very serious problem fo my website because I will have not have just one Item on a list but 300 to 400 items, and if I get the answer to the problem I have just wasted 1 year of my life developing something undevelopable (is that a word?). Any Help you can give me would greatly be appricated. Thank you in advance. I am on a shared hosting server running CentOS. I have copied a PHP extension (imagick.so) that was built on similar server to my shared hosting server. I have resolved most of the dependencies by placing the missing files in ~/lib but I have one that I can't figure out how to cope with. I am getting the following error: I have one array, called for example $MainImages : - Code: [Select] Array ( [0] => Array ( [widgetID] => 143 [image] => image_a.jpg ) [1] => Array ( [widgetID] => 147 [image] => image_b.jpg ) [2] => Array ( [widgetID] => 73 [image] => image_c.jpg ) ) and a second array, we'll call it $widgets: - Code: [Select] Array ( [0] => Array ( [widgetID] => 147 [seo_title] => An excellent class B Widget [name] => Widget B [categoryID] => 1 ) [1] => Array ( [widgetID] => 73 [seo_title] => An excellent class C Widget [name] => Widget C [categoryID] => 1 ) [2] => Array ( [widgetID] => 143 [seo_title] => An excellent class A Widget [name] => Widget A [categoryID] => 1 ) ) I want to merge the value from the [][image] key from the first array into a new [][image] key / value in the second, using a shared value as a reference...so the desired result array is: - Code: [Select] Array ( [0] => Array ( [widgetID] => 147 [seo_title] => An excellent class B Widget [name] => Widget B [categoryID] => 1 [image] => image_b.jpg ) [1] => Array ( [widgetID] => 73 [seo_title] => An excellent class C Widget [name] => Widget C [categoryID] => 1 [image] => image_c.jpg ) [2] => Array ( [widgetID] => 143 [seo_title] => An excellent class A Widget [name] => Widget A [categoryID] => 1 [image] => image_a.jpg ) ) Obviously the order is different and so they need to be merged based on the widgetID values. Also, the same widgetID may be in each array more than once. I've looked at a lot of help but can't find anything to do exactly what I need....any help would be greatly appreciated! Hi,
I would like to ask if someone knows a trick to know if the script is running on a shared hosting or a vps or a dedicated server.
Regards
Hi, I have Code: [Select] $to = 'rberbe2002@msn.com'; $subject = 'the subject'; $message = 'hello'; $headers = 'From: webmaster@example.com'; mail($to, $subject, $message, $headers); which works fine on a shared hosting website I have, but not on a website I have on my dedicated server. Any ideas or suggestions please? Hi all i was wondering if someone knows a way to make sure an image which is uploaded isn't infected by a virus. I have read about avclam, but if your on a shared host your mostly not allowed to add own software. Isn't there maybe a php trick to resize the image which would magically remove a virus? If anyone knows a nice way or tricks to limit the virus breating space to a certain folder please let me know. I implemented google's reCAPTCHA V2 on http:// on the remote apache shared server and it worked 100%. I then changed the protocol to my shared server SSL using the same PHP script as the non-SSL script. The older version of reCaptcha had an SSL 'false' to 'true' SSL parameter, whereas I can't find one for V2. I had to use htaccess to redirect the example.com to the shared SSL server https://serverid.net/example/ which works perfectly without recCAPTCHA. I incorporated reCAPTCHA V2 and the error message where the reCAPTCHA image should be shows "ERROR: Invalid domain for site key". This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=317008.0 Hi all, I am trying to create a socket that can read from and write to a client. This is my first attempt at it and the code in question is based more or less on a python script a friend sent me as well as some php tutorials google supplied. The problem is (and this seems to be a reoccurring one) when I run it from the command line Code: [Select] php -q server.php nothing visibly happens. Can anyone see what the problem might be? Code: [Select] <?php $host = "localhost"; $port = 50007; set_time_limit(0); // no timeout $socket = socket_create(AF_INET, SOCK_STREAM, 0) or die("Could not create socket\n"); // create $result = socket_bind($socket, $host, $port) or die("Could not bind to socket\n"); // bind $result = socket_listen($socket, 3) or die("Could not set up socket listener\n"); // listen echo "Waiting for connections...\n"; $contact = socket_accept($socket) or die("Could not accept incoming connection\n"); // accept $input = socket_read($contact, 1024) or die("Could not read input\n"); // read $input = trim($input); // clean $output = "Greetings, you have connected to a socket.\n"; socket_write($contact, $output, strlen ($output)) or die("Could not write output\n"); // return socket_close($contact); // close socket socket_close($socket); // close socket ?> I have a PHP app that I wrote that requires a new IP address each time that it is run. Currently I use Tor on my desktop and the Vidalia app to change the Tor identity each time I run the script but I want to automate this. Can anyone help with switching Tor identities with PHP? Essentially after my script runs I need to call a function that switches to a new Tor identity. I have the following code but it doesn't seem to work, and I am not sure why. I am running this from XAMPP on OSX, Tor is running locally (client not server)... in my Tor settings I have 127.0.0.1 and port 9051, set to "no password"... Code: [Select] <?php function tor_new_identity($tor_ip='127.0.0.1', $control_port='9051', $auth_code='') { $fp = fsockopen($tor_ip, $control_port, $errno, $errstr, 30); if (!$fp) { return false; //can't connect to the control port } fputs($fp, "AUTHENTICATE $auth_code\r\n"); $response = fread($fp, 1024); list($code, $text) = explode(' ', $response, 2); if ($code != '250') { return false; //authentication failed } //send the request to for new identity fputs($fp, "signal NEWNYM\r\n"); $response = fread($fp, 1024); list($code, $text) = explode(' ', $response, 2); if ($code != '250') { return false; //signal failed } fclose($fp); return true; } tor_new_identity(); ?> Hi, I'm a bit of a newbie when it comes to PHP. I'm a thirs year music/music tech student and for my disseration I took a very ambitious task. I want to create a sort of social networking site for musicians. But I wanted to create it dynamically using PHP and MySQL. I want to basically allow users to register and sign up with their details basically. But the first problem I came across was actually making a custom registration page, I wanted things such as post codes (zip codes) so that I would then have a Google Maps overlay showing where users were. So that you could 'see' you local music 'scene'. So far I've been playing around with Joomla, Drupal and WordPress. I tried writing the PHP from scratch but after following various tutorials, but I had no luck what-so-ever with that approach. So I started using content management systems, which got me a lot closer, but I found I couldn't really edit custom registration pages etc. And the I would have no idea how to get the Google maps idea working. If anyone could nudge me in the right direction and give me a few tips and ideas as to how I'm most likely to achieve this then please reply, I would be highly grateful for you responses. Thanks, Ewan Valentine. I'm trying to open a URL using fopen() and I keep getting this error: Code: [Select] Failed to open stream: Permission deniedI can not work out what is wrong, it's not a firewall as far as I can tell. I want to copy everything in templates/blue to the folder code/ However: shell_exec("cp -r 'templates/blue' 'code'"); Creates a folder called blue inside code. I tried cp -r 'templates/blue/*' 'code', but that didn't do anything. Any ideas? Hi,
I'm not sure if this is possible, however I'm sure somebody will be able to point me in the right direction. Relativley new to php here.
I would like to write a small app that will change my IP/Subnet Mask/Gateway depending on a selection made from a dropdown list. I will have a tota; of 50 different IP settings & drop downs (each drop down will represent a different location)
I have yet to start writing the app, just on paper so far - can this be done?
I have seen examples of batch scripts like the one below that work, would I need to incorporate something like this into my php?
netsh int ipv4 set address name="Local Area Connection" source=static address=10.127.86.25 mask=255.255.255.240 gateway=10.127.86.30This is just a personal project, I'm trying to further my knowledge! Thanks J |