PHP - Is My Php Correct? Cant Find Any Syntax Errors
<?php error_reporting(E_ALL); session_start(); include ("dbcon.php"); echo "include working"; $username1= ($_POST['username']); echo ($_POST['username']); if ($_POST) { if (!empty($_POST['username']) && !empty($_POST['pass'])) { $sql = "SELECT * FROM `user` WHERE `username`='($_POST['username'])' LIMIT 1"; $result = mysqli_query($sql); if (mysqli_num_rows($result) > 0) { //user is valid, check pass $query = mysqli_fetch_assoc($result); $password = ($_POST['pass']); if ($password !== $query['pass']) { //invaid pass, input error code echo "Wrong Password"; exit; } else { //valid user and pass, login $_SESSION['login'] = TRUE; $_SESSION['username'] = $_POST['username']; //echo "logged in"; header('location: home.php'); exit(); } } else { //user is not in database, input error code echo " User Not Found"; } } else { //form submitted but no username/password, input error code echo "Fields are Blank"; } } else { //page loaded, but no form submitted, input error code echo "Submition Error"; } ?>I can't figure out the problem........ Any help is appreciated! Similar TutorialsI have this connection file "database_connection.php" under folder C:\wamp\www\php\database\database_connection.php and I'm calling it using required_once on file "add_database.php" under folder C:\wamp\www\php\database\ManipulatingDatabase\add_database.php Here's the code on Code: [Select] <?php include_once('../database/database_connection.php'); ?> and I'm having this error Quote Warning: include_once(../database/database_connection.php) [function.include-once]: failed to open stream: No such file or directory in C:\wamp\www\php\database\ManipulatingDatabase\add_database.php on line 3 Warning: include_once() [function.include]: Failed opening './database/database_connection.php' for inclusion (include_path='.;C:\php5\pear') in C:\wamp\www\php\database\ManipulatingDatabase\add_database.php on line 3 I have tried everything else. Maybe there's something wrong on my .ini file?Anyone? $sql = "select * from {$tab} WHERE {$tab}_id ='".$id."'"; This was the error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE '_id' ='11/'' at line 1 This is what i am trying to achieve for my URL categories=$pagename &id=$myid this is what i am currently doing having some syntax errors please would appreciate if some one can resolve this the code is below echo "<a href=\"./categories.php?name=".$pagename.&id=$myid."\">\".$myid.\".\"</a>\"\n"; I just had a curiosity that was bugging me and I'm unsure of how to google for the answer, so I thought I'd put it up to the test here. I learned that when writing if statements in php the syntax is as follows: if(condition){ //Execute Code... }else{ //Execute Other Code... } However, I also see it written like so: if(condition) { //Execute Code... } else { //Execute Other Code... } I thought that the later style was used for Javascript and the earlier for php. While they both work, I was wondering, which is more correct? Thanks Everybody! E I have just discovered ternary conditionals and really like the time and space saving, they seem pretty simple and look neater than a bunch of if else statements crammed together. The thing I would like to know is what is the best or correct method of usng the following; $page = isset($_GET['page']) ? $_GET['page'] : '1'; or do I need the extra parentheses like below; $page = (isset($_GET['page'])) ? $_GET['page'] : '1'; I understand that if I used a second conditon I would need the extra parentheses e.g $page = (isset($_GET['page']) && is_numeric($_GET[page'])) ? $_GET['page'] : '1'; Thanks! <form action="blabla"> <input type="hidden" name="user" value="<?php echo $player;?>"> </form or <input type="hidden" name="user" value=<?php echo $player;?>> or are they both wrong ^_^ $tab is a variable for my table's name <?php while($row=mysqli_fetch_assoc($result)){ ?> <?php echo $row['{$tab}_name']?> anyone know why i would be getting errors in these SQL statements or how to debug? $sql3="SELECT FROM $tbl_name2(`id`,`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$id','$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; $result3=mysql_query($sql3) or die(mysql_error()); $sql5="select * from $tbl_name where username = '$UserName'"; the error(s) is just the generic one such as Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM (`id`,`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip' at line 1 What would be the correct way to use returned sql results as variables. I have tried the way in my script, but Im unsure of how I can echo just one of the $nt variables further on in my script. $code = $_GET['postcode']; $shortcode = substr($code,0,2); $query =mysql_query ("SELECT email FROM treesurgeons WHERE postcode like '%" . $shortcode . "%' ORDER BY companyName LIMIT 3"); echo mysql_error(); echo "<p>The email addresses you have requested are;</p>"; while($nt=mysql_fetch_row($query)){echo "$nt[0],$nt[1],$nt[2]<br>";} echo "<p>please use $nt[2] if you ever want to contact me</p>"; //this line doesnt work for me ?></body></html> is there is a way to assign variables such as; $nt[0] = $firstemail $nt[1] = $secondemail $nt[2] = $thirdemail this way I could use each of my sql values, just as I would any other variable? I just need another pair of eyes as I am not seeing the syntax error. I'm sure I'll figure it out right after I post this as that has happened many times before. query: <?php $sql = " INSERT INTO views (user_id,show,show_id,episode,episode_id) VALUES ( '" . $_SESSION['user']['id'] . "', '" . $showTitle . "', '" . $showID . "', '" . $episodeTitle . "', '" . $episodeID . "')"; ?> output: <?php $output = " INSERT INTO views (user_id,show,show_id,episode,episode_id) VALUES ('1','Criminal Minds','9','Episode Title','1')"; ?> error: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'show,show_id,episode,episode_id) VALUES ( '1', 'Criminal Minds', '9',' at line 2 I cannot see the error. I'm getting syntax errors on line 61 and line 67 indicated in comments on form. What am I missing? <?php $submit = $_POST['submit']; // Form Data $email = strip_tags($_POST['email']); $salonname = strip_tags($_POST['salonname']); if ($_POST[submit]) { echo "TRUE - CONTINUE_1"; //echo $_SESSION[key].' - '.$_POST[user_code].'<br>'; if ($_SESSION[key]==$_POST[user_code]) { echo "TRUE - CONTINUE_2"; $_SESSION[key]=''; } if ($salonname); { echo "TRUE - CONTINUE_3"; $email = trim($_POST['email']); if(!checkEmail($email)) { echo 'Invalid email address!'; echo "FALSE - STOP_4"; } else { echo "TRUE - CONTINUE_4"; // RUN Database Query } }//End IF salonname = TRUE else //LINE 61 {// STOP CODE echo "FALSE - STOP_3"; }// End salonanme check else //LINE 67 {// STOP CODE echo "FALSE - STOP_2"; }// End user code }// End if Sumbit else {// STOP CODE echo "FALSE - STOP_1"; } ?> Hi all, I am new to PHP and wish to use it simply to collect form data and email it to myself. From what I have gathered from PHP tutorials I have write the following script but I am getting syntax error warnings and cant figure out why. Can somebody please tell me where I am going wrong and if this script will actually work? The line I am getting errors on is Code: [Select] <?php //message contains $message = "Name:$name</br>Email:$email</br>Phone:$phone</br>Preferred Date:$date</br>Best Time To Contact:$time"; ?> Thank you in advance. Code: [Select] <body> <?php //my email $recipient = "info@hairlosslasergroup.co.uk"; //persons name $name = htmlspecialchars($_POST['name']); //persons email $email = htmlspecialchars($_POST['email']); if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/",$email)) { die("E-mail address not valid"); } //persons phone number $phone = htmlspecialchars($_POST['phone']); //preferred date $date = htmlspecialchars($_POST['comments']); //best time $time = htmlspecialchars($_POST['time']); //check required fields $required = check_input($_POST['required'], "Please go back and complete all required fields"); //email subject $subject = ($_POST['subject'] //message contains $message = "Name:$name</br>Email:$email</br>Phone:$phone</br>Preferred Date:$date</br>Best Time To Contact:$time"; //message mail($recipient, $subject, $message); //redirect to thank you page header('Location:$redirect'); ?> </body> </html> I have a form that is passing the User to following code. The code below is just ported from another site that I created, which works extremely well. I've had to change the datatable, database connection and some of the variables for this site, but it's otherwise the same. I've triple checked the variables. The datatable is accurate. It doesn't appear to be passing variable from the Form with the exception of "content", and I'm getting the following error: Quote You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'year='', position='', content='Test', ppg='', rp' at line 6 Query: INSERT INTO players SET playerFirst='', playerLast='', feet='', inches='' year='', position='', content='Test', ppg='', rpg='', apg='', spg='', bpg='', fgp='', ftp='', status='' What am I missing? Code: [Select] <?php include('db.php'); $playerFirst = $_POST['playerFirst']; $playerLast = $_POST['playerLast']; $feet = $_POST['feet']; $inches = $_POST['inches']; $year = $_POST['year']; $position = $_POST['position']; $content = $_POST['content']; $ppg = $_POST['ppg']; $rpg = $_POST['rpg']; $apg = $_POST['apg']; $spg = $_POST['spg']; $bpg = $_POST['bpg']; $fgp = $_POST['fgp']; $ftp = $_POST['ftp']; $status = $_POST['status']; //if(isSet($_POST['playerFirst']['playerLast']['feet']['inches']['year']['status'])) //{ /* search for existing row */ $sql = "SELECT msg_id FROM players WHERE playerFirst='".mysql_real_escape_string($playerFirst)."' AND playerLast='".mysql_real_escape_string($playerLast)."'"; if(!$result = mysql_query($sql)) { die(mysql_error()."<br />Query: ".$sql); } if(mysql_num_rows($result)) { $row = mysql_fetch_assoc($result); /* update existing row */ $sql = "UPDATE players SET feet='".mysql_real_escape_string($feet)."', inches='".mysql_real_escape_string($inches)."' year='".mysql_real_escape_string($year)."', position='".mysql_real_escape_string($position)."', content='".$content."', ppg='".$ppg."', rpg='".$rpg."', apg='".$apg."', spg='".$spg."', bpg='".$bpg."', fgp='".$fgp."', ftp='".$ftp."', status='".$status."', WHERE msg_id='".$row['msg_id']."'"; if(!$result = mysql_query($sql)) { die(mysql_error()."<br />Query: ".$sql); } } else { /* insert new row */ $sql = "INSERT INTO players SET playerFirst='".mysql_real_escape_string($playerFirst)."', playerLast='".mysql_real_escape_string($playerLast)."', feet='".mysql_real_escape_string($feet)."', inches='".mysql_real_escape_string($inches)."' year='".mysql_real_escape_string($year)."', position='".mysql_real_escape_string($position)."', content='".$content."', ppg='".$ppg."', rpg='".$rpg."', apg='".$apg."', spg='".$spg."', bpg='".$bpg."', fgp='".$fgp."', ftp='".$ftp."', status='".$status."'"; if(!$result = mysql_query($sql)) { die(mysql_error()."<br />Query: ".$sql); } } I used to have a straight forward piece of code that updated multiple rows of info using a foreach loop. However, ever since I've introduced a textarea box into the mix, it's been throwing up syntax errors. Here's my textarea box: Code: [Select] <textarea id=\"detail[]\" name=\"detail[]\" rows=\"7\" cols=\"35\" wrap=\"hard\">$data[detail]</textarea> And here's my UPDATE query: Code: [Select] foreach($_POST['mid'] as $key=>$val) { mysql_query("UPDATE val_mworks SET mworks_percent = ".$_POST['percent'][$key].", mworks_detail = ".$_POST['detail'][$key].", mworks_qty = ".$_POST['qty'][$key]." WHERE mworks_id = $val ") or die(mysql_error()); } Can anyone see anything obvious that I'm doing wrong? hey, I get this error on line 69 which is the end of my code, but I just can't find the missing or wrong curly bracket :s <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <p> <?php if(isset($_POST['_submit_check'])){ if($form_errors = validate_form()){ show_form($form_errors);} else{ process_form();}} else{ show_form();} function process_form(){ print "Hello, ".$_POST['user'];} if(array_key_exists('user', $_POST)){ process_form();} else{ show_form(); } function validate_form(){ $errors = array(); if(strlen($_POST['user']) < 1){ $errors[] = 'Your name must be at least 1 letter long.'; } return $errors;} if(array_key_exists('_submit_check', $_POST)){ if(validate_form()){ proces_form(); } else{ show_form();} } else{ show_form(); } function show_form($errors = ''){ if($errors){ print 'please correct these errors: <ul><li>'; print implode('</li><li>', $errors); print '</li></ul>'; } print<<<_HTML_ <form method = "POST" action="$_SERVER[PHP_SELF]"> Your name: <input type="text" name="user"> </br> <input type="submit" value="Verzenden"/> </br> <input type="hidden" name="_submit_check_" value="1"> </form> _HTML_; } ?> </p> </body> </html> It's pretty simple to see what I am trying to do here. For some reason all results in the table are the same exact cityName replacing all existing records. The echoed results are correct. I've include a small dump of my table as well. $query = "SELECT cityName FROM sys_city_dev_2"; $resource = mysqli_query($cxn, $query) or die("MySQL error: " . mysqli_error($cxn) . "<hr>\nQuery: $query"); while($result = mysqli_fetch_assoc($resource)) { $nox = $result['cityName']; $toUpper = ucfirst($nox); echo "$toUpper" . "<br />"; $setString = "UPDATE sys_city_dev_2 SET cityName = '" . $toUpper ."' WHERE cityName != ''"; mysqli_query($cxn,$setString); } 100 Records of table dump (pre running my script above): -- -- Table structure for table `sys_city_dev_2_backup` -- CREATE TABLE IF NOT EXISTS `sys_city_dev_2_backup` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Mid` int(11) NOT NULL DEFAULT '0', `cityName` varchar(30) NOT NULL DEFAULT '', `forder` int(4) NOT NULL DEFAULT '0', `disdplay` int(4) NOT NULL DEFAULT '0', `cid` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=113970 ; -- -- Dumping data for table `sys_city_dev_2_backup` -- INSERT INTO `sys_city_dev_2_backup` (`ID`, `Mid`, `cityName`, `forder`, `disdplay`, `cid`) VALUES (84010, 1, 'dothan', 0, 0, 0), (84011, 1, 'alabaster', 0, 0, 0), (84012, 1, 'birmingham', 0, 0, 0), (84013, 2, 'flagstaff', 0, 0, 0), (84014, 1, 'auburn', 0, 0, 0), (84015, 1, 'florence', 0, 0, 0), (84016, 1, 'gadsden', 0, 0, 0), (84017, 1, 'huntsville', 0, 0, 0), (84018, 1, 'mobile', 0, 0, 0), (84019, 1, 'montgomery', 0, 0, 0), (84020, 1, 'tuscaloosa', 0, 0, 0), (84021, 2, 'mohave valley', 0, 0, 0), (84022, 2, 'phoenix', 0, 0, 0), (84023, 2, 'prescott', 0, 0, 0), (84024, 2, 'sierra vista', 0, 0, 0), (84025, 2, 'tucson', 0, 0, 0), (84026, 2, 'yuma', 0, 0, 0), (84027, 3, 'bakersfield', 0, 0, 0), (84028, 3, 'chico', 0, 0, 0), (84029, 3, 'fresno / madera', 0, 0, 0), (84030, 3, 'gold country', 0, 0, 0), (84031, 3, 'humboldt county', 0, 0, 0), (84032, 3, 'imperial', 0, 0, 0), (84033, 3, 'inland empire', 0, 0, 0), (84034, 3, 'los angeles', 0, 0, 0), (84035, 3, 'alhambra', 0, 0, 0), (84036, 3, 'merced', 0, 0, 0), (84037, 49, 'fayetteville', 0, 0, 0), (84038, 49, 'fort smith', 0, 0, 0), (84039, 49, 'jonesboro', 0, 0, 0), (84040, 49, 'little rock', 0, 0, 0), (84041, 49, 'arkadelphia', 0, 0, 0), (84042, 49, 'texarkana', 0, 0, 0), (84043, 3, 'modesto', 0, 0, 0), (84044, 3, 'alta sierra', 0, 0, 0), (84045, 3, 'alpine', 0, 0, 0), (84046, 3, 'pedley', 0, 0, 0), (84047, 3, 'redding', 0, 0, 0), (84048, 3, 'alondra park', 0, 0, 0), (84049, 3, 'sacramento', 0, 0, 0), (84050, 4, 'canon city', 0, 0, 0), (84051, 3, 'san luis obispo', 0, 0, 0), (84052, 3, 'santa barbara', 0, 0, 0), (84053, 3, 'stockton', 0, 0, 0), (84054, 3, 'aliso viejo', 0, 0, 0), (84055, 3, 'visalia', 0, 0, 0), (84056, 3, 'yuba city', 0, 0, 0), (84057, 4, 'boulder', 0, 0, 0), (84058, 4, 'colorado springs', 0, 0, 0), (84059, 4, 'denver', 0, 0, 0), (84060, 4, 'applewood', 0, 0, 0), (84061, 4, 'pueblo', 0, 0, 0), (84062, 4, 'air force academy', 0, 0, 0), (84063, 5, 'avon', 0, 0, 0), (84064, 5, 'hartford', 0, 0, 0), (84065, 5, 'new haven', 0, 0, 0), (84066, 5, 'ansonia', 0, 0, 0), (84067, 5, 'fairfield', 0, 0, 0), (84068, 7, 'daytona beach', 0, 0, 0), (84069, 7, 'sebastian', 0, 0, 0), (84070, 5, 'wallingford center', 0, 0, 0), (84071, 8, 'belvedere park', 0, 0, 0), (84072, 7, 'sarasota springs', 0, 0, 0), (84073, 7, 'sandalfoot cove', 0, 0, 0), (84074, 7, 'san carlos park', 0, 0, 0), (84075, 7, 'st. augustine', 0, 0, 0), (84076, 7, 'tallahassee', 0, 0, 0), (84077, 7, 'safety harbor', 0, 0, 0), (84078, 7, 'ruskin', 0, 0, 0), (84079, 8, 'athens-clarke county', 0, 0, 0), (84080, 8, 'atlanta', 0, 0, 0), (84081, 8, 'augusta-richmond county', 0, 0, 0), (84082, 8, 'brunswick', 0, 0, 0), (84083, 8, 'columbus', 0, 0, 0), (84084, 8, 'americus', 0, 0, 0), (84085, 8, 'acworth', 0, 0, 0), (84086, 8, 'valdosta', 0, 0, 0), (84087, 10, 'boise', 0, 0, 0), (84088, 10, 'ammon', 0, 0, 0), (84089, 10, 'moscow', 0, 0, 0), (84090, 10, 'blackfoot', 0, 0, 0), (84091, 10, 'twin falls', 0, 0, 0), (84092, 10, 'meridian', 0, 0, 0), (84093, 10, 'jerome', 0, 0, 0), (84094, 10, 'idaho falls', 0, 0, 0), (84095, 11, 'addison', 0, 0, 0), (84096, 10, 'garden city', 0, 0, 0), (84097, 10, 'eagle', 0, 0, 0), (84098, 10, 'chubbuck', 0, 0, 0), (84099, 10, 'caldwell', 0, 0, 0), (84100, 12, 'bloomington', 0, 0, 0), (84101, 12, 'evansville', 0, 0, 0), (84102, 12, 'fort wayne', 0, 0, 0), (84103, 12, 'indianapolis', 0, 0, 0), (84104, 12, 'muncie / anderson', 0, 0, 0), (84105, 12, 'lafayette / west lafayette', 0, 0, 0), (84106, 12, 'south bend / michiana', 0, 0, 0), (84107, 12, 'terre haute', 0, 0, 0), (84108, 12, 'northwest indiana', 0, 0, 0), (84109, 13, 'ames', 0, 0, 0); I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you
<title>Inputing Travel Detials</title> <header> <h1 align="center"> Adding Travel Detials </h1> <body> <p> <center><img src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center> <table border="1"> <tr> <td><a href="index.php"> Home Page </a></td> <td><a href="administratorhomepage.html">Administrator Home Page </a></td> <td><a href="viewhomepage.html">View Home Page </a></td> <td><a href="Inputhomepage.html">Input Home Page </a></td> <td><a href="traveldetials.html">Enter More Travel Detials </a></td> </table> </p> <?php include "connection.php"; $Applicant_ID = $_POST["Applicant_ID"]; $Method_Of_Travel = $_POST["Method_Of_Travel"]; $Cost = $_POST["Cost"]; $ETA = $_POST["ETA"]; $Main_Gate_Advised = $_POST["Main_Gate_Advised"]; $query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'"); $result = mysqli_query($dbhandle, $query) or die(mysqli_error($dbhandle)); if($result){ echo "Success!"; } else{ echo "Error."; } // successfully insert data into database, displays message "Successful". if($query){ echo "Successful"; } else { echo "Data not Submitted"; } //closing the connection mysqli_close($dbhandle) ?> Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Hi guys
I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?
<?php
$con = mysql_connect("localhost:3306","root","password");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('sfapp', $con);
$sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')
VALUES
('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
?>
<?php
//if "email" variable is filled out, send email
if (isset($_REQUEST['pe_add'])) {
//Email information
$admin_email = $_REQUEST['pe_add'];
$forename = $_REQUEST['forename_add'];
$email = "autoreply@testing.com";
$subject = "Application";
$desc =
"Dear $forename
Thank you for submitting your online application, we will be in touch shortly.
"
;
//send email
mail($admin_email, "$subject", "$desc", "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
If you are seeing this, you need to go back and fill out the Personal Email section!
<?php
}
header("location:complete.php");
mysql_close($con)
?>
Thanks in advance.
How do I display the actual errors in IIS 7.5? If I miss a semicolon, I get: "HTTP Error 500.0 - Internal Server Error" absolutely useless. In prior versions, I could see the line and get to the PHP error. How do I display PHP errors? I've added: set_ini('display_errors', '1'); but it doesn't help. |