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PHP - What Do I Need To Do To Change Convert A Part Of Image To Another
HI
I'm thinking to do something like this , I've seen this in a website ,I'm a php designer but i don't know who something like this can be done . it's a website that sells sofas . we've the ability to change the color and fabric and see the result right away . for example ,this is the default sofa : then I can select a part of it and I can choose the fabric and color , then it make the result : thats it , How can I do that ? What should I do ? I'm really looking to hear from you King Regards Similar TutorialsI have created a flashcard program to teach Japanese vocabulary. I want to add sound files from native speakers so I have created a page with a recorder that
1. displays a word (on load)
2. allows the native speaker to record the word (on press of a button)
3. uploads the recording to the server (on press of another button)
I wrote the word display as a separate php script so that I could use Ajax to just change the word being recorded, so that I would not need to reload the entire page every time the speaker switched to a new word.
The js that gets the word to be recorded is:
function ajaxRequest(){
//declare the variable at the top, even though it will be null at first
var req = null;
//modern browsers
req = new XMLHttpRequest();
//setup the readystatechange listener
req.onreadystatechange = function(){
//right now we only care about a successful and complete response
if (req.readyState === 4 && req.status === 200){
//inject the returned HTML into the DOM
document.getElementById('cardData').innerHTML = req.responseText;
};
};
//open the XMLHttpRequest connection
req.open("GET","nextcard.php",true);
//send the XMLHttpRequest request (nothing has actually been sent until this very line)
req.send();
};
The section that uploads the file is:
$('#send').click(function(){
$.jRecorder.sendData();
}
and it gets the filename from another script:
$.jRecorder(
{
host : 'http://localhost:10088/NewFolder/japanese/jrecorder/acceptfile.php?filename=hello.wav'
The problem that I have is that when I get each word I want to change the name of the file being uploaded. It all works and if I reloaded the page each time I could do this:
$.jRecorder(
{
host : 'http://localhost:10088/NewFolder/japanese/jrecorder/acceptfile.php?filename=<?php echo $word.'_'.$reader_id;?>.wav'
but I want to stay on the Ajax path. So, I think that I need to convert the newcard program to return json with something like:
$response=array(filename=>$word.$reader_id, card_data=>$card_stuff); echo json_encode($response);but once I get the json back I don't see how I get the filename into the script that sets the upload url and make that script re-execute. Is there a reasonable way to do that? Hi all, first time here as I am a bit stuck. I am by no means a programmer and I was hoping that someone out there may have a simple solution to my problem?... So here goes" I have a voucher/offers site up-and-running. The site content is generated from an external feed. I want to create other sites and I want to track what sales/clicks have come from where. An example of the feed: (http://www.awin1.com/awclick.php?mid=251&id=28971&clickref=[URL_REFERENCE]&p=http://www.247electrical.co.uk) As you will see, I have [URL_REFERENCE] in each link. I want to automatically change that part of the string in the database. Does anyone have any thoughts? Hi, I have some images that I want to resize to a square dimention (40px 40px). However, not all image are square, so when they are resized, they lose their ration and look squashed. Is there a way I can display just a part of the original image, say 40px x 40px on the top middle of each image? I hope that makes sense I'll explain with an example: I have this image: http://www.fitnessvital.com/images/galeria/caballo-pastando-0.jpg I create a thumbnail of it: http://www.fitnessvital.com/images/galeria/thumbs/caballo-pastando-0.jpg You can see that it's a big image where the important thing is the horse. The grass is not important. So, the best thing to do it's to crop the extra grass and resizing the rest. So the question is: There's a way of recognizing the objects of an image and crop the rest ? Or identify the non important of an imagen and cropt it ? (the same rewrited) Thank you My query gets the results and orders by one of the fields. Once I get the MySQL results I would like to find the first entry that has a letter as the first character of the same field that the list was ordered by, then split the results in to two parts and swap them. So that the results that have a letter at the start of the same sorted field are as the begining and the results that have the numbers as the start at the end of the array. But also so that the array works the same way as the original results string, so i can use say $results['mysqlfield'] Code: [Select] <? $out = preg_replace('/^(.{701}[^.]*).*/i','$1.',$detrsltnewsrow[news_desc]); echo $out; ?> </td></tr><tr><td colspan="2" class="para" style="padding-left:10px;"> <?= substr(stripslashes(trim($detrsltnewsrow[news_desc])),701) ?> </td></tr> I have the above snippet.. The first php statement, basically grasp the first 701 characters with the closet next stop "." character and out puts it. then out puts the HTML tags I have a problem with the second statement. I want to output anything after what has been outputted by: Code: [Select] <? $out = preg_replace('/^(.{701}[^.]*).*/i','$1.',$detrsltnewsrow[news_desc]); echo $out; ?> So need the correct syntax for Code: [Select] <?= substr(stripslashes(trim($detrsltnewsrow[news_desc])),701) ?> Currently it breaks at exactly the 701 character, want it to continue from the sentence the first code ended in. I have a form where you can enter a image url and it's title. It calls display.php which displays the image as well as the title. But I want the image to be displayed as a thumbnail of size 150X100. Do i have to store it in directory before I convert it and display? If so, can somebody tell me how to convert the image into a thumbnail? Here is my code: Code: [Select] <table align="center" bgcolor="silver"> <form action="display.php" method ="post"> <tr> <td align="center"><b><font color="#214754" size="3">Reg</font></b></td> </tr> <tr> <td> Title: </td> <td><input type="text" size ="40" name="registry_title1" /></td> </tr> <tr> <td> Image URL: </td> <td><input type="text" size ="40" name="registry_img1" /></td> </tr> <tr> <td> <input type="submit" name="submit" value="submit" /> </td> </tr> </form> </table> </div> here is the code for display.php Code: [Select] <? /* Get Registry details */ $registry_img1=$_POST['registry_img1']; $registry_title1=stripslashes($_POST['registry_title1']); ?> <html> <body> <table width='600' cellspacing='0' cellpadding='0' border='0' bgcolor='#ffffff' align='center'> <tr> <td style='padding-bottom:8px';><font style='font-size:18px;color:rgb(0, 0, 0);text-decoration:none'><a style='font-size:18px;color:rgb(0, 0, 0);text-decoration:none' href='#'><? echo ucfirst($url); ?> Registry</font></a></td> </tr> <tr> <td style='padding-bottom:10px;'> <a style='color:rgb(206, 0, 0);font-size:14px;font-weight:bold;line-height:18px;text-decoration:none' href='<? echo $registry_url1; ?>' target='_blank'><img style='padding-right:10px' border='0' align='left' alt='' src='<? echo $registry_img1; ?>'><? echo $registry_title1;?> </a> </td> </table> </body> </html> Magandang Araw, Just want to ask if this idea is feasible or something, these past few days im doing some research on how materialize the said topic and apparently there were no sound solution so far. , im working on a script that allows users to publish html design to jpg, Im done with Imagemagik since its the nearest inline with the specs, so is there any other solution aside from this? im thinking of a php script that will do the job, more likely some gdlibrary manipulation or something. Salamat Jestoni Hi all, I am dealing with an html page in which a dynamically created PNG image is shown with: <img src="createchart.php"> The problem arises when users try to download the image since the default name that appears is just "createchart.php". Is there any way to make the browser suggest something like "chart.png"? Than you guys for your help, Mam Using php I have a dynamically filled select box with the names of images. How can I get an image box on my page and change upon selection? This creates an image 1500x1500 pixels. But it creates it in black... how can i make it white. And i have to use imagecreatetruecolor() not imagecreate(). <?php $im = imagecreatetruecolor(1500,1500); // Output the image to the browser header('Content-type: image/jpg'); imagejpeg($im); imagedestroy($im); ?> Thanks! Main URL of website home page: www.mysite.com and this shows image "A" in the header. I want to have a marketing campaign which will send people to my site via this link: www.mysite.com/index.php?ref=att When people get to my site via the 2nd link, I want to show image "B" instead of image "A". I put this at top of home page... Code: [Select] require_once("includes/session.php"); if (isset($_GET['ref']) && ($_GET['ref'] == "att")) { $_SESSION['ref'] = "att"; } else { } and this code is in my header include file, a little further down on the page... Code: [Select] <?php if (isset($_SESSION['ref']) && $_SESSION['ref'] == "att") { echo "<span class='phone'><img src='/images/B.png' /></span>"; } else { echo "<span class='phone'><img src='/images/A.png' /></span>"; } ?> Does this look right? because I can't get it to work. It's showing image A regardless of which URL I use. I have to be missing something obvious because I really thought this would be super easy to do. If anyone sees any problems, let me know. But I'll keep testing and hopefully find my mistake. Thanks! Hi,
I want to show one image for the new visitors of my website and another for the returning visitors. What I want to do is that after the visitor reload the page he will see another image instead of the first one.
Hey guys! I have the following php code that grabs variables (and the browsed image) from Flash. //FLASH VARIABLES $Name = $_POST['Name']; $itemNumber = $_POST['itemNumber']; $filename = $_FILES['Filedata']['name']; $filetmpname = $_FILES['Filedata']['tmp_name']; $fileType = $_FILES["Filedata"]["type"]; $fileSizeMB = ($_FILES["Filedata"]["size"] / 1024 / 1000); list($filename, $extension) = explode('.', basename($_FILES['Filedata']['name'])); $filename = $Name; $target = $filename . $itemNumber . "." . $extension; // Place file on server, into the images folder move_uploaded_file($_FILES['Filedata']['tmp_name'], "images/".$target); This works perfect, but what I want to change is the width and height of the uploaded image. Any ideas/suggestions on how this could be done? Thanks in advance!! Cheers! Currently, I insert a small thumbnail image at the begging of each row in a set of records from a mysql query. But that image is the same image for each record in that array. Is there a way to conditionally change which image is used, based on a value either in that same table, or a related table. See attached screenshot... and here's my current code.... Code: [Select] <?php $query = "select address from nvc"; $result = mysql_query($query); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $details=''; $details.='<li class="menu"><a href=detail.php?address='.(urlencode($row['address'])).'><img src="thumbs/house.png" /><span class="name">'.$row['city'].'</a>'; $details.='</li>'; echo($details); } ?> Thank you for any input. I have a PHP script that uploads images to a folder on my server (attachments folder). Currently the folder sits within my webroot and is publicly accessible (I have to use chmod 777 due to permissions issue). So, I created the "attachments" folder outside of my webroot (so that it is not publicly accessible), but I do not know how to set the path in the PHP code to upload it to that "attachments" folder outside of the webroot. As you see in the snippet of PHP code below, the code currently uploads the the "attachments" folder within the www (webroot) directory. How do I make it upload to the "attachments" folder OUTSIDE of the www (webroot) directory? foreach($files[$form] as $file){ $str = $file[1]; if (eval("if($str){return true;}")) { $_values[$file[0]] = $_FILES[$file[0]]["name"]; $dirs = explode("/","attachments//"); $cur_dir ="."; foreach($dirs as $dir){ $cur_dir = $cur_dir."/".$dir; if (!@opendir($cur_dir)) { mkdir($cur_dir, 0777);}} $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; copy($_FILES[$file[0]]["tmp_name"],$_values[$file[0]."_real-name"]); @unlink($_FILES[$file[0]]["tmp_name"]); }else{ $flag=true; if ($_isdisplay) { //$ExtFltr = $file[2]; //$FileSize = $file[4]; if (!eval("if($file[2]){return true;}")){echo $file[3];} if (!eval("if($file[4]){return true;}")){echo $file[5];} $_ErrorList[] = $file[0]; } } } i am new to web designing,
i don't know much about javascript.
<select id="plan" align="center" valign="center"> This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=347058.0 |
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