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PHP - Can Not Use Isset($_post)
I want to link this two file but not working,
first file to make drop down option form
Similar TutorialsRunning into some problems with my code. I am having the user search the Database with either a UAID or the user's full name. It works fine when you input both the UAID and name; however, I want it to work if only one is give (i.e. just the name or just the UAID). I decided to use the isset($_POST) function of php but I am not getting it to work correctly. PHP believe it is set even though it is empty. Here is my html form. <?php @include 'accesscontrol.php'; echo "<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\">" ."<html xmlns=\"http://www.w3.org/1999/xhtml\">" ."<title> Hello </title>" ."<meta http-equiv=\"Content-Type\" content=\"text/html; charset=iso-8859-1\" />" ."<head>" ."<style type=\"text/css\">" ."h1{" ."border-bottom-style: double;" ."border-bottom-color: black;" ."border-bottom-width: 5px;" ."}" ."p{" ."background-color:#4682B4;" ."}" ."</style>" ."</head>" ."<body style=\"background-color:#B8B8B8\">" ."<table align=\"center\" style=\"background-color:#B8B8B8\" WIDTH=\"100%\" HEIGHT=\"100%\">" ."<tr valign=\"middle\">" ."<td align=\"center\">" ."<form method=\"post\" action=\"user.php\">" ."<table align=\"center\" cellpadding=\"10\" style=\"background-color:#5CADFF\" width=\"500\" height=\"400\">" ."<tr>" ."<th colspan=6 align=\"center\"><h1>Welcome: ".$uid."</h1></th>" ."</tr>" ."<tr>" ."<td colspan=3 width=40% align=center>" ."UAID:<br> <input type=\"text\" size=\"8\" name=\"UAID\" /></td>" ."<td colspan=3 width=60% align=center>" ."Name (Last, First):<br><input type=\"text\" size=\"8\" name=\"last\"/>, <input type=\"text\" size=\"8\" name=\"first\" />" ."</tr>" ."<tr>" ."<td colspan=6 align=\"center\"><input type=\"submit\" value=\"submit\" />" ."</td>" ."</tr>" ."</tr>" ."</table>" ."<tr>" ."</tr>" ."</td>" ."</tr>" ."</table>" ."</body>" ."</html>"; ?> Here is the PHP: <?php @include 'accesscontrol.php'; //include 'common.php'; include 'db.php'; $fname = $_POST['first']; $lname = $_POST['last']; $sql = "SELECT * FROM `user` WHERE UAID='$_POST[UAID]'"; $result = mysql_query($sql); $rows = mysql_fetch_array($result); if(isset($fname) && isset($lname)) { echo "Post first $fname <br>" ."Post last $lname"; $firstname = $rows['firstname']; $lastname = $rows['lastname']; if($fname != $firstname OR $lname != $lastname) { ?> <html> <head> <script language="JavaScript"> alert(" Hello this is crap" ); history.back(); </script>"; </head> </html> <? exit; } else { echo "<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"URL\">" ."<html xmlns=URL>" ."<title> Hi </title>" ."<meta http-equiv=\"Content-Type\" content=\"text/html; charset=iso-8859-1\" />" ."<head>" ."<style type=\"text/css\">" ."h1{" ."border-bottom-style: double;" ."border-bottom-color: black;" ."border-bottom-width: 5px;" ."}" ."p{" ."background-color:#4682B4;" ."}" ."</style>" ."</head>" ."<body style=\"background-color:#B8B8B8\">" ."<table align=\"center\" style=\"background-color:#B8B8B8\" WIDTH=\"100%\" HEIGHT=\"100%\">" ."<tr valign=\"middle\">" ."<td align=\"center\">" ."<table align=\"center\" cellpadding=\"10\" style=\"background-color:#5CADFF\" width=\"600\" height=\"400\">" ."<tr>" ."<th colspan=6 align=\"center\"><h1>Welcome: ".$uid."</h1></th>" ."</tr>" ."<tr>" ."<form method=\"Post\" action=\"userview.php\">" ."<td colspan=3 width=40%>" ."UAID: <input type=\"text\" size=\"8\" name=\"UAID\" value= ".$_POST['UAID']." /></td>" ."<td colspan=3 width=60%>" ."Name (LAST, FIRST):<input type=\"text\" size=\"8\" name=\"last\" value= ".$_POST['last']." />, <input type=\"text\" size=\"8\" name=\"first\" value= ".$_POST['first']." />" ."</td>" ."</tr>" ."<tr>" ."<td colspan=3 width=40%>" ."Department:<input type=\"text\" size=\"8\" name=\"department\" value=" .$rows['BOG'].">" ."</td>" ."<td colspan=3 width=60%>" ."Employee ID:<input type=\"text\" size=\"8\" name=\"empID\" value=" .$rows['employeeID'].">" ."</td>" ."</tr>" ."<tr>" ."<td colspan=3 align=\"center\"><input type=\"submit\" value=\"View\">" ."</form>" ."</td>" ."<form method=\"Post\" action=\"homepage.php\">" ."<td colspan=3 align=\"center\"><input type=\"submit\" value=\"Back\">" ."</td>" ."</tr>" ."</tr>" ."</table>" ."<tr></tr></td></tr></table></body></html>"; }} mysql_free_result($result); ?> Is it possible to unset a submit button? <?PHP if(isset($_POST['Submit'])) { $date = $_POST['date']; if ($date = '1966-10-03'){ //Do Something } else { //Possible to unset? unset($date); unset($_POST['Submit']); } } else { ?> <form action="" method="post"> <input type="text" name="date" /> <input type="Submit" name="Submit" value="Submit" /> </form> <?PHP } ?> What I'm wondering is if it's possible to unset after submitting in the event of condition x. Should this not in turn echo out the form as it has been unset? I'm not sure why this code isn't working... I've done this many times before and this time it isn't working at all... Here's the code I'm using: <?php if(isset($_POST['submit'])){ if(filter_var($_POST['value1'], FILTER_VALIDATE_EMAIL)){ echo "Value is a valid email address."; } else { echo "Value is NOT a valid email address."; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="POST"> <input name="value1" type="text" id="value1" size="40" /> <input id="submit" name="submit" value="Validate Value" type="button" /> </form> </body> </html> I'm wondering whether anything has changed, but I don't see how this couldn't work. Thanks for any additional information! I have a simple log in form. By debugging I found that isset post submit function is not responding. It remains on the same page after submitting form. I have googled all the possible solutions to this problem but none worked. Any help is greatly appreciated. The form is in multiplelogin.php file and the code is in multi.php file. After login redirection is to teachers.php file. <?php session_start(); $conn = mysqli_connect("localhost", "root", "", "signup");
if(isset($_SESSION['username'])) {
?>
<head> <link rel="stylesheet" type="text/css" href="bootstrap.css"> <title> Teachers Students Login </title> </head> <body class="bg-secondary"> <div class="container"> <div class="row justify-content-center"> <div class="col-log-5 bg-light mt-5 px-0"> <h3 class="text-center text-light bg-primary py-3 px-5"> Log In </h3>
<div class="form-group px-5"> <input type="email" name="email" class="form-control form-control-lg" placeholder="Email" required> </div> <div class="form-group px-5"> <input type="password" name="password" class="form-control form-control-lg" placeholder="Password" required> </div> <div class="form-group px-5"> <input type="submit" name="submit" value="Submit" class="btn btn-primary btn-block"> </div> </form> </div> </div> </div>
<?php
ini_set( 'display_errors', 1 );
$password = $_POST['password'];
$stmt = mysqli_stmt_init($conn); header("Location: multilogin.php?error=sqlerror"); exit();
} else { mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
if ($pwdCheck == false) {
exit(); $_SESSION['username'] = $row['username']; $_SESSION['email'] = $row['email']; header("Location: teachers.php?login=success");
exit ();
exit();
exit();
else {
exit(); Isn't this code redundant... if (isset($_SESSION['loggedIn']) && $_SESSION['loggedIn'] == TRUE){ After all, if $SESSION['logged_in'] == TRUE then it is *obviously* set... Debbie I want to get the COUNT of the fields (ArrayM11 - ArrayM19), which has the word "YES". The code isn't working. Appreciate any help. $Array1 = array(); for($j=0;$j<count($ArrayM1);++$j) { $result = array_count_values($ArrayM1[$j]); if (isset($result['YES'])) { $points1 = $result['YES']; } } Hello all, i am hoping someone can help me. i have some code i have been working on and i am trying to add a 404 page if it cant find the page, i know it will be some sort of if statment, but with me been pretty much a noob at php i am stuck. heres the code that the page calls. Code: [Select] function get_content() { //Get page name from browser if none call it home $page = (isset($_GET['page'])) ? $_GET['page'] : 'home'; //Get The Page Content $sql = "SELECT * FROM content WHERE page = '$page'"; $res = mysql_query($sql) or die (mysql_error()); while($row = mysql_fetch_assoc($res)){ //Show The Page Content echo '<h1>' . $row['title'] . '</h1>'; echo $row['body']; } } thanks all. I believe that my problem is with the isset on line 7 and 39, but I do not know of anyway around it. Can someone enlighten me. <?php session_start(); if (isset($_GET['logout'])){ unset($_SESSION['logged_in']); } ?> <html> <head> <title>Add a New Car!</title> <?php if (isset($_POST['submit'])) { //print_r($_POST); $password = md5($_POST['password']); //echo'<p>'.$password.'</p>'; $username = ($_POST['username']); //echo'<p>'.$username.'</p>'; } $db = new PDO('sqlite:login.sqlite'); $login = 'SELECT * FROM login WHERE userid="'.$username.'" AND password="'.$password.'";'; //echo'<p>'.$login.'</p>'; $attempt = $db->query($login); foreach ($attempt as $row) { //print_r($row); $_SESSION['logged_in'] = $username; } ?> </head> <body> <?php if (!isset($_SESSION['logged_in'])){ ?> <form method="post" action="Db_login.php"> <p>Username:<br /><input type="text" name="username" /> </p> <p>Password:<br /><input type="password" name="password" /></p> <p><input type="submit" name="submit" value="Log In!" /></p> </form> <?php } else { ?> <?php if(isset($_POST['submit'])) { print_r($_POST); $make = ($_POST['make']); $model = ($_POST['model']); $year = ($_POST['year']); $fuel = ($_POST['fuel_type']); $vin = ($_POST['vin_number']); $reg = ($_POST['reg_number']); } $db = new PDO('sqlite:cars.sqlite'); $sqlCars = 'INSERT INTO cars ( ) VALUES("'.$make.'","'.$model.'","'.$year.'","'.$fuel.'","'.$vin.'","'.$reg.'");'; echo'<p>'.$sqlCars.'</p.>'; ?> <form method="post" action="Db_new_Cars.php" enctype="multipart/form-data"> <p>Make:<br /><input type="text" name="make" /> </p> <p>Model:<br /><input type="text" name="model" /></p> <p>Year:<br /><input type="text" name="year" /></p> <p>Fuel Type:<br /><input type="text" name="fuel_type" /></p> <p>Vin Number:<br /><input type="text" name="vin_number" /></p> <p>Reg Number:<br /><input type="text" name="reg_number" /></p> <p>Choose a image to upload:<br /> <input type="file" name="myfile"></input></p> <p><input type="submit" name="submit" value="Submit!" /></p> </form> <h1> Protected Content!</h1> <p>You are logged in as <em><?php echo $_SESSION['logged_in']; ?> </em></p> <p><a href="Db_login.php?logout=true">Log out!</a></p> <p><a href="New_Cars.php">Add a new car</a></p> <p><a href="Book_Out_Cars.php">Book out a car</a></p> <?php } ?> </body> </html> i Have two page login.php and verify.php In login.php user is entering Username and Password and in the action of the form i am writing verify.php. If verification is a success then i will start a session() Code: [Select] session_start(); $_SESSION['ls']="loggedin"; // ls stands for login status $_SESSION['id']=$row['id']; $_SESSION['user_name']=$row['user_name']; $_SESSION['email']=$row['email']; header('location : members.php'); die (" "); and will redirect them to members.php .... Everything is working fine... But in login.php i have written a code on the top... Code: [Select] <?php if(isset($_SESSION['ls']) && isset($_SESSION['id']) && isset($_SESSION['user_name']) && isset($_SESSION['email']) ) { header('location:members.php'); die(" "); } ?> I want if a session is started and if user will access login.php they will automatically go to members.php But this script is not working... Iam not getting whats the problem... also i m not getting any error login.php or anything CODE WRITTEN ON THE TOP OF members.php IS : Code: [Select] <?php session_start(); if(@$_SESSION['ls']!=="loggedin" ) // Checks if the person has done stage one (Registration.php) { header('Location: login.php'); //If they haven't done it, it sends them back. die (" "); } ?> guys this thing called isset() is bugging me.What is the difference in when you say Code: [Select] if(isset($_POST['name'])) and Code: [Select] if($_POST['name']) and Code: [Select] if(!$_POST['name']) and why would someone require a code such as Code: [Select] if($_POST['submit']=='Submit') And what is that code which tells you the user has entered something into the form Thanks People why dose this not work <?php if(isset($_SESSION['SESS_ADMIN'])) $loc = ../admin/admin.php; else $loc= ../head/head.php"; ?> <form><INPUT TYPE="button" value="Main Menu" onClick="parent.location='<?php echo $loc; ?>'"></form> </body> </HTML> Hi all I need to do a multiple if isset to get three variables from the URL. Here is my code for just one: if(isset($_GET['category'])) { $fetchproducts = mysql_query(" SELECT * FROM `products` WHERE category = '".$_GET['category']."'"); while($returnedProduct = mysql_fetch_array($fetchproducts)) { include('product-cell.php'); } How do I combine this to check what is the 'type' and 'colour' from the URL and fetch from the SQL accordingly? Many thanks for you help Pete Hi there, I'm inserting data into a mysql database. My submissions works fine, however when a part of the form is not filled out the php scripit crashes. How can I submit all data that is set and skip pieces that aren't filled out? For example I have a plant database which has an option to insert different types of common names for the plant. It's ok if they aren't all filled out. My code is as follows: Code: [Select] <?php //insert general plant data into db $queryplant="INSERT INTO actualplanttable (id, scientific, common1, common2, common3, family, genus, description, planting, growing, care, duration, reference) VALUES ('NULL', '$_POST[scientific]', '$_POST[common1]', '$_POST[common2]', '$_POST[common3]', '$_POST[family]', '$_POST[genus]', '$_POST[description]', '$_POST[planting]', '$_POST[growing]', '$_POST[care]','$_POST[duration]','$_POST[reference]')"; mysql_query($queryplant) or die ('Error updating actualplanttable'); //insert maintenance data into db $querymaintenance="INSERT INTO plantmaintenancelinktable (plant_id, maintenance_id) VALUES ('$inserted_id', '$_POST[maintenance]')"; mysql_query($querymaintenance) or die ('Error updating plantdurationtable'); ?> Should I be trying to work an isset function into this code? Any help would be greatly appreciated. Thanks! Bill... This is blowing my mind. I have this function and all I want it to do is check to make sure that the var $race is set and = '0'. The default value from the form is '0'. I also want it to check the value of race and if it is anything but the two listed , submit error. Yes I've tried to replace the || with &&.. Nothing works(Meaning that it will error when its not suppose to or it wont error when its suppose to).. Any ideas? Code: [Select] function check_Race ($race,$display_name,$member_id,$description,$ip) { //echo "This is the race". $race; //exit; if (isset($race) && $race ='0' && $race !== 'White' && $race !== 'Black'){ echo "This is an errror.!"; $t_error="19"; $member_id = $member_id; notify_Admin($t_error,$member_id,$ip); // logOut ($t_error); exit; } Hi guys, first time posting here. Anyway, heres my problem. I have this section of code at the beggining of my page: Code: [Select] if (isset($_POST['userChoice'])) { $try = check_word($_POST['userChoice']); echo ("We are into the loop"); } else { echo ("<br/>about to call change word"); changeword(); echo ("<br/> we called the changeword"); } And here is my form: Code: [Select] <html> <head> </head> <body> <form name="wordguess" action="Index.php" method="POST"> <table> <tbody> <tr> Try to guess what the following word is: <?=$scrambled ?> <br/> </tr> <tr> Your Guess: <input type="text" id="userChoice" size="20" /> <br/> </tr> <tr> <td> <input type="submit" name="submit" id="submit" value="Submit"> </td> </tr> <tr> <?=$correct?> </tr> </tbody> </table> </form> </body> </html>' Now, how i assumed it worked was that the first time the page is loaded it would display the form and that's it. However, even when they hit the submit button on the form, its not really doing the POST, so when the page reloads, gives me the same stuff so it always goes on the else part of the if. Any help would be appreciated. Thanks, GoodVibe Hi i am connecting to my database and i need the script to print something if the field is not empty, I am using the following, but its not working any ideas where i am going wrong? if (isset($row[image_zero])) { Hey, I've got a site and I need to query a database to check if there is a result. If there isnt then I need a default result... //Check the database and get a result $skinName = strtolower(get_post_meta($post_id, $key, $single)); if (isset($skinName)) { //If there is a result, then use it $skinName = strtolower(get_post_meta($post_id, $key, $single)); } else { //If NO result then use RED $skinName = 'red'; } //Build up the var to show REDsite $skinName = $skinName . 'site'; For some reason the above doesnt work. If there is a result then it uses it, however if there is no result then it simply shows "site" - not "redsite" like it should do. Any ideas what I missed? In my index.php I use a global $_GET variable he Code: [Select] $ibforums->input = $std->parse_incoming(); parse_incoming function is: Code: [Select] function parse_incoming() { global $HTTP_GET_VARS, $HTTP_POST_VARS, $HTTP_CLIENT_IP, $REQUEST_METHOD, $REMOTE_ADDR, $HTTP_PROXY_USER, $HTTP_X_FORWARDED_FOR; $return = array(); if( is_array($HTTP_GET_VARS) ) { while( list($k, $v) = each($HTTP_GET_VARS) ) { //-- mod_sec_update_131 begin if (strpos($k, "amp;") === 0) $k = substr($k, 4); //-- mod_sec_update_131 end if ( $k == 'INFO' ) { continue; } if( is_array($HTTP_GET_VARS[$k]) ) { while( list($k2, $v2) = each($HTTP_GET_VARS[$k]) ) { $return[$k][ $this->clean_key($k2) ] = $this->clean_value($v2); } } else { $return[$k] = $this->clean_value($v); } } } // Overwrite GET data with post data if( is_array($HTTP_POST_VARS) ) { while( list($k, $v) = each($HTTP_POST_VARS) ) { if ( is_array($HTTP_POST_VARS[$k]) ) { while( list($k2, $v2) = each($HTTP_POST_VARS[$k]) ) { $return[$k][ $this->clean_key($k2) ] = $this->clean_value($v2); } } else { $return[$k] = $this->clean_value($v); } } } //---------------------------------------- // Sort out the accessing IP // (Thanks to Cosmos and schickb) //---------------------------------------- $addrs = array(); foreach( array_reverse( explode( ',', $HTTP_X_FORWARDED_FOR ) ) as $x_f ) { $x_f = trim($x_f); if ( preg_match( '/^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$/', $x_f ) ) { $addrs[] = $x_f; } } $addrs[] = $_SERVER['REMOTE_ADDR']; $addrs[] = $HTTP_PROXY_USER; $addrs[] = $REMOTE_ADDR; //header("Content-type: text/plain"); print_r($addrs); print $_SERVER['HTTP_X_FORWARDED_FOR']; exit(); $return['IP_ADDRESS'] = $this->select_var( $addrs ); // Make sure we take a valid IP address $return['IP_ADDRESS'] = preg_replace( "/^([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})/", "\\1.\\2.\\3.\\4", $return['IP_ADDRESS'] ); $return['request_method'] = ( $_SERVER['REQUEST_METHOD'] != "" ) ? strtolower($_SERVER['REQUEST_METHOD']) : strtolower($REQUEST_METHOD); return $return; } Now, I use my $ibforums->input throughout my forum system, and I use it in EVERY SINGLE file, I have around 50 Files and I get "unidetified variable" errors. is there a way I can just make sure my global $ibforums->input is ISSET so it it's a GLOBAL ISSET? So I don't have to go through each file that uses $ibforums->input and put a isset( ) around it? It would take over prob 10 days to go through each file and change all 300-500 errors, using the $ibforums->input, there has to be a way I can globally defined my $ibforums->input Variable with a isset.. Thank you What I remember from my college days is that isset check whether the variable has a value set or not and return true or false value.
However I encountered a code in wordpress -
// Set up the content width value based on the theme's design and stylesheet. Code: [Select] if (isset($_COOKIE['hide_div']['0']) && isset($_COOKIE['hide_div']['2'])){ $cookie1 = $_COOKIE['hide_div']['0']; $cookie2 = $_COOKIE['hide_div']['2']; } if ($cookie1 == $cat_id OR $cookie2 == $cat_id) { foreach ($this->forums as $forum_id => $forum_data) { if ($forum_data['category'] == $cat_id) { //----------------------------------- // We store the HTML in a temp var so // we can make sure we have cats for // this forum, or hidden forums with a // cat will show the cat strip - we don't // want that, no - we don't. //----------------------------------- $temp_html .= $this->process_forum($forum_id, $forum_data); } } if ($temp_html != "") { $this->output .= $this->html->CatHeader_Expandedhidden($cat_data); $this->output .= $this->html->end_this_cat(); } unset($temp_html); }else{ $cookie1 = ''; $cookie2 = ''; why in the world is it displaying Undefined variable: cookie1 and cookie2 as errors? When I declared both of them even AFTER my if statement, this is bogus dude, lol this isset stuff is really confusing or am i just not doing it right? |
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