PHP - Newbie String Replace Question

hello again need some advice

cant get it working

Code: [Select]
SELECT * FROM `tsue_members` WHERE memberid=0

if ($row['memberid'] == '0')
        {
$img = "1.gif";
}

echo $img;

Hello All,
 
I've been knocking my head against the wall for several hours trying to figure out what's going on with a simple string replace.  For the most part it is working beautifully, but if a string contains a similar but not exact match it still replaces the non match.  I was under the impression that str_replace always looks for an exact match.
 
I have custom tags that are in strings of text that are structured like:  [A_CUSTOM_HEADER] [A_CUSTOM_TITLE]  and so on.  They always start with  "[A_CUSTOM"  and end with a " ] ".  In between the start and end can be just about anything.  So my problem is if I have [A_CUSTOM]  and [A_CUSTOM_TAG] in the same text str_replace seems to incorrectly replace all the [A_CUSTOM_TAG] with the [A_CUSTOM] content and the match never happens for the [A_CUSTOM_TAG] content.
 
For example:

$content = 'Here is some text and [A_CUSTOM].  Here is more text and [A_CUSTOM_TAG]'.
$content = str_replace('[A_CUSTOM]','I have a and custom',$content);
$content = str_replace('[A_CUSTOM_TAG]','I have a, custom and tag',$content);

So running that code The [A_CUSTOM_TAG] content never gets replaced correctly, it is replaced on the first pass with the [A_CUSTOM] replacement content.  
 
I hope this make sense I'm trying to explain it the best I can.
 
I tried using preg_replace() with \b to match the whole word but didn't get anything close to the respected results...haha
 
I'm sure I'm missing something simple...or at least I hope I am.
 
Thanks in advance!
Edited by Twitch, 22 May 2014 - 11:52 AM.

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=319445.0

Hi,


I am trying to take a string from a database and replace everything within {} with code... similar to how posting in a forum works.


so say I have "...Lorem ipsom {gallery:1} sit imet..."
it will take that string (from a DB) and replace "{gallery:1}" with "<?php gallery('1'); ?>". How can this be done? Or is there keywords I can search on to find the answer? Thank you in advance.

 hey guys just a simple one...im trying to replace {$name}  but i dont think ive got the right prefix in the str_replace function...if anyone could tell me where i am going wrong please

$content = str_replace("{/$".$variable."}", $value, $content);
{$name}

I wanted to replace a strings in a large text file .. what would be the fastest way ?!

e.g the text file contains ..

INSERT INTO `subjects` VALUES (1, 'some text here', 'some text here', 'some text here');
INSERT INTO `subjects` VALUES (2, 'some text here', 'some text here', 'some text here');
INSERT INTO `subjects` VALUES (3, 'some text here', 'some text here', 'some text here');
INSERT INTO `subjects` VALUES (4, 'some text here', 'some text here', 'some text here');
INSERT INTO `subjects` VALUES (5, 'some text here', 'some text here', 'some text here');

I wanted to replace the string " VALUES (1, " with  "VALUES (" in each line ..
I'm new in PHP so any response would be much appreciated .. thanks

I embed videos on my site. I submit the embed codes to my database using a form. The codes look like this:

<iframe width="560" height="315" src="//www.youtube.com/embed/xDIgbjDGsOM?rel=0" frameborder="0" allowfullscreen></iframe>

Before I submit each code, I have to change its width and height, and I have to add this:

&showinfo=0

after this:

?rel=0

Is there a function that will allow me to do all of that simultaneously?   I know about str_ireplace(). It will let me replace ?rel=0 with ?rel=0&showinfo=0, but I don't know how to simultaneously make the other changes.   It's not helping that the embed code includes quotation marks.

I have a web server which contains a public site and a private site. I want to be able to test for public or private using the page title and return the appropriate header which contains a different banner, css etc.

Firstly - the syntax below seems to be incorrect because it doesnt work correctly.
More importantly how do I add all the values to an array and than iterate through it to check for a matching page title?

Code: [Select]
public function publicSite() {
if ($this->getTitle()== 'Home' || 'About Us'||'Registration' || 'Sitemap' || 'Contact Us' || 'Useful Links' || 'Feedback') {
return true;
}
return false;
}
Then later on I would have:
Code: [Select]
if ($this->publicSite()) {
require($ROOT.'interface/pages/publicheader.php');
}
else {
require($ROOT.'interface/pages/privateheader.php');
}

Thanks heaps!

After looking around the net and getting i feel close i though i would post and ask you all.

I am trying to add x number of names to a database each on its own row. I found some code and have edited it and i understand most of what its doing but i cannot get it to work, it just add witch ever name was last.

Here is the form code just with 3 test fields.
Quote

<form id="form1" name="form1" method="post" action="addplayer2.php">
       <p>
        <input name="player[]" type="text" id="player[]" size="15" />
      </p>
         <p>
        <input name="player[]" type="text" id="player[]" size="15" />
      </p>
         <p>
        <input name="player[]" type="text" id="player[]" size="15" />
      </p>
 <input type="submit" name="submit" id="submit" value="Submit" />
</form>


Ok this the script i found in it unedited state, i thought i would be easy to understand if you saw it before i broke it.

I tried changing the word Activity to player and the work Act to play and then changing all other referanced.
Quote

<?php
$con = mysql_connect("localhost","Application","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("CpaApp", $con);

foreach($_POST['Activity'] as $row=>$Act)
{
$Activity=$Act; // why does this not have post? Or is it using the one above?
$Position=$_POST['Position'][$row];
$StartDate=$_POST['StartDate'][$row];
$EndDate=$_POST['EndDate'][$row];
}


//enter rows into database
foreach($_POST['Activity'] as $row=>$Act)
{
$Activity=mysql_real_escape_string($Act); // Same question why no $_POST? does it use the one above?
$Position=mysql_real_escape_string($_POST['Position'][$row]);
$StartDate=mysql_real_escape_string($_POST['StartDate'][$row]);
$EndDate=mysql_real_escape_string($_POST['EndDate'][$row]);
}


$involv = "INSERT INTO Involvement (Activity, Position, StartDate, EndDate)
VALUES ('.$Activity.','.$Position.','.$StartDate.','.$EndDate.')";


if (!mysql_query($involv,$con))
{
die('Error: ' . mysql_error());
}
echo "$row record added";

mysql_close($con)
?>


On filling out the fields with name lets say Paul Bill and Jack it echos that it has added x number of rows but when looking in the database it has only added the last in this case Jack.

If there is anyone willing to edit the code above so it will work with my single field i would be very great full, also if someone would answer the questions i placed in the script that would be great also.

Many thanks.
Lister471

Hello,  I'm new to PHP/MySQL.  Here's the situation: I have a simple little database called, "quiz."  (I want to keep it simple until I figure out what I'm doing.)  This database has one user, me, and two tables: Questions (QuestionID, QuestionText), and Answers (QuestionID, OptionText)  QuestionID is set to autoincrement.  I have one record so the biggest QuestionID is 1.

Here is the php file:

 <?php
$link = mysql_connect('PathToMySQL', 'MyUsername', 'MyPassword');
 if (!$link) {
  die('Could not connect: ' . mysql_error());
}
echo 'Connected!';
mysql_select_db(quiz);
$sql = 'SELECT QuestionID, MAX(QuestionID) FROM Questions;';

// everything works great until this point
// but I want the store the data into a variable so the
// answer form will know what QuestionID to assign to the answers.
// So I tried the following:

echo $sql;

// but that just echoed the query itself, not the result.
// I got: Connected!SELECT "QuestionID, MAX(QuestionID) FROM Questions;"
// I was expecting to see: "Connected!1"

// close database
mysql_close($link);
?>

 

I need to capture the value of QuestionID to pass that to the answers.  How do I do that?

Thank you all for this forum, and for any answers.  That PHP manual is thick and complex.  I always hate being a newbie.  I have been in Newbieville for several languages now; this is no different.  I can say from experience that the good news is that it gets better!

 

Richard Hollenbeck

Hi there, I am scratching my head for ages trying to get this to work.  I am adapting a script that simply outputs a floorplan image from a MySQL database. Only problem is that it outputs the <DIV> and all the title and formatting even if no image exists. I only want to output the <DIV> if an image exists.  Thanks in advance for any help. Charlotte


Code: [Select]
<div id="property-contact">
    <h2 id="h2-section" class="h2-section"><?php _e('Floor Plan',TS_DOMAIN) ?></h2>
    <div class="box2 clearfix">
   <?php $floor_plans_image_id =get_post_meta($post->ID, "_thumbnail_id", true);
    $myrows = $wpdb->get_results( "SELECT guid FROM wp_posts WHERE ID=".$floor_plans_image_id );

   ?>
   <a href="<?=$myrows[0]->guid?>" rel="prettyPhoto[gallery]"><img src="<?=$myrows[0]->guid?>" width="250px;"/></a>
</div><!-- end box3 -->
</div>

Hello, I'm sorry, I know nothing about php programming but need some help - I'm sure this will be a simple question! 

I have created a Formidable form on Wordpress (form is named BookingTest).  It has a drop down box on (called dropdown) that has a list of numbers that requires a unique value.  The plugin designers have shared some code that is supposed to remove used values from the drop down box but it's not working - I don't know if I've put it in the right place or if I need to edit it or anything like that.  

This is there documentation: https://formidableforms.com/knowledgebase/frm_setup_new_fields_vars/?fbclid=IwAR1Zj1jWo6iqdR4Cjq8MGpTLRW01XToPR7vp_2oN4XEmQ81SLAW-sbtbYKU#kb-remove-used-options

I have pasted this code in it's entirety to a Code Snippets plugin but I still get all the values appear.  

Do I need to amend it to refer to my form explicitly?  How is this filter called?  Do I need to add an action?!

Really confused :(

Thank you! 

Hi, I'm REALLY new to PHP, so any help would be appreciated .  I'm trying to make a script that truncates a post after a certain amount of words (Below).  And I suppose the article would have to have $description="blahblahblah";.  My question is; how would I go about making this script actually work?  Where would I put the code and the articles? Like I said, I have less than 2 days experience with PHP, so please don't judge
Code: [Select]
// this signifies how to truncate
function myTruncate($string, $limit, $break=".", $pad="...")
{
  // return with no change if string is shorter than $limit
  if(strlen($string) <= $limit) return $string;

  // is $break present between $limit and the end of the string?
  if(false !== ($breakpoint = strpos($string, $break, $limit))) {
    if($breakpoint < strlen($string) - 1) {
      $string = substr($string, 0, $breakpoint) . $pad;
    }
  }

  return $string;
}
And the code that says when to truncate:
Code: [Select]
// replace 'xxx' with the number desired

  $shortdesc = myTruncate($description, XXX);
  echo "<p>$shortdesc</p>";

Hi I'm trying to insert some information into my database but it tells me that the name is undefined how to I define it so that it works.

Here is my code
Code: [Select]
<html>
<body>

<form action="insert.php" method="post">
name: <input type="text" name="name" />
email: <input type="text" name="email" />
password: <input type="text" name="password" />

<input type="submit" />
</form>

</body>
</html>
<?php
$link = mysql_connect('localhost','test',''); 
if (!$link) { 
die('Could not connect to MySQL: ' . mysql_error()); 
} 
mysql_close($link); 

$sql="INSERT INTO emails (name,email, password)
VALUES
('$_POST[name]','$_POST[email]','$_POST[password]')";

mysql_close($con)
?>

Hye there im branded new in php here. Im trying to develop a system based on php and mysql.
I have 20 fields on my database table. Im trying to separate fields into 2 forms which is each form contain 10 fields
- form_1.php(contain 10 fields)
-form_2.php(contain 10 fields)

form_1.php and form_2.php is connected each other which is user have to insert data in the form_1.php and then there are NEXT button that will bring user to form_2.php.In the form_2.php there will be a SUBMIT button which send data to database.
Im trying to do but i cannot go through can someone show me any way to ??