PHP - Getting Data From A Previous Row, Based On The Current Row

i get this error Warning: current() [function.current]: Passed variable is not an array or object..

for this
Code: [Select]
$lastblock = current( ${"s".$row} );
print_r($lastblock);
when i change to this it works..
Code: [Select]
$lastblock = current( $s0 );
print_r($lastblock);
The problem is i won't know the $row seeing as it is in a while loop.  Solution?

I have a multi-step form that offers different options of membership to users with the e-mail domain 'vip.co.uk' I finally have it working but have hit a wall with pulling the variables together to form an URL that can be submitted to the payment gateway in the final step.   The variables I need to pass are username, password, email, subscription id (a value attached to a radio button in step 2 - not yet built it).   I have a JS fiddle at http://jsfiddle.net/zsasvoo4/15/.   The final form will be in PHP and I'd prefer to use that language.

This is the link to pull the page

http://127.0.0.1/kudos/?viewkudoid=###

This is the kudo-function.php page

function get_kudo_info($viewkudoid){
	global $wpdb;
    $tablename=acikudos_table_name();
    $viewsql = "SELECT * FROM $tablename WHERE kudoid='$viewkudoid'";
	$viewresult = $wpdb->get_results($viewsql);
    #$vewrow = mysql_fetch_assoc($viewresult);

    return $viewresult;
}

This is the kudo-view.php page

function show_kudos($viewkudoid)
{
   global $wpdb;
   
   $viewkudoid = $_GET['viewkudoid'];
   
   $getthekudo = get_kudo_info($viewkudoid);

    if ($viewkudoid == $getthekudo['kudoid']) {
        
		echo 'Congratulations, you have successfully fixed it!';
    } else {
    echo 'Everything is displayed';
}
	} 

 add_shortcode( 'kudosview', 'show_kudos' );

I know the issue is right in front of me but I can not find it.

Hello - I've come to an issue with something I'm working on and have searched around with no luck.

When editing user accounts I want it to not be able to change the e-mail address into existing ones on other rows, but when submitting the form it takes into account that this particular rows email address is the same as the one which was sent via $_POST and throws up the error.

The desired behaviour I want is for it to ignore the ID of the row which was posted, but take into account every other row.

Here's the code as it stands at the moment:

$email = $_POST['email'];
        $checkemail = mysql_query("SELECT email FROM users WHERE email='$email'");

} if (mysql_num_rows($checkemail) > 0) {

return $this->error("The e-mail address you provided is already associated with an account.");
}

Hi,

I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28

Any ideas guys?

Thanks lots!

I'm working on a store locator style program. I first get and sort all zip codes based on a their distance to an original location. I then use that zip code array to find all stores in the mysql database, but when I get the results, they're no longer arranged by distance from the original location.. and I can't just sort them ascending or descending based on their zip codes because that doesn't sort them correctly either.

So I need to sort the data I get from the mysql database based on their "zip_code" column and in order from the $zip array..

Here's an example of what $zip looks like.. the zip code is the key and the distance from the original zip is the value [meaning the first key is the $originalZip]:
Array (
[70601] => 0
[70616] => 1.12
[70629] => 1.2
[70612] => 1.24
[70602] => 1.31
[70615] => 1.88
[70609] => 3.41
[70605] => 4.4
[70669] => 4.62
[70606] => 4.9
[70611] => 7.23
[70607] => 9.68
[70663] => 9.74
)


and then I create the $WHERE variable by each key supplied:
$WHERE = "WHERE zip_code='$originalZip'";

foreach ($zip as $key => $value) {
if ($key == $originalZip) {}
else { $WHERE .= " OR zip_code='$key'"; }
}
}

Then I do the query [with a paginator]:
$query = query("SELECT * FROM " . $db['prefix'] . "stores $WHERE LIMIT $from, $maxResults");

but when I print the data, it doesn't keep the correct sorting format..
if (mysql_num_rows($query) > 0) {
for ($i = 0; $i<mysql_num_rows($query); $i++) {
$storeData = mysql_fetch_array($query, MYSQL_ASSOC);
// print store information here such as $storeData['name'] $storeData['address'] $storeData['zip_code']
} }

Is there an easy way to sort the mysql results based on the $zip array?

Hi,

I am hoping someone can help me out with a slight issue I have with php and mySQL.

I have an ajax-powered form with a select (dropdown) field populated through a php function. Based on the user-selected values in this field, data is displayed on the webpage; i.e. selected value 1 returns values x and y on the page. I am now trying to call additional data (value z) from a different table in the same database, and as before, use the selected values from the dropdown to display the data.

For some reason, value z is not changing according to the user-selected value.

This is my code:

[The function to populate the select field]

Code: [Select]
function kfl_get_funds_names()
{
$result = array();
$result['CDF'] = 'Crosby Dragon Fund';
$result['CPF'] = 'Crosby Phoenix Fund';
$result['AMZPIF'] = 'AMZ Plus Income Fund';
$result['KASBIIF'] = 'KASB Islamic Income Opportunity';
$result['KASBCPGF'] = 'KASB Capital Protected Gold Fund';
$result['KASBLF'] = 'KASB Income Opportunity Fund';
$result['KASBCF'] = 'KASB Cash Fund';
$result['KASBBF'] = 'KASB Asset Allocation Fund';
$result['KASBSMF'] = 'KASB Stock Market Fund';

return $result;
}
[the code calling and using the function to interact with the database]

Code: [Select]
$funds_to_display = kfl_get_funds_names();
$current_symbol = key( $funds_to_display );
$current_nav_rates = kfl_get_latest_rates( $current_symbol );
[the code calling additional data, value z, from the database, and using the info in the select field to filter it]
Code: [Select]
$cutoff = kfl_cutoff( $current_symbol );
The display of each of these items is as follows:

Code: [Select]
<?php echo $current_nav_rates['nav_date']; ?>
<?php echo $funds_to_display[$current_symbol]; ?>
<?php echo $cutoff['cutoff']; ?>
I can't get the $cutoff code to display the correct values. It picks up the first symbol to display and doesn't change with user selection. The code for the selection box, by the way:

Code: [Select]
<select id="dailynav-funds" autocomplete="off" name="dnf">
<?php
foreach ($funds_to_display as $fund_symbol => $fund_name)
{
echo '<option';
if( $fund_symbol == $current_symbol ) {
echo ' selected="selected"';
}
echo ' value="' . $fund_symbol . '">';
echo $fund_name;
echo '</option>';
}
?>
</select>
I've tried to get data using $_GET['dnf'] into the cutoff code, but that throws up parse errors. What am I doing wrong, and how can I resolve this issue?

Thanks in advance!

Not sure why this isnt working.
Code: [Select]
<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<script src="http://js.nicedit.com/nicEdit-latest.js" type="text/javascript"></script>
<script type="text/javascript">bkLib.onDomLoaded(nicEditors.allTextAreas);</script>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />


<LINK REL=StyleSheet HREF="inc/dyn_style.css" TYPE="text/css" MEDIA=screen />
<?php

 ?>
<?php include('logic.inc'); mysqlConnect(); ?>
<script type="text/javascript" src="bbeditor/ed.js"></script>
<link rel="stylesheet" type="text/css" href="dyn_style.css" />
<title>
Social
</title>
<script type="text/javascript">
function changeTitle(title)
{
document.title = title;
}
</script>

</head>

<body>
<?php
$inc = 'new_story.php';
$view = 'Newest ';
$by = 'added';
$where = " ";
$where2 = " ";
$order = "ASC"; 
$gen = "All";
$rat = 'All';
$blerg = "";
$sort = 'newest';
//----------------------------------------------------------------------
if(isset($_GET['sub']))
{
$sort = $_GET['sort'];
switch($sort)
{
case "Most Popular";
$by = 'views';
$view = 'Most Popular ';
$order = 'DESC';
break;
case "Most Reviewed";
$view= 'Most Reviewed  ';
$by = 'reviews';
$order = 'DESC';
break;
case "Newest";
$by = 'added';
$view = 'Newest';
$order = 'ASC';
break;
}

$genre = mysql_real_escape_string($_GET['cat']);
$rating = mysql_real_escape_string($_GET['rat']);
if($gen ==  'All')
{
$where = " ";
$blerg = "";
}
else
{
$where = "WHERE cat='$gen'";
}
if ($rat == "All")
{
$where2 = ' ';
$blerg = 'AND';

}
else 
{
$where2 = $blerg ."
 rating = '$rat'
";
}
}
//----------------------------------------------------------------------


?>
<?php serch(); ?>
<form action="story.php" method="get">
<label id='inline'> Order By: </label>
<select name='sort'>
<option selected='yes' label='Currently Selected' > <?php echo $view;  ?> </option>
<option> Newest   </option>
<option> Most Popular</option>
<option>  Most Reviewed </option>
</select>
<input type='hidden' value='spec_view' name='p' />
<label id='inline'> Genre/Catagory:  </label>
<select name='gen'>
<option selected='yes' label = 'Selected Genre - <?php echo $gen; ?>'> <?php echo $gen; ?> </option>
<option> All </option>
<option> Fantasy </option>
<option> Adventure </option>
<option> Science Fiction</option>
<option> Drama</option>
<option> Fable </option>
<option> Horror</option>
<option> Humor</option>
<option> Realistic Fiction </option>
<option> Tall Tale</option>
<option> Mystery  </option>
<option> Mythology  </option>
<option> Poetry  </option>
<option> Shorty Story </option>
<option> Romance </option>

</select>
<label id='inline'> Rating: </label>
<select name='rat'>
<option selected='yes' label = "Selected Genre - <?php echo $rat; ?>"> <?php echo $gen; ?> </option> 
<option> All </option>
<option> C </option>
<option> C13 </option>
<option> YA </option>
<option> A </option>

</select>

<input type='submit' value='Go!'  name = 'go' />
</form>
<?php

$query = "
SELECT * FROM story_info
ORDER BY $by $order 
$where
$where2
";
echo $query;
$select = mysql_query($query) or die(mysql_error());

while($rows = mysql_fetch_assoc($select))
{
$viewsdb = $rows['views'];
$titledb = $rows['title'];
$userdb = $rows['user'];
$catdb = $rows['cat'];
$ratdb = $rows['rating'];
$id_db = $rows['story_id'];
$sumdb = shorten($rows['sum']);
echo "<h3><a href='?p=page&id=$id_db'> $titledb </a>   </h3>";
echo "<div id='fun_info'>";
echo "$sumdb <br />";
echo "By <a href='?p=profile&user=$userdb'> $userdb </a> <br /> ";
echo "$viewsdb Views | Rated: $ratdb | Catagory: <a href='?p=cat_view&gen=$catdb'> $catdb </a>  </div>";
}
?>
</div>

</body>
</html>

I'm creating a tool for building project proposals for clients, with pricing.

I have a database with two tables: services and clients.

The services table looks like this:

Code: [Select]
| code        | name        | cost |
+-------------+-------------+------+
| logo_design | Logo design | 10   |
| web_design  | Web design  | 20   |

The clients table looks like this:

Code: [Select]
| id | client  | logo_design | web_design |
+----+---------+-------------+------------+
| 1  | Walrus  | yes         | yes        |
| 2  | Narwhal | no      | yes        |

How would I link the results from these two tables so that I only pull out the services each person wants from the database?

Here is what I have so far:

Code: [Select]
<?
$sql = "SELECT * FROM services";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result,MYSQL_ASSOC)) {

  echo $row{'name'} . ': $' . $row{'cost'} . '<br />';

} ?>

This, of course, displays all the services, with all the prices, like so:

Logo design: $10
Web design: $20

I want to add something here so that based on the selected client, we see only the services/prices they selected (ol' Narwhal's page would not show the "Logo Design" line). I've got the data from "clients" pulled in to this page as well, but don't know how to relate it to "services."

Thanks in advance! Let me know if I've left out any info that would help you to point me in the right direction.

Hello,

I've been trying this for hours now, looking at different examples and trying to change them to work for me, but with no luck...

This is what I am trying to do:

I have a simple form with:
- 1 input field, where I can enter a number
- 1 Submit Button

When I enter a number into the field and click submit, I want that number to be send to the php file that is in the ajax call, then the script will take that number and run a bunch of queries and then return a new number. I want that new number to be used to call the php script via ajax again, until no number is returned, or something else is returned like the word "done" or something like that, at which point is simply makes an alert or populated a div with a message...

The point is, that depending on the number entered it could take up to an hour to complete ALL the queries, so I want the script that is called to only run a fixed amount of queries at a time and then return the number it is currently at (+1), so that it can continue with the next number when it is called again.

I would like to use jquery, but could also be any other way, as long as I get this to work. I already have the php script completed that needs to be called by the ajax, it returns a single number when being called.

Thank you,
vb

Hi i have this drop down list current the year is 2010 and downwards but i want to change the list to 2010 upwards u can notice on the 50-- so shows current year minus so current is 2010 to 61 how can i change 2010 to 2030 or sunfin??

echo '<select name="year_of_birth">',"\n";
    $year = date("Y");
    for ($i = $year;$i > $year-50;$i--) {
      if($i == $thisYear) { 
        $s = ' selected'; 
      } else { 
        $s='';
      }
      echo '<option value="' ,$i, '"',$s,'>' ,$i, '</option>',"\n";
    }
  echo '</select>',"\n";

This portion is kind of stumping me. Basically, I have a two tables in this DB: users and users_access_level (Separated for DB normalization)

users: id / username / password / realname / access_level
users_access_level: access_level / access_name

What I'm trying to do, is echo the data onto an HTML table that displays users.username in one table data and then uses the users.access_level to find users_access_level.access_name and echo into the following table data, I would prefer not to use multiple queries if possible or nested queries.

Example row for users: 1234 / tmac / password / tmac / 99
Example row for users_access_level: 99 / Admin

Using the examples above, I would want the output to appear as such:

Username: Access Name: Tmac Admin
I am not 100% sure where to start with this, but I pick up quickly, I just need a nudge in the right direction.

The code I attempted to create just shows my lack of knowledge of joining tables, but I'll post it if you want to see that I did at least make an effort to code this myself.

Thanks for reading!

I'm trying to create a function where you specify the $points it will then do some mathematical stuff with the $points (explain later) an return an array containing the $rank and $level.

The mathematical stuff:

It starts at 99 and when it reaches +199 it changes the key of the array.

I'm not sure how to describe this theirfore i'll just provide examples:

Example 1:

If $points <= 99

It will return an array containing $ranks[0] and $levels[0], would be the following:

return array('Peon', 0);

Example 2:

If $points >= 100 && $points <= 299

It will return an array containing $ranks[1] and $levels[1], would be the following:

return array('Grunt', 1);

Example 3:

If $points >= 300 && $points <= 499

It will return an array containing $ranks[2] and $levels[2], would be the following:

return array('Berserker', 2);

etc.. until it reaches the 7th key of the $ranks/$levels array

Heres my code:

<?php

function rank($points){
//their are 0-7 levels
$levels = range(0, 7);

//7 ranks
$ranks = array('Peon', 'Grunt', 'Berserker', 'Tauren', 'Spirit Walker', 'Wind Rider');

for(...) {
return array($rank, $level);
}
}
?>

How can I get the next four and previous four rows?

Here is what I have and it isn't working at at all.
$q1 = Mysql::query("SELECT id, file, dir FROM photos WHERE id > $id AND album = '$al' ORDER BY id ASC LIMIT 4");
$q2 = Mysql::query("SELECT id, file, dir FROM photos WHERE id < $id AND album = '$al' ORDER BY id DESC LIMIT 4");

I have rows being generated in a foreach loop.  I need to find the time in the row before it (or maybe after it if my logic is screwed up) to see if the times are equal.  If they are equal, I need to see if the next row after that is equal. If it is not equal then stop.

mysql
user id     time        action
1               5            bought
1               5            purchased
1               5            sold
1               4            created

Code: [Select]
foreach($newsfeed as $k => $news)
{
if ($news['time'] == $news['time'] of $k--)
{
echo " you bought purchased and created";
}
        else
        {
                echo $news['action'];
         }
}