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PHP - Header Doesn't Seem To Work/ Doesn't Redirect

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Header Doesn't Seem To Work/ Doesn't Redirect	View Content

if ($count==1){
				
						
				header("Location:store.php");				
				
								}

very simple I have issolated it and it doesn't redirect maybe u can see where my mistake is

Full Excel VBA Course - Beginner to Expert

Header Doesn't Redirect Me To Main.php

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Problem: The page does not redirect the end user to main.php.

Notice: Use of undefined constant name_id - assumed 'name_id' in C:\x\xampp\htdocs\pages\form_process.php on line 48

Warning: Cannot modify header information - headers already sent by (output started at C:\x\xampp\htdocs\pages\form_process.php:48) in C:\x\xampp\htdocs\pages\form_process.php on line 87

The error messages displayed above make it seem like they are connected to the problem, but I don't understand why 'name_id' is undefined as its auto increments in mysql.

I also think my .htaccess might be preventing me from redirecting, is that possible?

" header('Refresh: 5; URL=http://localhost/pages/main.php'); "

Goal: redirect user to main.php without error messages being displayed.

form_process.php

<?php

//let's start our session, so we have access to stored data
session_start();

if (isset($_POST['terms_and_conditions']) == 0) {
  // the code was incorrect
  // handle the error accordingly with your other error checking

  // or you can do something really basic like this
  die('You must agree to the terms and conditions to create a profile.  Go back and try again.');
}

include_once $_SERVER['DOCUMENT_ROOT'] . '/securimage/securimage.php';

$securimage = new Securimage();

if ($securimage->check($_POST['captcha_code']) == false) {
  // the code was incorrect
  // handle the error accordingly with your other error checking

  // or you can do something really basic like this
  die('The code you entered was incorrect.  Go back and try again.');
}

else {
include 'db.inc.php';

$db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or
    die ('Unable to connect. Check your connection parameters.');
mysql_select_db(MYSQL_DB, $db) or die(mysql_error($db));

$error = array();

    $query = 'SELECT name FROM user WHERE ' .
         'name = "' . mysql_real_escape_string($_SESSION['values']['name'], $db) . '"' ;
    $result = mysql_query($query, $db) or die(mysql_error($db));

if(mysql_num_rows($result) > 0) {
$error['uname'] = '<p class="errText">Username is taken.</p>';
        header('Refresh: 5; URL=form1.php');
}
//let's create the query
else{
$query = sprintf("INSERT INTO user (
name_id, name, password)
VALUES ('%s','%s','%s')",
name_id,
mysql_real_escape_string($_SESSION['values']['name']),
mysql_real_escape_string(md5(SALTY . $_SESSION['values']['password'])));

//let's run the query
$result = mysql_query($query, $db) or die(mysql_error($db));

$name_id = mysql_insert_id();

$query = sprintf("INSERT INTO contact (
name_id, first_name, last_name, email, address, city, county,
post, home, mobile)
VALUES (LAST_INSERT_ID(),'%s','%s','%s','%s','%s','%s','%s','%s','%s')",
mysql_real_escape_string($_SESSION['values']['first_name']),
mysql_real_escape_string($_SESSION['values']['last_name']),
mysql_real_escape_string($_SESSION['values']['email']),
mysql_real_escape_string($_SESSION['values']['address']),
mysql_real_escape_string($_SESSION['values']['city']),
mysql_real_escape_string($_SESSION['values']['county']),
mysql_real_escape_string($_SESSION['values']['post']),
mysql_real_escape_string($_SESSION['values']['home']),
mysql_real_escape_string($_SESSION['values']['mobile']));

//let's run the query
$result = mysql_query($query, $db) or die(mysql_error($db));

$name_id = mysql_insert_id();

$query = sprintf("INSERT INTO profile (
name_id, bi, ex)
VALUES (LAST_INSERT_ID(),'%s','%s')",
mysql_real_escape_string($_SESSION['pro']['bi']),
mysql_real_escape_string($_SESSION['pro']['ex']));

$result = mysql_query($query, $db) or die(mysql_error($db));

        $_SESSION['logged'] = 1;


        header('Refresh: 5; URL=http://localhost/pages/main.php');
}

?>
<html>
<head>
  <title>Register</title>
</head>
<body>
  <p><strong>Thank you <?php echo $_SESSION['values']['name']; ?> for registering!</strong></p>
  <p>Your registration is complete! You are being sent to the page you
requested. If your browser doesn't redirect properly after 5 seconds,
<a href="main.php">click here</a>.</p>
</body>
</html>
<?php
session_destroy();
        die();
    }

?>

Redirect To Login With Dynamic Url Doesn't Work

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Redirect to login with dynamic URL (?p=) doesn't work

I have two webpages that I want to be accessible only when the user is logged in. One for admin and one for other users. When a user who isn't logged in arrive to these pages I want to redirect the page to login.php. This doesn't work with the website I am working on.

I use this script on the startpage:

Code: [Select]
<?php
if(file_exists($_GET['p'].".php")){
     include($_GET['p'].".php");
}

else{
if(empty($_GET['p']) OR $_GET['p'] == ""){
include("main.php");
    }

else{
    include("404.php");
    }
}
?>

and therefore my links have this format: ?p=mapp/filnamn and it doesn't work with header('Location: /?p=admin/login');

If I skip this script and use ordinary links header('Location: /admin/login.php'); it works, but I don't want to be forced to copy the same code over and over again to get header, footer, leftbar and rightbar on every single page.

I have almost teared my brain apart to find a solution but in vain. Today I have been sitting in front of the computer almost the whole day with this problem, but no luck. I don't even know what to search for. What is it I don't understand? Not long time ago I hade another problem just because I use dynamic links.

This is the script I use on the page that I don't want to be accessible if you aren't logged in:

Code: [Select]
<?php
session_start();
$username = $_SESSION['username'];

include ('functions.php');
db_connect();

if(!empty($_SESSION['username'])){
$sql = mysql_query("SELECT username, usertype FROM users WHERE username='$username'");
$result = mysql_num_rows($sql);
$row = mysql_fetch_array($sql);

if($_SESSION['username'] = $username AND $row['usertype']==1){
$_SESSION['username'] = $username;
$user_welcome = "Welcome ".$username;
}

else{
//header('Location: /?p=admin/login');
die("<a href='?p=admin/login'>You have to login as admin to access this page!</a>");
}
}

else{
//header('Location: /?p=admin/login');
die("<a href='?p=admin/login'>You have to login to access this page</a>");
}
?>
I use "die" because it is the only way for me to make it work, but I want to use what is in the comments. Maybe it's not such a bad idea to use the method I use today, but the problem is that when I get the message that I have to login to view the page, the rightbar disappear and the page therefor looks stupid.

Another question I am wondering about, is if the above script is secure? It doesn't feel like it, but maybe the security is all about the loginpage?

Ajax Redirect Doesn't Work After Php Insert Mysql Query

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I have created a registration page to access my website. After the user registrate himself should appear an alert saying that the registration was OK and a redirect to main.php page... however for some reason if I create an insert statement the alert and the redirect don't appear... If I remove the insert the alert and the redirect works... why?

This is part of the code of my 3 files:

registration.php (ajax call)

$('#submit').click(function() {
var username2 = $('#uname2').val();
var password2 = $('#psw2').val();
$.ajax({
url: 'ajax/response.php',
type: 'GET',
data: {username2 : username2, password2: password2},
success: function(data) {
if(data === 'correct') {
alert("Username and Password have been created!"); //don' work with the insert
location.replace("main.php"); //don' work with the insert
} else {
alert("Username or password are not correct... please register yourself!");
}
}
});
});

response.php (answer to ajax call)

if(isset($_GET['username2']) && isset($_GET['password2'])) {
$username2 = $_GET['username2'];
$password2 = $_GET['password2'];
if (checkUser($pdo, $username2) === true) {
echo 'duplicate';
} else {
insertUserPwd($pdo, $username2, $password2); //including this line the redirect and the alert doesn't work... the insert is OK
echo 'correct';
}
}

data_access.php (the function works but doesn't permit alert and redirect to appear)

function insertUserPwd(PDO $pdo, $usr, $pwd)
{
$data = [
'id' => '',
'user' => $usr,
'password' => $pwd
];
$sql = "INSERT INTO users (id, user, password) VALUES (:id, :user, :password)";
$stmt= $pdo->prepare($sql);
$stmt->execute($data);
}

Can someone help me to fix the code?

Php Write To Txt File Works, Redirect Doesn't : (

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Hi there,

If anyone has a spare minute, id really appreciate someone casting their eye over this and seeing if there's anything obviously wrong. Writing to the txt file works fine, but the redirect to the thankyou.html page doesn't. Cheers Guys.

<?PHP

$filename = "output.txt"; #CHMOD to 666
$forward = 1; # redirect? 1 : yes || 0 : no
$location = "thankyou.html"; #set page to redirect to, if 1 is above

## set time up ##

$date = date ("l, F jS, Y");
$time = date ("h:i A");

## mail message ##

$msg = "";

foreach ($_POST as $key => $value)
{
$msg .= ucfirst ($key) .", ". $value . ", ";
}

$msg .= "\n";

$fp = fopen ($filename, "a"); # w = write to the file only, create file if it does not exist, discard existing contents
if ($fp) {
fwrite ($fp, $msg);
fclose ($fp);
}
else {
$forward = 2;
}

if ($forward == 1) {
header ("Location:$location");
}
else if ($forward == 0) {
echo ("Thank you for submitting our form. We will get back to you as soon as possible.");
}
else {
"Error processing form. Please contact the webmaster";
}

?>

Many thanks,

Mike

$row[2] Doesn't Work

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$Row[2] doesn't work but if I use $Row["linkcat"] than it works fine.
Is there somewhere to activate in the php.ini file ?

Code: [Select]
// I got 9 fields to in the table tbl_link ! $Row[2] should give me a number.

$Verbinding = mysql_connect($db_host, $db_user, $db_passw);
mysql_select_db($db_name);
$sql = "Select * from tbl_link where userid=1";
$ResultShow = mysql_query($sql);

while ($Row = mysql_fetch_assoc($ResultShow)){

echo $Row[2];

}

Why Doesn't This Work? :s

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I've joined querys because I'm making my own forums. However, when it gets to the echoin out part, it shows the category and only ONE of the sub categorys.

Code: [Select]
<div id="forumContainer">
<?php
$lastboard = '';

$forumQ = mysql_query("SELECT

   f1.cat_name as catName,
   f1.cat_id as catID,
   f2.cat_id as subCatID,
   f2.sub_id as subID,
   f2.sub_name as subName,
   f2.sub_desc as subDesc

   FROM `forum_cats` as f1
    LEFT JOIN `forum_sub` as f2
    ON f1.cat_id = f2.cat_id
   GROUP BY f2.cat_id
   ");

while($forumF = mysql_fetch_assoc($forumQ))
{
if($forumF['catName'] != $lastboard)
{
echo '<div class="forumCat">'.$forumF['catName'].'</div>';
$lastboard = $forumF['catName'];
}
echo '<div class="forumSub">'.$forumF['subName'].'</div>';
}
?>
</div>

Header Redirect Does Not Work. Please Help!

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Here is the webpage.php which executes data entered in the email form. I want to display a webpage which would confirm that the email has been sent but the header redirect does not work. An email gets sent but a blank page is displayed instead of confirmation. Can anyone help? this is urgent

<?php error_reporting(6143);

require_once('recaptchalib.php');

$publickey = "6Ldmbr8SAAAAAGT17oCjkB8Y60kSqvq_0w7APAJp";
$privatekey = "6Ldmbr8SAAAAAMY5lEl-7LnkWCovoFa9G7Vl3_kA";

isset($_POST['Email']) ? $Email = $_POST['Email'] : $Email = "";
isset($_POST['name']) ? $name = $_POST['name'] : $name = "";
isset($_POST['surname']) ? $surname = $_POST['surname'] : $surname = "";
?>

<meta http-equiv="content-type" content="text/html; charset=iso-8859-2">

<body bgcolor="#000000"></body>

<link href="loginmodule.css" rel="stylesheet" type="text/css" />

<?php

if (isset($_POST['Submit']))
{
//Validate form
$errormessage = "";

$resp = recaptcha_check_answer ($privatekey,
                                $_SERVER["REMOTE_ADDR"],
                                $_POST["recaptcha_challenge_field"],
                                $_POST["recaptcha_response_field"]);

if ($name == '') { $errormessage .= "<li>Please provide your name.</li> ";}
if ($surname == '') { $errormessage .= "<li>Please provide your surname.</li>";}
if ($Email == '') { $errormessage .= "<li>What is your e-mail address?</li>";}
if (!eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$", $Email)){ $errormessage = $errormessage . "<li>This is not a valid email address!

</li>";}
if (!$resp->is_valid) {
     // What happens when the CAPTCHA was entered incorrectly
    $errormessage .= "<li>Please rewrite captcha characters</li>";
}

echo "</ul></p>";
//If errors, return error message(s) and form
if ($errormessage != "")
{ ?>

    <span class="link1"><a href="index.php">back to home page/a></span>
     <img src="images/clack.JPG">
<table align="center">
       <p align="center" class="err_bold">correct the following errors:</p> <span class="text_err"><ul><?=$errormessage?></span>
                        </table>

<?php
include("email-form.php");

} else {
//If good, mail to DL
$email_subject = "Hello, you have a new message";
$email_headers = "From: $name [$Email] \r\n";

$to = "blablabla@hotmail.com";
$message_content =
"----------------------------------------------------------------------------------\n".
" Hello\n".

"name: $name\n".
"surname: $surname\n".
"E-mail: $Email\n".

"-----------------------------------------------------------------------------------\n\n";



//Email message to Requestor

if (mail($to, $email_subject, $message_content, $email_headers))
{
//Display Sent Confirmation (Successful or NOT!) ?>
        <?php
        header ("Location: http://www.google.co.uk");
exit; ?>
<?php
}
}
} else {
?>
<span class="link1"><a href="index.php">back to home page</a></span>
<img src="images/clack.JPG"><br>
<p class="err" align="center">Please fill the form below<br/></p>

<?php include("email-form.php");?>

<?php
};

Need Help With Why Tag Cloud Doesn't Work

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Hey there, I am trying out some tag cloud code, but something is amiss, as am getting no tags displaying. Using PHP/MYSQL and JQuery.

<?php

//connection information
  $host = "localhost";
  $user = "username";
  $password = "pw";
  $database = "DBName";

//make connection
  $server = mysql_connect($host, $user, $password);
  $connection = mysql_select_db($database, $server);

//query the database
  $query = mysql_query("SELECT * FROM tags");

//start json object
$json = "({ tags:[";

//loop through and return results
  for ($x = 0; $x < mysql_num_rows($query); $x++) {
    $row = mysql_fetch_assoc($query);

//continue json object
    $json .= "{tag:'" . $row["tag"] . "',freq:'" . $row["frequency"] . "'}";

//add comma if not last row, closing brackets if is
if ($x < mysql_num_rows($query) -1)
$json .= ",";
else
$json .= "]})";
  }

//return JSON with GET for JSONP callback
$response = $_GET["callback"] . $json;
echo $response;

//close connection
mysql_close($server);

?>

and the JS

Code: [Select]
<script type="text/javascript">
$(function() {

//get tag feed
$.getJSON("/tagcloud.php?callback=?", function(data) {

//create list for tag links
$("<ul>").attr("id", "tagList").appendTo("#tagCloud");

//create tags
$.each(data.tags, function(i, val) {

//create item
var li = $("<li>");

//create link
$("<a>").text(val.tag).attr({title:"See all pages tagged with " + val.tag, href:"http://localhost/tags/" + val.tag + ".html"}).appendTo(li);

//set tag size
li.children().css("fontSize", (val.freq / 10 < 1) ? val.freq / 10 + 1 + "em": (val.freq / 10 > 2) ? "2em" : val.freq / 10 + "em");

//add to list
li.appendTo("#tagList");

});
});
});
</script>

when i turn on error reporting I get a lot of undefined index notices for tag and frequency so not sure if that is causing the problem or not.

Noob To Php: Why Doesn't This Work?

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Hey, I have made a audio button in dreamweaver and copied the code into my php panel:

<script language="JavaScript" src="http://www.MYWEBSITE.com/myname/audio/audio-player.js"></script>
<object type="application/x-shockwave-flash" data="http://www.MYWEBSITE.com/media_folder/audio/player.swf" id="audioplayer1" height="24" width="290">
<param name="movie" value="http://www.MYWEBSITE.com/media_folder/audio/player.swf">
<param name="FlashVars" value="playerID=audioplayer1&soundFile=http://www.MYWEBSITE.com/media_folder/audio/Reconstructed Ancient Egyptian Melody.mp3">
<param name="quality" value="high">
<param name="menu" value="false">
<param name="wmode" value="transparent">
</object>

However once I press save, all that is saved is:
<script language="JavaScript" src="http://www.MYWEBSITE.com/myname/audio/audio-player.js"></script>
<object type="application/x-shockwave-flash" data="http://www.MYWEBSITE.com/media_folder/audio/player.swf" id="audioplayer1" height="24" width="290">
<param name="movie" value="http://www.MYWEBSITE.com/media_folder/audio/player.swf">

The audio button works however because the code which includes the mp3 file never saves, it can never find the audio file. Can anyone tell me why the audio file part of the code doesn't save?

Thanks.

Pagination Doesn't Work

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Func_get_args Doesn't Work?

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Im using func_get_args, but it gives an error?:

Too few arguments?, when its correct (as the number of %s = the number of values within $args)

<?php
function sprintify() {
global $urls;
$args = func_get_args();
$input = $args[0];
unset($args[0]);
return sprintf($urls[$input], implode(', ', $args));
}

echo sprintify('default', 46, 464, 46);

/*
For your information:
$urls['default'] = '%s/%s/%s';
*/
?>

Why Doesn't Rsort Work

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Hi, when I output this, it's same order, I want it to be:

email/message/to/toLastName

please see code:
$testArray=array("toLastName","to","message","email");
$reversedTestArray=rsort($testArray);//rsort returns TRUE on success
//$strTestArrayReversed=implode(",",$testArray);
print_r($testArray);

Any idea what I am doingwrong, it looks fairly straightforward.

Any help much appreciated!

Mysql_real_escape_string() Doesn't Work

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Hello all, I'm trying to clean up some user input for my database but the mysql_real_escape_string function doesn't seem to work, and neither does addslashes(). I've browsed the net and made sure I'm connected to the database before the function is called. I can't figure out what I'm doing wrong. Here's the relevant part of the code:

Code: [Select]
<?php

mysql_connect("localhost","adminname","adminpassword") or die (mysql_error());
mysql_select_db("databasename") or die (mysql_error());

$comment=mysql_real_escape_string($_POST['commentbox']);

?>
...and then the result is put into the database along with some other data.

The database entry is correct, except, when I check the database or echo the result I get the same thing that was entered into 'commentbox'. For instance, if I enter "I am very 'confused' by this" into the box, the same string will be found in the database table. No slashes, just quotes. Anyone have an idea what's wrong with this? Because it all seems simple and correct but doesn't work.

Mysql_num_row Doesn't Work

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Hi, I am trying to get the previous id for the table xdocument, but browser outputs this warning:

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given

for this code:
Code: [Select]
<?php
//HELPER FCN used by FCN: writeXMLtoDBviaDOM
function mysql_next_id($table) {
    $result = mysql_query('SHOW TABLE STATUS LIKE "'.$table.'"');
    $rows = mysql_fetch_assoc($result);
    return $rows['Auto_increment'];
}

//TEST RUN:
$_filePath="C:\dir\email.xml";
$node=basename($_filePath);
$dom=new DOMDocument();
$dom->load($node);
$labelPath=array();
mysql_connect("localhost","root");
mysql_select_db("dummydpev");
$isXdocExist=mysql_query("SELECT (file_Path,file_Name) FROM xdocument WHERE file_Path='$_filePath' AND file_Name='$node'");
$docId=0;

if(mysql_num_rows($isXdocExist)==0) {
mysql_query("INSERT INTO xdocument (file_Path,file_Name) VALUES ('$_filePath','$node')");
$docId=mysql_next_id("xdocument")-1;
}
else
$docId=mysql_next_id("xdocument")-1;

writeXMLtoDBViaDOM($dom->documentElement,$labelPath,$docId,$_filePath);
?>
So I think my problem is with the multiple WHERE clause conditions, can I do it like what I have above?

Any help much appreciated!

$_session Doesn't Seem To Work...

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I've written a script where it counts the page impressions on my website.

When a visitor lands on the page, it counts their impression and then sets a $_SESSION so that if they reload or return to the page it doesn't count it again. But the problem is it sometimes does.

Does this mean that the $_SESSION isn't being set probably? That's what it seems to be. And if so, what would be the reason for that?

Here's my basic code:

Code: [Select]
if(isset($_SESSION['userid'])){
$userid = $_SESSION['userid'];
}
else{
$userid = rand(1000, 10000000);
$_SESSION['userid'] = $userid;
}

$date = date('Y-m-d');

$counters = mysql_query("SELECT * FROM counters
WHERE userid='$userid'
AND impressions='1'
AND date='$date'")
or die(mysql_error());

if(!mysql_num_rows($counters)){
mysql_query("INSERT INTO counters
(userid, impressions, date)
VALUES('$userid', '1', current_date)")
or die(mysql_error());
}

In_array Doesn't Work

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I have something like below

Code: [Select]
$j = explode("-", $ROW['options']);
if(array_search("src_str", $j) == false) echo '_no'; // This doesn't work
Also i tried
Code: [Select]
$j = explode("-", $ROW['options']);
if(!in_array("src_str", $j)) echo '_no'; // This also doesn't work
Is this bug or am i doing something wrong?

Don't Know Why A Sql Query Doesn't Work

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Hey,

$todo_upgrades_sql = "SELECT * FROM todo_upgrades WHERE time_completion >= $time";
$todo_upgrades_res = mysql_query($todo_upgrades_sql) or die (mysql_error()); results:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

My Php Code Doesn't Work

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Hi everybody!

I'm creating a site and none of my php-code works.

I tried to do a simple php-code to test it but it doesn't work either.

The simple php-code:
<?php

echo "hello";

?>

Php Image Doesn't Work

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I just started with php and made an image. But when I try to open it in my browser, it shows a broken image icon. I have put the font in the same folder as the .php file, but it doesn't work. Can somebody help me solve this problem?

Here is the code:
Code: [Select]
<?php
$font_path = "nakedchick.TTF";
$font_size = 30;

$img_number = imagecreate(300,50);
$backcolor = imagecolorallocate($img_number,0,162,255);
$textcolor = imagecolorallocate($img_number,255,255,255);

imagefill($img_number,0,0,$backcolor);
$number = " So your ip is $_SERVER[REMOTE_ADDR]? ";

ImageTTFText($img_number, $font_size,10,5,5,$number,$font_path,$textcolor);

header("Content-type: image/png");
imagepng($img_number);
?>

And also the files: (.php in attachment)
http://falcogerritsjans.nl/u/signature2.php
http://falcogerritsjans.nl/u/nakedchick.ttf

Delete From Does, But Doesn't, Work

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I have some code which deletes a record from my database (which has been selected from the previous page). Only problem is, it comes up with error code, but still deletes from the database?

Error:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /www/110mb.com/t/h/e/b/l/a/c/k/theblackwatch/htdocs/150749deleted.php on line 28

Code:
Code: [Select]
<?php
$id = $_GET[id];
// Start the connection to the database
$conn = mysql_pconnect("***", "***", "***");
// Select the database to use
mysql_select_db("***", $conn);
// Create the MySQL command to retrieve all records
$sql = "DELETE FROM **** WHERE id ='$id'";
$result = mysql_query($sql, $conn);
$array = mysql_fetch_array($result);
// Echo each entry as the value of the text boxes. This brings in the current info in the database
echo "<p>Entry has been deleted.</p>";
?>
Any way round it?