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PHP - Looking For Some Help To Not Include Something In Preg_replace
What I'm trying to do is replace message_tags to links and web addresses to links in facebook json data, the problem is I need to do these in 2 steps, first do the message tags then then web addresses. The message_tags need to be done first because they rely on offset and length of the message to do the replace.
To code to first replace the message_tags is
// convert message tags to links
if($post->message_tags) {
usort($post->message_tags, 'mySort');
foreach($post->message_tags as $message_tag) {
foreach($message_tag as $link) {
$post_text = substr_replace($post_text,"<a href=\"https://www.facebook.com/".$link->id."\" target=\"_blank\">".$link->name."</a>",$link->offset,$link->length);
}
}
}
The second part is to convert any web address (http://example.com) to a link (<a href ="http://example.com" title="http://example.com" target="_blank">http://example.com</a>)
// check if any entites exist and if so, replace them with hyperlinked versions
$post_text = preg_replace("/((http:\/\/|https:\/\/)[^ )]+)/e", "'<a href=\"$1\" title=\"$1\" target=\"_blank\">'. ((strlen('$1')>=250 ? substr('$1',0,250).'...':'$1')).'</a>'", $post_text);
So now to the problem, the second part now rewrites the first part and completely destroys the link because it just looks for http: and https: so in my preg_replace I need a way to not include anything that has already been converted, so not include anything that already has href="http
Similar TutorialsHi, I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed. So far I have this is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive. Creates an array with keys and values Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job? Can any one help? And please feel free to be as basic as possible :help: Thanks, Adam Code: [Select] function gardening(&$item) { #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array $rename=array( ' Gardening?' => '', 'Climber Plants' => 'Climbing Plants', 'Seeds.*Bulbs' => 'Seeds Bulbs', 'Plant protection' => 'Horticultural goods', 'Garden structures' => 'Garden buildings',); foreach ( $rename as $k => $v ) { list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2'])); } $item['menu_1']=ucfirst(strtolower($item['menu_1'])); $item['menu_2']=ucfirst(strtolower($item['menu_2'])); $item['menu_3']=ucfirst(strtolower($item['menu_3'])); $item['menu_4']=ucfirst(strtolower($item['menu_4'])); } i have: $msg = ereg_replace("[^A-z0-9]"," ",$msg); $msg = ereg_replace(" "," ",$msg); $msg = ereg_replace(" "," ",$msg); how will i apply preg_replace please??? thank you Hello ppl, I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com I'm trying to search a string for all occurences of a pattern, then append text after that pattern. The example is:
SUM("foo") as "bar"
and have it display as:
SUM("foo") over() as "bar"
The "SUM" could be any SQL aggregate and be case insensitive. So For bonus points, let's say the valid aggregates are array('SUM', 'MAX', 'MIN', 'AVG'). My plan right now is to figure it out for SUM, then loop it replacing the aggregate.
This is what I have so far... and it is not working.
$l= 'SUM("foo") as "bar"';
$l=preg_replace('/([^"]+")/','\0 over()',$l);
Thanks,
Ryan
Hi everyone, how do i add and ampersand symbol into preg_replace preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/" where do i place the symbol? & I am trying to pull out the image HTML tag but its not working as expected. Here is what I am doing $removeimagetag='/<a href/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); in the 'descr' there is a <a href="http://s635.photobucket.com...... When it post it does not strip out the <a href So the image is displayed. I tried a modified version to test to see if it work that looked like this. $removeimagetag='/goofy/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); When the word goofy appears in the text then its replaced with the word illegal, Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed" rather than just the part in the front...the <a href. Any help you can be will be greatly appreciated. I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant). The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped. Here's what I currently use to replace line breaks with a break tag. Code: [Select] $str=str_replace("\r\n","<br>",$str); Here's my attempt at introducing this new tag. Code: [Select] function BbToHtml($str) { $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str); $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str); $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str); $during=str_replace("\r\n","",$during); if($during != "") { // If the [nobr] tag was found, go with the new string. $str = $before.$during.$after; } else { // If the [nobr] tag was not found, go ahead like normal. $str=str_replace("\r\n","<br>",$str); } return $str; I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you! After days of searching I found this thread http://www.phpfreaks.com/forums/index.php?topic=236954.0 that helped me do what I was trying to do. I've gotten the code to create and rename my html document but I can't figure out how to use the preg_replace part. This is my template with the 3 variables I want to replace with values from a form. Code: [Select] <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php include_once('content.php') ?> </body> <SCRIPT language="JavaScript" SRC="javascript.js"></SCRIPT> <script type="text/javascript"> function nametitle(){ parent.iframe1.document.getElementById("div1").innerHTML = "VARIABLE1 <br>VARIABLE2"; parent.iframe1.document.getElementById("quotes").innerHTML = "VARIABLE3"; } </script> </html> I've spent hours reading and trying to understand how to make it work but it's a little over my head. Could someone help me with this? Thanks, im trying to do a complex(i think) prg replace but i keep getting the error: Code: [Select] Failed evaluating code: $lang->showing-1,1 the code i am trying to replace is: Code: [Select] <asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]> and the preg_replace is: Code: [Select] $content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content); its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)". So the output would be showing 1 of 1. Anyone know where im going wrong? Hi there! I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error: Warning: Wrong parameter count for preg_replace() while($row = mysql_fetch_array( $result )) { $reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/"; echo preg_replace ($reg_exUrl, $row['title'); Any suggestion? Thanks Hi Still a new comer when it comes to PHP. I have a situation where I want to use an include within an include and I am having trouble with my file paths. My main header include, includes everything for each page of my site, beyond the opening of the body to incorporate my navigation etc conditionally loading in css, and loading in titles and meta data etc depending on the page in question. This header needs to reference another include called the-pod.php which is required for every page, the only trouble is I want to use / to reference the root of the server and this is breaking my code. I can't use ../../ etc as its a different path depending on where the master file is located. So my question is how do I get around this? Can the root of the server or path to the root be stored in a variable? and if so how would I write this. Any tips / advice will be greatly appreciated. Hi Guys.. Merry Christmas Im kinda new to this fantastic world of PHP and i have a little problem i hope you can help me with. Im trying to build a website where I use include() to genereate my content. On my index.php i have a menu which includes content in a content div from external .php pages, my structure kinda goes like this.. (simplified) site/ index.php content/ fronpage.php products.php contact.php The HTML looks like this. <div id="menu"> <ul> <li><a href="index.php?page=frontpage">frontpage</a></li> <li><a href="index.php?page=products">frontpage</a></li> <li><a href="index.php?page=contact">frontpage</a></li> </ul> </div <div id="main"> <?php include('/content/'.$_GET['page'].'.php'); ?> </div> This all works very fine, but my problem is, can I have a include inside an already included page? I would like to have a menu on my products.php site, but that page is already included from above, and i would like the menu on the products.php site to stay as the content from the nested include changes with input from the /products folder. my idea was something like this. site/ index.php content/ frontpage.php products.php contact.php products/ product1.php product2.php the HTML on the index.php is the same as above and then i would add the include() on the products.php page, so its kinda the same thing, but one inside the other. HTML inside the products.php folder <div id="sub_menu"> <ul> <li><a href="#">frontpage</a></li> <li><a href="#">frontpage</a></li> <li><a href="#">frontpage</a></li> </ul> </div <div id="sub_main"> <?php include('/content/products'.$_GET['#'].'.php'); ?> </div> I dont know how to link to the new files so they will be included while the first include still stays on the page. Any of you know how and if this can be done? Or maybe at better way to do it? Hope this made sense, my first PHP question Thanks CanI put one INCLUDE statement INSIDE of another INCLUDE statement? i want to remove any links which get pulled out in my general information query. Code: [Select] $general_info = $row['general_info']; $general= preg_replace('/<a href="([^<]*)">([^<]*)<\/a>/', '', $general_info); echo '<h2>General Information : <img src="images/mag.png"></h2>'; echo '<div id="featurecontent">'; echo '<p>'. ucfirst($general).'</p>'; echo '</div>'; But the above code doesnt seem to be stripping out links. Can anyone see what i am doing wrong. Kind Regards Dean Hi there! I'm trying to use preg_replace to include/get content a php file with dynamic variable $txt = "Bla bla bla bla bla [gls]12[/gls] bla bla bla"; $txt = preg_replace("#\[gls\](.*?)\[/gls\]#si",file_get_contents('shipping.php?id=\\1'),$txt); ..and it doesn't work. I can not get ID. When I do like that $txt = preg_replace("#\[gls\](.*?)\[/gls\]#si","My Id is - \\1"),$txt); i see it, but not when I'm using file_get_contents function. Thanks in advance for help. I'm working with the youtube API and the function Code: [Select] $relatedVideo->watchURL returns a video url However when I use Code: [Select] preg_replace("youtube","test",$relatedVideo->watchURL); it gives me the following error Code: [Select] preg_replace() [<a href='function.preg-replace'>function.preg-replace</a>]: Delimiter must not be alphanumeric or backslash in <b>C:\wamp\www\site\test.php</b> on line <b>317 Help please? I have no idea what the problem is with preg_replace and strings smaller than 3 characters. I'm writing to do a pattern search of abreviations(array) and replacements (array)... tried word boundries, which seems not to work at all. (it is VITAL that im able to match the whole word) here is a quick example which I cannot understand maybe someone could explain to me: 1. why repitions of certain abrevs do not get replaced. 2. why '/\bs.\b/' wont get matched (where there is a space before the b. - hense the word boundry) here is a snippet of code could someone please explain why this happens: Code: [Select] <?php $string='de d. s. pres. div. de de d. s.'; //DEFINE PATTERN $patterns = array(); $patterns[0] = '/ s. /'; $patterns[1] = '/ b. /'; $patterns[2] = '/ pres./'; $patterns[3] = '/ Ind./'; $patterns[4] = '/ Mar./'; $patterns[5] = '/ Agt./'; $patterns[6] = '/ Agy./'; $patterns[7] = '/ Indpls./'; $patterns[8] = '/ Chgo./'; $patterns[9] = '/ Corp./'; $patterns[10] = '/ U./'; $patterns[11] = '/ Fin./'; $patterns[12] = '/ ls./'; $patterns[13] = '/ Pres. /'; $patterns[14] = '/ Internat. /'; $patterns[15] = '/ m. /'; $patterns[16] = '/ N.Y.C./'; $patterns[17] = '/ div. /'; $patterns[18] = '/ de /'; $patterns[19] = '/ d. /'; //DEFINE PATTERN REPLACE $replacements = array(); $replacements[0] = ' son of '; $replacements[1] = ' born in '; $replacements[2] = ' president'; $replacements[3] = ' Indiana '; $replacements[4] = ' March '; $replacements[5] = ' Agent '; $replacements[6] = ' Agency '; $replacements[7] = ' Indianapolis '; $replacements[8] = ' Chicago'; $replacements[9] = ' Corporation '; $replacements[10] = ' U '; $replacements[11] = ' Financial '; $replacements[12] = ' Island'; $replacements[13] = ' President '; $replacements[14] = ' International '; $replacements[15] = ' married to '; $replacements[16] = ' New York City '; $replacements[17] = ' divorced'; $replacements[18] = ' de '; $replacements[19] = ' daughter of '; echo '------ Original ---------<br>'.$string.'<br>'; $data = preg_replace($patterns, $replacements, $string); echo '<br>------ Abbreviation Replace ---------<br>'.$data.'<br>'; ?> OUTPUT: ------ Original --------- de d. s. pres. div. de de d. s. ------ Abbreviation Replace --------- de daughter of son of president divorcedde daughter of d. s. any help is appriciated thanks. This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=350441.0 Hi guys, this is what im trying to achieve, im trying to remove the links to the current page for all my web pages with a single script, like for example, if i am on a home page, then the home page hyperlink is disabled, and if i am on a about us page the hyperlink for about us is disabled, i have went through many forums and posts but the more i read the more confused i get, however i came up with a method of my own with many bits of code i've read about everywhere. firstly, the script collects the current url of the page(i dont need https or any sub direct, its just for example index.php) then it stores the page name, index.php into a variable say - $current Then a menu.php which is the navigation file is loaded and heres the part i cant get to work, i would like to match find that <a href="index.php"> index </a> and replace that with <a> index </> so that the link to the current page is disabled..i tried using preg_replace but failed miserably and opted to use str_replace Heres the code: <?php //the function below gets the current page url or file //i got this off webcheatsheet - http://www.webcheatsheet.com/PHP/get_current_page_url.php function getPage(){ return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1); } //store the current url or the file name into a variable $current = getPage(); echo "The current page name is ".$current; $menu=file_get_contents("menu.php"); $string = "<a>"+$current+"</a>"; $link = "<a href="+ current +"> "; //i could not get preg_replace to work or come up with an effective regular expression //which is why i use str_replace instead. $menu=str_replace("" , $string, $menu); echo $menu; ?> Hey, I am trying to write a sort of replace function where {user:1} is converted into a set of information from a database using preg_replace. So I have created the following preg_replace: $patterns = array(); $patterns[1] = '/\{user:([0-9]+)\}/'; $replacements = array(); $replacements[1] = UserCredit('$1'); ksort($patterns); ksort($replacements); $content_show = preg_replace($patterns, $replacements, $content); echo $content_show; and then the function UserCredit which is just above that on the page: function UserCredit($user_id) { require 'connect.php'; $user_lookup = mysql_query("SELECT * FROM prop_users WHERE ID = '$user_id'"); while($row = mysql_fetch_array($user_lookup)) { $user_name = $row['full_name']; $user_file = $row['credit_file']; $user_url = $row['link_url']; $user_url_alt = $row['link_alt']; } if(mysql_num_rows($user_lookup)==0){ die("An error has occured, Sorry for any Inconvenience Caused! User ID=".$user_id); } require 'close.php'; $output = "<li class=\"clearfix\"><div class=\"credimg\"><img src=\"".$user_file."\" width=\"75px\" height=\"75px\" alt=\"".$user_name."\" /></div><p><strong><a href=\"".$user_url."\" title=\"".$user_url_alt."\">".$user_name."</a></strong><br /><em>Writing / Code</em></p></li>"; return $output; } I have tested the function and it works when I echo UserCredit('1'); And the preg_replace works at simply extracting the value for the user. The only problem is that I can't figure a way for the preg_replace to carry the value of $1 into the function it just literally carries "$1" Is there something obvious that I am missing or am I going around this the wrong way? |
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