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PHP - How Can I Apply A Usa State Drop Down Menu Selection To Stay On Form Include Re-load?
My problem is when the entries in the form are validated and some fields with incorrect entries are found the fields filled out stay on the re-load of the form, all of them except the US States drop down menu which reverts back to Alabama every time.
I would like to see that the user selection stays in place even after a re-load of the form. and with my limited experience I am having an issue trying to figure this out for a school project. Any help at all would be greatly appreciated, like what variables to create/call on and where exactly I insert this code. Much appreciated. here is the display code: <?php
/* Program name: exercise_4_form.inc
* Description: Defines a form that collects a user's
* name and mailing address.
*/
$rows = array( "first_name" => "First Name (optional)",
"last_name" => "Last Name",
"phone" => "Phone Number",
"city" => "City",
"state" => "State",
"address" => "Address",
"zip_code" => "ZIP Code",
"e_mail" => "E-Mail");
$states_list = array('AL'=>"Alabama",'AK'=>"Alaska",'AZ'=>"Arizona",
'AR'=>"Arkansas",'CA'=>"California",'CO'=>"Colorado",'CT'=>"Connecticut",
'DE'=>"Delaware",'DC'=>"District Of Columbia",'FL'=>"Florida",'GA'=>"Georgia",
'HI'=>"Hawaii",'ID'=>"Idaho",'IL'=>"Illinois", 'IN'=>"Indiana", 'IA'=>"Iowa",
'KS'=>"Kansas",'KY'=>"Kentucky",'LA'=>"Louisiana",'ME'=>"Maine",
'MD'=>"Maryland", 'MA'=>"Massachusetts",'MI'=>"Michigan",'MN'=>"Minnesota",
'MS'=>"Mississippi",'MO'=>"Missouri",'MT'=>"Montana",'NE'=>"Nebraska",
'NV'=>"Nevada",'NH'=>"New Hampshire",'NJ'=>"New Jersey",'NM'=>"New Mexico",
'NY'=>"New York",'NC'=>"North Carolina",'ND'=>"North Dakota",'OH'=>"Ohio",
'OK'=>"Oklahoma", 'OR'=>"Oregon",'PA'=>"Pennsylvania",'RI'=>"Rhode Island",
'SC'=>"South Carolina",'SD'=>"South Dakota",'TN'=>"Tennessee",'TX'=>"Texas",
'UT'=>"Utah",'VT'=>"Vermont",'VA'=>"Virginia",'WA'=>"Washington",'WV'=>"West Virginia",
'WI'=>"Wisconsin",'WY'=>"Wyoming");
$submit = "Submit mailing information";
?>
<html>
<head>
<style type='text/css'>
<!--
body {
background: #42413C;
color: #000;
font-family: Tahoma, Geneva, sans-serif;
font-size: 90%;
}
form {
margin: 1em 2 2 2;
padding: 1;
width: 1100px;
margin-left: 35%;
}
.field {padding-bottom: 1em;
}
label {
font-weight: bold;
float: left;
width: 15%;
margin-right: 1em;
text-align: right;
background-color: #9F6;
padding-right: 5px;
}
select {margin-bottom: 1em;}
#submit {
margin-left: 15%;
}
h3 {
width: 500px;
margin-left: 35%;
}
-->
</style>
</head>
<body>
<h3>Please enter your mailing information below:</h3>
<?php
/* loop that displays the form */
echo "<form action='$_SERVER[PHP_SELF]' method='POST'>";
foreach($rows as $field => $label)
if($field == "state")
{
echo "<label for='$field'>$label</label>
<select id='$field' name='$field'>\n";
foreach ( $states_list as $abbr => $sname )
{
echo "<option value='$abbr'>$sname</option>\n";
}
echo "</select>\n";
}
else
{
echo "<div class='field'><label for='$field'>$label</label>
<input id='$field' name='$field' type='text' value='".@$$field."'
size='25%' maxlength='65' /></div>\n";
}
echo "<div id='submit'>
<input type='hidden' name='submitted' value='yes'>
<input type='submit' value='$submit'></div>";
?>
</form>
</body>
</html>
Here is the Logic on the combined php file that displays and has the statements on it for the form:<?php
/* Program name: exercise_4_form_verifications.php
* Description: Program checks all the form fields for
* blank fields and verifies them
*/
if(isset($_POST['submitted']) and $_POST['submitted'] == "yes")
{
foreach($_POST as $field => $value)
{
if(empty($value))
{
if($field != "first_name")
{
$blank_array[] = $field;
}
}
else
{
$good_data[$field] = strip_tags(trim($value));
}
}
if(@sizeof($blank_array) > 0)
{
$message = "<p style='color: black; margin-bottom: 0;font-weight: bold; margin-left: 35%'>
You didn't fill in one or more required fields.
You must enter:
<ul style='color: yellow; margin-top: 0; margin-left: 35%;
list-style: none' >";
foreach($blank_array as $value)
{
$message .= "<li>$value</li>";
}
$message .= "</ul>";
echo $message;
extract($good_data);
include("exercise_4_form.inc");
exit();
}
foreach($_POST as $field => $value)
{
if(!empty($value))
{
$name_verify = "/^[A-Za-z' -]{1,50}$/";
$phone_verify = "/^[0-9)(xX -]{7,20}$/";
$city_verify = "/^[A-Za-z' -]{1,50}$/";
$address_verify = "/^[A-Za-z0-9 .,'-]{1,50}$/";
$zip_verify = "/^[0-9]{5}(\-[0-9]{4})?$/";
$e_mail_verify = "/^.+@.+\\..+$/";
if(preg_match("/last/i",$field))
{
if(!preg_match($name_verify,$value))
{
$error_array[] = "$value is not a valid last name";
}
}
if(preg_match("/phone/i",$field))
{
if(!preg_match($phone_verify,$value))
{
$error_array[] = "$value is not a valid phone number";
}
} // endif phone format check
if(preg_match("/city/i",$field))
{
if(!preg_match($city_verify,$value))
{
$error_array[] = "$value is not a valid city";
}
}
if(preg_match("/address/i",$field))
{
if(!preg_match($address_verify,$value))
{
$error_array[] = "$value is not a valid address";
}
}
if(preg_match("/zip/i",$field))
{
if(!preg_match($zip_verify,$value))
{
$error_array[] = "$value is not a valid ZIP code";
}
}
if(preg_match("/e_mail/i",$field))
{
if(!preg_match($e_mail_verify,$value))
{
$error_array[] = "$value is not a valid e-mail address";
}
}
}
$clean_data[$field] = strip_tags(trim($value));
}
if(@sizeof($error_array) > 0)
{
$message = "<ul style='color: yellow; margin-top: 0; margin-left: 35%;
list-style: none' >";
foreach($error_array as $value)
{
$message .= "<li>$value</li>";
}
$message .= "</ul>";
echo $message;
extract($clean_data);
include("exercise_4_form.inc");
exit();
}
else
{
echo "<ol>";
foreach($_POST as $field => $value)
{ echo "<h3><li> $field = $value</li></h3>";
}
echo "</ol>";
}
}
else
{
include("exercise_4_form.inc");
}
?>
Edited by mac_gyver, 15 November 2014 - 12:14 PM. code tags around posted code please Similar TutorialsI have 10 tables in my database. I want load these 10 table names into a drop-down list. If a user selects a value form the drop-down list, a form should be displayed with related to the table. (form fields should be appropriate table's column headers) When user fill the form and submitted, data should be saved in the selected table. Give me a code example to do this. Need some help to define the php logic to echo back a selection if/when chosen from the drop down menu. Note: I'm using just a small subset of the USA states to show setup and what I'm trying to accomplish - it will be the same for all the other drop down menus as well.... Here's the example code: Code: [Select] <form name="form1" method="post" action="<?php $_SERVER[PHP_SELF]; ?>"> <select name="address_state" id="address_state" tabindex="25"> <option value="" selected> - Select State -</option> <option value="AK">Alaska</option> <option value="AL">Alabama</option> <option value="AR">Arkansas</option> <option value="AZ">Arizona</option> <option value="CA">California</option> <option value="CO">Colorado</option> <option value="CT">Connecticut</option> <option value="DC">District of Columbia</option> </select> <input name="submit" type="submit" value="submit" tabindex="900" id="submit" /> </form> Issue: I have validation (logic) define to check all the (other) text, radio, and check boxes of the form and that all works great! However, any time one of those particular fields fail validation, any selected "drop down" item is lost - it defaults back to no selection and the user has to make all drop down menu selections again. Can someone provide method to echo back - in php being the page reloads to itself - the drop down selection as in the example above? Thanks! Hi I'm new here, also I'm new in php. What I need to do is to write registration form with drop down menu. Actually, I need to have drop down menu which would write data into database when someone fill registration form. Also I need when someone choose one of the city name in drop down menu, to display certain image in specific php page. Can anyone help me. Here is my code for registration form : register.php <?PHP //Database Information $dbhost = ""; $dbname = ""; $dbuser = ""; $dbpass = ""; //Connect to database mysql_connect ( $dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); $name = $_POST['name']; $email = $_POST['email']; $username = $_POST['username']; $password = md5($_POST['password']); $grad = $_POST['grad']; // lets check to see if the username already exists $checkuser = mysql_query("SELECT username FROM users WHERE username='$username'"); $username_exist = mysql_num_rows($checkuser); if($username_exist > 0){ echo "I'm sorry but the username you specified has already been taken. Please pick another one."; unset($username); include 'register.html'; exit(); } $checkemail = mysql_query("SELECT email FROM users WHERE email='$email'"); $email_exist = mysql_num_rows($checkemail); if($email_exist > 0){ echo "Email koji ste izabrali vec postoji."; unset($email); include 'register.html'; exit(); } $checkname = mysql_query("SELECT name FROM users WHERE name='$name'"); $name_exist = mysql_num_rows($checkname); if($name_exist > 0){ echo "Ime koje ste izabrali vec postoji."; unset($name); include 'register.html'; exit(); } // lf no errors present with the username // use a query to insert the data into the database. $query = "INSERT INTO users (name, email, username, password, grad) VALUES('$name', '$email', '$username', '$password','$grad')"; mysql_query($query) or die(mysql_error()); mysql_close(); if(empty($name) || empty($email) || empty($username)) { echo "Nisu uneseni svi podaci."; } /*else if(empty(($password))) //ovaj uslov ne prolazi !!! { echo "Niste uneli lozinku."; }*/ else { echo "Uspesno ste se registrovali"; } ?> and for form : register.html <form name="login" method="post" action="register.php"> <table border="0" width="225" align="center"> <tr> <td width="219" bgcolor="#ff6600"> <p align="center"><font color="white"><span style="font-size:14pt;"><b>Registration</b></span></font></p> </td> </tr> <tr> <td width="555"> <table border="0" width="555" align="center"> <tr> <td width="116"><span style="font-size:12pt;">Name:</span></td> <td width="156"><input type="text" name="name" maxlength="100"></td> <td width="200"><p align="left"><span style="font-size:11pt;"><i>*Ukucajte vase puno ime i prezime*</i></span></p></td> </tr> <tr> <td width="116"><span style="font-size:12pt;">Email:</span></td> <td width="156"><input type="text" name="email" maxlength="100"></td><br/> </tr> <tr> <td width="116"><span style="font-size:12pt;">Username:</span></td> <td width="156"><input type="text" name="username"></td><br/> </tr> <tr> <td width="116"><span style="font-size:12pt;">Password:</span></td> <td width="156"><input type="password" name="password"></td><br/> </tr> <tr> <td width="116"> </td> <td width="156"> <p align="right"><input type="submit" name="submit" value="Submit"></p> </td> </tr> <tr> <td> <select name = "dropdown" value="options"> <option value "register.php">Izaberi grad</option> <option value = "Beograd">Beograd</option> <option value = "Nis">Nis</option> <option value = "Novi Sad">Novi Sad</option> </select> </td> </tr> </table> </td> </tr> <tr> <td width="219" bgcolor="#ff6600"> </td> </tr> </table> </form> I am creating a form that will allow the user to select the make of vehicle "FORD" for example. If that make of vehicle is selected among different makes of vehicles, then another box will appear, with all the models for that particular model "Fiesta" for example. What type of code accomplishes this setup in my web page? I do not want to list 500 models in one drop down list, but just those for each make in the first drop down list. Thanks much! Hi All, I have 2 tables: one CarMake - CarMakeID - CarMakeDesc two CarModel - CarModelID - CarModelMake - CarModelDesc Depending on what the user selects in the first dropdown (carmake) the possible selection in the second dropdown (model) needs to be limited to only the models from the selected carmake. in the second table (Carmodel : the 'CarModelMake' = CarMakeID, to identify the make) How do I limit the dropdown 'CarModel' based on the selected CarMake in the first dropdown. link : http://98.131.37.90/postCar.php code : -- -- -- Code: [Select] <label> <select name="carmake" id="CarMake" class="validate[required]" style="width: 200px;"> <option value="">Select CAR MAKE...</option> <?php while($obj_queryCarMake = mysql_fetch_object($result_queryCarMake)) { ?> <option value="<?php echo $obj_queryCarMake->CarMakeID;?>" <?php if($obj_queryCarMake->CarMakeID == $CarAdCarMake) { echo 'selected="selected"'; } ?> > <?php echo $obj_queryCarMake->CarMakeDesc;?></option> <?php } ?> </select> </label> <label> <select name="carmodel" id="CarModel" class="validate[required]" style="width: 200px;"> <option value="">Select MODEL...</option> <?php while($obj_queryCarModel = mysql_fetch_object($result_queryCarModel)) { ?> <option value="<?php echo $obj_queryCarModel->CarModelID;?>" <?php if($obj_queryCarModel->CarmodelID == $CarAdCarModel) { echo 'selected="selected"'; } ?> > <?php echo $obj_queryCarModel->CarModelDesc;?></option> <?php } ?> </select> </label> I'm a novice.. and appreciates all the help ! Code: [Select] <div id="nav"> <ul> <li class="item"><a href="/">Home</a>/</li> <li class="item"><a href="/one">one</a></li> <li class="item"><a href="/two>two</a></li> <li class="item"><a href="/three">three</a></li> </ul> <div> i want to add class='active' to the a tags . when the menu is the current page. namely.when i on the home page. the a label is Code: [Select] <li class="item"><a href="/" class="active">Home</a>/</li> .but the others a label are not have class="active". when i on the one page. it is is Code: [Select] <li class="item"><a href="one" class="active">one</a>/</li>.the others a label are not have class="active". GREAT this forum - JUST GREAT !... Issue: All data entered into my online form was lost (blanked out) and the form returned correctly with message "wrong verification code", when submitted with the wrong verification code. However, going through this great forum I managed to get all - manually entered - data back ! I placed value="<?php echo $_GET['the_field_name'];?>"/ after each input field. BUT... not so with input fields entered from drop-down menu ! How do I put a similar string for the field "Payment by" in this sample: <tr> <td class="table-inquire" width="47%"> <font face="Verdana" size="1" color="#000042"> Payment by:</font></td> <td class="table-inquire" width="51%" colspan="2"> <font color="#400000" face="Verdana"> <select name="payment" size="1"> <option value="VISA">VISA</option> <option value="MASTER">MASTER</option> <option value="CASH">CASH</option> <option value="T/T Banktransfer">T/T Banktransfer</option> <option selected>Please select</option> </select></font><font size="2" color="#400000" face="Verdana"></font></td> </tr> Any advise greatly appreciated. Thanks. Is there some way of a php include which is visible on every page (footer), itself having two php includes, but only one of which would be visible, then on the user refreshing the page or on visiting another page on the site, that include would be replaced with another php include? Preferably done without any js. Any help appreciated. Chris This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=349871.0 As a complete newbie to php and webdesigning i have a following problem.I would like to retrieve the data from database and display it in a drop down menu.Then i should allow the user to select the values from drop down list along with other details,in other words i have to embed the drop down output as the form input for the user and store the form data in another table.I am running a xampp server and i am using php 5.4 version.Please help.My code is as follows.In this case project_name is displayed as the drop down output.but how do i use the same drop down output as a input in the form. <html> <head></head> <body> <?php error_reporting(E_ALL ^ E_DEPRECATED); include 'connect.php' ; $tbl_name="projects"; $sql="SELECT project_name FROM $tbl_name "; $result=mysql_query($sql); if($result === FALSE) { die(mysql_error()); } ?> <form name="resources" action="hourssubmit.php" method="post" > <?php echo "<select name='project_name'>"; while ($row = mysql_fetch_array($result)) { echo "<option value='" . $row['project_name'] ."'>" . $row['project_name'] ."</option>"; } echo "</select>"; ?> </form> </body> </html> Hello All,
I have been going crazy trying to figure this out, I hope someone can help me out
I have header and footer.php files that on all my pages I get them to load with include,
but for some strange reason, this certain page it will not load I did some research and apparently theres problems with div and php, does anyone know how to make this work?
Thank you in advance,
Elaine
Attached Files
test.txt 4.81KB
7 downloads If I have a drop-down list... Code: [Select] <select name="attendees"> <option value="">--</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> </select> Where does the value that the user selects get stored? Does it get stored in $_POST by default (if a Form is used)? What variable would hold the selected value? Debbie guys i have this dropdown menu echo "<form method=\"post\" action=\"\">"; echo "<center><select name=\"mydropdown\" size=\"0\" style=\"height:4em; width:15em;\">"; echo "<option value=\"Milk1\">{$_SESSION['tem1']}</option>"; echo "<option value=\"Milk2\">{$_SESSION['tem2']}</option>"; echo "<option value=\"Milk3\">{$_SESSION['tem3']}</option>"; echo "</select></center>"; echo "</form>"; and i wand to update a variable every time i select one of the contents... how can i done this??? I am trying to make a Web Form for people to fill out that has two drop down menus where i want the first drop down menu's selection changes the values of the selections in the second drop down. ((IE. If the first drop down value is "product 01" then the second drop down shows values "Red, Green, Blue" while if the first drop down value is "product 02" then the second drop down shows values "Yellow, Green")) Anyone have any ideas? Thanks in Advance. hello fellas, need some help please if possible. i have created a date of birth section in my form where the user selects his/her date of birth from the dropdown menu. they would first select the day then month then year of their birthday. how would i setup the database to get this to work? i currently have: Code: [Select] day VARCHAR( 2 ) NOT NULL , month VARCHAR( 4 ) NOT NULL , year VARCHAR( 4 ) NOT NULL , is this correct? many thanks Hello, i want to reproduce a content switcher based on drop-down menu (example: http://www.infocercetare.ro/index.php) anyone can help me with the logic of the function the rest i think i can handle. best regards This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=341998.0 I have the website he http://bossexclusive.com/babyauction/index.php , and http://bossexclusive.com/babyauction/thanks.php . When you press submit on the index.php, it takes you to thanks.php. then, after 5s, it takes you back to index.php. My question is: How could I make it so when I press submit, the box submits the form, but instead of redirecting to thanks.php, it displays the same thank you message on the side, but stays on index.php? If that didn't make sense, let me know. My html and php are below (HTML) Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Baby Auction | Discounted Premium Brand Baby Products</title> <link rel="stylesheet" type="text/css" href="styles.css"/> </head> <body> <div id="main"> <div id="contact"> <h1>Sign up to recieve Auction notifications</h1> <form action="emailer.php" method="post"> <input type="text" name="email" id="email" placeholder="yourname@email.com" /> <input type="image" name="submit" src="images/submit.jpg" width="146px" height="20px" value="Submit"> </form> </div> </div> <div class="copyright"> <?php include 'footer.php'; ?> </div> </body> </html> and emailer.php: Code: [Select] <?php $email = trim(strip_tags($_POST['email'])); $subject = "Contact form submitted!"; $to = 'BlankingOutMyEmail@gmail.com'; $body = <<<HTML $message HTML; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; mail($to, $subject, $body, $headers); header('Location: thanks.php'); ?> HI there i am having trouble with some code hope someone can help, i have a webpage with in the page has 7 tabs, on the 7th tab is 3 button eavh one does something different, one will restart the server once pressed one turns it on and one off.
soo when i press the button it all works just i need it to be able to stay on that tab and not refresh the page back to the first tab
here is a sample of my code:
<form method="post" action="{$smarty.server.PHP_SELF}?action=productdetails"> <input type="hidden" name="id" value="{$id}" /> <input type="submit" name="turnoff" value="Power Off"> </form> </td> {php} if(isset($_POST['turnoff'])) { $customfield = $this->get_template_vars('customfield'); $RemoteReboot = explode(",", $customfield['value']); $mib = ".1.3.6.1.4.1.13742.4.1.2.2.1.3."; $mib = $mib.$RemoteReboot[1]; $community = "hjkuiouYUI23"; $result = snmpset($RemoteReboot[0], $community, $mib, i, "0"); #echo($result); } {/php} hey guys just wondering what u think the best way to do this.....on my form registration for users....I have a drop down for countrys....but I dont want to have 2 drop downs 1 for state and 1 for province if they choose canada/usa....I have seen alot of java scrit on such sites where if you choose Canada for country, then it switches to a drop down for just provinces, not states. Same for zip code/postal code...american zip code would be like 90210 where as a postal code would be like n5j2S1. Is there a script or something already I can use with all the countrys/provinces/states etc already entered so im not re-inventing the wheel here? If someone can point me in right directon id appreciate it. Thanks |
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