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PHP - 3 Buttons - Alert() Which Was Pressed
So say I have a page with 3 buttons on:
<button id="1" onclick="clickFunction()">1 </button> <button id="2" onclick="clickFunction()">2</button> <button id="3" onclick="clickFunction()">3</button>How do I then create an alert displaying which was pressed? e.g:
<script>
function clickFunction() { alert("Button X Was Pressed"); }
</script>
I know in this case I could create 3 different functions but I want to use it for a page with a lot more than 3.Thanks, Similar Tutorials
I Need To Show Data After Pressing Browser's Back Button [accidentally Pressed Enter Instead Of Tab]
Hello. I decided to create my own browser game and started learning PHP and HTML. Everything is going quite well now I'm creating a primitive version of the game. I'm reading tutorials and moving forward fast. But I started thinking about the combat system and got stuck. I want to let my users to choose which monster to attack with buttons. I made this form as an example: <p>Choose which monster you want to hunt:</p> Rat<br /> <form action='main.php?p=hunt' method='post'> <input type='submit' name='rat' value='Attack' /><br /><br /> Slime<br /> <form action='main.php?p=hunt' method='post'> <input type='submit' name='slime' value='Attack' /> </form> And I'd like to know what code should I use to know which submit button was pressed, the rat or slime one. I currently only know how to do a lot of IF's to determine it so is there a short way to do it? If anyone can, please help me, and if you can try to explain it simply as I'm still starting to understand php . And also I'd like some suggestions where to run my combat script (the same page where the form is or it should be on a different page, if the page should use id from a rand() function and so on). Thanks The situation: The script is fetching data from the database and printing it out with a while loop, at the same time the rows are being broken up into pages with pagination. The problem: I'm using if and elseif statements for a sorting and ordering functionality. When I now choose a certain category to print out ONLY the chosen category, then the pagination will still be intact. But as soon as I click forward on the pagination navigation links, a page refresh (reload) will happen and the query will default to it's default setting which is category = ALL (and not anymore that specific category I chose earlier). My question: Is there any way to make the script remember the last pressed submit condition? Meaning that if I choose a certain category which should be printed, then the chosen category still remains chosen even if I click the pagination links which cause a page reload? Here's a small script excerpt, to help picture the example: $select_category is taken with $_REQUEST from a drop down menu. // ALL but NO OTHER if (($select_category == 'All') || (!isset($select_category)) && (!isset($most_liked))) { $query = "SELECT * FROM con, user WHERE con.user_id = user.user_id ORDER BY contributed_date DESC"; pagination_start ($dbc, $query); $offset = $pag_array[0]; $rows_per_page = $pag_array[1]; $query = $query . " LIMIT $offset, $rows_per_page"; knuffix_list ($query, $dbc); pagination_end ($pag_array); // CATEGORY but NOT most_liked } elseif (isset($select_category) && !isset($most_liked)) { $query = "SELECT * FROM con, user WHERE con.user_id = user.user_id AND category = '$select_category' ORDER BY contributed_date DESC"; pagination_start ($dbc, $query); $offset = $pag_array[0]; $rows_per_page = $pag_array[1]; $query = $query . " LIMIT $offset, $rows_per_page"; knuffix_list ($query, $dbc); pagination_end ($pag_array); Hi, there is probably a straightforward solution to my problem, but I can't quite work it out. I use the following PHP line to check whether the submit button in an html form was pressed or not: Code: [Select] if (isset($_POST['buttonname'])==FALSE) {do something} If the html form is contained within a PHP script as follows: Code: [Select] <?php print" <html> <body> <form action=check.php method=POST //form here </form> </body> </html> "; ?> then the check works fine. But if the html form is contained within an external html file that is called upon in an iframe as follows: Code: [Select] <?php print" <html> <body> <iframe src ='form.htm'></iframe> </body> </html> "; ?> then the check doesn't work and it always thinks the submit button wasn't pressed. How can I perform this check when the submit button is in an external html file that is called upon in an iframe? Any help would be much appreciated! Thanks. not sure if this will find an answer but I am posting anyway. Any help is appreciated....my coder has left the team and no matter how I invite her to come and do some bug squashing, her new schedules won't fit a re-visit into my little aplication...I am eager to delve into the codes at my very low knowledge of php. I have initiated reading and is still trying to teach myself...but of course not as fast as the app needs the patch...here's the meat: Friends I am new to php and i have to submit my coursework in php by 3rd dec, I stuck at one place where i have to upload multiple photo and one can see all the photo he has uploaded and can edit or delete that photo so i have done uploading now i am showing those pics in table by running loop and generating tr and td but now i have two buttons with each row edit and delete now when i clicked on one delete or edit that pic should be delete or give text box to edit description of pic, Please help me how to do that....... Hi, can anybody check on this code? I don't have any errors in it, except that the supposedly alert after I deleted an information is not working. Thank you very much. **This is a modified code provided by a friend. It worked originally (I just lost the original file since I sold my old computer xD Here's the code: <?php include("dbconnection.php"); if(mysql_num_rows($result) > 0) { $query = "SELECT * FROM records WHERE id = '".$_GET["id"]."'"; $result = mysql_query($query, $connection); $status = mysql_result($result, 0, "status"); $territory = mysql_result($result, 0, "territory"); $job_title = mysql_result($result, 0, "job_title"); $area_of_work = mysql_result($result, 0, "area_of_work"); $employer = mysql_result($result, 0, "employer"); $department = mysql_result($result, 0, "department"); $location = mysql_result($result, 0, "location"); $date_posted = mysql_result($result, 0, "date_posted"); $closing_date = mysql_result($result, 0, "closing_date"); $gender = mysql_result($result, 0, "gender"); $first_name = mysql_result($result, 0, "first_name"); $last_name = mysql_result($result, 0, "last_name"); $telephone_number = mysql_result($result, 0, "telephone_number"); $title = mysql_result($result, 0, "title"); $address_1 = mysql_result($result, 0, "address_1"); $address_2 = mysql_result($result, 0, "address_2"); $address_3 = mysql_result($result, 0, "address_3"); $city = mysql_result($result, 0, "city"); $country = mysql_result($result, 0, "country"); $postal_code = mysql_result($result, 0, "postal_code"); $website = mysql_result($result, 0, "website"); $email_address = mysql_result($result, 0, "email_address"); $cg_comment = mysql_result($result, 0, "cg_comment"); $date_emailed = mysql_result($result, 0, "date_emailed"); $mailing_comments= mysql_result($result, 0, "mailing_comments"); $telesales_comments= mysql_result($result, 0, "telesales_comments"); } if(isset($_POST["btnSubmit"])) { $id = $_POST["id"]; $query = "DELETE FROM records WHERE id = '".$id."'"; mysql_query($query) or die(mysql_error()); echo "<script> alert('You have successfully deleted a record'); window.location = 'view_client.php'; </script>"; } ?> This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=317425.0 Hello, I had a page that lists the tags in a php page, I had make a link looks like : tag.php?ID=2&action=delete I need to give an alert before the tag being deleted. how can I do this? Thanks im trying to get new user messages to show up on my site.. i have looked around on google but can only find info on popup alerts.. i just need a simple javscript code that will display the number of new messages next to the link that takes them to their inbox.. if someone could point me to a site or if they have the code handy i would appreciate it more than you know.. thank you Hello all; I need to throw up a confirmation alert before allowing a database deletion. Here's the code I wrote: Code: [Select] echo "<a href='task.php?option=delete\"onclick=\"return (confirm('Do you really want to delete this?'));>Delete</a>"; The idea is that the Javascript prevents the .php from completing unless the user Confirms. It works great as .html, but I've clearly done something wrong in the .php version, as it never invokes the alert. Does anyone have any idea where I went so horribly, horribly wrong? Thanks! Kyle Hi, In my attendance system i want to add email alert using php. I want the system to check the records in my db and send email to everyone that forgot to clock-in after 7:30AM from Sunday to Thursday. What i need to use for this, ideas? This might be more than just a php question but here goes anyways. I have designed a php chat room page on my home Apache server just for a few friends & family. The problem I have is the only way for me to know if anyone is on the chat room page is if I'm actually viewing the php page. Is there a way that I can have the page alert me when someone accesses it? I was thinking something like activating a popup in my browser or even a beep so as long as I'm at my computer with my browser open that I will know someone has accessed the page. This is my code Code: [Select] $file = $file . $line; fclose($fh); echo "<script language= 'JavaScript'>alert(' . $file . ');</script>"; the alert box is not coming up. Please suggest a way to print the contents of the file in a alert box. Hello, I'm newbie in php. I would like to ask how to start writing php command in order to send due date alert via email. i'm successfully connect php with google smtp. the situation is like this. i would like to send notification to the user if the user is not return back the vessel to the laboratory before 5pm on the same day. Am trying to get an email address from the DB and send an alert but it's not working..
$search3 = mysql_query("SELECT email FROM users WHERE department = '$department' AND (position = '$position')") or die(mysql_error()); $acct1 = mysql_fetch_array($search3); $email = $acct1['email']; $to = $email; $subject = 'New Requisition Alert'; $message = 'You have a new message'; $headers = 'From: server@test.com' . "\r\n" . 'Reply-To: admin@test.com' . "\r\n" . 'X-Mailer: PHP/' . phpversion(); mail($to, $subject, $message, $headers); Hey all - Below is my code. I'm uncertain how to move correctly code (syntax) what I'm looking to do.. When the user clicks "Next" or "Previous," the following youtube clip will load into the div tag. (With the corresponding description tag). Where do I incorporate the str_replace? And how do I make sure both the youtube clip with the correct description is loaded? Any advice is appreciated! <?php $youtubeIds = array("rHNtuaVHenM","zIAdbIMNq9g","QQ4TlJLa-n4","JccPOA12ELI","JccPOA12ELI", "TWhhXVqVB7E"); $embedCode = '<object width="853" height="505"><param name="movie" value="http://www.youtube.com/v/__YOUTUBE_ID__?fs=1&hl=en_US"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/__YOUTUBE_ID__?fs=1&hl=en_US" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="853" height="505"></embed></object>'; if(isset($_GET['youtubeclip'])) { if(is_numeric($_GET['youtubeclip'])) { if($_GET['youtubeclip'] >= 0 && $_GET['youtubeclip'] <= 5) { $youtubeclip = $_GET['youtubeclip']; } else { $youtubeclip = 0; } } else { $youtubeclip = 0; } $prevyoutubeclip = $youtubeclip-1; if($prevyoutubeclip < 0) { $prevyoutubeclip = 5; } $nextyoutubeclip = $youtubeclip+1; if($nextyoutubeclip > 5) { $nextyoutubeclib = 0; } $clip_names= array('Episode #1', 'Episode #2', 'Episode #3', 'Episode #4', 'Episode #5', 'Episode #6'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <title>Billy Green</title> <link rel="stylesheet" type="text/css" media="screen" href="episode_style.css"> </head> <body> <div class="wrapper"> <?php include 'header.php'?> <div id="episode_content"> <div class="youtube_box"> <?php echo $embedCode; ?> </div> <h2 class="clip-description">"<?php echo $clip_names[$youtubeclip]; ?>" </h2> <div class="youtube_control"> <a href="episodes.php?youtubeclip=<?php echo $prevyoutubeclip; ?>"> Previous Clip </a> <a href="episodes.php?youtubeclip=<?php echo $nextyoutubeclip; ?>"> Next Clip </a> </div> </div> <div class="clearIt"> </div> <?php include 'footer.php'?> </div> </body> </html> Hi I have a live chat integrated into my website that uses Ajax, PHP and MySQL. When two people have the chat window open they can chat and it works fine. How can I send an alert to the person being requested to chat with, or for the chat.php page to popup automatically. It prob needs to be some function constantly running in the background check the DB for new message entries. Thanks Jay When I click on this span I want it to alert the ID if the span...
<span id='" . $thisid . "' onClick='likeThis()'><img src='https://cdn1.iconfinder.com/data/icons/nuvola2/32x32/apps/amor.png'>Like</center></span>
<script>
function likeThis(){
var lb = $(this).attr('id');
alert(lb)
}
</script>
However, it currently just says 'undefined'.
What's wrong?Thanks, Using Javascript, how do I do an alert and show the value of a variable? thanks This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=359083.0 |
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