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PHP - Mysqli Error 1062 (dealing With Multiple Duplicate Key Entries)
MySQL returns an error in the form of a number, a state, and a message. Without parsing the message you will not be able to determine what column is duplicated.While parsing the error code, I have also notice that, if you have multiple unique fields as duplicates, only the first duplicate encountered will be returned in the message. This is not very helpful to the end user.
Is there any way to parse the returned error code to reflect all duplicate fields, please see sample code below?
$error=array();
$sql = 'INSERT INTO staff(username, email, phone)
VALUES (?, ?, ?)';
$stmt = $conn->stmt_init();
$stmt = $conn->prepare($sql);
// bind parameters and insert the details into the database
$stmt->bind_param('sss', $username, $email, $phone);
$stmt->execute();
if ($stmt->errno == 1062) {
$errors[] = "One of the fields is already in use.";
}
Similar TutorialsI have a mysql table like so ID OrderID Name Image CatalogID 1 1 test pic1.jpg 1 2 2 test2 pic2.jpg 1 3 1 test3 pic3.jpg 2 4 1 test4 pic4.jpg 3 5 1 test5 pic5.jpg 4 6 2 test6 pic6.jpg 4 7 3 test7 pic7.jpg 4 etc etc (1) I want to use up and down buttons so that the OrderID can be modified to reflect the users order preference, how would I code it so it changes all the OrderID values in the table as necessary to produce the correct order using the buttons, the only affected items each time would be the ones in the same CatalogID group. (2) How do I re number the OrderID when an item is deleted so that it moves all the items below it in the same CatalogID group up one value to still reflect the correct order and not skip OrderID values. I am quite new so I am sure this is an easy fix for some of the experts around here. I am using the canned script below to add urls to the database as text. The problem is if you update one of the form text boxes it loads all the urls into the database again resulting in a lot of duplicates. My question is, How do I get the form to only post the new changes and not re-post the existing urls? <?php session_start(); if(isset($_SESSION['userSession']) && !empty($_SESSION['userSession'])) { include_once("dbc.php"); if($_POST) { $c = 0; $errMssg = ""; for($i=0;$i<count($_POST['url']);$i++) { if($_POST['url'][$i]=="") { $c++; } } if($c==5) { $errMssg = "Submission error . Please fill at least 1 url."; } else { for($j=0;$j<count($_POST['url']);$j++) { if(!empty($_POST['url'][$j])) { $sql = mysql_query("INSERT INTO images (id ,url ,user_id)VALUES (NULL , '".$_POST['url'][$j]."',".$_SESSION['userId'].")"); } } } } $sqlresult = mysql_query("SELECT * FROM images WHERE user_id =".$_SESSION['userId']); $count = 0; while($data = mysql_fetch_array($sqlresult)) { $image[$count] = $data['url']; $count++; } ?> Hi Guys, This is a new post based on my last post for the same but I've revamped the code a little from the last post since I couldn't get it to work even with the suggestions, so my new code is below... Basically I have an updates table (updates_all) and a subscriptions table (subscriptions) and in the updates table items are entered for multiple users with querydate which increases based on the unix timestamp of the update. The Subscriptions table holds the data for users who are subscribed to other user's profiles. My issue is to show a logged in user his subscriptions and when a user he is subscribed to has a new update that user shows up on top of the list of his users. With the code below, i've been able to list the contents of the updates table, filter out the profiles which he is not subscribed to, and order the results by the most recent querydate. My question now is how do I run the while loop so it filters out all but one result per/member name?? Results output below the code... Code: [Select] $sql_findsubs = "SELECT * FROM updates_all ORDER BY auto_id DESC"; $rs_findsubs = mysql_query($sql_findsubs); $subscripPID = array(); $sql="SELECT * FROM subscriptions WHERE memberid='$id' "; $rs=mysql_query($sql); while($row=mysql_fetch_array($rs)) { $subscripPID[] =$row['profileid']; } while($rowfs = mysql_fetch_assoc($rs_findsubs)) { $id = $rowfs['id']; if (in_array($id, $subscripPID)) { echo $rowfs['auto_id'].' - '.$rowfs['querydate'].'.......'.$rowfs['member']; echo '<br>'; } } RESULTS: So if John is subscribed to Bob, Mary, Jim and Andy, I want to only show the four rows below, not all the other entries because those have a smaller querydate for those members. AutoID - Querydate - Name 130 - 1109092040.......Bob <-------- I want to show this one only for Bob 129 - 1109092039.......Bob 128 - 1109091935.......Bob 98 - 1106162306.......Mary <-------I want to show this one only for Mary 97 - 1106162254.......Mary 96 - 1106162215.......Jim <-------I want to show this one only for Jim 90 - 1105062043.......Bob 89 - 1105052200.......Andy <------I want to show this one only for Andy 88 - 1105052154.......Bob 87 - 1105052154.......Bob 86 - 1105052038.......Bob 80 - 1105052034.......Andy 79 - 1105052032.......Andy 73 - 1105052023.......Bob 72 - 1105052018.......Andy 60 - 1103192354.......Bob 4 - 1103172045.......Bob Any help is greatly appreciated... Thanks. I've run into a little bit of a logistical nightmare on some registration pages I've taken over work on. On these pages, parents register their kids for classes. The pages have been coded as such: page one: the user enters name and personal info, and selects one or two classes to register for, on submit, they go to page two. page two: their info is entered into the mysql database's registration table on a unique id The user verifies the total, enters a discount and submits page three: credit card info is added to registration table, and sent to authorize.net. page four: payment processed, and they enter the data for their kids into the attendees table page five: confirmation and done. My issue is that, at first I saw people entering page one data, going to page two, then for some reason, hitting the back button. They could then enter the data again. I'd have two entries in the registration table for the same person. I was going to put some sort of unique key on the name and an email, but then I saw scenario two... Another person enters data and registers one kid.. then for whatever personal reason goes back and registers a second kid in a completely separate transaction. So I can't put that key on there, but is there a way to prevent them from going back and reentering twice. I don't want to have to blow up the code to do it at the end of everything. and that would take implementing sessions, wouldn't it? I'm not so versed at that. Any thoughts? The only 2 tables relevant to what I want to do are "User" and "Scores." Basically this database holds high scores for a project I've been working on. I only want to display 10 scores, all from different users. No 2 or more scores from the same user. This is my db structure within phpmyadmin: Quote database -> table -> X / User / Score / X / X / X / X / X / X / X / X If possible I'd like to run a query where it checks for duplicate entries by the same user and only show the highest score. The current query I'm running is below: $result = mysql_query("SELECT * FROM table ORDER BY Score DESC LIMIT 0, 10"); Is this possible? I can only seem to find information regarding the INSERT IGNORE clause and that obviously won't help me as the users and scores are already in the database. Thanks. I dont even know where to begin doing this. I am supposed to remove duplicate entries in this 2 dimensional array but I just can't find any answers anywhere. Code: [Select] <?php /* In the following two dimensional array (an array of arrays) you will notice that there are several duplicate entries (David and Patricia). 1) Write a basic function which will go through $input and remove the duplicate entries. A "duplicate" is an entry which has the same FirstName and LastName as another entry. Ignore the other fields. Call your function "dedupe1". It should return a two-dimensional array without these duplicates 2) Using your dedupe1 function, write one called dedupe2 which will detect empty DOB's and DOB's of '00/00/0000'. When an empty or zeroed DOB is detected, your code should use the entry with a complete DOB (if available). Like dedupe1 your code should return a two-dimensional array without duplicates. If you use the provided $input function, all of the returned entries should have a complete DOB listed. */ $input = array( array( 'FirstName' => 'Daniel', 'LastName' => 'Anderson', 'Phone' => '614-123-4568', 'Address' => '123 Main St', 'SSN' => '001-01-0001', 'DOB' => '01/11/1922' ), array( 'FirstName' => 'Aaron', 'LastName' => 'Williams', 'Phone' => '937-321-3993', 'Address' => '933 N Park St', 'SSN' => '992-23-1192', 'DOB' => '04/21/1965' ), array( 'FirstName' => 'David', 'LastName' => 'Taylor', 'Phone' => '223-293-9921', 'Address' => '123 Main St', 'SSN' => '003-19-2992', 'DOB' => '12/14/1995' ), array( 'FirstName' => 'Patricia', 'LastName' => 'Anderson', 'Phone' => '614-123-4568', 'Address' => '123 Main St', 'SSN' => '123-32-3123', 'DOB' => '00/00/0000' ), array( 'FirstName' => 'David', 'LastName' => 'Taylor', 'Phone' => '223-293-9921', 'Address' => '123 Main St', 'SSN' => '003-19-2992', 'DOB' => '' ), array( 'FirstName' => 'Patricia', 'LastName' => 'Anderson', 'Phone' => '614-123-4568', 'Address' => '123 Main St', 'SSN' => '123-32-3123', 'DOB' => '02/22/1957' ), ); // Get results from dedupe1 and print them $result1 = dedupe1($input); var_dump($result1); // Get results from dedupe2 and print them $result2 = dedupe2($input); var_dump($result2); print_r($input);//just to see the information in the web page function dedupe1($in_array) { // your code here } function dedupe2($in_array) { // your code here } ?> Hello, i am inserting some form data into my mysql db, i happen to get some duplicates so i want to check first if the entry exists already before i insert. my current code: Code: [Select] <?php if(isset($_POST['submit'])) { ?> <?php if (strlen($_POST['code']) == 19 && substr($_POST['code'],0,7) == '5541258') { mysql_query("INSERT INTO table(code,secret,ip,date) VALUES('$_POST[code]','$_POST[secret]','$_SERVER[REMOTE_ADDR]',CURDATE())"); Print "<font color='green'>The code will be checked now</font>"; } else { Print "<font color='red'>The code is invalid</font>"; } ?><?php } ?> I would like to use the value 'code' to check if the entry exists, that one is unique for each entry. How would i do that ? Thanks ! Hi all,
Its been a long time since last help request from real professional from here but I'm again in trouble with a much more spectacular plan I'm working on. For those who are interested in the plan then here it is: My Idea was to make a new build starting from scratch and make it as dynamical as possible. So my goal is not to make almost anything fixed in the code. I have made a decision to make a one supper large table for multiple different entries so no more joining and no more views for me.! In this help request I'm having trouble with Posting values to a page processing page lets call it record_changer.php The sole purpose of this file is to get form posts and decide what to do. Either update, delete, or insert. record_changer.php
<?php
include '../../config/config.inc.php';
if(is_ajax()){
# Checks if action value exists
if(isset($_POST["action"]) && !empty($_POST["action"])){
$action = $_POST["action"];
# Switch case for value of action
switch($action){
case "insert": datatable_insert_function();
break;
case "update": datatable_update_function();
break;
case "delete": datatable_delete_function();
break;
}
}
}
# Function to check if the request is an AJAX request
function is_ajax(){ return isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest'; }
function datatable_insert_function(){
}
function datatable_update_function(){
}
function datatable_delete_function(){
}
?>
The problem.The problem is that the $insert places two entries to the DB. I cant seem to understand why.?
# Test _POST values
$_POST['UserID'] = '2';
$_POST['WorkID'] = '22';
$_POST['Status'] = '1';
$_POST['Code'] = '1';
$_POST['Title'] = '1';
$columns = array();
foreach(array_keys($_POST) as $name){
# Exclude Action and ID
if($name == 'Action' || $name == 'ID' || $name == 'submit' ){ continue; }
$columns[] = $name;
}
print_r($columns);
echo "<br>";
$data = array_fill_keys($columns, 'NULL');
print_r($data);
foreach($data as $key => $value){
$data[$key] = empty($_POST[$key]) ? 'NULL' : "'".mysql_real_escape_string($_POST[$key])."'";
}
echo "<br>";
print_r($data);
$insert = mysql_query('INSERT INTO datatable (ID, '.implode(', ',$columns).')VALUES (null, '.implode(',',$data).')') or die(mysql_error());
No errors no nothing. Just two entries of correct data. PS. Sorry for a lot of prints in the code it is work and idea in the progress. The posts at the moment are fixed in the code so it is easier to refresh and debug. Please help if you spot the problem. Im really out of ideas. Some fresh eyes might make a difference. And Please for those who want to say it is a bad idea and why and why and so on.. Move a long.!!! Im not interested in whinging i have a great use for this and just having trouble with the two entries. Thanks. Edited by ztimer, 14 January 2015 - 03:27 PM. Hi I am new to PHP / mySQL although not to programming and am trying to work out how to deal with the following situation: I have a form for a user to add a book to a database, along with the genres that the book belongs to. Each book can have a number of genres . There are 3 tables, books, genres and bg_xref in the following formats table: books fields: id, title, author, date published table: genres fields: id, genre table: bg_xref fields: id, book_id, genre_id I am now trying to build the form that allows the user to update an existing entry for a book. the genres are selectable from a multi-selection list which I am populating from all the possible values in the genres table. Currently I have the following database selections: mysql_select_db($database_conn, $conn1); $query_rs_getBooks = "SELECT books.id, books.title, books.author, bg_xref.genre_id FROM books LEFT JOIN bg_xref ON books.id = bg_xref.book_id"; $rs_getBooks = mysql_query($query_rs_getBooks, $conn1) or die(mysql_error()); $row_rs_getBooks = mysql_fetch_assoc($rs_getBooks); mysql_select_db($database_conn, $conn1); $query_rs_getGenre = "SELECT * FROM book_genres ORDER BY genre ASC"; $rs_getGenre = mysql_query($query_rs_getGenre, $conn1) or die(mysql_error()); $row_rs_getGenre = mysql_fetch_assoc($rs_getGenre); I have then created a form that the user uses to update the book, but am trying to work out how to prepopulate the selection list based on teh results of the join e.g. <form method="POST" action="<?php echo $editFormAction; ?>" name="update_book"> <fieldset class="full"> <legend>Enter book details below</legend> <table> <tr><td>Title: </td><td><input type="text" size="50" value="<?php echo htmlentities($row_rs_getBooks['title'], ENT_COMPAT, 'iso-8859-1'); ?>" name="title"></td></tr> <tr><td>Author: </td><td><input type="text" size="30" value="<?php echo htmlentities($row_rs_getBooks['author'], ENT_COMPAT, 'iso-8859-1'); ?>" name="author_surname"></td></tr> <tr><td>Genre(s)</td><td><select name="genre" multiple size="4"> <?php do { ?> <?php if (($row_rs_getBooks['genre_id']) != $row_rs_getGenre['id']) { ?> <option value="<?php echo $row_rs_getGenre['id']?>"><?php echo $row_rs_getGenre['description']?></option> <?php } else { ?> <option value="<?php echo $row_rs_getGenre['id']?>" selected><?php echo $row_rs_getGenre['description']?></option> <?php } } while ($row_rs_getGenre = mysql_fetch_assoc($rs_getGenre)); $rows = mysql_num_rows($rs_getGenre); if($rows > 0) { mysql_data_seek($rs_getGenre, 0); $row_rs_getGenre = mysql_fetch_assoc($rs_getGenre); } ?> </select></td></tr> </table> </fieldset> <input type="hidden" name="id" value="<?php echo $row_rs_getBooks['id']; ?>"> <input type="submit" value="Update book details"> <input type="hidden" name="MM_update" value="update_book"> </form> Book id = 1 is classified against genres 1 and 5, so my SQL query returns 2 rows: book.id = 1 + bg_xref.genre_id = 1 book.id = 1 + bg_xref.genre_id = 5 At the moment the form is generated for the first row of the results set with <tr><td>Genre(s)</td><td><select name="genre" multiple size="4"> <option value="5">Humour</option> <option value="4">Non Fiction</option> <option value="2">Novel</option> <option value="3">Picture Books</option> <option value="1" selected>Poetry</option> with a second entry in the results set for book 1 and genre 5. What I need to end up with is a second occurence of book 1 with both genres 1 and 5 set in the form. Thanks Stuart I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. Hello, Hopefully I can ger som help here I have been googling this for months and seem to cant find anything that will help me out. I am trying to create a form (which is the easy part) but I want this form to send multiple entries at once from what I gather so far I need to use for each and/or loop which i am not familiar with it with my lack of knowledge........ what I have so far is Table= locations fields are id state county city the form is set up as follows state county city city city city city city city city city city city city The reason for so many cities is so i can update all cities in one county at the same time saving time I am not sure if its % doable in the manner i would like it to be done but i hope so ok i enter the state and county then i enter the cities i want i submit the form i want it to create the state/county and the first city with the next id # then enter the state/county and next city and id#. please some help me if u need to see my file let me know and ill post it im just not sure which one you need i believe it will be the save.php file but i also have the create.php file which is the form itself Thanks anyone for the help i can get Hello, For starters I'm not sure if what I want to do is possible, but if it is I would like your input. I have a script that will show a number of fields to fill out in a second form based on the number the user puts into the first from. the problem is that only the last one saves into the database and not all of them. Code: [Select] <form auction="index.php" method="post"> System Name: <input type="text" name="systemname"> Number of E-sites: <input type="text" name="events"> Number of Sigs: <input type="text" name="sigs"><br> <input type="reset" name="reset" value="Reset"> <input type="submit" name="start" value="Start"> </form> <form auction="index.php" method="post"> <?php $events = $_POST['events']; $system = $POST['systemname']; if (isset($_POST['start'])) { $num = $_POST['sigs']; $i = 0; While ($i < $num) { echo "Sig ID: <input type=text name=sigid>"; echo "Type: <input type=text name=type>"; echo "Name: <input type=text name=name>"; echo "Notes: <input type=text name=notes>"; echo "<br>"; $i++; } } ?> <input type="submit" name="enter" value="Enter"> </form> <?php $sigid = $_POST['sigid']; $type = $_POST['type']; $name = $_POST['name']; $notes = $_POST['notes']; mysql_connect('xt', 'x', 'x'); mysql_select_db('wormhole'); if (isset($_POST['enter'])) { $query = "INSERT INTO sites VALUES ('$system','$events','$sigid','$type','$name','$notes')"; mysql_query($query); } ?> How do I get it so all the data saves, lets say that $num = 5, I want all 5 to save not just the last one. Hi guys Im trying to delete multiple images from a page with the code below, I have retirieved the images successfully but i can not delete the with checkbox, wht it does is just refereshing the page and thats it, what im trying to do is to delete the image from the database but it wont. can u help me please? <?php session_start(); include ("../../global.php"); //welcome messaage $username=$_SESSION['username']; echo "$username"; $query=mysql_query("SELECT id FROM users WHERE username='$username'"); while($row = mysql_fetch_assoc($query)) { $user_id = $row['id']; } $ref=$_GET['reference']; $images=mysql_query("SELECT * FROM img WHERE refimage='$ref'"); while($row = mysql_fetch_array($images)) { $image=$row['image']; $thumb=$row['thumb']; ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="" method="post" action=''> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> <td bgcolor="#FFFFFF"><? echo "<a href='$image' rel='lightbox[roadtrip]'><img src= '$thumb' width='60' height='40' alt='$title'>";?></td> <? } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <?php // Check if delete button active, start this $delete = $_REQUEST['delete']; if( $delete != '' ){ $checkbox = $_REQUEST['checkbox']; $count = count($_REQUEST['checkbox']); for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $del = mysql_query("DELETE FROM img WHERE id = '$del_id'"); } } ?> I closed everything down last night and it was all fine, website was working as normal etc, but I've turned on the Xxamp server today and I am getting this error. Seems very random as nothing has changed since it was last on? Does anyone know how to sort this out and why I'm now getting this error? Thanks! Hi, I want to build into my html table that populates my database table to have a column for checkboxes with a delete button that takes the user to another page to confirm the deletion by outputting a message: Are you sure you want to delete ____, followed by a for loop to see how many checked records to get its ID in order to get its appropriate name. So I have a submit button with name attribute of "delete0" and the values of the input type of checkbox is $row['ID'], for some reason, I get the notice: "Notice: Undefined index: modifyArray in C:\display.php" and modifyArray is the name I give to the checkbox attribute (please see this in my display.php below) Here is my display.php Code: [Select] <table border="border"> <!--NB: checkbox form for multiple delete/update/insert--> <form method="post" action=""> <input type='submit' value='DELETE' name='delete0' /> <?php session_start(); require 'bellSessionDisconnect.inc'; require 'bellConnect.inc.php'; $result=mysql_query("SELECT ID, Image, Name, Manufacturer, Price, Description, SimSupport FROM bellProducts"); //phpinfo(); //NB: print table headings if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { //$counter+=1; print "<table border='border'>"; print "<tr> <th>ID</th> <th>Select entries to modifiy</th> <th>Image</th> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> <th colspan='2' align='center'>Modify</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { //extract($row); "<tr align='center'> <td>$row[ID]</td> <td><input type='checkbox' name='modifyArray[]' value='$row[ID]' /></td> <td>"; if(!empty($row['Image'])) { $curImage=$row['Image']; } else if(empty($row['Image'])) { $curImage='fileUploadIcon.jpg'; //$title="please upload item image"; } print "<img src=$curImage width='70px' height='90px' /> </td> <td> $row[Name] </td> <td> $row[Manufacturer] </td> <td> $$row[Price]</td> <td align='left'>$row[Description]</td> <td>$row[SimSupport]</td> <td><a href='bellUploadForm.php?ID=$row[ID]'>UPLOAD IMAGE</a></td> <td><a href='bellUpdateForm.php?ID=$row[ID]'>UPDATE</a></td> </tr>"; //}//END INNER IF }//END WHILE }//END BIG IF ?> <?php if(array_key_exists('delete0', $_POST)) { $modifyArray=$_POST["modifyArray"]; if(!empty($modifyArray)) { header("Location: http://localhost/bellDeleteForm.php"); exit(); } } ?> </form> </table> I will worry about redirecting to bellDeleteForm.php to confirm the records the user wants to delete after I get this going, please help!!! thanks Here is one of those purely conceptual questions, which involves no code. I'm trying to create a select query which among other things, allows a user of a website to search other members who fall within a particular age range. I have a column in the table where the members' information are stored which records their ages. Which brings us to the problem. On any given day, a member's age may increase by one year compared to what it was the previous day, hence the need to update this column periodically. I can't think of any way to automatically update this column on a daily basis. So my solution is to run an initial update query every time a member tries to search other members based on age, which updates the age column for all other members, before running the select query which eventually retrieves the desired age range. This leads to the second problem. Imagine there are thousands of users using the website. At any given instance, there could be hundreds of members, trying to search others based on age. This means hundreds of users will be updating a single column (the age column) in one table at the same time. Is this feasible? Can it cause the server to crash? Or is there really a more reasonable way to do all of this? Thank you all for taking your time to read this. Appreciate any responses. Hi all, I would like to perform two queries in a mysqli statement before closing the connection. I'm using prepared statements and I've read on the php.net you can perform a multi-query using mysqli->multi_query. My problem is that I'm only finding useful examples on how to select and fetch results not using prepared statements. I'm a bit lost with how to do this to update two tables. Currently i'm using two seperate connections to do the queries but want to combine these together: Query one (updates their password and resets number of logins to force password change on next login): Code: [Select] //reset logins to force the user to change password upon next login $loggedin = '0'; // connect to db for mysqli require('../db/db.php'); // updates password and number of logins $insert_stmt = $mysqli->stmt_init(); if ($insert_stmt->prepare("UPDATE users SET their_password=?, loggedin=? WHERE their_username=?")) { $insert_stmt->bind_param('sss', $their_password, $time, $user_email); $insert_stmt->execute(); $insert_stmt->close(); } // if query errors sends an email if ($mysqli->error) { try { throw new Exception("MySQL error $mysqli->error <br> Query:<br> $query", $mysqli->errno); } catch(Exception $e ) { $mess = "Error No: ".$e->getCode(). " - ". $e->getMessage() . "<br >"; $mess .= nl2br($e->getTraceAsString()); $contact_email = "webmaster@website.com"; $message_sub = "Mysqli Forgotten Password Query Error [UPASSWORD01]"; $hdrs = "From: " . $contact_email . "\r\n"; $hdrs .= "Reply-To: ". $contact_email . "\r\n"; $hdrs .= "MIME-Version: 1.0\r\n"; $hdrs .= "Content-Type: text/html; charset=UTF-8\r\n"; mail($contact_email, $message_sub, $mess, $hdrs); } header("refresh: 10; forgotpass.php"); die('ERROR: Unable to reset password. Please check you details and try again or report this error to us using our contact us form.<br><br>We will redirect you back to the forgotten password form in 10 seconds.'); exit(); } $mysqli->close(); Query two (updates a reset log - to keep track on our user password resets): Code: [Select] // change status $resetstatus = "Successful Reset"; // connect to db for mysqli require('../db/db.php'); // inserts a new record $null = NULL; $insert_stmt = $mysqli->stmt_init(); if ($insert_stmt->prepare("INSERT INTO passwordresets VALUES (?, ?, ?, ?, ?)")) { $insert_stmt->bind_param('issss', $null, $user_email, $time, $userip, $resetstatus); $insert_stmt->execute(); $insert_stmt->close(); } // if query errors sends an email if ($mysqli->error) { try { throw new Exception("MySQL error $mysqli->error <br> Query:<br> $query", $mysqli->errno); } catch(Exception $e ) { $mess = "Error No: ".$e->getCode(). " - ". $e->getMessage() . "<br >"; $mess .= nl2br($e->getTraceAsString()); $contact_email = "webmaster@website.com"; $message_sub = "Mysqli Forgotten Password Query Error [UARESETLOG01]"; $hdrs = "From: " . $contact_email . "\r\n"; $hdrs .= "Reply-To: ". $contact_email . "\r\n"; $hdrs .= "MIME-Version: 1.0\r\n"; $hdrs .= "Content-Type: text/html; charset=UTF-8\r\n"; mail($contact_email, $message_sub, $mess, $hdrs); } header("refresh: 10; forgotpass.php"); die('ERROR: Unable to reset password. Please check you details and try again or report this error to us using our contact us form.<br><br>We will redirect you back to the forgotten password form in 10 seconds.'); exit(); } $mysqli->close(); Any ideas would be greatly appreciated. Thank you Hi, I need help to check multiple rows for many columns, so that the script won't re-insert a duplicate entry. For eg: $isRowExist=mysql_query("SELECT (field1,field2) from table1 WHERE field1='$f1' AND field2='$f2' "); if(mysql_num_rows($isRowExist)==1) print "already in table1!"; else //proceed to insert into table table1 *BUT I tried this and it says mysql_num_rows expects resource, and this warning only shows when I have multipel columns I want to compare (it works just fine with one column in the WHERE clause above) Please help! Hi Hope someone can help me please. I have constructed an audio dictionary and have discovered an error now that I have added a few entries to the database. A user can search the database and can click on a result to be taken to the content associated with the entry he chooses. This is the search function; Code: [Select] $search=$_POST["search"]; //get the mysql and store them in $result $result = mysql_query("SELECT word FROM pro_words WHERE word LIKE '%$search%'"); //get the db content that is specified above if (mysql_num_rows($result) < 1) { echo "<br><br><h2> We didn't find anything. Sorry - we did look though.</h2>"; }else { echo '<table align="center" cellspacing="8" cellpadding="8" width="85%"><tr><td align="left"><b>Word</b></td></tr>'; echo "<br><br><h2>Success! Here's what we found:</h2><br>"; while ($r=mysql_fetch_array($result, MYSQLI_ASSOC)) echo '<h2><tr><td align="left"><a href="word.php?w=' . $r['word'] . '">' . $r['word'] . '</a></td></tr></h2>'; } You will see that content is displayed in a new file called word.php. This is relevant code from word.php Code: [Select] $query = "SELECT word,word_type1,sentence1,word_type2,sentence2,word_type3,sentence3 FROM pro_words"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo '<div class="colmask rightmenu">'; echo '<div class="colleft">'; echo '<div class="col1">'; echo '<p>Here are some example sentences that show how we use the word; </p>'; echo '<div id="small"><i> ' . $row['word_type1'] . '</i></div>'; echo '<p><div id="small">' . $row['sentence1'] . '</p></div>'; echo '<div id="small"><i> ' . $row['word_type2'] . '</i></div>'; echo '<p><div id="small">' . $row['sentence2'] . '</p></div>'; echo '<div id="small"><i> ' . $row['word_type3'] . '</i></div>'; echo '<p><div id="small">' . $row['sentence3'] . '</p></div>'; } The problem is that every entry on the database is echoed in word.php whereas I would like only the entries for the word selected to appear. Thanks in advance for any help; do say if you need more info. I'm using paypal PDT, so when the user has made payment he gets directed back to my site, on that page it executes a special sql query. I noticed I can refresh the page to make duplicate sql queries. How can I avoid this?? |
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