PHP - Create New Page After X Created Elements

I have created a login page, but i want the users to be directed to another page only if the login details are correct. How would i do this?any help is appreciate. Coding for the PHP is below: thank you.

Code: [Select]

<?php

$username = $_POST["username"];
$password = $_POST["password"];
//This if statement asks if the $username variable is set. If it is it executes the php script. Otherwise it echoes the login form.
if(isset($username)){

if (!($username == " " && $password == " "))

{

$connect = mysql_connect("","","") or die("Couldn't connect!");
mysql_select_db("") or die("Couldn't find db");

$query = mysql_query("SELECT * FROM users WHERE username='$username'");

$row = mysql_fetch_array($query);

$numrows = mysql_num_rows($query);

   $dbusername = $row['username']; 
   $dbpassword = $row['password'];
}
else {
echo ('<div id="username">
   <form action="" method="post"/>
<font color="red"> Please enter a username and password </font>
      <table><tr><td>
      <img src="imgs/Log In/username.png" alt=""/>
      </td><td>
      <input type="text" size="30" name="username" style="background-color:transparent;" />
      </td></tr></table>

      <table><tr><td>
      <img src="imgs/Log In/password.png" alt=""/>
      </td><td>
      <input type="password" name="password" size="30" />
      </td></tr></table>

      <form id="submitb" action="">
      <input type="submit" value="Log in" />
      </form>

      <p class="register">Not yet a member? <a href="Form.html">Register Here</a>, its Free!</p>
</div>');
}
//check to see if they match
if ($username == $dbusername && $password == $dbpassword) {
echo "You Are Now Logged In, Welcome To AdobeTuts!";
}
else
   echo ('<div id="username">
   <form action="" method="post"/>
<div id="new">
<font color="red"> Wrong Username Or Password, Please Try Again </font> </div> 
      <table><tr><td>
      <img src="imgs/Log In/username.png" alt=""/>
      </td><td>
      <input type="text" size="30" name="username" style="background-color:transparent;" />
      </td></tr></table>

      <table><tr><td>
      <img src="imgs/Log In/password.png" alt=""/>
      </td><td>
      <input type="password" name="password" size="30" />
      </td></tr></table>

      <form id="submitb" action="">
      <input type="submit" value="Log in" />
      </form>

      <p class="register">Not yet a member? <a href="Form.html">Register Here</a>, its Free!</p>
</div>');

}

//This next bit echoes the login form unless the $username variable is set.
else {
echo ('<div id="username">
   <form action="" method="post"/>
    
      <table><tr><td>
      <img src="imgs/Log In/username.png" alt=""/>
      </td><td>
      <input type="text" size="30" name="username" style="background-color:transparent;" />
      </td></tr></table>
      
      <table><tr><td>
      <img src="imgs/Log In/password.png" alt=""/>
      </td><td>
      <input type="password" name="password" size="30" />
      </td></tr></table>
      
      <form id="submitb" action="">
      <input type="submit" value="Log in" />
      </form>
      
      <p class="register">Not yet a member? <a href="imgs/Homepage tuts/Form.php">Register Here</a>, its Free!</p>
</div>');
}

?>

<?php
require_once('upper.php');
$error_msg='';
if(!isset($_COOKIE['LoginIdCookie'])){
if(isset($_POST['submit']))
{
require_once('database.php');
$LoginId=mysqli_real_escape_string($dbc,trim($_POST['LoginId']));
$Password=mysqli_real_escape_string($dbc,trim($_POST['Password']));
if((!empty($LoginId)) && (!empty($Password))){
$query="SELECT * FROM registration WHERE LoginId='$LoginId' AND Password=SHA('$Password') AND Flag='A'";
$result=mysqli_query($dbc,$query) or die('Not Connected');
if(mysqli_num_rows($result)==1)
{
$row=mysqli_fetch_array($result);
setcookie('LoginIdCookie',$row['LoginId']);
//$home_url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index1.php';
header('Location: index1.php');
}
else{
echo 'Enter right UserName/Password combination or You may not approved yet. ';
echo '<a href="ForgetPassword.php">Can\'t access your account?"</a>';
}}
else{
echo' Fill all fields';
}
}}
?>
<html>
<title>Log In</title>
<body>
<?php
if(empty($_COOKIE['LoginIdCookie']))
{
echo $error_msg;
?>
<form method="post" action="<?php echo $_SERVER['PHP_SELF'] ;?>" >
<div class="LoginValidator">
<fieldset>
<legend>
Log In</legend><table><tr><td>
<label for="username">User Name :</label><br/><br/></td>
<td><input type="text" name="LoginId"><br/><br/></tr>
<td><label for="password">Password :</label></td>
<td><head>
   <div id="divMayus" style="visibility:hidden">Caps Lock is on.</div>
   <SCRIPT language=Javascript>

function capLock(e){
 kc = e.keyCode?e.keyCode:e.which;
 sk = e.shiftKey?e.shiftKey:((kc == 16)?true:false);
 if(((kc >= 65 && kc <= 90) && !sk)||((kc >= 97 && kc <= 122) && sk))
  document.getElementById('divMayus').style.visibility = 'visible';
 else
  document.getElementById('divMayus').style.visibility = 'hidden';
}

</SCRIPT>
   </HEAD>

<input onkeypress='return capLock(event)' type="password" name="Password"><br/></td></tr></table>
<input type="submit" name="submit" value="Login" class="Login_button">
</fieldset>

</div>
</form>

<?php 
}
else{
echo 'You are logged in as '.$_COOKIE['LoginIdCookie'];
}
require_once('lower.php');
mysqli_close($dbc);
?>




HI friends..........
In above code when I enter wrong user name or password, it displays error msg properly but problem is that when i enter right user name and password instead to redirect to index1.php it displays LoginPage again..........
I think cookie is not created as well..........
I can't understand where is problem???????/
please help me....................

Hi again....

I'm working on a project that creates a profile page for the user (i.e. 'username.php') when they register. Because there are two ways to register, through Facebook and through the website itself, there has to be an if statement in this page that it crates as to which ID to use for that user. Because Facebook usernames are not unique, we must identify a user through their OAuth User ID which is a 10 digit number. When a user registers through the website itself, usernames are unique so their profile page can be ID'd by their username.

Here's the code that creates that profile page:
function createProfile($user) {
        $userFile = 'users/'.$result['oauth_uid'].'.php';
        $fh = fopen($userFile, 'w') or die("can't open file");
        $stringData = "<?php\n" . '$pageowner = "' . $result['oauth_uid'] . '";' . "\n" . 'include "profile.php";' . "\n?>";
        fwrite($fh, $stringData);
        fclose($fh);
}

$user is the username passed to the function when it's called.

Currently that is set to create a line of code in the new profile page ('userid'.php) that looks like this:
<?php
$pageowner = "100001745088506";
include "profile.php";
?>

I want to add an IF to that page that follows this structu
if oauth_provider == facebook { $pageowner = "oauth_uid" } else { $pageowner = username }

But I don't know how to write that he
 $stringData = "<?php\n" . '$pageowner = "' . $result['oauth_uid'] . '";' . "\n" . 'include "profile.php";' . "\n?>";

to make it show up in the page it creates. I want that if statement to be written IN the page that is created.

I just don't know the syntax well enough yet to do that. Would somebody help me out or point me in the right direction?

Thanks!

Ok i am stuck, i created a php script that draws data from a mysql dB into a php page. How can I send the page as the body in email? I do not need to preview the page, but can send it without ever viewing if that helps. When I put my code into a variable it does nothing. Is it caching? Should I load the results into mysql then send?please advise..

This topic has been moved to HTML Help.

http://www.phpfreaks.com/forums/index.php?topic=323045.0

hi all,

mine http call :
<script type="text/javascript">
var leadidarray =new Array();
leadidarray[1] = 100;
leadidarray[2] = 200;
leadidarray[3] = 300;
leadidarray[4] = 400;
leadidarray[5] = 500;
var url = 'test.php?query=test&leadarray='+leadidarray;
       $.getJSON(url,function(data){});
<script>

Now on the processing page i am getting

$row = $_GET[leadarray] ;
   var_dump($_GET[leadarray]); or print_r( $_GET[leadarray] ); gives me values 100,200,300,400,500

but i want all that separate variables or all values in array so i can compare with another array, how can i do that?

i don't know what this would fall under, but it sounds like php..........is there a way to make a form make a new page from a template........like I have a picture page and I can upload pictures from a form with a picture name....and that name turns into a /name.php file?  does this make sense?

please can you help me in this question , imt confused about it   Create a dice page, that allow the user to enter an integer (from1 to 6) and the program must generate a random number (from1 to 6). if the random number equals the users’ entered number an image with smiley facemust be displayed if not another image with sad face must be displayed. Also,you have to display the integer user entered and the program generated integer in the page.

Whats going on PHPfreaks? So this is what I've been trying to do for the whole weekend and just can't figure it out.

I want to let users create new pages on my site like wiki style but dont want a wiki or drupal or joomla or any of that. I know its possible with:

$text = $_POST['text'];
$file = fopen($text . ".php","x");
fwrite($file,"Welcome to your new page!");

but I'm not sure how to integrate it.

For further clarification here's an example: You come to the site and there is a list of previously made user pages all with their own user generated name. What I want to have is a create new page button that opens a new page allows the user to upload images then submit it to the database and upon refresh of the page their page is now in the list. The create new page resets and is available for another user and on and on.

Any help will be appreciated. I need to get this done it's driving me crazy.

First of all i create the page to copy the buttons as pixels to paste into a design, it's not for a working webpage.

It goes wrong here,
<option value="0">Day</option>
   <?= for(var i=0; i<31; i++){?>
   <option value="<?=i?>"><?=i?></option>
   <?= } ?>
</select>



Code: [Select]
<?php


?>
<html>

<head>
<title>Community Development Project</title>
</head>

<body>
<div id="container">
<form id="opties1" name="opties1" method="post" action="something.php">
<div class="forminput">
<input type="button" id="signin" name="signin" value="Sign In" /> <br/> <br/>
<input type="button" id="register" name="register" value="Register" /> <br/> <br/>
<input type="button" id="uploadimage" name="uploadimage" value="Upload Image" /> <br/> <br/>
<input type="button" id="next" name="next" value="Next" /> <br/> <br/>
<input type="button" id="addanother" name="addanother" value="Add Another" /> <br/> <br/>
<input type="button" id="register" name="register" value="Register" /> <br/> <br/>
<input type="button" id="create" name="create" value="Create" /> <br/> <br/>
<input type="button" id="addfolder" name="addfolder" value="Add Folder" /> <br/> <br/>
<input type="button" id="addimage" name="addimage" value="Add Image" /> <br/> <br/>
<input type="button" id="addtask" name="addtask" value="Add Task" /> <br/> <br/>
<input type="button" id="cancel" name="cancel" value="Cancel" /> <br/> <br/>
<input type="button" id="watch" name="watch" value="Watch" /> <br/> <br/>
</div>
</form>

<form id="opties2" name="opties2" method="post" action="something.php">
<div class="forminput">
<select id="day" name="day">
<option value="0">Day</option>
<?= for(var i=0; i<31; i++){?>
<option value="<?=i?>"><?=i?></option>
<?= } ?>
</select>

<select id="country" name="Country">
<option value="0">Netherlands</option>
<option value="1">Germany</option>
<option value="2">Belgium</option>
</select>

</div>
</form>


</div>
</body>

</html>

I'm using a popular PHP script for my web site, which uses main_1.htm for the header and footer, and inner_index.htm for the main part of the home page. Also, of course it has index.php.

How can I set up a duplicates of these files to work on and test changes to the home page, before I actually deploy the changes on to my live site's home page?

Thanks

Hi,

Please let me know which softwares are required to create a php page? And which is the best one for professional website creation?

Thanks.

This is more of an SEO question. 

I have a site with couple hundred categories within each city. I was wondering what the best approach is to do them?

www.mysite.com/browse/apples?city=new-york

www.mysite.com/browse/new-york?category=apples

Which one is the better way to do it for seo purposes? 

If it's the first method, that would mean I would have to create couple hundred pages for those categories yes?

Hi guyz,

I am looking to create a dymanic comment box for my website where already logged in users can comment on webpages.

It is quite a challenge getting to dynamically display only the comments a particular user posted on a web page.

What I mean is I would like to be able to click on a page, see only the comments logged users posted on that page, and then post my own comment on that page. At the moment I created a comment box for my webpages but the issue is my posted comments on one particular page is displaying on all web pages with is comment system..This is the problem and it is very difficult to find helpful material hopefully you guyz can come to the rescue.

Please guys any help or suggestions are more than welcome.

Thanks

Kdiamonds

Hello,

I am a C++ coder who is new to php so please excuse my n00bness.

I have a form which I am then passing into a MySQL database via a php script. I am also using fwrite to try and create a .php site out of the variables entered into the form. Everything is working fine and I have managed to do this with a .html site but when I try to pass php into fwrite it doesn't work.

example code


$newhtml = fopen("backup/$v_uniquename.php", "w");

fwrite($newhtml, '

<html code here>

');

works like a charm but when I use something like (just an example)

$newhtml = fopen("backup/$v_uniquename.php", "w");

fwrite($newhtml, '
   <?php
      while($row = mysql_fetch_array($result_date)){

      $date     = $row['1'];
      $team1    = $row['2'];
      $team2     = $row['3'];
   ?>
');

I get errors and I am assuming it is because I am passing using ' ' within the php code within a fwrite function. Is this correct? and is there a work around way to make a php page using this method or something similar.