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PHP - Update Query With Checkboxes On Input Form
Hello all,
I am completely sideways right now trying to get this to work. Basically I am attempting to make a form that fetches results based on a drop down and then populates a text box that the user can then edit. I have several issues, first of all, I would have to use check boxes for if a user has a certain file on record. Which would be editable, however, I have had issues displaying tinyint values of -1 as true and 0 as false.
Secondly, writing the data back to the table after clicking a submit button, I have still issues with checkboxes here and am thoroughly confused to if I need to use an array or what here.
Thirdly, should I be using PDO or mysql for this? We have an older NAS device that I will be running this on and the firmware is older.
All the info is stored in the same table, and would be selecting a single record at a time for a user to edit. I was thinking I would just write back ALL values to the table when submit is clicked? Is that a bad idea?
As you can tell I just need someone to kick my butt in the right direction, I feel like I have read all the different ways to skin a cat but confused myself in the process.
Thanks
Similar Tutorialsokay, what i have is a page part of my ACP, and what i am trying to do is list all images from database, the list of images will have a "Checkbox" beside it. the checkbox is for setting where the image will be displayed. reason for the checkbox is cuz the images are only being displayed on 2 separate pages. basicly the whole list of images are in 1 form so when submit is activated its suppose to update the image list where checkboxs have been changed. hope i explained this clearly since im sick haha. but heres what i got for code Code: [Select] <form method="post"> <input type="submit" name="submit" value="Submit" /><br /> <?php $result = mysql_query("SELECT * FROM items") or die("Query Failed: ".mysql_error()); while($row = mysql_fetch_array($result)){ list($id, $item_info, $item_img, $price, $sale, $location) = $row; if($location == 'home'){ $set_checked = 'checked="checked"'; }else{ $set_checked = ''; } if(isset($_POST['location'])){ foreach($_POST['location'] as $value){ $id = $_POST['id']; $insert = mysql_query("UPDATE items SET location='$value' WHERE id='$id'") or die('Insert Error: '.mysql_error()); } } echo '<img src="../images/items/'.$item_img.'" width="100" /> Home Page Slide Show: <input type="checkbox" id='.$id.' value="home" name="location[]" '.$set_checked.' /><br />'; } ?> <input type="hidden" name="hdnLine" value="<? echo $count ?>" /> <input type="submit" name="submit" value="Submit" /> </form> i also added a pic of how it looks like lol Please guys, I need your help on this one. How can call the data from mysql and make the values checked on the checkboxes Have got three tables. I am retrieving data and updating two tables at once... Hello All,
Being a newbie at PHP coding I'm at my wits end trying to figure out:
a) how to pull-in values from a delimeted text field (in a MySQL table) and check/select the appropriate checkboxes, based on the values that were stored in the text field,
b) how to write any changes (made by the user) back to the tables' text field.
Note that this is for an "update.php" file/process.
My "create.php" file/process uses the following HTML to display and accept the checkbox values:
<div class="control-group"> <label class="control-label">Limited Time Sale Days:</label> <div class="lts-checkboxes-container"> <label class="indent-to-the-left"> <input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='F'><span class='no-highlight'>Fri</span> </label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Sa'><span class='no-highlight'>Sat</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Su'><span class='no-highlight'>Sun</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='M'><span class='no-highlight'>Mon</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Tu'><span class='no-highlight'>Tue</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='W'><span class='no-highlight'>Wed</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Th'><span class='no-highlight'>Thu</span></label> </div> </div>And the code (certainly not the best code in the world, but it works) to collect, delemit/concatenate, and save to DB is as follows:
if(empty($_POST['limited_time_sale']))
{
// echo("You didn't select any weekday.");
$selected_lts = '';
$limited_time_sale = '';
}
else
{
$limited_time_sale = $_POST['limited_time_sale'];
$N = count($limited_time_sale);
$selected_lts = '';
// echo("You selected $N DoW(s): ");
for($i=0; $i < $N; $i++)
{
// echo($limited_time_sale[$i] . " ");
if ($i < ($N - 1))
{
$selected_lts .= $limited_time_sale[$i] . "-";
}
else
{
$selected_lts .= $limited_time_sale[$i];
}
}
}
if(!empty($selected_lts)) { $limited_time_sale = $selected_lts; }
Now, I've figured out how to bring-in, and separate the stored values using the following code, however I have no idea what to do next...in order to have only the approprite boxes checked/selected (in the event that all boxes were not selected during the create stage).
$limited_time_sale = isset($values['limited_time_sale']) ? $values['limited_time_sale'] : '';
$checked_lts = explode("-", $limited_time_sale);
In my "update.php" file, the HTML for the forms' checkboxes is as follows:
<div class="control-group"> <label class="control-label">Limited Time Sale Days:</label> <div class="lts-checkboxes-container"> <label class="indent-to-the-left"> <input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='F' <?php echo $lts1; ?>><span class='no-highlight'>Fri</span> </label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Sa' <?php echo $lts2; ?>><span class='no-highlight'>Sat</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Su' <?php echo $lts3; ?>><span class='no-highlight'>Sun</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='M' <?php echo $lts4; ?>><span class='no-highlight'>Mon</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Tu' <?php echo $lts5; ?>><span class='no-highlight'>Tue</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='W' <?php echo $lts6; ?>><span class='no-highlight'>Wed</span></label> <label><input class='lts-checkbox' type='checkbox' name='limited_time_sale[]' value ='Th' <?php echo $lts7; ?>><span class='no-highlight'>Thu</span></label> </div> </div>Attached picture shows that selected checkboxes are saved to the text field as/in the format of "F-Sa-Su-M-Tu-W-Th" - if all checkboxes/weekdays were selected....or as "Sa-M-W-Th" - if only Sat, Mon, Wed, and Thu checkboxes were selected Thanks. Attached Files checkbox-Question.png 403.99KB 0 downloads Hi. I have an input field where a date is entered, format dd-mm-yy. I need to query the database to see if this date exists. How can I convert the date to yyyymmdd before the query? Thanks Hello all, i have a table that displays data from mysql, now i want to update multiple rows from that table with checkboxes, the value will basically just switch from 'new' to 'done' so far i have this: Code: [Select] <tbody> <tr class="first"> </tr> <?php $ticketde=0; while ($ticketde < $numpscde) { $f1pscde=mysql_result($ticketresultde,$ticketde,"id"); $f2pscde=mysql_result($ticketresultde,$ticketde,"ticket"); $f4pscde=mysql_result($ticketresultde,$ticketde,"date"); $f5pscde=mysql_result($ticketresultde,$ticketde,"ip"); $f6pscde=mysql_result($ticketresultde,$ticketde,"done"); $setdone = ($f6pscde["done"] == 'n') ? "<a href=\"donepsc.php?id=".$f1pscde."\"><img src=\"ico_new.gif\" alt=\"new\" /></a>" : $f6pscde["done"]; if(isset($_POST['setdone'])){$checkbox = $_POST['checkbox']; $id = "('" . implode( "','", $checkbox ) . "');" ; $sql = "UPDATE ticket SET done='done' WHERE id='$f1pscde'"; $result = mysql_query($sql) or die(mysql_error()); } ?> <tr class="first"> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $f1pscde; ?></font></td> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $f2pscde; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4pscde; ?></font></td> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $f5pscde; ?></font></td> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $setdone; ?></font></td> <td class="tc"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $f1pscde['id']; ?>"></td> </tr> <?php $ticketde++; } ?> </tbody> </table> <center><input type="submit" name="setdone" id="setdone" value="Set selected to done" class="button"/> - <input type="submit" name="exporttxt" id="exporttxt" value="Export selected to .txt" class="button"/> </center> </fieldset> </form> I found that checkbox code sample on some other site and tried to implement it, i don't really know where to go from here, as it's a total mess to me now, any help would be greatly appreciated. Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete":
if(isset($_POST['highlight-purchased']))
{
// ****** Setup customized query to obtain only items that are checked ******
$sql = "SELECT * FROM shoplist WHERE";
for($i=0; $i < count($_POST['checkboxes']); $i++)
{
$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
}
$sql= rtrim($sql, "or");
$statement = $conn->prepare($sql);
$statement->execute();
// *** fetch results for all checked items (1st query) *** //
$result = $statement->fetchAll();
$statement->closeCursor();
// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";
$statementSetToN = $conn->prepare($sqlSetToN);
$statementSetToY = $conn->prepare($sqlSetToY);
/*** loop through the results/collection of checked items ***/
foreach($result as $row)
{
if ($row["purchased"] != "Y")
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToY = $statementSetToY->fetch();
foreach($resultSetToY as $row)
{
$statementSetToY->execute();
}
}
else
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToN = $statementSetToN->fetch();
foreach($resultSetToN as $row)
{
$statementSetToN->execute();
}
}
}
break;
}
CRUD Queston.png 20.68KB
0 downloads
Hi people. I have a form which inputs into a database. Here is the code that inserts a yes no option... Code: [Select] <select name = "consent"> <option value = "Yes" <?php if ($_POST['consent'] == 'Yes') { echo 'selected="selected"'; } ?>>Yes</option> <option value = "No" <?php if ($_POST['consent'] == 'No') { echo 'selected="selected"'; } ?>>No</option> </select> However, I have been asked if I can make it a yes or no checkbox instead. Please can you tell me how I need to code it so that the "yes" or "no" is recorded in the DB. At the moment I just have this Code: [Select] <input name="consent" type="checkbox" value="Yes" />Yes<br /> <input name="consent" type="checkbox" value="No" />No<br /> Thanks in advance VinceG I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance Currently I show a list of users and their information. You can than click that specific user and it shows you their information to edit. My problem is it's not updating the query with the new input information.
Here is the page that displays the registration information:
<?php
$con=mysqli_connect('localhost', 'root', '');
/* check connection */
if (mysqli_connect_errno($con)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
$query = "SELECT * FROM `bencobricks` . `users`";
$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);
?>
<table width="1000" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<table width="1000" border="1" cellspacing="0" cellpadding="3">
<tr>
<td colspan="4"><strong>List data from mysql </strong> </td>
</tr>
<tr>
<td align="center"><strong>Username</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Membership</strong></td>
<td align="center"><strong>First Name</strong></td>
<td align="center"><strong>Last Name</strong></td>
<td align="center"><strong>Gender</strong></td>
<td align="center"><strong>Birthdate</strong></td>
<td align="center"><strong>Sets</strong></td>
<td align="center"><strong>Checkbox</strong></td>
<td align="center"><strong>Admin Flag</strong></td>
</tr>
<?php
while($rows=mysqli_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['username']; ?></td>
<td><?php echo $rows['email']; ?></td>
<td><?php echo $rows['membership']; ?></td>
<td><?php echo $rows['firstName']; ?></td>
<td><?php echo $rows['lastName']; ?></td>
<td><?php echo $rows['gender']; ?></td>
<td><?php echo $rows['dateOfBirth']; ?></td>
<td><?php echo $rows['sets']; ?></td>
<td><?php echo $rows['checkbox']; ?></td>
<td><?php echo $rows['adminFlag']; ?></td>
<td align="center"><a href="update.php?userID=<?php echo $rows['userID']; ?>">update</a></td>
</tr>
<?php
}
?>
</table>
</td>
</tr>
</table>
<?php
mysqli_close($con);
?>
Page that displays specific user for updating:
<?php
$con=mysqli_connect('localhost', 'root', '');
/* check connection */
if (mysqli_connect_errno($con)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
$id=$_GET['userID'];
$query = "SELECT * FROM `bencobricks` . `users` WHERE `userID` = '$id'";
$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);
$rows=mysqli_fetch_array($result);
?>
<table width="1000" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="update_ac.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td> </td>
<td colspan="3"><strong>Update data in mysql</strong> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
</tr>
<tr>
<td align="center"><strong>Username</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Membership</strong></td>
<td align="center"><strong>First Name</strong></td>
<td align="center"><strong>Last Name</strong></td>
<td align="center"><strong>Gender</strong></td>
<td align="center"><strong>Birthdate</strong></td>
<td align="center"><strong>Sets</strong></td>
<td align="center"><strong>Checkbox</strong></td>
<td align="center"><strong>Admin Flag</strong></td>
</tr>
<tr>
<td align="center">
<input name="username" type="text" id="username" value="<?php echo $rows['username'] ;
echo (isset($_POST['username']) ? $_POST['username'] : ''); ?>">
</td>
<td align="center">
<input name="email" type="text" id="email" value="<?php echo $rows['email']; ?>" size="15">
</td>
<td>
<input name="membership" type="text" id="membership" value="<?php echo $rows['membership']; ?>" size="15">
</td>
<td>
<input name="firstName" type="text" id="firstName" value="<?php echo $rows['firstName']; ?>" size="15">
</td>
<td>
<input name="lastName" type="text" id="lastName" value="<?php echo $rows['lastName']; ?>" size="15">
</td>
<td>
<input name="gender" type="text" id="gender" value="<?php echo $rows['gender']; ?>" size="15">
</td>
<td>
<input name="dateOfBirth" type="text" id="dateOfBirth" value="<?php echo $rows['dateOfBirth']; ?>" size="15">
</td>
<td>
<input name="sets" type="text" id="sets" value="<?php echo $rows['sets']; ?>" size="15">
</td>
<td>
<input name="checkbox" type="text" id="checkbox" value="<?php echo $rows['checkbox']; ?>" size="15">
</td>
<td>
<input name="adminFlag" type="text" id="adminFlag" value="<?php echo $rows['adminFlag']; ?>" size="15">
</td>
</tr>
<tr>
<td> </td>
<td>
<input name="id" type="hidden" id="id" value="<?php echo $rows['userID']; ?>">
</td>
<td align="center">
<input type="submit" name="Submit" value="Submit">
</td>
<td> </td>
</tr>
</table>
</td>
</form>
</tr>
</table>
<?php
// close connection
mysqli_close($con);
?>
Finally the update query:
<?php
function test_input($data){
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
$con=mysqli_connect('localhost', 'root', '');
/* check connection */
if (mysqli_connect_errno($con)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
// update data in mysql database
if (empty($_POST["username"]))
{/* can never be empty due to design */}
else
{$username= test_input($_POST['username']);}
$id = 'id';
$query = "UPDATE `bencobricks`. `users` SET `username` = '$username', `password` = 'NULL', `email` = 'email', `membership` = 'membership', `firstName` = 'firstName', `lastName` = 'lastName',
`gender` = 'gender', `dateOfBirth` = 'dateOfBirth', `date` = 'NULL', `sets` = 'sets', `checkbox` = 'checkbox', `adminFlag` = 'adminFlag' WHERE `userID` = '$id'";
$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);
// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='editUser.php'>View Users Page</a>";
}
else {
echo "ERROR";
}
?>
Attached Files
1.PNG 19.06KB
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2.PNG 47.07KB
0 downloadsAfter a ton of trial and error and searching and searching for the answer, I have finally resorted to posting to ask for help. I am very new to php so please bear with me.
I have been building an employee training database at work. Basically to make sure that for example we have the current drivers liscense on file for those employees who drive and have gone through the required company training. I initially built an access database with a frontend that does everything needed. However, the company is very decentralized and we have several users who would regularly need access to the information when they are offsite. The database does work offsite however it is extremely slow. After purchasing a buffalo linkstation, I discovered it has the capability for a mysql server.
I have been able to migrate the data over to the mysql server and build a simple read only php form but cant get the changes you make to update back into the database.
I found a method of fetching the data using json that is based on a drop down selection, upon change, it goes and gets the correct data.
<script type="text/javascript">
function insertResults(json){
$("#Separated").val(json["Separated"]);
$("#id").val(json["id"]);
$("#Employee_ID").val(json["Employee_ID"]);
$("#Last_Name").val(json["Last_Name"]);
$("#First_Name").val(json["First_Name"]);
$("#Date_Of_Birth").val(json["Date_Of_Birth"]);
$("#Original_Hire_Date").val(json["Original_Hire_Date"]);
$("#Current_Hire_Date").val(json["Current_Hire_Date"]);
However, lets say you correct a mis-spelling in their name, I cant seem to write back to the db. I have a submit button that uses this code
<a href="InputFormSubmit.php?id=<?php echo $rows['id']; ?>"><input type="submit" name="submit2" value="Submit"></a>But I guess I cant seem to #1 completely grasp how to pass on the selected information using POST (correct?) to the next form "InputFormSubmit" and #2 correctly build the query for it? Code for it below:
<?php
include_once('db.php');
$Employee_ID = $_POST['Employee_ID'];
$Last_Name = $_POST['Last_Name'];
$First_Name = $_POST['First_Name'];
$id=$_POST['id'];
echo "$id";
echo "$Employee_ID";
// update data in mysql database
$con=mysql_connect("localhost","usernamegoeshere","passwordgoeshere","databasenamegoeshere");
// Check connection
mysql_query("UPDATE tbl_Employee_Master SET Last_Name='$Last_Name', First_Name='$First_Name' WHERE id='$id'");
mysql_close($con);
?>
The proper EmployeeID is passed from the previous form into this one, but the query dies I guess.
What I would like to do is pass the updated info into InputFormSubmit and then run the query and redirect back to the search page. Potentially passing back the employee ID and setting the drop down to that value so you would see the employees file you just updated again.
Super long post, thanks for any direction anyone can give me, Im sure my code looks awful from trying a thousand different things.
Thanks again.
Hi This does not make sense to me, I hope someone can tell me why this query don't work: Code: [Select] safe_query("UPDATE ".PREFIX."cup_challenges SET reply_date='$postdate', $select_map $select_date challenged_info='".$_POST['info']."', status='2' WHERE chalID='".$_GET['challID']."'");; and this query does work: Code: [Select] safe_query("UPDATE ".PREFIX."cup_challenges SET reply_date='$postdate', map1='".$_POST['map1']."', map2='".$_POST['map2']."', map3='".$_POST['map3']."', date1='".$_POST['date1']."', date2='".$_POST['date2']."', date3='".$_POST['date3']."', date4='".$_POST['date4']."', challenged_info='".$_POST['info']."', status='2' WHERE chalID='".$_GET['challID']."'"); Variables in $select_map and $select_date makes the query fail but when I copy/paste this (bold) in query it works: $select_map = map1='".$_POST['map1']."', map2='".$_POST['map2']."', map3='".$_POST['map3']."', $select date = date1='".$_POST['date1']."', date2='".$_POST['date2']."', date3='".$_POST['date3']."', date4='".$_POST['date4']."', am I using the variable in query incorrectly? Hi Guys, I'm hoping someone can find what I clearly cant see, I have a page meant to update database records, the page will load and populate with the existing data and allow 5 out of the 7 fields to be edited, however when editing any of those 5, the remaining 2 blank out and can't be filled in again. Im at a bit of loss and have been staring at it for a bit too long i think, hoping a fresh set of eyes can help. Here's the page (the fields I'm having issues with are inv1/inv2: <?php $page_title = 'Edit a Cart'; include ('style.html'); // Check for a valid ID, through GET or POST. if ( (isset($_GET['id'])) ) { // Accessed through active_search.php $id = $_GET['id']; } elseif ( (isset($_POST['id'])) ) { // Form has been submitted. $id = $_POST['id']; } else { // No valid ID, kill the script. echo '<div id="title">Page Error</div> <p class="error">This page has been accessed in error.</p><p><br /><br /></p>'; exit(); } require_once ('mysql_connect.php'); // Connect to the db. // Check if the form has been submitted. if (isset($_POST['submitted'])) { $errors = array(); // Initialize error array. // Check for a PO. { $po = trim($_POST['po']); } // Check for a Master Serial. { $sr = trim($_POST['serial']); } // Check for a Charger Serial. { $ch = trim($_POST['charger']); } // Check for a Battery Serial. { $bt1 = trim($_POST['battery1']); } // Check for a Battery Serial. { $bt2 = trim($_POST['battery2']); } // Check for a Inverter Serial. { $in1 = trim($_POST['inv1']); } // Check for a 2nd Inverter Serial. { $in2 = trim($_POST['inv2']); } // Check for a Radio Serial. { $abc = trim($_POST['abc']); } if (empty($errors)) { // If everything's OK. // Test for unique master serial. $query = "SELECT serial FROM serials WHERE serial='$id'"; $result = mysql_query($query); if (mysql_num_rows($result) == 1) { // Make the query. $query = "UPDATE serials SET po='$po', serial='$sr', charger='$ch', batt1='$bt1', batt2='$bt2', inv1='$in1', inv2='$in2', abc='$abc' WHERE serial='$id'"; $result = @mysql_query ($query); // Run the query. if (mysql_affected_rows() == 1) { // If it ran OK. // Print a message. echo '<div id="title">Success!</div> <p>The node has been edited.<a href="javascript:window.close();">Close</a></p><p><br /><br /></p>'; } else { // If it did not run OK. echo '<div id="title">System Error</div> <p class="error">The node could not be edited due to a system error. We apologize for any inconvenience.</p>'; // Public message. echo '<p>' . mysql_error() . '<br /><br />Query: ' . $query . '</p>'; // Debugging message. exit(); } } else { // Already registered. echo '<div id="title">Error!</div> <p class="error">The Serial has already been registered.</p>'; } } else { // Report the errors. echo '<div id="title">Error!</div> <p class="error">The following error(s) occurred:<br />'; foreach ($errors as $msg) { // Print each error. echo " - $msg<br />\n"; } echo '</p><p>Please try again.</p><p><br /></p>'; } // End of if (empty($errors)) IF. } // End of submit conditional. // Always show the form. // Retrieve the user's information. $query = "SELECT * FROM serials WHERE serial='$id'"; $result = @mysql_query ($query); // Run the query. if (mysql_num_rows($result) == 1) { // Valid ID, show the form. // Get the user's information. $row = mysql_fetch_array ($result); // Create the form. echo '<div id="title">Edit a Cart</div> <form action="serial_edit.php" method="post"> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td>P.O #:</td><td><input type="text" name="po" size="15" maxlength="15" value="' . $row['po'] . '" /></td> </tr> <tr> <td>Cart Serial:</td><td><input type="text" name="serial" size="15" maxlength="30" value="' . $row['serial'] . '" /></td> </tr> <tr> <td>Charger:</td><td><input type="text" name="charger" size="20" maxlength="40" value="' . $row['charger'] . '" /> </td> </tr> <tr> <td>Battery 1:</td><td><input type="text" name="battery1" size="20" maxlength="40" value="' . $row['batt1'] . '" /> </td> </tr> <tr> <td>Battery 2:</td><td><input type="text" name="battery2" size="20" maxlength="40" value="' . $row['batt2'] . '" /> </td> </tr> <tr> <td>Inverter 1:</td><td><input type="text" name="inverter1" size="20" maxlength="40" value="' . $row['inv1'] . '" /> </td> </tr> <tr> <td>Inverter 2:</td><td><input type="text" name="inverter2" size="20" maxlength="40" value="' . $row['inv2'] . '" /> </td> </tr> <tr> <td>ABC:</td><td><input type="text" name="abc" size="20" maxlength="40" value="' . $row['abc'] . '" /> </td> </tr> <tr> <td><input type="submit" name="submit" value="Submit" /><input type="hidden" name="submitted" value="TRUE" /></td> <td><input type="hidden" name="id" value="' . $id . '" /></td></tr> </form>'; } else { // Not a valid ID. echo '<div id="title">Page Error</div> <p class="error">This page has been accessed in error.</p><p><br /><br /></p>'; } mysql_close(); // Close the database connection. ?> Hi, i am currently designing a new website and am testing a few different compnents of it. One part gathers two variables of the url using the GET method and selects the relevant data from the database. It then performs an UPDATE of a field called balance before INSERTING a new record. Everything works and gets inserted except for the UPDATE. Here is the code Code: [Select] <?php include ("connect.php"); $id = ""; $offerid = ""; $id = $_GET['user_id']; $offerid = $_GET['offer_id']; $sql_user = mysql_query("SELECT * FROM user_info WHERE id = $id"); $sql_offer = mysql_query("SELECT * FROM offers WHERE offerid = $offerid"); $balance += $payout; mysql_query("UPDATE user_info SET balance = $balance WHERE id = $id"); mysql_query ("INSERT INTO offer_credited (id, offerid, date_credited, payout_to_user) VALUES ('$id', '$offerid', CURDATE(), '$payout')") or die(mysql_error()); echo "Your Offer has been recorded and Updated" ?> The balance field is a float that i want to increase by the amount of the payout variable which is from the offers table. However, the balance never gets updated and remains at 0. Any ideas what it could be, i am thinking it is something to do with, Code: [Select] $balance += $payout; But i can't think of what else to do. Hopefully this isn't too confusing. Thanks for the help I would like to edit a record that I already have in my database but my query is not working for some reason. Hope someone can help. The errors i get are Notice: Undefined variable: first_name in C:\chemicaluser\www\editinfo.php on line 40 Notice: Undefined variable: last_name in C:\chemicaluser\www\editinfo.php on line 40 Notice: Undefined variable: log_number in C:\chemicaluser\www\editinfo.php on line 40 .... line 40 = my query $query = "UPDATE table1 SET first_name = '$first_name', last_name = '$last_name' WHERE log_number = '$log_number' "; Very simple database, 1 table w/ 2 fields table name = table1 fields = first_name, last_name my php file Code: [Select] <?php require ('/menu.php'); require_once('sqlconnect.php'); if (isset($_GET['log_number']) && isset($_GET['first_name']) && isset($_GET['last_name']) ) { $log_number = $_GET['log_number']; $first_name = $_GET['first_name']; $last_name = $_GET['last_name']; } else if (isset($_POST['log_number']) && isset($_POST['first_name']) && isset($_POST['last_name']) ) { $log_number = $_POST['log_number']; $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; } if (isset($_POST['submit'])) { $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $query = "UPDATE table1 SET first_name = '$first_name', last_name = '$last_name' WHERE log_number = '$log_number' "; $result = mysqli_query($dbc, $query) or die ('Error querying database'); mysqli_close($dbc); } ?> my form Code: [Select] <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <label for="first_name">First name</label> <input type="text" id="first_name" name="first_name" value="<?php if (!empty($first_name)) echo $first_name; ?>"/> <label for="last_name">Last Name</label> <input type="text" id="last_name" name="last_name" value="<?php if (!empty($last_name)) echo $last_name; ?>" /> <input type="submit" value="Edit Information" name="submit" /> </form> Hi all, I'm trying to make a query that allows the user to edit the name of a entry in SQL. I believe I have the corect Syntax but I'm not sure if I have the code set up correctly. I am using 2 queries when I think it is possible with one. The first query is used to Pint out results for a certain year and the second to update the names. Code: [Select] $desiredYear = $_POST['year']; $nameEdit = $_POST['edit']; $origName = $_POST['orig']; echo ' The year you have chosen is '.$desiredYear; $describeQuery = "SELECT ID, Name, (SELECT SUM(SalesVolume) as SalesVolume FROM MonthlySales WHERE ProductCode=Products.ID AND Year = '$desiredYear') AS num_sales FROM Products"; $editQuery = "UPDATE Products SET Name = '$nameEdit' WHERE Name ='$origName'"; $results = sqlsrv_query($conn, $describeQuery); echo '<table border="1" BORDERCOLOR=Black>'; echo '<tr><th bgcolor = "LightBlue">Name</th><th bgcolor = "LightBlue" >ID</th> <th bgcolor = "LightBlue" >Sales</th></tr>'; while($row = sqlsrv_fetch_array($results, SQLSRV_FETCH_ASSOC)) { echo '<tr>'; echo '<td >' .$row['Name'].'</td>'; echo '<td>' .$row['ID'].'</td>'; echo '<td>' .$row['num_sales'].'</td>'; echo '</tr>'; } echo '</table>'; sqlsrv_close($conn); Can somebody help me with this? Thank you I have a value that in parts of my code i need to update. Its a number value, stored as TEXT. which i need to add numbers to it, at the moment I am using this to get the current value: Code: [Select] $sql2="SELECT * FROM weekly LIMIT 1"; $result2=mysql_query($sql2); $row2 = mysql_fetch_array( $result2 ); $rollingjackpot = $row2['rollingjackpot']; then i am adding the value to the varible, then using UPDATE to update it again, cant this be done in a simple query? something like: Code: [Select] $query = mysql_query("UPDATE weekly SET `rollingjackpot` + $amount WHERE `id` = '1'") or die(mysql_error()); Hi all, Firstly here is my code Code: [Select] <?php if (isset($_POST['update'])) { include('../config.php'); $name = $_POST['name']; $email = $_POST['email']; $id = $_POST['id']; $uquery=mysql_query("UPDATE customers SET name='$name' AND email='$email' WHERE id='$id'"); if($uquery) { echo mysql_error(); } else { echo mysql_error(); } } ?> <link href="../styles/clientbox.css" rel="stylesheet" type="text/css"> <link href="cancelform.css" rel="stylesheet" type="text/css" /> <link href="../styles/form_dark.css" rel="stylesheet" type="text/css" /> <body><br> <h3>My Details</h3> <div class="text"> Please keep your details updated below, for security reasons you cannot change your password.<br> <?php $id = $_GET['id']; include('../config.php'); $query=mysql_query("SELECT * FROM customers WHERE id='$id'"); while($row = mysql_fetch_assoc($query)) { $name = $row['name']; $email = $row['email']; } ?> <form class="dark" action="" method="post"> <ol> <li> <fieldset> <legend>My Details</legend> <ol> <li> <label for="name">Account Holder</label> <input type="text" id="name" name="name" value="<?php echo $name;?>" /> </li> <li> <label for="email">Contact/Login Email Address</label> <input type="text" id="email" name="email" value="<?php echo $email;?>" /> <input type="hidden" id="id" name="id" value="<?php echo $id;?>" /> </li> </ol> </fieldset> </li> </ol> <p style="text-align:right;"> <input type="reset" value="CANCEL" /> <input type="submit" value="UPDATE" name="update" /> </p> </form> Basically what is happening is that whatever you enter into the name box returns a 0 if its text or 1 if numbers are entered as opposed to storing the value inputed, if the email address is changed then nothing happens at all. Can someone see if I have made a noob mistake somewhere? The name and email fields are both varchar(256) in my database Thanks Good morning. I am looking fo some help with an update script to update all rows in a table. This is what I have for a form and all looks well. form.php <?php // run the query and put the results in an array variable called $result $result = mysql_query("SELECT * FROM table ORDER BY 'id', 'title', 'text', 'number'"); print "<form method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>ID</strong></td> <td align='center'><strong>Title</strong></td> <td align='center'><strong>text</strong></td> <td align='center'><strong>Number</strong></td> </tr>\n"; // start a loop to print all of the courses with their book information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['id']}</p></td>\n"; print "<td align='center'><input type='text' name='title' value='{$Update['title']}' /></td>"; print "<td align='center'><input type='text' size='40' name='text' value='{$Update['text']}' /></td>\n"; print "<td align='center'><input type='text' size='40' name='number' value='{$Update['number']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; print "</tr>\n"; ?><br /><br /> My question is. How do I update this info into the database with the proper info. ie. Update.php? hello all, im wondering if it is possible to have multiple check boxes that get created based on the number of rows in a table (one representing each row) Code: [Select] <input type='checkbox' name='approve[$tid]' value='ON'> and then have a submit button at the bottom of the page that will find all of the checkboxes (it could be 1, or 100) and submit it to my form handling page. thanks |
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