PHP - Php Get Current Time

I have a field called date_time in the database which is of type datetime.
I have a form which on submit needs to enter the current date and time in the date_time field.
I know I can get the current time using time()
$time=time();
Can do I do some kind of manipulation using strtotime() and store in the database in  datetime format?

Hi,

I have a problem. i want to show the current date and time in my tables of the database. I want to show it because i want to show it on my report generated in php.

By the way i do not have a "date" field in my form. Can anyone help me out?

Thanks,
Heshan.

i get this error Warning: current() [function.current]: Passed variable is not an array or object..

for this
Code: [Select]
$lastblock = current( ${"s".$row} );
print_r($lastblock);
when i change to this it works..
Code: [Select]
$lastblock = current( $s0 );
print_r($lastblock);
The problem is i won't know the $row seeing as it is in a while loop.  Solution?

Hi,

I'm wanting to find rows whose date is within the next week of the current month of the current year. The format of the date is, for example: 2010-10-28

Any ideas guys?

Thanks lots!

Hello - I've come to an issue with something I'm working on and have searched around with no luck.

When editing user accounts I want it to not be able to change the e-mail address into existing ones on other rows, but when submitting the form it takes into account that this particular rows email address is the same as the one which was sent via $_POST and throws up the error.

The desired behaviour I want is for it to ignore the ID of the row which was posted, but take into account every other row.

Here's the code as it stands at the moment:

$email = $_POST['email'];
        $checkemail = mysql_query("SELECT email FROM users WHERE email='$email'");

} if (mysql_num_rows($checkemail) > 0) {

return $this->error("The e-mail address you provided is already associated with an account.");
}

Hi i have this drop down list current the year is 2010 and downwards but i want to change the list to 2010 upwards u can notice on the 50-- so shows current year minus so current is 2010 to 61 how can i change 2010 to 2030 or sunfin??

echo '<select name="year_of_birth">',"\n";
    $year = date("Y");
    for ($i = $year;$i > $year-50;$i--) {
      if($i == $thisYear) { 
        $s = ' selected'; 
      } else { 
        $s='';
      }
      echo '<option value="' ,$i, '"',$s,'>' ,$i, '</option>',"\n";
    }
  echo '</select>',"\n";

PHP date and time function is not showing correct time on my local system

I have the following php code

date_default_timezone_set("Africa/Lagos");

$date = date('d-m-y h:i:s');

echo "Server Time ".$date ."<br>";

echo "The time is " . date("h:i:sa")."<br>";

$current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa')));

echo "Current time1: ".$current_datetime . "<br>";

 

Output

Server Time 21-05-21 09:55:39
The time is 09:55:39am
Current time1: 2021-05-21 09:55:39

 

Expected Output

Server Time 21-05-21 10:55:39
The time is 10:55:39am
Current time1: 2021-05-21 10:55:3

 

Any help would be appreciated.

 

Edited May 21 by Ponel

I am trying to simulate an ad expiration and carry out an action if the ad is expired. And I cannot get the if/else to work properly... I've tried many variations and I cannot see what I am doing wrong here. Any tips please 3 hours and counting of no solution!

$ad_start = time()-14 . "<br />"; // 14 days from today in the past (negative)
echo $ad_start;

$current_time = time() . "<br />"; // current epoch time
echo $current_time;

$days_past = $ad_start - $current_time; // days past

echo "<br />$days_past days have past since the ad started!<br />";

if($days_past <= 14)
{
echo "<br />Ad is less than 14 days.  Not expired.";
}
else
{
echo "<br />Ad is over 14 days. Expired.";
}

Basically I have recently been playing around with parsing a csv file. What I am looking to do at this point is simply take the date/timestamp (part of the csv file), which is in the following format:DD/MM HH:MM:SS.100th/s
For the sake of argument, lets say I have this in an array string called $csv[0] and the file has several lines that span the course of a couple hours. I wouldn't mind having to use explode() to breakup/remove the date or 100th/s IF that would make things a lot simpler.

So where would I start in trying to achieve this?. The result I am looking for will simply return "X Seconds". Storing this in a string variable would be a bonus, as I plan to use this to divide a separate piece of information.

Any examples or ideas would be great. Thank you.

ps:
Here is an example time from the csv file itself:
Code: [Select]
11/19 22:23:18.143

What are the differences and implications of UTC time and Zulu time?
  

<?php
function getArr(string $time):array
{
    $dateTime = new \DateTime($time);
    return [
        'time'=>$time,
        'timestamp'=> $dateTime->getTimestamp(),
        'dateTime' => $dateTime
    ];
}
$arr = getArr('2020-08-05');  
$arr_z = getArr('2020-08-05T00:00:00Z');  

print_r($arr);
print_r($arr_z);

echo('equal timestamps: '.($arr['timestamp'] === $arr['timestamp']?'true':'false'));

 

Array
(
    [time] => 2020-08-05
    [timestamp] => 1596585600
    [dateTime] => DateTime Object
        (
            [date] => 2020-08-05 00:00:00.000000
            [timezone_type] => 3
            [timezone] => UTC
        )

)
Array
(
    [time] => 2020-08-05T00:00:00Z
    [timestamp] => 1596585600
    [dateTime] => DateTime Object
        (
            [date] => 2020-08-05 00:00:00.000000
            [timezone_type] => 2
            [timezone] => Z
        )

)
equal timestamps: true

 

I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php

Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas?

Thanks!

This topic has been moved to Application Design.

http://www.phpfreaks.com/forums/index.php?topic=316461.0

Hello,

I tried to implement some PHP code to enable a web page to show "Dinner" specials versus "Lunch" specials based on the time.

The business is located in the Eastern Time Zone, so I only need to routine to work based on Eastern Time (New York).

What I am noticing is that the server is processing the lines of code so fast that the command to establish the correct time for the remaining code is not always being acknowledged.

This line of code appears to be processing too fast for the remaining lines of code:
date_default_timezone_set ( "America/New_York" );

Is there some additional code I can put in place to make sure the correct time is always ascertained?

I need the $hourmin variable to always return a combination of hour + minute based on 24-hour time and Eastern Time zone.

My code is as follows:


 <?php
   $name8 = file_get_contents("test/special8name.txt");
date_default_timezone_set ( "America/New_York" );
$gethour = date("H");
$getminutes = $gettimedate["minutes"];
$gettimedate = date();
$hourmin = $gethour . $getminutes;
$currentday = date("l", time());
$currentdate = date("M j, Y");
if ($hourmin < 1500 && $currentday <> "Saturday" && $currentday <> "Sunday") {
   echo "<span class=\"namesred\">$name8 </span>";
}
  else if ( $hourmin > 1500 && $hourmin < 2300 && $currentday <> "Saturday" && $currentday <> "Sunday") {
   echo "<span class=\"namesblue\">$name8 </span>";
  }
  else if ( $currentday == "Saturday" or $currentday == "Sunday") {
   echo "<span class=\"namesblue\">$name8 </span>";
  }
?>

PHP 5.2.6

We rent PHP server space on a server in California. Several of my pages generated by PHP show the current date and time, so when the page is printed, the user knows when the data was printed. Our users could be anywhere in the US, I am in Michigan. How do I convert the server time (PDT) into local time, regardless of where the user is?

Thanks.

OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time.

All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results...

Thanks.