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PHP - Add The User_id To The Random String
In the PHP script I'm using, in the Upload Form the user selects an image to Upload, the Form renames it like so:
$allowedExts = array("gif", "jpeg", "jpg", "pdf", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = strtolower( end($temp) );
if (!in_array($extension,$allowedExts))
{
echo ("Error - Invalid File Name");
}
$length = 20;
$randomString = (time());
$thumbnail = $randomString . "." . $extension;
The random string works successfully, but I'd like to add the user_id to the beginning of it and a dash, like this:
user_id -
So, the new file name would be something like: user_id-randomString.extension
Can you please help me add that?
Similar TutorialsHi guys, why am i getting this error: Illegal string offset 'user_id' but when echo $value it brings the correct output. Thanks
$user_id = 5;
$user_name = "obodo";
$_SESSION['test'] = array('user_id' => $user_id, 'user_name' => $user_name);
foreach( $_SESSION['test'] as $value )
{
echo $value['user_id']; //give error
/* echo $value //works */
}
Hey Guys, A very noob question...Here it goes: I want to update the field user_id on my database table, there a lot of rows that the user_id is the same... "testID", I just want to update only ONCE. mysql_query("UPDATE `users` SET status = '$StatusCheck' WHERE user_id = 'testID'"); Right now it's updating ALL the rows that have the user_id "testID". I just want to update only one. Any ideas? Thanks in advance! Cheers! Hi, I'm having trouble generating random string with 8 characters, when I refresh I sometimes get 6 characters and sometimes 8. "-" not included as character. Wrong: 6JW-F7W Correct: (should always generate random like this) DVMF-F36V I know I'm trying to achieve this in wrong methods but it's the only way I know. Hope someone can help. function getReference() { $length = 8; $characters = "0123456789abcdefghijklmnopqrstuvwxyz"; for ($p = 0; $p < $length; $p++) { $string .= $characters[mt_rand(0, strlen($characters))]; } return strtoupper(substr($string, 0, -$length/2)."-".substr($string, $length/2-1, -1)); } So I found this code from someone else on here who posted about creating a random string. I've copied the code for myself but when I upload php page to my server and view source... there is no php code. Essentially, i see no randomly generated text. what am i missing? Code: [Select] <?php function genRandomString() { $length = 5; $characters = array_merge(range(0,9),range('a','z'),range('A','Z')); $string = ""; for ($p = 0; $p < $length; $p++) { $string .= $characters[mt_rand(0, count($characters)-1)]; } return $string; } ?> Hey all, I'm looking to produce a random 10 character string like: abcABC0123 when the below method is called: <?php function randomize(){ $chars = explode(' ',(range("a","z"))) . explode(' ',(range("A","Z"))) . explode(' ',(range("0","9"))); $pass = ""; for($i = 0; $i < $len; $i += 1){ array_push($pass,$chars[rand(count($chars)-1)]); } return $pass; } var_dump(randomize(10)); ?> But the randomize method is not returning desired result. Any idea what I'm doing wrong? Thanks for response. i have to tables... forums & subscription i would like to insert a random character string into 'forums' to be used as a subscription id. and then have the same random string to be inserted into 'subscription' I'm looking for a function that creates a random string that contains random letters, numbers and symbols. Also it needs to generate it in a way that there are no repeating characters. Any ideas? currently using function gen_chars($length = 6) { // Available characters $chars = '0123456789abcdefghjkmnoprstvwxyz'; $Code = ''; // Generate code for ($i = 0; $i < $length; ++$i) { $Code .= substr($chars, (((int) mt_rand(0,strlen($chars))) - 1),1); } return $Code; } // Usage $var = gen_chars(12); echo $var; However ide like to know if theres a more efficient way of generating this since this is going to be using a lot. Thanks Hi everyone Well I've started learning php yesterday and now I encountered my first problem, I looked around but I don't really know what to search for if I want my answer so here I come Code: [Select] <html> <body> <?php $names = array('Peter','Quagmire','Joe'); $ages = array("Peter"=>32, "Quagmire"=>30, "Joe"=>34); $who = rand(0,2); $who2 = $names[$who]; echo "$names[$who] is $ages[$who2] years old"; ?> </body> </html> This is the script I have, and there is the kind of script I expected: Code: [Select] <html> <body> <?php $names = array('Peter','Quagmire','Joe'); $ages = array("Peter"=>32, "Quagmire"=>30, "Joe"=>34); $who = rand('Peter','Quagmire','Joe'); echo "$who is $ages[$who] years old"; ?> </body> </html> But after some search I concluded that rand is only used for random numbers So, my question is, which function should I use to achieve my goal? Is there any randstring('string1','string2',etc) command? Tnx for your time Hello everyone, I have this very short script I wrote with help from a book using arrays and the rand function. Basically it changes the images randomly on browser load or refresh. However, I am trying to add an additional, not sure what to call it, a string or another caption for each images. Instead of this being a caption, it will be a link, so a link will appear under each caption that goes to another page when it is clicked on. I tried adding another caption and adding a like to it but getting syntax error. Thanks everyone! Here is the code: Code: [Select] <?php $images = array( array('file' => 'image1', 'caption' => 'Caption 1'), array('file' => 'image2', 'caption' => 'Caption 2'), ); $i = rand(0, count($images)-1); $selectedImage = "graphics/{$images[$i]['file']}.png"; $caption = $images[$i]['caption']; ?> And here is where the images are written to the page: Code: [Select] <div id="stage"> <img src="<?php echo $selectedImage; ?>" alt="Random image" /> <p id="caption"><?php echo $caption; ?></p> </div> IC Hello, I've been racking my brains (and spending sleepless nights) trying to get a login system to work by where the member will insert their email address as [username] and password (already stored in the DB) - then the page to divert to an administration panel with their User_id for them to only edit their information. The Code I have so far..... The login_form.php Code: [Select] <?php //Start session session_start(); //Unset the variables stored in session unset($_SESSION['SESS_CLIENT_EMAIL']); unset($_SESSION['SESS_MAIN_ID']); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>Client Admin Panel</title> <link href="style.css" rel="stylesheet" type="text/css" media="screen" /> </head> <body> <div id="wrapper"> <div id="header"> <h1>CLIENT LOGIN</h1> <h2>CLIENT ADMINISTRATION PANEL</h2> version 2.10 </div> <div id="menu"> </div> <div id="content"> <div id="right"> <div class="post"> <h2>CLIENT ADMINISTRATION PANEL - CLIENT LOGIN</h2><br /> <h3><span class="err"><strong><font color="#800000">PLEASE LOGIN</font></strong></span></h3><form id="loginForm" name="loginForm" method="post" action="login-exec.php"> <table width="315" border="0" align="center" cellpadding="2" cellspacing="0"> <tr> <td width="150"><b>Email Address:</b></td> <td width="157"><input name="login" type="text" class="textfield" id="client_email" /></td> </tr> <tr> <td><b>Secret Word:</b></td> <td><input name="password" type="password" class="textfield" id="client_password" /></td> </tr> <tr bgcolor='#f1f1f1'> <td> </td> <td><input type="submit" name="Submit" value="Login" /></td> </tr> <tr> <td colspan="2"><hr /></td> </tr> <tr> <td><b>Forgot SecretWord?:</b></td> <td><font face='tahoma, arial, helvetica' size='2' ><a href='forgot-password.php'>Click Here</a></font></td> </tr> <tr> <td colspan="2"><hr /></td> </tr> <tr> <td><b>New Client?:</b></td> <td><font face='tahoma, arial, helvetica' size='2' ><a href='../dhsite/webpages/reg_1.php'> Register Here</a></font></td> </tr> </table> <br /> </form></p> </div> </div> </div> <div id="footer"> <p class="copyright">Copyright © *****************</p> </div> </div> </body> </html> And the handler: login_exec.php Code: [Select] <?php //Start session session_start(); $_SESSION['var'] = $val; //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $client_email = clean($_POST['login']); $client_password = clean($_POST['password']); //Input Validations if($client_email == '') { $errmsg_arr[] = 'Email Address missing'; $errflag = true; } if($client_password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } //Create query $qry="SELECT client_email, client_password, main_id FROM users WHERE client_email='$client_email' AND client_password='$client_password'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_CLIENT_EMAIL'] = $member['client_email']; $_SESSION['SESS_MAIN_ID'] = $member['main_id']; session_write_close(); header("Location: test_admin_panel.php?user_id=".$main_id.""); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?> Any help would be VERY much appreciated!! Hello all...fairly new to this php/mysql thing... working on my final project thats due in about 24 hours... and i hit a rut... im making a pretty basic, online classifieds site. users can sign up, login, post new listings and view others listings by clicking on different categories. the problem i am having right now is this...When the user clicks on "My listings" i need it to pull only the listings that were created by that users user_id, which is the primary key in my user_info table...my professor suggested storing it in hidden field through the login submit button...very confused and frustrated... any help is much appreciated... There is something wrong with my statement it is not returning sql queries results based on matching the url based based userid to match with the table user_id and get the Ablum id and Album name: Please hlep: Code: [Select] if(isset($_GET['userid'])) { $db =& JFactory::getDBO(); $user =& JFactory::getUser(); $id = $user->id; $album_id = $_GET['userid']; $query = 'SELECT user_id, id, format_id, year, name FROM #__muscol_albums WHERE user_id = ' . $album_id; //$query = 'SELECT user_id FROM #__muscol_albums WHERE id = ' . $album_id ; $result = mysql_query($query) or die('Error, No Album Search failed'); list($name, $user_id, $id, $year) = mysql_fetch_array($result); echo $id; //exit; } As above, I have a lottery style site that picks a random number between 1-8 but my users complain for some reason that this is not enough. So i was told to look into using fopen and random.org to generate a random number. Anyone have experience of this and perhaps a code snippet for me to look at and possibly use? help will be appreciated. Hi, I am trying to make some adjustments to uploadify.php which comes with the latest version of uploadify (3.0 beta), so that it works with a session variable that stores the login username and adds it to the path for uploads. Here is uploadify.php as it currently looks: Code: [Select] <?php session_name("MyLogin"); session_start(); $targetFolder = '/songs/' . $_SESSION['name']; // Relative to the root if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = $_SERVER['DOCUMENT_ROOT'] . $targetFolder; $targetFile = rtrim($targetPath,'/') .'/'. $_FILES['Filedata']['name']; // Validate the file type $fileTypes = array('m4a','mp3','flac','ogg'); // File extensions $fileParts = pathinfo($_FILES['Filedata']['name']); if (in_array($fileParts['extension'],$fileTypes)) { move_uploaded_file($tempFile,$targetFile); echo '1'; } else { echo 'Invalid file type.'; } } echo $targetFolder; ?> I added Code: [Select] echo $targetFolder; at the bottom so that I could make sure that the string returned was correct, and it is, i.e. '/songs/nick'. For some reason though, uploads are not going to the correct folder, i.e. the username folder, but instead are going to the parent folder 'songs'. The folder for username exists, with correct permissions, and when I manually enter Code: [Select] $targetFolder = '/songs/nick';all works fine. Which strikes me as rather strange. I have limited experience of using php, but wonder how if the correct string is returned by the session variable, the upload works differently than with the manually entered string. Any help would be much appreciated. It's the last issue with a website that was due to go live 2 days ago! Thanks, Nick Hey there, Thanks for taking the time to read my thread. My issue is that I can't think of a way to edit a XML file using PHP's XML functionality and then assign the edited contents to a string instead of saving the file. Because my issue is that I have to edit the XML file based upon a string brought from a remote location then give it back to that remote location using a string again, to be exact I am doing it via Linux command line utilizing SSH2. This is what I managed to complete on my own. function CheckIVMPConfig($ServerID) { global $Panel; if(is_numeric($ServerID) && $this->IsValidServer($ServerID)) { // We select the game server that the FTP account was created for. $Servers = mysql_query("SELECT * FROM control_servers WHERE server_id = '".mysql_real_escape_string($FTPAccount['ftp_server'])."'"); $Server = mysql_fetch_array($Servers); // Here we select the Box ID that the game server is on. $Boxs = mysql_query("SELECT * FROM control_machines WHERE machine_id = '".$Server['server_machine']."'"); $Box = mysql_fetch_array($Boxs); // Now we select the required package for the box. $Packages = mysql_query("SELECT * FROM control_packages WHERE package_id = '".$Server['server_package']."'"); $Package = mysql_fetch_array($Packages); // Retrive the file. $Config = $CProtocol->exec("cat /home/{$Server['server_id']}/{$Package['package_config']}"); $Parse = SimpleXMLElement($Config); foreach($Parse as $Entry) // loop through our books { if($Entry->port != $Server['server_port']) { // edit the value } else if($Entry->maxplayers > $Server['server_slots']) { // edit the value } } } } This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=326004.0 Hello all, I'm trying to change the end of a javascript call based on the end of the url string. The common part of all the url strings is sobi2Id=, I'm trying to do this with strstr but am having no luck. I'm new to php so my syntax knowledge is terrible! at the moment i've got Code: [Select] <?php $url = $_SERVER['REQUEST_URI']; $tag = strstr ($url, 'sobi2Id='); echo $tag; ?> but this returns an unexpected T_STRING, expecting ',' or ';' Can anyone debug this? I may well be being really silly! I have the following function, which takes a string with commas in it and attempts remove those commas. The way I have it here is that I use explode to take out the commas, which makes an array, and then iterate through that array to put a string back together without the commas. function tags_to_sort_by( $sortMeta ) { $sortByArray = explode(",", $sortMeta); $sortByCount = count($sortByArray); for ($i = 0; $i < $sortByCount; $i++) { $sortByString += $sortByArray[$i]; } return $sortByString; } What does not work is the following line: $sortByString += $sortByArray[$i]; Somehow that outputs a 0, which I don't understand. It should output something like: arrayItem1 arrayItem2 array3 etc. My question is if there either is an easier way to remove the commas from the original string or what I am doing wrong in this line: $sortByString += $sortByArray[$i]; // I am trying to concatenate each part of the array back into the string. Thanks a lot for help with this! |
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