PHP - Posted Copied Text

I need to echo back the users drop down selection.  How can  I do this without storing the value?

Code: [Select]
$isset = $_POST['industry'];

foreach ($industries as $industry)
{
if (isset($isset) && $industry['industry_id'] == $isset)
{
echo "<option value=\"{$industry['industry_id'] }\" selected=\"selected\">${industry['industry']}</option>\n";
}
else
{
echo "<option value=\"{$industry['industry_id'] }\">${industry['industry']}</option>\n";
}
}

Hi Friends,

I have form in that i am sending some values using POST method. But i cant able to get values using $_POST['var'] or $_REQEUST['var'] Data is not coming in IE6,

But it is coming in firefox and other browsers even in IE8.

What may be problem? any settings i have to make for IE6. ?

Any suggestions

How can I prioritize the data posted.  Right now this if statements are being posted at different times.  If I hit submit and all the if statements post to mysql it is saying that they all receive the same time stamp, but the data is never posted in the same order.  Can I order the posting process in php?

Code: [Select]
if ((isset($_POST['companywebsiteas'])) && ($_POST['companywebsiteas'] != $r['companywebsite']))
{
$details = $_POST['companywebsiteas'];
update_company_actions($info['companyid'], 18, $details);
}

if ((isset($_POST['companyindustryas'])) && ($_POST['companyindustryas'] != $info['industry']))
{
$details = $_POST['companyindustryas'];
update_company_actions($info['companyid'], 17, $details);
}

if ((isset($_POST['companystageas'])) && ($_POST['companystageas'] != $info['stage']))
{
$details = $_POST['companystageas'];
update_company_actions($info['companyid'], 10, $details);
}

if ((!isset($_POST['companystateas'])) && (($_POST['companycountryas'] != $info['country']) || ($_POST['companycityas'] != $info['city'])))
{
$details = $_POST['companycityas'].', '.$_POST['companycountryas'];
update_company_actions($info['companyid'], 11, $details);
}
else if ((isset($_POST['companystateas'], $_POST['companycityas'])) && (($_POST['companystateas'] != $info['state']) || ($_POST['companycityas'] != $info['city'])))
{
$details = $_POST['companycityas'].', '.$_POST['companystateas'];
update_company_actions($info['companyid'], 11, $details);
}

How can I echo the $id?  Every time I post approved it refreshes my page and I can see the echoed out ID.  I need to know what the ID value is.
Code: [Select]
if (isset($_POST['approve']))
{
if(is_array($_POST['approve'])) {
$keys = array_keys($_POST['approve']);
$id = $keys[0];

echo $id;
die();
//$sql = "UPDATE `blog_comments` SET `approved` = 1 WHERE `post_id` = '$id'";
//header("Location: " . $_SERVER['PHP_SELF'] . "?" . $_SERVER['QUERY_STRING'] );
}
}

Hi, I only want to display some included PHP code only if a value is displayed from  form input. The value is a zip code which is used to display weather information, but the app produces an error when you first enter the page, because their is no value for the zip variable. I know I need an if/else statement, but not sure what to put in it.

The form code is this

<h3>Enter your zip code to receive weather info.</h3>
             <form method="post" action="<?php echo $PHP_SELF;?>">
Enter Zip Code:<input type="text" size="12" maxlength="12" name="zip"><br /> 
<input id="submit" type="submit" name="Submit" value="Enter Zip"/>

</form>

<?php


// this is how we bring in the weather file

include 'weather_report.php' 

?>


the zip variable is set-up in the weather_report.php file as follows

$zip = $_POST["zip"];


but like I said until that value is set, an error is thrown by the weather app code.

I need some help displaying the posted values onto a second page. I thought I was doing it right, but nothing is showing up on my second page. I have my form set to PHP_SELF to validate before sending the user to the second page, and it's working just fine. If no errors are present, the user is redirected to the second page, but it's supposed to be displaying their posted data, but it's not. What am I doing wrong?

Code: [Select]
<?php

/*$name = "";
$address = "";
$city = "";
$state = "";
$zip = "";
$phone = "";
$position = "";
$display_errors = "";*/ 

if (@$_POST['submitted']){
    $name = (@$_POST['name']);
    $address = (@$_POST['address']);
    $city = (@$_POST['city']);
    $state = (@$_POST['state']);
    $zip = (@$_POST['zip']);
    $phone = (@$_POST['phone']);
    $position = (@$_POST['position']);
    
    if (get_magic_quotes_gpc()){
        $name = stripslashes($name);
        $address = stripslashes($address);
        $city = stripslashes($city);
        $state = stripslashes($state);
        $zip = stripslashes($zip);
        $phone = stripslashes($phone);
        $position = stripslashes($position);
        
    }
    
    $error_msg=array();
    if ($name==""){
        $error_msg[]="Please enter your name";
    }
    
    if ($address==""){
        $error_msg[]="Please enter your address";
    }
    
    if ($city==""){
        $error_msg[]="Please enter your city";
    }
    
    if ($state==""){
        $error_msg[]="Please enter your state";
    }
    
    if ($zip==""){
        $error_msg[]="Please enter your zip code";
    }
    
    if ($phone==""){
        $error_msg[]="Please enter your phone number";
    }
    
    if ($position==""){
        $error_msg[]="Please enter your desired position";
    }
    
    if ($error_msg){
        $display_errors =  "<ul style=color:red>\n";
            foreach ($error_msg as $err){
                $display_errors .= "<li>".$err."</li>\n";
            }
        $display_errors .= "</ul>\n";
        
    }
    
    if (!$error_msg){
        //echo $name . "<br>";
        //echo $address . "<br>";
        //echo $city . "<br>";
        //echo $state . "<br>";
        header('Location: process_U2IP.php');
        exit();
    }
    
    }
    
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Forms1.php</title>
</head>
<body>
<div id="content">
<form action="<?php $_SERVER['PHP_SELF']; ?>" method="post">
<h3>Please fill out the form below and upload your resume to apply for a position within our company:</h3>

<label for="name">Name*</label><br />
<input name="name" type="text" size="20" id="name" value="<?php echo $name; ?>" /><br />

<label for="address">Address*</label><br />
<input name="address" type="text" size="20" id="address" value="<?php echo $address; ?>" /><br />

<label for="city">City*</label><br />
<input name="city" type="text" size="20" id="city" value="<?php echo $city; ?>" /><br />

<label for="state">State*</label><br />
<input name="state" type="text" size="20" id="state" value="<?php echo $state; ?>" /><br />

<label for="zip">Zip*</label><br />
<input name="zip" type="text" size="20" id="zip" value="<?php echo $zip; ?>" /><br />

<label for="phone">Phone*</label><br />
<input name="phone" type="text" size="20" id="phone" value="<?php echo $phone; ?>" /><br />

<label for="position">Position*</label><br />
<input name="position" type="text" size="20" id="position" value="<?php echo $position; ?>" /><br />

<p><i>Your information will not be sold or shared with others.</i></p>

<p style="color: red;">* denotes required field</p>

<input type="hidden" name="submitted" value="1" />

<input type="submit" value="Submit" />
<input type="reset" name="reset" value="Reset" />
</form>

<?php echo $display_errors; ?>
</div>
</body>
</html>

Code: [Select]
<?php

$name = (@$_POST['name']);
$address = (@$_POST['address']);
$city = (@$_POST['city']);
$state = (@$_POST['state']);
$zip = (@$_POST['zip']);
$phone = (@$_POST['phone']);
$position = (@$_POST['position']);

$display_block = "
<table>
<tr>
<td><b>Name:</b></td>
<td>$name</td>
</tr>
<tr>
<td><b>Address:</b></td>
<td>$address</td>
</tr>
<tr>
<td><b>City:</b></td>
<td>$city</td>
</tr>
<tr>
<td><b>State:</b></td>
</tr>
</table>";

echo $display_block;
  
?>

It's just displaying the table but with no values or blank values for the posted variables. Can anyone help?

Hi everyone,   I've been running a self-written php shopping cart for the last 8 years, with lots of success.  Recently however, the credit card processor (Linkpoint) I use upgraded their gateway, and now I have a problem.   Basically, the last page of my checkout does a _POST to a specific url for their gateway.  I send through a bunch of <input> variables, some of them hidden, but all of them check out okay.  I have combed over their specs, made sure I'm not sending any bad characters, made sure I've got the right format for the fields they want, etc...    Right now the transaction is successful, the customer's card is charged, but Linkpoint's system is returning an error message: We are unable to process your request due to invalid data.   Long story short, their support staff has asked me to "send them the xml string" via email.  I have no idea how to do this (even after spending a few hours online trying to figure it out).   Is there a simple way to generate the xml string that's being passed during the _POST?  Some kind of php code I can incorporate into my final checkout page, run a test transaction, and maybe write the string out somewhere so I can get it to them?   Any help you guys could give me would be greatly appreciated.  Thanks in advance!
Danny  

To anyone,

Apache 2.2.21/PHP5.3.5/MySQL 5.2.36.  The following code returns the below errors.  I am trying to get the POSTed values into MySQL.  There are no other errors.  It's like the code stopped at the ?> closing statement.  Why would the code not return the 'echo' statements? 

Any ideas?????  Much appreciated....Buchberg

Notice: Use of undefined constant id - assumed 'id' in C:\website\do_addrecord_auth_users.php on line 2

Notice: Undefined index: id in C:\website\do_addrecord_auth_users.php on line 2

<?
if ((!$_POST[id]) || (!$_POST[f_name]) || (!$_POST[l_name]) ||
(!$_POST[username]) || (!$_POST[password]) || (!$_POST[firm]) || (!$_POST[email])) {
("Location: /show_addrecord_auth_users.html");
exit;
}
$db_name="booster";
$table_name="auth_users";
$connection=mysql_connect("localhost", "username", "password") or die (mysql_error());
$db=mysql_select_db($db_name, $connection) or die (mysql_error());
$sql="INSERT INTO $table_name
(id, f_name, l_name, username, password, firm, email) VALUES
('$_POST[id]', '$_POST[f_name]', '$_POST[l_name]', '$_POST[username]',
'$_POST[password]', '$_POST[firm]', '$_POST[email]')";
$result=mysql_query($sql, $connection) or die (mysql_error());
?>
<HTML>
<HEAD>
<TITLE>Add a record to Auth Users</TITLE>
</HEAD>
<BODY>
<H1>Adding a record to <? echo "$table_name"; ?></H1>
<TABLE CELLSPACING=3 CELLPADDING=3>
<TR>
<TD VALIGN=TOP>
<P>id<BR>
<? echo "$_POST[id]"; ?></P>
</TD>
<TD VALIGN=TOP>
<P>First Name<BR>
<? echo "$_POST[f_name]"; ?></P>
</TD>
<TD VALIGN=TOP>
<P>Last Name<BR>
<? echo "$_POST[l_name]"; ?></P>
</TD>
<TD VALIGN=TOP>
<P>Username<BR>
<? echo "$_POST[username]"; ?></P>
</TD>
<TD VALIGN=TOP>
<P>Password<BR>
<? echo "$_POST[password]"; ?></P>
</TD>
<TD VALIGN=TOP>
<P>Firm<BR>
<? echo "$_POST[firm]"; ?></P>
</TD>
<TD VALIGN=TOP>
<P>email<BR>
<? echo "$_POST[email]"; ?></P>
</TD>
<P><a href="show_addrecord_auth_users.html">Add Another</a></P>
</TD>
</TR>
</TABLE>
</BODY>
</HTML>

Here there,   This is a post for all of you ajax/php pimps who don't mind helping a beginner.  I have been working on a little ajax script to filter a table called "recipes2" in a database called "recipes" using a dropdown menu. Once I get this script to work, I can run queries without having to refresh the page.     The problem, something is not right, the php script does not seem to be getting the posted data. even though the ajax script returns success when i check for it.  What am I doing wrong?     Also please note that, if possible, I'd like all the code to stay on one page.    This is the SQL script if you want to create the database and table:     [attachment=3349:recipesDB.txt]   Here is the code, the file should be named 'filterRecipes.php'.  [attachment=3350:filterRecipes.txt]

<?php 

include("add_p2.php");




//basic pdo connection (with added option for error handling)

if (isset($_POST['submit'])) {
    try {




$stmt = $dbh->prepare("INSERT INTO passwords (description, username, password ) VALUES (:description, :username, :AES_ENCRYPT)");
$stmt->bindParam(':description', $description);
$stmt->bindParam(':username', $username);
$stmt->bindParam(':password', $password); 


	try {
    $statement->execute(array(
       "description" => "description",
       "username" => "username",
       "password" => "password"
    ));
} catch(PDOException $e) {
    echo "Exception caught: $e";
}	


//insert one row
$name = 'one';
$value = 1;
$stmt->execute();


header( 'Location: localhost/password_added.php' ); exit();


?>

<?php

$dsn = "mysql:host=127.0.0.1;dbname=pword_db;charset=utf8";
$opt = array(
    PDO::ATTR_ERRMODE            => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
$pdo = new PDO($dsn,'root','', $opt);


?>

<form action="add_p.php" method="post">
	<span class="cursive">Description:	</span><br>
	<textarea name="description" rows="20" cols="50"></textarea>
	<br>
	<span class="cursive">Username:	</span><br>
	<input type="text" name="username" />
	<br>
	<span class="cursive">Password:	</span><br>
	<input type="text" name="password" />
	<br>
	<input type="submit"/>
	</form>

    Hi,   above is the 3 components that should add form data into MySQL database using PDO.   all it's doing is entering empty values, I'm really not sure why this is?   please could someone help me with pointing me in the right direction, offer hint's making this work         Thanks                     Attached Files  PHPmyadmin.JPG   64.83KB   0 downloads

I have a basicc form that takes users info and when they submit it it show on a new web page in the proper order. I need to know how do I skip a blank field. This form takes a users First, Middle, and Last name but many times they leave the middle name blank so I would want to skip this field from showing up when the form is posted. Here is what I have for the basic php script ..Would like to know how to skip a field if it is left blank on the form.
 
echo $_POST["First"], print "."; ?><?php echo $_POST["Middle"], print "."; ?><?php echo $_POST["Last"], print "."; ?><?php echo $_POST["Persona1"], print ".";<br />

Hi,

I have a feeling that this is going to be an easy miss but I've been over is a good few times and cannot see what it could be. Essentially, when I post the form in the first set of code (I've got rid of a load of unecessary html) the SESSION variables are not loaded into the second piece of code. Any ideas?

Code: [Select]
<?php 
session_start();
require ("connect.php");
$timeout = 1800;
$logout_redirect_url = "login.php";
if (isset($_SESSION['start_time'])) {
    $elapsed_time = time() - $_SESSION['start_time'];
    if ($elapsed_time >= $timeout) {
        session_destroy();
        header("Location: $logout_redirect_url");
    }
}
$_SESSION['start_time'] = time();
?>

<div id="leftlink">
<a href="logout.php">Logout</a>
</div>
<table align="center" width="600px" cellpadding="0" cellspacing="0">
<tr>
<td>
<h2 align="center"><a href="index.php"><img src="images/logo.jpg" border="0" /></a> <br />  Emergency</h2>
  <hr />
  </td>
  </tr>
</table>
</head>
<body>
<form action="post_reset.php" method="post" name"passre">
<table width="500" border="0" align="center" cellpadding="2" cellspacing="1">
  <tr>
    <td width="230"><div align="right">E-mail Address : </div></td>
    <td width="40">&nbsp;</td>
    <td width="230"><div align="left">
<input name="email" readonly="readonly" value="<?php echo ($_SESSION['email']) ; ?>" /></div></td>
  </tr>

  <tr>
    <td colspan="3"><div align="center"><input type="submit" name="submit" value="Submit" /></div></td>
  </tr>
</table>
</form>
</body>
</html>
Code: [Select]
<?php
session_start;
echo ($_SESSION['start_time']);
require ("connect.php");

if (isset($_POST['submit'])){
$email = $_POST['email'];
$getde = "SELECT * FROM users WHERE email = '$email'";
$getder = mysql_query($getde, $conn);
$getdere = mysql_fetch_array($getder)

Thanks
Gareth

hi there,

basically in my database i have  DATETIME for when an article was posted, using this, I'd like to make it possible for viewers of the article to see when it was posted in a "Posted Today", "Posted Yesterday" or Posted 23 hours ago" format. If it was posted longer ago than yesterday, then I would like it to just be the normal date.

I know how to work out if it was posted today, just through:

$date = date('j F', strtotime($rows['date']));
$today=date('j F');

but not sure how to do the hours.

thanks!

this code is to create a new user based on posted variables. it works fine for creating the necessary tables and granting privileges. but then when i log out as root and try to log back in as the user it's failing. why is it failing? Thanks, G.

Code: [Select]
<?php
extract( $_POST );
include( '../php/userobject.php' );

@ $db = mysqli_connect('localhost', 'root', 'xxxxxx', 'mealchamp');
if ( mysqli_connect_errno() ) {
echo 'Error: could not connect to database as root.<br />';
exit;
}
else
echo 'Connected to database as root.<br />';

$query = "SELECT username FROM userlist WHERE username = $uname";
$result = mysqli_query($db, $query);

if ($result) 
echo 'That user name is already taken.<br/>Please hit back on your browser, and try a different user name.<br/>';
else {
echo 'That username is available.<br/>';
echo "$fname<br/>";
echo "$lname<br/>";
echo "$add1<br/>";
echo "$add2<br/>";
echo "$city<br/>";
echo "$prov<br/>";
echo "$ctry<br/>";
echo "$post<br/>";
echo "$email<br/>";
echo "$uname<br/>";
echo "$pass1<br/>";
echo "$sex<br/>";
echo "$birth<br/>";
echo "$height<br/>";
echo "$weight<br/>";

$query = "INSERT INTO userlist 
(firstname, lastname, address1, address2, city,  province, country, postal, email,  username, password, sex,  birth,  height,  weight) VALUES
('$fname', '$lname', '$add1', '$add2', '$city','$prov', '$ctry', '$post','$email','$uname', '$pass1', '$sex', '$birth', '$height',  '$weight')";
$result = mysqli_query($db, $query);
if ($result)
echo "Userlist was updated successfully<br />";
else
echo "Could not update userlist";

$query = "CREATE TABLE ".$uname."_persfood  
(persfoodid  INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
 food   VARCHAR(30) NOT NULL)";
$result = mysqli_query($db, $query);
if ($result)
echo "Personal food table was created successfully<br />";
else
echo "Could not create personal food table<br />";

$query = "GRANT select ON mealchamp.userlist TO ".$uname." IDENTIFIED BY '$pass1'";
$result = mysqli_query($db, $query);
if ($result)
echo "User priveleges were granted successfully<br />";
else
echo "Could not grant user priveleges<br />";
$query = "GRANT select, insert, update, delete, index ON mealchamp.".$uname."_persfood TO ".$uname." IDENTIFIED BY '$pass1'";
$result = mysqli_query($db, $query);
if ($result)
echo "User priveleges were granted successfully<br />";
else
echo "Could not grant user priveleges<br />";

mysqli_close($db);

@ $db = mysqli_connect('localhost', $uname, $pass1, 'mealchamp');
if ( mysqli_connect_errno() ) {
echo 'Error: could not connect to database as user.<br />';
exit;
}
else {
echo 'Connected to database as user.<br />';
?>