PHP - Session Variable Page 2 (mac-adres From $post Page 1) Lost On Page 3

Hi everyone, as the title stated, I would like to know how I could submit a form in one page(cart) and unset a session variable on other page.   Right now my form is setting a variable within the page back to 0, however I would like the form to unset the session variable from other page as well.   The issue with my code is that every time I attempt to clear out all items, my code can empty out the cart. But whenever I close and reopen the cart, the same content will show up again. So I need to unset the session variable.   Please let me know what should I do in order to solve the problem and I greatly appreciate your help.   My code is currently looking like this: cart.php

if(!empty($_GET['aID']))
{	
$aID = $_GET['aID'];
echo $aID;
if(isset($_POST['removeAll']))
{
$aID = "0";
}
$cartSQL = "SELECT * from article where aID in ($aID)";
echo "cart sql :$cartSQL";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
	$aTitle[] = $row[ 'name' ];
}
}
<form action = "" method = "POST">
<td style = "width = 200px"><input type="submit" value="Empty cart" name="removeAll"></td>
</form>

And this is the session variable from other page where I would like it to be unset upon submitting the form.

if(!empty($cartSubmit))
	$_SESSION["cartSubmit"] = $cartSubmit;
else	
	$cart = $_SESSION["cartSubmit"];

<a href="javascript:popup('cart.php?aID=<?php if(empty($cartSubmit)) echo "$cart"; else echo "$cartSubmit";?>')">Cart</a>

Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way.

First set up everything for DB:

<?php
//connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//create the main database if it doesn't already exist
$query = 'CREATE DATABASE IF NOT EXISTS moviesite';
mysql_query($query, $db) or die(mysql_error($db));

//make sure our recently created database is the active one
mysql_select_db('moviesite', $db) or die(mysql_error($db));

//create the movie table
$query = 'CREATE TABLE movie (
        movie_id        INTEGER UNSIGNED  NOT NULL AUTO_INCREMENT,
        movie_name      VARCHAR(255)      NOT NULL,
        movie_type      TINYINT           NOT NULL DEFAULT 0,
        movie_year      SMALLINT UNSIGNED NOT NULL DEFAULT 0,
        movie_leadactor INTEGER UNSIGNED  NOT NULL DEFAULT 0,
        movie_director  INTEGER UNSIGNED  NOT NULL DEFAULT 0,

        PRIMARY KEY (movie_id),
        KEY movie_type (movie_type, movie_year)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die (mysql_error($db));

//create the movietype table
$query = 'CREATE TABLE movietype (
        movietype_id    TINYINT UNSIGNED NOT NULL AUTO_INCREMENT,
        movietype_label VARCHAR(100)     NOT NULL,
        PRIMARY KEY (movietype_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

//create the people table
$query = 'CREATE TABLE people (
        people_id         INTEGER UNSIGNED    NOT NULL AUTO_INCREMENT,
        people_fullname   VARCHAR(255)        NOT NULL,
        people_isactor    TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,
        people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,

        PRIMARY KEY (people_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Movie database successfully created!';
?>



********************************************************************
***********************************************************************

second file to load info into DB:



<?php
// connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//make sure you're using the correct database
mysql_select_db('moviesite', $db) or die(mysql_error($db));

// insert data into the movie table
$query = 'INSERT INTO movie
        (movie_id, movie_name, movie_type, movie_year, movie_leadactor,
        movie_director)
    VALUES
        (1, "Bruce Almighty", 5, 2003, 1, 2),
        (2, "Office Space", 5, 1999, 5, 6),
        (3, "Grand Canyon", 2, 1991, 4, 3)';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the movietype table
$query = 'INSERT INTO movietype
        (movietype_id, movietype_label)
    VALUES
        (1,"Sci Fi"),
        (2, "Drama"),
        (3, "Adventure"),
        (4, "War"),
        (5, "Comedy"),
        (6, "Horror"),
        (7, "Action"),
        (8, "Kids")';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the people table
$query  = 'INSERT INTO people
        (people_id, people_fullname, people_isactor, people_isdirector)
    VALUES
        (1, "Jim Carrey", 1, 0),
        (2, "Tom Shadyac", 0, 1),
        (3, "Lawrence Kasdan", 0, 1),
        (4, "Kevin Kline", 1, 0),
        (5, "Ron Livingston", 1, 0),
        (6, "Mike Judge", 0, 1)';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Data inserted successfully!';
?>



**************************************************************
****************************************************************

MY CODE FOR THE QUESTION:


<?php
$db = mysql_connect('localhost', 'root', '000') or
die ('Unable to connect. Check your connection parameters.');

mysql_select_db('moviesite', $db) or die(mysql_error($db));

//get our starting point for the query from the URL
if (isset($_GET['offset'])) {
   $offset = $_GET['offset'];
} else {
   $offset = 0;
}

//get the movie
$query  = 'SELECT
   movie_name, movie_year
FROM
   movie
ORDER BY
   movie_name
LIMIT ' . $offset . ' , 1';
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
?>
<html>
<head>
<title><?php echo $row['movie_name']; ?></title>
</head>
<body>
<table border = "1">
<tr>
<th>Movie Name</th>
<th>Year</th>
</tr><tr>
<td><?php echo $row['movie_name']; ?></td>
<td><?php echo $row['movie_year']; ?></td>
</tr>
</table>
<p>
<a href="page.php?offset=0">Page 1</a>,
<a href="page.php?offset=1">Page 2</a>,
<a href="page.php?offset=2">Page 3</a>
</p>
</body>
</html>

Hi

I need some help.
I wanted to create a start and end event date using date picker and also after selecting the start and end date, it will calculate the number of days (duration).
I have found the date picker which can do what I want but I need help to post the duration to another php page when user click on submit.

Can anyone help me.
You might want to refer to my attach PHP page and here is the link to the datepicker, http://www.kelvinluck.com/assets/jquery/datePicker/v2/demo/datePickerStartEnd.html

Thanks
Ben Chew

[attachment deleted by admin]

lets say I have two pages:

Code: [Select]
one.php

Code: [Select]
two.php
Now with that in mind, is there a way for page one.phpto automatically post values to page two.php viathe $_POST variable?

I want my form to POST to the same page, but not have the 'document expired' problem when sessions are being used somewhere in the script (when I hit press the back button in the browser). I know this can be avoided by posting to a different PHP page, and then use a header(location) to redirect, but I ideally want to keep it on the same page as I use some of the variables produced from within the processing section.    Please excuse the crude examples,   This works:

session_start();

/*HEADER*/
if(isset($_POST['test']){
    
    //do some validation
    $validated= true;
    
    if($validated){
        //process the form
        $_SESSION['notification'] = 'form submitted successfully';
        header('location: samepage.php');
        exit;
    }
    else{
        $_SESSION['notification'] = 'there was an error';
        header('location: samepage.php');
        exit;
    }
}

/*BODY*/
if(!isset($_SESSION['notification'])){
     //show the form.. posts 'test' to current page
}
else {
    echo $_SESSION['notification'];
    unset($_SESSION['notification']);
}

And this method shows the document expired when the page is refreshed...

session_start();

/*HEADER*/
if(isset($_POST['test']){
    
    //do some validation
    $validated= true;
    
    if($validated){
        //process the form
        $success = true;
    }
    else{
        $success = false;
    }
}

/*BODY*/
if(!isset($success)){
     //show the form.. posts 'test' to current page
}
else if($success){
     echo 'form submitted successfully';
}
else{
     echo 'there was an error';
}

I've read that I can edit the php.ini file to allow caching, which should solve the issue for example 2.   Is example 1 the correct way to be doing this? It's been pointed out that I shouldn't be using 'exit' so much so I'm trying to explore the correct methods
Edited by paddy_fields, 31 July 2014 - 07:04 AM.

I have my php pages set up like this:

1. log in with login.php

2. that sends you to main.php

3. in main.php, there are links to page-a.php, page-b.php, page-c.php, etc.

when you type in a password at login.php, it passes your input to main.php.

the correct password is hardcoded in main.php. if it matches, a session variable is set, which should be able to be used on page-a.php, page-b.php, page-c.php, etc. to verify that whoever accesses those pages has gone through the login process. if the session variable doesn't match (or null) the user is redirected to the login page.

also the session variable is checked (recursively) when accessing main.php, just like the other pages.

the problem is, it's as if each page starts over. the session variable does not make it beyond the page that sets it. it should be passed on to the next page but it's not.

I used an echo statement in page-a.php to verify and rem'd out the rest of the code. no echo because session value is null, page goes on to load the html. without the code rem'd out it redirects the user to login.php.

code:

LOGIN.PHP
<?
session_start();  
if(isset($_SESSION['aaa']))
unset($_SESSION['aaa']); 
?>
<html>
<head>
<title>title</title>
</head>
<body>
<table width="400" align="center" border="0" bordercolor="#000099" bordercolordark="#000066" bordercolorlight="#6666FF">
  <tr bgcolor="#B0C4DE"> 
    <td> 
      <form action="main.php" method="POST">
        <p align="center"><strong><font size="2" face="Verdana, Arial, Helvetica, sans-serif" color="#FFFFFF"><br>
          Password</font></strong> 
          <input name="pwfield" type="password" value size="20" maxlength=20>
<input type="submit" value="Login"></p>
      </form>
    </td></tr></table>
</body></html>

MAIN.PHP
<?
if ($_SESSION['aaa']!="abcdef")
{
$password="twinkies";
if ($_POST["pwfield"]==$password)
$_SESSION['aaa']="abcdef"; // successful login
else 
{header("Location: login.php"); exit();}
}
?> 
<html>
<head>
<title>title</title>
</head>
<body>
<a href="page-a.php">Page A</a>
<a href="page-b.php">Page B</a>
<a href="page-c.php">Page C</a>
</body></html>

PAGE-A.PHP
<?
echo $_SESSION['aaa'];
//if ($_SESSION['aaa']!="abcdef")
//header("Location: login.php");
//exit();
?>
<html>
<head>
<title>title</title>
</head>
<body>
...

Hi,
I have a user/password protected page that displays a list of clients.
When clicking on them you're redirected to the client record update page. This is how I am linking to taht page now:
Code: [Select]
<a href="DIST_clientes_update.php?id_cliente=<?php echo $row_clients_RS['id_cliente']; ?>The problem with this is that the client id is appended to the url and so if the user chnges it will be able to access records from a different user...and I dont want that.
So I have created a session:
Code: [Select]
$_SESSION["idCliente"] = $row_clients_RS['id_cliente'];but how do I pass it to the update page without showing in the url?
Thanks

Hi. I have problem and I would like to know if anyone here has any ideas on how to fix it.

My home page is where my log in form resides. If I leave the home page to browse other pages of my site I want to stay logged in. However, when I return to the home page I see the log in form. The log in form should not be there if I already logged in. Instead I should see the welcome message. Which does appear after loggin in but does not stay on the home page when I leave the page and come back.
Code: [Select]
<?php
//Starts the PHP Sesssion
session_start();
//Includes the MYSLQ Connection Info from another PHP Page
include ('spartacus_mysql.php');
//Submits Log In Info to Database and encrypts Password
if (isset ($_POST['loginsubmit'])) {
$username = mysql_escape_string($_POST['username']);
$userpassword = mysql_escape_string(md5($_POST['userpassword']));

if (!empty ($username) && !empty ($userpassword)) {
//Runs Query to Selects the Username and Password from the Database
$sql = mysql_query ("SELECT * FROM users
WHERE username='".$username."' AND userpassword='".$userpassword."' LIMIT 1");
//Finds and Matches the Log In Info from the Database to the one submitted
if(mysql_num_rows ($sql) > 0) {
$_SESSION['loggedin'] = true;
$_SESSION['username'] = $username;
//Runs This Message if the right Username/Password is entered
echo
'<div id="welcome_member">
Welcome,&nbsp; '.$_SESSION['username'].'.<br />
You are now logged in!<br/>
The Combat Tips and Downloads is now accessible!<br />
Enjoy!<br />
</div>';
} else {
//Runs This Error if the Username/Password do not match the Database 
echo '<div id="welcome_member">
Your username and/or password is incorrect! <a href="spartacus_home.php">Try Again</a>
</div>';
}
} else {
//Runs This Code if the Log In Form is Left Blank
echo '<div id="welcome_member">
You must enter a username and a password! <a href="spartacus_home.php">Try Again</a> 
or <a href="spartacus_joinsite.php">Register</a>
</div>';
}
} else {
//This is the code for the Log in Form
echo'<div id="join">
<a href="spartacus_joinsite.php">{ JOIN! }</a><br />
</div>
<div class="signin">
<div id="titles">
{ SIGN IN }
</div><br />
<form method="post" action="spartacus_home.php">
<table>
<tr><td>
Username: <input type="text" name="username" />
</td></tr>
<tr><td>
&nbsp;Password: <input type="password" name="userpassword"/>
</td></tr>
<tr><td>
<input class="submit" name="loginsubmit" type="submit" />
</tr></td>
</table>
</form>
</div>';
}
?>
<!--end sign in PHP-->

Here is my code

hey guys

i'am newb in php and i'am doing some algorithm in php, in some codes i need to use session but in that particular page the code does not know if session_start() has been called or not.
wonder to if there is anyway that i can get if session is started or not in my code?

thanks in advance

I'm building a login page that then redirects to a new page. But it seems the session isn't working. But I don't know much about sessions, so I'm not sure what I might be doing wrong.

The login page sets the session with this code:
Code: [Select]
// Fetch the result - This will tell us whether this user exists
      $userExists = mysql_fetch_assoc($doQuery);

      // If user exists log them in
      if($userExists){
        mysql_free_result($doQuery);
        mysql_close();

        // Set the SESSION variables

        $_SESSION['first_name'] = $userExists['first_name'];
        $_SESSION['id']         = $userExists['id'];

The page that it redirects to is this:
Code: [Select]
<?php 
session_start();
if(isset($_SESSION['id'])) {
      echo "<html><body><p> You are now logged in,{$_SESSION['ID']}.</p>"; 
      } else { 

echo 'something went wrong';
       exit(); 
       }
ob_end_flush();

?>

When a person visits my site I would like for the form on the page to submit and reload with the predetermined search criteria.  Is this possible?

So for example...if you visited my site as soon as you entered the from would submit and display Google search results for "php freaks"

I tried header("location: mysite.com?q=php+freaks"); but that is a continuous loop.



-Any thoughts

Hello,
I've been hacking at this for about 5 hours, and have been unable to get my session data to pass through to the 3rd page. Here is my code. As you can see I've been trying all types of variation of retrieval. On page 2 I can pull the data from page 1 fine with REQUEST or the longer version.. But for some reason page 3 will not display the first_name and last_name... I'm desperate at this point. I have not been able to find a working answer. I'm running php 5 w/ trans... OFF (default) in .ini.

Page 1
Code: [Select]
<?php session_start(); ?>
<?php
$PHPSESSID = session_id();
echo "<strong>Session ID:</strong> $PHPSESSID"; "<br /><br />";
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>0</title>
</head>
<body>
<form method="post" action="multi_page_post_2.php">
<label>First Name</label>
<input name="first_name" value="" width="50" type="text" />
<br /><br />
<label>Last Name</label>
<input name="last_name" value="" width="50" type="text" />
<br /><br />
<input type="submit" name="submit" value="Enter your Data - Continue to Step 2 >>" />
</form>
</body>
</html>
Page 2
Code: [Select]
<?php session_start(); ?>
<?php
$PHPSESSID = session_id();
echo "<strong>Session ID:</strong> $PHPSESSID";
$first_name = $_REQUEST['first_name'];
echo $first_name;
?>
<?php echo "<br /><br />"; print_r($_SESSION); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Step 2</title>
</head>
<body>
<h2>Step 2 - Is this data correct?</h2>
<hr />
<strong>First Name:</strong> <?php echo $_SESSION['first_name'] = $_POST['first_name']; ?>
<br /><br />
<strong>Last Name:</strong> <?php echo $_SESSION['last_name'] = $_POST['last_name']; ?>
<br /><br />
<form method="post" action="multi_page_post_3.php">
<label>Sons First Name: </label>
<input name="sons_first_name" value="" width="50" type="text" />
<br /><br />
<input type="submit" name="submit" value="YES! Continue to Step 3 >>" />
&nbsp;
<input type="hidden" name="PHPSESSID" value="<?php echo $PHPSESSID ?>" />
<input type="button" value="No! Back to Previous Page" onClick="javascript: history.go(-1)">
</form>
<br /><br />
<a href="" onclick="<?php session_destroy(); ?>">Session D E S T R O Y !</a>
</body>
</html>

Page 3
Code: [Select]
<?php session_start(); ?>
<?php
$PHPSESSID = session_id();
echo "<strong>Session ID:</strong> $PHPSESSID";
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Step 3</title>
</head>
<body>
<h2>Step 3 - Is this data correct?</h2>
<hr />
<strong>First Name:</strong> <?php echo $_SESSION['first_name'] = $_REQUEST['first_name']; ?>
<br /><br />
<strong>Last Name:</strong> <?php echo $_SESSION['last_name']; ?>
<br /><br />
<strong>Sons First Name:</strong> <?php echo $_REQUEST['sons_first_name']; ?>
<br /><br />
<form method="post" action="multi_page_post_4.php">
<input type="hidden" name="PHPSESSID" value="<?php echo $PHPSESSID ?>" />
</form>
<br /><br />
<a href="" onclick="<?php session_destroy(); ?>">Session D E S T R O Y !</a>
</body>
</html>

Hi Everyone,

I wonder if somebody could help me. I have been at this for hours and am really struggling.

I have a timer which I have set up for a quiz.  The quiz opens in a javascript shadow box.  When the quiz is opened a session variable for the timer is set up to keep track of the time. 

What I need is for this session variable to end when the shadow box is closed. I have a onClose hook to peform actions when the shadow box is closed which is in javascript.

Obviously I cannot end the session variable in the javascript function due to js being client side and php being server side.

Has anyone any suggestions how I can resolve this issue.

I need to end this session variable as if the user exits the quiz and then selects another quiz to do the timer uses the current time session rather than assigning the new time value for that particular quiz.

Thanks in advance. 

Edd

Form.php

Code: [Select]
<html>
<head>
<script type="text/javascript">
function addsmiley(code)
{
var pretext = document.smile.message.value;
              this.code = code;
              document.smile.message.value = pretext + code;
}

function a()
{
 var x = document.smile.message.value;
 if(x=="")
 {
  alert("Please insert an message!");
  return false;
 }
 
}

</script>
<style type="text/css">
body{ background-color: #d8da3d }
</style>
</head>
<body>
  <form name="smile" method="post" action="registration.php" onSubmit="return a()" >
   Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br>
   <img src="smile.gif" alt=":)" onClick="addsmiley(':)')" style="cursor:pointer;border:0" />
   <img src="blush.gif" alt=":)" onClick="addsmiley('*blush*')" style="cursor:pointer;border:0" />
   <input type='submit' name='submit' value='Set Name' class='biasa'  ></form>
   
   
 
  <br> <br>
  </body>
</html>
Registration.php
Code: [Select]
<?php
$m=$_POST['message'];
echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('$m')</SCRIPT>");
?>
<html>
<head>
<script type="text/javascript">
  function a()
{
   var x = document.register.username.value;
   var y = document.register.pass.value;
   var z = document.register.pass2.value;
   
   if(x==""&& y==""&& z=="")
   {
    alert("Please insert all message!");
    return false;
   }
   if(x=="")
   {
     alert("Please insert an username!");
     return false;
   }
   if(y=="")
   {
     alert("Please insert an password!");
     return false;
   }
   if(z=="")
   {
     alert("Please insert an password2!");
     return false;
   }
   
   if (y!=z)
   {
     alert("Your passwords did not match");
     return false;
   }
   



}
</script>
</head>
<body>



  <form name="register" method="post" action="login.php"  onsubmit="return a()">
  <table border='0'>
  <input type="text" name="<?php $m?>">
  <tr><td>Username:</td><td><input type="text"name="username" maxlength="60"></td></tr>
  <tr><td>Password:</td><td><input type="password" name="pass" maxlength="10"></td></tr>
  <tr><td>Confirm Password:</td><td><input type="password" name="pass2" maxlength="10"></td></tr>
  <tr><th colspan=2><input type="submit" name="sub" value="Register"></th></tr> </table>
  </form>
 

  </body>
 </html>
Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br>     This i took from form.php and when it passed to registration.php when im called it in javascript  <?php
$m=$_POST['message'];
echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('$m')</SCRIPT>");  it can show the message im put in form.php but when im put into input text that is  <input type="text" name="<?php $m?>">  but the input text is blank not put the message im post in form php may i know which is the error

Hi,
 
 Can any  one help me wit the pagination in android mobile App  Pls find the attached file for full code
 
As per the below coe it displays only 40 posts but i have around 500 posts. I can increse
 
function add_query_vars($public_query_vars) {
        $public_query_vars[] = $this->namespace.'_p';
               return $public_query_vars;
    }
 
 
 
$args = array(
                'post_type' => 'post',
                'post_status' => 'publish',
                'category__in' => $categories,
            );
            if ($wp->query_vars[$this->namespace.'_p'] == 1){
                $args['posts_per_page'] = 10;
                $args['offset'] = 0;
            }else{
                $args['posts_per_page'] = 40;
                $args['offset'] = 10;
            }
            
            $posts = get_posts($args);
 
 
I have tried but i am getting only 210 posts.only if i increse the post_per_page more than 70 in mobile android app it shows loding
 
$args = array(
                'post_type' => 'post',
                'post_status' => 'publish',
                'category__in' => $categories
            );
          if ($wp->query_vars[$this->namespace.'_p'] == 1){
                $args['posts_per_page'] = 70;
                $args['offset'] = 0;
            }
            if ($wp->query_vars[$this->namespace.'_p'] == 2){
                $args['posts_per_page'] = 140;
                $args['offset'] = 70;
            }
            if ($wp->query_vars[$this->namespace.'_p'] == 3){
                $args['posts_per_page'] = 210;
                $args['offset'] = 140;
            }

           

            $posts = get_posts($args); Attached Files  wp-app-maker.php   49.23KB   1 downloads