PHP - Can You Use Data From A Database In A Combo Box Select Form?
I have a simple database table that has the names of countries listed with just 2 fields ID & country.
I want to use this in a form to choose the country and provide statistics regarding that country.
I know how to get the data from MySQL, but I don't know how I can use this in the form as a selection?
How do I get the options to iterate all of the countries so that when the form is displayed a combo type box is displayed with a dropdown list?
I have not shown any code as I am not sure if this is possible.
Please can anyone advise if this is possible and if so some example code?
Similar TutorialsI have a form on our website that a user can fill out for custom product. I want the form data to be 1) stored into a mysql database AND after storing said data, 2) email the same data to our sales department. 1) The form data DOES get stored into mysql database (except for the first two fields, for some weird reason) 2) I added a "mail" section to the php file that stores the data into the database, but it is not working correctly. I have stripped the email portion down to sending just one of the fields in the "message" to make it easier for troubleshooting I have included here, both the form section of the html file, and the formdata.php file that processes the data for your analysis. I am relatively new to php so there are going to be some issues with security, but I can work on those after I get the store & email process to work correctly. Please review my code and see if anyone can be of assistance. I looked through the forums and couldn't find another issue that was the same as mine. If I just overlooked, please tell me the thread post #. Thanks THE FORM WHICH COLLECTS THE DATA ******************************* <form method=POST action=formdata.php> <table width="640" border=0 align="center"> <tr> <td align=right><b>First Name</b></td> <td><input type=text name=FName size=25></td> <td><div align="right"><b>Telephone</b></div></td> <td><input type=text name=Tel size=25></td> </tr> <tr> <td align=right><b>Last Name</b></td> <td><input type=text name=LName size=25></td> <td><div align="right"><b>Fax</b></div></td> <td><input type=text name=Fax size=25></td> </tr> <tr> <td align=right><b>Title</b></td> <td><input type=text name=Title size=25></td> <td><div align="right"><b>Email</b></div></td> <td><input type=text name=Email size=50></td> </tr> <tr> <td align=right><b>Company</b></td> <td><input type=text name=Comp size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Address</b></td> <td><input type=text name=Addr size=25></td> <td><div align="right"><b>Estimated Annual Volume</b></div></td> <td><input type=text name=EAV size=25></td> </tr> <tr> <td align=right><b>City</b></td> <td><input type=text name=City size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>State/Province</b></td> <td><input type=text name=SProv size=25></td> <td><div align="right"><b>Application</b></div></td> <td><input type=text name=Appl size=25></td> </tr> <tr> <td align=right><b>Country</b></td> <td><input type=text name=Ctry size=25></td> <td><div align="right"><b>Type of System</b></div></td> <td><input type=text name=Syst size=25></td> </tr> <tr> <td align=right><b>Zip/Postal Code</b></td> <td><input type=text name=ZPC size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td><div align="right"><strong><font color="#FFFF00" face="Arial, Helvetica, sans-serif">COIL DESIGN</font></strong></div></td> <td><font color="#FFFF00" face="Arial, Helvetica, sans-serif"><strong>PARAMETERS</strong></font></td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Primary Resistance (ohms)</b></td> <td><input type=text name=Pres size=25></td> <td><div align="right"><b>Primary Inductance (mH)</b></div></td> <td><input type=text name=Pind size=25></td> </tr> <tr> <td align=right><b>Secondary Resistance (ohms)</b></td> <td><input type=text name=Sres size=25></td> <td><div align="right"><b>Secondary Inductance (H)</b></div></td> <td><input type=text name=Sind size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Peak Operating Current (Amps)</b></td> <td><input type=text name=POC size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Output Energy (mJ)</b></td> <td><input type=text name=Egy size=25></td> <td><div align="right"><b>Output Voltage (kV)</b></div></td> <td><input type=text name=Volt size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b># HV Towers per Coil</b></td> <td><input type=text name=TPC size=25></td> <td><div align="right"><b># of Coils per Package</b></div></td> <td><input type=text name=CPP size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <th colspan=4><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan=4><textarea name=Mess cols=50 rows=10 id="Message"></textarea></th> </tr> </table> </dl> <div align="center"> <p> <input type=hidden name=BodyTag value="<body bgcolor="#484589" text="#FFFFFF" link="#FFFF00" alink="#FFFFFF" vlink="#FF7F00">"> <input type=hidden name=FA value=SendMail> </p> <p><font color="#FFFF00" face="Arial, Helvetica, sans-serif"><strong>PLEASE MAKE SURE ALL INFORMATION<br> IS CORRECT BEFORE SUBMITTING</strong></font></p> <p> <input type=submit value="Submit Form"> </p> </div> </form> THE FILE THAT PROCESSES THE FORM DATA (formdata.php) *********************************************** <?php $con = mysql_connect("localhost","XXX","XXX"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("customform", $con); $sql="INSERT INTO formdata (Fname, Lname, Title, Comp, Addr, City, SProv, Ctry, ZPC, Tel, Fax, Email, EAV, Appl, Syst, Pres, Pind, Sres, Sind, POC, Egy, Volt, TPC, CPP, Mess) VALUES ('$_POST[Fname]','$_POST[Lname]','$_POST[Title]','$_POST[Comp]','$_POST[Addr]','$_POST[City]','$_POST[SProv]','$_POST[Ctry]','$_POST[ZPC]','$_POST[Tel]','$_POST[Fax]','$_POST[Email]','$_POST[EAV]','$_POST[Appl]','$_POST[Syst]','$_POST[Pres]','$_POST[Pind]','$_POST[Sres]','$_POST[Sind]','$_POST[POC]','$_POST[Egy]','$_POST[Volt]','$_POST[TPC]','$_POST[CPP]','$_POST[Mess]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your Information Was Successfully Posted"; mysql_close($con); $to = "recipient email address here"; $subject = "Custom Form"; $email = $_POST['Email'] ; $message = $_POST['Comp'] ; $headers = "From: $Email"; $sent = mail($to, $subject, $message, $headers) ; if($sent) {print "Your mail was sent successfully"; } else {print "We encountered an error sending your mail"; } ?> could anyone please help me with the code which is i have already displayed data as a multi select list but now i need to select one or more from them and insert into another database table. would be appreciate your help. thanx Not sure why this isnt working. Code: [Select] <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <script src="http://js.nicedit.com/nicEdit-latest.js" type="text/javascript"></script> <script type="text/javascript">bkLib.onDomLoaded(nicEditors.allTextAreas);</script> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <LINK REL=StyleSheet HREF="inc/dyn_style.css" TYPE="text/css" MEDIA=screen /> <?php ?> <?php include('logic.inc'); mysqlConnect(); ?> <script type="text/javascript" src="bbeditor/ed.js"></script> <link rel="stylesheet" type="text/css" href="dyn_style.css" /> <title> Social </title> <script type="text/javascript"> function changeTitle(title) { document.title = title; } </script> </head> <body> <?php $inc = 'new_story.php'; $view = 'Newest '; $by = 'added'; $where = " "; $where2 = " "; $order = "ASC"; $gen = "All"; $rat = 'All'; $blerg = ""; $sort = 'newest'; //---------------------------------------------------------------------- if(isset($_GET['sub'])) { $sort = $_GET['sort']; switch($sort) { case "Most Popular"; $by = 'views'; $view = 'Most Popular '; $order = 'DESC'; break; case "Most Reviewed"; $view= 'Most Reviewed '; $by = 'reviews'; $order = 'DESC'; break; case "Newest"; $by = 'added'; $view = 'Newest'; $order = 'ASC'; break; } $genre = mysql_real_escape_string($_GET['cat']); $rating = mysql_real_escape_string($_GET['rat']); if($gen == 'All') { $where = " "; $blerg = ""; } else { $where = "WHERE cat='$gen'"; } if ($rat == "All") { $where2 = ' '; $blerg = 'AND'; } else { $where2 = $blerg ." rating = '$rat' "; } } //---------------------------------------------------------------------- ?> <?php serch(); ?> <form action="story.php" method="get"> <label id='inline'> Order By: </label> <select name='sort'> <option selected='yes' label='Currently Selected' > <?php echo $view; ?> </option> <option> Newest </option> <option> Most Popular</option> <option> Most Reviewed </option> </select> <input type='hidden' value='spec_view' name='p' /> <label id='inline'> Genre/Catagory: </label> <select name='gen'> <option selected='yes' label = 'Selected Genre - <?php echo $gen; ?>'> <?php echo $gen; ?> </option> <option> All </option> <option> Fantasy </option> <option> Adventure </option> <option> Science Fiction</option> <option> Drama</option> <option> Fable </option> <option> Horror</option> <option> Humor</option> <option> Realistic Fiction </option> <option> Tall Tale</option> <option> Mystery </option> <option> Mythology </option> <option> Poetry </option> <option> Shorty Story </option> <option> Romance </option> </select> <label id='inline'> Rating: </label> <select name='rat'> <option selected='yes' label = "Selected Genre - <?php echo $rat; ?>"> <?php echo $gen; ?> </option> <option> All </option> <option> C </option> <option> C13 </option> <option> YA </option> <option> A </option> </select> <input type='submit' value='Go!' name = 'go' /> </form> <?php $query = " SELECT * FROM story_info ORDER BY $by $order $where $where2 "; echo $query; $select = mysql_query($query) or die(mysql_error()); while($rows = mysql_fetch_assoc($select)) { $viewsdb = $rows['views']; $titledb = $rows['title']; $userdb = $rows['user']; $catdb = $rows['cat']; $ratdb = $rows['rating']; $id_db = $rows['story_id']; $sumdb = shorten($rows['sum']); echo "<h3><a href='?p=page&id=$id_db'> $titledb </a> </h3>"; echo "<div id='fun_info'>"; echo "$sumdb <br />"; echo "By <a href='?p=profile&user=$userdb'> $userdb </a> <br /> "; echo "$viewsdb Views | Rated: $ratdb | Catagory: <a href='?p=cat_view&gen=$catdb'> $catdb </a> </div>"; } ?> </div> </body> </html> Hello everyone and thank you for taking the time to read this. I am very new to coding and I am helping a friend with a website. I'm trying to create a form with a <select> dropdown and filling the options with items from a database, there are very man items so I'm not sure 100% how to go about this, I have some code but I know it's wrong I'm just looking for a nudge in the right direction, any help is appreciated the code can be found below: Code: [Select] <div style="float:left;"> <select> $team = $sql->query("SELECT * FROM teams WHERE arenaid ='$platid'"); <option value="<?echo $teams>"></option> </select> </div> Again, thank you for taking the time to read this and thank you also for any help you can provide. This is a continuation of a previous post. I am trying to get the names of countries that are in a database table. It's not working! All I get is a Submit button, but no data. This is what I understand from the code that Psycho suggested: I am unfamiliar with the function and the use of the FOREACH constuct. looking at the PHP manual there are two syntaxes. It appears that Psyhco has used the second form where the current element's key is assigned to $key variable for each itteration. foreach (array_expression as $key => $value The 2 variables he used are $id and $label I assume that the line: $optionsHTML = ''; is the array built from the expression: $optionsHTML .= "{$label}\n"; Because I was not familiar with the PDO method, but have used mysqli, I had to rewrite the data retrival part which I believe is OK. I guess that the line : $countryOptions = buildSelectOptions($countries); is used in conjunction with the function to build the array. The HTML part that Psycho wrote puts the variable into the Form format for a selection list. Why is the $optionsHTML also inclosed in the option tags? Have I got the HTML part correct or is it the data extraction part that is incorrect? Here is the code: <? include("AddStats_admin_connect.php"); //connect to database doDB(); //Function to build select options based on passed array function buildSelectOptions($options) { $optionsHTML = ''; foreach($options as $id => $label) { $optionsHTML .= "<option value='{$id}'>{$label}</option>\n"; } return $optionsHTML; } //Run query to get the ID and Name from the table //Then populate into an array $clist_sql = "SELECT CID, Country FROM Countries"; $clist_res= mysqli_query($mysqli, $clist_sql) or die(mysqli_error($mysqli)); if (mysqli_num_rows($clist_res) < 1) { //this Country not exist $display_block = "<p><em>You have selected an invalid Country.<br/> Please try again.</em></p>"; } $countries = array(); while($Ctry_info = mysqli_fetch_array($clist_res)) { $countries[$Ctry_info['CID'] = $Ctry_info['Country']]; } $countryOptions = buildSelectOptions($countries); ?> <!DOCTYPE html> <html lang="en"> <head> <title>Stats</title> <link rel="stylesheet" href="stylesheets/style.css" /> <!--[if IE]> <script src="http://html5shim.googlecode.com/svn/trunk/html5.js"></script> <![endif]--> </head> <body> <? echo $countryOptions; ?> </br></br></br></br></br></br></br></br> <!Later in the HTML for the page <form action="Ctrystats.php" method="post"> <option name="country" value=<? echo $countryOptions;?>Country</option></br></br> <input type="submit" value="Submit Choice"> </form></p> </body> </html>I think I am nearly there so I would appreciate some help to finish this coding. Note: If you make your questions easy to read, then you have better chances of a quality answer. Use [ code ] ] tags. I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. The company I work for is a not-for-profit organization, we provide medical services for people who can not afford to go to the regular doctor. We need a way to keep track of our patients and their visits and a way to search the data. I found an html form, with name, address, phone number, zip code,,,,,, and made a few changes to fit our needs. But I do not know how to get that information into the database. I also need a way to make sure the information is not a duplicate. Since we are a not-for-profit organization, funds are kinda tight. That is why I want to go with php instead of buying medical software. Most of the medical software on the market cost more then we can afford. I'am a computer tech here at the office, but my field is hardware, networking, and malware removal. PHP programming is new to me. So where do I start? Hi All I have a contact form whcih works great - its has a little validation on it and sends me all the information I need via email. I now want to store all data submitted via the form to be stored in a MySQL database. What is the best way to do this?? Attached is my form as it is, just being emailed to the relevent accounts. Look forward to your replies. Adi I almost have it but I am missing something. The form is being sent and the row is being created but there is not data. It is blank. I know it is something simple I am missing but I cannot figure it out
If anyone can look at my code below and tell me what I am missing to make the inputed info be seen, I would sure appreciate it.
<?php include_once('class/class_email.php'); // contact to database $connect = mysql_connect("localhost", "admin", "password") or die ("Error , check your server connection."); mysql_select_db("database"); $fname = $_POST['fname']; $lname = $_POST['lname']; $email = $_POST['email']; $company = $_POST['company']; $telephone = $_POST['telephone']; $comments = $_POST['comments']; $EID = $_POST['eid']; extract ($_POST); // Pick up the form data and assign it to variables // $id = intval($id); $fname = strip_tags($fname); $lname = strip_tags($lname); $email = strip_tags($email); $company = strip_tags($company); $telephone = intval($telephone); $query="INSERT INTO users(`id`, `fname`, `lname`, `email`,`company`,`telephone`) VALUES('$id','$fname','$lname','$email','$company','$telephone')"; echo $query; mysql_query($query) or die(mysql_error()); echo mysql_error(); $SQL_GetEquipment = "SELECT * FROM `new_equip` WHERE `id`='$EID' LIMIT 1;"; $result = mysqli_query($connect,$SQL_GetEquipment); $row = mysqli_fetch_assoc($result); $EmailBody = "$fname $lname has requested a quote from NAPE on Item $EID\n Information on quote request: \n Name: $fname $lname \n Email: $email \n Company: $company \n Number: $telephone \n Comments: $comments \n \n Information Requested for: {$row['itemname']}\n The URL to {$row['itemname']} is: http://www.mydomain.com.com/new-product.php?Item=$EID \n Click to send a quote now:\n http://www.mydomain.com.com/Admin/send-quote.php?id=$EID "; $e = new email(); //First value is the URL of your server, the second the port number $e->set_server( 'mail.mydomain.com.com', 26); //First value is your username, then your password $e->set_auth('noreply@mydomain.com', '112233'); //Set the "From" setting for your e-mail. The Name will be base64 encoded $e->set_sender( 'Quote Requested', 'noreply@mydomain.com' ); //for one recipient //$send_to = array('myemail@mydomain.com','myemail2@mydomain.com'); $send_to = ('myemail@gmail.com'); //you may also specify multiple recipients by creating an array like this: //$send_to = array('foo1@localhost.local', 'foo2@localhost.local', 'foo3@localhost.local'); $subject = 'Quote Request from NAPE'; $body = "$EmailBody"; if( $e->mail($send_to, $subject, $body, $headers) == true ) { //message was received by the smtp server //['last'] tends to contain the queue id so I like to save that string in the database echo 'last: '.htmlspecialchars($e->srv_ret['last']).''; }else{ //something went wrong echo 'all: '.nl2br(htmlspecialchars($e->srv_ret['all'])).''; echo 'full:'.nl2br(htmlspecialchars($e->srv_ret['full'])).''; } ?> helo does anyone know how to display data from db in checkbox form? i have been searching for days and still cannot find answer that i can understand. i hope someone can help me. i really am lost. any help is much appreciated how i want to display data from database to look like this : <table width="633" height="224" border="1"> <tr bgcolor="#999900"> <td width="45">Bil</td> <td width="121">Course_name</td> <td width="83">session</td> <td width="83">start_date</td> <td width="83">end_date</td> <td width="83">notes</td> <td width="89">pre-req</td> </tr> <tr bgcolor="#6A7AEA"> <td rowspan="2">1.</td> <td rowspan="2" bgcolor="#6A7AEA">Math</td> <td>1st session </td> <td>1 jan 11 </td> <td>6 jan 11 </td> <td rowspan="2"> </td> <td rowspan="2"><image icon that will link to the oter site> </td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session </td> <td bgcolor="#6A7AEA">8 jan 11 </td> <td bgcolor="#6A7AEA">15 jan 11 </td> </tr> <tr> <td bgcolor="#0066CC">2.</td> <td bgcolor="#0066CC">English</td> <td bgcolor="#0066CC">1st session </td> <td bgcolor="#0066CC">1 feb 11 </td> <td bgcolor="#0066CC">6 feb 11 </td> <td bgcolor="#0066CC"> </td> <td bgcolor="#0066CC"><image icon that will link to the oter site></td> </tr> <tr> <td rowspan="2" bgcolor="#6A7AEA">3.</td> <td rowspan="2" bgcolor="#6A7AEA">Science</td> <td height="29" bgcolor="#6A7AEA">1st session </td> <td bgcolor="#6A7AEA">8 march 11 </td> <td bgcolor="#6A7AEA">15 march 11 </td> <td rowspan="2" bgcolor="#6A7AEA"> </td> <td rowspan="2" bgcolor="#6A7AEA"><image icon that will link to the oter site></td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session</td> <td bgcolor="#6A7AEA">16 march 11 </td> <td bgcolor="#6A7AEA">21 march 11 </td> </tr> </table> ** all the view data is called from database including the icon image thanks... I have deleted mysql info for safety reasons. Here are the two webpage's codes i'm using right now menu.php <? session_start(); if(!session_is_registered(myusername)){ header("location:login.php"); } ?> <html><title>ChronoServe - Saving Time</title> <link href="style.css" rel="stylesheet" type="text/css"> <body> <table width="100%" border="0" cellpadding="0" cellspacing="0" class="container"> <tr> <td> <table width="335px" height="50%" border="1" align="center" cellpadding="0" cellspacing="0" class="centered"> <tr> <td> <form method="post" action="insertvalues.php"> <table width="100%" border="0" align="center" cellpadding="3" cellspacing="10"> <tr> <td colspan="2"><div align="center" class="font2">Activation Information</div></td> </tr> <tr> <td colspan="2"></td> </tr> <tr> <td width="40%" class="font3">First Name :</td> <td width="60%"> <div align="center"> <input name="firstname" type="text" class="font3" id="firstname" maxlength="25" /> </div></td> </tr> <tr> <td class="font3">Last Name :</td> <td> <div align="center"> <input name="lastname" type="text" class="font3" id="lastname" maxlength="25" /> </div></td> </tr> <tr> <td height="28" class="font3">Phone Number :</td> <td> <div align="center"> <input name="pnumber" type="text" class="font3" id="pnumber" maxlength="10" /> </div></td> </tr> <tr> <td class="font3">Personnel Activated :</td> <td> <div align="center"> <input name="numberactivated" type="text" class="font3" id="numberactivated" maxlength="3" /> </div></td> </tr> <tr> <td height="37" colspan="2"></td> </tr> <tr> <td colspan="2"><div align="center"> <input name="submit" type="Submit" class="font3" value="Submit" /> </div> </td> </tr> </table> </form></td> </tr> </table> </td> </tr> </table> </body> </html> insertvalues.php <?php if(isset($_POST['Submit'])) { $firstname = $_POST['firstname']; $lastname = $_POST['lastname']; $pnumber = $_POST['pnumber']; $numberactivated = $_POST['numberactivated']; mysql_connect ("deleted", "deleted", "deleted") or die ('Error: ' . mysql_error()); mysql_select_db ("deleted"); $query = "INSERT INTO disney_database (id, firstname, lastname, pnumber, numberactivated, date) VALUES ('NULL', '".$firstname."', '".$lastname."', '".$pnumber."', '".$numberactivated."', 'NULL')"; mysql_query($query) or die('Error updating database'); header("location:menu.php"); echo "Database Updated With: ".$firstname."" - "".$lastname."" - "".$pnumber."" - "".$numberactivated.""; } else { echo "Database Error" { ?> Here is my problem. I set a one <form> on every form field I have including the submit button. Now whenever I press the submit button it redirects to insertvalues.php which it should be doing. In insertvalues i told it to query the form data and post it into my database's table. Its not doing that and tells me that it has a database error which i set it to tell me if something goes wrong. Anyone can help me? BTW I can manually query in the information using sql with phpmyadmin. so can someone please review my code for me? thanks big help! You can see what is happening. Visit www.chronoserve.com The username and password are "admin" I am having difficulty inserting the following codes values into my database. I know that the variables contain a value as I am displaying them on the output screen. Code: [Select] $link = mysql_connect($db_host,$db_user,$db_pass) or die('Unable to establish a DB connection'); mysql_select_db($db_database,$link); mysql_query("SET names UTF8"); $usr = $userid; $golfer = $_REQUEST['golfer']; $tourney = $_REQUEST['tournament']; $backup = $_REQUEST['backup']; date_default_timezone_set('US/Eastern'); $time = date("Y-m-d H:i:s"); $t_id=1; mysql_query("INSERT INTO weekly_picks (t_id, tournament, user, player, backup, timestamp) VALUES ('$t_id', '$tournament', '$usr', '$golfer', '$backup', '$time') or die('Error, insert query failed')"); echo $t_id; echo "<br />"; echo $tourney; echo "<br />"; echo $usr; echo "<br />"; echo $golfer; echo "<br />"; echo $backup; echo "<br />"; echo $time; echo "<br />"; echo $userdetail['email']; echo "<br />"; $to = $userdetail['email']; $subject = "Weekly Tournament Pick for: $tourney"; $message = "This email is to confirm your pick for $tourney has been received. Your pick is: $golfer. Your backup pick is: $backup The time it was submitted was $time Do not reply to this email, the mailbox does not exist. Contact me with any issues at xxxxxxx@xxxxxxx.com"; $from = "noreply@chubstersgcc.com"; $headers = "From:" . $from; mail($to,$subject,$message,$headers); ?> <div> <p>This is to confirm that your pick has been submitted for the following tournament: <?php echo $tourney; ?>. A confirmation of your pick as also been emailed to you.</p> <p>Your golfer: <?php echo $golfer; ?></p> <p>Your backup: <?php echo $backup; ?></p> <p>Your pick was submitted at: <?php echo $time; ?></p> </div> Hi everyone, First off thank you very kindly to anyone who can provide some enlightenment to this total php/mysql newb. I am creating my first database and while I have been able to connect to the database within my php script (or so I believe), the form data does not appear to be actually getting sent. I have development experience in other languages but this is completely new to me so if I've missed something that appears painfully obvious like a parse error of some sort, I do apologize. I am creating a website using Godaddy as the hosting account, and attempting to connect to the mysql database at the following URL (maybe this is where I'm going wrong): "pnmailinglist.db.4662743.hostedresource.com" Below is my very simple code: <?php //Verify successful connection to database. $connect = mysql_connect("pnmailinglist.db.4662743.hostedresource.com", "*********", "*********"); if(!$connect) {die("Could not connect!"); } //Initialize variables with form data. $firstname = $_POST['FirstName']; $lastname = $_POST['LastName']; $email = $_POST['Email']; $howfound = $_POST['HowFound']; //Post data to database, or return error. mysql_select_db("pnmailinglist", $connect); mysql_query("INSERT INTO mailinglist (First, Last, Email, How_Found) VALUES ($firstname,$lastname,$email,$howfound)"); mysql_close($connect); echo "Thank you for joining our mailing list! We will contact you soon with the dates and times of our upcoming events."; ?> Thank you again very much for any pointers or hints as to where I'm screwing up. I get no runtime errors, no syntax errors, and the echo message does display fine at the end -- just no data when I go to check my database! Best Regards, CL Lets say I have this database: table brand [brandID] [brandName] where brandID -> auto increment and one brand always has the same brandID table product [brandID] [productID] [price] where productID -> auto increment I want to insert new product into the database using only values [brandName] and [price] and want brandID and productID to be created automatically I use this form: <form id="insertingDataToBrand" action="administratorCode.php" method="post"> <div>Brand Name: <input type="text" name="brandName"/></div> <div>Price: <input type="text" name="price"/></div> </form> And here is the php code: <?php //connection to database include 'connectToDatabase.php'; //data retrieveing $brand = $_POST['brandName']; $price = $_POST['price']; //As I am inserting to two different tables I use two INSERT statements $sql = "INSERT INTO brand (brandName) values ('$brand')"; mysql_query($sql) or die (mysql_error()); //as brandID is created automatically I am going to insert the same value to another table $last_id = mysql_insert_id (); $sql = "INSERT INTO product (price, brandID) values ('$price', '$last_id')"; ?> This should work just fine (it doesnt tho) BUT my question is: I have 3 different brands (brand A with brandID 1, brand B with brandID 2, brand C with brandID 3). When want to insert brand D, automatically created brandID should be automatically set to 4. BUT when I want to insert product of the same brand, lets say brand A (with different productID) brandID is automatically set to 4(or higher) as well. What do I have to do(use) so it would be able to realise what brandID should be added? Thanks a lot. Hi I making some forms that write to mysql database, Im now in the process of making the update form so the user can update there details on the form, I want it to populate the form with existing data but its not doing it at all. Thanks in advance
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3 downloads Hello Im quite confused at what filtering I should use on my data when pulling it from a MySQL database. I don't sanitize my data on input because I am using prepared statements with PHP's PDO Driver which means I don't need to use mysql_real_escape_string() at all. When I pull the data to be displayed i.e. in a HTML Table I use the below function to make it safe for HTML output. public static function htmlSafe($data) { return nl2br(htmlentities($data, ENT_QUOTES)); } However the rules change when Im using a HTML Form to edit the data, and I am unsure what I need to strip out. I.e. What would I need to do to make all data safe to insert into the following form input. <input id = "someInput" type = "text" value = "<?php echo $someVarThatNeedsFiltering ?>" /> Also, one more question, in my html attributes (Valid ones like class, name, id, style, _target) I use a mixture of double quotes(") and single quotes ('), for quoting my values. Which one should I use or which one is more valid, doubles, or singles? So i have an event page where it will show the next 3 events, then i need logged in users to click either of two buttons to say there attending or not attending. i have the below code showing events, and the <form> and the submit and both buttons, but if i submit 1 button on event ID: 1 it inserts data into the database but for event ID: 2, and if i click the button on event ID :2 it also puts it into database with eventid:2 so no matter which event i click it seems to submit data with the latest event ID shown on page, and not for "each" event seperatly. i have moved the submit query everywhere around and still same results or duplicate results if its in the loop. i assume its looping the submit and only submitting the latests event ID.
<?php if ($result = $con->query("SELECT * FROM events ORDER BY id ASC LIMIT 3")) { if ($result->num_rows > 0) { while ($row = $result->fetch_object()) { $event_id = $row->id; // set up table and echo data! echo "<table border='1' cellpadding='2' width='50%'>"; echo "<tr><td>"; echo "<p><img src='images/raid_banners/" . $row->bannerimg . "'>" . $row->name . " (iLvl: " . $row->itemlevel . ")</p>"; echo "<p>Event Starts: " . $row->datestart . " - " . $row->timestart . "</p>"; echo "<p>Event Ends: " . $row->dateend . " - " . $row->timeend . "</p>"; echo "<p>Raid Lead: " . $row->raidlead . "</p>"; echo "<form action='' name='$event_id' method='post'>"; // Process and populate SELECT form element echo "<select name=\"charname\">"; $sql = mysqli_query($con, "SELECT * FROM characters WHERE userid = $userid"); while ($row = $sql->fetch_assoc()){ echo "<option value=\"{$row['id']}\">{$row['charname']}</option>"; } echo "</select>"; echo "<input type='hidden' name='raidid' value ='$event_id'>"; echo "<input type='hidden' name='action' value='submit' />"; echo "<input type=\"submit\" name=\"submit\" value=\"going\">"; echo "<input type=\"submit\" name=\"submit\" value=\"notgoing\">"; echo "</form></td></tr></table><br><br>"; } if(isset($_POST['action'])){ $charid = $_POST['charname']; $submit = $_POST['submit']; // Submit the data from dropdown in the form mysqli_query($con,"INSERT INTO eventsignup (eventid, charid, userid, status) VALUES ('$event_id', '$charid', '$userid', '$submit')"); } } else { echo "No results to display!"; } } else { echo "Error: " . $con->error; } $con->close(); ?> any help would be awesome. im tearing my hair out here. Hi. Can someone show me the proper way to do a feedback form (like a "Contact US" form). I have read about SQL injections and would like to know I am protecting against it. And the proper way to store the submitted data in a database for a client's records. I have a basic form I use, but I am unable to store the data properly. Any help or a code idea would be appreciated. Thanks much. |