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PHP - Help With Php Admin Login..

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Help With Php Admin Login..	View Content

Hallo I have a problem. This is my code:

<?php include 'connect.php';
?>

<html>
<head>
<title>Admin Insert page!</title>
</head>
<body>
<?php
error_reporting(-1);ini_set('display_errors',1);
if (isset($_POST['submit'])){
$name = $_POST['name'];
$password = $_POST['password'];
$result = mysql_query("SELECT * FROM users WHERE user='$name' AND password='$password'");
$num = mysql_num_rows($result);
if($num == 0){
echo "Bad login, go <a href='login.php'>back</a>";
}else{
session_start();
$_SESSION['name'] = $name;
header("Location: admin.php");
}
}else{
?>
<form action='login.php' methody='post'>
Username: <input type='text' name='name'/><br />
Password: <input type='password' name='password'/><br />
<input type='submit' name='submit' value='Login' />

</body>
</html>

I try to use console to find the problem but I didn't.... I know that there is some problem with $num Can somebody help me? Thank you.
Edited by Artur, 19 October 2014 - 12:11 PM.

Full Excel VBA Course - Beginner to Expert

Login Form - Member And Admin Page After Login

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hi

i need help an idea how can i separate members from admins
since i dont know how to create login form i used tutorial ( http://www.youtube.com/watch?v=4oSCuEtxRK8 ) (its session login form only that i made it work other tutorials wre too old or something)
how what i want to do is separate members and admins because admin need more rights to do
now i have idea but dont know will it work like that
what i want to do is create additional row in table named it flag and create 0 (inactive user) 1 (member) 2 (admin) will that work?
and how can i create different navigation bars for users and admins? do you recommend that i use different folders to create it or just script based on session and flag?

Helping With Admin Login And User Login

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Hi guys,

Can anyone assist me. I am trying to create a login for admin and user (if user not a member click register link) below is my code: But whenever I enter the value as: Username: admin Password:123 - I got an error message "That user does not exist!"

Any suggestion and help would be appreciated.
Thanks.

login.php

<?php

//Assigned varibale $error_msg as empty

//$error_msg = "";

session_start();

$error_msg = "";

if (isset($_POST['submit'])) {

if ($a_username = "admin" && $a_password = "123")

{

//Define $_POST from form text feilds

$username = $_POST['username'];

$password = $_POST['password'];

//Add some stripslashes

$username = stripslashes($username);

$password = stripslashes($password);

//Check if usernmae and password is good, if it is it will start session

if ($username == $a_username && $password == $a_password)

{

session_start();

$_SESSION['session_logged'] = 'true';

$_SESSION['session_username'] = $username;

//Redirect to admin page

header("Location: admin_area.php");

}

$username = (isset($_POST['username'])) ? $_POST['username'] : '';

$password = (isset($_POST['password'])) ? $_POST['password'] : '';

if($username && $password) {

$connect = mysql_connect("localhost", "root", "") or die ("Couldn't connect!");

mysql_select_db("friendsdb") or die ("Couldn't find the DB");

$query = mysql_query ("SELECT * FROM `user` WHERE username = '$username'");

$numrows = mysql_num_rows($query);

if ($numrows != 0){

while ($row = mysql_fetch_array($query)) {

$dbusername = $row['username'];

$dbpassword = $row['password'];

}

//Check to see if they are match!

if ($username == $dbusername && md5($password) == $dbpassword) {

header ("Location: user_area.php");

$_SESSION['username'] = $username;

}

else

$error_msg = "Incorrect password!";

//code of login

}else

$error_msg = "That user does not exist!";

//echo $numrows;

}

else

$error_msg = "Please enter a username and password!";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Login Page</title>
</head>

<body>
<br />
<?php

require "header.php";
?><br />
<div align="center">
<table width="200" border="1">

<?php

// If $error_msg not equal to emtpy then display error message

if($error_msg!="") echo "<div id=\"error_message\"style=\"color:red; \">$error_msg</div><br />";?>

<form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post">

Username: <input type="text" name="username" /><br /><br />

Password: <input type="password" name="password" /><br /><br />

<input type="submit" name = "submit" value="Log in" />
</form> <p> </p>

Register a <a href="register.php">New User</a>
</table>
</div>
</body>
</html>

Login With Admin

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Any help would be greatly appreciated!

<?php
$host="localhost"; // Host name
$username="user"; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name=""; // Table name

mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

$barcodeID=$_POST['barcode'];

echo $barcodeID;

$barcodeID = stripslashes($barcodeID);
$barcodeID = mysql_real_escape_string($barcodeID);

$sql="SELECT * FROM $tbl_name WHERE BarcodeID='$barcodeID'";

$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
$count=mysql_num_rows($result);

if($count==1){

$_SESSION['barcode'] = $barcodeSession;
$_SESSION['userlevel'] = $row['Priority'];

if($row['userlevel'] == "Admin") {
header("location:AdminSection.php");
}else{
header("location:index.php");
}

header("location:LoggedIn.php");
}
else {
header("location:index.php");
}
?>

when the script has been run, I want it to redirect to either the user page or admin page depending on their priority level.

if Priority field == "Admin" then go to admin page.

Can you see anything missing?

Thank You

Problem With Admin Login

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Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\sas\shoppingcart\adminlogin.php on line 16

Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\sas\shoppingcart\adminlogin.php:16) in C:\xampp\htdocs\sas\shoppingcart\adminlogin.php on line 33

Admin Login - The Correct Way

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Ok.. I have made an admin section for a couple of sites, and it works fine, alough i'm almost certain that the way i have done it is not the "proper way".

What I have done is had a form with a password field that sends the password via POST to another script that checks the password is correct via variable, something like this:
Code: [Select]
<?php

  $pass = $_POST["pass"];
  $correct = "imapassword";

  if($pass == $correct){

  //display contents of page

  else{
  //return user to login screen
  }
?>

And then it saves the password into a cookie, that dies either over time or when the browser closes. And then on each page it tests wether that cookie is still there and is correct. When the user wants to log out it just destroys the cookie.

This seems like a really hashed up way of doing it, could anybody let me know the bare essentials for making a similar system, but the "right way". Thankyou in advance

Admin Login Script

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hi guys how you doing? i new here so take it easy on me .

basically just need some quick help and i thought this would be the best place to ask. ive been working on a admin login script but cant seem to get it right, i mean i can login in with random passwords :/ and also everytime i go to the index.php it shows the information i dont want it without being logged in. ive got the script running live just incase anyone wants to see what i mean its at http://www.lukerodham.co.uk/admin

heres the code. Thanks in advance.

index.php
Code: [Select]
<?php
require_once("login.php");

$adminuser = $_SESSION['user'];
?>

<html>
<head>
<title>hoonigans.co.uk</title>
</head>
<body>
<h3 align="center">Welcome to the admin page.</h3>
<span class="maintext"><br />
<p align="center">If you would like to post some news please <a href="news/post.php">click here</a>.<br />
To logout please <a href="logout.php">click here</a></p>
</body>
</html>

login.php
Code: [Select]
<?php

function loginpage($error){
    echo "
    <html>
    <body>
    <div align='center'>
    <form method='post' action='".$_SERVER['REQUEST_URI']."'>
    <label>username:
    <input type='text' name='username' id='username'><br>
    <label>password:
    <input type='password' name='password' id='password'><br>
    </label>
    <label>
    <input type='submit' name='submit' id='submit' value='submit'>
    </label>
    </form>
    </div>
    </body>
    </html>
    ";
}

$username = $_POST['username'];
$password = $_POST['password'];
$login = $_post['login'];

$host = *********;
$dbuser = *********;
$dbname = *********;
$dbpass = *********;

mysql_connect("$host","$dbuser","$dbpass");
mysql_select_db("$dbname");

session_start();
if($_SESSION['user'] != $username){
if(!$submit){
loginpage(false);
}
    elseif($submit){
        $get = mysql_query("SELECT * FROM users WHERE username='$username'");
        while ($row = mysql_fetch_assoc($get)){

           $admin = $row['admin'];
           $passwordmatch = $row['password'];

           if ($passwordmatch==$password&&$admin==1){

            $_SESSION['user']="$username";
            echo "this worked";
           }
           else{
            die("Sorry wrong information.");
           }
        }
    }
}
?>

Admin Login Problems

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Hello,

I have a problem with my website, Admin login page (http://www.tranceprofile.com/storeadmin/admin_login.php

I can not login to my Admin controle panel.

Login information:
Username: Mitch
Password: schuur111

Username: Admin
Password: poopoo

Can someone help me ?

Here is my admin_login.php source code.
If you need some other source code in my /storeadmin folder please tell
Code: [Select]
<?php
session_start();
if (isset($_SESSION["manager"])) {
    header("location: index.php");
    exit();
}
?>
<?php
// Parse the log in form if the user has filled it out and pressed "Log In"
if (isset($_POST["username"]) && isset($_POST["password"])) {

$manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); // filter everything but numbers and letters
    $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); // filter everything but numbers and letters
    // Connect to the MySQL database
    include "../storescripts/connect_to_mysql.php";
    $sql = mysql_query("SELECT id FROM admin WHERE username='$manager' AND password='$password' LIMIT 1"); // query the person
    // ------- MAKE SURE PERSON EXISTS IN DATABASE ---------
    $existCount = mysql_num_rows($sql); // count the row nums
    if ($existCount == 1) { // evaluate the count
     while($row = mysql_fetch_array($sql)){
             $id = $row["id"];
}
$_SESSION["id"] = $id;
$_SESSION["manager"] = $manager;
$_SESSION["password"] = $password;
header("location: index.php");
         exit();
    } else {
echo 'That information is incorrect, try again <a href="index.php">Click Here</a>';
exit();
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Admin Log In </title>
<link rel="stylesheet" href="../style/style.css" type="text/css" media="screen" />
</head>

<body>
<div align="center" id="mainWrapper">
<?php include_once("../template_header.php");?>
<div id="pageContent"><br />
<div align="left" style="margin-left:24px;">
<h2>Please Log In To Manage the Store</h2>
<form id="form1" name="form1" method="post" action="admin_login.php">
User Name:<br />
<input name="username" type="text" id="username" size="40" />
<br /><br />
Password:<br />
<input name="password" type="password" id="password" size="40" />
<br />
<br />
<br />

<input type="submit" name="button" id="button" value="Log In" />

</form>
<p>  </p>
</div>
<br />
<br />
<br />
</div>
<?php include_once("../template_footer.php");?>
</div>
</body>
</html>

Admin Login Script Issue.

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Hi all,

Sorry to be a pain, but I've been out of the php game for quite a few years and have just come back to it briefly to help someone out.
I've been using an old admin auth script that I used to use a long time ago but it's not working, and I can't for the life of me work it out :/

I apologise for the noobishness of the code, but as I said, it's been a long time.
Any and all help would be very greatly appreciated.

Here is the code:

<?

   require("config.php");

   mysql_connect($server,$login,$password) or die('Error connecting to server');
   mysql_select_db($base) or die('Error connecting to database');

   $req = mysql_query("SELECT username,mempass,level FROM members WHERE username='$admin_login'");
   $data = @mysql_fetch_array($req);
   $member_name = $data["username"];
   $member_pass = $data["mempass"];
   $member_userlevel = $data["level"];

   if($member_pass == $admin_pass)
      {
      SetCookie("mgdwebby","$member_name:$member_pass:$member_userlevel");
      }

include("header.php");

?>

<?

if($action=="login")
   {

   if($admin_login==""){ echo"Wrong info. "; }
   elseif($admin_pass==""){ echo"Wrong info. "; }
   else{

   require("config.php");

   mysql_connect($server,$login,$password) or die('Error connecting to server');
   mysql_select_db($base) or die('Error connecting to database');

   $req = mysql_query("SELECT username,mempass,level FROM members WHERE username='$admin_login'");
   $data = @mysql_fetch_array($req);
   $member_name = $data["username"];
   $member_pass = $data["mempass"];

   if($member_pass == $admin_pass)
      {

      echo"<head><meta http-equiv=\"refresh\" content=\"2;URL=admin.php\"></head><br><center>Please

Wait.</center><br>";
      $auth = explode(":",$HTTP_COOKIE_VARS["mgdwebby"]);
      if(empty($auth[0]) || empty($auth[1]))
         {
         }
      else
         {
         echo"Welcome<br>";
         include("admin_left.php");
         }
      }
   else
      {
      echo"Wrong info. ";
      }
     }
   }
else
   {

   echo"<form method='post' action='?action=login'>
   <table width='307' align='center' cellspacing='0' cellpading='0' border='0'>
     <tr>
     <td width='200'> Login : </td>
     <td> <input type='text' name='admin_login'></td>
     </tr>
      <tr>
     <td width='200'> Password : </td>
     <td> <input type='password' name='admin_pass'></td>
     </tr>
     <tr>
     <td colspan='2' align='center'><center><input type='submit' value='Login'></center></td>
   </table> ";

   }

?>

<?

include("footer.php");

?>

Cannot Figure Out Simple Admin Login

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I am trying to learn php and I cannot figure out how to get a simple login form going. I am getting this error. Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given I have no clue what I am doing wrong. I am following the "HowTo". Here is my code Index.php ( Login Form )

<form name="form1" method="post" action="checklogin.php">
<div id="wrappermiddle">
<h2>Login</h2>
<div id="username_input">
<div id="username_inputleft"></div>
    <div id="username_inputmiddle">

    <input name="myusername" type="text" id="myusername" value="Email Address">
    <img id="url_user" src="./images/mailicon.png" alt="">			
    </div>
    <div id="username_inputright"></div>
    </div>

    <div id="password_input">
    <div id="password_inputleft"></div>
    <div id="password_inputmiddle">				
    <input name="mypassword" type="text" id="mypassword" value="Password">
    <img id="url_password" src="./images/passicon.png" alt="">				
    </div>
    <div id="password_inputright"></div>
    </div>

    <div id="submit">	
    <input type="image" src="./images/submit.png" name="Submit" value="Login">			
    </form>
    </div>

checklogin.php

<?php
    $host="localhost"; // Host name
    $username="MY DB USER"; // Mysql username
    $password="Password"; // Mysql password
    $db_name="MY DB Name"; // Database name
    $tbl_name="admin"; // Table name


// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

// username and password sent from form 
$myusername=$_POST['myusername']; 
$mypassword=$_POST['mypassword']; 

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);
$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){

// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword"); 
header("location:login_success.php");
}
else {
echo "Wrong Username or Password";
}
?>

Any help would be greatly appreciated.
Edited by Oblivion13, 07 October 2014 - 05:25 PM.

Sending Email On Admin Login

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Howdy colleagues, Please help! I am writing a WP plugin the boss of the website to be notified when an admin logs in. So far so good, but I can't make the damn code to send the email when the user logs in. If I change the add_action to "admin_notices" the email is being sent, but if I put "wp_login" it does not Please help, here is the code so far...

function _emnoti_get_time_of_login(){
		$time_of_login = date('l F Y');
		return $time_of_login;
	}
#   Get the IP of the user that logged themselves as admin

	function _emnoti_get_ip(){
		$sources = array(
	'REMOTE_ADDR',
	'HTTP_X_FORWARDED_FOR',
	'HTTP_CLIENT_IP',
);
	foreach ($sources as $source) {
		if(!empty($_SERVER[$source])){
			$ip = $_SERVER[$source];
		}
	}
	return $ip;
	}

#   Email all the info above to a pointed email address
	function emnoti_send_email($user_login, $user){
		if(_emnoti_check_if_admin() === true){
		//	print _emnoti_get_time_of_login();
		//	print _emnoti_get_ip();
			wp_mail("MY EMAIL!", "Test subject", 'test body');
		}
	}

add_action('wp_login', 'emnoti_send_email', 10, 2);

?>

Not Able To Login - Help Me Disable Admin Check In The Code Below

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<?php
session_start( );
include_once( dirname( __FILE__ )."/../inc/func/get_sth.php" );
include_once( _ABSPATH_."/inc/func/header.php" );
if ( $_GET["f"] == "login" )
{
$adminuser = strtolower( strip_tags( trim( $_POST["adminuser"] ) ) );
$r_0 = strtolower( strip_tags( trim( $_SESSION["r"] ) ) );
$r_1 = strtolower( strip_tags( trim( $_POST["r"] ) ) );
if ( $r_0 == $r_1 )
{
$result = mysql_query( "SELECT password FROM admin where adminuser='".$adminuser."'" );
$val = mysql_fetch_array( $result );
if ( !$val["password"] )
{
$loginfail = 1;
}
else
{
if ( $val[password] === md5( $_POST["password"] ) )
{
$_SESSION['admin'] = $adminuser;
header( "Location: ./" );
exit( );
}
$loginfail = 1;
}
}
else
{
$loginfail = 2;
}
}
$page_title = l( "Administration Login" )." | ".get_sitename( );
$smarty->assign( "page_title", $page_title );
$smarty->assign( "loginfail", $loginfail );
$smarty->display( "mgt/login.tpl" );
?>

Admin Login Form For E-comm Site

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Hey guys,

I'm kind of a n00b with PHP and i'm trying to practice by building a mock e-comm site, but i'm having a problem with my admin login form. When the information is submitted the form just clears and doesn't redirect me to the index.php file i have set-up. My knowledge of php isn't where i'd like it to be yet, so i'm here for help! I'll post the code for bpoth the admin login page and the index.php file.

ADMIN LOGIN PAGE
|
|
V
<?php
session_start();
if (isset($_SESSION["username"])) {
header("location: index.php");
exit();
}

?>
<?php

if (isset($_POST["username"]) && isset($_POST["password"])){

   $username = $_POST["username"]; // filter everything but numbers and letters
$password = $_POST["password"]; // filter everything but numbers and letters

include "../storescripts/connect_to_mysql.php";
$sql = mysql_query("SELECT id FROM admin WHERE username='$username' AND password='$password' LIMIT 1");

$existCount = mysql_num_rows($sql); // count the row nums
if ($existCount == 1) { // evaluate the count
     while($row = mysql_fetch_array($sql)){
$id = $row["id"];
       }
       $_SESSION["id"] = $id;
       $_SESSION["username"] = $username;
       $_SESSION["password"] = $password;
       header("location: index.php");
exit();
} else {
      echo 'That information is incorrect, try again <a href="index.php">Click Here</a>';
      exit();
   }
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
   <head>
      <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
      <title>Store Admin Area</title>
<link rel="stylesheet" type="text/css" href="../css/main_style.css" />
   </head>

   <body>
<div id="wrapper">
<div id="text"><br />
   <div align="left" style="margin-left:100px; margin-top:100px;">
      <h2>Please Login To Manage The Store</h2>
<br /><br />
      <form id="form1" name="form1" method="post" action="admin_login.php">
<strong>Username</strong>
   <input name="username" type="text" id="username" size="40" />
<br /><br />
<strong>Password</strong>
   <input name="password" type="password" id="password" size="40" />
<br />
<br />
   <input type="submit" name="button" id="button" value="Login" />
</form>
   </div>
   </div>
   </body>
</html>

INDEX.PHP FILE
|
|
V

<?php
session_start();
if (!isset($_SESSION["username"])) {
header("location: admin_login.php");
exit();
}

$usernameID = preg_replace('#[^0-9]#i', '', $_SESSION["id"]);
$username = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["username"]);
$password = preg_replace('#[^A-Za-z0-9]#i', '', $_SESSION["password"]);

include "../storescripts/connect_to_mysql.php";
$sql = mysql_query("SELECT * FROM admin WHERE id='$usernameID' AND username='$username' AND password='$password' LIMIT 1"); // query the person

$existCount = mysql_num_rows($sql); // count the row nums
if ($existCount == 0) { // evaluate the count
    echo "Your login session data is not on record in the database.";
exit();
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
   <head>
      <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
      <title>Store Admin Area</title>
<link rel="stylesheet" type="text/css" href="../css/main_style.css" />
   </head>

   <body>
      <div id="wrapper">
<div id="text"><br />
   <div align="left" style="margin-left:100px; margin-top:100px;">
      <h2>Hello store manager, what would you like to do today?</h2>
      <p><a href="inventory_list.php">Manage Inventory</a><br />
      <a href="#">Manage Blah Blah </a></p>
   </div>
   <br />
<br />
<br />
</div>
   </body>
</html>

Any help and suggestions are greatly appreciated! Thanks!

One Login Form Can Differentiate User Or Admin

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Login.php

Code: [Select]
<?php
    mysql_connect("localhost","root") or die(mysql_error());
    mysql_select_db("Regis") or die(mysql_error());

     if (isset($_POST["sub"]))
     {
        $_POST['pass'] = md5($_POST['pass']);
      if (!get_magic_quotes_gpc())
       {
        $_POST['username'] = addslashes($_POST['username']);
        $_POST['pass'] = addslashes($_POST['pass']);
      }

       $usercheck = $_POST["username"];

       $check = mysql_query("SELECT username FROM registration WHERE username = '$usercheck'") or die(mysql_error());

       $check2 = mysql_num_rows($check);
        //if the name exists it gives an error
     if ($check2 != 0)
     {
      echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('Sorry, the username" ." ".$usercheck." ". "is already in use.')</SCRIPT>");
      echo ("<SCRIPT LANGUAGE='JavaScript'>setTimeOut(window.location = 'registration.php',1)</script>");

     }

      else if($_POST['username'] && $_POST['pass'] && $_POST['pass2'] )
     {
      $insert = "INSERT INTO registration (username, password) VALUES ('".$_POST['username']."', '".$_POST['pass']."')";
      $add_member = mysql_query($insert);
      echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('Registration had been succesfully added :)')</SCRIPT>");
     }

     }

?>

<html>
<head>
<script type="text/javascript">
function a()
{
var x = document.login.username.value;
var y = document.login.pass.value;

if(x==""&& y=="")
{
alert("Please insert all message!");
return false;
}
if(x=="")
{
alert("Please insert an username!");
return false;
}
if(y=="")
{
alert("Please insert an password!");
return false;
}
}
</script>
</head>
<body>
<table border="0">
<form name="login" method="post" action="form2.php" onsubmit="return a()">
<tr><td colspan=2><h1>Login</h1></td></tr>
<tr><td>Username:</td>
<td><input type="text" name="username" maxlength="40"></td></tr>
<tr><td>Password:</td>
<td><input type="password" name="pass" maxlength="50"></td></tr>
<tr><td><input type="submit" name="submit" value="Register"></a></td>
<td><input type="submit" name="submit" value="Login"></td></tr>
</form>
</body></html>

form2.php

Code: [Select]
<?php
mysql_connect("localhost","root") or die(mysql_error());
mysql_select_db("cute") or die(mysql_error());
$message=$_POST['message'];
$n=$_POST['username'];

if(isset($_POST['submit'])) //if submit button push has been detected

{

   if(strlen($message)>1)
   {
      $message=strip_tags($message);
      $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP
      $checkforbanned="SELECT IP from ipbans where IP='$IP'";
      $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS");

    if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list
    {
     print "You IP is banned from posting.";
    }

    else
    {
     $thedate = date("U"); //grab date and time of the post
     $insertmessage="INSERT into chatmessages (name,IP,postime,message) values('$n','$IP','$thedate','$message')";
     mysql_query($insertmessage) or die("Could not insert message");
    }
   }
}

?>
<html>
<head>
<script type="text/javascript">
function addsmiley(code)
{
var pretext = document.smile.message.value;
this.code = code;
document.smile.message.value = pretext + code;
}

function a()
{
var x = document.smile.message.value;
if(x=="")
{
alert("Please insert an message!");
return false;
}

}

</script>
<style type="text/css">
body{ background-color: #d8da3d }
</style>
</head>
<body>
<form name="smile" method="post" action="form2.php" onSubmit="return a()" >
Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br>
<img src="smile.gif" alt=":)" onClick="addsmiley(':)')" style="cursor:pointer;border:0" />
<img src="blush.gif" alt=":)" onClick="addsmiley('*blush*')" style="cursor:pointer;border:0" />
<input type="hidden" name="username" value="<?php echo $n;?>">
<input type='submit' name='submit' value='Send' class='biasa' ></form>

<br> <br>
</body>
</html>

My problem is in login.php in form section, can one form can be used user or admin because just now im doing is for user if user login it goes to form2.php but im want also in the same form if admin the form post to form3.php any way to do that thank you

How To Make The Session Login Both User And Admin Can Be View

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Login.php

Code: [Select]
<?php
    session_start();
    mysql_connect("localhost","root") or die(mysql_error());
    mysql_select_db("cute") or die(mysql_error());
    $username = $_POST['username'];
    $password = $_POST['pass'];
    if (isset($_POST["submit"]))
    {
     $log = "SELECT * FROM regis WHERE username = '$username'";
     $login = mysql_query($log);
     $row = mysql_fetch_array($login);
     $number = mysql_num_rows($login);
     if ($number > 0)
     {

        $_SESSION['username'] = $row['username'];
        $_SESSION['userlevel'] = $row['userlevel'];


        if($_SESSION['userlevel']==1)
       {
        $_SESSION['is_logged_in'] == 1;
        header("Location: form2.php");
       }
        else if($_SESSION['userlevel']== 0)
       {
         $_SESSION['is_logged_in'] == 1;
         header("Location: registration.php");
       }
     }

Registration.php

Code: [Select]
<?php
echo 'Welcome:' .$_SESSION['is_logged_in'];?>
form2.php

Code: [Select]
<?php
session_start();
if (empty($_SESSION['is_logged_in']))
{
header("Location:chatframe.php");
die();     // just to make sure no scripts execute
}
?>
<?php
mysql_connect("localhost","root") or die(mysql_error());
mysql_select_db("cute") or die(mysql_error());
$message=$_POST['message'];
$a=$_SESSION['username'];

if(isset($_POST['submit'])) //if submit button push has been detected

{

   if(strlen($message)>1)
   {
      $message=strip_tags($message);
      $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP
      $checkforbanned="SELECT IP from ipbans where IP='$IP'";
      $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS");

    if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list
    {
     print "You IP is banned from posting.";
    }

    else
    {
     $thedate = date("U"); //grab date and time of the post
     $insertmessage="INSERT into chatmessages (name,IP,postime,message) values('$a','$IP','$thedate','$message')";
     mysql_query($insertmessage) or die("Could not insert message");
    }
   }
}

?>
<html>
<head>
<script type="text/javascript">
function addsmiley(code)
{
var pretext = document.smile.message.value;
this.code = code;
document.smile.message.value = pretext + code;
}

function a()
{
var x = document.smile.message.value;
if(x=="")
{
alert("Please insert an message!");
return false;
}

}

</script>
<style type="text/css">
body{ background-color: #d8da3d }
</style>
</head>
<body>
<form name="smile" method="post" action="form2.php" onSubmit="return a()" >
Your message:<br><textarea name='message' cols='40' rows='2'></textarea><br>
<img src="smile.gif" alt=":)" onClick="addsmiley(':)')" style="cursor:pointer;border:0" />
<img src="blush.gif" alt=":)" onClick="addsmiley('*blush*')" style="cursor:pointer;border:0" />
<input type='submit' name='submit' value='Send' class='biasa' ></form>

<br> <br>
</body>
</html>
In this registration.php when im called back its appear nothing im means the number is not showing and the login code even im had also put the "$_SESSION['is_logged_in'] == 1;" outside if else userlevel statement and then i put $d= $_SESSION['is_logged_in'] == 1; and im echoing back but it is nothing im thinks something wrong in session is login

and also still it cannot redirect to admin -form2.php when session is login in is 1

Password Protected Pages / Simple Admin Login With Php

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Hello everyone:

I wanted to see how I can make a simple login page (user name and password) that redirects to a page(s) if the login is correct. Also, I wanted to put protection on the page(s) that will send the user back to the login page if the credentials are nor correct.

I would imagine the username/password would be stored in a database table (Admins), and the correct login info would be stored in a session ..?

I am use to doing this with ASP, but never PHP. I want to make sure I understand how to do this properly and securely so I can use this as a model for other systems.

In ASP I would do a protected page like this:
a_login_check.asp
Code: [Select]
<%
if session("admin_user_name") = "" then
session.abandon
response.redirect "login.asp"
end if
%>

Protected-Page.asp
Code: [Select]

<html>
...
CONTENT

...
</html>

And of course there is the login page itself ...
(I thought it would be nice to add a "Forgot Password" link on the login page, but if that is too complicated I can do that later .. or is it easy ??)

Anyway, can someone point-out to me how to do this.

I would appreciate it!

Login Script With Level User And Admin Gives Blank Page

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Hi guy's,

I'm having problems adjusting a script to add a level (user rights) function. When i login with a admin or normal user it gives a blank page (not redirecting to home.php). It even does'nt return an echo that user / pass is incorrect. I'm breaking my head over this for day's now. Can you help me out?

Code: [Select]
<?php
session_start();

//Login form (index.php)

include "db_connect.php";
if(!$_POST['submit'])
{
?>

<html>
<head>

<![if !IE]>
<link rel="stylesheet" type="text/css" href="firefox.css" />
<![endif]>
</head>
<body>
<div id="wrapper">
<div id="header">
<?php include('header.php'); ?>
</div>
<div class="divider">

<strong>Login</strong>
<form method="post" action="index.php">

<div class="formElm">
<label for="username">Klantnummer:</label>
<input id="username" type="text" name="username" maxlength="16">
</div>

<div class="formElm">
<label for="password">Wachtwoord:</label>
<input type="password" name="password" maxlength="16">
</div>

<input type="submit" name="submit" value="Login">
</form>

</div>
<div id="footer">
<?php include('footer.php'); ?>
</div>
</div>
</html>

<?php
}
else
{
  $user = protect($_POST['username']);
  $pass = protect($_POST['password']);
  $level = protect($_POST['level']);

if($user && $pass && $level)
{
$pass = md5($pass); //compare the encrypted password
$sql1 ="SELECT id,username FROM `users` WHERE `username`='$user' AND `password`='$pass' AND `level`='1'";
$sql2 ="SELECT id,username FROM `users` WHERE `username`='$user' AND `password`='$pass' AND `level`='9'";
$queryN=mysql_query($sql1) or die(mysql_error());
$queryA=mysql_query($sql2) or die(mysql_error());

if(mysql_num_rows($queryN) == 1)
    {
      $resultN = mysql_fetch_assoc($queryN);
  $_SESSION['id'] = $resultN['id'];
      $_SESSION['username'] = $resultN['username'];
header("location:home.php");
    }
    elseif(mysql_num_rows($queryA) == 1)
    {
      $resultA = mysql_fetch_assoc($queryA);
  $_SESSION['id'] = $resultA['id'];
      $_SESSION['username'] = $resultA['username'];
header("location:home.php");
}

else{
echo "Wrong Username or Password";
}
}
}
?>
and the mysql code:

Code: [Select]
CREATE TABLE `user` (
`id` int(4) unsigned NOT NULL auto_increment,
`username` varchar(32) NOT NULL,
`password` varchar(32) NOT NULL,
`level` int(4) default '1',
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=27 DEFAULT CHARSET=latin1;

Inserting Values From Admin To User Then User Add Value And Admin See It

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hello. I need your help please. I'm building logistics website with user panel and admin panel. I've done all login and register forms. now I want to : admin can add package with: tracking number , weight , cost , and declaration form. user can fill declaration form after admin add package to user panel. then admin can see the declared form. is it possible in php? thank you in advance

Php Admin Dashboard

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Hello,

Do you know where I can download a nice looking PHP admin dashboard for free?

Thanks in advance for the help

Admin Check

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Hey guys, I've set up a database with a login and logout script for my site..

There is a TINYINT value called admin and it either equals 1 or 0 depending on whether the user is an admin or not..

The registration script works perfectly to create the table value and the login script works fine for the site..

The question I had was if I wanted to add a link to the bottom of every page that said:

Go to Administration Panel and make it only viewable by ADMINS I figured this little script would work..

Here would be the end of the page:
Code: [Select]
<br />
<center>Copyright &copy 2010 <a href="http://www.website.com">www.WEBSITE.com</a></center>

<?php include('includes/start_admincheck.php'); ?>
<center><a href="<?php echo $homedir .'admin.php'; ?>">Go to Administration Panel</a></center>
<?php include('includes/end_admincheck.php'); ?>

</body>

</html>
Inside start_admincheck.php I have:

(NOTE: $cUsername refers to a setcookie and $cAdmin does as well.. They are defined on my Variable page included at the top.)
Code: [Select]
<?php include('variables/variables.php'); ?>

<?php
  mysql_connect("$mysql_hostname", "$mysql_username", "$mysql_password") or die(mysql_error());
  mysql_select_db("$mysql_database") or die(mysql_error());

  if(isset($cUsername))
  {
    $check = mysql_query("SELECT * FROM users WHERE username = '$cUsername'")or die(mysql_error());

    while($info = mysql_fetch_array( $check ))
    {
      if (($cAdmin == 1) && ($info['admin'] == 1))
      {
?>
And this is the end_admincheck.php
Code: [Select]
<?php include('variables/variables.php'); ?>

<?php
      }

      else
        die();
    }
  }
  else
    die();
?>
?>
I get this Parse error thrown at the bottom of the page:

Code: [Select]
Parse error: syntax error, unexpected $end in /*******/includes/start_admincheck.php on line 15
Naturally I would checkout line 15 in start_admincheck.php, but normally when I get an $end error it is the last line of the code and leaves me lost..

Something I'm missing guys?

As always, thanks in advance

Help With A Admin Panle

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So i got my login down and the cookies, kinda set up
my problem is how do i make the admin panle save the true/false in the string in settings.php
id like do do it with a drop down menu to enable/disable it.
any help?

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