|
PHP - Turning A .txt File Into An Array
I am trying to turn a .txt file into an array, count the items in the array, and display a random quote from it.
<p class = "center">
<?php
$Proverb = file('../proverbs.txt');
$ProverbCount = count($Proverb);
echo rand(0, $ProverbCount-1);
?>
<br>
© 2014
</p>
The issue I am having is that it states the file does not exist:
FULL PATH: G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\Includes\inc_footer.php
TEXT FILE: G:\EasyPHP-5.3.2i\www\PHP_Projects\ChineseZodiacs\proverbs.txt
Please help, thank you.
Similar TutorialsHey i'm having trouble figuring out how to do this. This is the code grabbing the users who are online and listing them one by one. Code: [Select] $qt=mysql_query("SELECT username FROM users WHERE lastvisit > '$tm' and online='ON'"); echo mysql_error(); while($nt=mysql_fetch_array($qt)){ echo "<tr><td> $nt[username] </td></tr>"; } ?> what i want to do is have each username be a hyperlink that links to their profile how would i go about this? cause i'm completely clueless on this. is there some way i can do it in the php or will i need to make a varchar column for each player that holds their profile link and grab that with the query too? having a problem turning this sql into a query and I need it to only update rows where id field is empty. Code: [Select] UPDATE systems SET naqahdah = naqahdah + naqahdah_mines * 2 I tried this out with failure Code: [Select] <?php mysql_query("UPDATE systems SET naqahdah= naqahdah + naqahdah_mines * 2 WHERE id <> ' ' "); ?> so i tried getting rid of WHERE and couldnt even get this to work. I tested the sql out it works fine. Code: [Select] <?php mysql_query("UPDATE systems SET naqahdah= naqahdah + naqahdah_mines * 2 "); ?> I got a tab menu, where the user choose his category and a list of sub categories appear. Personally I like the old fashion way, where everything listed like in craiglist.com ... How can I turn the following tab menu, into a simple 3 column list? <!--CATEGORIES--> <div id="selCategories"> <div class="slidetabsmenu menu_fix"> <ul> <?php if(isset($groups) and $groups->num_rows()>0) { $i=0; foreach($groups->result() as $group) { ?> <li id="gr<?php echo $i;?>" class="<?php if($i == '0') echo "selected"; ?>"><a href="javascript:;" onclick="getCat('<?php echo $i ?>','<?php echo $groups->num_rows ?>',<?php echo $group->id;?>);"><span><?php echo $group->group_name;?></span></a></li> <?php $i++;} } ?> </ul> </div> <div class="clsInfoBox"> <div class="block"> <div class="grey_t"> <div class="grey_r"> <div class="grey_b"> <div class="grey_l"> <div class="grey_tl"> <div class="grey_tr"> <div class="grey_bl"> <div class="grey_br"> <div class="cls100_p"> <h4><span class="clsCategory"><?php echo $this->lang->line('CATEGORIES');?></span></h4> <div class="clsCategoryList clearfix" id="catInner"> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> <!--END OF CATEGORIES--> Your tips, directions, and support is highly appreciated. Hi, I'm pretty new to PHP, struggled my way through most of my encounters with PHP so far, but getting the hang of it I'm looking for a simple script that turns a number or word served by a weather station into a graphic. E.g. If the temp is 20 degrees, a graphic I've designed would be shown, or a cloud or the sun or whatever. At the moment the weather station feed is converted from 'webtags' in to php tags (temp is $temp, wind is $wind etc.) and these echo out as numbers and words on the website. I can sort of see how it would work in my head, but need a little help. Can anyone please point me in the right direction? Thanks (for reference site is www.southtyneweather.co.uk) I recently had a need to check several arrays, and if an index wasn't set, set a variable to a given value. The code was such that I couldn't perform the isset check all at once. I then thought "wouldn't it be great if I could try the script, and catch the error or warning". Searching a bit, I came across the following script. I am a little nervous, however, that there might be negative consequences of doing so. Thoughts?
set_error_handler(function($errno, $errstr, $errfile, $errline, array $errcontext) {
// error was suppressed with the @-operator
if (0 === error_reporting()) {
return false;
}
throw new ErrorException($errstr, 0, $errno, $errfile, $errline);
});
try {
dns_get_record();
} catch (ErrorException $e) {
// ...
}
right now i have my date system to say "X amount of seconds ago, X hours ago, X days ago, X years ago, How could i turn mktime() (1290874161) into a mm/dd/yyyy format? so it would say like, "Nov 27, 2010 at Hour:Minute" (whatever the hour/minute is) I have got a date field in my mysql database with events, and as you know date in MYSQL uses yyyy/mm/dd but I would first like to turn this around to dd/mm/yyyy but also turn this into for example "Tuesday - May 1990" would anyone like to point me into the right direction? Much appreciated! Hi guys, I have written a page that contains a form. When the user chooses a color, it is posted, then the posted value is re-written as a filename, sent through a function, and the image on the page uses the "colorized.gif" created by the function to make an image swap "onclick. Problem is, no matter the choice, it always changes the picture to orange! Here is the code for the form: <?php include('function.php'); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>PHP GD CONFIGURATOR</title> </head> <body> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> Red<input type="radio" name="color" value="red" /> Orange<input type="radio" name="color" value="orange" /> Ivory<input type="radio" name="color" value="ivory" /> Black<input type="radio" name="color" value="black" /> <input type="submit" name="submit" value="submit" /> </form> <?php if($_POST['color'] != NULL){ echo $_POST['color']; $file =('gdimages/' . $_POST['color'] . '.gif'); createImg($file); } ?> <img src="default.jpg" name="lola" alt="lola dining chair" onclick="this.src = 'colorized.gif'" /> </body> </html> And here is the function... function createImg ($imgname1) { $base = imagecreatefromgif("gdimages/base.gif"); $top = imagecreatefromgif($imgname1); if ($top) { imagecopy($base, $top, 0, 0, 0, 0, 250, 250); imagejpeg($base, 'colorized.gif'); imagedestroy($base); } else{ header("Content-Type: text/html"); } } I really can't understand it...this is my first attempt at programming something new by myself...and I really need it to work!!! I also plan for this to work with combining more than 2 images from more than two choice menus...so debugging now is definitely necessary. Any suggestions? i run several wordpress on domains - and wthin the wordpress i have a plugin that allows uploads of images -within a certain plugin the interesting thing: image upload is - sometimes possible and sometinmes impossible: see here the circumstances - PHP Version : 5.3.28 PHP Safe Mode : On image upload is impossible - and on the same server - a second vhost PHP Version : 5.3.28 PHP Safe Mode : off image upload is possible why is this so - does it have to do with the safe-mode - say I have a file, it has information in it in this format 123489 ABDFDS 232356 DSFKWE and so on, new number and letters on each line separated by a space, what do I have to do so that like 123489 and 232356 would be in the aray numbers[] and the ABDFDS and DSFKWE would be phrases[] any ideas? Thanks I am trying to use the variable $RATETHESE to include an array into file A. The array is in file B. PhP File A include_once(dirname(__FILE__) . '/PhpFileB.php'); global $RATETHESE; $VALID_RATING_IDS = $RATETHESE; Php File B $RATETHESE = "array("1", "2");" For some reason it is printing the array on the page, and the array is not being used to run the script. Did i do anything wrong? Hello I was trying from days to create an array from a txt file by i can't make it happen. I am so desperate now and i want your help guys The code create a txt file from a textarea feild after it's submited each on a line. After that the php code need collect these data from the txt file and create an array from them. Example: if i type in the textarea: test test1 test2 I want these usernames to be inserted in the array so it would be like this: $names = array('test','test1','test2'); Anyone can help me This is the code <html> <head> <title></title> <style type="text/css"> body{ background-color:#1166aa; } #mainbox{ width:inherit; background-color:#FFFFFF; padding:14px; border:solid 3px #000000; float:left; } #mainbox2{ background-color:#CCCCCC; border:solid 2px #000000; padding:11px; } #contaner{ border:solid 0px #00FF00; } h1:hover{ color:#0000CC; cursor:pointer; } #msg{ cursor:pointer; } table td{ border-top:outset 1px #999999; } #amount{ color:#FF0000; cursor:crosshair; } #to{ color:#3300FF; } #from{ color:#3300FF; } #subject{ color:#3300FF; } </style> </head> <body alink="#003399" vlink="#003399"> <?php ///////////////////////////////////////////////// function create_list(){ $list= ($_GET ['name_list']); $file= "list.txt"; $file_pointer = fopen($file ,'w'); fwrite($file_pointer , $list); fclose($file_pointer); } ////////////////////////////////////////////////// $list= ""; create_list(); ////////////////////////////////////////////////// function explodeRows($data) { $rowsArr = explode("\n", $data); return $rowsArr; } $filename = "list.txt"; $handle = fopen($filename, 'r'); $data = fread($handle, filesize($filename)); $rowsArr = explodeRows($data); for($i=0;$i<count($rowsArr);$i++) { $name = explodeRows($rowsArr[$i]); function name(){ $names = array('the usernames submited to be inserted here','the usernames submited to be inserted here',.......); } } //////////////////////////////////////////////////// if ($_GET ['submit'] == "submit"){ create_list(); name(); } ?> <script type="text/javascript"> function foo(textarea,limit){ var val=textarea.value.replace(/\r/g,'').split('\n'); if(val.length>limit){ alert('You can not enter\nmore than '+limit+' lines'); textarea.value=val.slice(0,-1).join('\n') } } </script> <table align="center" id="contaner"> <tr><td> <form action="<?php $_SERVER [SERVER_NAME]; ?>" method="get"> <div id="mainbox"> <div id="mainbox2"> <table> <tr> <td>name List :</td> </tr> </table> <textarea id="name_list" name="name_list" cols="60" rows="9" onkeyup="foo(this,50)"></textarea> </div> <tr> <td><center><input name="submit" type="submit" value="submit"/></center></td> </tr> </div> </form> </tr></td> </table> </body> </html> I got two values from a form in a page by POST method. Now I want to add this values to a text file. The code of form1.htm is like this: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> </head> <body> <form action="write1.php" method="post"> <fieldset> <legend>Log In...</legend> <input type="text" name="uname" /><br> <input type="text" name="pass" /><br><br> <input type="submit" name="button" value="Log In" /> </fieldset> </form> </body> </html> And the code of write1.php is like this: <?php function arr_func() { $name = $_POST['uname']; $pass = $_POST['pass']; //trying to catch values in an array $arr[] = array("name"=>"$name", "pass"=>"$pass"); foreach ($arr as $val_arr) { foreach ($val_arr as $key=>$val) { echo "$key - $val<br>"; } echo '<br>'; } } $arr1 = arr_func(); //values are printed, no problem echo $arr1; //trying to change the array into string, is it wrong approach? $var1 = strval($arr1); // set file to write $file = 'student/dump.txt'; // open file $fh = fopen($file, 'w') or die('Could not open file!'); // write that variable into file fwrite($fh, "$var1\n") or die('Could not write to file'); // close file fclose($fh); ?> After log in in form1 I get two values of $name and $pass in write1.php but no values being added to the file mentioned in the path. Here is a section of php file A include_once(dirname(__FILE__) . '/PhpfileB.php') $VALID_RATING_IDS = $Ratethese Here is all of php file B $Ratethese = "array("1", "2",);" I need the var $VALID_RATING_IDS to = $Ratethese from file B I am trying to include an array from php file B in php file A. Is this possible? How can i accomplish this? Hello I am tring to import a .txt file into an array. I am stuck will somone please help me. ?<php $fp = fopen("ArrayTestFile.txt", 'wb'); $X = fread("ArrayTestFile.txt" 'w'); for ($j = 0 ; $j < 6 ; ++$j) { $written = fwrite($fp, "ArrayTestFile.txt"); if ($written == FALSE) break; } print $fp[0] . " " . $fp[1] . " " . $fp[2] . " " . $fp[3] . " " . $fp[4]; fclose($fp); ?> <?php $file = 'test.txt'; $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); preg_match_all('/id="r4_([\d]+)">/', $lastfm, $matches); file_put_contents($file, $matches[1]); sleep(100000); ?> That puts the array in a file but I need each value on a new line but it bunches it all up.. this just puts "Array" in file [php] <?php $file = 'test.txt'; $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); preg_match_all('/id="r4_([\d]+)">/', $lastfm, $matches); file_put_contents($file, $matches[1]."\n"); sleep(100000); ?> what do I need to do to print all of the values on a new line? Thanks Hello,
I have been assigned a PHP problem for my programming class. I'm a beginner so I am finding it really hard to figure out what to do. I got this far thanks to the internet. The problem is to take a list of students, place it in a multidimensional array, sort it, then divide it in half and place each half in two new files. I can't seem to figure out the last step. This is my code so far:
<?php
$students=array_map('str_getcsv', file('student.txt'));
foreach ($student as $key => $row) $lastname [$key] = strtolower ($row[2]);
array_multisort($lastname, SORT_ASC, $students);
$groupone= array_slice($students,0,10);
$grouptwo=array_slice($students,10);
echo "<pre>" , print_r($groupone), "</pre>";
echo "<pre>" , print_r($grouptwo), "</pre>";
$firstgroup=fopen(firstgroup.txt, "w");
echo fwrite ($firstgroup,$groupone);
fclose($firstgroup);
At this point I get an error because I should use a string not an array to write the new file.
I don't actually know how to create a new file and export the information onto it, this is me guessing.
I would really really appreaciaite it if someone could help me out or point me in the right direction.
Thank you so much,
Camilla
Ok I need to write an array to a file here is the code if($place[2] < 10){ echo "Account Invalid"; $account = var_dump($account_data[$i][0]); echo $account; $fp3=fopen('invalid.txt', 'a+'); fwrite($fp3, $account); fclose($fp3);} when I try if($place[2] < 10){ echo "Account Invalid"; $account = var_dump($account_data[$i][0]); echo $account; $fp3=fopen('invalid.txt', 'a+'); fwrite($fp3, $account_data[$i][0]); fclose($fp3);} I just get "Array[1]" written to the file.. What can I do to write the array to the file? Thanks |
|||||||