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PHP - Help With Php Widget Link
Hi all,
I've got a problem with a php code on my website. I don't know why, but the hyperlink is wrong, because it's taken also the link of the current page, before the one of the page of destination. (see the attachment)
Where is the mistake?
Thanks all for the help
$post_id = $instance['posts_name'];
$title = apply_filters('widget_title', $instance['title']);
if ( empty($title) )
$title = false;
echo '<div class="widget top-story">';
if ( $title )
echo $before_title . $title . $after_title . "\n"; ?>
<div>
<?php $post = get_post( $post_id ); ?>
<a href="<?php echo $post->post_name; ?>" class="image"><?php echo get_the_post_thumbnail( $post_id, 'top-story'); ?><span class="comment-icon"><?php echo $post->comment_count; ?></span></a>
<span><?php the_time('d.m.Y | g:i A'); ?></span>
<span class="rating"><a href="#" class="active"></a><a href="#" class="active"></a><a href="#"></a><a href="#"></a><a href="#"></a></span>
<p><a href="<?php echo $post->post_name; ?>"><?php echo $post->post_title; ?></a></p>
</div>
<?php echo '</div>';
}
/* Update widget settings */
function update( $new_instance, $old_instance ) {
$instance = $old_instance;
$instance['title'] = strip_tags( $new_instance['title'] );
$instance['posts_name'] = $new_instance['posts_name'];
return $instance;
}
/* Widget form */
function form( $instance ) {
$defaults = array(
'title' => '',
'posts_name' => '',
);
$instance = wp_parse_args( (array) $instance, $defaults ); ?>
<p>
<label for="<?php echo $this->get_field_id( 'title' ); ?>">Title:</label>
<input type="text" class="widefat" id="<?php echo $this->get_field_id( 'title' ); ?>" name="<?php echo $this->get_field_name( 'title' ); ?>" value="<?php echo $instance['title']; ?>" />
</p>
<p>
<label for="<?php echo $this->get_field_id('posts_name'); ?>">Choose Post:</label>
<select name="<?php echo $this->get_field_name('posts_name'); ?>" id="<?php echo $this->get_field_id('posts_name'); ?>" class="widefat">
<?php $posts_array = get_posts( array('numberposts' => -1) ); ?>
<?php foreach( $posts_array as $post ) : setup_postdata($post); ?>
<option value="<?php echo $post->ID; ?>"<?php selected( $instance['posts_name'], $post->ID ); ?>><?php echo $post->post_title; ?></option>
<?php endforeach; ?>
</select>
</p>
<?php
}
}
Edited by AV88, 18 October 2014 - 06:39 AM. Similar TutorialsHello everyone, I have created a widget with php which allows users to put on their webpage and displays some information. To display the widget I am creating a javascript code for users to put on their websites. The javascript has a source of php page like src="widget.php?id=123" When they put the code on their websites php file is executed and displays some texts which is read from a remote XML file. There is no problem up to this point. But while I am reading from this XML file, the texts which are displayed on users webpage, are not in good format becouse I am converting string texts to ISO_8859-9 charset with "iconc" function. If the charset of webpage is ISO-8859-9 text are displayed correctly but if it is not, text are not displayed as expected. In example if the webpage charset is set to UTF-8, characters become unreadable. If I know the charset of webpage I can then convert strings to that charset. But could not find a predifined function thats doing this. Any idea about this problem ? or any other solutions you advice for this problem ? Thank you... Hi All I am trying to insert a feed on my site that automatically updates the football league etc like this one http://news.bbc.co.uk/sport1/hi/football/eng_div_1/table/default.stm is there a way to do this please? thanks Hello.
I have a bit of a problem. When I fetch the link field from the database.i don't see an actual link on the page.
One more thing, what type of field should I use to store the link in the database? Probably there is where I went wrong.
All help is
Hi I've got this database I created with fields ProductId ProductName Image I've managed to get it to list the ID,productname, and Image urls in a list. My next step is to have the image field actually display an image and make it clickable: heres what I've done so far: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("productfeed", $con); $result = mysql_query("SELECT * FROM productfeeds"); echo "<table border='0'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Image</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; echo "<td>" . $row['ImageURL'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Heres what I want to do: Code: [Select] while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; // my changes beneath echo "<td>" . <a href="<?php echo $row['ImageURL'];?>"> <img src="<?php echo $row['LinkURL']; ?>"> </a>. "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Can you guys point me in the right direction? Many thanks Hi Support, I have a form, where it collects user description input. I can collect the inputs and store it with newline. The issue is - how to collect the http link to actual hyperlink ref during display. The following is my code: <textarea name="description" cols="50" rows="10" id="description"><?php echo str_replace("<br>", "\n", $description);?></textarea></td> For example, User input: Hi, Check it out - http://www.google.com/ I would like to display google link as href so that Viewers can click the link and go to the page. Right now, it is not href and user need to copy the link to new tabs or pages and then it can come. Thanks for your help. Regards, Ahsan hi hope you all are fine. i have been working on a Email Form (like user fills up the form which send the information to our email) but i was having problem with (URL field i created) link of form is (http://services.shadowaura.com/allquotations/static.php) field which is not working is "Inspirational Website:" when i submit the form it says (Forbidden You don't have permission to access /allquotations/staticworking.php on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.) Can some one help me out ????????????? code behind this form is: Code: [Select] <?php /* Email Variables */ $emailSubject = 'Shadow Aura Contact Info!'; $webMaster = '*****@shadowaura.com'; /* Data Variables */ $Name = $_POST['Name']; $email = $_POST['email']; $Cell = $_POST['Cell']; $Phone = $_POST['Phone']; $CompanyName = $_POST['CompanyName']; $TypeOfBusiness = $_POST['TypeOfBusiness']; $Address = $_POST['Address']; $YourBudget = $_POST['YourBudget']; $HaveDomain = $_POST['HaveDomain']; $RunningWeb = $_POST['RunningWeb']; $WebLink = $_POST['WebLink']; $Inspiration1 = $_POST['Inspiration1']; $Inspiration2 = $_POST['Inspiration2']; $NumberPages = $_POST['NumberPages']; $UseFlash = $_POST['UseFlash']; $TimeFrame = $_POST['TimeFrame']; $Provided = $_POST['Provided']; $Comments = $_POST['Comments']; $body = <<<EOD <h1> Static Website Quotation </h1> <br> <b>Name of Client:</b>$Name<br> <b>Your Email:</b>$email<br> <b>Cell Number:</b>$Cell<br> <b>Line Phone Number:</b>$Phone<br> <b>Company Name:</b>$CompanyName<br> <b>Type of Business:</b>$TypeOfBusiness<br> <b>Address:</b>$Address<br> <b>Your Budget:</b>$YourBudget <br> <b>Do you have Domain:</b>$HaveDomain<br> <b>Your Site is Running:</b>$RunningWeb <br> <b>Website Link:</b><a href="$WebLink">$WebLink</a><br> <b>Inspiration:</b>$Inspiration1<br> <b>2nd Inspiration:</b>$Inspiration2<br> <b>Number of Pages:</b>$NumberPages<br> <b>Use Flash:</b>$UseFlash <br> <b>Time Frame:</b>$TimeFrame<br> <b>You will provide:</b>$Provided<br> <b>Comments:</b>$Comments<br> EOD; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; $success = mail($webMaster, $emailSubject, $body, $headers); /* Results rendered as HTML */ $theResults = <<<EOD <html> <head> <title>sent message</title> <meta http-equiv="refresh" content="3;URL=http://services.shadowaura.com/"> <style type="text/css"> <!-- body { background-color: #8CC640; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 20px; font-style: normal; line-height: normal; font-weight: normal; color: #fec001; text-decoration: none; padding-top: 200px; margin-left: 150px; width: 800px; } --> </style> </head> <div align="center">Your email will be answered soon as possible! You will return to <b>Shadow Aura Services</b> in a few seconds !</div> </div> </body> </html> EOD; echo "$theResults"; ?> here's my code that i've used to send an email. Code: [Select] $link = "<a href=\"http://www.example.com/" . $num . "\">" . $num . "</a>"; $query = "SELECT content FROM emails"; $result = mysql_query($query) or die(); $email_content = mysql_result($result, 0); $email = sprintf($email_content, $first, $name, $from, $link, $record, $rec, $inc, $max); $email_body = stripslashes(htmlentities($email, ENT_QUOTES, 'UTF-8')); // this is sent to another php script via post.... $subject = $_POST['subject']; $message = nl2br(html_entity_decode($_POST['email_body'])); $to = "me@whatever.com"; $charset='UTF-8'; $encoded_subject="=?$charset?B?" . base64_encode($subject) . "?=\n"; $headers="From: " . $userEmail . "\n" . "Content-Type: text/html; charset=$charset; format=flowed\n" . "MIME-Version: 1.0\n" . "Content-Transfer-Encoding: 8bit\n" . "X-Mailer: PHP\n"; mail($to,$encoded_subject,$message,$headers); in the db, emails.content is of the text type and contains several lines of text with %4$s which inserts the value of $link into the body. when the email arrives, there is a link and it appears fine, with the value of $num hyperlinked. however when you click on it it doesn't go anywhere. when copying the link location from the email it gives me x-msg://87/%22http://www.example.com/16 what is x-msg? how can i get this to work properly? Hi guys, I'm using a twitter script that grabs the title and publishings it like so: "Title - Read More at..." I was wondering how i would be able to post the direct link into twitter.. like news.php?id=1 for example. Code: [Select] $tweet->post('statuses/update', array('status' => ''.$_POST[title].' - more at MY URL')); This part is in the script to publish automatically when the users adds to the news database. How am i able to get the ID just after the posting of the news? Thanks! I have a line like this it prints text link but I prefer image link how should i edit it I would appreciate some feedback Code: [Select] $templates['etiket'] = array('name' => t('ETİKET'), 'module' => 'uc_invoice_pdf', 'path' => $templates_uc_invoice_pdf_path, 'pdf_settings' => $pdf_settings); I have a lovely RSS creation script which dynamically writes an RSS feed using the information from the database, which you can automatically update every time a blog entry (or anything else generated by a script) is added. The only issue with it, is that the Code: [Select] <strong> tags have had to be deleted using strip_tags() because the RSS doesn't like it. I want to keep the original formatting of the blog article but because I have to strip out the strong links, the hyperlinks are also removed. I don't know enough about RSS (IMHO) to work out how to put the links back in - do I need to format the STRONG tags differently, or do i need to change the PHP to str_replace() the strong tags with nothing? Here's some code that does work: Code: [Select] <item rdf:about="http://www.manteya.com/blog/Music-Improves-Productivity_24.html"> <title>Music Improves Productivity</title> <link>http://www.manteya.com/blog/Music-Improves-Productivity_24.html</link> <description>Research shows that music can improve speed of working within organisations. There is a double-edged sword to this article, however. Music with fast tempos can help the release of adrenalin and therefore increase the heart rate of the listener. Music producers here in the UK have taken advantage And here's some that doesn't: Code: [Select] <item rdf:about="http://www.manteya.com/blog/Music-Improves-Productivity_24.html"> <title>Music Improves Productivity</title> <link>http://www.manteya.com/blog/Music-Improves-Productivity_24.html</link> <description>Research shows that music can improve <strong>speed</strong> of working within organisations. There is a double-edged sword to this article, however. Music with fast tempos can help the release of adrenalin and therefore increase the heart rate of the listener. Music producers here in the UK have taken advantage I'm sure you geniuses (or geniei) can work it out, so any help would be very welcome indeed. Hi Everyone, So I am building a page that list records from a table, in this case customers, and I want to the printed last name (lname) of the record to be the link to the a detail php page that displays the detailed record. Any suggestions on how to do that? Here is what I'm using now. I don't like the button look, that's why i'm trying to make a link. Any Suggestions? Thanks <? session_start(); include 'menu.php'; include ("include/connect.php"); // how many rows to show per page $rowsPerPage = 10; // by default we show first page $pageNum = 1; // if $_GET['page'] defined, use it as page number if(isset($_GET['page'])) { $pageNum = $_GET['page']; } // counting the offset $offset = ($pageNum - 1) * $rowsPerPage; $sql = @mysql_query("SELECT * FROM customer ORDER BY id LIMIT $offset, $rowsPerPage"); $id = ''; echo "<table border='0' align='center'><tr><td align='left' colspan='2'>Last Name</td><td align='center'>Location</td><td align='right'>Date Posted</td></tr>"; while ($row = mysql_fetch_array($sql)) { if ($id != $row['id']) { echo "<tr><td><form action='customerdetail.php' method='post'><input type='hidden' name='locationp' value='{$row['location']}' /><input type='hidden' name='titlep' value='{$row['title']}' /><input type='hidden' name='idp' value='{$row['id']}' /><b><font size='4'><input type='submit' value='{$row['lname']}'></font></b></form></td><td> </td><td align='center'><b><font size='4'>{$row['location']}</font></b></td><td align='right'><b><font size='4'> {$row['datep']}</font></b> </td></tr><tr><td colspan='4'> </td></tr>"; $id = $row['id']; } } echo "</table>"; // how many rows we have in database $query = "SELECT COUNT(id) AS numrows FROM customer"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result, MYSQL_ASSOC); $numrows = $row['numrows']; // how many pages we have when using paging? $maxPage = ceil($numrows/$rowsPerPage); // print the link to access each page $self = $_SERVER['PHP_SELF']; // creating previous and next link // plus the link to go straight to // the first and last page if ($pageNum > 1) { $page = $pageNum - 1; $prev = " <a href=\"$self?page=$page\">[Prev]</a> "; $first = "<br><center> <a href=\"$self?page=1\">[First Page]</a> "; } else { $prev = ' '; // we're on page one, don't print previous link $first = '<br><center> '; // nor the first page link } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " <a href=\"$self?page=$page\">[Next]</a> "; $last = "<a href=\"$self?page=$maxPage\">[Last Page]</a></center> "; } else { $next = ' '; // we're on the last page, don't print next link $last = ' </center>'; // nor the last page link } // print the navigation link echo $first . $prev . " Showing page $pageNum of $maxPage pages " . $next . $last; // and close the database connection mysql_close($con) // ... and we're done! ?> This link dnt seem to work. Can someone help? echo "<td><a href =" . $rows['url'] .">"</a>"</td>"; Thankz. Hello dear friends, Let say we have Code: [Select] $to = "gigi"; then we have link like this Code: [Select] mysite.com/$to_$id.html with indeed .htaccess code Code: [Select] RewriteRule -(.*)\.htm file.php?id=$1 it will works , Now what if i want to make the link like this Code: [Select] mysite.com/$id/$to.html what will be the .htaccess code in this way ??? Hello dear friends, Let say we have Code: [Select] $space ="hello world"; then remove spaces between the words by using Code: [Select] $title = str_replace(' ', '-', trim($space)); so it would be here as "hello-world" and let say we have stored title,article text...whever in an database table that call back all this using id then for an article with id=1 its link will be Code: [Select] site.com/index.php?id=1 it is clear that the Code: [Select] echo "$id"; //<--- 1 now some wordpress or/and blogs using rewrite .htaccess to make the link as Code: [Select] site.com/$title-$id (as our example site.com/hello-world-1) then how they know its $id = 1 to get any variables from database that needs the id i've tried but never works and only works if i made something like Code: [Select] site.com/$title_$id //<-- site.com/hello-word_1 cause it needs difference separate in order to understand the id so how to make it ? how to make it understand that the last separated is the id thanks I'd like to put a password requirement in this program & an expiration date (database record)so that at 11 months I output an alert and at the end of one year it shuts down. ? The below code works for the password but I can't find how to link to my main page? PHP Code: <?php mysql_connect(localhost,root,""); mysql_select_db(entrydb) or die( "Unable to select database"); if(!empty($_POST["submit"])) { $password = $_POST['password']; $expdate = $_POST['expdate']; $query="SELECT password, expdate FROM entrydata Where password='$password'"; $result=mysql_query($query); if(mysql_num_rows($result)) { echo "<form action='#' method='post'>"; echo "</form>"; } else{echo "Access denied<br />";} } ?> <form method="post" action="#"><br /> <input type="text" name="password"/><p> <input type="submit" name="submit" value="enter password"/> </form> Please reply in simple terms, 'cause I'm simple! Hello all. If I have a list of links on a page like: >Manchester United >Manchester City >Aresnal How do I make clicking one of the links then query my database for that record? So I click on manchester united and the body of the page calls all the information on the database for that club? Surely I don't need each page to link to their own PHP page do I? The manchester united link doesn't need to point to manchester-united.php? Can I have all the links pointing to club.php that changes in content depending on the link that was clicked? How do I achieve this? What's this called? Please help! Thanks all in advance. I have problem, there are users with "?" character in username, and their address to profile is /profile/username/. I have var: $username that is that username, now, how can i replace all that characters which cant open users profile.. I mean for "?" i need to put "%3F", how can i replace? I know with str_replace, but is there any other solution like htmlencode or something like that? :S Just need a correction on this please, there is a Parse error, think I got the quote marks wrong somewhere? echo "<li>" . <a href="/stock/$stock.htm"> .$Stock . ": " . $Name . "</a></li>\n"; Thanks Hello friends. I'm needing a bit of help with some code. I have this code to show my users their referral link: (this code goes in the reg.php file) Code: [Select] if($_COOKIE['referido']) { $ref = $_COOKIE['referido']; } else { $ref = $do->get_r_file_url(); $ref = str_replace(array(".html", "/"), "", $ref); if(eregi('.php', $ref)) { $ref=false; } setcookie("referido", $ref, time()+60*60*24*30); } And then this one on the user's profile to show their referral URL: Code: [Select] $dp = $do->get_loc()."reg.php/{$signin_username}.html"; So the result is "mysite.com/reg.php/referral.html" and I want it to be "mysite.com/reg.php?referral" I just need to get rid of the "/" I've seen sites like "thesite.com/?r=referral" How can i do something like that? Thanks! Hello friends! I just need the last help to have everything working ok. I'm having an issue because the input won't show the referral ID. Here is the .htaccess code: /*This changes the URL mysite.com/reg.php/referral.html to mysite.com/reg.php?referral*/ Code: [Select] Options +FollowSymlinks RewriteEngine on RewriteRule ^reg.php/(.*)\.html$ http://www.mysite/reg.php?$1 Then the code in the reg.php page: Code: [Select] if($_COOKIE['referido']) { $ref = $_COOKIE['referido']; } else { $ref = $do->get_r_file_url(); $ref = str_replace(array(".html", "/"), "", $ref); if(eregi('.php', $ref)) { $ref=false; } setcookie("referido", $ref, time()+60*60*24*30); } And then the input: <input size='3' style='width:170px;' id='referral' type='hidden' name='6' value='{$ref}' > So how do I do to make the input show the referral ID? Thanks! |
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