PHP - Multi Page Forms, Losing The Session Variable
I'd describe myself as a "basic" php programmer....
I'm trying to build my first multi-page forms.
The first page is calculator_q1.php
No session variables are needed here, I have omitted a few options, the code looks like this
<form id="page1" method="post" action="calculator_q2.php"> <h1>1. Which best describes the primary and secondary sports combination that will be played on your pitch?</h1> <table> <tr><td>Rugby only</td><td><input type="radio" name="1_primary_secondary_combo" value="Rugby only"></td></tr> <tr><td>Rugby/Soccer</td><td><input type="radio" name="1_primary_secondary_combo" value="Rugby Soccer"></td></tr> <tr><td>Soccer/Hockey</td><td><input type="radio" name="1_primary_secondary_combo" value="Soccer Hockey"></td></tr> </table> <input class="blue" type="submit" value="Next"> </form>The 2nd page is calculator_q2.php. This has some php to start the session, copy the result of form 1 to a session var, I do a debug echo and the variable is printed correctly so I think have captured it correctly. In extract, I do this: <?php //Start the session session_start(); //Store our posted values in the session variables $_SESSION['1_primary_secondary_combo'] = $_POST['1_primary_secondary_combo']; ?> <?php $debug=True; if ($debug) { echo ("Debug: session for q1 = ".$_SESSION['1_primary_secondary_combo']); } ?> <form id="page2" method="post" action="calculator_q3.php"> <h1>2. Please choose a preferred surface</h1> <table> <tr><td>3G Rubber Crumb Filled Turf</td><td><input type="radio" name="2_preferred_surface" value="3G Rubber Crumb Filled Turf "></td></tr> <tr><td>Sand Filled Turf</td><td><input type="radio" name="2_preferred_surface" value="Sand Filled Turf"></td></tr> <tr><td>Sand Dressed Turf or<br>a Water Based Surface</td><td><input type="radio" name="2_preferred_surface" value="Sand Dressed Turf or a Water Based Surface"></td></tr> </table> <p> <script> function submitForm(action){ document.getElementById('page2').action = action; document.getElementById('page2').submit(); } </script> <input class="blue" type="button" onclick="submitForm('/calculator_q1.php')" value="Previous" /> <input class="blue" type="button" onclick="submitForm('/calculator_q3.php')" value="Next" /> </form>So far so good, but when I introduce page 3 (calculator_q3.php) then it prints the previous page's (from page 2) variable but can't find the session variable from question 1. This is from calculator_q3.php: <?php //Start the session session_start(); //Store our posted values in the session variables $_SESSION['2_preferred_surface'] = $_POST['2_preferred_surface']; ?> <?php $debug=True; if ($debug) { echo ("Debug: session for q1 = ".$_SESSION['1_primary_secondary_combo']); echo ("<br>Debug: session for q2 = ".$_SESSION['2_preferred_surface']); } ?> <form id="page3" method="post" action="calculator_q4.php"> <h1>3. Please choose one watering option</h1> <table> <tr><td>With a Rain Gun System</td><td><input type="radio" name="3_watering_option" value="With a Rain Gun System"></td></tr> <tr><td>With a Rain gun System + Water Borehole</td><td><input type="radio" name="3_watering_option" value="With a Rain gun System + Water Borehole"></td></tr> <tr><td>Not Required</td><td><input type="radio" name="3_watering_option" value="Not Required"></td></tr> </table> <p> <script> function submitForm(action){ document.getElementById('page3').action = action; document.getElementById('page3').submit(); } </script> <input class="blue" type="button" onclick="submitForm('/calculator_q2.php')" value="Previous" /> <input class="blue" type="button" onclick="submitForm('/calculator_q4.php')" value="Next" /> </form>To see this in action see: http://www.sports.ha...lculator_q1.php Any insights would be appreciated. Many thanks. Similar TutorialsI'm having an issue with holding a session variable in the statement below $Color is losing its value in the if statement. For example int the ( ) $Color is a zero while in the echo part $Color is being displayed correctly as Blue. SET UP: Windows vista # XAMPP 1.7.3, # Apache 2.2.14 (IPv6 enabled) + OpenSSL 0.9.8l # MySQL 5.1.41 + PBXT engine # PHP 5.3.1 # phpMyAdmin So I'm getting this error message: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '", )' at line 8. I can't see where the '", )' code is in that script. I've looked and contrl + find it but no joy. I've looked through the previous pages and mysql database to ensure the variables and the tables match up. Any help would be appreciated. Maybe some good mysql debug advice. Is there a good debug open source program out there? Any help would be appreciated. <?php //let's start our session, so we have access to stored data session_start(); include 'db.inc.php'; $db = mysql_connect('localhost', 'root', '') or die ('Unable to connect. Check your connection parameters.'); mysql_select_db('ourgallery', $db) or die(mysql_error($db)); //let's create the query $query = sprintf("INSERT INTO subscriptions ( name, email_address, membership_type, terms_and_conditions, name_on_card, credit_card_number, credit_card_expiration_data) VALUES ('%s','%s','%s','%s','%s','%s','%s')", $_SESSION['email_address'], $_SESSION['membership_type'], $_SESSION['terms_and_conditions'], $_POST['name_on_card'], $_POST['credit_card_number'], $_POST['credit_card_expiration_data']); //let's run the query mysql_query($insert_query); ?> Some code from my pages ,
Page1 ( Redirecting page )
<html> <title>login_redirect.</title> body> <form name="redirect" action="http://mysite/page2.php" method="post"> <input type="hidden" name="mac" value="$(mac)"> </form> <script language="JavaScript"> <!-- document.redirect.submit(); //--> </script> </body> </html>Page 2 ( select product ) <?php session_start(); ini_set('display_errors',1); error_reporting(E_ALL); include '../lib/config.php'; include '../lib/opendb.php'; // get user mac adres from redirect post page1 $_SESSION['macid'] = $_POST['mac']; // set $macid for other use ( maybe not needed, am learning ) $macid = $_SESSION['macid']; // echo $macid does show mac adress, so variable is not empty here if (!empty($_POST["submit"])) { $product_choice = $_POST['accounttype']; $query= "SELECT AccountIndex, AccountCost, AccountName FROM AccountTypes WHERE AccountIndex='$product_choice'"; $result = mysql_query($query) or die('Query failed. ' . mysql_error()); while($row = mysql_fetch_array($result)) { $_SESSION['AccountIndex'] = $row['AccountIndex']; $_SESSION['AccountCost'] = $row['AccountCost']; $_SESSION['AccountName'] = $row['AccountName']; } header('Location: page3.php'); } // did leave out the other/html/form stuff herePage 3 ( show Session variables ) <?php ini_set('display_errors',1); error_reporting(E_ALL); session_start(); print_r($_SESSION); ?>Now, on page 3 i do see the right session varables, only the "macid" is empty. why ? Afternoon, Not sure if i've been staring at the screen for too long or not, but have a log in script which saves the password as a session variable and I can pass that variable across my page like so: <?php session_start(); //Print_r ($_SESSION); echo "Erm, I have reached page.php and the password is ".$_SESSION['password']; ?> However, I want to make this secure, so I added a function to it which when you log in says if $_SESSION['password'] does not exist then send me away, like so: <?php session_start(); function checklogin() { session_start(); if(!isset($_SESSION['password'])) { header("location: /index/"); exit; } } checkLogin(); Print_r ($_SESSION); echo "Erm, I have reached page.php and the password is ".$_SESSION['password']; ?> However, using the function and a valid log-in it (as shown above) it chucks me out of the page even though $_SESSION['password'] exists? Am I doing something really stupid here? Thank you Hey all, I am having a situation where I have a singleton class with a static array in it. I insert an element into that array, and then I redirect the user to another page. At that page, I then retrieve that array (it's stored in the session vars), but the array is then empty when I retrieve it. I can't figure out why. Here are some pertinent code snippets. First, the class with the static array: class Logger { private static $instance = NULL; private static $messages = array(); //Private constructor to prevent this class from being instantiated multiple times private function __construct() { } //The clone function is private to prevent cloning of this class private function __clone() { } //Returns the singleton instance of this class public static function GetInstance() { if (!self::$instance) { self::$instance = new Logger; } return self::$instance; } public static function GetMessageCount() { return count(self::$messages); } public static function LogMessage($new_message) { self::$messages[] = $new_message; } public static function GetMessages() { return self::$messages; } public static function ClearMessages() { self::$messages = array(); } } Here is the code where I insert something into the aformentioned array (the process is that a user tries to log in, but the login fails, and so we insert a message into the array saying that the login credentials failed). //Retrieve the message logging instance from the session data to be able to pass messages to the user. $message_log = $_SESSION['user_messages']; $user = $_SESSION['user_account']; //Create a new instance of the database management class and //try to connect to the database $dbm = new DBM(); if ( !$dbm->isConnected() ) { $message_log::LogMessage("We are sorry, but we are unable to access the database at this time. Please try again later."); } else { //Retrieve the user login information $useremail_dirty = $_POST['useremail']; $password_dirty = $_POST['userpassword']; //Check to see if the email we were given exists in the database, and if the password matches $doesPasswordMatch = $dbm->doesPasswordMatch ( $useremail_dirty, $password_dirty ); if ( $doesPasswordMatch ) { //Correct login information was received. Login the user and redirect appropriately. $user->Login(); header ( "Location: ".BASE_URL."/userpage.php" ); exit; } else { //If an incorrect email or password was given, report that information to the user. $message_log::LogMessage("Incorrect login information."); } } //The user has failed to login. Redirect to the appropriate page. header ( "Location: ".BASE_URL."/loginfailed.php" ); And finally, given an unsuccessful login attempt, this is where I pick back up the array of messages to display the messages to the user: $message_log = $_SESSION['user_messages']; $all_messages = $message_log::GetMessages(); print $message_log::GetMessageCount()."<br>"; print count($all_messages)."<br>"; foreach ($all_messages as $message_string) { $prepared_string = prepare_text_for_html_output($message_string); echo $prepared_string."<br>"; } $message_log::ClearMessages(); Unfortunately, the "all_messages" variable has nothing in it...it's like the messages that I logged in the previous PHP script never even existed. I am calling session_start, so don't worry about that (even though it's not seen in these code snippets). What could be going wrong? Hello,
I have a secure login script that uses sessions to maintain a users logged in status. I regenerate the session ID on each page reload for added security. Sometimes, I will lose sessions, and I am hard time figuring out why. It seems to be when I have a slow internet connection. I am wondering what could be causing this?? I have a few ideas, do any of these seem plausible.
-A max execution error, returns a fatal error.
-An ajax request get sent before the previous request returns, so the session ID's dont match an I am kicked out.
Any other ideas would be helpful.
Best,
James
I have four session variables, two I am valueing using $_POST elements from a previous page's form, the other two I am valueing using items retrieved from a database. Here is the code - ---------------------------------------------------- <?php session_start(); $_SESSION['UserLastName'] = strtolower(trim($_POST['txtLastName'])); $_SESSION['BadgeID'] = trim($_POST['txtBadgeID']); //get list for supervisor drop down $q1 = sprintf("select * from emps where emp_last = '".$_SESSION['UserLastName']."' and emp_badge = '".$_SESSION['BadgeID']."'"); $rs_emp_info = hitMSSQL($q1,"intra_sql","employees","xxxx","xxxx",1); $_SESSION['SSN'] = $rs_emp_info->fields("emp_ssn"); $_SESSION['CostCenter'] = $rs_emp_info->fields("emp_costcenter"); if ($_POST['rdoAction'] == 0) { header("Location: http://webapps/injury/empForm.php"); } ?> ---------------------------- When I get to the next page, empForm.php, the Last name and badge ID session vars are populated but the SSN and Cost Center session vars are not. I have tried several things including putting an exit(); after my header statement and first putting the database items into plain old $vars and then trying to populate the session vars with the value of the regular $vars, but nothing seems to work. I have a session_start() at the top of all of my scripts. Any idea why I am losing these values? (and why this box that I am typing into on this site is bouncing around so badly that I can't see what I am typing here???) I am not sure If I am loosing my variable or if it is just getting cancelled out by the syntax. The error I get is this: Query string: "SELECT * FROM timeslip WHERE 1 and Initials=" ORDER BY "Date" ASC, "Cost" ASC Failed with error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"SELECT * FROM timeslip WHERE 1 and Initials=" ORDER BY "Date" ASC, "Cost" ASC' at line 1 Initials should have the value of GEC at this moment Here is my code: $qry_str="SELECT * FROM timeslip WHERE 1 "; if($_POST['Initials']) { $Initials=$_POST['Initials']; $qry_str.='and Initials="'.$Initials . '"'; } if($_POST['Identifier']) { $Identifier=$_POST['Identifier']; $qry_str.='and Identifier LIKE "%'.$Identifier . '%"'; } if($_POST['Type']) { $Type=$_POST['Type']; $qry_str.='and Type LIKE "%'.$Type . '%"'; } if($_POST['Terms']) { $Terms=$_POST['Terms']; $qry_str.='and Terms LIKE "%'.$Terms . '%"'; } if($_POST['Memo']) { $Memo=$_POST['Memo']; $qry_str.='and Memo LIKE "%'.$Memo . '%"'; } if($_POST['date1']) { $date1=$_POST['date1']; $date2=$_POST['date2']; $start=date('Y-m-d', strtotime($date1)); $end=date('Y-m-d', strtotime($date2)); $qry_str.="and Date >= $start and Date <= $end "; } if($_POST['order1'] && $_POST['order2']) { $order1=$_POST['order1']; $order2=$_POST['order2']; $qry=$_POST['qry']; $qry_str=' "'.$qry.'" ORDER BY "'.$order1 . '" ASC, "'.$order2 . '" ASC '; } elseif(isset($_POST['order1'])) { $order1=$_POST['order1']; $qry=$_POST['qry']; $qry_str='$qry ORDER BY $order1 ASC'; } else { if(isset($_POST['order2'])) { $order2=$_POST['order1']; $qry=$_POST['qry']; $qry_str='$qry ORDER BY $order2 ASC'; } } if( !$result = mysql_query($qry_str) ) { echo "<br>Query string: $qry_str<br>Failed with error: " . mysql_error() . '<br>'; } i'm creating a page counter which updates a value in a database each time the page is loaded. I'm trying to make it so that it checks to see if a session has been set, if not, it updates the database, and then sets the session. This way it wont update every time someone refreshes the page. $id=$_GET['id']; if(!isset($_SESSION[$id])){ $_SESSION[$id]= $id; $views = $row['views'] + 1; $update_views=mysql_query("UPDATE topic SET views='".$views."' WHERE topic_id='".$id."'") i want to set the session variable as that of the page id ($id) The problem is that it keeps updating the database everytime the page is reloaded. I'm not sure if i'm setting the session variable correctly. Any ideas would be great Thanks Hey there, Pretty frustrated with this. It seems so simple, but I've been staring at it and toying with it for ages, so I figured I'd post here. I have a variable called "$isTaken" that seems to be losing its value in an essential step in my function. Take a look. function subdomainTaken($inputtedSubdomain) { //Initialize $isTaken to 'true' $isTaken = true; echo "isTaken STARTS AS: <i>" . $isTaken . "</i><br />"; //FOR TESTING PURPOSES ONLY. VARIABLE HAS VALUE HERE //Check subdomain in database $subdomainDBQuery = mysql_query("SELECT * FROM `companies` WHERE company_subdomain = '$inputtedSubdomain'"); $foundResult = mysql_num_rows($subdomainDBQuery); if ($foundResult > 0) { $isTaken = true; } else { $isTaken = false; } return $isTaken; } By the time I get to the if statement, $isTaken has no value. I've echoed it to be sure. Any ideas? Thanks, Frank I am trying to retain information from the $get variable after checking if a user, (Joomla code), is logged in but it is not working. (url: http://domain.com/script.php?file=data) define( '_JEXEC', 1 ); define( 'DS', DIRECTORY_SEPARATOR ); define('JPATH_BASE', '/path/to/joomla/dir/'); require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' ); require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' ); $mainframe =& JFactory::getApplication('site'); $mainframe->initialise(); $session =& JFactory::getSession(); $user =& JFactory::getUser(); // get username and name of user $username = $user->get('username'); $name = $user->get('name'); if (empty($username)) { die('Not logged in'); } $file = $_GET['file']; echo &file; exit; Any help appreciated. Hi everyone, as the title stated, I would like to know how I could submit a form in one page(cart) and unset a session variable on other page.
Right now my form is setting a variable within the page back to 0, however I would like the form to unset the session variable from other page as well.
The issue with my code is that every time I attempt to clear out all items, my code can empty out the cart. But whenever I close and reopen the cart, the same content will show up again. So I need to unset the session variable.
Please let me know what should I do in order to solve the problem and I greatly appreciate your help.
My code is currently looking like this:
cart.php
if(!empty($_GET['aID'])) { $aID = $_GET['aID']; echo $aID; if(isset($_POST['removeAll'])) { $aID = "0"; } $cartSQL = "SELECT * from article where aID in ($aID)"; echo "cart sql :$cartSQL"; $cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc)); while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH)) { $aTitle[] = $row[ 'name' ]; } } <form action = "" method = "POST"> <td style = "width = 200px"><input type="submit" value="Empty cart" name="removeAll"></td> </form>And this is the session variable from other page where I would like it to be unset upon submitting the form. if(!empty($cartSubmit)) $_SESSION["cartSubmit"] = $cartSubmit; else $cart = $_SESSION["cartSubmit"]; <a href="javascript:popup('cart.php?aID=<?php if(empty($cartSubmit)) echo "$cart"; else echo "$cartSubmit";?>')">Cart</a> This is what I have $eeee = $_POST['forum_reply']; $eeee = strip_tags($eeee, '<p>'); echo $eeee; this is what prints out Quote Untitled document testinggg this is a print_r of $_Post Quote Array ( [forum_reply] => testinggg [form_reply_submit] => Reply ) Please someone tell me what in binary's name is going on! My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using: <?php session_start(); function verify() { //verify that the user is logged in via the login page. Session_start has already been called. if (!isset($_SESSION['loggedin'])) { header('Location: /index.html'); exit; } //if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. $user === $_SESSION['name']; //Connect to Databse $link = mysqli_connect("127.0.0.1", "database user", "password", "database"); if (!$link) { echo "Error: Unable to connect to MySQL." . PHP_EOL; echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL; echo "Debugging error: " . mysqli_connect_error() . PHP_EOL; exit; } //SQL Statement to lookup privlege information. if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) { //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv. while ($row = $result->fetch_assoc()) { $priv === $row["su"]; } } // close SQL connection. mysqli_close($link); // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special //accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. if ($priv !== 1) { echo $_SESSION['name']; echo "you have privlege level of $priv"; echo "<br>"; echo 'Your account does not have the privleges necessary to view this page'; exit; } } verify(); ?>
Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu Which one is better for standards practices in PHP. 1. Using the same form for everything. (Add and edit). Meaning setting up one form to handle adding new records, as well as editing existing records. Or 2. Using two different forms for both actions. Use one form/area to handle Adding, and one form/area to handle editing. Which one of these are better from a standards/practice point of a view. Which one better fits into the MVC platform (a framework like Codeignitor, or Cake). Should their be separate controller functions/views for add and edit or should they all be in the same controller function/form. Thanks for the feedback. hi all , i am working on a script which is oop driven and i m not much familiar with it, i appericiate if someone can help me to solve this problem , so basicaly current script is only setting one session variable to true if user login $_SESSION['is_successful_login'] , here is my code <?php include('files/db.php'); class ajaxLoginModule { private $timeout = null; private $target_element = null; private $wait_text = null; private $form_element = null; private $wait_element = null; private $notify_element = null; function __construct() { include ('config.php'); $msql = new Db; $msql->connect(); $this->is_login(); } function get_config() { $this->set_ajax_config(); } function set_ajax_config() { $this->timeout = AJAX_TIMEOUT; $this->target_element = AJAX_TARGET_ELEMENT; $this->wait_text = AJAX_WAIT_TEXT; $this->wait_element = AJAX_WAIT_ELEMENT; $this->notify_element = AJAX_NOTIFY_ELEMENT; $this->form_element = AJAX_FORM_ELEMENT; } function initLogin($arg = array()) { $this->get_config(); $this->login_script(); } function initJquery() { return "<script type='text/javascript' src='files/jquery-1.3.2.min.js'></script>"; } function login_script() { include ('files/login_script.php'); } function is_login() { if(isset($_POST['username'])) { $username = $_POST['username']; $password = $_POST['password']; $strSQL = "SELECT * FROM ".USERS_TABLE_NAME." WHERE username ='$username' AND password = '$password' "; $result = mysql_query ($strSQL); $row = mysql_fetch_row($result); /* //THIS IS WHAT I NEED $_SESSION['user'] = $row['username']; $_SESSION['id'] = $row['id']; */ $exist = count($row); if($exist >=2) { $this->jscript_location(); } else { $this->notify_show();} exit; } } function notify_show() { echo "<script>$('.".AJAX_NOTIFY_ELEMENT."').fadeIn();</script>"; } function jscript_location() { $this->set_session(); echo "<script> $('#container').fadeOut();window.location.href='".SUCCESS_LOGIN_GOTO."'</script>"; } function set_session() { session_start(); $_SESSION['is_successful_login'] = true; } } ?> i comment that line what i need is username and id to store in those session variables $_SESSION['user'] = $row['username']; $_SESSION['id'] = $row['id'] i tried to add code in function set_session but did not helped, appreciate for any help. Thanks Hi I am using very simple code. Here it is Code: [Select] <?php session_start(); $user = "guest"; $uid = "1"; echo $_SESSION['user']."<br />"; echo $_SESSION['uid']; ?> it displays this error Code: [Select] Notice: Undefined index: user in C:\wamp\www\DealDash\index.php on line 5 Notice: Undefined index: uid in C:\wamp\www\DealDash\index.php on line 6 how can I solve this problem? Help please I wonder whether someone can help me please. I'm using the script below to create a page whereby users are presented with a list of image folders they have created. Clicking on any of the folders allows the user to drill down and view the individual images. Code: [Select] <?php session_start(); $_SESSION['username']=$_POST['username']; $_SESSION['locationid']=$_POST['locationid']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <?php //This variable specifies relative path to the folder, where the gallery with uploaded files is located. $galleryPath = 'UploadedFiles/' . $_SESSION['username'] . '/' . $_SESSION['locationid'] . '/'; $absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR; $descriptions = new DOMDocument('1.0'); $descriptions->load($absGalleryPath . 'files.xml'); $items = array(); for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) { $xmlFile = $descriptions->documentElement->childNodes->item($i); $path = $xmlFile->getAttribute('name'); $path = explode('/', $path); $t = &$items; for ($j = 0; $j < count($path); $j++) { if (empty($t[$path[$j]])) { $t[$path[$j]] = array(); } $t = &$t[$path[$j]]; } $t['/src/'] = $xmlFile->getAttribute('source'); $t['description'] = $xmlFile->getAttribute('description'); $t['size'] = $xmlFile->getAttribute('size'); } $basePath = empty($_GET['path']) ? '' : $_GET['path']; if ($basePath) { $basePath = explode('/', $basePath); for ($j = 0; $j < count($basePath); $j++) { $items = &$items[$basePath[$j]]; } } $files = array(); $dirs = array(); function urlpartencode(&$item, $index) { $item = rawurlencode($item); } foreach ($items as $key => $value) { if (isset($value['/src/'])) { $value['/src/'] = explode('/', $value['/src/']); array_walk($value['/src/'], 'urlpartencode'); $value['/src/'] = implode('/', $value['/src/']); $files[] = array( 'name' => $key, 'src' => $value['/src/'], 'description' => htmlentities($value['description'], ENT_COMPAT, 'UTF-8'), 'size' => htmlentities($value['size'], ENT_COMPAT, 'UTF-8') ); } else { $dirs[] = $key; } } $basePath = empty($_GET['path']) ? '' : $_GET['path']; $up = dirname($basePath); if ($up == '.') { $up = ''; } sort($files); sort($dirs); ?> <head> <title>View Image Folders</title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link href="Styles/style.css" rel="stylesheet" type="text/css" /> <script src="Libraries/jquery/jquery-1.4.3.min.js" type="text/javascript"></script> <style type="text/css"> <!-- .style1 { font-size: 14px; margin-top: 5px; margin-right: -50px; } --> </style> <body style="font-family: Calibri; color: #505050; margin-right: 160px; margin-left: -180px;"> <div align="right" class="style1"> <a href = "index.php" /> Add Images <a/> → <a href = "javascript:document.imagefolders.submit()"> View All Images </a> </div> <form id="imagefolders" name="imagefolders" class="page" action="gallery.php" method="post" enctype="application/x-www-form-urlencoded"> <div id="container"> </div> <div id="center"> <div class="aB"> <div class="aB-B"> <?php if ('Uploaded files' != $current['title']) :?> <?php endif;?> <div class="demo"> <input name="username" type="hidden" id="username" value="IRHM73" /> <input name="locationid" type="hidden" id="locationid" value="1" /> <div class="inner"> <div class="container"> <div class="gallery"> <table class="gallery-link-table" cellpadding="0" cellspacing="0"> <thead> <tr class="head"> <th class="col-name"> Name </th> <th class="col-size"> Size </th> <th class="col-description"> Description </th> </tr> </thead> <tbody> <tr class="directory odd"> <td class="col-name"> <a href="?path=<?php echo rawurlencode($up); ?>">..</a> </td> <td class="col-size"> </td> <td class="col-description"> </td> </tr> <?php $i = 1; ?> <?php foreach ($dirs as $dir) : ?> <tr class="directory <?php $i++; echo ($i % 2 == 0 ? 'even' : 'odd'); ?>"> <td><a href="?path=<?php echo rawurlencode(($basePath ? $basePath . '/' : '') . $dir); ?>"><?php echo htmlentities($dir, ENT_COMPAT, 'UTF-8'); ?></a></td> <td>Folder</td> <td></td> </tr> <?php endforeach; ?> <?php foreach ($files as $file) : ?> <tr class="<?php $i++; echo ($i % 2 == 0 ? 'even' : 'odd'); ?>"> <td><a target="_blank" href="<?php echo $galleryPath . $file['src']; ?>"><?php echo htmlentities($file['name'], ENT_COMPAT, 'UTF-8'); ?></a></td> <td><?php echo htmlentities($file['size'], ENT_COMPAT, 'UTF-8'); ?></td> <td><?php echo htmlentities($file['description'], ENT_COMPAT, 'UTF-8'); ?></td> </tr> <?php endforeach; ?> </tbody> </table> </div> </div> </div> </div> </div> </div> </div> </div> </div> </div> </form> </body> </html> I can create the list of folders, but when I click on any of these, instead of being able to view the images, I receive the following error: Quote Warning: DOMDocument::load() [domdocument.load]: I/O warning : failed to load external entity "/homepages/2/d333603417/htdocs/development/UploadedFiles/files.xml" in /homepages/2/d333603417/htdocs/development/imagefolders.php on line 16 Warning: Invalid argument supplied for foreach() in /homepages/2/d333603417/htdocs/development/imagefolders.php on line 52 Line 16 is this line Code: [Select] $descriptions->load($absGalleryPath . 'files.xml'); and line 52 is this Code: [Select] foreach ($items as $key => $value){ However, if I change this line Code: [Select] $galleryPath = 'UploadedFiles/' . $_SESSION['username'] . '/' . $_SESSION['locationid'] . '/'; to Code: [Select] $galleryPath = 'UploadedFiles/' . 'IRHM73' . '/' . '1' . '/'; i.e. replacing the 'Session Variables' with the actual values, the page works. I've been working on this for days now, and I just can't find the solution. I just wondered whether someoen could perhaps have a look at this and let me know where I'm going wrong. Many thanks and regards Need help declaring some session variable guys. I have a login form where the member enters his 1. Pilot Callsign 2. Password I want to declare that Pilot Callsign as the session variable on authentication. Using that Pilot Callsign session variable, I will fetch data from the database relevant to his profile. I already have the whole login page coded along with the restricted access pages (not coded by me). Check this out 1. Page is coded like this and working PERFECTLY --- Code: [Select] <?php // *** Validate request to login to this site. if (!isset($_SESSION)) { session_start(); } $loginFormAction = $_SERVER['PHP_SELF']; if (isset($_GET['accesscheck'])) { $_SESSION['PrevUrl'] = $_GET['accesscheck']; } if (isset($_POST['pilot_callsign'])) { $loginUsername=$_POST['pilot_callsign']; $password=$_POST['password']; mysql_select_db($database_brn_system, $brn_system); $LoginRS__query=sprintf("SELECT pilot_callsign, password, staff_level, firstname FROM pilots WHERE activated = 1 AND pilot_callsign=%s AND password=%s", GetSQLValueString($loginUsername, "text"), GetSQLValueString($password, "text")); $LoginRS = mysql_query($LoginRS__query, $brn_system) or die(mysql_error()); $loginFoundUser = mysql_num_rows($LoginRS); if ($loginFoundUser) { $loginStrGroup = mysql_result($LoginRS,0,'staff_level'); if (PHP_VERSION >= 5.1) {session_regenerate_id(true);} else {session_regenerate_id();} //declare two session variables and assign them $_SESSION['MM_Username'] = $loginUsername; $_SESSION['MM_UserGroup'] = $loginStrGroup; ?> --- 2. As you can see, there already is a session variable declared for Pilot Callsign But on the next page "Restricted Access Page", when I try to call this same Session Variable, it doesn't work. I tried doing this <?php echo $_SESSION['MM_Username'] ?> Moreover, I even tried to fetch data from the table like this - SELECT * FROM pilots WHERE pilot_callsign=$_SESSION['MM_Username'] Doesn't work |