|
PHP - Notice: Undefined Variable: Delete In C:\xampp\htdocs\dbmultidelete.php On Line 60
I have 2 issues happening, first one I need to get resolved is, line 60 is giving me a 'Notice: Undefined variable: delete'. This codes had multi issues but was able to resolve all but this one and my table not filling in with the data from my database. If you need any other info please let me know, Again I am new at this.
<tr>
<td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete value="delete"></td> </tr> <?php // Check if delete button active, start this *line 60* -----> if ($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysqli_query($sql); } // if successful redirect to delete_multiple.php if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">"; } } mysqli_close($con); ?> Similar TutorialsHell Every one , there is some problem in this code one line 54,117,129 and 133
please help me
l attached
registration.php 5.72KB
1 downloads file .please download the attached file.
I really dont no what the problem is and im new here so i dont no if this is the right place to put this but im trying to make a registration page for my server and when i bring it up it says Undefined index: action in C:\xampp\htdocs\index.php on line 56 and idk what to do >.< this is the line that has the problem if($_POST['action']!="signup") so hopefully u guys could help me :/ Im using xampp btw I am getting these errors . This is my complete HTML page. Everything seems to work fine but when i retweet a message these error show up. Here is my tweet.php and the errors are at line 32 and 41. Previously there was an error at line 24: It was like this: '.((!empty($tweet->retweetMsg) && $tweet->tweetID === $retweet['tweetID'] or $tweet->retweetID > 0) ? ' I changed it to this and the error went away '.((isset($retweet['retweetID']) ? $retweet['retweetID'] === $tweet->retweetID OR $tweet->retweetID > 0 : '') ? ' Maybe this could help! I will really appreciate any suggestion coming my way! Hi. I installed xampp to practice php scripting. Until today, it has worked fine, but now it says: Notice: Undefined variable: text in E:\xampp\htdocs\Experiments\Tutorial\HelloWorld.php on line 6 What can I do to fix this? I'm told that variable don't need to be defined before being initialized, but that doesn't really mean much to me! Please help I am new to php and html, I am trying to make a search function where you can search by a persons firstname or lastname but I am getting an error. the error is Notice: Undefined variable: searchq in C:\wamp\www\search2.php on line 17. Can anyone help me please hi, I need help really badly for my PHP-Postcard Script. Basically it sends the card out but the URL does not work, I get the following error message: The URL is not valid and cannot be loaded It also states that Notice: Undefined index: www.voluntary.awardspace.co.uk in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 Notice: Undefined index: Postcard.php in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 See Code below: <?php session_start(); //check error log ini_set('display_errors', 1); ini_set('log_errors', 1); ini_set('error_log', dirname(__FILE__) . '/error_log.txt'); error_reporting(E_ALL); // CHANGE PARAMETERS HERE BEGIN $senderName = " Holidays From Home "; // Eg.: John's Postcards $senderEmail = "chris01@voluntary.awardspace.co.uk"; // Eg.: john@postcard.com // Change only if you have problems with urls $postcardURL = "http://".$_SERVER["www.voluntary.awardspace.co.uk"].$_SERVER["Postcard.php"]; // CHANGE PARAMETERS HERE END $result = 0; $msg = ""; $msg1 = ""; $pic = ""; function displayPhotos() { global $pic; $columns = 5; $act = 0; $act1 = 0; // Open the actual directory if($handle = opendir("thumbs")) { // Read all file from the actual directory while($file = readdir($handle)) { if(!is_dir($file)) { if(isset($pic[1])) { if($pic[1] == $act1){$sel = "checked";} else{$sel = "unchecked";} } if($act == 0){echo "<tr>";} echo "<td align='center'><img src='thumbs/$file' alt='postcard'/><br/><input type='radio' name='selimg' value='$file,$act1' $sel/></td>"; $act++; $act1++; if($act == $columns){$act = 0;echo "</tr>";} } } echo "</tr>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <head> <title>Micro Postcard</title> <link href= "style/style.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <div class="style1" id="caption"> <div align="left" class="style1"></div> </div> <?php //makes sure form is correctly filled in if(!empty($_POST["submit"])) { if(empty($_POST["selimg"])){$msg = "Please select an image from above!";$result = 3;} else{$pic = explode(",",$_POST["selimg"]);} if(empty($_POST["email"]) && empty($result)){$msg1 = "You must enter an email address!";$result = 3;} $secCode = empty($_POST["secCode"]) ? "" : strtolower($_POST["secCode"]); if($secCode == $_SESSION["securityCode"] && $result != 3) { $filename = date("YmdGis"); $f = fopen("messages/".$filename.".txt","w+"); fwrite($f,$pic[0]."\n"); fwrite($f,$_POST['email']."\n"); fwrite($f,stripslashes($_POST["message"])."\n"); fclose($f); // Compose the mail $from = "From: $senderName <$senderEmail>\r\n"; $replay = "Reply-To: $senderEmail\r\n"; $params = "MIME-Version: 1.0\r\n"; $params .= "Content-type: text/plain; charset=iso-8859-1\r\n"; $mailtext = "You have just received a Virtual Postcard!\r\n\r\n You can pick up your postcard at the following web address:\r\n $postcardURL?show=$filename\r\n\r\n We hope you enjoy your postcard, and if you do, please take a moment to send a few yourself!\r\n\r\n Regards,\r\n Holidays From Home\r\n $postcardURL"; // Send email @mail($_POST["email"],"You've received a postcard",$mailtext,$from.$replay.$params); echo "<center> Your postcard was sent successfully!<br /><br /> <img src='images/$pic[0]' alt='postcard' /><br /><br /><br />".stripslashes($_POST["message"]). "</center>"; $result = 1; } else{if($result != 3){$result = 2;}} } if(!empty($_GET["show"])) { $file = $_GET["show"]; $content = file("messages/$file.txt"); $pic = $content[0]; unset($content[0]); unset($content[1]); foreach($content as $value){$main .= $value;} echo "<center> Your postcard!<br /><br /> <img src='images/$pic' alt='postcard' /><br /><br /><br />$main </center>"; } if((empty($result) || $result == 2 || $result == 3) && empty($_GET["show"])) { echo "<form action='#' method='post'> <table align='center'>"; displayPhotos(); echo "</table> <div style='color:#f00;font-size:16px;'>$msg</div> <h2>Fill in the Form and then click on Send Card!!</h2> <table width='100%'> <tr><td>Send to (email address):</td><td><div style='color:#f00;font-size:16px;'>$msg1</div><input type='text' name='email' size='30' value='".$_POST["email"]."' /></td></tr> <tr><td>Message:</td><td><textarea name='message' rows='10' cols='40'>".stripslashes($_POST["message"])."</textarea></td></tr> <tr><td colspan='2'>".($result == 2 ? "<p style='color:#f00;font-size:16px;'>Sorry the security code is invalid! Please try it again!</span></p>" : " ")."</tr> <tr> <td>Security code: <input class='text' name='secCode' type='text' size='10' /> </td><td><img src='securityCode.php' alt='security code' border='1' /></td> </tr> <tr><td colspan='2'> </tr> <tr><td colspan='2' align='left'><input type='submit' value='Send card!' name='submit'/></td></tr> </table> </form>"; } ?> Absolutely any help would be much appreciated. I want ot know is there a way round this problem? Here is the http://voluntary.awardspace.co.uk/Postcard.php I am absolutely desperate to solve this burning issue hello, please i need ur help!!!! when i enter this url in my browser:http://localhost:10080/ntop/dumpData.html?language=php&proto i get: $ntopHash = array( 'ff02::1:2' => array( 'index' => '0', 'hostNumIpAddress' => 'ff02::1:2', 'hostResolvedName' => 'ff02::1:2', 'firstSeen' => '1337008485', 'lastSeen' => '1337009340', 'minTTL' => '0', 'maxTTL' => '0', 'pktSent' => '0', 'pktRcvd' => '15', 'ipBytesSent' => '0', 'ipBytesRcvd' => '0', etc...... so i'm writing a script to extract these informations and put them in a new web interface in a table. my script is: Code: [Select] <HTML> <HEAD> <LINK REL=stylesheet HREF=http://localhost:3000/style.css type="text/css"> </HEAD> <BODY BGCOLOR=red> <?php $host="localhost"; $port=10080; $url="http://localhost:10080/ntop/dumpData.html?language=php&proto"; $fp = fsockopen ($host, $port); if (!$fp) { echo "$errstr ($errno)<br>\n"; } else { $outStr = ""; fputs($fp, "GET $url HTTP/1.1\r\nHost: $host\r\n\r\n"); while (!feof($fp)) { $out = fgets($fp,128); if($out == "\n") $begin = 1; else if($begin = 1) $outStr = $out; } fclose ($fp); #echo "<pre>$outStr</pre>"; eval($outStr); } echo "<center>\n<table border>\n"; echo "<tr><th BGCOLOR=white>Sessions</th><th BGCOLOR=white>Values</th></tr>\n"; while (list ($key, $val) = each($ntopHash)) { echo "<tr><th align=center BGCOLOR=white>$key</th>\n"; echo "<td><table border>\n"; while (list ($key_1, $val_1) = each ($val)) if(gettype($val_1) == "array") { echo "<tr><th align=left>$key_1</th><td><table border>\n"; while (list ($key_2, $val_2) = each ($val_1)) { echo "<tr><th align=left>$key_2</th><td align=right> $val_2</td></tr>\n"; } echo "</table></td></tr>\n"; } else if($val_1 != "0") { if($key_1 == "sessionState") { if($val_1 == 0) $val2 = "SYN"; else if($val_1 == 1) $val2 = "SYN_ACK"; else if($val_1 == 2) $val2 = "ACTIVE"; else if($val_1 == 3) $val2 = "FIN1_ACK0"; else if($val_1 == 4) $val2 = "FIN1_ACK1"; else if($val_1 == 5) $val2 = "FIN2_ACK0"; else if($val_1 == 6) $val2 = "FIN2_ACK1"; else if($val_1 == 7) $val2 = "FIN2_ACK2"; else if($val_1 == $val2 = "TIMEOUT"; else if($val_1 == 9) $val2 = "END"; echo "<tr><th align=left>$key_1</th><td align=right> $val2</td></tr>\n"; } else echo "<tr><th align=left>$key_1</th><td align=right> $val_1</td></tr>\n"; } echo "</table></td></tr>\n"; } echo "</table>\n"; // echo "<pre>$outStr<pre>"; ?> </center> </body> </html> and i'm having this error: Sessions Values Warning: Variable passed to each() is not an array or object in C:\xampp\htdocs\projet\sessions.php on line 33 please i need your helpppp Hi Guys.
Doing an assignment for uni, and stuck on an error. Ill attach some files to show the problem and any help very much appreciated.
Error and the screen it comes on
Code
<?php $select = mysqli_query($con, "SELECT * FROM categories");
while ($row = mysqli_fetch_assoc($select)) { }
function dispsubcategories($parent_id) {
}
function getnumtopics($cat_id, $subcat_id) {
and the structure of the database
Edited March 28, 2020 by Ben555
Hi im coding a php form using a tutorial im completely new at php need help what am i doing wrong <?php
class Post{
private $user_obj;
private $con;
public function __construct($con, $user){
$this->con = $con;
$this->user_obj = new User($con,$user);
}
public function submitPost($body,$user_to){
$body = strip_tags($body);////Removing HTML TAGS
$body = mysqli_real_escape_string($this->con,$body);
$check_empty = preg_replace('/\s+/', '', $body);//delte all spaces
if($check_empty != ""){
//Current Date and time
$date_added = date("Y-m-d H:i:s");
//get username
$added_by = $this->user_obj->getUsername();
//if user have not a profile send to the none
if($user_to == $added_by){
$user_to = "none";
}
////insert query
$query = mysqli_query($this->con,"INSERT INTO posts VALUES('','$body','$added_by','$user_to','$date_added','no','no','0')");
$retured_id = mysqli_insert_id($this->con);
//insert notification
//Update post count for user
$num_post = $this->user_obj->getNumPosts();
$num_post++;
$update_query = mysqli_query($this->con,"UPDATE users SET num_post = '$num_post' WHERE username = '$added_by'" );
}
public function loadPostsFriends(){
$str = ""; //string to return
$data = mysqli_query($this->con,"SELECT * FROM posts where deleted = 'no' ORDER by id DESC");
while($row = mysqli_fetch_array($data))
{
$id = $row['id'];
$body = $row['body'];
$added_by = $row['added_by'];
$date_time = $row['date_added'];
/// Creating user post on other user profile
if($row['user_to'] == "none"){
user_to = "";
else {
$user_to_obj = new User($con,$row['user_to']);
$user_to_name = $user_to_obj->getFirstandLastname();
$user_to = "to <a href='" . $row['user_to'] . "'>" .$user_to_name . "</a>";
}
// check if user account was closed
$added_by_obj = new User($this->con,$added_by);
if($added_by_obj ->isClosed()){
continue;
}
$user_details_query = mysqli_query($this->con,"SELECT first_name,last_name,profile_pic FROM users where username = '$added_by'");
$user_row = mysqli_fetch_array($user_details_query);
$first_name = $user_row['first_name'];
$last_name = $user_row['last_name'];
$profile_pic= $user_row['profile_pic'];
///time stamp
$date_time_now = date("Y-m-d H:i:s");
$start_date = new Date_Time($date_time);////Time_of_post
$end_date = new Date_Time($date_time_now);///Current_time
$intervel = $start_date->diff($end_date);
if($intervel->y >< 1 ){
if($intervel ==1 )
$time_message = $intervel->y . " year ago";/// 1 Year Ago
else
$time_message = $intervel->y . " years ago"; //1+ year ago
}
else if($intervel-> m >= 1 ){
if($intervel->d == 0){
$days = " ago";
}
else if($intervel->d == 1){
$days = $intervel->d."day ago";
}
else
{
$days = $intervel->d."day ago";
}
if($intervel->m == 1){
$time_message = $intervel->m." month".$days;
}
else
$time_message = $intervel->m." months".$days;
}
}
else if($intervel->d >= 1){
if($intervel->d == 1){
$days = "Yesterday";
}
else
{
$days = $intervel->d."days ago";
}
}
else if($intervel->h >= 1){
if($intervel->h == 1){
$time_message = $intervel->h." hour ago";
}
else
{
$time_message = $intervel->h." hours ago";
}
}
else if($intervel->i >= 1){
if($intervel->i == 1){
$time_message = $intervel->i." minute ago";
}
else
{
$time_message = $intervel->i." minutes ago";
}
}
else{
if($intervel->s < 30){
$time_message = "Just Now";
}
else
{
$time_message = $intervel->s." seconds ago";
}
}
$str .= "<div class='status_post'>
<div calss='post_profile_pic'>
<img src='$profile_pic' width='50'>
</div>
<div calss='posted_by' style='color#ACACAC;'>
<a href = '$added_by'> $first_name $last_name </a> $user_to ; ; $time_message
</div>
<div id = 'post_body'$body<br></div>
</div>
"
}
echo $str;
}
}
?>
When i run this code this show me the error Parse error: syntax error, unexpected 'public' (T_PUBLIC) in C:\xampp\htdocs\social\Classes\Post.php on line 39 the line 39 is public function loadPostsFriends() I check the code again and again but i cant find the error please help in this error i get the error for this code: <?php $news = fopen("test.txt", "rb"); while (!feof($news) ) { $line = fgets($news); $parts = explode('=', $line); print $parts[0] . $parts[1]. "<BR>";//line 60!!! } fclose($news); ?> i know that this means that the array gets one argument instead of two but i do'nt know how to solve it... this code works fine in my localhost but not on the server I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); Hello all - am looking for help with dynamic links in PHP not returning data and coughing out "Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200" The initial search is being fed from a mysql into table of results in another page ('ViewMore' being a column in my database and 'UniversityCourses' being the trigger to search that column):
echo "<td class='result'><a href='Uni More Info.php?ID={$row['UniversityCourses']}'>{$row['ViewMore']}</a></td>";
This is working fine as I can see the various links changing when you hover over them in the table. clicking the links goes to "Uni More Info.php" where my PHP code is:
<?php
session_start();
ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL);
//Connect to the database
$mysqli = new mysqli("localhost", "jj3wg2td_wix", "MYPASSWORD", "MYDATABASE");
if(isset($_GET['post'])){
$ID=mysqli_real_escape_string($mysqli, $_GET['ID']);
$sql="SELECT * FROM uni2020 WHERE UniversityCourses='$ID'";
$result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql");
$row=mysqli_fetch_array($result);
if(isset($_GET['post'])){
$Website=mysqli_real_escape_string($mysqli,$_GET['Website']);
$UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']);
$OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']);
$sql= "INSERT INTO UniversityCourses (Website, UcasPointsRequired) VALUES ('$Website', $UcasPointsRequired');";
$result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql");
}
}
?>
<content>
<?php echo $row['Website']?>
<?php echo $row['UcasPointsRequired']?>
<?php echo $row['OverallScore']?>
</content>
The error codes are showing:
Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200 Which is the section in-between the <content></content> tags. Reading up into "Undefined Variable", it suggest that I havent "Declared the variables", but isn't that this section?:
if(isset($_GET['post'])){
$Website=mysqli_real_escape_string($mysqli,$_GET['Website']);
$UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']);
$OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']);
I am new to PHP and am learning as I go along....but yet again...I'm stumped! Any help is very much appreciated (again)!!!!
Steven Hello! Help me please!
My site nice work on php version 5.2.12, but now php version is changed to 5.2.17 and some code is not working.
It showing error:
"Notice: Undefined variable: newCode in ....../humancheck.php on line 29"
In file humancheck.php on line 29:
for($i=0; $i<$config_max_digits;$i++) $newCode = $newCode.rand(0,9);This variable, it seems, taken from another file - humancheck_showcode.php: session_start(); $newCode = $HTTP_SESSION_VARS["newCode"];And, in index.php file at the beginning of the file written:
require ('human_check/humancheck.php');
And, in index.php file below is written:
<IMG src="humancheck_showcode.php">When I call the index.php file it shows error. So, I think, that variable "newCode" should be taken from file humancheck_showcode.php, but it don't do that. I'm getting the following notice: Notice: Undefined variable: TotaalBerichten in C:\Users\Sander\Documents\**********************\index.php on line 60 Is it because it is in the IF? The code: //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} EDIT: translated to english If i modify it to: $TotaalBerichten=0; /////////////ADDED //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); echo $TotaalBerichten; //////////////////////////////////////////////////////////////////////////ADDED //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} The $TotaalBerichten is '0' while there IS a message in the database??? I don't know why I am getting an undefined variable when the url is define. look at the deleteid=6 it means it is defined and in the code it is written as below URL Quote http://www.ppp.com/storeprueba/storeadmin/inventory_list.php?deleteid=6 Code: [Select] <?php if(isset($_GET['deleteid'])){ //which is clearly active in the url then get it, /* line 27 ===> */ echo'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; exit(); } if (isset($_GET['yesdelete'])) { // remove item from system and delete its picture // delete from database $id_to_delete = $_GET['yesdelete']; $sql = mysql_query("DELETE FROM products WHERE id='$id_to_delete' LIMIT 1") or die (mysql_error()); // unlink the image from server // Remove The Pic ------------------------------------------- $pictodelete = ("../inventory_images/$id_to_delete.jpg"); if (file_exists($pictodelete)) { unlink($pictodelete); } header("location:inventory_list.php"); exit(); } ?> the echo Code: [Select] <?php echo 'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; ?> won't display the . $GET ['deleteid'] . after "Do you really want to delete product with ID of which is 6 but it won't display the number six with the actual configuration, instead it display it like Quote Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Do you really want to delete pdoruct with ID of ? Yes | No Notice not number in between 'ID of' and '?' Code: [Select] <form method="post" action=""> <input type="input" name="user_name" /> <input type="submit" name="user_name_submit" /> </form> <?php if(!empty($_POST['user_name'])) $user_name = $_POST['user_name']; if(isset($_POST['user_name_submit'])) { $user_name_submit = $_POST['user_name_submit']; } $user_name_preg_match = preg_match('/[a-zA-Z0-9]/', $user_name); if($user_name_preg_match) { echo 'true'; } else { echo 'false'; } ?> In this script I am getting the notice: Code: [Select] Notice: Undefined variable: user_name Any suggestions how to avoid the notice in this case? Hello i am new to this forum and coding. I am trying to fix a auto torrent downloading script which is php and curl. I have been stucked with Undefined offset error. Your help will be very appretiated, thanks. Starting download: Mp3-data1 Notice: Undefined variable: temp in /var/www/html/torrents/bgrahul2.php on line 338 Array ( => HTTP/1.1 200 OK Server: Transmission Content-Type: application/json; charset=UTF-8 Date: Wed, 21 Sep 2011 19:58:44 GMT Content-Length: 49 {"arguments":{"torrents":[]},"result":"success"} [1] => ) Marked those lines to bold Quote $result = callTransmission(array("filename" => "/var/www/html/donofwarez/xxx/torrents/$torrentfile", "download-dir" => "/home/Downloads/$title/"), "torrent-add", $arr[1]); callTransmission(array("seedRatioLimit" => 50, "seedRatioMode" => 1), "torrent-set", $arr[1]); /* echo "<pre>"; print_r($result); echo "</pre>"; */ if (preg_match('/"percentDone":[0-9.]+/i', $result[0], $matches)) $temp = str_replace('"id":', "", $matches[0]); // $temp="hlDr1wqu2ONtM3McVGHoVzfrkp2UgUcGwDt66IuxAe0LBkru"; $id[0] = $temp; //***OMG! We need the ids as integers! *** foreach ($id as $key => $value) { $id[$key] = (int) $value; } Ik ben bezig met een gastenboek en snap de volgende foutmelding niet: Notice: Undefined variable: iCountFiles *************** regel 261 //Smilies toegestaan? if ($GetConfiguratie['smiley'] == 1) {$AfbeeldingenPerRegel = 12 ; if (!$rHandle = opendir('./images/smilies')) {$sP_Smilies = 'Geef de map "smilies" leesrechten!';} else {$sP_Smilies = ''; while (false !== ($sFile = readdir($rHandle))) {if (preg_match("/^([sa-zA-Z0-9]+){3}(:?\.gif|\.jpg)$/", $sFile)) { $sFileShort = preg_replace("/^([sa-zA-Z0-9]+)(:?\.gif|\.jpg)$/", "(\\1)",$sFile); $iCountFiles++ ; /////////////////////////////////////////////////////////////REGEL261 if ($iCountFiles % $AfbeeldingenPerRegel == 0) {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /><br />';} else {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /> ';} } } closedir($rHandle); } } hoe los ik dit het best op? |
|||||||