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PHP - Multiple Update In Ci
Hi coders,
im trying to update multiple rows of record using check-box and have a default value "RCV" and now im getting difficulties since im new in CI and any body can help and solve or can improve this code below.
view
<tr> <td><input type = "hidden" value = "<?php echo $row->pull_out_id ?>" name = "po_id"></td> <td><input type="checkbox" class="case" name="case" value="rcv"/></td> </tr>controller
public function update_po_receive()
{
$po_id = $this->input->post('po_id');
$this->public_base_model->update_po_receive($po_id);
redirect('public_base/search_stocks', 'refresh');
}
model
public function update_po_receive($po_id)
{
$data = array('temp' => $this->input->post('case'));
$this->db->where('pull_out_id', $po_id);
$this->db->update('pull_out', $data);
}
Similar TutorialsAs the title says I need help with multiple update system.. Can't really get it to work at all >.< Here's some code: $selectt = mysql_query("SELECT * FROM exercises WHERE user='" . $_SESSION["user"] . "' AND exname='" . $_GET["edit"] . "'"); echo '<form method="POST" action="exercises.php?edited">'; echo '<div id="newexx">'; while($raw = mysql_fetch_array($selectt)) { echo '<input type="text" name="up[' . $raw["id"] . ']" value="' . $raw["swe"] . '">'; echo '<input type="text" name="up1[' . $raw["id"] . ']" value="' . $raw["eng"] . '"><br>'; echo '<input type="hidden" name="id[' . $raw["id"] . ']">'; } echo '</div>'; echo '<input type="submit" value="Update Exercise">'; echo '</form>'; if(isset($_GET["edited"])) { $swe = $_POST["up"]; $eng = $_POST["up1"]; $id = $_POST["id"]; foreach($id as $value => $index) { $update = "UPDATE exercises SET swe='".$swe."', eng='".$eng."' WHERE id='".$index."'"; mysql_query($update); } Would be thankful for reply! Need help in updating the tables I have array of data coming from a form which I'm inserting in my DB. I have 5 tables product filter product_filter heater product_heater Im able to put the data in the "product", "filter" & "heater" tables but i dont know how to put data inside the "product_filter" & "product_heater" table. Any help or direction to any tutorails is appreciated. My Tables structu product id int(5) product text cost text details text filter id int(5) filter text imgpath text product_filter id int(5) id_product int(5) id_filter int(5) heater id int(5) heater text imgpath text product_heater id int(5) id_product int(5) id_heater int(5) Code: [Select] // Product data Update $name = mysql_real_escape_string($_POST['product']); $cost = mysql_real_escape_string($_POST['cost']); $details = mysql_real_escape_string($_POST['details']); $sql_title = "INSERT INTO product ( id , product , cost , details , ) VALUES ( NULL , '$name' , '$cost' , '$details')"; if (!mysql_query($sql_title,$con)) { die('Error: ' . mysql_error()); } echo "records for product added<br />"; // Filter update // This is the array which is coming from the form /* Array ( [0] => ehiem [1] => Hagan [2] => Rena [3] => jobo ) Array ( [0] => img1.jpg [1] => img2.jpg [2] => img3.jpg [3] => img4.jpg ) */ $filtername = mysql_real_escape_string($filtername); $filterimgpath = mysql_real_escape_string($filterimg); $combined_array = array_combine($filtername, $filterimgpath); $values = array(); foreach ($combined_array as $filtername => $filterimgpath) { $values[] = "('$filtername', '$filterimgpath')"; } $sql = "INSERT INTO filter (filter , imgpath) VALUES " . implode(', ', $values); //echo $lastid = mysql_insert_id()."<br />"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "records added<br />"; //Product Filter Update table // This is where Im stuck. Not able to even think of anything.... // heater update // This is the array which is coming from the form /* Array ( [0] => ehiem [1] => Dolphin [2] => Rena [3] => jobo ) Array ( [0] => img1.jpg [1] => img2.jpg [2] => img3.jpg [3] => img4.jpg ) */ $heatername = mysql_real_escape_string($heatername); $heaterimgpath = mysql_real_escape_string($heaterimg); $combined_array = array_combine($heatername, $heaterimgpath); $values = array(); foreach ($combined_array as $heatername => $heaterimgpath) { $values[] = "('$heatername', '$heaterimgpath')"; } $sql = "INSERT INTO heater (heater , imgpath) VALUES " . implode(', ', $values); //echo $lastid = mysql_insert_id()."<br />"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "records added<br />"; //Product heater Update table // This is where Im stuck. Not able to even think of anything.... hey can someone advice me on how to make my update script update multiple rows. here's what i've got so far: update.php <?php require('connect.php'); $update = mysql_query("SELECT DISTINCT rideName FROM ride ORDER BY rideName DESC" ); $numrows = mysql_num_rows($update); echo "<form action='mysql_update.php' method='POST'> <select name='updateRide' >"; while ($row=mysql_fetch_assoc($update)) { #$rideID = $row ['rideID']; $rideName = $row ['rideName']; #$seatNumber = $row ['seatNumber']; #$time = $row ['time']; #$price = $row ['price']; echo "<option value='$id'> $rideName </option>"; } echo "</select> <input type='text' name='tochange'> <input type='submit' name='submit' value='change'> </form>"; ?> and now the handler script: mysql_update.php <?php require ('connect.php'); $updateRide=$_POST['updateRide']; $tochange=$_POST['tochange']; if ($updateRide&&$tochange) { $change = mysql_query("UPDATE ride SET rideName='$tochange' WHERE $id='updateRide'"); } ?> When I try this I get nothing, no changes. In the table there is 3 distinct rideNames each have more than 20 rows. Is there a way using the drop down box and ext field like i Have to update all of the distinct rideNames in the table? Thanks. Ok, so I need to know how I can get these codes to interact and work to update multiple rows/columns in a database. this code is what pulls the query and displays info(it displays fine): Code: [Select] <?php if (isset($_POST['submitted'])) { include('connect1.php'); $category = $_POST['category']; $criteria = $_POST['criteria'] ; $query = ("SELECT name, badges, rank, userid FROM members WHERE $category LIKE '%".$criteria."%'"); $result = mysqli_query($dbcon, $query) or die('error getting data'); $num_rows = mysqli_num_rows($result); echo "$num_rows results found"; echo "<table width=\"896\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\">"; echo "<tr bgcolor=\"#F7E496\"><td bgcolor=\"#F7E496\"><strong>name</strong></td><td bgcolor=\"#F7E496\" ><strong>Merit Badges</strong></td><td bgcolor=\"#F7E496\"><strong>Rank</strong></td><td bgclor=\"#F7E496\"></td></tr>"; while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {$color = ($color == 'white')?'#fffccc':'white'; echo "<tr bgcolor='$color'><td> "; echo $row['name']; echo " </td><td> <form action=\"scout.php\" method=\"post\"> <input type=\"text\" name=\"userid\" id=\"userid\" value='".$row['userid']."'> <textarea name=\"badges[]\" id=\"badges\" cols=\"40\" rows=\"3\" type=\"textarea\">".$row['badges']."</textarea></td><td> <span class=\"adfa\"> </span> <select name=\"rank[]\" id=\"rank\"> <option value=\"Scout\">Scout</option> <option value=\"Tenderfoot\">Tenderfoot</option> <option value=\"Second Class Scout\">Second Class Scout</option> <option value=\"First Class Scout\">First Class Scout</option> <option value=\"Star Scout\">Star Scout</option> <option value=\"Life Scout\">Life Scout</option> <option value=\"Eagle Scout\">Eagle Scout</option> <option value=\"\" selected=\"selected\">".$row['rank']."</option> </td><td>"; } echo "</td></tr>"; echo "</table>"; echo "<input type=\"submit\" name='submit[]' id=\"submit\" value=\"Save\" /> </form>"; } ?> and this code is what is supposed to update the database: Code: [Select] if ($_POST[submit]){ foreach ($_POST[rank] as $key => $value) { $badges = $_POST['email1'][$key]; $userid1 = $_POST['userid'][$key]; $q = "UPDATE members SET badges='$badges', rank='$rank' where userid='$userid1'"; $sql = mysql_query($q) or die("Problem with the query: $q<br>" . mysql_error()); printf("Records updated: %d\n", mysql_affected_rows());} exit(); } // close if post again, I am really new to arrays and don't know If i am using them right here......... I have ran this code before and it worked but not it won't update. Can anyone see what I am doing wrong? Code: [Select] <? if(isset($_POST[sort_invest])) { // if form was submitted $id = $_POST['sel_record']; $sort = $_POST['sort']; for($i=0;$i<$count;$i++){ $sql = "UPDATE invest SET id='$id[$i]', sort='$sort[$i]' WHERE id='$id[$i]'"; $sql_result = mysql_query($sql,$con) or die (mysql_error()); } } // if form was submitted or if it came from another page if (isset($_POST['order_invest']) || isset($_POST['sort_invest'])) { ?> <p><strong>Order Invest</strong></p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <? $sql = "SELECT id, sort, title FROM invest ORDER BY sort ASC"; $sql_result = mysql_query($sql,$con) or die(mysql_error()); while ($row = mysql_fetch_array($sql_result)) { $id = $row["id"]; $title = $row["title"]; $sort = $row["sort"]; ?> <input type="hidden" name="sel_record[]" value="<? echo "$row[id]"; ?>"> <table width="545" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="69"><input type="text" name="sort[]" value="<? echo "$row[sort]"; ?>" size="3"></td> <td width="476"><? echo "$row[title]"; ?></td> </tr> </table> <br> <? } } ?> <input name="sort_invest" type="submit" value="Sort"> </form> I have a code that I am using to update multiple products at one time instead of one at a time. It works great except that my processing page is not updating the very last product. My process page is receiving all of my products as I know how many products that I am updating and I have my process page tell me how many products are updated as well as listing the name of each product updated. It is always the last product that is not updated. Here is my process update code. Code: [Select] <?php $size = count($_POST['casketid']); //$size = 306; $i = 1; while ($i < $size) { $product=$_POST['productid'][$i];//getting case # $price=$_POST['price'][$i]; $model=$_POST['model'][$i]; $active=$_POST['active'][$i]; //Getting pricerange if(($price > "0") && ($price <= "1000.00")) $pricerange = "1"; elseif(($price >= "1001.00") && ($price <= "1500.00")) $pricerange = "2"; elseif(($price >= "1501.00") && ($price <= "2000.00")) $pricerange = "3"; elseif(($price <= "2001.00") && ($price <= "2500.00")) $pricerange = "4"; elseif(($price <= "2501.00") && ($price <= "3000.00")) $pricerange = "5"; elseif(($price >= "3001.00") && ($price <= "3500.00")) $pricerange = "6"; elseif(($price >= "3501.00") && ($price <= "4000.00")) $pricerange = "7"; elseif(($price >= "4001.00") && ($price <= "4500.00")) $pricerange = "8"; elseif(($price >= "4501.00") && ($price <= "4500.00")) $pricerange = "9"; elseif($price >= "5001.00") $pricerange = "10"; $query = "UPDATE products SET price='$price', pricerange='$pricerange', active='$active' WHERE productid='$product'"; mysql_query($query) or die ("Error in query: $query"); echo "$model = $price & active = $active</em><br />$size<br />"; ++$i; } ?> can anyone see anything wrong here?? it wont update the Ships table.. i should of gone bed hours ago but its bugging me: <?php $sql="SELECT * FROM ships ORDER BY auction='Yes' DESC"; $result=mysql_query($sql); // Count table rows $count=mysql_num_rows($result); ?> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> <tr> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>Active?</strong></td> <td align="left"><strong>typeID</strong></td> <td align="left"><strong>Item Name</strong></td> <td align="left"><strong>Base Price</strong></td> <td align="left"><strong>Market Price</strong></td> <td align="center"><strong>Auction</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <?php if ($rows['auction'] != "Yes") { ?> <td align="center"><img src="../images/site/delete.png" /></td> <?php } else { ?> <td align="center"><img src="../images/site/accept.png" /></td> <? } ?> <td align="left"><span class="isk"> <? $typeID[]=$rows[typeID]; ?> <? echo $rows['typeID']; ?></span></td> <td align="left"><span class="eveyellow"><? echo $rows['typeName']; ?></span></td> <td align="left"><span class="normal"><?php echo number_format($rows['basePrice'])?> isk</span></td> <td align="left"><input name="marketPrice[]" type="text" size="10" id="marketPrice" value="<? echo $rows['marketPrice']; ?>"> <span class="credits">(<?php echo number_format($rows['marketPrice']/1000000, 2)?> m)</span></td> <td align="center"><input name="auction[]" type="text" size="6" id="auction" value="<? echo $rows['auction']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if($Submit){ for($i=0;$i<$count;$i++){ $sql1="UPDATE ships SET marketPrice='$marketPrice[$i]', auction='$auction[$i]' WHERE typeID='$typeID[$i]'"; $result1=mysql_query($sql1); } } if($result1){ header("location:ship.php"); } mysql_close(); ?> typeID is my primary key in the table and i only want to update "marketPrice" and "auction" upon submit. its a update multiple rows form by the way. thank you so much for helping me... again.. would be lost without phpfreaks. This has been bugging me for quite a while and I've tried so many different things and just run into all kinds of problems... What I'm doing or trying at least is pulling data from a table displaying it into a multiple select box allowing the user the oppertunity to remove one or more options. As the code stands now I'm getting no value at all in the post variable, by taking the [] brackets out of the inputs name i was able to get the first selected option but the php code was then unable to remove that value from the database. I hope I'm explaining this well enough but the code follows I'd really appreciate some help or direction on this one. The FORM Code: [Select] <FORM action='' method='post'> <select size='8' multiple name='remove_player[]'> <?php foreach ($members as $key => $mem) { if ($mem != "") { $mem = str_replace("-", " ", $mem); $mem = ucwords($mem); echo ("<option value='" . $mem . "'>" . $mem . "</option>"); } } ?> </select> and then the handler code: Code: [Select] $to_remove = $_POST['remove_player']; $as_team = str_replace(" ", "-", $teamname); $as_team = strtolower($as_team); $for_remove = "SELECT * FROM teams WHERE name = '$as_team'"; $for_query = (mysql_query($for_remove)); foreach ($to_remove as $y => $z) { $z = str_replace(" ", "-", $z); $z = strtolower($z); } while($arr_remove = mysql_fetch_array($for_query)) { foreach ($arr_remove as $a => $b) { foreach ($to_remove as $c => $d) { if ($b == $d) { unset($arr_remove[$a]); } } } foreach ($arr_remove as $e => $f) { $add_replace = (mysql_result($for_query, 0, 'members')); $replace = ($add_replace . "\r\n" . $f . "\r\n"); $replace_mem = "UPDATE teams SET members = '$replace'"; $replace_q = (mysql_query($replace_mem)); } } echo "Member List successfully updated.<br>"; foreach ($to_remove as $h => $g) { echo ($g . " removed from the team.<br>"); } Also any time i try to print any part of the array/s I get no values but the database is being updated with 2 line breaks and a "3" at the end of the table which has me a bit confused as well. Thanks! ok, so I have this code: Code: [Select] <?php if (isset($_POST['submitted'])) { include('connect1.php'); $category = $_POST['category']; $criteria = $_POST['criteria'] ; $query = ("SELECT name, badges, rank, userid FROM members WHERE $category LIKE '%".$criteria."%'"); $result = mysqli_query($dbcon, $query) or die('error getting data'); $num_rows = mysqli_num_rows($result); echo "$num_rows results found"; echo "<table width=\"896\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\">"; echo "<tr bgcolor=\"#F7E496\"><td bgcolor=\"#F7E496\"><strong>name</strong></td><td bgcolor=\"#F7E496\" ><strong>Merit Badges</strong></td><td bgcolor=\"#F7E496\"><strong>Rank</strong></td><td bgclor=\"#F7E496\"></td></tr>"; while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {$color = ($color == 'white')?'#fffccc':'white'; echo "<tr bgcolor='$color'><td> <input type=\"text\" name=\"userid\" id=\"userid\" value='".$row['userid']."'>"; echo $row['name']; echo " </td><td> <form action=\"scout.php\" method=\"post\"> <textarea name=\"badges\" id=\"badges\" cols=\"40\" rows=\"3\" type=\"textarea\">".$row['badges']."</textarea></td><td> <span class=\"adfa\"> </span> <select name=\"rank\" id=\"rank\"> <option value=\"Scout\">Scout</option> <option value=\"Tenderfoot\">Tenderfoot</option> <option value=\"Second Class Scout\">Second Class Scout</option> <option value=\"First Class Scout\">First Class Scout</option> <option value=\"Star Scout\">Star Scout</option> <option value=\"Life Scout\">Life Scout</option> <option value=\"Eagle Scout\">Eagle Scout</option> <option value=\"\" selected=\"selected\">".$row['rank']."</option> </td><td>"; echo "<input type=\"submit\" name=\"submit\" id=\"submit\" value=\"Save\" /> "; echo "</form>"; } echo "</table>"; echo "</td></tr>"; } ?> and this is the code that does the posting: Code: [Select] <?php session_start(); // Must start session first thing /* Created By Adam Khoury @ [URL=http://'http://www.flashbuilding.com/']www.flashbuilding.com[/URL] -----------------------June 20, 2008----------------------- */ // Here we run a login check if (!isset($_SESSION['id'])) { echo 'Please <a href="login.php">log in</a> to access your account'; exit(); } //Connect to the database through our include include_once "connect_to_mysql.php"; // Place Session variable 'id' into local variable $userid = $_SESSION['id']; // Query member data from the database and ready it for display // Process the form if it is submitted if ($_POST['submit']) { $badges = $_POST['badges']; $userid = $_POST['userid']; $rank = $_POST['rank']; $sql = mysql_query("UPDATE members SET badges='$badges', rank='$rank' WHERE userid='".$_GET['userid']."'"); printf("Records updated: %d\n", mysql_affected_rows()) ; exit(); } // close if post ?> So what I need to know is how I can make it so that each result has it's user id associated with it......and I can update multiple rows at once according to each userid that is associated..........right now I can only get it to do one if I add on ?userid=".$row['userid']." in the first piece of code.......how can I make it update lets say 78 as soon as I click submit...... PS I know there will be a submit button with each row right now.......I will move it out of the loop later..... Only the last row will update when I submit. I have this form (and one nerve left): <form action="" method="post" > echo" <input style=\"text-align:center\" type=\"text\" name=\"linkorder\" value=\"".$row['order']."\" /> <input type=\"hidden\" name=\"id\" value=\"".$row['id']."\"/> "; <input type="submit" name="updateorder" value="Save Order" /> </form> On Submit: if (isset($_POST['updateorder'])){ connect(); $changeorder = mysql_unbuffered_query("update links set `order` = '".$_POST['linkorder']."' where id = '".$_POST['id']."'") or die(mysql_error()); } I was going put my fist through the monitor but then I remembered I could get help here. Thank you! Hi there, Im fairly new at php and mysql but nevertheless im trying to build a web based campaign game for starwars minatures boardgame. Its fairly straightforward and going well.. However ive been thinking about how it will work and have stumbled across a possible problem (because of my limited craft at programming). I want to have a single form that updates all records in the tables, this would simulate an "end of turn" button. Im sure i can do this if doing stuff in the game (e.g. move, create , modify, delete, fleets/ships and auto increment ships hulls simulating repair) if it was done on the same page. However i wanted to to initiate some of these adjustments in their respective pages (fleet.php, planets.php, ships.php etc) and then once the user is happy to click the end turn button somewhere which would update all of these things at the same time.. Is this possible at all??? If anybody could help that would be brilliant. Thank you p.s. if anybody wants a copy of the finished product when its complete, your most welcome. hi i was working on a code where i need to use multiple categories for a post, i get help before to add post in multi categories, now i need help on what would be my query to do update for a multiple categories post, to insert a new post with multiple categories i used this $values = array(); foreach($_POST['categories'] as $catID) { $values[] = "($postID, $catID)"; } $sql = "INSERT INTO `relation` (`postid`, `catid`) VALUES " . implode(', ', $values); $query = $db->query($sql); so if a post had 3 categories it will add in relation table, now i wants to update that post and modify the categories, all other part is done only problem is to update this relational category table which have two columns only associated with post. i tried like this but did not work $sql = "UPDATE relation SET `catid` = " . implode(', ', $values) . " WHERE postid ='$id' "; please any help hello i had a look here its prety simple example
http://www.formget.com/php-checkbox/
i wish something like this but with many more check boxes about 100,
the senario ls like this
there will be many users in a system,
each user profile will have these kind of questions
for example
Hobby :
tenis []
badminton[]
footbal[]
carrom[]
programming language :
perl[]
python[]
cobol[]
as3[]
favorit biscuit :
bakers[]
subana[]
ect[]
ect ect
these checkbox need to reflect for diferent users.
administrator can add new category [ ie hobby , programming language]
under each category he can add more options such as football, tenis ect
he should be able to have an interface to modify the options entered by user when a user request a change
what is a good way to implement this in php mysql
Hi ive been stuck for a while now and i just cant get my head around it so if you could help i'd be well chuffed. I'm trying to update multple rows in a table depending upon the results of another. I have a form that enables me to update a table called fleet. Another table called ships is realted to the fleet table as each ship is in a fleet: fleet ----- Fleetname* Location Detected ships ------ ShipID* Fleetname * Shipname The particular fleet i am editing is parsed as a url parameter. I made a query to search for all the ships that are in the fleet i am editing: Code: [Select] $colname_ShipsInfleet = "-1"; if (isset($_GET['recordID'])) { $colname_ShipsInfleet = (get_magic_quotes_gpc()) ? $_GET['recordID'] : addslashes($_GET['recordID']); } mysql_select_db($database_swb, $swb); $query_ShipsInfleet = sprintf("SELECT * FROM ships WHERE FleetName = %s", GetSQLValueString($colname_ShipsInfleet, "text")); $ShipsInfleet = mysql_query($query_ShipsInfleet, $swb) or die(mysql_error()); $row_ShipsInfleet = mysql_fetch_assoc($ShipsInfleet); $totalRows_ShipsInfleet = mysql_num_rows($ShipsInfleet); It searched the ships WHERE the FleetName (which is the primary key of the fleet table) is parsed as a url parameter. The appropriate ship records that are generated i want to use so a field can be updated. For example im updating a fleet record and and setting the location (Planet Name) to a different value. I want the Ship records that are of that particular fleet to update a field (PlanetName) in ship table when the fleet table is updated. Code: [Select] if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE ships WHERE ShipID = $row_ShipsInfleet['ShipID'] SET PlanetName=%s", GetSQLValueString($_POST['select'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); $updateSQL = sprintf("UPDATE fleet SET PlanetName=%s, Detected=%s, Faction=%s WHERE FleetName=%s", GetSQLValueString($_POST['select'], "text"), GetSQLValueString(isset($_POST['checkbox']) ? "true" : "", "defined","1","0"), GetSQLValueString($_POST['hiddenField2'], "int"), GetSQLValueString($_POST['hiddenField'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); I'm really not sure how to proceed here so please if you can help me out that would be ace. Thank You Hi is it possible to update multiple records of the same table using a single hidden field with a while loop??? For example: Code: [Select] <?php if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE ships SET HealthA=%s WHERE ShipID=%s", GetSQLValueString($_POST['healtha'], "int"), GetSQLValueString($_POST['shipid'], "text")); ?> <input name="healtha" type="hidden" id="healtha" value="<?php echo $row_Ships['HealthA'] + 1; ?>" /> <input name="shipid" type="hidden" id="shipid" value="<?php while($row = mysql_fetch_assoc($Ships)){ echo $row_Ships['ShipID']; }?>" /> If its not possible what else could i do to achieve this please? Thank you This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=325508.0 Hello all, im new to this forum, im a noobie, just started coding about 3 weeks ago, don't be too hard on me.
My question is I wan't to check for challenges a user's team posted that have not been excepted after 1 day, then auto refund the user's team back there credits, and then also delete all the challenges. So far here is my code.
//Delete all matches not accepted after 1 day
$arrayin = array();
$autorefund = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " "
. "AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < " . ((int) time()) . ")");
if (mysql_num_rows($autorefund) > 0) {
while ($autorefund = mysql_fetch_assoc($autorefund)) {
$arrayin[] = $autorefund['id'];
mysql_query("UPDATE `teams` SET `balance` = `balance` + " . $autorefund['credits'] . " "
. "WHERE `id` IN (" . mysql_real_escape_string(implode(',', $arrayin)) . ")");
mysql_query("DELETE FROM `challenges` WHERE `a` IN "
. "(" . mysql_real_escape_string(implode(',', $arrayin)) . ") "
. "AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 "
. "AND (`expires` < " . ((int) time()) . ")");
}
}
FYI here is the code i had, it works fine, however it will only delete 1 challenge per team, not all of there challenges.
$autorefund = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time()).")");
if (mysql_num_rows($autorefund) > 0) {
while ($autorefund = mysql_fetch_assoc($autorefund)) {
if ($autorefund['accepted'] == 0 and $autorefund['expires'] < time()) {
mysql_query("UPDATE `teams` SET `balance` = `balance` + " . $autorefund['credits'] . " WHERE `id` = " . $team['id'] . "");
mysql_query("DELETE FROM `challenges` WHERE `a` = " . $team['id'] . " AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time())."));
}
}
}
I inherited this script, its using deprecated statements, i know im not skilled to rewrite the entire site to use prepared statements.I made a small editing system for my news page, and I need to update three columns within my table "announcements" in the database. I tried a method of updating all of them with one MySQL query instead of using three as it just isn't neat. I've searched several methods via google and I've tried all of them, but just can't seem to get it to work. Is this MySQL query correct? mysql_query("UPDATE announcements SET title = {$title} WHERE id = '$id', content = {$content} WHERE id = '$id', lastmodified = ". date('M-d-Y') ." WHERE id = '$id'"); I am moving my website to a new Service Provider. The script I use for multiple updating worked on the older server but not on the new one. It shows the information but does not update the records. Any help would be greatly appreciated. Old Server : PHP 5.2.11 MYSQL: 5.0.92-community New Server : PHP 5.2.17 MYSQL: 5.1.47-community Script: <?php include("head.php"); $host="localhost"; // Host name $username="xxxxxxx"; // Mysql username $password="xxxxxxx"; // Mysql password $db_name="xxxxxxx"; // Database name $tbl_name="xxxxxxx"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name limit 20"; $result=mysql_query($sql); // Count table rows $count=mysql_num_rows($result); ?> <title>PowerMan South Africa</title> <META HTTP-EQUIV="Pragma" CONTENT="no-cache"> <META HTTP-EQUIV="Expires" CONTENT="-1"> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" href="style.css" type="text/css" media="screen" /> <style type="text/css" media="screen,projection"> @import url(calendar.css); </style> </head> <table width="500" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> <tr> <td> <table width="500" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>ID</strong></td> <td align="center"><strong>Company</strong></td> <td align="center"><strong>contact</strong></td> <td align="center"><strong>Email</strong></td> <td align="center"><strong>Telephone</strong></td> <td align="center"><strong>Type</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td> <td align="center"><input name="company[]" type="text" id="company" value="<? echo $rows['company']; ?>"></td> <td align="center"><input name="contact[]" type="text" id="contact" value="<? echo $rows['contact']; ?>"></td> <td align="center"><input name="email[]" type="text" id="email" value="<? echo $rows['email']; ?>"></td> <td align="center"><input name="telephone[]" type="text" id="telephone" value="<? echo $rows['telephone']; ?>"></td> <td align="center"><input name="type[]" type="text" id="type" value="<? echo $rows['type']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if($Submit){ for($i=0;$i<$count;$i++){ $sql1="UPDATE $tbl_name SET company='$company[$i]', contact='$contact[$i]', email='$email[$i]',type='$type[$i]', telephone='$telephone[$i]' WHERE id='$id[$i]'"; $result1=mysql_query($sql1); } } if($result1){ header("location:update_multiple.php"); echo "<meta http-equiv=Refresh content=0;url=update_multiple.php>"; } mysql_close(); ?> Hello all, i have a table that displays data from mysql, now i want to update multiple rows from that table with checkboxes, the value will basically just switch from 'new' to 'done' so far i have this: Code: [Select] <tbody> <tr class="first"> </tr> <?php $ticketde=0; while ($ticketde < $numpscde) { $f1pscde=mysql_result($ticketresultde,$ticketde,"id"); $f2pscde=mysql_result($ticketresultde,$ticketde,"ticket"); $f4pscde=mysql_result($ticketresultde,$ticketde,"date"); $f5pscde=mysql_result($ticketresultde,$ticketde,"ip"); $f6pscde=mysql_result($ticketresultde,$ticketde,"done"); $setdone = ($f6pscde["done"] == 'n') ? "<a href=\"donepsc.php?id=".$f1pscde."\"><img src=\"ico_new.gif\" alt=\"new\" /></a>" : $f6pscde["done"]; if(isset($_POST['setdone'])){$checkbox = $_POST['checkbox']; $id = "('" . implode( "','", $checkbox ) . "');" ; $sql = "UPDATE ticket SET done='done' WHERE id='$f1pscde'"; $result = mysql_query($sql) or die(mysql_error()); } ?> <tr class="first"> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $f1pscde; ?></font></td> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $f2pscde; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4pscde; ?></font></td> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $f5pscde; ?></font></td> <td class="tc"><font face="Arial, Helvetica, sans-serif"><?php echo $setdone; ?></font></td> <td class="tc"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $f1pscde['id']; ?>"></td> </tr> <?php $ticketde++; } ?> </tbody> </table> <center><input type="submit" name="setdone" id="setdone" value="Set selected to done" class="button"/> - <input type="submit" name="exporttxt" id="exporttxt" value="Export selected to .txt" class="button"/> </center> </fieldset> </form> I found that checkbox code sample on some other site and tried to implement it, i don't really know where to go from here, as it's a total mess to me now, any help would be greatly appreciated. |
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