PHP - New File Name In A Session Variable. Is This Correct?

Hello everyone,

I can get Test 2 to successfully operate the if statement using a variable variable.

But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed?

Code: [Select]

<?php
# TEST 1
$_SESSION[test_variable] = "abcd";
$session_variable_name = "_SESSION[test_variable]";
if ($$session_variable_name == "abcd")
{
echo "<br>line 373, abcd<br>";
}

# TEST 2
$test_variable = "efgh";
$test_variable_name = "test_variable";
if ($$test_variable_name == "efgh")
{
echo "<br>line 379, efgh<br>";
}

?>
Many thanks,

Stu

I am uncertain of how to go about checking if my variables have values, and if I have to do this at every step in my code?!   

For instance...

In my "Member" table, the fields "id" and "name" are required.  So when I run this query, presumably there are always values there, right?

Code: [Select]
// Build query.
$q = 'SELECT id, first_name
FROM member
WHERE email=? AND pass=?';

1.) Is that a fair assumption?


After the above code, I initialize these two variables...

Code: [Select]
// Initialize variables.
$memberID = $memberFirstName = '';

Next I have...
Code: [Select]
// Bind result-set to variables.
mysqli_stmt_bind_result($stmt, $memberID, $memberFirstName);

2.) Did I need to initialize those two variables if I am assigning them values a few lines down?

3.) Can I assume that "$memberID" and "$memberFirstName" will have values based on the comments above?


Then a few more lines after this, I have...
Code: [Select]
// Set Session variables.
$_SESSION['memberID'] = $memberID;
$_SESSION['memberFirstName'] = $memberFirstName;
$_SESSION['loggedIn'] = TRUE;

4.) Again, do I need to keep checking for values (e.g. using ISSET)??

I suppose *anything* is possible, but you could also make your code so full of error-checking code that it would come to a screeching halt?!

Please enlighten me!!


Debbie

Hi.

Below is a working PHP script.
How do I echo the variable "artist" the correct way?

I've tryed everything I know, but cant get this to work ...
(in chronoforms in Joomla 1.7)


$chart2 = mysql_query("SELECT * FROM Combination where artist='$artistsearch' ORDER BY total DESC limit 5");
$num_rows = mysql_num_rows($chart2);     
while($row = mysql_fetch_assoc($chart2))
{echo $row['artist']." ... "
 .$row['city']." ("
 .$row['country'].") "
 .$row['total']." USD<br>";}

Best regards Morris

Hi

I am using very simple code. Here it is

Code: [Select]
<?php
session_start();
$user = "guest";
$uid = "1";
echo $_SESSION['user']."<br />";
echo $_SESSION['uid'];
?>
it displays this error
Code: [Select]
Notice: Undefined index: user in C:\wamp\www\DealDash\index.php on line 5
Notice: Undefined index: uid in C:\wamp\www\DealDash\index.php on line 6
how can I solve this problem? Help please

hi all , i am working on a script which is oop driven and i m not much familiar with it, i appericiate if someone can help me to solve this problem , so basicaly current script is only setting one session variable to true if user login $_SESSION['is_successful_login']  , here is my code
<?php
include('files/db.php');
class ajaxLoginModule  {
  private $timeout         = null;
  private $target_element  = null;
  private $wait_text       = null;
  private $form_element    = null;
  private $wait_element    = null;
  private $notify_element  = null;
   
  function __construct() {
     include ('config.php'); 
 $msql  = new Db;
 $msql->connect();
 $this->is_login();
  } 
  function get_config() {
 $this->set_ajax_config();
  } 
  function set_ajax_config() {
     $this->timeout         = AJAX_TIMEOUT;
     $this->target_element  = AJAX_TARGET_ELEMENT;
     $this->wait_text       = AJAX_WAIT_TEXT;
 $this->wait_element    = AJAX_WAIT_ELEMENT;
     $this->notify_element  = AJAX_NOTIFY_ELEMENT;
     $this->form_element    = AJAX_FORM_ELEMENT;
  }
  function initLogin($arg = array()) {
 $this->get_config();
 $this->login_script();     
  }
  function initJquery() { 
 return "<script type='text/javascript' src='files/jquery-1.3.2.min.js'></script>";
  }
  function login_script() { 
 include ('files/login_script.php');
  }
  function is_login() {
      if(isset($_POST['username']))  {
     $username   = $_POST['username'];
 $password   = $_POST['password'];
 $strSQL = "SELECT * FROM ".USERS_TABLE_NAME."
    WHERE username ='$username' AND password = '$password'
   ";
        $result  = mysql_query ($strSQL); 
$row     = mysql_fetch_row($result);
   /*
//THIS IS WHAT I NEED
$_SESSION['user'] = $row['username'];
 $_SESSION['id'] = $row['id'];
*/
$exist   = count($row);
if($exist >=2) { $this->jscript_location();  } 
else { $this->notify_show();}
exit;
  }   
  }
  function notify_show() {
    echo "<script>$('.".AJAX_NOTIFY_ELEMENT."').fadeIn();</script>";
  }
  function jscript_location() {
    $this->set_session();
    echo "<script> $('#container').fadeOut();window.location.href='".SUCCESS_LOGIN_GOTO."'</script>";
  }
  function set_session() {
      session_start();
  $_SESSION['is_successful_login'] = true;

  }    
  
}  
?>  

i comment that line what i need is username and id to store in those session variables

$_SESSION['user'] = $row['username'];
 $_SESSION['id'] = $row['id']

 i tried to add code in  function set_session but did not helped, appreciate  for any help.

Thanks

Need help declaring some session variable guys.

I have a login form where the member enters his
1. Pilot Callsign
2. Password

I want to declare that Pilot Callsign as the session variable on authentication.

Using that Pilot Callsign session variable, I will fetch data from the database relevant to his profile.

I already have the whole login page coded along with the restricted access pages (not coded by me).

Check this out

1. Page is coded like this and working PERFECTLY
---

Code: [Select]
<?php
// *** Validate request to login to this site.
if (!isset($_SESSION)) {
  session_start();
}

$loginFormAction = $_SERVER['PHP_SELF'];
if (isset($_GET['accesscheck'])) {
  $_SESSION['PrevUrl'] = $_GET['accesscheck'];
}

if (isset($_POST['pilot_callsign'])) {
  $loginUsername=$_POST['pilot_callsign'];
  $password=$_POST['password'];
  
  mysql_select_db($database_brn_system, $brn_system);
  
  $LoginRS__query=sprintf("SELECT pilot_callsign, password, staff_level, firstname FROM pilots WHERE activated = 1 AND pilot_callsign=%s AND password=%s",
  GetSQLValueString($loginUsername, "text"), GetSQLValueString($password, "text")); 
   
  $LoginRS = mysql_query($LoginRS__query, $brn_system) or die(mysql_error());
  $loginFoundUser = mysql_num_rows($LoginRS);
  if ($loginFoundUser) {
    
    $loginStrGroup  = mysql_result($LoginRS,0,'staff_level');
    
if (PHP_VERSION >= 5.1) {session_regenerate_id(true);} else {session_regenerate_id();}
    //declare two session variables and assign them
    $_SESSION['MM_Username'] = $loginUsername;
    $_SESSION['MM_UserGroup'] = $loginStrGroup;      
?>
---

2. As you can see, there already is a session variable declared for Pilot Callsign
But on the next page "Restricted Access Page", when I try to call this same Session Variable, it doesn't work.

I tried doing this
<?php echo $_SESSION['MM_Username'] ?>

Moreover, I even tried to fetch data from the table like this -

SELECT * FROM pilots WHERE pilot_callsign=$_SESSION['MM_Username']

Doesn't work 

I wonder whether someone can help me please.

I'm using the script below to create a page whereby users are presented with a list of image folders they have created. Clicking on any of the folders allows the user to drill down and view the individual images.

Code: [Select]
<?php session_start(); 

$_SESSION['username']=$_POST['username'];
$_SESSION['locationid']=$_POST['locationid'];
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<?php 
  //This variable specifies relative path to the folder, where the gallery with uploaded files is located.
  $galleryPath = 'UploadedFiles/' . $_SESSION['username'] . '/' . $_SESSION['locationid'] . '/';
  
  $absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR;  
  
  $descriptions = new DOMDocument('1.0');
  $descriptions->load($absGalleryPath . 'files.xml'); 
  
  $items = array();

  for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) {
    $xmlFile = $descriptions->documentElement->childNodes->item($i);
    $path = $xmlFile->getAttribute('name');
    $path = explode('/', $path);
    
    $t = &$items;
    for ($j = 0; $j < count($path); $j++) {
      if (empty($t[$path[$j]])) {
        $t[$path[$j]] = array();
      }
      $t = &$t[$path[$j]];
    }
    $t['/src/'] = $xmlFile->getAttribute('source');
    $t['description'] = $xmlFile->getAttribute('description');
    $t['size'] = $xmlFile->getAttribute('size');
  }
  
  $basePath = empty($_GET['path']) ? '' : $_GET['path'];
  if ($basePath) {
    $basePath = explode('/', $basePath);
    for ($j = 0; $j < count($basePath); $j++) {
      $items = &$items[$basePath[$j]];
    }
  }
  
  $files = array();
  $dirs = array();
  
  function urlpartencode(&$item, $index) {
    $item = rawurlencode($item);
  }
  
  foreach ($items as $key => $value) {
    if (isset($value['/src/'])) {
      $value['/src/'] = explode('/', $value['/src/']);
      array_walk($value['/src/'], 'urlpartencode');
      $value['/src/'] = implode('/', $value['/src/']);
      $files[] = array(
        'name' => $key,
        'src' => $value['/src/'],
        'description' => htmlentities($value['description'], ENT_COMPAT, 'UTF-8'),
        'size' => htmlentities($value['size'], ENT_COMPAT, 'UTF-8')
      ); 
    } else {
      $dirs[] = $key;
    }
  }
  
  $basePath = empty($_GET['path']) ? '' : $_GET['path'];
  $up = dirname($basePath);
  if ($up == '.') {
    $up = '';
  }
  
  sort($files);
  sort($dirs);
?>
<head>
  <title>View Image Folders</title>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
  <link href="Styles/style.css" rel="stylesheet" type="text/css" />
  <script src="Libraries/jquery/jquery-1.4.3.min.js" type="text/javascript"></script>
   <style type="text/css">
<!--
.style1 {
font-size: 14px;
margin-top: 5px;
margin-right: -50px;
}

-->
  </style>
<body style="font-family: Calibri; color:  #505050; margin-right: 160px; margin-left: -180px;">
<div align="right" class="style1"> <a href = "index.php" /> Add Images <a/> &rarr; <a href = "javascript:document.imagefolders.submit()"> View All Images </a> </div>
<form id="imagefolders" name="imagefolders" class="page" action="gallery.php" method="post" enctype="application/x-www-form-urlencoded"> 
   <div id="container">
  </div>
    <div id="center">
      <div class="aB">
        <div class="aB-B">
          <?php if ('Uploaded files' != $current['title']) :?>
          <?php endif;?>
          <div class="demo">
  <input name="username" type="hidden" id="username" value="IRHM73" />
          <input name="locationid" type="hidden" id="locationid" value="1" />
            <div class="inner">
              <div class="container">
                <div class="gallery">
                  <table class="gallery-link-table" cellpadding="0" cellspacing="0">
                    <thead>
                      <tr class="head">
                        <th class="col-name">
                          Name
                        </th>
                        <th class="col-size">
                          Size
                        </th>
                        <th class="col-description">
                          Description
                        </th>
                      </tr>
                    </thead>

                    <tbody>
                      <tr class="directory odd">
                        <td class="col-name">
                          <a href="?path=<?php echo rawurlencode($up); ?>">..</a>
                        </td>
                        <td class="col-size">
                        </td>
                        <td class="col-description">
                        </td>
                      </tr>
                      <?php $i = 1; ?>
                      <?php foreach ($dirs as $dir) : ?>
                      <tr class="directory <?php $i++; echo ($i % 2 == 0 ? 'even' : 'odd'); ?>">
                        <td><a href="?path=<?php echo rawurlencode(($basePath ? $basePath . '/' : '') . $dir); ?>"><?php echo htmlentities($dir, ENT_COMPAT, 'UTF-8'); ?></a></td>
                        <td>Folder</td>
                        <td></td>
                      </tr>
                      <?php endforeach; ?>
                      <?php foreach ($files as $file) : ?>
                      <tr class="<?php $i++; echo ($i % 2 == 0 ? 'even' : 'odd'); ?>">
                        <td><a target="_blank" href="<?php echo $galleryPath . $file['src']; ?>"><?php echo htmlentities($file['name'], ENT_COMPAT, 'UTF-8'); ?></a></td>
                        <td><?php echo htmlentities($file['size'], ENT_COMPAT, 'UTF-8'); ?></td>
                        <td><?php echo htmlentities($file['description'], ENT_COMPAT, 'UTF-8'); ?></td>
                      </tr>
                      <?php endforeach; ?>
                    </tbody>
                  </table>
                </div>
              </div>
            </div>
          </div>
        </div>
      </div>
  </div>
        </div>
      </div>
    </div>
</form>
</body>
</html>
I can create the list of folders, but when I click on any of these, instead of being able to view the images, I receive the following error:
Quote

Warning: DOMDocument::load() [domdocument.load]: I/O warning : failed to load external entity "/homepages/2/d333603417/htdocs/development/UploadedFiles/files.xml" in /homepages/2/d333603417/htdocs/development/imagefolders.php on line 16

Warning: Invalid argument supplied for foreach() in /homepages/2/d333603417/htdocs/development/imagefolders.php on line 52


Line 16 is this line Code: [Select]
$descriptions->load($absGalleryPath . 'files.xml'); and line 52 is this Code: [Select]
foreach ($items as $key => $value){
However, if I change this line Code: [Select]
$galleryPath = 'UploadedFiles/' . $_SESSION['username'] . '/' . $_SESSION['locationid'] . '/'; to
Code: [Select]
$galleryPath = 'UploadedFiles/' . 'IRHM73' . '/' . '1' . '/'; i.e. replacing the 'Session Variables' with the actual values, the page works.

I've been working on this for days now, and I just can't find the solution. I just wondered whether someoen could perhaps have a look at this and let me know where I'm going wrong.

Many thanks and regards

Hi all - hoping somebody can see this clearer than me...

Goal: to create a very simple shopping cart page that receives $_POST  info and stores it as an array in a session variable so items will be displayed in cart on clients return to shopping cart page.

Problem: I can get the array to display the first item that I add to the shopping cart but each susequest item just overwrites the first because it is using the same session variable name.  How do I store the next product info in a DIFFERENT session variable and display it on the shopping cart page without writing over the first?

I have two pages with products on them which need to submit orders to the shopping cart page.  They use a simple form with these fields:

<form method="post" action="cartaction.php">
               <p>
                  <input type="submit" name="submit" value="Buy" />
                  <input type="hidden" name="cartaction" value="add" />
                  <input type="hidden" name="item" value="coppercasserole" />
               </p>
            </form>


This is what I have so far on the cartaction page which can display the first product added to the cart:

<?php
//If form is submitted, call the function and save all data into the array $_SESSION['form']
if($_POST['submit'] == "Buy"){ setSessionVars(); }
 
function setSessionVars() {
      
   if ( !isset($_SESSION['cart']) ) $_SESSION['cart'] = array();
     
    $item = array();
foreach($_POST as $fieldname => $fieldvalue) {
        $item[$fieldname] = $fieldvalue;
     
        } 
$_SESSION['cart'] = $item;
         
          echo "<table> <tr> <td>" .'<img src="images/'.$item['item'].'.jpg"' . "<td/> <td>"
          . $item['item'] . "</td> <td>" . '<input type="text(30)" name="value" value="1" />
                  <input type="submit" name="puchasednum" value="Update This One Item" />' . "</td> </tr> </table>";   
}
?>



I am new to PHP and have hit a brick wall as to how to display each product array as a new session variable in the shopping cart.  I would like to keep it as simple as possible as I am getting easily confused!  Is there a way that I can increment the session variable with something like this:

<?php //session counter
   $counter = count($_SESSION['cart']);
if (($_POST['name'] !="")){
    $counter = $counter + 1;
    $_SESSION['cart'][$counter] = array();
} ?>


Or can I pass a field as a product ID and use this somehow to create a new session variable for each product or clear the post variables somehow?

Any help would be much appreciated?

Thanks

hi there,
i'm trying to put a message in the footer of a page which welcomes a person who is logged in with his/her name, using sessions of course; when i place this:
Code: [Select]
$username = $_SESSION['valid_user'];
in the footer before the echo:
Code: [Select]
echo "You are logged in as $username";
but the session is also needed before the footer to use the username for other things , such as -checking his credit- so if place in footer the footer shows name in browser but checking credit would not happen as the assignment is at the buttom.

IF i place the assignment above at the top of the file:

everything works for the user and checking credit ..etc...but the footer is not there...

cud not put this any clearer..sorry...hope if someone cud help...thanks

Hey guys, been awhile since I have been here, but I hit a little issue in reading session data reliably every time.

What I am doing is reading the variables and values from a rarurlencoded string.
Then putting that into a session array to populate parts of a form and fill in some hidden fields.
After the form posts every now and then, about 1 in 50 or so attempts, I have one (always the same one) that just vanishes.

Anyone ever experience anything like this?

I'm using Session variables for the first time on a site I'm developing. I had it working fine while I was doing some admin and testing in subfolders. But the problem is I'm losing the session variables when I load the page from www.example.com, but it works from www.example.com/index.php. I would be happy to post some code if needed.

Hi Guys,        Here is the code, once logged in using known credentials it should display the content "welcome..." but it doesn't, instead it is showing "you are not authorized..." as if the session['username']); isn't being taken? 

<?php 	
ini_set('display_errors',1); 
 error_reporting(E_ALL);
		

		

include_once 'includes/db_connect.php';
include_once 'includes/functions.php';
 
sec_session_start();
?>
<!DOCTYPE html>
<html>
    <head>
        <meta charset="UTF-8">
        <title>Secure Login: Protected Page</title>
        <link rel="stylesheet" href="styles/main.css" />
    </head>
    <body>
        <?php if (login_check($mysqli) == true) : ?>
            <p>Welcome <?php echo htmlentities($_SESSION['username']); ?>!</p>
            <p>
                This is an example protected page.  To access this page, users
                must be logged in.  At some stage, we'll also check the role of
                the user, so pages will be able to determine the type of user
                authorised to access the page.
            </p>
            <p>Return to <a href="index.php">login page</a></p>
        <?php else : ?>
            <p>
                <span class="error">You are not authorized to access this page.</span> Please <a href="index.php">login or register</a>.
            </p>
        <?php endif; ?>
        
    </body>
</html>

I am using WAMP and have made sure the username and password is in the database correctly, how do i debug this?    the error reporting has been switched on but it doesn't help me    is the problem with: 

 <?php if (login_check($mysqli) == true) : ?>

I am trying to follow this guide: http://www.wikihow.c...n-PHP-and-MySQL   Please could i get some help on how to make the login "detect" the username from my MySQL database and display the username   Thanks   Attached Files  login_success.php.jpg   14.31KB   0 downloads

page.php
<a href="cart.php?action=add&id=38">

cart.php

session_start();
$cart = $_SESSION['cart'];

$action = $_GET['action'];

switch ($action) {
   case 'add':
if ($cart)
   $cart =$cart. ','.$_GET['id'];
   else
      $cart = $_GET['id'];
}


$_SESSION['cart'] = $cart;
echo $cart;
output:
 Insted of one time it adds the id two times.

It prints : 38,38.
can pls suggest me what's problem in the code. Thank's in advance.

I have a session variable called $_SESSION['patchurl'] in a php file , if i get in to an else statement this session variable gets set and i go to http://yyy page.

below is the snippet of the code

<?php
session_start();
?>
<?php
echo '<script type="text/javascript">' . "\n";
if(isset($_SESSION["Email"])){
echo 'window.location="http://www.xxx";';
}
else{
$_SESSION['patchurl'] = "true";
echo 'window.location="http://yyy";';
}
echo '</script>';?>

once the patchurl session variable is set i call a php file which sets an other session variable called $_SESSION["Email"]. now what happens is the $_SESSION['patchurl'] is gone and ONLY the $_SESSION["Email"] is accessible ...can i not set two session variables? why does creating a new session varible overwrites an other one even though they are called different ? am i doing something wrong ?
Edited by Ch0cu3r, 08 September 2014 - 01:05 PM.

Hello

i have problem in set session variables in .htaccess file.

i have tried some codes which are belows but i did not effect in php info file.

<IfModule mod_php5.c>
  php_value session.gc_maxlifetime 86400
  php_value session.cache_expire 86400
</IfModule>

please let me know if any one have solutions fot this