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PHP - Server Displays Index Of/
I have set up two directories in www which reflect two domains I have using uniform server z which is a wamp package.
I have set up Vhosts also.
The sever is accessible from the internet
The directories hold a simple hello world page ( one index HTML and one index.php) I set these up on uniform server z to test access as I have previously had problems getting virtual host to work on coral 6.8 I can test the IP address fine and ping the sever. I can access the two addresses from the net (not on my local network) How ever when I access either site externally I get the Index of/ My DirectoryIndex in the main apache config allows index.php & index.html. I also have that in the .htaccess and in the Vhosts ht access. The Index of however only shows a favicon and not the index.html/php Any help appreciated. Similar TutorialsHi, I am not a PHP programmer. I took on a new client with a simple PHP site, without any databases. The site is up and running on the web. I would like to get it running on my local machine for further development. I have latest version of WAMP installed, running Apache version 2.2.11 and PHP version 5.3.0 I created a directory in the WAMP "www" project directory and it shows up there like it's supposed to when I browse to "localhost" Problem: The home page of website displays text but no, images, styles, footer, header, nav links, etc. Here is the code for the home page: <? define("NAV","home"); require_once('local/local.php'); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>TITLE</title> <meta name="keywords" content=""> <meta name="Description" content=""> <? include("common/dochead.php"); ?> </head> <body onLoad="<? include('common/preloads.php'); ?>"> <!-- ============================ main ============================= --> <div id="main-frame"><div id="main" class="noCollapse"> <? include("common/sign.php"); ?> <div id="right-frame"> <? include("common/navigation.php"); ?> <div id="content-frame"> <div id="content"> <h1>Welcome</h1> <p>This is the content area. This is the content area. This is the content area. </p> </div><!-- end content --> </div><!-- end content-frame --> </div><!-- end right-frame --> <div class="clearFloats"></div> </div><!-- end main --></div><!-- end main-frame --> <? include("common/footer.php"); ?> </body> </html> Any help would be greatly appreciated. I have spent many hours on this. Regards Hey guys,
So I making a basic website form to do CRUD operations on a database, and all of my components work, but I keep getting 500 - Internal server error on my index.php
Heres my code:
<?php
require_once('config.php');
require_once('menu.php');
echo '<h1>View All Alien Interactions</h1>';
/* Start the table with the fields we want to display
Remember $fields is now in config.php */
echo '<table>
<tr>';
foreach($fields AS $label){
// th is a table header; the column's title or label.
echo "<th>{$label}</th>";
}
//Add the edit and delete columns at the end of the table
echo '<th>Edit</th><th>Delete</th>';
echo '</tr>';
/*
Select the fields we want, from all the rows
The first line takes the array keys from our $fields array
and implodes them, using backticks and commas. The end result
will look like `first_name`, `last_name`, `phone_number`...
The next line creates a SELECT query using that string.
*/
$fields_str = '`contact_id`, `'.implode(array_keys($fields), '`, `').'`';
$sql = "SELECT {$fields_str} FROM `aliens_abduction`";
foreach($dbh->query($sql) as $row) {
echo '<tr>';
// Loop through the fields again to display them for this row.
// Note: The tutorial originally contained an error here, this has been updated.
foreach($fields AS $field=>$value){
// if the field is blank, we want to empty a blank space, otherwise the HTML won't work properly
echo '<td>'.(isset($row[$field]) && strlen($row[$field]) ? $row[$field] : ' '.'</td>');
}
echo '</tr>';
echo '<td><a href="edit.php?contact_id='.$row['contact_id'].'">Edit</a></td>';
echo '<td><a href="delete.php?contact_id='.$row['contact_id'].'">Delete</a></td>';
echo '</tr>';
echo '</table>';
?>
and heres my config.php code (idk if this is the root of the problem, i dummied out my credentials):
<?php
//Connect to the database
$dbh = new PDO('mysql:host=xxxxxxxxx;dbname=db_demo', 'xxxxx', 'xxxxx');
//Set the default fetch mode to be an associative array.
$dbh->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
//Define the fields for our CRUD application
$fields = array(
'first_name' => 'First Name',
'last_name' => 'Last Name',
'when_it_happened' => 'When it happened',
'how_many' => 'How many',
'alien_description' => 'Alien description',
'what_they_did' => 'What they did',
'fang_spotted' => 'Fang spotted',
'email' => 'Email'
);
?>
Edited by tekkenfan2, 30 June 2014 - 11:56 AM. I really dont no what the problem is and im new here so i dont no if this is the right place to put this but im trying to make a registration page for my server and when i bring it up it says Undefined index: action in C:\xampp\htdocs\index.php on line 56 and idk what to do >.< this is the line that has the problem if($_POST['action']!="signup") so hopefully u guys could help me :/ Im using xampp btw Hi there, I was wondering if there is a way to display content on only my index.php page? I believe there is a way and I have done it before, but some of my pages use index.php?category etc. Is there a way to show content just on index.php and not on any dynamic pages? Thanks I have a PHP web system that store in a windows server. In the system, there is a function for user to upload files to another server (Shared server in Unix). When i try to upload a file, it gives warning: Warning: move_uploaded_file(\\unixserver/sharedfolder/upload/test.txt) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\wamp\www\upload\index.php on line 40 For your information, my username has been assigned in xxx's group that has access to read and write on that folder. Besides, i'm able to open,create and delete files on that folder's server manually (samba). The safe mode setting is off. Does anybody has any idea why this thing happen? I'm trying to make a simple website where people register to my website. When the user doesn't fill anything inside the boxes they get a message "Please fill all required fields" on the register.php page On my local host require_once works good. It shows up.
But when i upload the files to my sever the require_once does not show up on the register.php It just refreshes and i dont get the message "Please fill all required fields"
This is the code that works in local host but not in a live server <?php require_once 'messages.php'; ?>
Here is my full code
Register page: <html> <?php require_once 'messages.php'; ?> <br><br> <form action="register-clicked.php" method="POST"> Username:<br> <input type="text" name="usernamebox" placeholder="Enter Username Here"> <br><br> Email:<br> <input type="text" name="emailbox" placeholder="Enter email here"> <br><br> Password:<br> <input type="password" name="passwordbox" placeholder="Enter password here"> <br><br> Confirm Password:<br> <input type="password" name="passwordconfirmbox" placeholder="Re-enter password here"> <br><br> <input type="submit" name="submitbox" value="Press to submit"> <br><br> </form> </html>
Register clicked <?php
session_start();
$data = $_POST;
if( empty($data['usernamebox']) ||
empty($data['emailbox']) ||
empty($data['passwordbox']) ||
empty($data['passwordconfirmbox'])) {
$_SESSION['messages'][] = 'Please fill all required fields';
header('Location: register.php');
exit;
}
if ($data['passwordbox'] !== $data['passwordconfirmbox']) {
$_SESSION['messages'][] = 'Passwords do not match';
header('Location: register.php');
exit;
}
$dsn = 'mysql:dbname=mydatabase;host=localhost';
$dbUser='myuser';
$dbPassword= 'password';
try{
$connection = new PDO($dsn, $dbUser, $dbPassword);
} catch (PDOException $exception){
$_SESSION['messages'][] = 'Connection failed: ' . $exception->getMessage();
header('Location: register.php');
exit;
}
messages.php <?php
session_start();
if (empty($_SESSION['messages'])){
return;
}
$messages = $_SESSION['messages'];
unset($_SESSION['messages']);
?>
<ul>
<?php foreach ($messages as $message): ?>
<li><?php echo $message; ?></li>
<?php endforeach; ?>
</ul>
Edited Wednesday at 12:49 AM by bee65 Hi folks, I'm curious if I can for example, save a file from my server and it will save to all other servers - obviously if they accepted the connection first. It's for a software I developed and is almost complete and know there will be frequent updates to it. Instead of users downloading upates, I want the update files from my server to somehow synchronize to their server automatically? Anything called this?? Thanks for info. Following a tutorial on udemy, i tried to learn the very basics of mvc structure. I built the same project on my local server and it worked without giving me any error. but when i tried it on live server. its not working as it should. not showing any error. I tried to figure out the problem and found that for every page loading, it stops at the same line in my main.php file. <?php require($view); ?> starting from the above line. it stops. i came here to share my problem but i am unable to upload my files here. if there is a way to upload and share my files, please guide. zip file size of the whole project is 31.6 kb This isn't exactly an application design question, but rather a system design one.
I am about to install an Inventory Control System inside this store I work in.
The store itself also owns a Linode VPS running Centos 6.4 which hosts our website.
This new Inventory System will come built in with a Microsoft SQL Server, and supposedly it is a SQL Anywhere database, but I'm not too sure what that means.
I need to make this database publicly accessible, but only via the Linode VPS. Surely, setting restrictions is easy enough to address that issue. That isn't my question.
My first idea is to put this server into the DMZ, easy. But it doesn't exactly sound safe. So my next idea was to put a middleman server in the DMZ, this way the Linode can send queries to that middleman server and it will send that data to the SQL Server and back. This is very vaguely described I know, but I don't want to get too much into details, but rather, understand how I can create that middleman server, and what could Install onto it that would allow me to securely process queries?
My first thought was to install a webservice, that accepts an XML/JSON request and returns an XML/JSON response.
Then, I realized directly afterwards that I don't have any experience setting up a webservice like that.
What kind of options are there out there? Ultimately, my question is, should I just put the Server in the DMZ or should I create the middleman, and if so, can someone point me in the right direction as to getting a webservice set up? Edited by Zane, 15 July 2014 - 11:28 PM. (This might be the wrong forum; it might be server-side configuration, but alas it is the code that *calls* fwrite, so I'll start here.) I have written a script, and one thing it does is generate a file to disk using fwrite. No big deal. Here's what interests me: On most servers, the file is written successfully when the folder's permissions are 755 with recursive permissions. On some servers, 755 fails. Only 777 works. How could this be? Are permissions=permissions=permissions? Why will 755 work on one machine but not another? I'm just a logic guy; I know very little of server-side configuration and/or why there would be a difference here. Just trying to learn. Hey. I am wanting to move a couple of files from my current server to another. If i am uploading the file this is fine but if it is already on the server then im not sure how to move it. When uploading I can just use ftp_put($conn_id, $destination_file, $myFile, FTP_BINARY); What i need to do is figure out how to get a hold of the file and store it in $myFile then this would work fine. Is this possible? Cheers Hi. I am pretty new to this and am having difficulty looping through rows. I have the code below which first selects a name based upon the id sent from a GET on a separate page. It then has a second select query to get the data from all rows which have this name. I then want it to display the name, and city once but all of the comments. The code below only shows one of each though. Thanks in advance Code: [Select] <?php $id = $_GET['id']; // Retrieve data from database $sql="SELECT landlord_name AS name FROM $tbl_name WHERE id=$id"; $query=mysql_query($sql); //loop through the rows while ($rows = mysql_fetch_array($query)){ $name = $rows['name']; } $sql2="SELECT city, landlord_name, landlord_comments FROM $tbl_name WHERE landlord_name= '$name'"; $query2=mysql_query($sql2) or die(mysql_error()); while ($data = mysql_fetch_array($query2)){ ?> <table width="600" border="1" cellspacing="0" cellpadding="0" align="center"> <tr> <div id="name"><? echo $name ?></div> <div id="city"><? echo $data['city']; ?></div> <div id="comments"><? echo $data['landlord_comments']; ?></div> </tr> </table> <? } //End While ?> Hi There, I have the following code: two arrays: $user_body_group & $DB_Seconday_muscles I want to look up the "$DB_Seconday_muscles" Array and search for the elements in the "$user_body_group" array The result would be displaying a checkbox list with only the items in the "$user_body_group" array checked: foreach($DB_Seconday_muscles as $value) { echo "<input name=\"colors[]\" type=\"checkbox\" value=\"$value\""; if (in_array($value,$user_body_group)) { echo "CHECKED"; } echo "> $value "; } BUT... When i run thi script i only get the first element in the searched array ticked. Can anyone help! Many Thanks! Leatfield I must be mixing apples and oranges here or something trying to get two columns/fields of MySQL data to display.
The basic HTML page display OK and there are no MySQL Connection errors (finally resolved those).
<HTML snipped>
<?php
require '...<URL snipped>...';
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT `name`, `id` FROM `roster`";
$result = mysqli_query($con,$sql);
$num=mysqli_num_rows($result);
mysqli_close($con);
?>
<table border="0" cellspacing="2" cellpadding="2">
<tr>
<td>
<font face="Arial, Helvetica, sans-serif">NAME</font>
</td>
<td>
<font face="Arial, Helvetica, sans-serif">ID</font>
</td>
</tr>
<?php
function mysqli_result($res, $row, $field=0) {
$res->data_seek($row);
$datarow = $res->fetch_array();
return $datarow[$field];
}
$i=0;
while ($i < $num) {
$f1=mysqli_result($result,$i,$datarow[$field]);
$f2=mysqli_result($result,$i,$datarow[$field]);
?>
<tr>
<td>
<font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font>
</td>
<td>
<font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font>
</td>
</tr>
<?php
$i++;
}
?>
</table>
<?php
?>
<HTML snipped>
Any assistance is appreciated.
Thanks very much.
- FreakingOUT
Howdy! A client's web page is .shtml and includes various PHP files via standard virtual include: Code: [Select] <!--#include virtual="session.php" --> These PHP includes worked fine until recently, when PHP files that produce no visible output began displaying a 0 (zero). For instance, the session.php file above is here in it's entirety: Code: [Select] <?php session_start(); ?> The include is on the first line of the .shtml file, and includes that bit of code, but displays a 0 in the browser. If I echo anything at all the 0 goes away, but of course we don't want to echo anything before the <html> tag in the .shtml file. The short-term and unacceptable solution is to echo an empty HTML comment, as follows: Code: [Select] <?php session_start(); echo "<!-- -->"; ?> As noted, this causes the 0 to disappear but now we have <!-- --> before the HTML. Repeat: This was not happening when the .shtml and PHP was installed, and the files have not changed. Therefore, it seems that this problem is caused by a change in PHP and/or Apache configuration. Has anyone seen this and/or can anyone explain what's going on? Thanks! I have two servers: WebServer and FaxServer. WebServer needs to send a fax. Is my approach shown below fairly secure? Before sending a fax, ServerWeb needs to store a record in a table representing the message, and I am using a pseudo random value for the PK which is generated as 2147483648+mt_rand(-2147483647,2147483647). WebServer then generates a hash equal to hash('sha256',$pk.'secretCodeWhichOnlyWebServerAndFaxServerKnow'). WebServer then sends curl request to FaxServer using POST which includes $pk, the hash, the fax number, some text to include in the fax, and an optional array of document to include (array(array('id'=>321,'name')=>'fileName.pdf')). FaxServer verifies that the hash is correct given $pk, that the minimum information has been received, and that the fax number is a valid phone number, and quickly responds to WebServer by echoing 0 or 1 so the code in the WebServer could continue and inform the user. If all looks okay, a new instance of PHP is started.
if(missingInformation) {echo(0);}
else {
session_start();
$_SESSION['_xfr']=$_POST;
exec('/usr/bin/php -q /path/to/send_fax.php '.session_id().' >/dev/null &');
echo(1);
}
New instance of PHP send_fax.php then does the following:
session_id($argv[1]);//Set by parent
session_start();
$data=$_SESSION['_xfr'];
$doc_list=null;
foreach ($data['documents'] AS $doc)
{
if(ctype_alnum($doc['id']))
{
$file='/some/tmp/directory/'.$doc['id'];
if(!file_exists($file))
{
$url='http://machine.WebServer.com/index.php?task=displayDocument&id='.$doc['id'].'&x='.hash('sha256','displayDocument'.$doc['id'].'secretCodeWhichOnlyWebServerAndFaxServerKnow');
$cmd='wget -O '.$file.' '.escapeshellarg($url);
exec($cmd);
}
$doc_list.=' '.$file;
}
exit('invalid document');
}
//Send the fax...
//Send another CURL request to the WebServer similar to the wget giving the fax status.
exit;
When WebServer receives the wget request for a document, it confirms the hash and sends the document to the FaxServer using X-Sendfile.When WebServer receives the CURL request regarding status, it updates the database for the applicable message. Seem reasonably secure? What I'm trying to do is copy all files from one server to another folder on another server. Here is what I have have so far.. <?PHP //connection settings $ftp_server = "server"; $ftp_user_name = "user"; $ftp_user_pass = "pass"; $dir = "/var/test/"; $destination_file = "/test/"; // set up basic connection $conn_id = ftp_connect($ftp_server); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); // check connection if ((!$conn_id) || (!$login_result)) { echo "FTP connection has failed!"; echo "Attempted to connect to $ftp_server for user $ftp_user_name"; exit; } else { echo "Connected to $ftp_server, for user $ftp_user_name"; } if (ftp_chdir($conn_id, $dir)) { echo " <br/>Current directory is now: " . ftp_pwd($conn_id) . "\n<p/>"; } else { echo "Couldn't change directory\n<p/>"; } $buff = ftp_rawlist($conn_id, $dir); foreach($buff as $files) { echo $files. "<br/>"; if (ftp_get($conn_id, $destination_file."test.file", $dir."test.txt", FTP_BINARY)) { echo "<br/>Successfully written to $destination_file\n"; } else { echo "There was a problem\n"; } ?> That doesn't work. Any ideas? Thanks, Sean First, I would like to say when i tried to recover my account from this website, I took me 10 attempts to get the captcha right and then finally it said it sent me an email to my gmail account. I checked spam folder and everything there was no such email from this site. Then I decided to create a new account, well, it took me another 10 attempts to get the captcha right and finally when it was submitted, the page was loading for around 3 minutes before it signed me in.
My question is about the php date() function. It accepts a format to display a time. In the following example I use F for full representation of month, d for 2-digit day of month with leading zeros, Y for full year, g for 12-hour format without leading 0s, s for seconds and A for meridiem. It uses the correct format, but it gives me the wrong time. My local time is 4:43 and it prints out 4:12:
<?php echo "<p>order processed on " . date("F d, Y g:sA") . "</p>"; ?> Why is it 30 minutes behind? |
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