PHP - Bizzar Foreach Behavior (skipping)

Hello, i have an array like:
Code: [Select]
Array
(
    [0] => http://www.google.com/asdasfsdafas
    [1] => http://www.google.com/join.html
    [2] => http://www.google.com/dfsgjkd
    [3] => http://www.google.com/join.html
    [4] => http://www.google.com/ddfgyyhujh
    [5] => http://www.google.com/join.html
    [6] => http://www.google.com/ghklkl
)I'm trying to  transform it like:
Code: [Select]
Array
(
    [0] => http://www.google.com/asdasfsdafas
    [1] => http://www.google.com/dfsgjkd
    [2] => http://www.google.com/ddfgyyhujh
    [3] => http://www.google.com/ghklkl
)I used array_fliter but with no success any advise?

Thanks

I have three records in this table, yet the script below only displays two records, skipping the first item.  I have tried it in other fields also, and it is always skipping the first record?
Code: [Select]
$result = mysql_query("SELECT * FROM `content_type_ads`");

$row = mysql_fetch_array( $result );

while($row = mysql_fetch_array($result)){
echo $row['nid']. " - ". $row['field_item_id_value'];
echo "<br />";
}

Hey guy's, have been stuck at this hurdle for a little whole now and I can't seem to find the right solution and would very much appreciate anyones help on this.

Ok, so I have a table of votes and each time a user votes, they're added to this table. Now, I have a 'pool' table which will display certain items. What I'm trying to do is display the 'pool' items, but if this specific user has already voted on this particular item, then I want it to skip the item in the 'pool' and go to the next item, until the argument of has that user voted is false.


The current code I'm pasting will obviously not work, it isn't even in the right position, but I've separated it so that you can hopefully understand what I'm trying to do in order to help.



Below is the code I use to check if a user has already voted on a particular photo:

<?php
$result=mysql_query("SELECT * FROM votes WHERE vVoter='$_SESSION[userID]' AND vPhoto='$_SESSION[currentphoto]'");
$rowCheck = mysql_num_rows($result);
$alreadyv = 0;
if($rowCheck > 0){
   $alreadyv = 1;
        //user has already voted on this photo, need to use this info to be able to skip it in the 'pool'
} else {
   //do nothing
}
?>

totalVoted is basically how many times a user has voted, so that people who vote more, get more votes:

<?php
$result=mysql_query("SELECT * FROM pool ORDER BY totalVoted DESC LIMIT 1");
$rowCheck = mysql_num_rows($result);

if($rowCheck > 0){
   while($row = mysql_fetch_array($result)){
      $photoid = $row['photoInPool'];
      
         $result2=mysql_query("SELECT * FROM photos WHERE pID='$photoid'");
         $rowCheck2 = mysql_num_rows($result2);

         if($rowCheck2 > 0){
            while($row2 = mysql_fetch_array($result2)){
               if($alreadyv == 1) {
                  //I NEED THIS TO SHOW THE NEXT PHOTO IN THE ARRAY, HOWEVER, IF THEY HAVE ALREADY VOTED ON THE NEXT PHOTO, IT WILL STILL DISPLAY IT, THIS IS MY PROBLEM I NEED HELP WITH PLEASE
               } elseif ($alreadyv != 1) {
                  $fname = $row2['pFileName'];
               }
            }
         }
   
      $_SESSION[currentphoto] = $row['photoInPool'];
      echo "<center><img src='user_images/$fname'></center>";
   }
}

?>

I hope I've explained this well enough and hope somebody can help. Many thanks in advance

This is new. For some reason, the PHP errors are not counting my //commented lines.   Example:

<?php
//my comment
:
?>

Parse error: syntax error, unexpected ':' in D:\www\myscript.php on line 2   The error is on line 3. If I add more comments, the error is the same:

<?php
//my comment
//my comment
//my comment
//my comment
//my comment
:
?>

Parse error: syntax error, unexpected ':' in D:\www\myscript.php on line 2   Where is this setting? Thanks.

I have a script that uploads and images, creates 2 versions of it, re-sizes the images and inserts all the info into a DB.

The odd thing is that if I don't have an image to upload, it will still run the script but it will completely skip over the description.  If I upload an image, it works fine.  Not too sure what the issue is.
Is it because my variable of $desc causing a conflict?

Here's my code:

Code: [Select]

<?php 
ini_set("display_errors",1);
include 'dbconn.php';

$change="";
$abc="";


 define ("MAX_SIZE"," 10000");
 function getExtension($str) {
         $i = strrpos($str,".");
         if (!$i) { return ""; }
         $l = strlen($str) - $i;
         $ext = substr($str,$i+1,$l);
         return $ext;
 }

 $errors=0;
  
 if($_SERVER["REQUEST_METHOD"] == "POST")
 {
  $image =$_FILES["file"]["name"];
$uploadedfile = $_FILES['file']['tmp_name'];
     
 
  if ($image) 
  {
 
  $filename = stripslashes($_FILES['file']['name']);
 
   $extension = getExtension($filename);
  $extension = strtolower($extension);


 if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) 
  {

  $change='<div class="msgdiv">Unknown Image extension </div> ';
  $errors=1;
  }
  else
  {

 $size=filesize($_FILES['file']['tmp_name']);


if ($size > MAX_SIZE*1024)
{
$change='<div class="msgdiv">You have exceeded the size limit!</div> ';
$errors=1;
}


if($extension=="jpg" || $extension=="jpeg" )
{
$uploadedfile = $_FILES['file']['tmp_name'];
$src = imagecreatefromjpeg($uploadedfile);

}
else if($extension=="png")
{
$uploadedfile = $_FILES['file']['tmp_name'];
$src = imagecreatefrompng($uploadedfile);

}
else 
{
$src = imagecreatefromgif($uploadedfile);
}

echo $scr;

list($width,$height)=getimagesize($uploadedfile);


$newwidth=150;
$newheight=($height/$width)*$newwidth;
$tmp=imagecreatetruecolor($newwidth,$newheight);


$newwidth1=50;
$newheight1=($height/$width)*$newwidth1;
$tmp1=imagecreatetruecolor($newwidth1,$newheight1);

imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height);

imagecopyresampled($tmp1,$src,0,0,0,0,$newwidth1,$newheight1,$width,$height);

$famname = $_POST['famname'];
$desc =  $_POST['description'];
$petname = $_POST['petname'];
$letter = $_POST['letter'];
$filename = "images/". $_FILES['file']['name'];
$filename1 = "images/small". $_FILES['file']['name'];



imagejpeg($tmp,$filename,100);

imagejpeg($tmp1,$filename1,100);

imagedestroy($src);
imagedestroy($tmp);
imagedestroy($tmp1);
}}

}

//If no errors registred, print the success message
 if(isset($_POST['Submit']) && !$errors) 
 {
 
 $insert="insert ignore into tbl_tribue (petname,familyname,letter,description,imgpath,thumbpath) values ('$petname','$famname','$letter','$desc','$filename','$filename1')";
   mysql_query($insert);
   //mysql_query("update gallery set imgpath='$filename'");
  $change=' <div class="msgdiv">Pet Added Successfully!</div>';

print $insert;

 }
 
?>


I had turned on the error and the print to see the output.  Anyone have any ideas?  Thanks!

We have a php application that is just a form, that takes in data to a mysql database and then displays that data in queue(php web page) for the client. It has been working for the past 5  or more years. Six weeks ago, the client noticed that the numbering started skipping a number each time a request was entered.  It then seemed to stop, now it has started again.  See attached image.

Some detail he   after user has completed web form and hits submit, three fields are populated in the mysql "REQUEST" table, then the actually data from the submitted web form is sent to the ANSWER table.  The REQUEST table is in sync and is always populated, and numbering is in sequence but upon submit, the actual data from the request does NOT always go to the ANSWER table hence the "skipping of numbers."
     
What do I even begin looking at/for to determine what happened?  Reminder: this is a 5+ year old app that worked fine until maybe 6 weeks ago.  No changes have been made to the database or the code base since 2008.  The code that adds the data to the ANSWER table [the one that appears to skip] is below.  The applicate is in php 4.3.1, mysql 5, linux server.

This topic has been moved to Application Frameworks.

http://www.phpfreaks.com/forums/index.php?topic=355772.0

Hey, So what im trying to do is put my database variables into a session array. So this is what im trying to accomplish...

$_SESSION['Name_of_Row'] = $value

 This is the script I wrote:

Code: [Select]
Function setupSession(){
session_start();
$query = "SELECT * FROM users WHERE u_id ='{$this->u_id}'";
    $result = mysql_query($query);
        $row = mysql_fetch_array($result);

foreach($row as $key => $value){
    if(!empty($value)){
        $_SESSION[$key] = $value;   
            }
                }
}

When that runs I get the following warning. Can anyone tell me what this means and how to fix it?

Error: Notice: Unknown: Skipping numeric key 0 in Unknown on line 0

So i am currently coding database connection class and i have encountered very strange behavior from my script.

base.class.php:
Code: [Select]

<?php

class base{
   
    private $settings;
 

    function get_settings(){
       
        $settings["dbhost"] = 'localhost';
        $settings["dbuser"] = '*****';
        $settings["dbpass"] = '*****';
        $settings["dbname"] = 'core';
        return $settings;
      
        }
    }


?>


database.class.php
Code: [Select]

<?php

require_once 'base.class.php';





class database extends base{
    
    
    private $query_now;
    private $link;
    
   
    public function __construct(){
       
        $settings = base::get_settings();
        

      
        $dbhost = $settings["dbhost"];
        $dbuser = $settings["dbuser"];
        $dbpass = $settings["dbpass"];
        $dbname = $settings["dbname"];
              
        
        
        $this->link = mysql_connect($dbhost, $dbname, $dbpass) or die ("Could not connect to the mysql database");
        mysql_select_db($dbname, $this->link) or die ("Could not select the database"); 
        
        }
        
        
        
   
        function query($query){
            
            $this->query_now = $query;
            return mysql_query($query, $this->link);
        
            }
        
      
        function getArray($result){
            
            return mysql_fetch_array($result);
            
            
            }
  
    
    }

    
    



?>
When i try to create an instance of database class, i get mysql_connect error. I have tried to echo my array and it seems that correct information is being passed over. Now the strange thing is if i remove my password from the base class i don't get a mysql_connect error but this time instead i get "Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'core'@'localhost' (using password: YES) " In case you are wondering, does my mysql database user has a password, the answer is: yes for sure... (Also i have tried to setup a simple script for connecting to my database and everything worked fine) So any ideas?

I'm returning a table row that contains information about a file, but it seems in IE versions older than 10, it is cutting off some of the returned json when being used.   The data is being returned properly as seen in the following json:

{"file_name":"<i class='video'><\/i> <a href=\"\/Development\/test(4).mp4\" class=\"is_file\" target=\"_blank\">test(4).mp4<\/a>"}

But when you use it, it cuts off the html.  A simple alert will return

</i> test(4).mp4</a>

and same when appending it and the sort.  It is also happening for another part of HTML that is being returned properly in the json.  It is working for everything else that is returned.   I have been searching around for a very long time trying to find why this is happening.  Has anyone other than me encountered this?

This topic has been moved to Application Design.

http://www.phpfreaks.com/forums/index.php?topic=353396.0

Current time when testing was: 1291064453

I run the following: echo date('m/d/y', strtotime('first day', 1291064453));
Expecting: 11/1/10

What I actually get: 11/30/10

Can anyone explain this?

I am trying to create an HTML Comments Form where people can send feedback or ask for help.

The main goal is to reduce/eliminate spam since my e-mail will be hidden.

When a Customer fills out the Form and clicks "E-mail Comments", what behavior would you expect to happen next?

1.) Do I load the Comments Form again?

2.) Display a message?

3.) Redirect somewhere?

4.) Other?


Debbie

Hey, been banging my head against the wall for a couple of hours now.
There is an If () in the code that is driving me crazy because it is not behaving like I expect it to..


foreach ( $types as $type ) {
    if ( !isset( $type->modclass ) or !isset( $type->typestr ) ) {
        debugging( 'Incorrect activity type in ' . $modname );
        continue;
    }
    $var = (string)$type->type;
    if ( $var != 'assignment&type=online' ) {

        print '<br/>' . $var . '<br/>';
        
        if ( $type->modclass == MOD_CLASS_RESOURCE ) {
            $resources[$type->type] = $type->typestr;
        } else {
            $activities[$type->type] = $type->typestr;
        }
    }
}


results in...

Code: [Select]
label

resource&type=text

resource&type=html

resource&type=file

resource&type=directory

resource&type=ims

assignment_group_start

assignment&type=upload

assignment&type=online

assignment&type=uploadsingle

assignment&type=offline

assignment_group_end

 

Notice the assignment&type=online in the output... I'm just about ready to give up as to why it is still outputting $var when it is clearly equal to the compared string?

Any ideas?