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PHP - Insert Now() From Array? Escape Issue?
Hi,
I'm currently passing an array of values to be updated in my database, but am struggling on the best way to escape the quotation marks around the NOW statement below, as understand this will only work without them.
This is what is being passed to the DB which does not currently work. I'm seeking some help to find the best way to remove the "" from around the NOW statement, but retain it in the array structure which i believe needs the '' to understand its a value. UPDATE staff SET staff_last_login="NOW()" WHERE staff_id="1"
array('staff_last_login'=>'NOW()')
My question is - whats the best way to escape this?
I understand forward slashes can sometimes be used, and double quotes - but feel like i have exhausted all my known options.
Any help much appreciated.
MoFish
Similar TutorialsI need a help in the following : I have an admin page from where the admin attaches an gif image.This attached image should be shown to the user as a scrolling image. The code for the scrolling image is done through javascript. So my actual problem is getting the name of the attached gif image to the javascript array which is used for scrolling horizontally. I have an array $array_1 Code: [Select] ARRAY( [0] => info 1 [1] => info 2 [2] => info 3 ) and I have another array $array_2 Code: [Select] ARRAY( [0] =>thank you and welcome to what ever [1] =>the info you added * thanks for entering your info ) I want to loop though the first array and place the values into the [1] of the second array. But the tricky thing is I want it to insert were the * is. Code: [Select] foreach ($array_1 as $key => $val) { //not sure about this insert into ($array_2[1],after *, $val); } any help would be awesome. Hello everyone, I am trying to write a client database in php & mysql, Its going to be a localized system not online, just run through a home server. really simple stuff not much security, etc. For some reason it does not want to insert into the database, keeps giving me different errors, at first i tried the account# as '' and it told me to check my version of mysql for proper syntax, i am using version 5.1.13, but then i tried $_POST, and im getting a parse error, i'm lost here, dont understand why its not matching up, everything is spelled right. basically i have a customer information table with the fields, account_# {primary key, auto increment}, name_first, name_last, address, city, state, zipcode, telephone, telephone_alt here is my web form code "very very rough draft, just started trying to make it work before it looks pretty lol" Code: [Select] <form action="add_customer.php" method="post"> Account#: <input type="text" name="account_#" /> Firstname: <input type="text" name="name_first" /> Lastname: <input type="text" name="name_last" /> Address: <input type="text" name="address" /> City: <input type="text" name="city" /> State: <input type="text" name="state" /> Zipcode: <input type="text" name="zipcode" /> Telephone: <input type="text" name="telephone" /> Telephone Alt: <input type="text" name="telephone_alt" /> <input type="submit" /> </form> then add_customer.php is Code: [Select] mysql_select_db("terra_elegante_operations", $con); $sql="INSERT INTO customer_information (account_#, name_first, name_last, address, city, state, zipcode, telephone, telephone_alt) VALUES ('$_POST[account_#]','$_POST[name_first]','$_POST[name_last]','$_POST[address]','$_POST[address]','$_POST[city]','$_POST[state]','$_POST[zipcode]','$_POST[telephone]','$_POST[telephone_alt]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; Hi, I've been playing around with inserting the name of a file ($additional_upload_nameX) into the database only if it has been uploaded (it's not mandatory). When I submit the form, I'm told I have a problem with my WHERE clause. Any idea what I'm doing wrong here? Code: [Select] $query2 = "INSERT INTO uploads (date, upload_name, topic, year, status, keywords, description )" . "VALUES (NOW(), '$additional_upload_nameX', '$topic', '$year', '$status', '$keywords' , '$description') WHERE $additional_upload_nameX != ''"; //if($query){echo 'data has been placed'} mysql_query($query2) or die(mysql_error()); This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344127.0 Hi people I am new to php and I need your help.
I am usig libchart and want to make the bars colored based on value:
Original code:
$this->setBarColor(array( new Color(42, 71, 1), )); I want to make something like this: $this->setBarColor(array( if ( ( condition1 )) new Color(42, 171, 1), if ( ( condition2 )) new Color(42, 71, 1), if ( ( condition3 )) new Color(42, 71, 211), )); I do not know php syntax yet, so how can I do this? Thank you, Alex Hi again , I am stuck with simplest problem of array .. i searched all forums and couldn't find similar problem.. Iam collecting array post data "data m_name[][email]" from a form, but I don't know how to get 2 array variables at the same time, here's what I tried : <form action="" method="post" name="myForm"> <div> <input type="text" name="m_name[]" /> <input type="text" name="m_name[][email]" /> </div> <div> <input type="text" name="m_name[]" /> <input type="text" name="m_name[][email]" /> </div> <div> <input type="text" name="m_name[]" /> <input type="text" name="m_name[][email]" /> </div> <input type="submit" name="button" id="button" value="Submit" /> </form> other page where I want to receive above array <?php if($_POST) { print_r($_POST['m_name']); // Output is : Array ( [0] => someone [1] => Array ( [email] => 3 ) [2] => someone two [3] => Array ( [email] => 4 ) [4] => someone three [5] => Array ( [email] => 5 ) ) while (list ($key,$val) = @each ( $_POST['m_name'])) { echo $val.val2 ???"<br/>"; // here I want to get both value $_POST['m_name'] and $_POST['m_name'] ['email'] since I am putting them in db << } } ?> I want to get both values of $_POST['m_name'], I don't know how to do it or is there another way to do it? thankx in advance!! phpfreaks have been very helpful .. I'm trying to insert array of posts categories into MySQL. I'm getting category IDs from drop down list.. ERR: Notice: Notice: Array to string conversion in C:\laragon\*********\includes\functions.php on line 477
Array
Array
(
[0] => Array
(
[0] => 4
[1] => 5
)
)
PHP
try {
$sql = "INSERT INTO posts_category_ids (post_id, category_id) VALUES";
$insertQuery = array();
$insertData = array();
foreach ($filter_category as $row) {
$insertQuery[] = '(?, ?)';
$insertData[] = $id;
$insertData[] = $row;
}
if (!empty($insertQuery)) {
$stmt = $this->conn->prepare($sql);
$stmt->execute($insertData); //477
}
}catch (Exception $e){
echo $e->getMessage();
}
}
HELP!!! PLEASE!!! Here's what's happening: I have a string much like this one: Code: [Select] $str = "84,390961CPK_100,'Pink Coloured Cord',15,'390961CPK_100',1"; I need to insert apostrophes around the first instance of 390961CPK_100 so it reads '390961CPK_100' and not simply 390961CPK_100. To do this I have made the string into an array as follows: Code: [Select] $str_array = str_split($str); Now I need to insert quotes into the array of characters, then convert the whole mess into back into a string. I can't go by hard coded index numbers, because all of the text in this string is variable in length, so I have to go by the first and second positions of the commas. I have no idea how to do this, and it needs to be done yesterday! Mucho Gracias to anyone who can help me with this. I looked through all the array functions in the manual, but didn't see what I needed (might have just missed it) Is there a way to stick a value into the middle of an array, without writing over the current value? I would need it to just push the rest back 1. Hope that explains what Im looking for! Thanks in advance If I have an array like this, what makes the most sense for inserting a key value pair after a given key? This is how I came up with to do it, after looking at the manual I'm not sure if there's a function I'm missing, because this seems way too complicated. Code: [Select] <?php function addKV($arr, $keyToFind, $addKey, $addValue){ $keys = array_keys($arr); $spot = array_search($keyToFind, $keys); $chunks = array_chunk($arr, ($spot+1)); array_unshift($chunks[1], array($addKey=>$addValue)); $arr = call_User_Func_Array('array_Merge', $chunks); return $arr; } $myArr = array('id'=>1, 'name'=>'Name', 'created'=>time(), 'modified'=>time()); $myArr = addKV($myArr, 'name', 'foo', 'bar'); ?>$myArr now looks like Code: [Select] array('id'=>1, name=>'Name', 'foo'=>'bar', 'created'=>time(), 'modified'=>time()); Hi - I have an HTML form which is dynamically produced using CodeIgniter / PHP and presents products a customer has ordered. When the customer has finished changing his quantities they must now submit the form. My problem is that my form will contain many of the same named fields for example, 'Product ID', or 'Product Name' or 'quantity'. So now when it gets processed a typical post array like product id could look like this: Code: [Select] Array ( [0] => 28 [1] => 24 [2] => 101 [3] => 23 [4] => 17 ) Of course I get an error: Quote Severity: Notice Message: Array to string conversion Filename: mysql/mysql_driver.php I really need some advice on how I should pre-process the various POST arrays so I can get them into my DB. A very grateful student of PHP ! Thanks Hi, I am creating a new menu (food) in my system. This consists of a menu, menu_items and menu_connection table. I can insert the menu name just fine and return its id just fine. When inserting the menu items, i need to get each of the menu_item_ids to use in the query that inputs the menu_connection. This is what i have so far:
if ($_SERVER['REQUEST_METHOD']=="POST") {
/////////////////////
//menu name insert //
/////////////////////
$mname = mysqli_real_escape_string($conn, $_POST['newMenuName']);
$stmt=$conn->prepare('
INSERT IGNORE INTO ssm_menu (menu_name) VALUES (?);
');
$stmt->bind_param('s',$mname);
$stmt->execute();
$menuInsId = $stmt->insert_id;
echo $menuInsId;
$stmt->close();
/////////////////////
//menu item insert //
/////////////////////
$mitname = $_POST['newMenuItem'];
$stmt=$conn->prepare('
INSERT IGNORE INTO ssm_menu_items (menu_item_name) VALUES (?);
');
foreach ($_POST['newMenuItem'] as $k => $nmItem) {
$mitname = mysqli_real_escape_string($conn, $nmItem);
$stmt->bind_param('s',$mitname);
$stmt->execute();
$menuItmInsId = $stmt->insert_id;
echo $menuItmInsId;
}
$stmt->close();
///////////////////////////
//menu connection insert //
///////////////////////////
$stmt=$conn->prepare('
INSERT IGNORE INTO ssm_menu_connection (menu_id, menu_item_id) VALUES (?,?)
');
foreach ($_POST['newMenuItem'] as $k => $nmItem) {
$stmt->bind_param('ii',$menuInsId, $menuItmInsId);
$stmt->execute();
$connectionInserId = $stmt->insert_id;
echo $connectionInserId;
}
$stmt->close();
}
Currently it is inserting each of the items in the connection table with the same id - i understand why but i dont know how to collect up all of the ids to use later I am trying to insert records from an foreach array, it only inserts the first record and I cannot work out how to get it to loop through all of the records. Thank you foreach($_SESSION['post_data_array'] AS $seat) { $rowId = substr($seat, 0, 1); $columnId = substr($seat, 1); echo $rowId . $columnId . ", "; } $sql125 = "INSERT INTO booked_seats(booking_id, row_id, column_id) values ('$book_id', '$rowId', '$columnId')"; $result125 = mysql_query($sql125); if ($result125) { echo "worked"; } else { echo "didnt work"; } Hello, I'm working on a form that once submitted, it inserts the result into my SQL table, but I'm trying to get it so it will update an imploded array. EG: current SQL table is "red,blue,green". Then user submits 'white', the SQL table should then update to: "red,blue,green,white" (notice how its added to the end). This is what I have so far: Code: [Select] $attack_out = $info['attack_out']; $attack_out_split = explode(",", $attack_out); if(isset($_POST["submit_attack"])){ $attack_user = $_GET["attack"]; // user - sent from form //$troops_send = $_POST["troop_send"]; // ammount - sent from form $attack_user_array = array(); $i = 0; $max = (count($attack_out_split) + 1); while($i < $max){ $reverse = ($max - 1) - $i; $attack_user_array[$i] = $attack_out_split[$reverse]; $attack_user_array[$max - 1] = $attack_user; $i++; } $attack_user_glue = implode(",",$attack_user_array); $result = mysql_query("UPDATE users SET attack_out='$attack_user_glue' WHERE username='$username'"); } I can't figure out the algorithm in my while loop. Would appreciate any help, thanks Good evening,
I am working on a program that takes images, and casts them into an associated array, I then want to display thumbnails of those images into a 3 column by 4 row table...
[image][image][image]
[image][image][image]
[image][image][image]
[image][image][image]
(For my visual friends)
here is my current, pardon for the mess, but right now, functionality is more important.
<!DOCTYPE html>
<html>
<head>
<title>Zodiac Gallery</title>
</head>
<body>
<h2 style="text-align:center">Zodiac Gallery</h2>
<p>Click a thumbnail image to see enlarged view.</p>
<?php
$ZodiacArray = array (
"Images/rat.jpg" => "Rat",
"Images/ox.jpg" => "Ox",
"Images/tiger.jpg" => "Tiger",
"Images/rabbit.jpg" => "Rabbit",
"Images/dragon.jpg" => "Dragon",
"Images/snake.jpg" => "Snake",
"Images/horse.jpg" => "Horse",
"Images/goat.jpg" => "Goat",
"Images/monkey.jpg" => "Monkey",
"Images/rooster.jpg" => "Rooster",
"Images/dog.jpg" => "Dog",
"Images/pig.jpg" => "Pig");
foreach ($ZodiacArray as $image => $zodiac)
{
echo "<table>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
</table>";
?>
Help is welcome, thank you.
Hello, I have been at this for awhile now and cant seem to figure it out. I have 2 separate arrays like shown below and I am trying to insert each value into my database using one update query. I have tried a for loop inside each array, but only one column populates. I have tried breaking the values outside their for loop, etc, etc. Does anyone know a way this can be done? Code: [Select] //Cars $cars = array('ford', 'toyota', 'bmw'); //Places $places =arrray('Orlando','California','Texas'); foreach ($cars as $car){ foreach ($places as $place){ $place .=$place; } mysql_query("INSERT INTO vehicles (cars, places) VALUES ('" . $car. "', '" . $place . "'')"); } I'm trying to prevent the reinsertion of data if a user refreshes a page. Tried using header() to take them to a new page but I'm using sessions, and it gives an error. Now I'm doing a basic check to see if the field exists before insert... but I'm inserting arrays. Not sure if I've got this right. Would this work. Code: [Select] if(sizeof($_POST['fname'])) { // loop through array $number = count($fname); for ($i=0; $i<$number; $i++) { $fnames = $fname[$i]; $lnames = $lname[$i]; $phones = $phone[$i]; $emails = $email[$i]; $bdates = $bdate[$i]; $bdates2 = $bdate2[$i]; $bdates3 = $bdate3[$i]; $wids = $wid[$i]; $rids = $rid[$i]; $number_of_rows = mysql_num_rows(mysql_query("SELECT * FROM tbl_attendees WHERE attendee_fname='$fnames' AND attendee_lname='$lnames' AND attendee_registrationid='$rid'")); if($number_of_rows > 0) { // nothing to do. Just want to reload the page without running query insert } else { $query_insertItemWorkshop = "INSERT INTO tbl_attendees (attendee_fname, attendee_lname, attendee_registrationid, workshop_id, attendee_email, attendee_telephone, attendee_bday, attendee_bmonth, attendee_byear) VALUES ('$fnames', '$lnames', '$reg_alone', '$wids', '$emails', '$phones', '$bdates', '$bdates2', '$bdates3')"; $dberror = ""; $ret = mysql_query($query_insertItemWorkshop); } <!-- rest of page --> |
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