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PHP - Mysql Query Creation Help, Multiple Inner Joins And Specifying Rows To Return
Given the below 3 database tables I am trying to construct a SQL query that will give me the following result:
customer_favourites.cust_id customer_favourites.prod_id OR product.id product.code product.product_name product.hidden product_ section.section_id (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108) product_ section.catpage (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108) product_ section.relative_order (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108) I currently have.... SELECT customer_favourites.cust_id, customer_favourites.prod_id, product.code, product.product_name, product.hidden, product_section.section_id, product_section.relative_order, product_section.catpage FROM customer _favourites INNER JOIN product ON customer_favourites.prod_id = product.id INNER JOIN product_section ON product_section.product_code = product.code WHERE `cust_id` = '17' AND `hidden` = '0' GROUP BY `code` ORDER BY `section_id` ASC, `relative_order` ASC, `catpage` ASC LIMIT 0,30 This gives me what I want but only sometimes, at other times it randomly selects any row from the product_section table. I was hoping that by having the row I want as the last row (most recent added) in the product_section table then it would select that row by default but it is not consistent. Somehow, I need to be able to specify which row to return in the product_section table, it needs to be the row with the lowest section_id value or it should by the last row (most recent). Pulling my hair out so any help is gratefully received. customer_favourites id cust_id prod_id 70 4 469 product id code product_name hidden 469 ABC123 My Product 0 product_section id section_id catpage product_code relative_order recommended 44105 19 232 ABC123 260 1 44106 3 125 ABC123 87 1 44107 2 98 ABC123 128 1 44108 1 156 ABC123 58 0 Similar TutorialsI insert data in mysql table row using multiple method : 1#2#3 . 1 is ID of country, 2 is Id of state, 3 is ID of town . now i have this table for real estate listings. for each list(home) i have country/state/town (1#2#3). in country table i have list of country - in country table i have list of state - in country table i have list of town. i need to The number of houses in country / state / town . my mean is : Code: [Select] USA [ 13 ] <!-- This Is equal of alabama+alaska+arizona --> ----Alabama [8] <!-- This Is equal of Adamsville+Addison+Akron --> -------Adamsville [2] -------Addison[5] -------Akron[1] ......(list of other City) ----Alaska [ 3 ] -------Avondale[3] ......(list of other City) ----Arizona [ 2 ] -------College[2] ......(list of other City) Lisintg Table : Code: [Select] ID -- NAME -- LOCATION -- DATEJOIN -- ACTIVE 1 -- TEST -- 1#2#3 -- 20110101 -- 1 2 -- TEST1 -- 1#2#3 -- 20110101 -- 1 3 -- TEST2 -- 1#3#5 -- 20110101 -- 1 4 -- TEST3 -- 1#7#6 -- 20110101 -- 1 Country Table : Code: [Select] id -- name 1 -- USA stats Table : Code: [Select] id -- countryid -- name 1 -- 1 -- albama 2 -- 1 -- alaska 3 -- 1 -- akron town Table : Code: [Select] id -- countryid -- statsid -- name 1 -- 1 -- 1 -- adamsville 2 -- 1 -- 1 -- addison 3 -- 1 -- 1 -- akron Thanks For Any Help. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=351561.0 Ok I'm trying to insert multiple rows by using a while loop but having problems. At the same time, need to open a new mysql connection while running the insert query, close it then open the previous mysql connection. I managed to insert multiple queries before using a loop, but for this time, the loop does not work? I think it is because I am opening another connection... yh that would make sense actually? Here is the code: $users = safe_query("SELECT * FROM ".PREFIX."user"); while($dp=mysql_fetch_array($users)) { $username = $dp['username']; $nickname = $dp['nickname']; $pwd1 = $dp['password']; $mail = $dp['email']; $ip_add = $dp['ip']; $wsID = $dp['userID']; $registerdate = $dp['registerdate']; $birthday = $dp['birthday']; $avatar = $dp['avatar']; $icq = $dp['icq']; $hp = $dp['homepage']; echo $username." = 1 username only? :("; // ----- Forum Bridge user insert ----- $result = safe_query("SELECT * FROM `".PREFIX."forum`"); $ds=mysql_fetch_array($result); $forum_prefix = $ds['prefix']; define(PREFIX_FORUM, $forum_prefix); define(FORUMREG_DEBUG, 0); $con = mysql_connect($ds['host'], $ds['user'], $ds['password']) or system_error('ERROR: Can not connect to MySQL-Server'); $condb = mysql_select_db($ds['db'], $con) or system_error('ERROR: Can not connect to database "'.$ds['db'].'"'); include('../_phpbb_func.php'); $phpbbpass = phpbb_hash($pwd1); $phpbbmailhash = phpbb_email_hash($mail); $phpbbsalt = unique_id(); safe_query("INSERT INTO `".PREFIX_FORUM."users` (`username`, `username_clean`, `user_password`, `user_pass_convert`, `user_email`, `user_email_hash`, `group_id`, `user_type`, `user_regdate`, `user_passchg`, `user_lastvisit`, `user_lastmark`, `user_new`, `user_options`, `user_form_salt`, `user_ip`, `wsID`, `user_birthday`, `user_avatar`, `user_icq`, `user_website`) VALUES ('$username', '$username', '$phpbbpass', '0', '$mail', '$phpbbmailhash', '2', '0', '$registerdate', '$registerdate', '$registerdate', '$registerdate', '1', '230271', '$phpbbsalt', '$ip_add', '$wsID', '$birthday', '$avatar', '$icq', '$hp')"); if (FORUMREG_DEBUG == '1') { echo "<p><b>-- DEBUG -- : User added: ".mysql_affected_rows($con)."<br />"; echo "<br />-- DEBUG -- : Query used: ".end($_mysql_querys)."</b></p><br />"; $result = safe_query("SELECT user_id from ".PREFIX_FORUM."users WHERE username = '$username'"); $phpbbid = mysql_fetch_row($result); safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('2', '$phpbbid[0]', '0', '0')"); safe_query("INSERT INTO `".PREFIX_FORUM."user_group` (`group_id`, `user_id`, `group_leader`, `user_pending`) VALUES ('7', '$phpbbid[0]', '0', '0')"); mysql_close($con); } include('../_mysql.php'); mysql_connect($host, $user, $pwd) or system_error('ERROR: Can not connect to MySQL-Server'); mysql_select_db($db) or system_error('ERROR: Can not connect to database "'.$db.'"'); } So I need to be able to insert these rows using the while loop.. how can I do this? I really appreciate any help. Ok so I am pretty good with mysql and performing queries to get the data that I need. However, I have a question for any of you gurus out there that may be able to help me with an issue that I always run into with certain types of queries. Say I have 2 tables like this: Galleries id name 1 My Photos Gallery Photos id gallery_id photo 1 1 photo1.jpg 2 1 photo2.jpg 3 1 photo3.jpg Now usually when I pull this info from the database I have to do 2 separate queries in order to get the data and then link them so I would do something like. <?php //make the gallery query $query = "SELECT * FROM galleries"; $results = mysql_query($query); //setup an array for the galleries data $gallery_data = array(); //loop through the galleries for($i=0;$i<mysql_num_rows($results);$i++){ //add the gallery info to the gallery data array $gallery_data[$i] = mysql_fetch_array($results); //make the photos query with the gallery id $photo_query = "SELECT * FROM gallery_photos WHERE gallery_id='".mysql_real_escape_string($gallery_data[$i]['id'])."'"; $photo_results = mysql_query($photo_query); //setup the photos array $photo_data = array(); //put the photos in the array for($n=0;$n<mysql_num_rows($photo_results);$n++){ $photo_data[$n] = mysql_fetch_array($photo_results); } //add the photos to the gallery array $gallery_data[$i]['photos'] = $photo_data; } //now to display it is like this if(is_array($gallery_data)){ foreach($gallery_data as $gallery){ echo $gallery['name']; //show the photos if(is_array($gallery['photos'])){ foreach($gallery['photos'] as $photo){ echo $photo['photo']; } } } } ?> So my question is there a way to get all of this data at one time. I know how to do multiple queries in one and to do joins but they can only return one row as far as I know of. The only other way that I know how to do this is by ordering them by name and selecting them directly from the photos table and then just getting the gallery name like this: SELECT *,(SELECT name FROM galleries WHERE id=gallery_photos.id) AS gallery_name FROM gallery_photos ORDER BY gallery_id Then I could just do one loop and see if the name has changed and if so to output the new name. But I would like to know if there is a way to get a second set of results as an array from a query so I could just select the galleries and photos all in one query. Any help is appreciated. Hey, I was wondering if there is a way to pull multiple rows at once using a list of unique identifiers. For example, I want to pull the rows with the IDs of 4,13,91 and 252 I know the WHERE part of this query is incorrect, but I'm putting it to hopefully help you guys understand what I'm looking for. $result = mysql_query("SELECT * FROM $table WHERE id='4' OR '13' OR '91' OR '252'"); while($row = mysql_fetch_array($result)) { echo($row['name']); } Or is the best way simply to do it one query at a time without a while statement? There could be as many as a few dozen records being pulled per page. I'm trying to write a php page that displays data from a JOIN query for a specific ID table view brandinfo ID, brand, discounttype 1, antioni, no discount brandproducts brandID, producttype, price 1, Tshirt, 20.00 1, Pants, 30.00 1, Shoe, 40.00 the returned result is 1 antioni, no discount, Tshirt, 20.00, 2 antioni, no discount, Pants, 30.00 3 antioni, no discount, Shoe 40.00 The way I want the page to be displayed is ------------------ Antioni (at the top) Table 1. Tshirt 20.00 2. Pants 30.00 3. Shoe 40.00 no discount (at the bottom) ---------------------------- How should I construct the PHP page from the result since they're retrieved as rows? Hi Everyone, Well I have a bit of a problem... I have created a search page that I would like to return results from my MySQL database. However for some reason I can not get my page to display the results. Instead I am getting an error page. Below is the code I am using: In addition to this, should I wish for a user to be able to edit the returned results by clicking a link, how would I do that? <?php session_start(); ?> <link rel="stylesheet" type="text/css" href="css/layout.css"/> <html> <?php $record = $_POST['record']; echo "<p>Search results for: $record<br><BR>"; $host = "localhost"; $login_name = "root"; $password = "P@ssword"; //Connecting to MYSQL MySQL_connect("$host","$login_name","$password"); //Select the database we want to use mysql_select_db("schedules_2010") or die("Could not find database"); $result = mysql_query("SELECT * FROM schedule_september_2010 WHERE champ LIKE '%$record%' ") or die(mysql_error()); // keeps getting the next row until there are no more to get while($row = mysql_fetch_array( $result )) { // Print out the contents of each row echo "<br><p>Your Schedule<BR></p><br>"; echo "<table border=1>\n"; echo "<tr> <td bgcolor=#444444 align=center><p><b>Champ</p></td> <td bgcolor=#444444 align=center><p><b>Date</p></td> <td bgcolor=#444444 align=center><p><b>Start Time</p></td> <td bgcolor=#444444 align=center><p><b>End Time</p></td> <td bgcolor=#444444 align=center><p><b>Department</p></td> <td bgcolor=#444444 align=center><p><b>First Break</p></td> <td bgcolor=#444444 align=center><p><b>Second Break</p></td> <td bgcolor=#444444 align=center><p><b>Login ID</p></td> </tr>\n"; do { printf("<tr> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> </tr>\n" , $row["champ"] , $row["date_time"] , $row["start_time"] , $row["end_time"] , $row["department"] , $row["first_break"] , $row["second_break"] , $row["login_id"] ); } while ($row = mysql_fetch_array($result)); echo "</table>\n"; } else { echo "$champ No Records Found"; } mysql_free_result($result); mysql_close($con); ?> </html> Hello everyone, Once again i need your help this time i want to know that, if I inserting multiple row by single insert query with the help of foreach (loop) then how to insert another cell value according to the name wise so that's way i send my hole code to you. <?php //include configuration file for connection include_once('config.php'); $sql = "select * from CLASS_STUDENT ORDER BY STUDENT_NAME ASC "; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <form name="form1" method="post" action=""> <table style="text-align: left; padding: 5px;" cellpadding="0px" cellspacing="0px"> <tbody> <tr> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Name</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Class</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Section</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Current Date</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Present</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Absent</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Comment</th> </tr> <?php while($rows=mysql_fetch_array($result)) { ?> <tr> <td class="table1"> <? $id[] = $rows['STUDENT_NAME']; ?><? echo $rows['STUDENT_NAME'];?> </td> <td class="table1"> <input name="class[<? echo $rows['STUDENT_NAME']; ?>]" type="text" value="<? echo $rows['STUDENT_CLASS']; ?>"> </td> <td class="table1"> <input name="section[<? echo $rows['STUDENT_NAME']; ?>]" type="text" value="<? echo $rows['STUDENT_SECTION']; ?>"> </td> <td class="table1"> <input name="date[<? echo $rows['STUDENT_NAME']; ?>]" type="text" value="<? echo $rows['PRESENT_DATE']; ?>"> </td> <td id="present"> <input type="radio" name="present[<? echo $rows['STUDENT_NAME']; ?>]" checked="checked" value="PRESENT">Present </td> <td id="absent"> <input type="radio" name="present[<? echo $rows['STUDENT_NAME']; ?>]" value="ABSENT">Absent </td> <td style="text-align: left; padding: 5px; border: 1px #000000 solid; height: 33px;"> <input name="comment[<? echo $rows['STUDENT_NAME']; ?>]" type="text" value="<? echo $rows['COMMENT'];?>"> </td> </tr> <?php }?> <tr> <td colspan="7" style="vertical-align:middle; text-align: center;"><br><br> <input id="Submit" type="submit" name="Submit" value="Insert" style="text-align: center; background-color: #000000; color: #ffffff; border: 1px #000000 solid;"> </td> </tr> </tbody> </table> </form> <?php if(isset($_POST['Submit'])) { foreach($_POST['present'] as $id => $value) { $class=$_POST['class']; $section=$_POST['section']; $date=$_POST['date']; $comment=$_POST['comment']; $sql = "INSERT INTO ATTENDANCE(STUDENT_NAME, STUDENT_CLASS, STUDENT_SECTION, PRESENT_DATE, STUDENT_PRESENT, COMMENT) VALUES ('".$id."', '$class[$value]', '$section[$value]', '$date[$value]', '".$value."', '$comment[$value]') "; $result = mysql_query($sql); } } if($result) { header("location:Tea_home.php"); } else { //print_r ($_POST); echo "Your entry is not completed at this time............."; } ?> My result is comming just like that STUDENT_ID || STUDENT_NAME || STUDENT_CLASS || STUDENT_SECTION || PRESENT_DATE || STUDENT_PRESENT ||COMMENT 231 || PRASHANT KUMAR || || || 1/1/0001 12:00:00 AM || ABSENT || 230 || JYOTI NANDA || || || 1/1/0001 12:00:00 AM || PRESENT || 229 || TARUN NANDA || || || 1/1/0001 12:00:00 AM || PRESENT || 228 || RAVI KUMAR || || || 1/1/0001 12:00:00 AM || PRESENT || 227 || RAJIV KUMAR || || || 1/1/0001 12:00:00 AM || PRESENT || 226 || PRASHANT KUMAR || || || 1/1/0001 12:00:00 AM || ABSENT || 225 || JYOTI NANDA || || || 1/1/0001 12:00:00 AM || PRESENT || can you help me where i am writing wrong code I am trying to update multiple rows in a mysql db through php but I am getting an error message in this line: $size = count($_POST['uid']); My db field names are uid (which autoincrements and does not need to be updated), fname, lname and email fields. Here is a link for the project I need to develophttp://users.cis.fiu.edu/~vagelis/classes/COP5725/project.htm Here is the content for the first page: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head> <style type="text/css"> body { margin:50px 0px; padding:0px; text-align:center; font:13px Tahoma,Geneva,sans-serif } #content { width:1000px; margin:0px auto; text-align:left; padding:15px; border:1px dashed #333; background-color:#eee; } </style> <link rel="icon" href="http://www.mysite.com/favicon.ico" type="image/vnd.microsoft.icon" /> </head> <body> <div id='content'><h3><center>Update Information</center></h3> <?php //create a connection $connection = mysql_connect("localhost","root","r2d2c3po"); //test the connection if (!$connection) { die("Database connection failed: " . mysql_error()); } //select database to use mysql_select_db("music_social_network", $connection); //setup query $sql = "SELECT * FROM `user` ORDER BY uid"; //get results from query or die $result = mysql_query($sql, $connection) or die(mysql_error()); //fetch rows from query $rows = mysql_fetch_assoc($result); ?> <?php // find out how many records there are to update $size = count($_POST['uid']); // start a counter in order to number the input fields for each record $i = 0; print "<table width='100%' border='0' cellspacing='1' cellpadding='0'><tr><td>"; // open a form print "<form name='namestoupdate' method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>User ID</strong></td> <td align='center'><strong>First Name</strong></td> <td align='center'><strong>Last Name</strong></td> <td align='center'><strong>Email</strong></td> </tr>\n"; // start a loop to print all of the users with their information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { print "</tr>\n"; // assuming you have three important columns (the index (id), the course name (course), and the book info (bookinfo)) // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['uid']}</p></td>\n"; print "<td align='center'><input type='text' fname='fname[$i]' value='{$Update['fname']}' /></td>"; print "<td align='center'><input type='text' size='40' lname='lname[$i]' value='{$Update['lname']}' /></td>\n"; print "<td align='center'><input type='text' size='40' email='email[$i]' value='{$Update['email']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection ++$i; } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; mysql_close($connection); ?><br /><br /><div></body> </html> here is the content for the update.php page: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head> <style type="text/css"> body { margin:50px 0px; padding:0px; text-align:center; font:13px Tahoma,Geneva,sans-serif } #content { width:1000px; margin:0px auto; text-align:left; padding:15px; border:1px dashed #333; background-color:#eee; } </style> <link rel="icon" href="http://www.mysite.com/favicon.ico" type="image/vnd.microsoft.icon" /> </head> <body> <div id='content'><h3><center>Success! </center></h3> <table width='100%' border='0' cellspacing='1' cellpadding='0'><tr><td> <table width='100%' border='0' cellspacing='1' cellpadding='1'> <tr> <td align='center'><strong>User ID</strong></td> <td align='center'><strong>First Name</strong></td> <td align='center'><strong>Last Name</strong></td> <td align='center'><strong>Email</strong></td> </tr> <?php //create a connection $connection = mysql_connect("localhost","root","r2d2c3po"); //test the connection if (!$connection) { die("Database connection failed: " . mysql_error()); } //select database to use mysql_select_db("music_social_network", $connection); //setup query $sql = "SELECT * FROM `user` ORDER BY uid"; //get results from query or die $result = mysql_query($sql, $connection) or die(mysql_error()); //fetch rows from query $rows = mysql_fetch_assoc($result); // find out how many records there are to update $size = count($_POST['uid']); // start a loop in order to update each record $i = 0; while ($i < $size) { // define each variable $uid = $_POST['uid'][$i]; $fname = $_POST['fname'][$i]; $lname = $_POST['lname'][$i]; $email = $_POST['email'][$i]; // do the update and print out some info just to provide some visual feedback $query = "UPDATE `user` SET `fname` = '$fname', `lname` = '$lname', `email` = '$email' WHERE `uid` = '$uid' "; mysql_query($sql) or die ("Error in query: $query"); print " </tr> <td align='left'><p>$uid</p></td> <td align='left'>$fname</td> <td align='left'>$fname</td> <td align='left'>$lname</td> </tr> "; ++$i; } mysql_close($connection); ?> <tr> <td colspan='4' align='center'> </td> </tr> </table> </td> </tr> </table></div></body></html> Mod edit: [code] . . . [/code] tags added. Hi, I'm trying to a query to check whether a record has a reference in two other tables, I have the following: Explain SELECT COUNT(*) AS new FROM entity_details LEFT JOIN entity_turned_prospect ON entity_details.id = entity_turned_prospect.entityRef LEFT JOIN entity_turned_customer ON entity_details.id = entity_turned_customer.entityRef WHERE entity_details.ownerRef = 41 AND entity_details.typeRef = 4 AND entity_details.dateCreated = MONTH(NOW()) AND entity_turned_prospect.id = NULL AND entity_turned_customer.id = NULL But I get 0 results returned when I know for a fact there should be some. If I change the count to just select * I then get an error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS new FROM entity_details, LEFT JOIN entity_turned_prospect ON' at line 1 Could someone show me how to fix this? Hi Guys Just need some advice to go in the right direction. I'm working on a csv upload script (part of a bigger thing i'm building), so i read in the csv to a multipdimensional array and then build a query that inputs all rows in one query - i read this is the most efficient way to import multiple rows of data at once(rather than multiple insert statements). Just for illustration here's the code i use to build the query so you understand what i'm on about: Code: [Select] $sql = "INSERT INTO teams (company, teamname, teamnum, amountraised, country, president) VALUES "; // $rows is a count of the rows in the csv for($i=1; $i<$rows; $i++){ $sql.="('{$myarray[$i][0]}','{$myarray[$i][1]}','{$myarray[$i][2]}','{$myarray[$i][3]}','{$myarray[$i][4]}','{$myarray[$i][5]}')"; echo $i . "<br/>"; if($i >= 1 && $i < $rows - 1) { $sql.= ","; } } Anyway, the issue is that one of the fields("teamnum") needs to be unique - so i've set this as unique on the table in mysql. But when i run my query it doesn't import anything if one of the records isn't unique. What i really want is for it to import the ones it can and catch the ones it cant import to present to the user. So my question is - to acheive the above would i need to rewrite the query so that it inserts each row one at a time, instead of all together? Or can someone point me in the right direction for a better solution? Probably something very simple i've missed i am sure... Thanks chaps! Hi All, I'm hoping someone can help me. I'm looking to create a form that will submit multiple entries to a MySQL database depending on the options selected on the form. I am able to submit single entries, but the multiple entire is a bit of a mystery to me. I have attached an JPG image to show an example of how I would like the form to work. I have also added the description/explination below to this example: Example 1 The form was completed and three access types were selected. Thus Three entries, all with the Same Reference number were captured into the database Example 2 The form was completed and Two Access Types were selected. Thus Two entries, all with the Same Reference number were captured into the database Example 3 The form was completed and Four Access Types were selected. Thus Four entries, all with the Same Reference number were captured into the database I'm trying to echo multiple rows from a MySQL database with no luck. I've tried this code and many other combinations with it, but can't seem to get a result. Quote $query = "select email,mens,womens from newsletters"; $result = mysql_query($query); while ($row = mysql_fetch_assoc($result)) {foreach ($row as .$email. .$mens. .$womens.) {echo "$email - $mens - $womens<BR>";}} What am I doing wrong? I've got a region-type select form where a user chooses his/her continent, and depending on the selection, a second select form is filled with country values relating to that continent. From there, depending on the country selection, a third select form is dynamically filled with regions relating to that country and continent. See the code attached: <form action="" method="POST"> <select id="continent" name="continent" style="min-width: 170px;"> <option value="">Select Continent</option> <?php $q = "SELECT * FROM table_areaContinent"; $r = mysql_query($q) or die(mysql_error()); while($row = mysql_fetch_array($r)){ $continent_id = $row['cont_id']; $continent = $row['continent']; print '<option value="' . $continent_id . '">' . $continent . '</option>' . "\n"; } ?> </select> <br /><br /> <select id="country" name="country" style="min-width: 170px;"> <option value="">Select Country</option> <?php $q = "SELECT * FROM table_areaCountry JOIN table_areaContinent USING (cont_id)"; $r = mysql_query($q) or die(mysql_error()); while($row = mysql_fetch_array($r)){ $country_id = $row['country_id']; $country = $row['country']; $continent_id = $row['cont_id']; print '<option value="' . $country_id . '" class="' . $continent_id . '">' . $country . '</option>' . "\n"; } ?> </select> <br /><br /> <select id="region" name="region" style="min-width: 170px;"> <option value="">Select Region</option> <?php $q = "SELECT * FROM table_areaRegion JOIN table_areaCountry USING (country_id)"; $r = mysql_query($q) or die(mysql_error()); while($row = mysql_fetch_array($r)){ $region_id = $row['region_id']; $region = $row['region']; $country_id = $row['country_id']; print '<option value="' . $region_id . '" class="' . $country_id . '">' . $region . '</option>' . "\n"; } ?> </select> <br /><br /> <input type="submit" value="Submit" name="submit" class="submit" /> </form> Now, I simply just want to echo out the Continent, Country and Region that the user selected after the form is submitted. I currently have this : <?php if(!empty($_POST['submit'])){ $continent = $_POST['continent']; $country = $_POST['country']; $region = $_POST['region']; print ' <b>Continent: ' . $continent . '<br /> <b>Country: ' . $country . '<br /> <b>Region: ' . $region . '<br /> '; } ?> Which echoes out the ID numbers for each variable. What would be the best direction to take when pulling data from multiple tables to echo out the actual Names that the IDs are assigned to? Hi, I am having difficulty deleting rows in my table using check boxes. I have all the check boxes displaying for each row and a delete button below the table. However when i click on the delete button it isnt deleting the checked rows, i have displayed the code below that i am using; Code: [Select] <?php $result = mysql_query("SELECT * FROM contact ORDER BY msg_id ASC"); echo "<table border='1'> <tr> <th>Delete</th> <th>Message ID</th> <th>Name</th> <th>Email</th> <th>Message</th> </tr>"; while($row = mysql_fetch_array($result)) { ?> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $row['del_id']; ?>"></td> <?php echo "<td>" . $row['msg_id'] . "</td>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['email'] . "</td>"; echo "<td>" . $row['msg'] . "</td>"; echo "</tr>"; } echo "</table>"; ?> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <?php // Check if delete button active, start this if(isset($_GET['delete'])) { for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM contact WHERE id=".$_GET['del_id']; $result = mysql_query($sql); } // if successful redirect to delete_multiple.php if($result){ } } mysql_close(); ?> Please help Thank you hello friend, I use these code for update my database with radio button checked or unchecked through array but my code could not update the server data please help me ::: my code is ::: <?php //include configuration file for connection include_once('config.php'); $sql = "select * from ATTENDANCE"; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <form name="form1" method="post" action="<? echo $_SERVER['REQUEST_URI']; ?>"> <table style="text-align: left; padding: 5px;" cellpadding="0px" cellspacing="0px"> <tbody> <tr> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student ID</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Name</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Present</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Student Absent</th> <th style="text-align: center; padding: 5px; border: 1px #000000 solid;">Comment</th> </tr> <?php while($rows=mysql_fetch_array($result)) { ?> <tr> <td class="table1"> <? $id[] = $rows['STUDENT_ID']; ?><? echo $rows['STUDENT_ID']; ?> </td> <td class="table1"> <? echo $rows['STUDENT_NAME']; ?> </td> <td id="present"> <input type="radio" name="present<? echo $rows['STUDENT_ID']; ?>" checked="checked" value="PRESENT">Present </td> <td id="absent"> <input type="radio" name="present<? echo $rows['STUDENT_ID']; ?>" value="ABSENT">Absent </td> <td style="text-align: left; padding: 5px; border: 1px #000000 solid; height: 33px;"> <? echo $rows['COMMENT']; ?> </td> </tr> <?php }?> <tr> <td colspan="5" style="vertical-align:middle; text-align: center;"><br><br> <input id="Submit" type="submit" name="Submit" value="Submit" style="text-align: center; background-color: #000000; color: #ffffff; border: 1px #000000 solid;"> </td> </tr> </tbody> </table> </form> <?php if($_POST['$Submit']) { foreach($_POST['STUDENT_ID'] as $id) { $sql = "UPDATE ATTENDANCE SET STUDENT_PRESENT = '".$_POST["present".$id]."' WHERE STUDENT_ID = '".$id."' "; $result = mysql_query($sql); } } if($result) { print_r ($_POST); header("location:report.php"); } else { echo "Your entry is not completed at this time............."; } ?> Check out my code below and you will see what I am trying to do. I cannot figure out what is going wrong. Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/mskordus/public_html/index.php on line 25 Code: [Select] <?php $result = mysql_query("SELECT * FROM students,teachers,specialEd,course,sched,notes WHERE students.studentId=notes.studentId AND students.studentId=sched.studentId AND students.teacherId=teachers.teacherId AND students.specialId=specialEd.specialId AND students.courseId=course.courseId AND "); echo "<table>"; while ($row = mysql_fetch_array($result)){ echo "<tr>"; echo "<td>" . $row['students.fName'] . "</td>"; echo "<td>" . $row['teachers.fName'] . "</td>"; echo "</tr>"; } echo "</table>"; ?> Hi guys, I'm trying to query two tables for different data and echo the results that match both tables. Here are the tables I have and the query I'm trying to run. (Table) qc_reports (Fields) id report_date report_lot_number report_po report_supplier report_buyer report_inspectedby report_pulptemprange report_carrierconditions report_supplierclaim report_carrierclaim report_temprecorder report_temprange_N report_temprange_M report_temprange_B report_suppliercontact report_contactedby report_time report_comments (Table) qc_lots (Fields) id report_id lot_temprange lot_commodity lot_rpcs lot_brand lot_terms lot_cases lot_orgn lot_estnum lot_avgnum This is the query that I'm trying to do. Code: [Select] <?php $sql = "SELECT * FROM qc_reports, qc_lots WHERE "; if (!empty($start_date) and !empty($end_date)) $sql .= " qc_reports.report_date BETWEEN '$start_date' and '$end_date' AND "; if (!empty($search_fronteralot)) $sql .= " qc_reports.report_lot_number = '$search_fronteralot' AND "; if (!empty($search_buyer)) $sql .= " qc_reports.report_buyer = '$search_buyer' AND "; if (!empty($search_supplier)) $sql .= " qc_reports.report_supplier = '$search_supplier' AND "; if (!empty($search_po)) $sql .= " qc_reports.report_po = '$search_po' AND "; if (!empty($search_carrierconditions) and $search_carrierconditions != 'all') $sql .= " qc_reports.report_carrierconditions = '$search_carrierconditions' AND "; if (!empty($search_commodity) and $search_commodity != 'all') $sql .= " qc_lots.lot_commodity = '$search_commodity' AND "; if (!empty($search_inspectedby)) $sql .= " qc_reports.report_inspectedby = '$search_inspectedby' AND "; $sql = substr($sql, 0, -4); $query = mysql_query($sql); $numrows = mysql_num_rows($query); ?> RESULTS - <?php echo $numrows; ?> <hr> <table width='500'><tr><td><b>Date</b></td><td><b>Lot Number</b></td><td><b>PO</b></td><td> </td></tr> <tr> <td> </td> </tr> <?php while ($row = mysql_fetch_assoc($query)) { $id = stripslashes($row['id']); $report_lot_number = stripslashes($row['report_lot_number']); $report_po = stripslashes($row['report_po']); $report_date = stripslashes($row['report_date']); echo "<tr> <td>" . $report_date . "</td></td><td>" . $report_lot_number . "</td><td>" . $report_po . "</td><td><a href='view_report.php?id=" . $id . "'>View</a></td> </tr>"; } echo '</table><br><br><br><hr><br><br>'; } ?> All the variables are passed from a HTML form with $_POST. I need the search to work like this: If there is a value in a form field then the query gets appended with that value but when it gets to the $search_commodity it needs to search the second table (qc_lots) and check for the results. Any results that match have to be matched to the results from the first table (qc_reports) and display (echo) only qc_reports that match to both tables. The only common field is the report_id on the qc_lots table and the id on the qc_reports table. I'm stuck and need some guidance. Can someone help please? I made a small editing system for my news page, and I need to update three columns within my table "announcements" in the database. I tried a method of updating all of them with one MySQL query instead of using three as it just isn't neat. I've searched several methods via google and I've tried all of them, but just can't seem to get it to work. Is this MySQL query correct? mysql_query("UPDATE announcements SET title = {$title} WHERE id = '$id', content = {$content} WHERE id = '$id', lastmodified = ". date('M-d-Y') ." WHERE id = '$id'"); I am loading notifications from a database table called "notifications" and I am having a little trouble getting them to order in the correct way. my query I'm using right now: Code: [Select] $query = mysql_query("SELECT B.* FROM (SELECT A.* FROM notifications A WHERE A.user_id='$session' AND A.from_id!='$session' ORDER BY A.id ASC ) AS B ORDER BY B.state ASC LIMIT 7"); this works well as far as showing the unread notifications on top, then the read notifications below, however it's not ordering the two sets by ID (which the id auto increments so the higher id number is the newest) from newest on top to the oldest on bottom, still keeping them separated by the unread on top, read on bottom (column name is state for showing whether they're read or not). The order the notifications are displaying by their ID is: 3 5 2 4 1 when it should be: 5 3 2 4 1 |
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