PHP - Duplicated Webpage Does Not Show Wordpress Blog

Hi guys,

I am currently stuck in a situation.

I have duplicated names in my form. View duplicated.jpg for a reference.

What exactly went wrong? Any help will be greatly appreciate! How do I eliminate the duplicated names. Thanks!!

And my $count is currently not working as well, it is supposed to be 5 columns per row.

Code: [Select]
<?php
/***Pre-School Level***/
echo '<input name="level[]" type="checkbox" id="level_1" value="1">';
echo '<span class="zone_text_enlarge"><label for="level_1">Pre-School</label></span><br/>';

$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME)
or die(mysqli_error($dbc));

$query = "SELECT sl.subject_level_id, sl.level_id, sl.subject_id, tl.level_name AS level_name, ts.subject_name AS subject_name " .
        "FROM tutor_subject_level AS sl " .
        "INNER JOIN tutor_level AS tl USING (level_id) " .
        "INNER JOIN tutor_subject AS ts USING (subject_id) " .
"ORDER BY subject_level_id ASC LIMIT 7";

    $sql = mysqli_query($dbc, $query)
or die(mysqli_error($dbc));


$query1 = "SELECT subject_level_id FROM tutor_overall_level_subject WHERE tutor_id = '" . $_GET['tutor_id'] . "'";

$sql1 = mysqli_query($dbc, $query1)
or die(mysqli_error($dbc));

$selected_subjects = array();
while ($row = mysqli_fetch_array($sql1)) {
array_push($selected_subjects, $row['subject_level_id']);
}

echo'<table><tr>'; // Start your table outside the loop... and your first row
$count = 0; // Start your counter
while($data = mysqli_fetch_array($sql)) {
/*  Check to see whether or not this is a *new* row
If it is, then end the previous and start the next and restart the counter.
*/
if ($count % 5 == 0) { 
echo "</tr><tr>"; $count = 0;
}
foreach($selected_subjects as $selected_subject) {
if ($data['subject_level_id'] == $selected_subject) {
echo '<td><input name="subject_level[]" class="subject_a" type="checkbox" checked="checked" id="subject_level_'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>';
echo '<label for="subject_level_'.$data['subject_level_id'].'" class="subject_1">'.$data['subject_name'].'</label></td>';
$count++; //Increment the count
}
else {
echo '<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>';
echo '<label for="subject_level_'.$data['subject_level_id'].'" class="subject_1">'.$data['subject_name'].'</label></td>';
$count++; //Increment the count
}
}

} 
echo '</tr></table><br/>'; //Close your last row and your table, outside the loop
?>

This is the end result of the HTML code, through 'view page source' in web browser
Code: [Select]
<input name="level[]" type="checkbox" id="level_1" value="1">

<span class="zone_text_enlarge"><label for="level_1">Pre-School</label></span><br/>

<table><tr></tr>

<tr>
<td><input name="subject_level[]" class="subject_a" type="checkbox" checked="checked" id="subject_level_1" value="1"/>
<label for="subject_level_1" class="subject_1">Mathematics</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_1" value="1"/>
<label for="subject_level_1" class="subject_1">Mathematics</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_2" value="2"/>
<label for="subject_level_2" class="subject_1">English</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_2" value="2"/>
<label for="subject_level_2" class="subject_1">English</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_3" value="3"/>
<label for="subject_level_3" class="subject_1">Chinese</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_3" value="3"/>
<label for="subject_level_3" class="subject_1">Chinese</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_4" value="4"/>
<label for="subject_level_4" class="subject_1">Tamil</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_4" value="4"/>
<label for="subject_level_4" class="subject_1">Tamil</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_5" value="5"/>
<label for="subject_level_5" class="subject_1">Malay</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_5" value="5"/>
<label for="subject_level_5" class="subject_1">Malay</label></td>
</tr>

<tr>
<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_6" value="6"/>
<label for="subject_level_6" class="subject_1">Phonics</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" checked="checked" id="subject_level_6" value="6"/>
<label for="subject_level_6" class="subject_1">Phonics</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_7" value="7"/>
<label for="subject_level_7" class="subject_1">Creative Writing</label></td>

<td><input name="subject_level[]" class="subject_a" type="checkbox" id="subject_level_7" value="7"/>
<label for="subject_level_7" class="subject_1">Creative Writing</label></td></tr>

</table><br/>

Hello. I have here a php code getting information from mysql but when printing the result is duplicated, or more.

Code: [Select]
<?php 
$query = "SELECT SUM(amount) FROM user_detail"; 
 
$result = mysql_query($query) or die(mysql_error());

// Print out result
while($row = mysql_fetch_array($result)){
echo "<p align=\"left\">Total ".$row['SUM(amount)']."</p>";

}

?>
and then I get result like this:



you can see there are 3 result and I need to print only one time. I use for sql connection other file with :

include_once("./includes/config.php");

Need help to solve this Thanks in advance

Hello, I'm trying to code a private message system and got stuck (yup, again) on this part:

At the page where the messages are read, I'd like to display all the messages where the same sender and the receiver participate, like this:

Code: [Select]
SELECT * FROM messages WHERE sender = 1 AND receiver = 2 OR sender = 2 AND receiver = 1 ORDER BY date LIMIT 0,10;
Is there anyway to do something like that?
Thank you.

(Again, sorry for the weird Subject, I gave my best)

Hello, I have 3 tables for clients, orders and the products they ordered.   Here are the tables...

Clients
CLIENT_ID
CLIENT_NAME

Orders
o_id client_id
o_number
o_date o_notes   Products
o_id
qty
name   I am getting the results I need with this query...

SELECT
    clients.CLIENT_ID, clients.CLIENT_NAME,
    orders.o_id, orders.client_id, orders.o_date, orders.o_number, orders.o_notes,
    products.o_id, products.qty, products.name
    FROM clients, orders, products
    WHERE clients.CLIENT_ID = orders.client_id
    AND orders.o_id = products.o_id
    AND orders.o_id = $theOrder

..and this is the php I use to display it...

while ($row = $result->fetch_assoc()) {

    echo "<h2>$row[CLIENT_NAME]</h2>";
    echo '<label>Date</label><input type="text" value="'.timechange($row['o_date']).'" readonly><br>';
    echo '<label>Order No.</label><input type="text" value="'.$row['o_number'].'" readonly><br>';
    echo '<label>Notes</label><input type="text" value="'.$row['o_notes'].'" readonly>';
    echo '<label>Product Qty.</label><input type="text" value="'.$row['qty'].'" readonly><br>';
    echo '<label>Product Name</label><input type="text" value="'.$row['name'].'" readonly><br>';
}

However - rather predictably I am getting three forms printed out as the results from MySQL look like this...  mysql0.jpg   33.47KB   0 downloads   Is it possible to somehow get my form to display the results, like this...  mysql1.jpg   22.54KB   0 downloads   I hope I'm explaining myself well enough - and thank you for reading.
Edited by tHud, 04 July 2014 - 11:06 AM.

Hi,

Right when a form is submit the data in the form is added to the database basically I need to know how I can check one of the inputs to see if 'http://' has been add along with an URL, if it has not I need to add it in front of the string. How can this be done?

Regards

Lee

Hi,

I have a question. Currently, when I retrieve the records in my zone 'North', there is no misalignment.

However when I tried to copy the same coding to make up zone 'West', the alignment went off? May I know what is the reason? Any advice to align it properly.

Attached is the picture of my example



<div id ="location">
<input name="zone[]" type="checkbox" id="1" value="1">
    <label for="1">North</label><br />
   
   <?php
      $dbc = mysqli_connect('localhost', 'aliendatabase', '1234567', 'aliendatabase')
      or die(mysqli_error());
      $query = ("SELECT * FROM tutor_preferred_district ORDER BY district_id ASC");
      $sql = mysqli_query($dbc, $query)
      or die(mysqli_error());
      echo'<table><tr>'; // Start your table outside the loop... and your first row
      $count = 0; // Start your counter
         while($data = mysqli_fetch_array($sql)) {
            /*    Check to see whether or not this is a *new* row
               If it is, then end the previous and start the next and restart the counter.
            */
            if ($count % 3 == 0) {
            echo "</tr><tr>"; $count = 0;
         }
            echo '<td><input name="district[]" type="checkbox" id="'.$data['district_id'].'" value="'.$data['district_id'].'">';
            echo '<label for="'.$data['district_id'].'">'.$data['district_name'].'</label></td>';
            $count++; //Increment the count
      }
     echo '</tr></table><br />'; //Close your last row and your table, outside the loop
   ?>
   

   <input name="zone[]" type="checkbox" id="2" value="2">
    <label for="2">West</label><br />
   <?php
      $dbc = mysqli_connect('localhost', 'aliendatabase', '1234567', 'aliendatabase')
      or die(mysqli_error());
      $query = ("SELECT * FROM tutor_preferred_district ORDER BY district_id ASC");
      $sql = mysqli_query($dbc, $query)
      or die(mysqli_error());
      echo'<table><tr>'; // Start your table outside the loop... and your first row
      $count = 0; // Start your counter
         while($data = mysqli_fetch_array($sql)) {
            /*    Check to see whether or not this is a *new* row
               If it is, then end the previous and start the next and restart the counter.
            */
            if ($count % 3 == 0) {
            echo "</tr><tr>"; $count = 0;
         }
            echo '<td><input name="district[]" type="checkbox" id="'.$data['district_id'].'" value="'.$data['district_id'].'">';
            echo '<label for="'.$data['district_id'].'">'.$data['district_name'].'</label></td>';
            $count++; //Increment the count
      }
     echo '</tr></table>'; //Close your last row and your table, outside the loop
   ?>
</div>

I am assuming doing the following is bad practice as the short name "Account" is both for the repository and account.  Agree?  Appears that use always takes precedent over namespace and just Account\User is always short for \NotionCommotion\Domain\Entity\Account\User and not \NotionCommotion\Api\Account\User.  Still sees like it could easily result in confusion.

namespace NotionCommotion\Domain\Repository\Account;
use NotionCommotion\Domain\Entity\Account;
class AccountRepository
{
    public function getUser(string $mainKey, int $userId):?Account\User {
        //
    }
}

Would it be better to do something like the following?  Interestingly, it worked fine on the below class but when I tried to do so on the above AccountRepository class, it resulted in AccountDir\User class not found error.  Is there any logic reason why that might/should happen, or is it more likely I just have some error elsewhere?

namespace NotionCommotion\Api\Account;
use NotionCommotion\Domain\Entity\Account as AccountDir;
class AccountService
{
    public function read():AccountDir\Account {
        //
    }
}

I have a php tutorial that I followed for creating, inserting, selecting and updating a MySQL database with php.  Everything works fine so I wanted to put it into Wordpress.  I took the code and placed it into the wordpress page and everything worked just fine except the update function. 

Here is the tutorial I used. http://www.phpsimple.net/mysql_insert_record.html  It is also the part I am having trouble with.  I am able to create a record and I am also able to select a record but when I choose "update" the form doesn't load the data.  It will outside the website but not inside wordpress.  I am hoping this is not vague but because of my inexperience I am not sure what else to say.  I will be more than happy to provide any other information you need.

Hello, guys. I'm using the following code to send me an automated mail in case the user find a broken link. But there are 2 problems: 1) after submitting I'd rather not disrupt their game by refreshing the page. So, is there any way to send mail without the post refreshing? 2) if the user hits F5, the page reloads and the code runs again, sending two or more times the same email. How can I avoid duplicated emails caused by manual browser refresh?

(the most important solution currently is how to to avoid duplicated entries, in case an ajax solution is too hard to post here.)

<form name="fbrlink" action="<?= $_SERVER['PHP_SELF']."?page=ok" ?>" method="post">
<?php
echo('<input name="sbrlink" id="B1" type="button" value="broken Link?" style="border:none; background-color:#FFFFFF; font-family:Trebuchet MS; font-size:15px; font-weight:bold; color:#1A4877; cursor:pointer; display:block; text-decoration:underline;" onclick="this.form.submit();"/>');
?>

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{ if ($_SERVER['QUERY_STRING'] == 'page=ok') {
echo '<script type="text/javascript" >confirm("Click OK to notify us.");</script>';
mail("contact@ctt.net","report broken link","Game notified:MarioBros");
echo '<script type="text/javascript" >document.fbrlink.sbrlink.disabled = true;</script>';
?>
<script type="text/javascript" >document.fbrlink.action='<?php echo $a; ?>';
alert('<?php $_SERVER['QUERY_STRING'];?>');
</script>
<?php
}
else  {}
}else{
}
?>

For solely to reduce duplicated code and when injection isn't applicable, should one use inheritance or traits?

<?php
abstract class BaseClass
{
    private $id, $name;
    public function __construct(int $id, string $name) {
        $this->id=$id;
        $this->name=$name;
    }

    public function getId():int
    {
        return $this->id;
    }

    public function getName():string
    {
        return $this->name;
    }
}

<?php
class A extends BaseClass{}
class B extends BaseClass{}
class C extends BaseClass
{
    private $foo;
    public function __construct(int $id, string $name, Foo $foo) {
        parent::__construct($id, $name);
        $this->foo=$foo;
    }
    public function getFoo():Foo {
        return $this->foo;
    }
}

<?php
trait MyTrait
{
    private $id, $name;
    public function __construct(int $id, string $name) {
        $this->id=$id;
        $this->name=$name;
    }

    public function getId():int
    {
        return $this->id;
    }

    public function getName():string
    {
        return $this->name;
    }
}

<?php
class A
{
    use MyTrait;
}
class B
{
    use MyTrait;
}
class C
{
    use MyTrait;
    private $foo;
    public function __construct(int $id, string $name, Foo $foo) {
        $this->id=$id;
        $this->name=$name;
        $this->foo=$foo;
    }
    public function getFoo():Foo {
        return $this->foo;
    }
}

 

Edited January 2, 2020 by NotionCommotion

I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith.

The cookie doesn't show if I go to that url page. But it does show up once I reload the page.  So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page?

Here is my code.

// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);

if(!empty($url_ref_name)) {

  $number_of_days = 365;
  $date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
  setcookie( "ref", $url_ref_name, $date_of_expiry,"/");

} else if(empty($url_ref_name)) {
  if(isset($_COOKIE['ref'])) {
    $user_cookie = $_COOKIE['ref'];
  }
} else {}

// This is for the sign up form
if(isset($_COOKIE['ref'])) {
  $user_cookie = $_COOKIE['ref'];
  ?>
  <fieldset>
    <label>Referred By</label>
    <div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
    <input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
  </fieldset>
  <?php
}

 

I am displaying rows from a database onto a page using:

while($row=mysql_fetch_array($query)){

echo $row['name'];

}

I need to figure out how to limit the rows shown to the page to 100. And if there are 100 rows on the page, a link will be displayed at the bottom, that says "Next 100". Then this will display the next 100 rows.
Can you give an example how to do this please?

Thanks

Hi ,

I know my code sucks but i'm learning fast!! I'm trying to show a form if the qty value in a database == 10 or a different form if the value ==20.  I tried but failed.  Any help really appreciated.

Code: [Select]

<?php require_once('Connections/book.php'); ?>
<?php
$colname_cardpayment = "-1";
if (isset($_GET['orderid'])) {
  $colname_cardpayment = (get_magic_quotes_gpc()) ? $_GET['orderid'] : addslashes($_GET['orderid']);
}
mysql_select_db($database_book, $book);
$query_cardpayment = sprintf("SELECT * FROM cards WHERE orderid = '%s' ORDER BY qty ASC", $colname_cardpayment);
$cardpayment = mysql_query($query_cardpayment, $book) or die(mysql_error());
$row_cardpayment = mysql_fetch_assoc($cardpayment);
$totalRows_cardpayment = mysql_num_rows($cardpayment);

 // Database connect
$con = mysql_connect("mysql1.myhost.ie","admin_book","root123");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("book_test", $con);


//Parse Values from Coupon.php Form
$orderid = mysql_real_escape_string(trim($_POST['orderid']));
$name  = mysql_real_escape_string(trim($_POST['name']));
$surname  = mysql_real_escape_string(trim($_POST['surname']));
$add1 = mysql_real_escape_string(trim($_POST['add1']));
$add2 = mysql_real_escape_string(trim($_POST['add2']));
$town = mysql_real_escape_string(trim($_POST['town']));
$county = mysql_real_escape_string(trim($_POST['county']));
$postcode = mysql_real_escape_string(trim($_POST['postcode']));
$phone = mysql_real_escape_string(trim($_POST['phone']));
$email = mysql_real_escape_string(trim($_POST['email']));
$letterstyle = mysql_real_escape_string(trim($_POST['letterstyle']));


$sql="INSERT INTO custdetails (orderid, name, surname, add1, add2, town, county, postcode, phone, email, letterstyle)
VALUES
('$orderid','$name','$surname','$add1','$add2','$town','$county','$postcode','phone','$email','$letterstyle')";

if (!mysql_query($sql))
  {
  die('Error: ' . mysql_error());
  }
?>

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Digital Scribe Books</title>
<link href="style.css" rel="stylesheet" type="text/css" />

<script type="text/javascript">
function MM_preloadImages() { //v3.0
  var d=document; if(d.images){ if(!d.MM_p) d.MM_p=new Array();
    var i,j=d.MM_p.length,a=MM_preloadImages.arguments; for(i=0; i<a.length; i++)
    if (a[i].indexOf("#")!=0){ d.MM_p[j]=new Image; d.MM_p[j++].src=a[i];}}
}
function MM_swapImgRestore() { //v3.0
  var i,x,a=document.MM_sr; for(i=0;a&&i<a.length&&(x=a[i])&&x.oSrc;i++) x.src=x.oSrc;
}
function MM_findObj(n, d) { //v4.01
  var p,i,x;  if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) {
    d=parent.frames[n.substring(p+1)].document; n=n.substring(0,p);}
  if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i++) x=d.forms[i][n];
  for(i=0;!x&&d.layers&&i<d.layers.length;i++) x=MM_findObj(n,d.layers[i].document);
  if(!x && d.getElementById) x=d.getElementById(n); return x;
}

function MM_swapImage() { //v3.0
  var i,j=0,x,a=MM_swapImage.arguments; document.MM_sr=new Array; for(i=0;i<(a.length-2);i+=3)
   if ((x=MM_findObj(a[i]))!=null){document.MM_sr[j++]=x; if(!x.oSrc) x.oSrc=x.src; x.src=a[i+2];}
}
</script>


</head>

<body onload="MM_preloadImages('images/buttons/home_over.png','images/buttons/books_over.png','images/buttons/cards_over.png','images/buttons/letters_over.png')">


<div id="snow">
<div id="wrapper">


<div id="header">

<div id="logo"><img src="images/digital_scripe.png" width="218" height="91" /></div>


<div id="menu"><a href="index.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Home','','images/buttons/home_over.png',1)"><img src="images/buttons/home_act.png" name="Home" width="131" height="132" border="0" id="Home" /></a><a href="books.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Books','','images/buttons/books_over.png',1)"><img src="images/buttons/books_act.png" name="Books" width="131" height="132" border="0" id="Books" /></a><a href="cards.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Cards','','images/buttons/cards_over.png',1)"><img src="images/buttons/cards_act.png" name="Cards" width="131" height="132" border="0" id="Cards" /></a><a href="letters.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Letters','','images/buttons/letters_over.png',1)"><img src="images/buttons/letters_act.png" name="Letters" width="131" height="132" border="0" id="Letters" /></a></div>
 </div>
 
 
 
 
<div id="content">



<?php 
echo 'Order ID is :  '. $orderid . '.<br />';

if ($row2['qty'] == 10)
    echo "<div>

<form action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="business" value="accounts@agraphics.ie">
<input type="hidden" name="lc" value="IE">
<input type="hidden" name="item_name" value="10 Christmas Cards">
<input type="hidden" name="item_number" value="<? echo $orderid; ?>">
<input type="hidden" name="amount" value="12.99">
<input type="hidden" name="currency_code" value="EUR">
<input type="hidden" name="button_subtype" value="services">
<input type="hidden" name="shipping" value="2.99">
<input type="hidden" name="return" value="http://www.digitalscribe/thanks.php">
<input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted">
<input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!">
<img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1">
</form>
</div>";

if ($row2['qty'] == 20)
    echo "<div>

<form action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="business" value="accounts@agraphics.ie">
<input type="hidden" name="lc" value="IE">
<input type="hidden" name="item_name" value="20 Christmas Cards">
<input type="hidden" name="item_number" value="<? echo $orderid; ?>">
<input type="hidden" name="amount" value="21.99">
<input type="hidden" name="currency_code" value="EUR">
<input type="hidden" name="button_subtype" value="services">
<input type="hidden" name="shipping" value="2.99">
<input type="hidden" name="return" value="http://www.digitalscribe/thanks.php">
<input type="hidden" name="bn" value="PP-BuyNowBF:btn_buynowCC_LG.gif:NonHosted">
<input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_buynowCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!">
<img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1">
</form>
</div>";


?>

</div>


<div id="footer" class="clear"><div id="sign"><div id="sign_text">Personalised<br />
Books</div>
</div></div>

</div></div>






</body>
</html>
<?php
mysql_free_result($cardpayment);
?>

Hi,

I would like to do the following but not sure how.

If the you/user is on index.php of http://www.domain.com/ show one page
If not show another

How would I do this?

Thanks

 

Hey I have this blog http://www.nikita-andrews.com/ingrid/?page_id=34 ... Im trying to remove the prettyphoto enlargement on posts to this page ... and not sure how to go about it.

The code for thumbnail.php is
Code: [Select]
<?php if (has_post_thumbnail()) { 
$data = get_post_meta( $post->ID, 'key', true );
if ($data[ 'project_link' ]) { ?>
<a class="externalLink tooltip" title="View Live Site" target="_blank" href="<?php echo $data[ 'project_link' ]; ?>">&infin;</a>
<?php } ?>

<?php $large_image_url = wp_get_attachment_image_src( get_post_thumbnail_id(), 'large');
if ($data[ 'video_link' ]) { ?>
<a class="thumbLink video" rel="prettyPhoto" href="<?php echo $data[ 'video_link' ]; ?>">
<?php } else { 
echo '<a class="thumbLink" href="' . $large_image_url[0] . '" title="' . the_title_attribute('echo=0') . '" >'; 
}
the_post_thumbnail(); 
echo '</a>';
} ?>
I want the thumbnails to still show but just not enlarge. Infact itd be even better if they just linked directly to the post itself.

Any help would be much appreciated!