|
PHP - Saving Files To A Directory How To Check That Its There
Hello, Its my first day coding so please forgive me for some of the silly errors I might make.
I am writing a small upload script and I want to have some sort of orginazation by uploading images to a direcotry based on the day.
The following is my code but it will fail to save the file Warning: file_put_contents(images/14-09-26/5425905a18bba.png): failed to open stream: No such file or directory This is becuase the directory with the data part is not created how should I go about first checking that this directory is there and then creating it ?
<?php
ini_set('display_errors',1);
error_reporting(E_ALL);
$today = date('y-m-j');
define('UPLOAD_DIR', 'images/' .$today. '/');
$img = $_POST['data'];
$img = str_replace('data:image/png;base64,', '', $img);
$img = str_replace(' ', '+', $img);
$data = base64_decode($img);
$file = UPLOAD_DIR . uniqid() . '.png';
$success = file_put_contents($file, $data);
print $success ? $file : 'Unable to save the file.';
?>
Similar TutorialsHello dear, I'm willing to use thumbnails into my website which is mainly like websites directory. I've been thinking to save url thumbnails into certain directory ! If i've index.php with the following image code (this would show thumbnail image of the website ANY_SITE.COM Code: [Select] <img src='http://thumbnails_provider.com/url=ANY_SITE.COM'/> then how to save the generated image into certain directory like my_site.com/thumbnails i've been thinking about Using cURL but i don't know how to apply it any help ~thanks i have made an delete files script which works for only one directory but not sub directory so i want to delete files of same extention from directory and subdirectory. My current code is Code: [Select] <? $dir = 'hmm/'; function scanr($dir){ $arr = glob($dir.'/*.jpg'); foreach($arr as $vv){ //check if $vv is a file if(is_file($vv)){ //if file, get the filename $vx=explode('/',$vv); $file=$vx[count($vx)-1]; // if no extension delete the file unlink($vv); // print the deletion message echo $vv." deleted!<br>";}else{ // if $vv is a dir then scan it again for files scanr($vv); }} } scanr($dir); ?> I have a bunch of users in a database (id, name, etc).
I have a bunch of documents which belong to users (id, filename, users_id, etc), and expect 500 or less per user.
The documents will be renamed to the document_id, and X-Sendfile (since they are stored under the document root) will be used to retrieve them and a header will be used to return them to their original name.
Is it recommended to make a separate folder for each user and store each individual user's documents in that folder, or create one folder for all documents?
If I go with the one folder approach, I will need some method from keeping the total files per folder below some reasonable limit (1,000?). My thought is to estimate the maximum potential number of folders, and creating subfolders under the main document folder. I will likely hash the ID, and use the first character to create the first subfolder, the second character to create a second subfolder in the first subfolder, and continue as long as needed to accommodate the maximum potential documents (if there are 1,000,000 potential folders, then three levels will keep the maximum per folder under 244).
Please provide rational for one approach over the other.
Thank you
Hi:
Am not sure if this is the best algorithm to go about saving a record and uploading (plus moving to another directory) files. I feel i need another algorithm?
if (self::post()->isPost()) {
#check if there is any file
if($this->request->hasFiles() == true){
$uploads = $this->request->getUploadedFiles();
$isUploaded = false;
#do a loop to handle each file individually
foreach($uploads as $upload){
#define a "unique" name and a path to where our file must go
$path = 'temp/'.md5(uniqid(rand(), true)).'-'.strtolower($upload->getname());
#move the file and simultaneously check if everything was ok
if($upload->moveTo($path)) {
#Build an array to be sent to the API for moving the uploaded file to front end directory
$files="";
$files = array(
'name' => $upload->getName(),
'link' => $this->di['url']->get('temp/' . $upload->getName()),
'direction' => 'adverts'
);
$saveResult = self::request()->request('move-advert/', array('file' => $files), 'POST');
if($saveResult->response == 'success') $isUploaded = true; else $isUploaded = false;
}
}
#if any file couldn't be moved, then throw an message
if($isUploaded) {
$save_response = self::request()->request('advert/' . $id, self::editValues(self::post()->getPost()), 'POST');
if ($save_response->response == 'success')
{
$this->flashSession->success('Advert Updated');
return $this->response->redirect('adverts/list-adverts');
} else {
$this->flashSession->notice('Could not update Advert');
}
} else {
$this->flashSession->notice('Some error ocurred. Please try again');
}
}else {
$this->flashSession->notice('You must Choose an advert image');
}
}
Any suggestions?
Hi guys, I am using a MySQL table to store if a user has access permisisons to a file. The files are stored outside the webdirectory in drive F:\ So I have this code I have been playing around with in order to display the file I access and check permissions for: <?php $file = $_GET['file']; $myfile = 'F:\files\/'.$file.'.jpg'; echo "<img src='$myfile' />"; ?> So a sample case would be say on index.php <img src="http://somedomain.com/files?file=abcdefghijkl" /> and only if the current user had permissions to view that file would they see it. Any help on how I can do this is greatly appreciated. I do understand all my above code is probably totally wrong. Cheers I almost have it but can't figure why the code below only shows one file per folder. I think it is showing the last file. I need $ul somehow looping to show all the files in $file. <?php $year = date('Y'); if ($handle = opendir("results/$year/Boys")) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { if ($handle2 = opendir("results/$year/Boys/$file")) { while (false !== ($file2 = readdir($handle2))) { if ($file2 != "." && $file2 != "..") { $ul = "<li><a href=\"#\">$file2</a></li>"; $li = "<li><a target=\"_blank\" href=\"javascript:void(0)\">$file</a> <ul> $ul </ul> </li>"; } // close if file2 }echo $li; } } } }closedir($handle);closedir($handle2); ?> Dear sirs, I need to upload files to FTP and To waste less time, I zip the files, but the problem that since it is Automation it zips with directory - like this C:/DIR.zip in zip file I have a DIR/files.... How to unzip all files to main directory on the server. Right now if the main dir is /main/html/ it unzips to /main/html/dir/files But I need /main/html/files Thank you. I am trying to find a script that will show just the file names of files in a specific directory. I tried this code posted previously on this forum and it works but shows the directory name. Code: [Select] <?php filesInDir('attachments'); function filesInDir($tdir) { $dirs = scandir($tdir); foreach($dirs as $file) { if (($file == '.')||($file == '..')) { } elseif (is_dir($tdir.'/'.$file)) { filesInDir($tdir.'/'.$file); } else { echo $tdir.'/'.$file."<br>"; } } } ?> Result is: attachments/Sedona_and_Slot_Canyon_links.docx Thanks for the help. Hello everyone. I am having trouble trying to write some script that will unlink all files in a directory. Can anyone help me? I am not sure of the best way to do this? Thankyou. I am using the following code to list mp3 files from a directory and find out if there is a file for it in mysql if so not to include it in the list. The code below is listing each file twice I only would like them to be listed once. if($_POST['submit'] != 'select') { echo'Choose an mp3 to add information.<p><select name="file">'; $dir = "/uploads/"; $result = mysql_query("SELECT * FROM dj_pool") or die(mysql_error()); $num_rows = mysql_num_rows($result); // Open a known directory, and proceed to read its contents if (is_dir($dir)) { if ($dh = opendir($dir)) { while (($file = readdir($dh)) !== false) { $info = explode(".", $file); if($info[1] == "mp3") { $i = 0; while ($i < $num_rows) { $file2 = mysql_result($result,$i,mp3); if ($file != $file2) { echo "<option value='$info[0]'>$info[0]</option>"; } $i++; } } }closedir($dh);} } print "</select><p><input type=submit value=select name=submit>"; I have a function that reads all the picture files in a folder and displays them as thumbnails. It also displays a large version of the first image in the folder and clicking the thumbnail changes the large picture. I'm trying to use pictures of arrows as a button to allow users to click and have the next picture displayed large rather than having to click each individual thumbnail but don't really know how to get started. Can anyone suggest a method or give me a hint? This is my code so far if that helps: function displayPhotos(){ global $columns,$dir,$album; generateThumbnails(); $act = 0; $keyid = 0; $thumb_selected = (isset($_GET['thumb']) ? $_GET['thumb']:''); if ($thumb_selected !==""){ $dirName = substr($thumb_selected,0,strpos($thumb_selected,basename($thumb_selected))); $thumbName = basename($thumb_selected); $thumbFile = $dirName.$thumbName; $large = str_replace('_th.jpg','.jpg',$thumbFile); } else{ $picture_array = glob("$dir*"); $large = $picture_array[$keyid]; } echo "<tr><td colspan='3' height='300' width='400' align='center'><img src='$large' alt=''></td></tr> <tr><td><img src='gallery/icons/arrow-blue-rounded-left.jpg' alt='Previous'></td><td></td><td align='right'><img src='gallery/icons/arrow-blue-rounded-right.jpg' alt='Next'> </td></tr><tr><td height='50'></td></tr>"; if ($handle = opendir("$dir")) { while (false !== ($file = readdir($handle))) { $file=$dir.$file; if (is_file($file)){ if (strpos($file,'_th.jpg')){ ++$act; if ($act > $columns) { echo "</tr><tr><td width='160' height='120' align='center'><a href='?album=$album&thumb=$file'><img src='".$file."' alt='".$file."'/></a></td>"; $act = 1; } else { echo "<td width='160' height='120' align='center'><a href='?album=$album&thumb=$file'><img src='".$file."' alt='".$file."'/></a></td>"; } } } } } } Thanks very much to anyone having a look at this! I have a directory full of pictures that I would like to display in a gallery. Originally I was going to write HTML like this...
<li> <img src=/photos/img_001.jpg"> </li>
And then simply copy and paste that for the number of photos I have, and then tweak the code to: img_002.jpg, img_003.jpg, and so on. I guess that is silly considering that I have over 500 photos to display! How could I use PHP to go to my /photos/ directory, scan all of the files in that directory, and then grab the file name so I could automate this process? Sorry, but I haven't written PHP in several years so all of this escapes me! ☹️ Hey guys, I've written a script that is suppose to Display the files within a specified directory /documents/ with check boxes to the right of them.. This worked out great. Then I wanted to devise a method to remove or unlink the selected files (via check box) when the user pressed a Submit button.. File Permissions on the server are 777 and I have hardcoded an unlink to test to see if it works and it does.. So the bug lies within my code.. Before I post the code let me explain my method in doing this. I created a for loop to name each check box after the corresponding file to the left and created a variable with the file name (to use later) Then on button press I made a for loop (it goes up to 50 because I wasn't sure how to make it the exact number of files and I didn't want to overload the server with say 1000000 :?) that goes through and checks the check box's values and if they equal 1, unlink the file in /documents/ Here's the code: Code: [Select] <html> <body> <form action="" method="post" class="delete"> <?php $dir = "documents/"; if ($handle = opendir($dir)) { echo '<h2>List of Files in '.$dir.'</h2>'; echo '<table>'; for ($i = -2; false !== ($file = readdir($handle)); $i++) { if ($file != "." && $file != "..") { echo '<tr><td><a href="'.$dir.''.$file.'">'.$file.'</a></td><td><input type="checkbox" name="Del['.$i.']" /></td</tr>'; $DelFile[$i] = $file; } } echo '</table>'; closedir($handle); } ?> <br /> <input type="submit" name="submit" value="Delete Checked Files" /> </form> <?php for ($i = 0; $i <= 50; $i++) if ('Del['.$i.']' == 1) unlink("'.$dir.''.$DelFile[$i].'"); ?> </body> </html> Help is extremely appreciated, and Thanks in advance guys! I have a file system browser i'm writing for a client. I would like to know if there's a way to determine if an object is a directory or file, so I can display a proper icon next to it depending on what it is. Any help is appreciated. Good day.
I have just written my first php phpexcell file importing into mysql without errors. now my next step is to try and read multiple excell files in a directory " files are same format" and import into mysql.
Heres my code so far.
<?php
$db_host = "localhost";$db_user = "root";$db_pass = "";$db_name ="kk";$db_table = "test";
require '/Classes/PHPExcel.php';
require_once '/Classes/PHPExcel/IOFactory.php';
$objPHPExcel = PHPExcel_IOFactory::load('Amersfoort_WR.xlsx');
foreach ($objPHPExcel->getWorksheetIterator() as $worksheet)
{
$worksheetTitle = $worksheet->getTitle();
$highestRow = $worksheet->getHighestRow(); // e.g. 10
$highestColumn = $worksheet->getHighestColumn(); // e.g 'F'
$highestColumnIndex = PHPExcel_Cell::columnIndexFromString($highestColumn);
$nrColumns = ord($highestColumn) - 64;
echo "File ".$worksheetTitle." has ";
echo $nrColumns . ' columns';
echo ' y ' . $highestRow . ' rows.';
echo "$cellValue";
$link = mysql_connect($db_host,$db_user,$db_pass);
if(!$link) die ('Could not connect to database: '.mysql_error());
mysql_select_db($db_name,$link);
for ($row = 2; $row <= $highestRow; ++ $row)
{
$val=array();
for ($col = 0; $col < $highestColumnIndex; ++ $col)
{
$cell = $worksheet->getCellByColumnAndRow($col, $row);
$val[] = $cell->getValue();
}
$sql = "insert into test (F1, F2, F3, F4) values('".$val['0']."', '".$val['1']."', '".$val['2']."','".$val['3']."')";
mysql_query($sql);
}
}
mysql_close($link);
?>
Hi All I am trying to set up a system that where a user sets up an account the system automatically sets up a new directory and inserts template files into it. I understand mkdir is something to do with it. Does anyone know how to go about this please? thanks Hi, how do I output the total files in a given directory? Here is code I cannot get to work: Code: [Select] <?php $file=fopen('C:\\dir\\folder\\proj_ath\\', 'a+'); for($i=0;$i<count($file);$i++) { print "tot files so far: $i <br />"; } ?> Any help much appreciated! How do you include files from a higher up directory? I'm currently working on a file in public_html/Directory/otherdirectory and want to include a config file that's in public_html/Directory so how would I include public_html/Directory/config.php in the public_html_Directory/otherdirectory/index.php file? I've tried using ../ and ../Directory/ in the includes line but got errors both times Edited April 11, 2020 by Nematode128Displaying the number of files in a directory and its subdirectorys <?php $path = './images_cache'; if ($handle = opendir($path)) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $fName = $file; $file = $path.'/'.$file; if(is_file($file)) $numfile++; if(is_dir($file)) $numdir++; }; }; closedir($handle); }; echo $numfiles.' files in a directory'; echo $numdir.' subdirectory in directory'; ?> |
|||||||