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PHP - Bash Syntax
This is a simple permutation function that i was converting from php:
string_gen(){
declare -a chars=('a' 'b')
max=4
let length=${#chars[@]}-1
n=0
combination=" "
for i in `seq 0 $max`;
do
let n=($n*($length))+($length)
done
remainder=0
for i in `seq 0 $n`;
do
current=$i
combination=" "
while [[ $current > 0 ]]
do
remainder=($current%$length)
echo remainder
if [ $remainder -eq 0 ]; then
combination="$combination"${chars[$length]}
else
combination="$combination"${chars[$remainder]}
current = $current/$length
fi
done
done
echo $combination
}
What is wrong with the syntax?
Link to PHP version: http://stackoverflow...o-certain-lengt
Similar Tutorials
First off I want to thank everyone that is involved here in passing on the knowledge. After all that is what its all about. Okay so I want to do a campaign on password awareness and try to capitalize a little off of it. I came across the Breached_Compilation which is 1.4 billion email and plain text passwords. It has bash scripting in it to search and parse out the info from plain text documents which are in folders then prints the results in terminal. The other thing is that it posts the passwords in clear text. How would I obfuscate a portion of the clear text passwords? What would be the best way to integrate this to PHP? I am new to coding in PHP so any help is very much appreciated. Thanks an advance. Here is the Bash script.
#!/bin/bash
dir=$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )
if [ "$1" != "" ]; then
letter1=$(echo ${1,,}|cut -b1)
if [[ $letter1 == [a-zA-Z0-9] ]]; then
if [ -f "$dir/data/$letter1" ]; then
grep -ai "^$1" "$dir/data/$letter1"
else
letter2=$(echo ${1,,}|cut -b2)
if [[ $letter2 == [a-zA-Z0-9] ]]; then
if [ -f "$dir/data/$letter1/$letter2" ]; then
grep -ai "^$1" "$dir/data/$letter1/$letter2"
else
letter3=$(echo ${1,,}|cut -b3)
if [[ $letter3 == [a-zA-Z0-9] ]]; then
if [ -f "$dir/data/$letter1/$letter2/$letter3" ]; then
grep -ai "^$1" "$dir/data/$letter1/$letter2/$letter3"
fi
else
if [ -f "$dir/data/$letter1/$letter2/symbols" ]; then
grep -ai "^$1" "$dir/data/$letter1/$letter2/symbols"
fi
fi
fi
else
if [ -f "$dir/data/$letter1/symbols" ]; then
grep -ai "^$1" "$dir/data/$letter1/symbols"
fi
fi
fi
else
if [ -f "$dir/data/symbols" ]; then
grep -ai "^$1" "$dir/data/symbols"
fi
fi
else
echo "[*] Example: ./query name@domain.com"
fi
I would like PHP to kick off the following command: Code: [Select] arp -a|sed 's/ /,/g'>arp.csv I also have an executable makeArpFile.sh: Code: [Select] #!/bin/bash arp -a|sed 's/ /,/g'>arp.csv And I have tried executing it in php with the following: $arp = exec("bash makeArpFile.sh", $output, $exit_code); echo("Last line: " . $arp . "\n"); echo("Output: " . $output . "\n"); echo("Exit Code: " . $exit_code . "\n"); /*returns: Last line: Output: Exit Code: 127 */ I also tried just plain old: $arp = exec("makeArpFile.sh", $output, $exit_code); echo("Last line: " . $arp . "\n"); echo("Output: " . $output . "\n"); echo("Exit Code: " . $exit_code . "\n"); /*returns: Last line: Output: Exit Code: 127 */ I can run plain old arp>arp.txt but I really need it formatted in BSD style (arp -a>arp.txt) in order to be able to parse it properly later. Any thoughts? EDIT: for fun I made a useBash.sh script that executed "bash makeArpFile.sh" still no luck. Hello, I am mounting google drive to my raspberry pi with this command from command line; sudo gdfs -o allow_other /var/www/html/gdfs.creds /media/pi/gdrives İt is working from command line, but it is not work when i execute it from web browser. Here php content;
shell_exec("sudo gdfs -o allow_other /var/www/html/gdfs.creds /media/pi/gdrives");
and i changed my sudoers file giving permission www-data. here is my sudoers file content # This file MUST be edited with the 'visudo' command as root. # # Please consider adding local content in /etc/sudoers.d/ instead of # directly modifying this file. # # See the man page for details on how to write a sudoers file. # Defaults env_reset Defaults mail_badpass Defaults secure_path="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin" # Host alias specification # User alias specification # Cmnd alias specification # User privilege specification root ALL=(ALL:ALL) ALL # Allow members of group sudo to execute any command %sudo ALL=(ALL:ALL) ALL www-data ALL=NOPASSWD: ALL # See sudoers(5) for more information on "#include" directives: #includedir /etc/sudoers.d Can anyone tell me what i am doing wrong ? For those not knowing about this, is a new security hole found in all linux/unix based operating systems that should be patched.
http://arstechnica.c...with-nix-in-it/
Does anyone already fix the bug. I found something interesting in the error_log file this morning
x.x.x.x - - [25/Sep/2014:01:12:34 -0500] "GET /cgi-bin/defaul_p.cgi HTTP/1.0" 404 312 "-" "() { :;}; /bin/ping -c 5 "209.126.230.74"
I'm trying to make colourized output of bash script in php. So far I have this:
<?php
$cmd = '/home/thebalk/FiveM/manage.sh restart';
while (@ ob_end_flush()); // end all output buffers if any
$proc = popen($cmd, 'r');
echo '<pre>';
while (!feof($proc))
{
echo fread($proc, 4096);
@ flush();
}
echo '</pre>';
//
// Converts Bashoutput to colored HTML
//
function convertBash($cmd) {
$dictionary = array(
'[1;30m' => '<span style="color:black">',
'[1;31m' => '<span style="color:red">',
'[1;32m' => '<span style="color:green">',
'[1;33m' => '<span style="color:yellow">',
'[1;34m' => '<span style="color:blue">',
'[1;35m' => '<span style="color:purple">',
'[1;36m' => '<span style="color:cyan">',
'[1;37m' => '<span style="color:white">',
'[m' => '</span>'
);
$htmlString = str_replace(array_keys($dictionary), $dictionary, $cmd);
return $htmlString;
}
?>
and my output looks like this: [1;36m BOT:[0;39m THE [1;32m TheBalkanRP-SRV01-test SERVER [0;39m WAS RUNNING [1;36m BOT:[0;39m STOPPING THE [1;32m TheBalkanRP-SRV01-test SERVER [1;36m BOT:[0;39m GTA V SERVER HAS STOPPED [1;36m BOT:[0;39m REMOVING CACHE FOLDER [1;36m BOT:[1;31m CACHE FOLDER HAS BEEN REMOVED [0;39m [1;36m BOT:[0;39m STARTING THE [1;32m TheBalkanRP-SRV01-test [0;39m SERVER [1;36m BOT:[1;32m SERVER HAS STARTED [0;39m I know my function is not connected with the code above but what is the right way to do it? Thank you! Hey y'all. Probably a dumb question here but I'm at a loss. I've got a PHP service script that has an include, written as so:
$config = new Config('config/config.json');
The config directory is next to the PHP script and does contain the config.json file, so when I run this from the CLI everything works great. However, I've got about 17 PHP services I need to start and really don't feel like typing them all out, so I've written a shell script that does this: #!bin/bash cd /path/to/my/script /usr/local/bin/php ./my-script.php This does start the service, but it bombs out because it can't find the config.json file. If I change the PHP to
$config = new Config('./config/config.json');
it works as expected from the shell script. Updating the files is technically possible, but fraught right now for reasons I can't really get into (sorry). Anybody know what the difference is, or have any ideas on how to get around this? Edited September 5, 2020 by maxxdI have a PHP file in /var/www/html/ called foobar.php with the following content: Quote
<?php
I set the permissions of the foobar.php file to different settings. I set the owner and group of foobar.php and /tmp/output to different values. I tried modifying the httpd.conf file. When I placed this stanza in the httpd.conf file QuoteLoadModule php7_module /usr/lib64/httpd/modules/libphp7.so I could not restart the httpd service. I tried using just QuoteLoadModule php7_module modules/libphp7.so But this failed too. I thought PHP would interpret the file regardless of how I access it (e.g., via a web page and with the php command from a Linux terminal). How do I get PHP to invoke a Bash command when someone visits a .php web page? Hi everyone, i'm trying to get it so when i visit my webpage called start.php it executes the command (/bigbrotherbot start) in the terminal which then should start the process on my linux machine. I'm currently using this code Code: [Select] <?php shell_exec('sudo /bigbrotherbot start'); ?> This script doesn't appear to do anything though. I'm very new to php and would really appreciate the help. P.S the file bigbrotherbot is the bash script which works if i actually go to the terminal myself and type /bigbrotherbot start yet when i try to make the php do it it doesnt do anything. any ideas? I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you
<title>Inputing Travel Detials</title>
<header>
<h1 align="center"> Adding Travel Detials </h1>
<body>
<p> <center><img src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
<table border="1">
<tr>
<td><a href="index.php"> Home Page </a></td>
<td><a href="administratorhomepage.html">Administrator Home Page </a></td>
<td><a href="viewhomepage.html">View Home Page </a></td>
<td><a href="Inputhomepage.html">Input Home Page </a></td>
<td><a href="traveldetials.html">Enter More Travel Detials </a></td>
</table>
</p>
<?php
include "connection.php";
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
$result = mysqli_query($dbhandle, $query)
or die(mysqli_error($dbhandle));
if($result){ echo "Success!"; }
else{ echo "Error."; }
// successfully insert data into database, displays message "Successful".
if($query){
echo "Successful";
}
else {
echo "Data not Submitted";
}
//closing the connection
mysqli_close($dbhandle)
?>
Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Hi guys
I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?
<?php
$con = mysql_connect("localhost:3306","root","password");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('sfapp', $con);
$sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')
VALUES
('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
?>
<?php
//if "email" variable is filled out, send email
if (isset($_REQUEST['pe_add'])) {
//Email information
$admin_email = $_REQUEST['pe_add'];
$forename = $_REQUEST['forename_add'];
$email = "autoreply@testing.com";
$subject = "Application";
$desc =
"Dear $forename
Thank you for submitting your online application, we will be in touch shortly.
"
;
//send email
mail($admin_email, "$subject", "$desc", "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
If you are seeing this, you need to go back and fill out the Personal Email section!
<?php
}
header("location:complete.php");
mysql_close($con)
?>
Thanks in advance.
Hi.. I create mysql syntax for query testing before i input to my php code here is my mysql code: Code: [Select] set @t = 0; set @rqty=31968; SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN @t+OUTPUT_QTY > @rqty THEN @rqty -@t ELSE OUTPUT_QTY END as qty, @t := @t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (@t < @rqty); and i attach the sample output of the above query. Now that query test is work i will input that code to my php codes. $sql = "SELECT SKUCode, Materials, Comp, Qty FROM bom WHERE SKUCode = '$SKUCode'"; $res = mysql_query($sql, $con); ($row = mysql_fetch_assoc($res)); $Materials = $row['Materials']; $Qty = $row['Qty']; $Comp = $row['Comp']; //P28 //-----Compute Req Qty and Save to table---// $ReqQty = $Qty * $POReq; // 31968 $sql = "UPDATE bom SET ReqQty = '$ReqQty' WHERE SKUCode = '$SKUCode' AND Materials = '$Materials'"; $resReqQty = mysql_query($sql, $con); $t = 0; $sql = "SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN $t+OUTPUT_QTY > $ReqQty THEN $ReqQty -$t ELSE OUTPUT_QTY END as qty, $t := $t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '$Comp' AND ($t < $ReqQty)"; when I echo the query: I got this: SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN 0+OUTPUT_QTY > 31968 THEN 31968 -0 ELSE OUTPUT_QTY END as qty, 0 := 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (0 < 31968) then I run it to the sql and I got an error: Error Code : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':= 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '' at line 1 (0 ms taken) Any help is highly appreciated Thank you so much Which of the below syntax is the better to be using? $bal = 100; if($bal > 100) { echo "you have over 100 pounds; } else { echo "you have less than 100 pounds"; } if ($bal > 100); echo "you have over than 100"; else ; echo "you have less than 100"; endif; The issue is there seems to be NO syntax error. 1. There is no relevant code before or after this line. 2. Yes, one would think a ! should be there as did I (I didn't write the code), however, even with the ! it still gives the same error. if (function_exists('gzcompress')) die(FUNCTION_NOT_FOUND); is giving me a syntax error, unexpected 'if', expecting 'function' or 'const' I am updating this code from PHP5.3 to PHP7.4 and I can't figure out what the syntax problem is since PHP allows this. I am using Eclipse PHP to do the conversion. Hi, I'm trying to redirect like this: Code: [Select] header("Location: PC_images_display.php?imagenupdated=true&id_categoria = $row_images_update_RS['id_categoria']"); } but the variable $row_images_update_RS['id_categoria'] is being passed and causes a 500 error...I know it must be a syntax error ut I can't figure it out... Thanks in advance Hi, I have this as part of my shopping basket: Code: [Select] $ATC_itemDescription = "".$row_productos_RS['color_eng'] ."";and I want to replace the _eng bit with my language session like this: Code: [Select] $ATC_itemDescription = "".$row_productos_RS['color_<?php echo ($_SESSION['session_idioma']);?>'] ."";but t doesn't work...I getthe following error Parse error: syntax error, unexpected T_STRING, expecting ']' in /usr/home/web/productos.php on line 162 Please help. Thanks I just came up with a line of code that I am not able to understand what's it doing. The code is: Code: [Select] function cost() { return $this->costStrategy->cost($this); } here costStrategy is a class property which holds a reference to the object of type CostStrategy class and cost() is a method defined in CostStrategy. I need help with some syntax for this line of code. I know what I have surrently isn't right. echo "<h3>Welcome $_SESSION['FirstName'] </h3>"; just trying to echo out a session var in a string. |
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