PHP - Ajax Passing Php Variable

This is driving me MAD!

The Variable gets passed through the URL but when I try and echo the result I gte NOTHING.

First Page.

Code: [Select]
<?php include'config.php';


$result = mysql_query("SELECT * FROM carbontrust");

while($entry = mysql_fetch_array($result))


Print "$entry[contact] - $entry[company] :: <a href='edit.php?id=$entry[id]'>Edit</a><br>";

exit;

?>


Second Page. (Where I want the Variable passed to)
Code: [Select]
<?php include'config.php';


$id = $_GET['id'];
echo "ID: $id";


}


?>

Its probably just a stupid error but iv looked through a load of tutorials and this should be correct. :/

The below script for some reason isn't passing along the product_id variable.
Code: [Select]
$product_id=$_GET['product'];
session_start();
$error=$_SESSION['error'];
$content.='<div class="product_information_text review_form">
<div class="review_header">Write a Review for '.$product_name.'</div>
<form action="./review_process.php?product='.$product_id.'">
<p class="form_item"><label>Name:</label> <input type="text" name="review_name" size="30" /></p>';
if(isset($error[0])){$content.='<p class="red">This field is required.</p>';}
$content.='
<p class="form_item"><label>E-Mail:</label> <input type="text" name="review_email" size="30" /></p>
<p class="form_item"><label>Location:</label> <input type="text" name="review_location" size="30" /></p>
<p class="form_item"><label>Describe Yourself:</label> <input type="text" name="review_describe" size="30" /></p>
<p class="form_item"><label>Review Title:</label> <input type="text" name="review_title" size="30" /></p>
<p class="form_item"><label>Best Use of Product:</label> <input type="text" name="review_best_use" size="30" /></p>
<p class="form_item"><label>Product Pros:</label> <input type="text" name="review_pros" size="30" /></p>
<p class="form_item"><label>Product Cons:</label> <input type="text" name="review_cons" size="30" /></p>
<p class="form_item"><label>Product Rating:</label><br />
<div class="rating_radio"><input type="radio" name="review_product_rating" value="1" /> <br />1</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="2" /> <br />2</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="3" checked /> <br />3</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="4" /> <br />4</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="5" /> <br />5</div>
<div class="worst">(Worst)</div><div class="best">(Best)</div>
</p>
<p>&nbsp;</p>
<p class="form_item"><label>Comments on Product:</label><br />
<textarea name="review_text" rows="10" cols="60"></textarea>
</p>
<p><input type="submit" value="Submit" name="Submit" /></p>
</form>
</div>
';
session_unset();
session_destroy();

That code shows the proper product=$product_id value in the form action tag.

Code: [Select]
$product_id=$_GET['product_id'];

$review_name=$_POST['review_name'];
$review_name = stripslashes($review_name);
$review_name = mysql_real_escape_string($review_name);
if($review_name==""){
$error0=1;
}
else{
$error0=0;
}

$review_title=$_POST['review_title'];
$review_title = stripslashes($review_title);
$review_title = mysql_real_escape_string($review_title);
if($review_title==""){
$error1=1;
}
else{
$error1=0;
}

$review_email=$_POST['review_email'];
$review_email = stripslashes($review_email);
$review_email = mysql_real_escape_string($review_email);
if($review_email==""){
$error2=1;
}
else{
$error2=0;
}

$review_location=$_POST['review_location'];
$review_location = stripslashes($review_location);
$review_location = mysql_real_escape_string($review_location);
if($review_location==""){
$error3=1;
}
else{
$error3=0;
}

$review_describe=$_POST['review_describe'];
$review_describe = stripslashes($review_describe);
$review_describe = mysql_real_escape_string($review_describe);
if($review_describe==""){
$error4=1;
}
else{
$error4=0;
}

$review_best_use=$_POST['review_best_use'];
$review_best_use = stripslashes($review_best_use);
$review_best_use = mysql_real_escape_string($review_best_use);
if($review_best_use==""){
$error5=1;
}
else{
$error5=0;
}

$review_pros=$_POST['review_pros'];
$review_pros = stripslashes($review_pros);
$review_pros = mysql_real_escape_string($review_pros);
if($review_pros==""){
$error6=1;
}
else{
$error6=0;
}

$review_cons=$_POST['review_cons'];
$review_cons = stripslashes($review_cons);
$review_cons = mysql_real_escape_string($review_cons);
if($review_cons==""){
$error7=1;
}
else{
$error7=0;
}

$review_product_rating=$_POST['review_product_rating'];
$review_product_rating = stripslashes($review_product_rating);
$review_product_rating = mysql_real_escape_string($review_product_rating);

$review_text=$_POST['review_text'];
$review_text = stripslashes($review_text);
$review_text = mysql_real_escape_string($review_text);
if($review_text==""){
$error8=1;
}
else{
$error8=0;
}

$review_show="n";

date_default_timezone_set('US/Eastern');
$review_date = date("F j, Y, g:i a T");

$error="".$error0."".$error1."".$error2."".$error3."".$error4."".$error5."".$error6."".$error7."".$error8."";

if($error!=="000000000"){
session_start();
$_SESSION['error']=$error;
header("Location: ./store.php?product=".$product_id."#review");
}
else{
$sql="INSERT INTO $tbl_name3 (product_id, review_show, review_title, review_email, review_name, review_location, review_date, review_describe, review_best_use, review_pros, review_cons, review_product_rating, review_text) VALUES ('$product_id', '$review_show', '$review_title', '$review_email', '$review_name', '$review_location', '$review_date', '$review_describe', '$review_best_use', '$review_pros', '$review_cons', '$review_product_rating', '$review_text')";
mysql_query($sql);
echo "Thank You for submitting your review. It should appear on the site
within 48 hours.";
}

The above redirects to store.php?product=#review with no product id. Ideas on why?

I had an iframe working for the last few months on a site at hostgator.  Yesterday, it quit working (403 permissions error).  After a long bout of trouble-shooting, I found out that it has something to do with mod_security that they have suddenly enabled (have no idea as I'm not a Linux guy). 

They told me they fixed the problem on my domain by whitelisting it as an exception, but strangely, even though the permissions error went away, the actual src= box of the iframe, which was the url variable I was passing in the url, no longer loads. 

So.. I'm trying to break this down into the simplest form to figure it out.  I just understand php basics so needing some verification that I'm doing this right/wrong. 

Here's my code.. 

page1.php
Code: [Select]
<? $testurl = "http://google.com"; ?>
<a href="http://mysite.blah/page2.php?url=<? echo $testurl; ?>">page2.php</a>
page2.php
Code: [Select]
if (isset($_GET['testurl'])) echo $testurl;
else echo "sorry dude";
I am only able to print "sorry dude". 
Am I doing something wrong or shouldn't this send the url? 

Thanks for the help!

hello all,

I'm new here and I'm learning mysql/php.  Currently I have a dynamic table on one of my webpages, and the loop code looks like this:while ($i < $numRows) {
$fname = mysql_result($result, $i, "fname");
$fcode = mysql_result($result, $i, "fcode");
$ftype = mysql_result($result, $i, "ftype");
$fdesc = mysql_result($result, $i, "fdesc"); ?>
  <tr>
<td><a href="showfunction.php?fname=<?php echo "$fname"; ?>" target="_self"> <?php echo "$fname"; ?></a></td>
<td> <?php echo "$fdesc"; ?> </td>
<td><div align="center"> <?php echo "$ftype"; ?> </div></td>
  </tr>
<?php $i++; 
  } ?>
what I would like to do is pass the ''fname'' variable to the "showfunction" page so it can printed from the database.  Here is the relevant portion of the page:<body><div class="codeblock"> 
<div class="title">Code:<br /> 
</div><code><pre>

<?php echo $fcode; ?>

</pre></code></div>
<br /><pre><hr />
</pre>
I know that doesn't work, and I didn't expect it to because there is no way to 'get' the 'fname' variable from the preceeding script.  I do not want to use the GET method with this because from what I understand, you can only use it with Forms.  I really don't want to put controls in all of my table fields just to be able to pass the function name to the next page.  Does that make sense?

If I could get a jumpstart on this one last hurdle, I would appreciate it.  thank you so much!

Cheers.

How, if possible, can a $var  be passed to the  forms action php file?

I tried everything with no success.

Edited December 24, 2019 by cyberRobot
Removed email address

I have a PHP page that makes a checkbox appear after a certain textbox is exited. This part of the functionality is working - the user leaves the textbox, the AJAX call is made, and if certain criteria are met, the checkbox appears or it doesn't.   Here's where I need help. When the checkbox appears on the form and the form is submitted via POST, I can't get its value. Here's the code that's in the HEAD section:

<script type="text/javascript">
$(document).ready(function() {
	$('#id2').blur(function(){
      $.post("biz/add_official.php", {
        id1: $('#id1').val(),
        id2: $('#id2').val()
      }, function(response){
        $('#usernameResult').fadeOut();
        setTimeout("finishAjax('usernameResult', '"+escape(response)+"')", 400);
      });
    	return false;
	});
});

function finishAjax(id, response) {
 /* $('#usernameLoading').hide();*/
  $('#'+id).html(unescape(response));
  $('#'+id).fadeIn();
} //finishAjax
</script>

And here's the code that's in the FORM section:

<span id="usernameResult" style="color:green;"></span>
<script>
$('.container').find('.checkOfficial input[type="checkbox"]').val()
</script>

When the form is submitted via POST, how do I see if checkbox was checked or unchecked? Both of these variables appear empty when the form is submitted: $_POST['checkOfficial'] $_POST['usernameResult']

 

My index.php,

$output .= '
		<div class="col-sm-3 col-lg-4 col-md-3">
			<div style="border:1px solid #ccc; border-radius:5px; padding:10px; margin-bottom:16px; height:300px;">
				<audio controls controlsList="nodownload" style="padding: 10px 10px 10px 10px;margin-left: -21px;">
					<source src="audio_sample/'. $row['voice_audio_file'] .'" alt="" class="img-responsive">
				</audio>
				<p align="center"><strong> '. $row['voice_name'] .'</strong></p>

				<p style="font-size: 12px;">
				Id				  : '. $row['voice_id'].' <br />
				Name			  : '. $row['voice_name'].' <br />
				Gender		      : '. $row['voice_gender'].' <br />
				Genres 			  : '. $row['voice_genres'].' <br />
				Voice Modulation  : '. $row['voice_voice_modulation'].' <br />
				Languages		  : '. $row['voice_languages'].' <br />
				Jingle Moods	  : '. $row['voice_jingle_moods'].' <br />
				Ivr 			  : '. $row['voice_ivr'].' <br /> </p>
				
				<button type="button" class="btn btn-primary" type="submit" onclick="addCart('. "'".$row["voice_id"]."'".','."'". $row["voice_name"]."'".');" style="padding: 5px 83px 5px 83px;">Add to PlayList </button>

same page ajax :

 

<script>
function addCart(voice_id, voice_name)
	{

		$.ajax({
			type: 'POST',
			url: 'cart.php',
			data: {
				voice_id   : voice_id,
				voice_name : voice_name
			},
			dataType: 'text',
			success: function(data) {
				// alert(data);


			}
		});
	}
$(document).ready(function(){

});
</script>

and get.php

 

<?php 


$voice_id =" ";
$voice_name=" ";
if(isset($_POST['voice_id']) && isset($_POST['voice_name']))
{
    $voice_id = $_POST['voice_id'];
    $voice_name = $_POST['voice_name'];

}

echo "$voice_id, . "&". , $voice_name";


?>

if click button, the value send but the get.php not properly get the value and display on the php page.

 

Edited June 12, 2019 by aveeva

Okay, I have been looking into this for the last 3 hours, and cant find shit.  I have a page with a javascript game where the player moves around on a map. They have an X and Y coordinate, but I'm having a problem. The problem is I need to store that info in a database, and I'm having trouble learning AJAX.  Heres a little list of things:

Play loads the game. A php variable is taken from a database.
The player goes to those X and Y coordinates.
The player may move around. Once they move, the player is sent to a php page that updates the Database information.
The page is refreshed to the game again, where they may then move around some more.

The problem is, when the page is changed the values are lost. For some reasons cookies aren't working at all (like just not working for anything, even a completely different file.)  I heard something about using $_GET or $_POST, but I dont see how...

i have this code in a form, i need to pass a variable $time to next page, how can i do that ?


      if( $sErr ) print "<script language='javascript' type='text/javascript'>location.href='#error';</script>";;;

else:

     print "<script language='javascript' type='text/javascript'>location.href='paypal.php';</script>";;;

i need to pass the id called id from the maim page to an iframe, but it failes to send. i'm wondering if anyone knows why it fails.

Code: [Select]
<iframe src="details.php?ID=<?php echo $ID; ?>" width="700px" height="150px">
 </iframe>

I want to build an image with text variables.
I can get the image OK but not the text, which I need to pass in an img tag from a form.
I have not posted the form  here as I know the post field is populated.
The static string shows overlayed on the image but not the variable string passed in the query string.
Any help appreciated.
My code is as follows:-
input form

<?php

if (isset($_POST['submitted'])) {

if(isset($_POST['AuthorName'])){

$str=($_POST['AuthorName']);

?><img src="http://localhost:8888/test_upload/text-create2.php?str=' . $str . '"/><?php

}

}
?>



The recieving script


<?php
$str2=$_GET['$str'];
$image = ImageCreateFromPNG("http://localhost:8888/wordpress_3/wp-content/plugins/Authors2/jackets/GDL.png");
$color = imagecolorallocate($image, 0xFF, 0xFF, 0xFF);
$colorShadow = imagecolorallocate($image, 0x66, 0x66, 0x66);
$font = 'Tahoma.ttf';
$fontSize = "10";
$fontRotation = "0";
$str= "Successful Home Catering";


/* Shadow */
ImageTTFText($image, $fontSize, $fontRotation, 27, 22, $colorShadow, $font, $str );

/* Top Level */
ImageTTFText($image, $fontSize, $fontRotation, 25, 20, $color, $font, $str);

ImageTTFText($image, $fontSize, $fontRotation, 25, 100, $color, $font, $str2);

header("Content-Type: image/PNG");
ImagePng ($image);
imagedestroy($image);
?>

hey

ive got a page that lists a users bank accounts...when the user chooses to update an account it goes to a new page where they can edit the details...when it goes to this new page it takes the user's ID and the account ID with it in the URL (http://localhost/oswp/bank/updateaccounts.php?id=34&cid=1)

so i know these variables are correctly being transferred.

now when the user has made their changes and clicked the update button it should update the database and then re-locate back to the original page listing all accounts...to get back to this page and show the correct accounts for that user i thaught i needed to take the ID from the URL...give it a variable...and use it in the URL back to the original page. so for example the variable and update sql and re-locate code would look like this.


$cid = $_GET['cid'];

//updating the table
$result=mysql_query("UPDATE accounts SET accno='$accno', pin='$pin', type='$type', name='$balance', balance='$balance', active='$active' WHERE accid=$id");

header("location:accounts.php?id=$cid");


however currently when the user clicks update and it tries to relocate back to the original page its not getting the variable in the URL.
(http://localhost/oswp/bank/accounts.php?id=)

and im getting the errors:

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\uni\oswp\assignment\bank\accounts.php on line 26
's bank accounts


Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\uni\oswp\assignment\bank\accounts.php on line 30

basically saying its expected a number up in the URL and its not finding one...but i dont know why...any ideas please its quite urgent.

here is the relevant code for this section:

Accounts.php:
<a href="adminlogout.php">Logout</a><br />
<?php
$id = $_GET['id'];
if(!isset($_SESSION['myusername'])) {
header("location:adminlogin.php");
}
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = 'bank';

$conn = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($db);
$result = mysql_query("SELECT * FROM customer WHERE cusid=$id");
$row2 = mysql_fetch_array($result);
echo $row2['name'] . "'s bank accounts" . "<br><br>";
$result2 = mysql_query("SELECT * FROM accounts WHERE cusid=$id");
echo "<form method='post' action='accounts.php?id=$id'>";
while($row = mysql_fetch_array($result2))
{
echo "<input type='hidden' value='$row[accid]' name='accid'>" . $row['accno'] . $row['name'] . $row['type'] . $row['balance'] . $row['active'] . "<a href='updateaccount.php?id=$row[accid]&cid=$id'>Update</a>" . "<br>";
}
echo "</form>";
?>


updateaccounts.php:
$id = $_GET['id'];
$cid = $_GET['cid'];
if(!isset($_SESSION['myusername'])) {
header("location:adminlogin.php");
}
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = 'bank';

$conn = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($db);

if(isset($_POST['update']))
{
$accno=$_POST['accno'];
$pin=$_POST['pin'];
$type=$_POST['type'];
$name=$_POST['name'];
$balance=$_POST['balance'];
$active=$_POST['active'];
// checking empty fields
//if item field is empty
if(empty($accno))
{
echo "<font color='red'>account number field is empty.</font><br/>";
}
elseif(empty($pin))
{
echo "<font color='red'>pin field is empty.</font><br/>";
}
elseif(empty($type))
{
echo "<font color='red'>account type field is empty.</font><br/>";
}
elseif(empty($name))
{
echo "<font color='red'>account name field is empty.</font><br/>";
}
elseif(empty($balance))
{
echo "<font color='red'>balance field is empty.</font><br/>";
}
elseif(empty($active))
{
echo "<font color='red'>active field is empty.</font><br/>";
}

else
{
//updating the table
$result=mysql_query("UPDATE accounts SET accno='$accno', pin='$pin', type='$type', name='$balance', balance='$balance', active='$active' WHERE accid=$id");
header("location:accounts.php?id=$cid");
}
}

Hi Guys,

I'm working on an image resizer, to create thumbnails for my page. The resizer works on principle of include a DIRECT link to the image. But what I want to do is put in the PHP Variable in the URL string, so that it points to that file and resizes it accordingly.

My code is as follows :
Code: [Select]
<img src="thumbnail.php?image=<?php echo $row_select_property['image_url']; ?>

Image Resize :
Code: [Select]
<?php 
// Resize Image To A Thumbnail

// The file you are resizing 

 $image = '$_GET[image_url]'; 
 
 //This will set our output to 45% of the original size 
 $size = 0.45; 
 
 // This sets it to a .jpg, but you can change this to png or gif 
 header('Content-type: image/jpeg'); 
 
 // Setting the resize parameters
 list($width, $height) = getimagesize($image); 
 $modwidth = $width * $size; 
 $modheight = $height * $size; 
 
 // Creating the Canvas 
 $tn= imagecreatetruecolor($modwidth, $modheight); 
 $source = imagecreatefromjpeg($image); 
 
 // Resizing our image to fit the canvas 
 imagecopyresized($tn, $source, 0, 0, 0, 0, $modwidth, $modheight, $width, $height); 
 
 // Outputs a jpg image, you could change this to gif or png if needed 
 imagejpeg($tn); 
?>

What I am trying to do is pass on the variable "image=<?php echo $row_select_property['image_url']; ?>" to the Thumbnail script. At the moment I am passing it through the URL string, but it doesnt  seem to load the graphic.

I'll try expand on this more, should you have questions as I am finding it a little difficult to explain.

Thanks in advance.

I'm starting to fear that this is impossible.. I will severely appreciate any kind of advice!

On site A, I have a link (an affiliate type link) that redirects to site B. When clicking the link on site A, I use this code to redirect..

header('HTTP/1.1 301 Moved Permanently');
header('Location: ' .  $url);
exit;

the $url var is just site's A URL. What I can't figure out is how to pass a variable from the redirection script onto site B without using a query string in the URL itself ( for example, http://www.siteB.com/?var_to_pass=something)

Can passing a variable between two sites be achieved with js.. or XML? I'm willing to use anything as long as I don;t have to add the variable in the URL.