PHP - How To Write This Query Properly?

I have a simply query where I want show how many unique contests are there. So if I have 100 entries in a single contest, then each entry row will have the same contest id in this example.

So even though there are 100 entries, they all belong to the same contest id. That means the echo of $total_contests should be 1. But instead I am getting the same count as the entry rows, which is 100.  What am I doing wrong?

$global_user_id = 1;

$count_contests = $db->prepare("SELECT COUNT(*) FROM entries WHERE user_id = :user_id GROUP BY contest_id");
$count_contests->bindParam(':user_id', $global_user_id);
$count_contests->execute();
$total_contests = $count_contests->fetchColumn();

echo $total_contests;

 

Hey guys,

New to the forum and a newer user of PHP / MySQL.  I am having trouble with some code I've written up.  I don't seem to get any errors when running it, but it's not updating my database the way that it should.  hopefully a simple fix.  I am thinking that it must be on the MySQL side of things. 

Couple of things to start. 

My html form is comprised completely of drop down list inputs.  I'm the only user so I thought this would be the easiest approach.

Because of that I've made my PHP as follows:

Code: [Select]
<?php

$season = $_POST['season'];
$month = $_POST['month'];
$day = $_POST['day'];
$year = $_POST['year'];
$time = $_POST['time'];
$event = $_POST['event'];
$game = $_POST['game'];
$buyin = $_POST['buyin'];

$connect = mysql_connect('localhost','root','') or die('can not connect');

if ($connect)
{
    echo "connected to database";
}

$db = mysql_select_db('dpl') or die('can not find database');

if ($db)
{
    echo "DPL Selected";
}

$query = sprintf("INSERT INTO events (season , month , day , year , time , event , game , buyin)
    VALUES ('%s' , '%s' , '%s' , '%s' , '%s' , '%s' , '%s' , '%s')",
       $season ,
       $month ,
       $day ,
       $year ,
       $time ,
       $event ,
       $game ,
       $buyin
       );

if ($query)
{
    echo "Your event has been added";
}

?>
My connection is working, my database is selected and I'm even now getting confirmation that my query is working, but when i go to check my database there are no entries in it?

any thoughts?

I've tried the drop down variables as both VARCHAR and TEXT inputs in MySQL, but I can't seem to get it to work.

Any help is greatly appreciated.

Hello All,   I'm having trouble trying to "wrap my head around" how I can make the query in my code below more efficient, elegant, and certainly immune to a SQL-injection attack   So, I have a form (which can be seen in the attached screenshot) which has the user first select a search-type via a dropdown listbox. The two choices pertain to two columns in the underlying table i.e. store_name and item_description. Once that selection is completed the user is expected to enter a search-term (which is typically in relation to the choice selected in the first prompt).   Now, what I would like to happen is that the query be created based on both, the value in the search-type prompt, as well as the value in search-term textbox, and of course, the query must be a parameterized prepared statement (to minimize the possiblity of a SQL-inection attach).   Essentially I would like to get rid of the following code (which I believe is potentially redundant, and contains a hard-coded column name between the WHERE and LIKE), to make things less complicated and more elegant/flexible

if ($searchtype == "store_name")
   {
       $sql = "SELECT * FROM `shoplist` WHERE store_name LIKE :searchterm ORDER BY store_name ASC";
   }
else if ($searchtype == "item_description")
   {
       $sql = "SELECT * FROM `shoplist` WHERE item_description LIKE :searchterm ORDER BY store_name ASC";
   }

Here's what I tried:

// Tried this first but it didn't work...gave some kind of error pertaining to the parameter 2    
// Prepare the query ONCE
$query = "SELECT * FROM `shoplist` WHERE ? LIKE ? ORDER BY ? ASC";

$searchterm = '%' . $searchterm . '%';

$statement = $conn->prepare($query);
$statement->bindValue(1, $searchtype);                                                        
$statement->bindParam(2, $searchterm);
$statement->bindValue(3, $searchtype);
$statement->execute();

// ----------------------------------------------------------------------------------------------------------- //

// Tried this as well, but was getting unexpected results (mostly all rows being returned, regardless of input)
// Prepare the query ONCE
$query = "SELECT * FROM `shoplist` WHERE :searchtype LIKE :searchterm ORDER BY :searchtype ASC";

$searchterm = '%' . $searchterm . '%';

$statement = $conn->prepare($query);
$statement->bindValue(':searchtype', $searchtype);
$statement->bindValue(':searchterm', '%' . $searchterm . '%');
$statement->execute();

Here's the complete code (pertaining to the problem/request):

// create short variable names
if(isset($_POST['searchtype']))
    {                                            
        $searchtype=$_POST['searchtype'];
    }
if(isset($_POST['searchterm']))
    {                            
        $searchterm=trim($_POST['searchterm']);
    }

if(isset($_POST['searchtype']) && isset($_POST['searchterm']))
    {
        if (!get_magic_quotes_gpc())
            {
                $searchtype = addslashes($searchtype);
                $searchterm = addslashes($searchterm);
            }
    }

if(isset($_POST['searchtype']) && isset($_POST['searchterm']))
    {
        // ****** Setup customized query ******
        if ($searchtype == "store_name")
            {
                // The following statement is potentially open to SQL-inection attack and has therefore been REM(arked)
                // $sql = "SELECT * FROM `shoplist` WHERE " . $searchtype . " LIKE :searchterm ORDER BY store_name ASC";

                // The following may not be open to SQL-injection attack, but has the column name hard-coded in-between the WHERE and LIKE clauses
                // I would like the the column name to be set based on the value chosen by the user in the form dropdown listbox for "searchtype"
                $sql = "SELECT * FROM `shoplist` WHERE store_name LIKE :searchterm ORDER BY store_name ASC";
            }
        else if ($searchtype == "item_description")
            {
                // The following statement is potentially open to SQL-inection attack and has therefore been REM(arked)
                // $sql = "SELECT * FROM `shoplist` WHERE " . $searchtype . " LIKE :searchterm ORDER BY item_description ASC";

                // The following may not be open to SQL-injection attack, but has the column name hard-coded in-between the WHERE and LIKE clauses
                // I would like the the column name to be set based on the value chosen by the user in the form dropdown listbox for "searchtype"
                $sql = "SELECT * FROM `shoplist` WHERE item_description LIKE :searchterm ORDER BY item_description ASC";
            }

        $statement = $conn->prepare($sql);
        $statement->bindValue(':searchterm', '%' . $searchterm . '%');
        $statement->execute();
        ...
        ...
        ...
    }

Thanks guys!     Attached Files  Search-Screen-SS.png   21.31KB   0 downloads

Hello all,   Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).   The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).   Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:   In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).   I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.   Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.   So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:   1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red. 2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red. 3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.   Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.   Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.   Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.   Cheers guys!

case "update-delete":
	if(isset($_POST['highlight-purchased'])) 
		{
			// ****** Setup customized query to obtain only items that are checked ******
			$sql = "SELECT * FROM shoplist WHERE";
					for($i=0; $i < count($_POST['checkboxes']); $i++)
						{
							$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
						}
					$sql= rtrim($sql, "or");
											
			$statement = $conn->prepare($sql);
			$statement->execute();
																						
			// *** fetch results for all checked items (1st query) *** //
			$result = $statement->fetchAll();

			$statement->closeCursor();
											
			// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
			$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
											
			// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
			$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";

			$statementSetToN = $conn->prepare($sqlSetToN);
			$statementSetToY = $conn->prepare($sqlSetToY);
											
			/*** loop through the results/collection of checked items ***/
			foreach($result as $row)
				{
					if ($row["purchased"] != "Y")
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToY = $statementSetToY->fetch();
															
							foreach($resultSetToY as $row)
								{															
									$statementSetToY->execute();																
								}
						}
					else
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToN = $statementSetToN->fetch();
															
							foreach($resultSetToN as $row)
								{															
									$statementSetToN->execute();																
								}
						}
				}
				break;
		}

 CRUD Queston.png   20.68KB   0 downloads    

Here is my code:
// Start MySQL Query for Records
$query = "SELECT codes_update_no_join_1b" .
"SET orig_code_1 = new_code_1,
       orig_code_2 = new_code_2" .
"WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)";
$results = mysql_query($query) or die(mysql_error());
// End MySQL Query for Records


This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this???

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1

If you also have any feedback on my code, please do tell me. I wish to improve my coding base.

Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference.

Code:

  Code: [Select]
mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
Full code:

Code: [Select]
<?php
include_once("includes/config.php");
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><? $title; ?></title>
<meta http-equiv="Content-Language" content="English" />
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
</head>
<body>
 
<div id="wrap">
 
<div id="header">
<h1><? $title; ?></h1>
<h2><? $description; ?></h2>
</div>
 
<? include_once("includes/navigation.php"); ?>
 
<div id="content">
<div id="right">
<h2>Create</h2>
<div id="artlicles">
<?php
 
if(!$_SESSION['user'])
{
 
        $username = mysql_real_escape_string($_POST['username']);
        $password = mysql_real_escape_string($_POST['password']);
        $name = mysql_real_escape_string($_POST['name']);
        $server_type = mysql_real_escape_string($_POST['type']);
        $description = mysql_real_escape_string($_POST['description']);
 
        if(!$username || !$password || !$server_type || !$description || !$name)
        {

        echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>";
        echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'>
       
        <option value='Any'>Any</option>
        <option value='PvP'>PvP</option>
        <option value='Creative'>Creative</option>
        <option value='Survival'>Survival</option>
        <option value='Roleplay'>RolePlay</option>
       
        </select></td></tr>
       
        <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>";
        echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>";
        }
        elseif(strlen($password) < 8)
        {
        echo "Password needs to be higher than 8 characters!";
        }
        elseif(strlen($username) > 13)
        {
                echo "Username can't be greater than 13 characters!";
        }
        else
        {
                $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1");
               
                if(mysql_num_rows($check1) < 0)
                {
                        echo "Sorry, there is already an account with this username and/or server name!";
                }
                else
                {
                        $ip = $_SERVER['REMOTE_ADDR'];

                        mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
                        echo "Server has been succesfully created!";
                }
        }
       
}
else
{
        echo "You are currently logged in!";
}
 
?>
</div>
</div>
 
<div style="clear: both;"> </div>
</div>
 
<div id="footer">
<a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop
</div>
</div>
 
</body>
</html>

Say I have this query:

site.com?var=1

..I have a form with 'var2' field which submits via get.

Is there a way to produce:

site.com?var=1&var2=formdata

I was hoping there would be a quick way to affix, but can't find any info. Also, the query could sometimes be:

site.com?var2=formdata&var=1

I would have to produce:

site.com?var2=updatedformdata&var=1

Is my only option to further parse the query?

I was just wondering if it's possible to run a query on data that has been returned from a previous query?  For example, if I do

Code: [Select]
$sql = 'My query';
$rs = mysql_query($sql, $mysql_conn);

Is it then possible to run a second query on this data such as

Code: [Select]
$sql = 'My query';
$secondrs = mysql_query($sql, $rs, $mysql_conn);

Thanks for any help

I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like
UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5';
this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice?

What would be the correct way to close a mysql query?

At current the second query below returns results from the 1st query AND the 2nd query
The 3rd query returns results from the 1st, 2nd and 3rd query.
 etc etc.

At the moment I get somthing returned along the lines of...

QUERY 1 RESULTS
Accommodation 1
Accommodation 2
Accommodation 3

QUERY 2 RESULTS
Restaurant 1
Restaurant 2
Restaurant 3
Accommodation 1
Accommodation 2
Accommodation 3

QUERY 3 RESULTS
Takeaways 1
Takeaways 2
Takeaways 3
Restaurant 1
Restaurant 2
Restaurant 3
Accommodation 1
Accommodation 2
Accommodation 3

Code: [Select]

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<?php 
  include($_SERVER['DOCUMENT_ROOT'].'/include/db.php');
?>
<title>Untitled Document</title>
<style type="text/css">
<!--
-->
</style>
<link href="a.css" rel="stylesheet" type="text/css" />
</head><body>
<div id="listhold">

<!------------------------------------------------------------------------------------------------------------------------------------------------------>

<div class="list"><a href="Placestostay.html">Places To Stay</a><br />
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

<!------------------------------------------------------------------------------------------------------------------------------------------------------>

<div class="list"><a href="Eatingout.html">Eating Out</a><br />
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

<!------------------------------------------------------------------------------------------------------------------------------------------------------>

<div class="list"><a href="Eatingin.html">Eating In</a><br />
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

<!------------------------------------------------------------------------------SKILLED TRADES BELOW--------------------------------------------------->

<div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/>
<?php
$title ="TITLE GOES HERE";
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileUsed = str_replace('_',' ',$nt[$i]);
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>"  . $nt[$i] . "</a>" . "<br/>";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
?>
</div>

here's the code:

Code: [Select]
$companyName = 'big company';
$address1 = 'big bay #8';
$address2 = 'some big warehouse';
$city = 'big city';
$province = 'AB';
$postalCode = 'T1T0N0';
$phone = '0123456789';
$email2 = 'bigKahuna@bigKahuna.edu';

$query = "INSERT INTO clients (
                   companyName, address1, address2, city, province, postalCode, phone, email)
                 VALUES ( ".
                    $companyName.",".$address1.",".$address2.",".$city.",".$postalCode.",".$phone.",".$email2.")";

$result = mysql_query($query, $connexion);

if ($result)
{
// Success!
echo "Fabulous!  check the DB, we did it! :D<br>";
?>

<pre>
<?php
print_r($result);
?>
</pre>

<?php
} else {
// Fail!
echo"CRAAAAAPP!  something went wrong.  FIX IT!  :P<br>";
echo mysql_error();
}

if (isset($connexion)) { mysql_close($connexion); }
i copied it over from an old *working* file to illustrate how a simple INSERT works.

this is the error i get:

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'company,big bay #8,some big warehouse,big city,T1T0N0,0123456789,bigKahuna@bigKa' at  line 4
looks completely valid to me.  all the database table elements are set to VARCHAR(80), so it can't be a space/type issue...

halp! 

WR!

I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate.

What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop.

It doesn't matter if I get to the next page using a header redirect or a form submit.  I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. 

I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. 

Any ideas?

Code: [Select]
if (file_exists("images/".$id."/img01.jpg")) { echo "<a href=\"/v1/images/".$id."/img01.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb01.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img02.jpg")) { echo "<a href=\"/v1/images/".$id."/img02.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb02.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img03.jpg")) { echo "<a href=\"/v1/images/".$id."/img03.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb03.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img04.jpg")) { echo "<a href=\"/v1/images/".$id."/img04.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb04.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img05.jpg")) { echo "<a href=\"/v1/images/".$id."/img05.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb05.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img06.jpg")) { echo "<a href=\"/v1/images/".$id."/img06.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb06.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img07.jpg")) { echo "<a href=\"/v1/images/".$id."/img07.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb07.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img08.jpg")) { echo "<a href=\"/v1/images/".$id."/img08.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb08.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>&nbsp;"; }
if (file_exists("images/".$id."/img09.jpg")) { echo "<a href=\"/v1/images/".$id."/img09.jpg\" rel=\"lightbox\"><img src=\"/v1/images/".$id."/thumb09.jpg\" class=\"img\" border=\"0\" width=\"60\" height=\"60\"></a>"; }
This code works but it just seems a bit tedious. I may also include up to 20 images to check if they exist. Better way to do this?

hello

how would i write,

if $a has 1 or more of $b do something ?
for example

Code: [Select]

if($a >1 $b){
do something
}else{
do nothing
}


or >2
or >3

etc...

thanks

I want to create a xml-based rss which is readable by RSS readers
Code: [Select]
<?xml version="1.0"?>
<rss version="2.0">
  <channel>
    <title>Title</title>
    <link>http://link.com/</link>

How I can write php strings from a php file into it as
Code: [Select]
<item>
      <title><? echo $title ?></title>
      <link><? echo $link ?></link>
      <description><? echo $description ?></description>
      <pubDate><? echo $date ?></pubDate>
      <guid><? echo $id?></guid>
    </item>