PHP - Freeing Mysqli Objects
I have gotten into the habit of freeing MySQLi result objects once they are no longer needed. However, I'm curious about the cases where multiple MySQLi objects are being used.
Similar TutorialsEver since I started using OOP this past week, I have not been able to go back to the old "procedural" methods. HOwever, I seem to be stuck on creating a mysql connection that I can reuse in all of my classes. After I set up a connection to mysql using the mysqli object, I am unable to use the mysqli in other objects. Code: [Select] $mysqli = new mysqli(.....); class new_class { function quickQuery () { $mysqli->query('some query') } } Obviously, this doesn't work, because $mysqli is not defined within that functions scope. One way, is to use global keyword. Code: [Select] global $mysqli However, globals "are the root of all evil" and simply go against the idea of encapsulation in OOP. What's a way around this? HOWEVER: 1) I still want to use the mysqli object 2) I don't want to reference the $link of the db each time I instantiate a new class .... Maybe I'm asking too much? And I've google for the past hour or so. Singleton seems interesting but it requires the creation of a new db connection class. I want to use the mysqli object. Hello all!
I have this array of objects:
Array ( [0] => stdClass Object ( [first_name] => test [last_name] => test [title] => test [id] => 34 [type] => 4 [manager] => 4 [email] => p@yahoo.com [date] => 2014-09-21 07:23:12 [status] => 2 [approval_date] => 2014-09-21 07:31:10 [assessment_id] => 1 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-21 07:31:27 [mainmanger] => 3 ) [1] => stdClass Object ( [first_name] => test [last_name] => test [title] => test [id] => 34 [type] => 4 [manager] => 4 [email] => p@yahoo.com [date] => 2014-09-20 07:39:55 [status] => 2 [approval_date] => 2014-09-20 07:40:41 [assessment_id] => 3 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-20 07:41:07 [mainmanger] => 3 ) [2] => stdClass Object ( [first_name] => jimmy john john [last_name] => john [title] => Lorad and Master [id] => 32 [type] => 4 [manager] => 3 [email] => j@j.com [date] => 2014-09-21 07:38:50 [status] => 2 [approval_date] => 2014-09-19 07:39:25 [assessment_id] => 2 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-19 07:39:25 [mainmanger] => 0 ) )Where "id" = the user ID. If there are two or more entries for a user, I want to remove all but the most recent by the "approval_date",... So for the above example it would return: Array ( [0] => stdClass Object ( [first_name] => test [last_name] => test [title] => test [id] => 34 [type] => 4 [manager] => 4 [email] => piznac@yahoo.com [date] => 2014-09-21 07:23:12 [status] => 2 [approval_date] => 2014-09-21 07:31:10 [assessment_id] => 1 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-21 07:31:27 [mainmanger] => 3 ) [1] => stdClass Object ( [first_name] => jimmy john john [last_name] => john [title] => Lorad and Master [id] => 32 [type] => 4 [manager] => 3 [email] => j@j.com [date] => 2014-09-21 07:38:50 [status] => 2 [approval_date] => 2014-09-19 07:39:25 [assessment_id] => 2 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-19 07:39:25 [mainmanger] => 0 ) )I'm having a hard time wrapping my head around this concept, so I don't have any example code. And I don't really need or expect someone to code this for me,. just a push in the right direction would be awesome. I have the following three tables (and also delta_point and hist_point which are purposely left out and just mentioned for context). Before going down the Doctrine ORM long curvy road, aggrType was just used to restrict possible values so that I didn't need to use MySQL's ENUM, but now I am thinking there may be value to making it an entity and include some methods (and a second reason because I still can't figure out how to make Doctrine create a FK constraint yet not populate the parent entity with a AggrType object). point -id (int PK) -data -dType /* descriminator. Options are AggregatePoint, DeltaPoint, and HistoricPoint */ aggr_point -id (int PK, FK to point) -aggrType (char FK to aggrType) -data aggrType -type (char PK) /* there are about five types */ I have a service to create a new point based on the provided desired type and user data. I don't like the switch statement to determine which type of point to create, but don't know a better way. Also my entity is responsible to provide the appropriate validation rules for the given point type which might not be considered proper but it seems to work for me. Any constructive criticism is welcomed. <?php namespace NotionCommotion\PointMapper\Api\Point; use NotionCommotion\PointMapper\Domain\Entity\Point; class PointService { public function create(string $type, array $params):integer { $class=[ 'aggr'=>'AggregatePoint', 'delta'=>'DeltaPoint', 'hist'=>'HistoricPoint', ][$type]; //$class='Point\\'.$class; //This doesn't seem to be possible and I needed to use the fully qualifed name without the short cut used namespace. $class='\\Greenbean\Datalogger\Domain\Entity\Point\\'.$class; $point=new $class(); $validator=$this->getValidator($point); $params=$validator->sanitize($params); $validator->validate($params); $point->setAccount($this->account); $point->populate($params, $this->em); //Will be addressed later $this->em->persist($point); $this->em->flush(); $point->setIdPublic($this->em->getRepository(Point\Point::class)->getPublicId($point->getId())); return $point->getIdPublic(); } } Now, this is the part I am struggling with the most. I only have one service to create any type of point, so I do wish to put a bunch of if/thens in it and instead move logic to the individual point type being created. The AggrPoint in question requires a sub-point and I don't think it is appropriate to inject the entity manager into a point entity and as an alternative solution find an existing point which is associated with the account which resides in the new AggrPoint. Maybe not appropriate, but it works. This type of point also has a sub-object AggrType as discussed at the very beginning of this post, so I first attempt to create a new one from scratch, but that doesn't work and I need to set $aggrType with an existing one. As an alternative, I passed the entity the entity manager, but as stated I think this is a bad idea. Any recommendations where to go from here? Thank you namespace NotionCommotion\PointMapper\Domain\Entity\Point; class AggregatePoint extends Point { public function populate(array $params, \Doctrine\ORM\EntityManager $em):\NotionCommotion\PointMapper\Domain\Entity\Entity{ $criteria = \Doctrine\Common\Collections\Criteria::create() ->where(\Doctrine\Common\Collections\Criteria::expr()->eq("id_public", $params['pointId'])); if(!$subpoint = $this->getAccount()->getPoints()->matching($criteria)->current()){ throw new \Exception("Invalid subpoint ID $params[pointId]"); } $this->setSubpoint($subpoint); //This won't work since I must use an existing AggregateType and not create a new one $aggrType=new AggregateType(); $aggrType->setType($params['aggrType']); //This just seems wrong and I shouldn't be passing the entity manager to an entity $aggrType=$em->getRepository(AggregateType::class)->findOneBy(['type'=>$params['aggrType']]); $this->setAggregateType($aggrType); unset($params['pointId'], $params['aggrType']); // parent::populate($params) not shown, but it basically calles appropriate setters based on the property name return parent::populate($params); } public function getValidatorRules():array { return $this->filesToArr(['/point/base.json', '/point/aggr.json']); } }
Hi I am new to PHP and I need to create an array and add both books to the array and than loop through the array this is where I am having trouble if the price of a book is less than $20.00 output the book’s name and price if the book’s title comes after the letter R in the alphabet output the book’s title. I am getting these error:
Notice: Trying to get property 'price' of non-object in C:\xampp\htdocs\PHP objects\books.php on line 45 My code is:
<?php
// Methods
$first_book = new Book();
foreach ($book as $bookItem) { Any help will be very much appreciated Thank you
The below code produces a dropdown and when a selection is made and submitted produces --------------------------------------------------------------------------- <!DOCTYPE><html><head> <title>lookup menu</title> </head> <body><center><b> <form name="form" method="post" action=""> <?php // error_reporting(0); error_reporting(E_ALL ^ E_NOTICE); include 'homedb-connect.php'; //This creates the drop down box echo "<select name= 'target'>"; echo '<option value="">'.'--- Select account ---'.'</option>'; $query = mysqli_query($con,"SELECT target FROM lookuptbl"); $query_display = mysqli_query($con,"SELECT * FROM lookuptbl"); while($row=mysqli_fetch_array($query)) {echo "<option value='". $row['target']."'>".$row['target'] .'</option>';} echo '</select>'; ?> <input type="submit" name="submit" value="Submit"/> </form><center> <?php // error_reporting(0); error_reporting(E_ALL ^ E_NOTICE); include 'homedb-connect.php'; if(isset($_POST['target'])) { $name = $_POST['target']; $fetch="SELECT target, purpose, user, password, email, visits, date, saved FROM lookuptbl WHERE target = '".$name."'"; $result = mysqli_query($con,$fetch); if(!$result) {echo "Error:".(mysqli_error($con));} //display the table echo '<table border="1"><tr><td bgcolor="#ccffff" align="center">lookup menu</td></tr> <tr><td> <table border="1"> <tr> <td> Target </td> <td> Purpose </td> <td> User </td> <td> Password </td> <td> Email </td> <td> Visits </td> <td> Date </td> <td> Saved </td> </tr>'; while($data=mysqli_fetch_row($result)) { $url= "http://localhost/home/crud-link.php?target=". $data[0]; $link= '<a href="'.$url.'">'. $data[0]. '</a>'; echo ("<tr><td> $link </td><td>$data[1]</td><td>$data[2]</td><td>$data[3]</td> <td>$data[4]</td><td>$data[5]</td><td>$data[6]</td><td>$data[7]</td></tr>"); } echo '</table> </td></tr></table>'; } ?> </body></html>
hello , I'm starting to use mysqli and i have few questions. is there a guide for mysqli? and how do i use this functions at mysqli ? mysql_num_rows mysql_query mysql_fetch_assoc mysql_fetch_array thanks , Mor. I am using mysqli, OO, to connect to MySQL. I have only today started looking at this and am used to: Code: [Select] <?php $con = mysql_connect();//etc mysql_close($connection); ?> Am I right that with mysqli (OO) that I don't need to set a connection variable wither when connecting or closing?? Code: [Select] <?php mysqli::connect();//etc mysqli::close(); ?> What about with multiple databases, does mysqli keep track for me, as I am used to this: Code: [Select] <?php $con1 = mysql_connect();//db1 $con2 = mysql_connect();//db2 ?> //etc Hi, The following code is what I want in that it creates a menu and I can select and display a table row.
I still need to use that selection to update the "lastused". I really appreciate your help. <!DOCTYPE><html><head><title>email menu</title></head> <body><center> <form name="form" method="post" action=""> <?php $con=mysqli_connect("localhost","root","cookie","homedb"); //============== check connection if(mysqli_errno($con)) {echo "Can't Connect to mySQL:".mysqli_connect_error();} else {echo "Connected to mySQL</br>";} //This creates the drop down box echo "<select name= 'target'>"; echo '<option value="">'.'--- Select email account ---'.'</option>'; $query = mysqli_query($con,"SELECT target FROM emailtbl"); $query_display = mysqli_query($con,"SELECT * FROM emailtbl"); while($row=mysqli_fetch_array($query)) {echo "<option value='". $row['target']."'>".$row['target'] .'</option>';} echo '</select>'; ?> <input type="submit" name="submit" value="Submit"/><!-- update "lastused" using selected "target"--> </form></body></html> <!DOCTYPE><html><head><title>email menu</title></head> <body><center> <?php $con=mysqli_connect("localhost","root","cookie","homedb"); if(mysqli_errno($con)) {echo "Can't Connect to mySQL:".mysqli_connect_error();} if(isset($_POST['target'])) { $name = $_POST['target']; $fetch="SELECT target,username,password,emailused,lastused, purpose, saved FROM emailtbl WHERE target = '".$name."'"; $result = mysqli_query($con,$fetch); if(!$result) {echo "Error:".(mysqli_error($con));} $lastused = "CURDATE()"; // update "lastused" using selected "target" //display the table echo '<table border="1">'.'<tr>'.'<td bgcolor="#ccffff align="center">'. 'Email menu'. '</td>'.'</tr>'; echo '<tr>'.'<td>'.'<table border="1">'.'<tr>'.'<td bgcolor="#ccffff align="center">'.'target'.'</td>'.'<td bgcolor="#ccffff align="center">'.'username'.'</td>'.'<td bgcolor="#ccffff align="center">'.'password'.'</td>'.'<td bgcolor="#ccffff align="center">'.'emailused'.'</td>'.'<td bgcolor="#ccffff align="center">'.'lastused'.'</td>'.'<td bgcolor="#ccffff align="center">'.'purpose'. '</td>'.'<td bgcolor="#ccffff align="center">'. 'saved' .'</td>'.'</tr>'; while($data=mysqli_fetch_row($result)) {echo ("<tr><td>$data[0]</td><td>$data[1]</td><td>$data[2]</td><td>$data[3]</td><td>$data[4]</td><td>$data[5]</td><td>$data[6]</td></tr>");} echo '</table>'.'</td>'.'</tr>'.'</table>'; } ?> </body></html> Ok I am trying to use mysqli instead of the usual mysql. Mysql would be outdated. With mysqli, sgl-injection is impossible if you use the "?" in those codes. I would normally use a function but I've made a simple script to find the error. I use $parameters and $sql because these are the data I need to give as parameters to the function, so I used it here too but without the function actually. Code: [Select] ini_set('display_errors',1); // 1 == aan , 0 == uit error_reporting(E_ALL | E_STRICT); # sql debug define('DEBUG_MODE',true); // true == aan, false == uit $userid = 11; $lang = 1; $newLink = "testing123"; $db_host = "localhost"; $db_gebruiker = "root"; $db_wachtwoord = ''; $db_naam = "projecteasywebsite"; $sql= "INSERT tbl_link(userid,linkcat,linksubid,linklang,linkactive,linktitle) VALUES(?, ?, ?, ?, ?, ?)"; $parameters = '"iiisis", $userid, 1, 0, $lang, 1, $newLink'; echo $parameters; $mysqli = new mysqli($db_host, $db_gebruiker, $db_wachtwoord, $db_naam); $stmt = $mysqli->prepare($sql); $stmt->bind_param($parameters); $stmt->execute(); echo "<br><br>". mysqli_connect_errno(); echo "<br><br>". mysqli_report(MYSQLI_REPORT_ERROR); $stmt->close(); $mysqli->close(); I got Wrong parameter count for mysqli_stmt::bind_param() So naturally a problem when we execute : Warning: mysqli_stmt::execute() [mysqli-stmt.execute]: (HY000/2031): No data supplied for parameters in prepared statement ($stmt->execute() Is someone using mysqli too ? Hello everyone, For two weeks now, I'm trying to get this database connection in my query. Can someone give me a solution and tell me what I've done wrong? Am I overlooking something? <?php class Mysql{ public function connect(){ $mysqli = new mysqli('localhost','root','','login'); } } class Query extends Mysql{ public function runQuery(){ $this->result = parent::connect()->query("select bla bla from bla bla"); } } $query = new Query; $query->runQuery(); ?> When running the following code i get the error: Call to undefined method mysqli::errno() the code: $conn = new mysqli(HOST, USER, PASSWORD, DATABASE); if ($conn->errno() !== 0) { $msg = $conn->error(); throw new connErrorException($msg, 'Connect'); } I am fairly new to classes but as i understand it this should be correct. I am using mysql 5.1 so mysqli is on by default. I have even checked the php ini and everything looks fine there in respect to this. Any advice? I have just started using MySQLi and am clueless it is giving me the follow errors in which i do not understand
Warning: mysqli_select_db() expects exactly 2 parameters, 1 given in C:\xampp\htdocs\Login\connect.php on line 23 Notice: Trying to get property of non-object in C:\xampp\htdocs\Login\connect.php on line 25 Notice: Use of undefined constant mysqli - assumed 'mysqli' in C:\xampp\htdocs\Login\connect.php on line 32 Warning: mysqli_query() expects parameter 1 to be mysqli, string given in C:\xampp\htdocs\Login\connect.php on line 32 Warning: mysql_fetch_assoc() expects parameter 1 to be resource, null given in C:\xampp\htdocs\Login\connect.php on line 33 can someone please explain to me why i am getting these? and my code is $mysqli_db = mysqli_select_db("$db_name"); if($mysqli_db->connect_errno) { printf("Database not found: %s\n", $mysql->connect_error); exit(); } $sql = "SELECT * FROM $tbl_name WHERE username='$username' AND password='$password'"; $result = mysqli_query($sql); $row = mysqli_fetch_assoc($result);I just got rid off most the errors the only ones left are Warning: mysqli_query() expects at least 2 parameters, 1 given in C:\xampp\htdocs\Login\connect.php on line 32 Fatal error: Call to undefined function mysqli_result() in C:\xampp\htdocs\Login\connect.php on line 33 Code Updated: $mysqli_db = mysqli_select_db($mysqli_connect, $db_name); if(!$mysqli_db) { printf("Database not found: %s\n", $mysqli->connect_error); exit(); } $sql = "SELECT * FROM $tbl_name WHERE username='$username' AND password='$password'"; $query = mysqli_query($sql); $result = mysqli_result($query); $row = mysqli_fetch_assoc($result); Edited by Tom8001, 30 November 2014 - 12:43 PM. I dont know whether the statement is correct.....i just tried it.....and it didn't work. $stmt->bind_param('ssiiiss',$_POST['name'],$_POST['email'],$_POST['d'],$_POST['m'],$_POST['y'],$_POST['add'],$_POST['phone']); here my first two values are strings and next 2 tiny int's next is int and last 2 again strings. Hi all,
I am working with the following 2 page script: https://github.com/k...hi/php-riot-api. All works well and the data is pulled via the API as intended. However, depending on the data I'm trying to display on screen, the object contains multiple values.
For example:
$r = $test->getSummoner($summoner_id,'name'); print_r($r);outputs their ID and name: {"585897":"TheirName"} Just as the following: $r = $test->getSummonerByName($summoner_name); print_r($r);outputs username, ID, Name, profile icon ID, level, and timestamp: {"theirname":{"id":585897,"name":"TheirName","profileIconId":642,"summonerLevel":30,"revisionDate":1405652924000}} Depending on which function I am calling (on example.php), I would like to be able to split the values so I can echo them throughout a page: Name: <value> ID: <value> Level: <value> etc... Any guidance would be appreciated. I know it is often frivolous, but sometimes I can't help trying to optimize things, and use the following two methods to create either an object injected with a string or one of a set of objects. For both cases, the class has no setters so there is no chance that the object will later be changed. I first stated doing this in continuously running server applications which I believe makes sense, however, it has leaked over to standard HTTP requests. Please commit good or bad on this approach. Thanks
public static function create(string $unit):self { static $stack=[]; if(!isset($stack[$unit])) { $stack[$unit] = new self($unit); } return $stack[$unit]; } public static function create(string $class):FunctionInterface { static $stack=[]; if(!isset($stack[$class])) { $stack[$class] = new $class; } return $stack[$class]; }
I took an object, and saved it into a database serialized. Code: [Select] $object_here = serialize($theobject); Then later on, I go and I get that data from a database, and try to unserialize it.. Code: [Select] $objecthere = unserialize($row->theobject) And it throws the following error...any advice? Quote Warning: unserialize() [function.unserialize]: Node no longer exists in /path/to/file on line 20 I found it helpful to configure all my objects in one or several bootstrap scripts. Before doing so, I would often find myself forgetting that I already had written some class which is located deep in some script and recreating it for some other need (granted, composer definitely helped in this regard, but using it wasn't always applicable). <?php $c=new Pimple\Container(getMySettings()); $c['pdo'] = function ($c) { $db = $c['settings']['mysql']; return new \PDO(bla); }; $c['foo'] = function ($c) { return new Foo( $c->get('pdo') ); }; $c['bar'] = function ($c) { return new Bar( $c->get('foo') ); }; It is all good until I find myself needing to create some new instance of some class instead of just passing some common instance to whoever needs it. class Foo { private $pdo; public function __construct(\PDO $pdo) { $this->pdo=$pdo; } public function getSomething():SomeClass { return new SomeClass($this->getAllDataFromDB($GET['id'])); } } class SomeClass { private $arr; public function __construct(array $records) { foreach($records as $record) { $arr[]=new SomeOtherClass($record); } } } I've read that one shouldn't create new objects in a given class's constructor, and while I could instead do so in some class's method and pass the object to the given class's constructor, to me it seems to really be the same thing. The three issues I have with this scenario a Needing to remember that these classes exist as they are hidden deep in some classes. Makes it more difficult to replace one of the classes with some other class in the future. Some duplication of code.Are there other compelling reasons not to do so? Is it worth the effort to do differently? If so, how would you recommend doing so? My thoughts would either to use Pimple's factory() method are create my only factory which also relies on anonymous functions. Maybe something else? $c['someClass'] = $c->factory(function (array $record, Container $c) { return new SomeClass($record); }); Thanks In a relational database, you "link" tables together. For example, Customer (parent) ---> Product (child) How do you do that with Objects? I have a "User" class and an "AddressBook" class. A User can have zero or more Addresses (in their AddressBook). If I create a User object and an AddressBook object, I need a way to link them up similar to how they are linked up in the database. Make sense?! TomTees I am trying to extend my knowledge from using basic mysql_connect etc. into something better. I am searching on Google, and looking up as much info as possible but find that I learn best with a brief overview that allows me to channel down my searches. (1) I know PDO v mysql_connect v mysqli isn;t right - I think PDO is a class, mysql_connect is a command and mysqli is something else. Am I on the right track? (2) What is the best solution? I am using a full OOP coding style and want to learn the best - I am a novice at this but would consider myself an 8/10 programmer at other parts of PHP. An very brief overview to get me started and channel my Google searches would be much appreciated. - I have heard PDO is slower. - I don't need support for different databases (only MySQL). Thanks in advance. Dear Sir/Madame I am making a website where user can insert data and wait for the admin to approve/reject the form. Now i am stuck with the update status where an admin can submit with a click pending to approval or reject with comments. I am new to PHP programming. Can somebody help me with the issue. Part 1 is inserting the data and part two is fetching the data but i am unable to solve the status approve/reject and comment at the same time on the view.php? page. Kindly help. Thank you. <?php $host="localhost"; $username="root"; $pass=""; $db="ems1"; $conn=mysqli_connect($host,$username,$pass,$db); if(!$conn){ die("Database connection error"); } // insert query for register page if(isset($_REQUEST['proposal'])) { $details=$_POST['details']; $location=$_POST['location']; $date=$_POST['date']; $time=$_POST['time']; $status="Pending"; $comment=$_POST['comment']; $query="INSERT INTO `proposal` (`details`,`location`,`date`,`time`,`status`,`comment`) VALUES ('$details','$location','$date','$time','$status','$comment')"; $res=mysqli_query($conn,$query); if($res){ $_SESSION['success']="Not Inserted successfully!"; header('Location:'); }else{ echo "Leave not Applied, please try again!"; } } ?> <div class="col-xs-6 col-xs-push-3 well"> <form class="form-horizontal" method="post" action="" > <input type="hidden" name="proposal" value=""> <fieldset> <legend>New Proposals </legend> <!----left box-----------> <!----right box-----------> <div class="col-xs-9"> <div class="form-group"> <label for="inputEmail" class="col-lg-3"><b>Details:</b></label> <div class="col-lg-9"> <input type="text" name="details" class="form-control"> </div> </div> <div class="form-group"> <label for="inputEmail" class="col-lg-3"><b>Location:</b></label> <div class="col-lg-9"> <input type="text" name="location" class="form-control" > </div> </div> <div class="form-group"> <label for="inputEmail" class="col-lg-3"><b>Date:</b></label> <div class="col-lg-9"> <input type="date" name="date" class="form-control"> </div> </div> <div class="form-group"> <label for="inputEmail" class="col-lg-3"><b>Time:</b></label> <div class="col-lg-9"> <input type="time" name="time" class="form-control" > </div> </div> <div class="col-lg-9"> <input type="hidden" name="status" class="form-control" > </div> </div> <div class="form-group"> <label for="inputEmail" class="col-lg-3"><b></b></label> <div class="col-lg-9"> <input type="hidden" name="comment" class="form-control"> </div> </div> </div> <div class="form-group"> <div class="col-lg-12"> <button type="reset" class="btn btn-default">Cancel</button> <button type="submit" class="btn btn-primary">Submit</button> </div> </div> </fieldset> </form> </div> </div> <body> <h2 style="text-align:center; color:orangered;"> DASHBOARD </h2> <table> <h3> <tr style="background-color:#E4EBC5; color:orangered;"> <th>ID</th> <th>Details</th> <th>Location</th> <th>Status</th> <th>Comment</th> </tr> </h3> </table> <?Php //////////////////////////////////////////// require "dbconfig.php"; // MySQL connection string $count="SELECT id,details,location,time,status,comment FROM proposal"; if($stmt = $connection->query($count)){ while ($nt = $stmt->fetch_assoc()) { echo " <body> <table> <tr> <td><a href=view.php?id=$nt[id]>$nt[id]</a></td> <td>$nt[details]</td> <td>$nt[location]</td> <td>$nt[status]</td> <td>$nt[comment]</td> </tr> </table> </body> "; } }else{ echo $connection->error; } ?>
|