PHP - What Are You Listening To?

I'm trying to make a page with multiple $_GET situations

example if my user wants to log out, he clicks the loggout link which sends him to
user.php?v=dc

if($_GET['v']=="dc") { session_destroy(); exit; }
if(isset($_GET['v'])=="dc") { session_destroy(); exit; }

but it seems no matter where the user goes it destroys the session.

if($_GET['v']=="mail") { // show mail }

but instead it does what's in $_GET['v']=="dc"

<?php

if(isset($_GET["v"])=="dc"){

if($_SESSION[user]=='Guest'){

echo "You are not logged in fool.";

exit;

}else{

echo "Session closed!";

session_destroy();

}

}

?>
That above doesn't work, when I go elsewhere it still destroy the session... no matter if it's a guest or not. If I go to ($_GET['v']=="godknows") as a user and not a guest, it will destroy the session.

I get the strangest errors...
S.O.S

Hi Guys, I am trying to get the while function to list four of my items on a row however I have no idea how and every time I try, I fail. Please give me a hand? Here is the code I have so far

Code: [Select]



if($row['photo'] == "#no_photo")
$photo = ('<img src="images/item_pictures/default_item.png" width="150" height="150" alt="Default Item">');
else
$photo = $row['photo'];


echo "<br /> <br />" ;


echo "<br />
<font face='Comic Sans MS, cursive'>Click on an item to view it in full.</font>
<br />
<br />";


if($row['photo'] == "#no_photo")
$photo = ('<img src="images/item_pictures/default_item.png" width="100" height="100" alt="Default Item">');
else
$photo = $row['photo'];


echo "<br /> <br />" ;


$i = 0;
while ($i < $num) {




$f1 = "<tr><td><font size='6'><a href='item.php?id=" . mysql_result($result,$i,"item_id") . "'>" . mysql_result($result,$i,"item_name") . "</a></font></td><td> "    . $photo . "</td></tr>";




echo "" .  $f1 ."" ;
$i++;




Thanks, Jacbey