PHP - Php/html/sql Allow Contenteditable Cell To Write Back To Sql Database
I have a table that has a cell that I've made editable:
echo "<td contenteditable='true'>" . $row['Comments'] . "</td>";Which is cool I guess, but it doesn't go anywhere from there. I'd like to make it so that upon changing, it links back to an SQL UPDATE query that I define. Is this possible through some sort of onChange function? Similar TutorialsSay I have the following text stored in a MySQL database... Code: [Select] <b>Classic Quote from movie</b> and I retrieve it into a variable called $text, how do I properly echo that so that it keeps the bold tags and actually display the text "Classic quote from movie" in BOLD? I'm doing something wrong somewhere along the line (simply doing "echo $text;") because it displays on the page as... Code: [Select] <b>Classic Quote from movie</b> Instead of... Classic Quote from movie Any info on properly storing and echoing back HTML would be very appreciated. Hello everyone! I am a new user and I have a simple question. How to download the database and create a backup. I have a profile page where the user answers a list of about 20 questions. These questions are then put into a mysql table with username, questionid, and answer. I can store the answers to the table, but I cannot figure out how to get them back to view and edit. My form is built from basic HTML. I know how to pull answers from a db table with only 1 row of results, where each field is a different question, but this one is different, as it will pull 20 rows, and each row is for a different question. Here is how I populate the questions and then fill in the answers. Code: [Select] // If this user has never set their profile, insert empty questions into the database $query1 = "SELECT * FROM u_profile WHERE username = '" . $_SESSION['username'] . "'"; $data = mysqli_query($dbc, $query1); if (mysqli_num_rows($data) == 0) { // First grab the list of questionids $query2 = "SELECT questionid FROM questions ORDER BY q_order"; $data = mysqli_query($dbc, $query2); $questionids = array(); while ($row = mysqli_fetch_array($data)) { array_push($questionids, $row['questionid']); } // Insert empty question rows into the u_profile table, one per question foreach ($questionids as $questionid) { $query3 = "INSERT INTO u_profile (username, questionid) VALUES ('" . $_SESSION['username']. "', '$questionid')"; mysqli_query($dbc, $query3); } } // If the questionnaire form has been submitted, write the responses to the database if (isset($_POST['submit'])) { // Write the questionnaire response rows to the response table foreach ($_POST as $answer_id => $answer) { $query4 = "UPDATE u_profile SET answer = '$answer' WHERE username = '" . $_SESSION['username'] . "' AND questionid = '$answer_id'"; $uprofile_set = "CALL uprofile_set('" . $_SESSION['username'] . "')"; mysqli_query($dbc, $query4) or die( "Connection Error1" . mysqli_error($dbc) ) ; mysqli_query($dbc, $uprofile_set) or die( "Connection Error2" . mysqli_error($dbc) ) ; } $races = "SELECT * FROM u_raceschedule WHERE username = '" . $_SESSION['username'] . "'"; $data = mysqli_query($dbc, $races); if (mysqli_num_rows($data) > 0) { set_time_limit(30); $buildplan = "CALL tplan('" . $_SESSION['username'] . "')"; mysqli_query($dbc,$buildplan) or die("Connection Error2" . mysqli_error($dbc) ) ; Would LOVE any help. I am really new to this whole coding thing. Hi.. I've seen code for back up database but when I run the code the database was backup outside the folder. I want to put the back up database inside the folder here is the code: Code: [Select] <?php include 'config.php'; backup_tables('localhost','root','','payroll'); /* backup the db OR just a table */ function backup_tables($host,$user,$pass,$name,$tables = '*') { $link = mysql_connect($host,$user,$pass); mysql_select_db($name,$link); //get all of the tables if($tables == '*') { $tables = array(); $result = mysql_query('SHOW TABLES'); while($row = mysql_fetch_row($result)) { $tables[] = $row[0]; } } else { $tables = is_array($tables) ? $tables : explode(',',$tables); } //cycle through foreach($tables as $table) { $result = mysql_query('SELECT * FROM '.$table); $num_fields = mysql_num_fields($result); $return.= 'DROP TABLE '.$table.';'; $row2 = mysql_fetch_row(mysql_query('SHOW CREATE TABLE '.$table)); $return.= "\n\n".$row2[1].";\n\n"; for ($i = 0; $i < $num_fields; $i++) { while($row = mysql_fetch_row($result)) { $return.= 'INSERT INTO '.$table.' VALUES('; for($j=0; $j<$num_fields; $j++) { $row[$j] = addslashes($row[$j]); $row[$j] = ereg_replace("\n","\\n",$row[$j]); if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; } if ($j<($num_fields-1)) { $return.= ','; } } $return.= ");\n"; } } $return.="\n\n\n"; } //save file $myfoldername = "backup_DBPayroll";//your folders name $handle = fopen(getcwd().$myfoldername.'db-backup-'.time().'-'.(md5(implode(',',$tables))).'.sql','w+'); // $handle = fopen('db-backup-'.date('m-d-Y').'-'.(md5(implode(',',$tables))).'.sql','w+'); fwrite($handle,$return); fclose($handle); } $smarty->display('header_cat.tpl'); $smarty->display('backup.tpl'); $smarty->display('footer.tpl'); ?> Thank you in advance Ok so I have this site where I'm posting a message to my Database. But when I go to pull the message from the MYSQL DB it's one long sentence. Any suggestions? Hi All, I have a table (with an ID of example) that can be seen he http://tinyurl.com/cfla7wp The following script calls jeditable.js and makes the Telephone & Mobile columns editable. Once edited, the table shows the new value plus a * symbol. Code: [Select] <script type="text/javascript"> $(document).ready(function() { /* Init DataTables */ var oTable = $('#example').dataTable(); /* Apply the jEditable handlers to the table */ $('td:eq(4), td:eq(5)', oTable.fnGetNodes()).editable( 'update_table_tenants.php', { "callback": function( sValue, y ) { var aPos = oTable.fnGetPosition( this ); oTable.fnUpdate( sValue, aPos[0], aPos[1] ); }, "submitdata": function ( value, settings ) { return { "row_id": this.parentNode.getAttribute("1"), "column": oTable.fnGetPosition( this )[2] }; }, "height": "14px" } ); } ); </script> What I need to do however is add the value entered into my database, but I do not know how to do this. I believe I need to do something like: UPDATE my_table VALUE whatever column has been edited in the table WHERE tenID is the same as the row selected in the table i.e. if I update the MOBILE NUMBER of the person called BILL GATES it would find his tenID, update numMobile in the table called my_table All help appreciated Dave Hi guys, I have a trouble of updating the data in the database by input the data at the end of the url. It have not been added in the table. Here it is updated: <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'myusername'); define('DB_PASSWORD', 'mypassword'); define('DB_DATABASE', 'mydatabasename'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $login = clean($_GET['user']); $password = clean($_GET['pass']); $firstname = clean($_GET['firstname']); if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD ID missing'; $errflag = true; } if($value == '') { $errmsg_arr[] = 'THE first name IS missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $qry="SELECT * FROM members WHERE login='$login' AND passwd='$password'"; $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if(mysql_num_rows($result) > 0) { $row = mysql_fetch_row($result); echo $row[0]; } else { echo 'Username, Password or first name is not found.'; close; $sql="INSERT INTO members (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "first name have been updated"; } ?> It have only login in the database but did not doing any update when I have input the data at the end of the url to get the database update. Do you know why I can't update the data in the database by input the data in the url like this? http://www.mysite.com/updatemysql.php?user=test&pass=test&firstname=shitorwhateveriwanttoinputandgetitupdate Do you have any idea and maybe if I have miss something? Hi Everyone, Hopefully this will be a quick one. How would i write each line in a textbox as a new row in a mysql database? I cant seem to find the solution on google. Thanks Hi guys i have another question about my shopping cart.
I have in my sql database table called products. It consist of 4 columns (product_id, description, quantity, price).
Now on my index page, I want to call just one product from cell, which would have special price. But i don't know how to call one single product.
So my code looks like that:
<?php $sql="SELECT product_id FROM Products"; $query=mysql_query($sql); $row=mysql_fetch_array($query); ?><table > <tr><img src="Images/Image.jpg" width="380" height="300" /> </tr> <tr> <td><a href="index.php?page=index&action=add&id=<?php echo $row['product_id']?>">Add to cart</a></td> </tr> <?php ?> </table>This code display me first product but i would like to call 3 product how would i do that, so i have 6 products and i would like to call product N.3 to my index page. My code calls the first one, how would it call the third. Not sure where to post this question. I have a MySQL database and add records with a PHP form to the tables. I have 2 fields (char) in one table. When the fields contain the character ' it wont write the record to the table! For example...if I enter. " John's house" it wont accept the record since ' appears in John's name! How do I work around this? Thanks I have a form that users input user name, password, and email... all writes to csv fine. My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv.. I need the csv to be this username,password,email,user,category,text with http://sub.domain..com/splash/,something,something here's what i have Code: [Select] <?php if($_POST['formSubmit'] == "Submit") $varUserName = $_POST['username']; $varPW = $_POST['PW']; $varEmail = $_POST['email']; { $fs = fopen("testcsv.csv","a"); fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',)); fclose($fs); exit; } ?> and of course I'm getting Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9 I have a MySQL database with each record of a person who has registered for an event, I am displaying the information on a web page for a user, but he wants to be able to print out all the records in alphabetical order by last name, first name later on so he will have a hard copy of each person who has registered at the table when they arrive. How can I write each record to a Txt file that he can print out later that will be formated with the record contents along with each fields definition (Ex. Last Name - Smith, First Name - John, etc)? I am a complete newbie. I have installed xampp. I created a database and the tables but that is all. I need to create all my relationships and test my database. to do this, do I now need to write the php code to view the results in a browser or... do I do it in MySQL. If so, Can someone just point me in the direction I need to go for my next step.
Thanks
The subject could be a bit vague, but my problem is simple. (I think so) So I made a php test site that is quite similar to a forum. Where you see a title or a subject and when you click on it you will see more details about that subject. I made my database and script for inserting data into my mySQL database. I also did my output aswell, so every topic is posted on a webpage "archive" where you can see all the subjects. But now I want to see the full details of that type of subject by clicking on it. I have no idea how to make that happen googled it but didn't find any results...just wondering if it's even possible to do that. I'm a new guy here! Hello everyone. I am writing this order/feedback form using a php script.
Every time i hit submit, the html page (that has the form inside) just reloads and does not perform the script
could anyone give me some pointers in my code the form/php?
I have made sure they are linked verbatim
I am a nube so please forgive my inexperience
Here is the form in the html , down below it is the corresponding php code for the form
I would like to be able to use this
<img src="user/<?=$log_username. '/' . $main_image;?>" width="130" height="150" id="pic5"/>to work within php and i am having a had time doing so . Any ideas? $log_username refers to the users specific username folder within the main users folder html source code looks like this ,but i need to reference this within a PHP code block not html <img src="user/lexi/pic.png" width="130" height="150" id="pic5">any ideas? thanks guys "BACK" or REFRESH: Preventing database interaction / code execution how to prevent database interaction / code execution when user presses back or refresh button? can i detect? can i disable back/refresh? Please, take a look to the following code.After clicking Next it goes to overview.php.Why when I click back on my browser to return to this page again, it is not returning back? When I click back I receive "Confirm Form Resubmission" message. After refreshing page it loads page. I guess problem is in "session_start();" part. Something to do with cookies. Please, help me it is very urgent for me. <?php session_start(); echo "<html> <head> <title>Hello World</title> <meta http-equiv='Content-Type' content='text/html; charset=Windows-1252'/> </head>"; require_once ('functions.inc'); if(!isset($_POST['userid'])) { echo "<script type='text/javascript'>"; echo "window.location = 'index.php'"; echo "</script>"; exit; }else{ session_register("userid", "userpassword"); $username = auth_user($_POST['userid'], $_POST['userpassword']); if(!$username) { $PHP_SELF = $_SERVER['PHP_SELF']; session_unregister("userid"); session_unregister("userpassword"); echo "Authentication failed " . "Please, write correct username or password. " . "try again "; echo "<A HREF=\"index.php\">Login</A><BR>"; exit; } } function auth_user($userid, $userpassword){ global $default_dbname, $user_tablename; $user_tablename = 'user'; $link_id = db_connect($default_dbname); mysql_select_db("d12826", $link_id); $query = "SELECT username FROM $user_tablename WHERE username = '$userid' AND password = '$userpassword'"; $result = mysql_query($query) or die(mysql_error()); if(!mysql_num_rows($result)){ return 0; }else{ $query_data = mysql_fetch_row($result); return $query_data[0]; } } echo "hello"; echo "<form method='POST' name='myform' action='overview.php'>"; echo "<input type='submit' value='Next'>"; echo "</form>"; ?> I'm reading over this book and I came across something that looked very odd:
public function DisplayHeader() { ?> <table width="100%" cellpadding="12" cellspacing="0" border="0"> <tr bgcolor ="black"> <td align ="left"><img src = "logo.gif" /></td> <td> <h1>TLA Consulting Pty Ltd</h1> </td> <td align ="right"><img src = "logo.gif" /></td> </tr> </table> <?php }In the function it closes a php tag, uses raw html that is rendered as is on the page, and then returns back to opening the php tag. I understand why it is being done. It is easier to write raw html here than to echo it in a php block, but it just looks odd. Anyone actually use this technique? I have a stdClass Object array with nested User arrays as a value that I would like to display in a table cell. I am struggling and have exhausted a lot of time. I am hoping to get a shove in the right direction if possible. The image below will show what I am trying to do.
$someArray = json_decode($token_result); foreach ($someArray as $key => $value) { $combined[] = "<tr><td>" . $value->customer . "</td><td>" . $value->city . '</td> <td>' . $value->state . "</td><td>" . $value->zipcode . '</td> <td>' . $value->totalUsers . "</td><td>" . $value->totalActiveUsers . "</td><td>" . $value->totalInActiveUsers . '</td><td> <a href="">' . $value->users . "</a></td></tr>"; } foreach ($combined as $value) { print $value; } Here is what my Array and Objects look like Array ( [0] => stdClass Object ( [customer] => SWSH [city] => Thomasville [state] => GA [zipcode] => 31792 [totalUsers] => 6 [totalActiveUsers] => 6 [totalInActiveUsers] => 0 [users] => Array ( [0] => stdClass Object ( [firstName] => xxx [lastName] => xxx [phoneNumber] => [userName] => cb_igwrth@xxx.com [createdBy] => [isActive] => 1 ) [1] => stdClass Object ( [firstName] => Dan [lastName] => Stewart [phoneNumber] => +11111111111 [userName] => dan.sxx@xxx.ga.gov [createdBy] => kwilliams@xxx.com [isActive] => 1 ) ) ) [1] => stdClass Object ( [customer] => xxxx [city] => Carver [state] => MA [zipcode] => 02330 [totalUsers] => 3 [totalActiveUsers] => 3 [totalInActiveUsers] => 0 [users] => Array ( [0] => stdClass Object ( [firstName] => Leo [lastName] => Furtado [phoneNumber] => 781-000-0000 [userName] => LFurtado@xxx.com [createdBy] => TConger@ccccc.com [isActive] => 1 ) ) ) ) Table is attached
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